|
PHP - Experienced Php Oop Developer - Simple Project - Beautiful Code
Experienced, skilled and perfectionist coded needed for a small, minimal application.
Skills
- Skilled using raw PHP (no framework), utilising PHP5, in OOP structure
- Experienced designing optimised and clean MYSQL schemas
- Concious of both performance and security
- Understanding of Jquery
Perfered
- Knowledge of stripe
- Knowledge of sending emails with third party (SMTP etc)
- Basic HTML / CSS
Personal Qualitied
- Perfectionist
- Enjoys writing clean, clear and efficient code
Edited by jameswillson, 03 September 2014 - 08:47 AM. Similar TutorialsHey, everyone. My name is Matthew and I have a new project I would like developing. It is a social network site based on Twitter where you can upload content and follow other users. I am looking for someone experienced in developing who will be able to start this from the beginning. The project should take around 1-2 months to be up and running fully. If you are interested please send me a) Your Portfolio b) Your Location c) Your Price per hour ($) to boyle.matthew(@)gmail.com and hopefully we can talk further. Thanks, Matthew Hi guys and girls im a new guy on this forums and im here to beg for a favor, for my school assignment i have to make a simple php script and i have no idea how to do that so, here i am what i need is basically a video store rental application that store staff would use. Nothing fancy just that it works. We also got sakila-db to work with and use witch is 30% of my problem if a got to make my own db i would not be quite as confused right now. Can any1 help me because im starting to panic. i apologize if i posted in the wrong place. im including small dijagram of how this thing is supposed to look any help would be appreciated. [attachment deleted by admin] I am looking for a PHP developer to develop an application in which is almost completed. I can pay, but I expect HIGH quality work like my other PHP Developer. Here is a link to the project that needs to be finished: http://inzernettechn...es.com/StreamIT
Please contact me ASAP! Thanks
Skype: inzernettechnologies.admin
E-Mail: cody-admin@inzernettechnologies.com
Contact form: http://inzernettechn...ore/contact.php
Hi I have a simple idea for a webapp I would like to pay someone to develop for my small business. It's a system for tracking "one off" orders we get. Basically at the moment we use paper notes. Problems with this:- - They get lost - In 6 months time if the customer wants to reorder, you have to take the customer's details again, which isn't very professional - If I remember I've taken an order for something I can't do anything about it (i.e. let my colleagues know) until I'm next at work. etc etc I wanted built a web app (basically a webpage front end to a as yet non-existent database) which would allow us to log these items and then have a search/query function where we would look through:- "open orders" "closed orders" "orders awaiting collection" etc offers to mefijob@forward.cat thanks! There is only one thing I want to know. How to I fill out a text box, click submit and make that information go to a msql database? This is very simple but I am very new to php. This is all I want to learn. Also showing the value on a table after I submitted would be great. Thanks and I hope someone can help. hello dear friends if we want to put a facebook-fanbox on a wordpress-page - so that it looks like this he http://www.designche...ial-media-tabs/ we can go like so: we take the test from the facebook-deeloper site: https://developers.f...e-box-for-pages Initialize the JavaScript SDK using this app: books-page... <div id="fb-root"></div>
<script>(function(d, s, id) {
var js, fjs = d.getElementsByTagName(s)[0];
if (d.getElementById(id)) return;
js = d.createElement(s); js.id = id;
js.src = "//connect.facebook.net/en_GB/sdk.js#xfbml=1&appId=473241986032774&version=v2.0";
fjs.parentNode.insertBefore(js, fjs);
}(document, 'script', 'facebook-jssdk'));</script>
Include the JavaScript SDK on your page once, ideally right after the opening <body> tag. or do i need to inclue this <div class="fb-like-box" data-href="https://www.facebook.com/FacebookDevelopers" data-colorscheme="light" data-show-faces="true" data-header="true" data-stream="false" data-show-border="true"></div>` love to hear from you I'm trying to figure out how I can reduce as much functionality as possible and still keep it doing what it needs to do. What I mean by functionality is the number of queries being performed or any of the other code for that matter. I do show at the bottom of my post what I have so far, however that doesn't cover all the queries. Code: [Select] <?php if ($access_level_id == 2 || $access_level_id == 3) { $query = "SELECT characters.id FROM characters"; $result = mysqli_query ($dbc,$query); $total_num_characters = mysqli_num_rows($result); $query = "SELECT user_characters.id FROM user_characters INNER JOIN user_accounts ON user_accounts.id = user_characters.user_id"; } else { $query = "SELECT user_characters.id FROM user_characters INNER JOIN user_accounts ON user_accounts.id = user_characters.user_id WHERE user_accounts.id = '".