PHP - How To Dynamically Determine Unknown File Extension From File In Web Folder
I have a page using forms to help build listing templates for eBay. I have a folder where I have hundreds of logos stored. I know the logo names but not their extensions. . . . I have to test each potential (jpg, jpeg, gif, png, etc.) until I guess right. Here is an example code for the web form:
<form action="extension_test2.php" method="post">
<p>Logo: <input name="e" value="" type="text" size="15" maxlength="30" /><p> <input name="Submit" type="Submit"/> </form> and the form's result: <? $e =$_POST['e']; if(!empty($e)) { echo '<img src="http://www.gbamedica...ebayimg/logos/'.$e.'">'; }; ?> Here is a link to the example: http://www.gbamedica...ension_test.php Use "olympus.jpg" for test. I am looking for code that can determine the file type and dynamically add the extension. Can it be done? Similar TutorialsI want to remove the file extension - I have done that.
I want to remove the trailing slash. - I have done that
But I cannot for the life of me get the the regular page to display instead of the folder which show a tree of files within it.
site.com/website-tips.php site.com/website-tips/increase speed.php The extension drops off and the trailing slash too but when I navgate back through the vreadcrumb to website-tips (without php in html code) it gives me the folder and shows the file tree (files within website tips folder) How would I solve this? right now if I access the website-tips.php file, it shows the directory and its interior pages Pls hlp out. Folks,
I am building a membership script for 21 months now!!! That long!!!
Not pasting the whole script as really long. Would do your head in. if($_SERVER["REQUEST_METHOD"] == "POST") { if(!isset($_FILES["id_verification_video_file"])) //REtype { echo "no isset"; } else { $id_verification_video_file = $_FILES['id_verification_video_file']; //REtype //Feed Id Video Verification File Upload Directory Path. $directory_path = "uploads/videos/id_verifications/"; //Make Directory under $user in 'uploads/videos/id_verifications' Folder. if(!is_dir("$directory_path" . "$user")) { $mode = "0777"; mkdir("$directory_path" . "$user", "$mode", TRUE); //Thanks Requinix for my "$mode" typo hint. } //Grab Uploading File details. $Errors = Array(); //SHOULD I KEEP THIS LINE OR NOT ? $file_name = $_FILES["id_verification_video_file"]["name"]; $file_tmp = $_FILES["id_verification_video_file"]["tmp_name"]; $file_type = $_FILES["id_verification_video_file"]["type"]; $file_size = $_FILES["id_verification_video_file"]["size"]; $file_error = $_FILES['id_verification_video_file']['error']; //Grab File Extension details. $file_extension = pathinfo($file_name, PATHINFO_EXTENSION); if(file_exists('$directory_path' . '$user/' . '$file_name')) { $Errors[] = "Error: You have already uploaded a video file to verify your ID!"; exit(); } else { //Feed allowed File Extension(s). $allowed_file_extensions = array("mp4" => "video/mp4","wmv" => "video/wmv"); //Feed allowed file size. $max_file_size_allowed_in_bytes = 1024*1024*100; //Allowed limit: 100MB. $max_file_size_allowed_in_kilobytes = 1024*100; $max_file_size_allowed_in_megabytes = 100; $max_file_size_allowed = "$max_file_size_allowed_in_bytes"; //RETYPE //Verify File Extension. if(!array_key_exists($file_extension,$allowed_file_extensions)) die("Error: Select a valid video file format. Select an MP4 or WAV file."); //Verify MIME Type of the file. elseif(!in_array($file_type,$allowed_file_extensions)) { echo "Error:<font size ='5' font color ='red'><b>There was a problem uploading your video file $file_name! Make sure your file is an MP4 or a WAV file. You may try again now.</b></color></size>"; //THANKS TO REQUINIX FOR BRINNGING IT TO MY ATTENTION I AM STILL PROCESSING THE SCRIPT AFTER THIS LINE WHEN I SHOULD NOT. exit(); } //Verify File Size. Allowed Max Limit: 100MB. elseif($file_size>$max_file_size_allowed) die("Error: Your Video File Size is larger than the allowed limit of: $max_file_size_allowed_in_megabytes."); //Fixed variable name typo. Thanks to Requinix & Simon JM. //Move uploaded File to newly created directory on the server. move_uploaded_file("file_tmp","$directory_path" . "$user/" . "$file_name"); //Notify user their File was uploaded successfully. echo "<font size ='5' font color ='red'><b>Your Video File \"$file_name\" has been uploaded successfully! You will get notified once your Id has been verified successfully.</b></color></size>";
