|
PHP - Question About Php Inside Html Code.
Hello, people!
I was watching some php tutorials in youtube and, in a video, the guy was showing how put php script inside html code. I would like to know why in the following code he didn't use only one php script?
1- Code used in the video:
<html> <body> <?php $color = $_GET['clr']; ?> <b><font color="<?php echo $color;?>">This is a test.</font></b> </body> </html>2- Modified code by me to test with one script: <html> <body> <?php $color = $_GET['clr']; echo "<b><font color=\"$color\"> This is a test. </font></b>"; ?> </body> </html>Is his code more correct(with two scripts)? Why? Similar TutorialsI have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=316454.0 The PHP code sends me an email from the server, but the user input is empty or "blank". I only receive: "From: \ Email: \ Subject: \ Message: " and that's it. How do I fix my PHP and/or HTML code to receive user input from the form? Attached is my existing HTML and PHP code that doesn't send me any "user input" from the form. Thanks to anyone who can help!!
The org variable holds the value of the folder name. The problem is that the header is sending out ".$org." and not the actual value of $org. Example output url: http://127.0.0.1/application/".$org."/display/trackingboard.php I want this url if the value is test: http://127.0.0.1/application/test/display/trackingboard.php Thanks! Code: [Select] $org = "test"; header('Location: ../application/".$org."/display/trackingboard.php'); Cant get it to work!! here is the code , how do i fix this? Code: [Select] <script type="text/javascript"> function popup(var) { alert(var); } </script> <?php $calendar.= "<td class='calendar-day'><div style='position:relative;height:100px;' onclick='popup('hello')'>"; ?> hi i have this form that runs with ASP. [this is a must since i didn't create that form] and must run in the wordpress header.php... is this even possible? How can I insert PHP code inside MySQL DB? I have mixed HTML and PHP code like this: <div class="rightpanel"> <div class="hltred"> <div class="hlthead"> <p><?php echo $pages->naslov; ?></p> </div> <div class="hltcontent"> <p> ovde treba da ide loop sa svi podlinkovi za taj glavni koji je aktivan</p> </div> </div> </div>, but when i insert it into DB i get this code (I use htmlspecialchars function to store): <div class="rightpanel"> <div class="hltred"> <div class="hlthead"> <p> <!--?php echo $pages---> naslov; ?></p> </div> <div class="hltcontent"> <p> ovde treba da ide loop sa svi podlinkovi za taj glavni koji je aktivan</p> </div> </div> </div> This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=348601.0 Hi all, I am trying to replicate/modify this checkbox for a different script and I don't understand what the php code is doing in this form? Could someone explain to me whats happening by including that php code in the form? Code: [Select] <input type="checkbox" onclick="showArchive()" NAME="showarchive" id="showarchive" <?php echo ($showarchive ? 'checked="checked"' : '');?> /> Thanks! Hello, I have a php code within a javascript. The javascript gets invoked on button click. The php code withing javascript never gets executed. I don't face the same problem in other browsers. Any help is much appreciated! Regards, Cole Hi, I have this curl string required by an email verification vendor I use. Inside my php file I wish to run it. Apparently there is a problem with the syntax as I’m getting the following error in the browser: ”Parse error: syntax error, unexpected '--' (T_DEC) in /var/www/html/wp-content/plugins/dw_functionality_plugin/dw_functionality_plugin.phpon line 398 Here is the code string:
< > any help much appreciated! Edited March 23 by dwest100hi silly little question but if I want to bracket something inside PHP how do I do it eg my code is Code: [Select] <th class="alignright"><?php echo $ass_descrip; ?> (<?php echo $ass_accro ; ?>) <?php echo FindTypeName ($type_id); ?></th> printing out British Eventing (BE) But the brackets at the moment are outside the PHP I want to put a conditional on it and include the brackets inside my conditional statement.? Hi there i was wondering how i would go about using html tags inside the php tags so i could put data from a database into a textarea / text input i had a go but had no such luck with this attempt: <?php echo "Title:<br>"; echo "<input type="text" name="title" value="$row['Title']">"; ?> the code above is to give you an idea of what i want to do, if you can point me to any guides or show me how it will be greatly appriciated Thanks, Blink359 How can this be written in PHP? Code: [Select] echo '<IMG alt="" src=".