$user_id."'"; } $result = mysqli_query($dbc,$query); echo $num_available_characters = mysqli_num_rows($result); if (($num_available_characters > "1") || (($access_level_id == 2 || $access_level_id == 3) && (isset($total_num_characters)) && ($total_num_characters > "0"))) { ?> <form method="POST" id="change_default_character"> <select class="dropdown" name="new_default_character_id" id="new_default_character_id" title="Select Character"> <?php if ($default_character_id > "0") { print "<option value=".$default_character_id.">".$default_character_name; } else { print "<option value=0>- Select -"; } if ($access_level_id == 2 || $access_level_id == 3) { $query = "SELECT characters.id, characters.character_name FROM characters WHERE characters.id <> '".$default_character_id."' AND characters.status_id = '1' ORDER BY characters.character_name"; } else { $query = "SELECT characters.id, characters.character_name FROM characters INNER JOIN user_characters ON characters.id = user_characters.character_id INNER JOIN user_accounts ON user_accounts.id = user_characters.user_id WHERE user_accounts.id = '".$user_id."' AND user_characters.character_id <> '".$default_character_id."' AND characters.status_id = '1' ORDER BY characters.character_name"; } $result = mysqli_query ($dbc,$query); $num_rows = mysqli_num_rows ($result); if ($num_rows > 0) { if ($access_level_id == 2 || $access_level_id == 3) { print "<optgroup label=\"** Active Characters **\">"; } while ( $row = mysqli_fetch_array ( $result, MYSQL_ASSOC ) ) { print "<option value=\"".$row['id']."\">".$row['character_name']."</option>\r"; } } if ($access_level_id == 2 || $access_level_id == 3) { $query = "SELECT characters.id, characters.character_name FROM characters WHERE characters.id <> '".$default_character_id."' AND characters.status_id = '2' ORDER BY characters.character_name"; } else { $query = "SELECT characters.id, characters.character_name FROM characters LEFT JOIN user_characters ON characters.id = user_characters.character_id LEFT JOIN user_accounts ON user_accounts.id = user_characters.user_id WHERE user_accounts.id = '".$user_id."' AND user_characters.character_id <> '".$default_character_id."' AND characters.status_id = '2' ORDER BY characters.character_name"; } $result = mysqli_query ($dbc,$query); $num_nows = mysqli_num_rows($result); if ($num_rows > "0") { print "<optgroup label=\"** Inactive Characters **\">"; while ( $row = mysqli_fetch_array ( $result, MYSQL_ASSOC ) ) { print "<option value=\"".$row['id']."\">".$row['character_name']."</option>\r"; } } ?> </select> </form> <?php } else { print "<h1>".$default_character_name."</h1>\n"; } ?> Code: [Select] <?php /** * Get roster list * * @return object/NULL */ function getRosterList() { $this->db->from('rosterList'); $query = $this->db->get(); if ($query->num_rows() > 0) { return $query->result(); } return null; } /** * Get list of roster by user ID * * @return object/NULL */ function getRosterByUserID() { $this->db->from('rosterList'); $this->db->where('userID', $userID); $query = $this->db->get(); if ($query->num_rows() > 0) { return $query->result(); } return null; } ?> Okay, I need to make it so it shows " ago " after the time it states. It shows "2minutes 20 seconds" but I can't figure out how to make it say "2minutes 20 seconds ago" (simply just need to add "ago" after) This uses alot of ternary operators, and I am not very knowledgable in that area, so if You can help, it would be great. Code: [Select] function timeAgo($tm,$rcs = 1) { $cur_tm = time(); $dif = $cur_tm-$tm; $pds = array('second','minute','hour','day','week','month','year','decade'); $lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600); for($v = sizeof($lngh)-1; ($v >= 0)&&(($no = $dif/$lngh[$v])<=1); $v--); if($v < 0) $v = 0; $_tm = $cur_tm-($dif%$lngh[$v]); $no = floor($no); if($no <> 1) $pds[$v] .='s'; $x=sprintf("%d %s ",$no,$pds[$v]); if(($rcs > 0)&&($v >= 1)&&(($cur_tm-$_tm) > 0)) $x .= $this->timeAgo($_tm, --$rcs); return $x; } Simply, just need to add "ago" somewhere, but I can't figure it out, this uses unixtimestamp also. This is just my software assignment. We have to create a functioning vending machine. How does it look so far? Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Vending Machine Assignment</title> <link href="vending.