Can you spot my coding error ? My uploader allows the following file formats: jpg gif png I tested that if someone was to name a file configure.php.jpg, my uploader allows it to upload I want to do a check to see if the user has 2 extensions, and if so it will not allow them to upload. I was thinking of just checking if the file name has two "." (dots) in the name. What function could I use to do this? Or .. is there a better way? I can determine which radio button is selected for each file upload prompt because I have a name and a value. So the array name=image can have one of three values for each file upload prompt. Is there a way to determine which of the three file upload prompts was loaded (clicking browse & select image) with an image and which was not? There doesn't seem to be a value like there is with radio buttons. I want to be able to replace an already uploaded image with another. Thanks. <input type='radio' name='image[image0]' value='keep' checked='checked'/> <input type='radio' name='image[image0]' value='delete' /> <input type='radio' name='image[image0]' value='replace' /> <input type="file" name="image[]" /> <input type='radio' name='image[image1]' value='keep' checked='checked'/> <input type='radio' name='image[image1]' value='delete' /> <input type='radio' name='image[image1]' value='replace' /> <input type="file" name="image[]" /> <input type='radio' name='image[image2]' value='keep' checked='checked'/> <input type='radio' name='image[image2]' value='delete' /> <input type='radio' name='image[image2]' value='replace' /> <input type="file" name="image[]" /> if (isset($_POST['submitted']) && ($image = $_POST['image'])) { foreach($image as $imageKey => $imageValue) { if ($imageValue == 'keep') { do this } } } When I upload new files, their file name is stored into my database. I have been told that a couple of the file downloads weren't working. Upon further investigation I figured out that the file the person wanted to download was nowhere to be seen in my downloads directory. How can I determine if a file exists in my directory? I assume I can somehow use the location that is stored inside my database (ex: myfile.pdf) and compare that with what's in the folder. I have a variable that holds the name of a File... Code: [Select] $origFileName = $_FILES['userPhoto']['name']; What is the best way to just get the File Name from this? Debbie Hi, how do I extract just file extension? eg: $file="hello.xml"; $fileExt=??? print $fileExt; Any help much appreciated! Hi Guys, I am having some issues in trying to return a file extension in a php upload script, here is what I am trying to do, no extension is added when a file is uploaded. $p_id = $row['p_id']; $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = $_SERVER['DOCUMENT_ROOT'] . $_REQUEST['folder'] . '/'; $filename = $HTTP_POST_FILES['Filedata']['name']; $ext = end(explode('.', $filename)); $nfilename = $p_id . $ext; $targetFile = str_replace('//','/',$targetPath) . $nfilename; This code uploads a file to the server then renames it to the next id number from the database and adds the extension .jpg to the file name. index.php - I need .jpg to be a variable that will append .gif if it's a gif file or .png if it's a png file. Currently, if the file is a .jpg, .gif, or .png, the files are given the extension .jpg. <?php copy($_FILES['banner']['tmp_name']['file'], './banners/'.$photo_id.'.jpg'); ?> _photo.php - I want to replace .jpg in this code with the variable from above. <a href="<?php echo safe_output($photo['web_url']); ?>" target="_blank" class="bannerImg"><img src="banners/<?php echo $photo['id']; ?