$row['id']/thumb.png">'; I'm trying to create a Facebook fangate, and I want an imagemap to come up to fans, but a static image to come up for non-fans. Here's the code. Someone please tell me what I'm doing wrong. I've tried it 3 different ways. (I searched Google and this forum before posting...nothing I found worked for me). While I've removed identifying information, I have tested and made sure the bitmapped image works properly (can call it through facebook on its own) as well as the regular image. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html lang="en" xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <link rel="stylesheet" type="text/css" href="style.css" /> <style type="text/css"> body { width:520px; margin:0; padding:0; border:0; }</style> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> </head> <body> <? require 'facebook.php'; $app_id = "XXXXXXXXX"; $app_secret = "XXXXXXXXXXX"; $facebook = new Facebook(array( 'appId' => $app_id, 'secret' => $app_secret, 'cookie' => true )); $signed_request = $facebook->getSignedRequest(); if ($like_status) { ?> <div><img src="http://xxxxxx.com/facebook/FBnavbar.png" alt="" usemap="#FB Nav Bar" style="border-style: none" /></div> <div> <map id="FB Nav Bar" name="FB Nav Bar"> <area shape="rect" alt="About xxxxxx Social Media" coords="6,21,80,42" href="http://www.facebook.com/xxxxxxx?sk=info" title="About xxxxxx Social Media" /> <area shape="rect" alt="xxxxxx Blog" coords="222,24,276,38" href="http://www.facebook.com/xxxxxxxsk=app_?????" title="xxxxxx Blog" /> <area shape="rect" alt="xxxxxx Social Media" coords="297,23,391,39" href="" title="xxxxxx Social Media" /> <area shape="rect" alt="Contact xxxxxx Social Media" coords="409,23,508,39" href="../../../contact/" title="Contactxxxxxx Social Media" /> <area shape="rect" alt="Subscribe to our RSS feed" coords="443,1,459,14" href="http://feedburner.com/xxxxx" title="Subscribe to our RSS feed" /> <area shape="rect" alt="Share us on delicious" coords="463,0,478,18" href="http://www.delicious.com/share?new=1&hash=e16eda577a70c83c0dfa2c8c29e52d24&key=tnNrKLSea55V6Tkd2ze9ujDWVOs-&title=xxxxxxx%2xxxxp%20Reputation%20Management&url=http%3A%2F%2Fxxxxxxx%2F&jump=%2Furl%2Fe16eda577a70c83c0dfa2c8c29e52d24" title="Share us on delicious" /> <area shape="rect" alt="Add us on LinkedIn" coords="485,3,499,18" href="http://www.linkedin.com/company/xxxxxx" title="Add us on LinkedIn" /> <area shape="rect" alt="Follow our Director on Twitter" coords="503,1,519,17" href="http://www.twitter.com/xxxxxxx" title="Follow our Director on Twitter" /> <area shape="rect" alt="Learn about xxxxxxxx's Services" coords="98,21,202,40" href="http://www.facebook.com/xxxxxx?sk=app_?????" title="Learn about xxxxxxx's Services" /> <area shape="default" nohref="nohref" alt="" /></map></div> <?php } else { ?> <img src="http://xxxxx.com/facebook/landing/SRfanpage3.png" /> <?php } ?> </body> </html> I'm very new at this (not a php coder, just grabbed some code from a tutorial and am trying to make it work), so please be gentle. Thanks for your help in advance. Hey guys! Im trying to setup an IF statement on my home page. Its purpose is to show EITHER a login form and state your not logged in if it cannot find a stored cookie OR if it does find a stored cookie it will NOT show the HTML form and state you are logged in. I have it mostly working apart from the fact Im not sure how to insert a HTML form into PHP IF statement and make it work. Since I dont want the user to see the login form when they are already logged in. Here is a link to the php script: http://pastebin.com/aenq4gbE Here is link to the live page: http://jfbsystems.co.uk/secure Any help or ideas would be much appreciated! JellyFishBoy I'm redoing my login script using functions and a basic switch function checking against a $_GET variable (hope you guys know what I'm talking about). What I want to do is create two functions: 1 that displays the login form and 1 that processes the information The form tag would look like this: <form action=\"<?php $_SERVER['PHP_SELF']?>?action=process\" method=\"post\"> </form> Here's my switch statement: Code: [Select] <?php //**************************************** //****************Action****************** //**************************************** switch ($_GET["action"]) { default: case "index": if (!$_SESSION["member"]) { if (!$timeout) { display_form(); } else { echo $timeout_error; } } else { echo "You are already logged in."; } break; case "process": if (!$_SESSION["member"]) { if (!$timeout) { process_form(); } else { echo $timeout_error; } } else { echo "You are already logged in."; } break; } ?