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="vending_machine_base"> <img src="vending_machine_base.gif" alt="Vending Machine Base" title="Vending Machine Base" /> </div> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <p>Coke<input type="radio" name="item" value="Coke" /></p> <p>Sprite<input type="radio" name="item" value="Sprite" /></p> <p>Fanta<input type="radio" name="item" value="Fanta" /></p> <input type="text" size="15" name="quantity" value="Enter quantity here" /> $<input type="text" value="Enter your financial balance." name="credit_input" size="23" /> <input type="submit" value="Submit" /> </form> <?php error_reporting(E_ALL); // Cost of items $coke_price = "1.25"; $sprite_price = "1.50"; $fanta_price = "1.75"; // Quantity of items $coke_quantity = "7"; $sprite_quantity = "5"; $fanta_quantity = "3"; // Selected radio button into variable $selected_item = $_POST['item']; // Credit into variable $credit = $_POST['credit_input']; // If funds are less than price, dispay error message if (($_POST['submit']) && ($selected_radio = 'coke') && ($credit >= $coke_price)) { echo "You have purchased a $selected_item!"; } else { echo "You do not have sufficient funds to purchase a $selected_item."; } if (($_POST['submit']) && ($selected_radio = 'sprite') && ($credit >= $sprite_price)) { echo "You have purchased a $selected_item!"; } else { echo "You do not have sufficient funds to purchase a $selected_item."; } if (($_POST['submit']) && ($selected_radio = 'fanta') && ($credit >= $fanta_price)) { echo "You have purchased a $selected_item!"; } else { echo "You do not have sufficient funds to purchase a $selected_item."; } // Item quantity if (($_POST['submit']) && ($coke_quantity = 0)) { echo ""; } else { echo "Coke resources depleted."; } if (($_POST['submit']) && ($sprite_quantity = 0)) { echo ""; } else { echo "Sprite resources depleted."; } if (($_POST['submit']) && ($fanta_quantity = 0)) { echo ""; } else { echo "Fanta resources depleted."; } // Item cost subtracted from credit if (($coke_quantity >= 1) && ($credit >= $coke_price)) { $coke_price - $credit; } if (($sprite_quantity >= 1) && ($credit >= $sprite_price)) { $sprite_price - $credit; } if (($fanta_quantity >= 1) && ($credit >= $fanta_price)) { $fanta_price - $credit; } // Funds available echo "Your current funds accumlate to $credit "; ?> </body> </html> Hi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Okay so I have a table that displays grades. If the stupid has 100 for the grade points then I want a A to be displayed under the table... I think it does something like this... if grade_type >=100 $final_grade = A Idk, im new to php and need help doing this... here is my code... Code: [Select] <?php ini_set ("display_errors", "1"); error_reporting(E_ALL); require_once('database.php'); session_start(); if (isset($_POST['add_grade'])) { $query = "INSERT INTO grades (grade_id, student_id, grade_type, grade_name, grade_points) "; $query .= "VALUES (:grade_id, :student_id, :grade_type, :grade_name, :grade_points) "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $_SESSION['student_id']); $statement->bindValue (':grade_id', $_SESSION['grade_id']); $statement->bindValue (':grade_type', $_POST['grade_type']); $statement->bindValue (':grade_name', $_POST['grade_name']); $statement->bindValue (':grade_points', $_POST['grade_points']); $statement->execute(); $statement->closeCursor(); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>View Course Grades</title> <link rel="stylesheet" type="text/css" href="main.css" /> </head> <body> <?php $student_name = $_SESSION['student_name']; $student_id = $_SESSION['student_id']; $query = "SELECT * FROM grades WHERE student_id = :student_id "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $student_id); $statement->execute(); $grades = $statement->fetchAll(); $statement->closeCursor(); echo "<h1>Show Grades for $student_name </h1>"; foreach ($grades as $grade) { echo $grade['grade_type'] . " " . $grade['grade_name']. " " . $grade['grade_points'] . "<br />"; } ?> <div id="content"> <!-- display a table of products --> <table> <tr> <th>Grade Type</th> <th>Grade Name</th> <th>Grade Points</th> <th>Remove</th> </tr> <?php foreach ($grades as $grade) : ?> <tr> <td><?php echo $grade['grade_type']; ?></td> <td><?php echo $grade['grade_name']; ?></td> <td><?php echo $grade['grade_points']; ?></td> <td><form action="delete_grade.php" method="post"> <input type="submit" name="remove" value="Delete" /> <input type="submit" name="update" value="Update" /> </form></td> </tr> <?php endforeach; ?> </table> </div> </div> <div id="footer"> </div> <form name="grades" method="post" action="grades.php"> <p>Grade Type<SELECT NAME="grade_type"> <OPTION VALUE="Mid-Term">Mid-Term <OPTION VALUE="Final">Final <OPTION VALUE="Lab">Lab </SELECT> <br> Grade Name:<input type="text" name="grade_name" value=""><br /> Grade Points:<input type="text" name="grade_point" value=""> <input type="submit" name="add_grade" value="Add Grade"> </form> </table> </body> </html> Code: [Select] <html> <head> <title>Delete Grade</title> </head> <body> <form method="post" action="delete_grade.php"> <?php ini_set ("display_errors", "1"); error_reporting(E_ALL); $dbc = mysqli_connect('localhost', 'se266_user', 'pwd', 'se266') or die(mysql_error()); //delete grades if (isset($_POST['remove'])) { foreach($_POST['delete'] as $delete_id) { $query = "DELETE FROM grades WHERE grade_id = $delete_id"; mysqli_query($dbc, $query) or die ('can\'t delete user'); } echo 'grade has been deleted.