>.jpg"/></a> Need some help with this script. I'm looking to limit the type of file you can upload to my server the script uploads ok but i when i try t view the uploaded file but i get an error cant find file extension for this file what am i doing wrong as i'm very new to php . Thank for your help in advance Code: [Select] <?php $allowedExtensions = array("jpg","jpeg","gif","png","bmp"); foreach ($_FILES as $image) { if ($image['tmp_name'] > '') { if (!in_array(end(explode(".", strtolower($image['name']))), $allowedExtensions)) { die($image['name'].' is an invalid file type!<br/>'. '<a href="javascript:history.go(-1);">'. '<< Go Back</a>'); } } } $target = "testimages/"; $target = $target . basename( $_FILES['image']['name']); // $company=$_POST['company']; $image=($_FILES['image']['name']); mysql_connect("localhost", "user", "pass") or die(mysql_error()) ; mysql_select_db("testupload") or die(mysql_error()) ; mysql_query("INSERT INTO `table` (company, image) VALUES ('$company', '$image')") ; if(move_uploaded_file($_FILES['image']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { echo "Sorry, there was a problem uploading your file."; } ?> Help me I am getting Notice: Undefined index: extension I'm trying to determine why when I select Upload, on the html page I see a message "My extension is:" only, instead of My extension is: webM" for example.Here's the code, I look forward to any assistance: <?php foreach (array('video', 'audio') as $type) { if (isset($_FILES["${type}-blob"])) { $fileName = $_POST["${type}-filename"]; $uploadDirectory = 'uploads/' . $fileName; // make sure that one can upload only allowed audio/video files $allowed = array( 'webm', 'wav', 'mp4', 'mov' ); $extension = pathinfo($filePath, PATHINFO_EXTENSION); die("My extension is: " . $extension); if (!$extension || empty($extension) || !in_array($extension, $allowed)) { echo 'Invalid file extension: '.$extension; return; } if (!move_uploaded_file($_FILES["${type}-blob"]["tmp_name"], $uploadDirectory)) { echo (" problem moving uploaded file"); } } } ?>
I'm not fluent in php, but I think this should be an easy fix for someone who is. Basically, I have a Wordpress theme that auto generates the images from posts in each slide of the feature slider on the homepage. Goal: for php to remove the css border around the image if it is a .png file Purpose: I want borders on photos in the feature slider, but no borders on images with transparent backgrounds... like free floating logos. So I figured I could use an if/else statement to determine if the file has a .png extension... if it does then it inserts the html style to remove the border. Here is the original code from the theme where it gets the image Code: [Select] <a href="<?php echo($arr[$i]["permalink"]); ?>" title="<?php printf(__('Permanent Link to %s', 'TheCorporation'), $arr[$i]["fulltitle"]) ?>"> <?php print_thumbnail($arr[$i]["thumb"], $arr[$i]["use_timthumb"], $arr[$i]["fulltitle"] , $width, $height, 'thumb'); ?> </a> Here is what I was trying to get to work.. I tried taking the variable for $file from the code I assumed was populating the image path Code: [Select] <?php $file = `print_thumbnail($arr[$i]["thumb"]`; $ext = `pathinfo($file, PATHINFO_EXTENSION)`; ?> <a <?php if($ext == ".png") echo ?>style="border:none 0px !important;" <?php ; else null; ?> href="<?php echo($arr[$i]["permalink"]); ?>" title="<?php printf(__('Permanent Link to %s', 'TheCorporation'), $arr[$i]["fulltitle"]) ?>"> <?php print_thumbnail($arr[$i]["thumb"], $arr[$i]["use_timthumb"], $arr[$i]["fulltitle"] , $width, $height, 'thumb'); ?> </a> Any help would be appreciated. Thanks. Hello,
I have managed to find, retrieve and save a file using CURL. But I am having to hard code the file extension, is there a way to find the file extension automatically? (it seems the file extension isn't within the download URL)
(also, is there a way of getting the file name so I can save it as the same filename - that would be great)
Thanks for your help,
Stu
p.s. I've tried the pathinfo($url) function, but that gets information out of the download URL rather than the download file.
