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PHP - Create Computer Client Unique Identification For Fraud
Hello Good day,
I am have a project for company. Can you please give me advice on how will I going to determine each computer assigned to each employee.
I have my own working unit (PC), of course that i used to login on our company web site. But when someone try to log in on our web site using their own account on my working unit it will be registered as fraud.
My problem is how will i am going to check if accountTwo try to log in on accountOne pc unit. Right now we're using cookie but if they use other browser or private browser the data on the cookie was not send on the request.
Righ now I am trying to determine using Mac Address of each PC, but still can't figure out how to get the Mac Address. It gives the server address where the site was hosted.
Similar TutorialsHey Guys,
I'm currently in a program managed by IT Department of India. My topic is Vehicle Offence Management System. Unfortunately I failed with android finger print scanning. I need to record face of every individual when registering offence and I need to retrieve data when the same face is captured. is there is any Solution in PHP ??? for matching 2 faces ?
Thanks Hello guys, I have a mysql table which will store users email addresses (each is unique and is the primary field) and a timestamp. I have added another column called `'unique_code' (varchar(64), utf8_unicode_ci)`. What I would very much appreciate assistance with is; a) Generating a 5 digit alphanumeric code, ie: 5ABH6 b) Check all rows the 'unique_code' column to ensure it is unique, otherwise re-generate and check again c) Insert the uniquely generated 5 digit alphanumeric code into `'unique_code'` column, corresponding to the email address just entered. d) display the code on screen. What code must I put and where? **My current php is as follows:** Code: [Select] require "includes/connect.php"; $msg = ''; if($_POST['email']){ // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('You are already on the notification list.'); } if($ajax){ die('{"status":1}'); } $msg = "Thank you!"; } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } I really need some serious help with the design of a PIN (Personal Identification Number) Management System. When a user (with ID) logs in with the PIN (which already exist in my database), i want the system to assign that PIN to that user (ID) alone. No other user (ID) can access that PIN, the PIN is only assigned to that User (ID). I need the PHP codes, MySQL database tables, and some lil' explanation. Thanks. I wish to create validation rules once which are used both on the client and on the server.
For instance, I will start off with the following PHP object:
stdClass Object
(
[rules] => stdClass Object
(
[email] => stdClass Object
(
[required] => 1
[email] => 1
[remote] => stdClass Object
(
[url] => check-email.php
[type] => post
[data] => stdClass Object
(
[username] => function() {return $( '#username' ).val();}
)
)
)
)
[messages] => stdClass Object
(
[email] => stdClass Object
(
[required] => an email is required
)
)
)
When the edit page is downloaded to the client, I will include this object in some format suitable to the client.
The client will then use the jQuery Validation plugin (http://jqueryvalidation.org/) along with the validation object, and client side validate the page.
When the form passes client side validation and is uploaded, PHP will use the same validation object to serverside validate the form (I have this part working as desired).
My question is how should I pass this data to the client? Originally, I would just use PHP to write some JavaScript.
exit('var myObj='.json_encode($myObj));
Note that when I json_encode the object, the value of $myObj->rules->email->remote->data->username is a string with quotes around it, however, I can easily use PHP to strip these tags before sending it to the client.
As Jacques1 pointed out in http://forums.phpfre...ascript-client/, I should never ever use PHP to generate JavaScript, and should use AJAX to download the JSON directly. I tried doing the later, but found that a callback function could not be included in the JSON.
Please advise on the best way to accomplish this.
Thank you
Is there a way to get my visitors PC or Device Name? I am not looking for server name or ip. I need to get my current visitors computer name. Example: MAIN, HOME, OFFICE, TOM32154}}{|\] like when first naming a PC with a new windows install. I have used sessions before I don't know whats going on. My sessions wont die. this is what im doing: <?php session_start(); $_SESSION['user'] = $_POST['email']; $_SESSION['pass'] = $_POST['pass']; ?> ok new page <?php session_start(); echo $_SESSION['user']; echo "<br>"; echo $_SESSION['pass'] ?> OK great is show the same info but now if I close my browser and go back to the second page where it echos it still shows the user//pass I have tried restarting and it still saves the dam session! Should it kill the session if i close my browser? wtf? i have recently bought a new samsung netbook so i downloaded the latest version of WAMP to develop my site. However when i run my site i get the internal server error associated with the htaccess file. The thing is that this file works on my desktop pc. The version i have of WAMP on this netbook is newer than the one i have at home, socould this be the problem? i can post the contents of the htaccess file if you think it will help, its just a lot of rewrite rules. Thanks I am running php on one computer at work and want other users on other computers to access the index page by sharing it.after mapping the page, I see no data on the other machine. Does php, as pache need to beer installed on other computers footer it too work properly Hey, I'm trying to code a page which is supposed to bring up the time of a person's computer. Is this possible without majorly complicated coding? I'm good with GMT offsets and stuff but I don't know how to get the time of a person's computer. I don't want other stuff, just the time so I can edit the time based on where they are. I don't know if I'm making sense so here's an example... If someone does a forum post at 2pm Sydney time but it's 5pm Perth time. How can I make it so that someone in Perth sees 5pm but someone in Sydney sees 2pm...without them manually telling me their timezone? I read about using IP addresses but don't know much (Ok anything) about this , any hints or good sites to view would be appreciated? Or the answer if it's not too complex. Preferably I'd like to get the time in the 11 digit "time()" format so I can use it in tables and translate it with an existing function. IceKat Hi all, I've created a data-entry HTML page that posts to update.php. I am using mysql to store the data entered. When I enter data and hit "update database" button, the php file pops up and correctly shows the data entered, but the update.php file does not show that same data on another computer. I have checked the mysql database and it clearly shows that it the new data has been stored. Why isn't the data showing up on any other computer? I can provide codes as needed. Thanks. Richard I am trying to pull in computer information using PHP for program compatibility and want to know if it is possible and if so, what functions to use. Hi, i have problem with libraries, with fpdf and PHPEcel, problem is same... Can't open file C:\xampp\htdocs\skripta\.... - this is path to php script on my computer everything work ok on localhost when i test, but when i upload to web server, pdf script try to create file with old windows path: Can't open file C:\xampp\htdocs\skripta\, and not with linux path... does anyone have solution, and why is that? I know about