<br />'; } if (isset($_POST['update'])) { foreach($_POST['update'] as $update_id) { $query = "UPDATE grades SET grade_id = $update_id"; mysqli_query($dbc, $query) or die ('can\'t update user'); } } //Display grade info with checkbox to delete $query = "SELECT * FROM grades"; $result = mysqli_query($dbc, $query); while($row = mysqli_fetch_array($result)) { echo '<input type="checkbox" value="' .$row['grade_id'] . '" name="delete[]" />'; echo ' ' .$row['grade_type'] .' '. $row['grade_name']; echo '<br />'; } mysqli_close($dbc); ?> <p>Grade Type<SELECT NAME="grade_type"> <OPTION VALUE="Mid-Term">Mid-Term <OPTION VALUE="Final">Final <OPTION VALUE="Lab">Lab </SELECT> <br> Grade Name:<input type="text" name="grade_name" value=""><br /> Grade Points:<input type="text" name="grade_point" value=""> <input type="submit" name="remove" value="Remove" /> <input type="submit" name="update" value="Update" /> </form> </body> </html> Hi!
I'm new to php so, please forgive if this is a really simple question or if it doesn't make sense.
I have an www.domain.com web site and then I have an microprocessor at home connected to the internet also hosting and simple page. That page is acessible from the internet.
When I'm browising on my www.domain.com i want to add an botton that sends an request to the microprocessor, right now what i do is when the button is clicked, it opens the microprocessor page like : microprocessor.ddns.net/?update=1.
How can i make the www.domain.com send the "?update=1" to the microprocessor without the user have to see the microprocessor page.
The main purpose is to hide the microprocessor address so it's harder to be hacked..
Thanks for the help!
Hello I do not know anything about php this is the code <?php echo do_shortcode( “[covid19 country=‘Pakistan’ title=‘Pakistan’]” ); echo do_shortcode( “[covid19 country=‘India’ title=‘India’]” ); echo do_shortcode( “[covid19]” ); ?>
can anyone help me to center the numbers of cases death recovered:
Hello ..Im so glad to be here with u all I am a novice in the use of this php/sql and I have to complete my project..but Unfortunately, I got this problem and I couldent figure out where the mistake lies.. please any advice here u my code Code: [Select] <html> <body background="3d-background-blue.jpg"> <?php $x1=$_POST['fname']; $x2=$_POST['age']; $x3=$_POST['password']; $x4=$_POST['email']; $x5=$_POST['yourtype']; mysql_connect("localhost","root","")or die("there is a problem "); mysql_select_db("order1")or die("no DB"); // check if the username is taken $check = "select id from users where fname = '$x1'"; $qry = mysql_query($check) or die ("Could not match data because ".mysql_error()); $num_rows = mysql_num_rows($qry); if ($num_rows != 0) { echo "Sorry, there the username $x1 is already taken. "; echo "Try again"; echo "<a href= iinterface.html >home</a>"; echo "<br>"; exit(); } else { // insert the data $query="insert into users (fname,age,password,email,type) values('$x1','$x2','$x3','$x4','$x5')"; $result=mysql_query($query); if($result){ echo "thanks for registering $x1 " ;echo "<br>"; echo "the date of registeration is "; Echo gmdate ("D, d M Y H:i:s"); echo "<br>"; echo "<br>"; echo "<a href=iinterface.html > back to main </a>"; echo "<br>"; } else {echo"insertion error"; } ?> </body> </html> the massege of error is : Quote Parse error: parse error in insert2.php on line 45 I have this Shopping cart that allows for the creation of products with product sizes and so if a customer purchases a shirt which regular price is $10 but he/she chooses a large size which is marked @ $12 then of course the shopping cart then charges $12 - then the customer receives a purchase notification email defining the purchase of the $12 size large shirt, and thats all fine except that currently the notification email defines the shirt with $0.00 price in a row and in another row it defines the shirt size with the $12.00 price. So it basically defines the product twice, and i don't want it to do that. I want the product price and size to all be included in the same row. Attached is the .php file that needs the modification. I had a developer tell me that it could not be done. Can someone please have a look at this file and tell me if its true that what I want cannot be done! - all i want to do is merge those two rows together. I've attached the php that is responsible for writing the tables containing the purchased items.