$url="http://webmail.WEBSITE.com/src/redirect.php"; $cookie="cookie.txt"; $postdata = "login_username=USERNAME&secretkey=PASSWORD&js_autodetect_results=0&just_logged_in=1"; # get the cookie $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 0); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_COOKIEJAR, $cookie); curl_setopt ($ch, CURLOPT_REFERER, $url); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); curl_close($ch); $ch = curl_init(); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie); //read cookies from here curl_setopt($ch, CURLOPT_URL, "http://webmail.WEBSITE.com/src/right_main.php"); curl_setopt($ch, CURLOPT_HEADER, 0); $result = curl_exec($ch); curl_close($ch); # download file $source = "http://webmail.WEBSITE.com/src/download.php?mailbox=INBOX&passed_id=6475&startMessage=1&override_type0=text&override_type1=html&ent_id=2&absolute_dl=true"; $ch = curl_init(); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie); //read cookies from here curl_setopt($ch, CURLOPT_URL, $source); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSLVERSION,3); $data = curl_exec ($ch); $error = curl_error($ch); curl_close ($ch); # !!! The line below needs to be automated !!! $destination = "./files/test.html"; $file = fopen($destination, "w+"); fputs($file, $data); fclose($file); Edited by stubarny, 17 June 2014 - 04:46 PM. Hi Gusy, Would be great if you can help me to sort this out and Thank you in advance. I would like to hide all files with "swf" extension from my file and folder directory, I know how to hide one specific file but not ll files with same extension. For example: *.swf. Here is my code which is work for full file names but not all files with same extension. <?php $filearray = array(); if ($handle = opendir('.')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != ".." && $file != ".htaccess" && $file != "index.php" && $file != "style.css" && $file != "Images" && $file != "*.swf" && $file != "index.html") { $filearray[] = $file; } } closedir($handle); natcasesort($filearray); foreach($filearray as $f) { $thelist .= '<img width="15" height="15" alt="[DIR]" src="/Images/folder.jpg"> <a href="'.$f.'">'.$f.'</a> '; } } ?> As you can see I have "&& $file != "*.swf"" which need your advise in this part. I just want people not seeing all .SWF files in the index directory of my server. I have already have index.html inside my folder as well which has been hided because of "$file != "index.html"". But this is not hiding my ".SWF" files. Many Thanks. Hello guys i have been trying to find an alternative file function to read multiple files into an array. My aim is to preg_replace every file in directory starting with Audit_Report with the font colours...i have been googling it for like 2 hours and the closest answer i can get to is using the glob() function but it doesn't work for me still. I would like you guys to give me suggestions if you can..thanks!! <?php $file = "Audit_Report.(SEAN).(192.168.199.129).txt"; $lines = file($file); foreach ($lines as $line) { $string = $line; $patterns = array(); $patterns[0] = '/\bPass\b/'; $patterns[1] = '/\bFail\b/'; $patterns[2]='/\b============ Major Audit and Account Policies============ \b/'; $replacements = array(); $replacements[1] = "<font color=red>Fail</font>"; $replacements[0] = "<font color=green>Pass</font>"; $replacements[2] = "<br><b>==== Major Audit and Account Policies====</b>"; ksort($patterns); ksort($replacements); $a = preg_replace($patterns, $replacements, $string); echo "$a<br />\n"; file_put_contents(basename($file, substr($file, strpos($file, '.'))) . ".html","$a<br />\n", FILE_APPEND) or die("Cannot write file"); } ?> This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=308625.0 I upload an image and put every information inside $_SESSION['tmp'] and $_SESSION['path'] then once user click on button then i use move_uploaded_file($_SESSION['tmp'],$_SESSION['path']) but file uploaded not appeared in my upload folder, and again i try to echo everything but all information still kept well in $_SESSION is there something missing here? thanks The root directory:
header.php
stylesheet.css
In the following example I am trying to include the header.php file in a sub folder.
When I include the header.php like in the following example then the stylesheet.css file will not work anymo
<?php include("../header.php"); ?>The stylesheet.css file is included in the head tags of the header.php file. Is the above example the right way to do it? If yes, how can I do it so the stylesheet.css file will work too. Hello all, i am go9090go. Today i made a domains for a jar file people can upload from my website. I made this to make the jar file close source and its easy to update. Now i made a java classloader and everything i made works. The classloader call a php document with the password and username. The pass and name will be checked inside a databse and if its inside i use header() to load the jar file. But when i just go to my main domain i get the index of the site and people can easly download the jar file without have to walk thru the php pass checker. So i want to place the jar file inside a protected folder,and i want that only way you get acces to this jar is by the php file. How can i get a file from a protected folder? here is the php used when the jar file is not inside a protected folder: <?php $DBName = "name";//name database $DBUser = "name";//user $DBPassword = "pass"; //passs $DBHost = "host"; //might be different mysql_connect($DBHost, $DBUser, $DBPassword); mysql_select_db($DBName); $username = $_GET['username']; $password = $_GET['password']; $IP = $_SERVER['REMOTE_ADDR']; $string = "Java"; $pos = strpos($agent, $string); if (!strpos($_SERVER['HTTP_USER_AGENT'], "Java")) { echo("Your Auth has been banned for trying to breach security."); //mysql_query("delete from users where username='$username'"); exit(); } $query = "select * from users where name='$username' and pass='$password'"; mysql_query($query); $num = mysql_affected_rows(); if ($num > 0) { header('Location:script/Script.jar'); } ?> now i want to use the header to a file inside a folder that is protected : so how can i make the header() methode to open script.jar inside a protected folder. The folder haves name and pass: blabla,balbla for exempel thanks for help |