<input type="file" >which allows one to upload files from one’s computer. But now I need a pop-up window that allows the user to choose first if he uploads from his computer or from the internet. How may I achieve that ? This question is perhaps better suited for the "Javascript" or even "AJAX" forum ; if someone advises me to, I will move that question and put it in the appropriate forum. This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=318425.0 Hi, I have a challenging dilema. A client keeps track of his stock using a microsoft access database in store. His ecommerce website which is hosted elsewhere uses php and mysql. Is it possible to to integrate the 2 so that when someone buys a product from the website, the store MS access database is updated to reflect this and vice versa? If so how would I go about it? Thanks in advance. P.S: I'm extremely tempted to suggest that he should stop using his ms access db and instead reccommend that I set him up a suitable backend on his website for keeping stock control, then he just login to that in the store. Is there a reason why on my local machine with php, my login system works, but then when I upload my files and test it on my web host, the login system doesn't work properly. I'm using the same php version on my local machine and on my webhost, so I don't understand why it wouldn't work the same. When I try logging in on my webhost, everything processes as normal when a correct user/pass combo is found in the database, however, my session just doesn't seem to be saved, and therefore I won't be logged in. It'll end up refreshing to the home page (as I have it setup), but it won't show me as logged in. Is there something special I need to do in order for the session to be stored correctly? (I realize I haven't pasted any code, but I'm not sure exactly how much code would be needed for me to show in order to resolve the issue).
<?php
shell_exe ("172.18.9.25\photoshop\photoshop.exe");
?>
When I run this from the server computer program opening. But when i tried from a diferent computer it is only downloading the exe file to the client computer. How can I open the application from a diferent computer in the same network. Hello everyone, I am working on a form that is similar to a shopping cart system and I am thinking of creating a button that submits the checked value and saves them to a $_SESSION variable. And also a link that links to a cart.html that takes the values of a $_SESSION variable. I am have trouble figuring what tag/attribute should I use in order to achieve that.
Right now my code attached below submits the checked values to cart.html directly. However I want my submit button to save the checked box to a $_SESSION variable and STAY on the same page. And then I will implement a <a> to link to the cart.php.
I researched a little bit about this subject and I know it's somewhat related to ajax/jquery. I just wanted to know more about it from you guys. I appreciate your attention for reading the post and Thanks!
Below is the form that I currently have:
<form name= "finalForm" method="POST" action="cart.php">
<input type="Submit" name="finalSelected"/>
<?php foreach($FinalName as $key => $item) {?>
<tr>
<td><input type="checkbox" name="fSelected[]" value="<?php echo htmlspecialchars($FinalID[$key])?>" />
<?php echo "$FinalID[$key] & $item";?>
</td>
</tr>
<?php } ;?>
Below is the code for cart.php
<?php
require ('connect_db.php');
if(isset($_POST['finalSelected']))
{
if(!empty($_POST['fSelected']))
{
$chosen = $_POST['fSelected'];
foreach ($chosen as $item)
echo "aID selected: $item </br>";
$delimit = implode(", ", $chosen);
print_r($delimit);
}
}
if(isset($delimit))
{
$cartSQL = "SELECT * from article where aID in ($delimit)";
$cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc));
while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH))
{
$aTitle[] = $row[ 'name' ];
}
}
?>
<table>
<?php if(isset($delimit)) {
$c=0; foreach($aTitle as $item) {?>
<tr>
<td>
<?php echo $aTitle[$c]; $c++;?>
</td>
</tr>
<?php }}?>
</table>
Dear all, I'm working on a website that is hosted on a server with 10Mb of file size limit via HTTP file uploading approach (eg. PHP file uploading form using move_uploaded_file()), although there's no file size limit via FTP file uploading approach (eg. Using FTP client). Therefore, I was thinking about using PHP FTP functions to bypass the file size limit. However, when I upload file bigger than 10Mb, I still got this error message telling me that my file can't be over 10Mb... So my question is...what exactly are the differences between PHP FTP and FTP Client, that the web server used to determine whether to block the file bigger than 10Mb or not? Thank you very much! Below is my code: Code: [Select] <?php echo '<form action="" method="post" enctype="multipart/form-data">'; echo 'Click the Browse button to find the file you wish to upload'; echo '<input type="file" name="add_file">'; echo '<INPUT TYPE="submit" name="upload" value="upload">'; echo '</form>'; if($_POST['upload']) { $add_file = $_FILES['add_file']; //change these values to suit your site $ftp_user_name = 'username'; $ftp_user_pass = 'password'; $ftp_server = 'ftp.domainname.com'; $ftp_root = '/'; //File upload $temp_path = $ftp_root . $add_file['tmp_name']; $target_path = basename($add_file['name']); $max_size = 26214400; if($add_file['error'] == 0 && $add_file['size'] < $max_size) { // set up basic connection $conn_id = ftp_connect($ftp_server); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); // upload a file ftp_chdir($conn_id, '/root/second/'); if (ftp_put($conn_id, $target_path, $temp_path, FTP_ASCII)) { echo "successfully uploaded " . $target_path; } else { echo "There was a problem while uploading " . $target_path; } } else { echo "There's been an error, please try again later."; } // close the connection ftp_close($conn_id); } ?> |
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