Attached Files
orderSaveAjax.php 25.56KB
7 downloads Looking for someone to create a client side script to meet the following requirements:
Client side
Login to multiple affiliate accounts of mine (around 30)
Gather information required
log out
Display results client side in a nice and organized fashion
Please PM me or e-mail me with approximate price given the requirements above along with your experience.
Payment will be through paypal.
e-mail a3lankee@gmail.com
heres the code... <?php mysql_connect("localhost","peter","tizer") or die("Error: ".mysqlerror()); mysql_select_db("matquant"); //replace TestTable with the name of your table //also in a real app you would get the id dynamically $idtochange=$_POST['idtochange']; $sql="select * from `quantites` where id = $idtochange"; $query=mysql_query($sql); while ($row=mysql_fetch_array($query)){ $id = $row['id']; $material = $row['material']; $quantity = $row['quantity']; $unit = $row['unit']; //we will echo these into the proper fields } mysql_free_result($query); ?> <html> <head> <title>Edit material list</title> <link href="css/quant1.css" rel="stylesheet" type="text/css"> </head> <body> <div id="leftcol"> <form "method="post"> <p><br/> <input type="text"value="1" name="idtochange" > <p> <input type="submit"value="submit changes"/> </form> <form action="changequan.php"method="post"> <p>Material Id currently active<br/> <input type="text"value="<?php echo $id;?>" name="id" disabled/> </p> <p> Enter new material name: </p> <input type="text"value="<?php echo $material;?>" name="material"/> <br/> change quantity: <input type="text"value="<?php echo $quantity;?>" name="quantity"/> <br/> unit of mesurement for quantity<br/> <input type="text"value="<?php echo $unit;?>" name="unit"/> <br/> </p> <input type="submit"value="submit changes"/> </form> </div> <div id="rightcol"><?php // make connection mysql_connect ("localhost", "peter", "tizer") or die ('I cannot connect to the database becuase: ' . mysql_error()); mysql_select_db ("matquant"); // build query $query = mysql_query("SELECT * FROM `quantites` ORDER BY `id` ASC"); // display results while ($row = mysql_fetch_array($query)) { echo "<br /> ..... " .$row ['id']. " ....... " .$row ['material']. " ...... " .$row['quantity']. " ...... " .$row['unit']. "<br />";} echo mysql_error(); ?> <a href="index.html">Home </a> <p> <a href="quanform.php">Insert new material and quantity form</a></p></div> </body> </html> I'm struggling with php. Any help anyone can give would be appreciated. Sorry this page is not available or has been accessed in error An error occurred in script 'C:\xampp\htdocs\public_html\login\plugins\delete_product.php' on line 45: Undefined variable: id Date/Time: 8-24-2010 00:50:10 Array ( [GLOBALS] => Array *RECURSION* [_POST] => Array ( ) [_GET] => Array ( [id] => 2 ) <?php # Script 9.2 - delete_product.php // This page is for deleting a album. require_once ('../includes/config.inc.php'); // Check for a valid product ID, through GET or POST: if ( (isset($id)) && (is_numeric($id)) ) { // From editproducts.php $id = $_GET['id']; } elseif ( (isset($_POST['id'])) && (is_numeric($_POST['id'])) ) { // Form submission. $id = $_POST['id']; } else { echo '<p class="error">Sorry this page is not available or has been accessed in error</p>'; } echo $id; require_once(MYSQL); // Check if the form has been submitted: if (isset($_POST['submitted'])) { if ($_POST['sure'] == 'Yes') { // Delete the record. // Make the query: $q = "DELETE FROM products WHERE product_id='$id' LIMIT 1"; $r = @mysqli_query ($dbc, $q); if (mysqli_affected_rows($dbc) == 1) { // If it ran OK. // Print a message: echo '<p>The Product has been deleted.</p>'; } else { // If the query did not run OK. echo '<p class="error">The Product could not be deleted due to a system error.