> This runs as soon as "login.php" loads. It'll automatically run the commands under case "default" and "index". It'll first check to see if the member's logged in. If not, it'll then check to see if "$timeout" is true ($timeout becomes true if the member has attempted to login 5 times and failed). If not, it'll display the login form, by running "display_form()". Once the form has been filled and submitted, the commands under case "process" will be performed. Again it will first check to see if the member's logged in. If not, it'll check to see if "$timeout" is true. If not, it'll start validating the forms. For the validation, I've created a variable called "$errors_found", and scripted one if statement checking to see if the email and password exist. If so, the variables "$rm_field_un" and "$rm_field_pw" become true, as well as "$errors_found". So, back to submission of the form... If "$errors_found" is true, display the form (when the form is displayed, there will be an if statement within that says "<?php if ($rm_field_un) { echo "Username is wrong."; } ?>", which will be displayed right underneath the username field and label. Same with the password elements). If "$errors_found" is not true, go ahead and register the member. Now, here's where I need help, because I'm really confused as to how to accomplish this. The "display_form()" function will contain a single variable called "$login_form". It will contain a value of the HTML constructed login form, and the function will return the variable. Remember how I stated in the third paragraph up that I will have <php> statements within the form which would display errors if necessary? Well, how do I put those if statements within the HTML, which is contained within the variable? If that last question confuses you, allow me to present you with an instance: Code: [Select] <?php function display_form() { $login_form = " <form name=\"login_form\" method=\"post\" action=\"<?php $_SERVER['PHP_SELF']?>?action=process\"> Username: <input type=\"text\"> <?php if ($rm_field_un) { echo "Username is wrong"; } ?> "; return $login_form; } ?> See what I mean? This code confuses me ALOT. I'm not sure if the <php> tags are needed as it is already contained within existing ones, or what. Can somebody please help me out? Any and all help is much appreciated. =D I am having trouble implementing PHP inside a HTML attribute. Every time I try to fix it, I seem to make things worse. Can someone please help me: <INPUT name="id" type="text" value=""<?php echo "$row['id']"; ?>""> This topic has been moved to CSS Help. http://www.phpfreaks.com/forums/index.php?topic=351491.0 Hey guys,
I'm facing an issue compiling the above stack from a source code inside lxc using centos 6.5 as a domain OS.
[lxc@lxc1 httpd-2.4.9]$ ./configure --with-included-apr checking for chosen layout... Apache checking for working mkdir -p... yes checking for grep that handles long lines and -e... /bin/grep checking for egrep... /bin/grep -E checking build system type... x86_64-unknown-linux-gnu checking host system type... x86_64-unknown-linux-gnu checking target system type... x86_64-unknown-linux-gnu configu configu Configuring Apache Portable Runtime library... configu configuring package in srclib/apr now checking build system type... x86_64-unknown-linux-gnu checking host system type... x86_64-unknown-linux-gnu checking target system type... x86_64-unknown-linux-gnu Configuring APR library Platform: x86_64-unknown-linux-gnu checking for working mkdir -p... yes APR Version: 1.5.1 checking for chosen layout... apr checking for gcc... gcc checking whether the C compiler works... yes checking for C compiler default output file name... a.out checking for suffix of executables... checking whether we are cross compiling... configu error: in `/home/lxc/httpd-2.4.9/srclib/apr': configu error: cannot run C compiled programs. If you meant to cross compile, use `--host'. See `config.log' for more details configure failed for srclib/apr This problem has been detected by me when I replaced my desktop machine with new one and installed a centOS again. This such a problem never happened before using my old machine with the same version of OS and libvirt. Just to be clear, a new selinux policy into a "domain machine" has been created to be able to use the "dbus daemon" to all containers and if I try to complile this stack from source using the "domain os" this problem never happens at all. All "Development tools" is installed to this particular container, in case someone asks me why I get the following error message - "configu error: cannot run C compiled programs" Any ideas? Edited by jazzman1, 08 June 2014 - 01:37 PM. |
|||||||