</p>'; // Public message. echo '<p>' . mysqli_error($dbc) . '<br />Query: ' . $q . '</p>'; // Debugging message. } // Make the query: $q = "DELETE FROM photos WHERE product_id='$id'"; $r = @mysqli_query ($dbc, $q); } else { // No confirmation of deletion. echo '<p>The Product has NOT been deleted.</p>'; } } else { // Show the form. // Retrieve the albums information: $q = "SELECT name FROM products WHERE product_id='$id' Limit 1"; $r = @mysqli_query ($dbc, $q); if (mysqli_num_rows($r) == 1) { // Valid user ID, show the form. // Get the user's information: $row = mysqli_fetch_array ($r, MYSQLI_NUM); $form = $_SERVER['PHP_SELF']; // Create the form: echo '<form action="' . $form . '" method="post"> <h1>Delete ' . $row[0] . '?</h1> <p>Are you sure you want to delete ' . $row[0] . '?<br /> <p><b>Warning if you delete this album all content inside of it will be losed!</b><br /> <input type="radio" name="sure" value="Yes" /> Yes <input type="radio" name="sure" value="No" checked="checked" /> No</p> <p><input type="submit" name="submit" value="Submit" /></p> <input type="hidden" name="submitted" value="TRUE" /> <input type="hidden" name="id" value="' . $id . '" /> </form>'; } } mysqli_close($dbc); ?> Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\parkhall\quantities.php on line 21 This is the error message. This is the code. simple array query to display contents of table and I cant see where i have made the mistake. hopefully someone can help. <?php mysql_connect ("localhost", "******", "*****") or die ('I cannot connect to the database becuase: ' . mysql_error()); mysql_select_db ("matquant"); $query = mysql_query("SELECT * FROM quantities"); while ($row = mysql_fetch_array($query)) { //line referred to in error message echo "<br /> ID: " .$row ['id']. " material : " .$row ['material']. "quantity:" .$row['quantity']. "<br />";} ?> Please point out the probably glaring error. I'm relatively new to this and I am really not finding php easy to learn. Hello; I'm new to php and to programming in general, but i want to do a little app to help a process on my work, you know, just being pro-active (hoping it doesnt come and byte me in the a** in the future, you know.. "you did it now our life depend on it and you fix it right now!!). So.. I have this really simple piece of code, but its not working and i cant figure out why. I'm trying to use echo to print a couple of link but when i put in the second line everything messes up. the code is: (note the "test lines" i just added them to try to understand what is doing) <?php $client = $_GET['client']; echo "Client " . $client . "<br />"; echo "test line 1"; echo "<a href=\"link1.php?client=".$client.">Link 1</a><br>"; echo "test line 2"; echo "test line 3"; echo "<a href=\"link2.php?client=".$client.">Link 2</a><br>"; ?> When i open the page on firefox i get: === Client myclient test line 1Link 2 === Where the link (underlined) text is "Link 2" but the it points to something totally different (a mix of the rest of the code). If I remove the second link, like he <?php $client = $_GET['client']; echo "Client " . $client . "<br />"; echo "test line 1"; echo "<a href=\"link1.php?client=".$client.">Link 1</a><br>"; echo "test line 2"; echo "test line 3"; ?> I get what i'd expect: === Client myclient test line 1Link 1 test line 2test line 3 === Im totally lost, im not sure if its a browser issue, a server issue or just the code My setup: WAMP 2.1 (Apache) I'm opening the "site" with Firefox 3.6.15 and IE6, both show the same result Windows XP (dont know if it matters) The file is saved as php tried changing "echo" with "print", same result Umm.. thats it... Please let me know if you need any more info Thanks everyone edit: typo on subject edit: yet another typo |
|||||||