PHP - Multiple Query On Same Table

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=351561.0

these DB  are on the same server
sp
inter
query
how do i combine the mysql_db()?
Code: [Select]
SELECT * FROM `sp.bookings` LEFT JOIN sp.bookings_items ON sp.bookings.id_item = sp.bookings_items.id LEFT JOIN inter.apartments ON inter.apartments.ID = sp.bookings_items.id_ref_external WHERE  sp.bookings.the_date BETWEEN '$from_date' and '$to_date' and id_state=1   LIMIT 0 , 30

mysql_query("UPDATE mods SET version='$version' AND name='$title' AND descritpion='$description' AND lastupdate='$date' WHERE id='$id'");


I don't think I'm doing it correctly. :/

Hey,

I have a query running inner joins... which currently works, but I need some more information pulled from other tables...

Code: [Select]
define('WPSC_TABLE_PRODUCT_LIST', "{$wp_table_prefix}wpsc_product_list");
define('WPSC_TABLE_PRODUCTMETA', "{$wp_table_prefix}wpsc_productmeta");
define('WPSC_TABLE_CATREF', "{$wp_table_prefix}wpsc_item_category_assoc");
define('WPSC_TABLE_CATNAME', "{$wp_table_prefix}wpsc_product_categories");


$cf="Linked Products";
$sku = get_post_meta($post->ID, $cf, true);
$array = explode(",",$sku);

$products = array_count_values($array);

foreach($products as $key => $value) {
$product = $wpdb->get_row("SELECT meta.product_id AS pid, list.name AS name, list.price AS price, retailer.category_id AS catid FROM ".WPSC_TABLE_PRODUCTMETA." AS meta INNER JOIN ".WPSC_TABLE_PRODUCT_LIST." AS list ON ( list.id = meta.product_id ) INNER JOIN ".WPSC_TABLE_SHOPNAME." AS retailer ON ( retailer.product_id = meta.product_id ) WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC");
?>
But I also need the category name - So I have to cross reference the following...

wordpdem_wpsc_product_list

id      name
433   itemone
432   itemtwo
431   itemthree

wordpdem_wpsc_item_category_assoc

id   product_id    category_id
1    433                    1
2    432                    2
3    410                    3

wordpdem_wpsc_product_categories

id  name
1   Bread
2   Fish
3   Snacks

I've now written:
Code: [Select]
SELECT
meta.product_id AS pid,
list.name AS name,
list.price AS price,
retailer.category_id AS catid,
category.name AS catname

FROM wordpdem_wpsc_productmeta AS meta
INNER JOIN wordpdem_wpsc_product_list AS list ON ( list.id = meta.product_id )
INNER JOIN wordpdem_wpsc_item_category_assoc AS retailer ON ( retailer.product_id = meta.product_id )
INNER JOIN `wordpdem_wpsc_product_categories``wordpdem_wpsc_product_list` AS category ON ( retailer.category_id = category.id )
WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC
However it fails on line 12 (the Where statement...)

Any ideas what I've done wrong?

I can use the first while loop, but there is no data in the second while loop. Is there a better way as I have never done this before...

Code: [Select]
              <?php
                $featured_results = mysql_query("SELECT * FROM products LEFT JOIN product_images ON products.product_id=product_images.product_id WHERE products.product_featured='1' AND products.product_active='1' AND thumb='1'");

$fa=0;
while($featured_row = mysql_fetch_assoc($featured_results))
   {
$fthumb_result = mysql_query("SELECT image_name FROM product_images WHERE product_id='".$featured_row['product_id']."' AND thumb='1'");
$fthumb = mysql_fetch_row($fthumb_result);

if ($fa==0) {
echo "\n<img id=\"home-slider-photo-".$fa."\" class=\"home-slider-photo preload\" src=\"/includes/getimage.php?img=".$fthumb[0]."&w=370&h=370\" alt=\"\" />";
} else {
echo "\n<img id=\"home-slider-photo-".$fa."\" class=\"home-slider-photo preload home-slider-photo-unsel\" src=\"/includes/getimage.php?img=".$fthumb[0]."&w=370&h=370\" alt=\"\" />";
}
$fa++;
}

echo "<div id=\"home-slider-photo-price\">";
$fb=0;
while($featured_row2 = mysql_fetch_assoc($featured_results))
   {
if ($fb==0) {
echo "\n<div id=\"home-slider-photo-price-".$fb."\" class=\"home-slider-photo-price\">\n<span>only</span>$".$featured_row2['product_price']."\n</div>";
} else {
echo "\n<div id=\"home-slider-photo-price-".$fb."\" class=\"home-slider-photo-price home-slider-photo-price-unsel\">\n<span>only</span>$".$featured_row2['product_price']."\n</div>";
}
$fb++;
}
echo "</div>";
?>

Hello,

I'm fairly new to php and I'm working on a website for a chess club. I'd like the user to select all of his or her personal results from a general results table.  The results table looks as follows:

id         name_white         name_black         result           season_id

1          john                    pete                    1-0              2010-2011
2          charles                steve                   0-1              2010-2011
3          richard                john                    1-0               2010-2011
etc
11        isaac                   john                    1-0               2011-2012
12        william                kate                     0-1              2011-2012
13        john                    bobby                  1-0              2011-2012
etc

Let us say that the user wants to see all the results of player john in the 2010-2011 season.  The following query (probably quite naively) gives me the error "supplied argument is not a valid MySQL result resource":

Code: [Select]
$result_personal = mysql_query("SELECT * FROM results WHERE name_white = '$seleted_name' AND name_black = '$selected_name' AND season id ='$selected_season'");
Could anyone help me steer in the right direction?  Should I use a JOIN query instead?  Or a IN query?

All the best and thanks in advance for your time,

Wouter.

Hi,

I am currently working on a very detailed personal project during my vacation to keep me busy, but I have a problem, I am trying to create a unique id, without having the chance of a repetition of the id, even if its infinitely small. So I found the flickr ticket id system to be a good choice, since it was sequential and effective.

My problem now is, how can I execute 2 queries simultaneously, given the hypothetical change that if I execute them with two separate queries (mysql_query), that there is the chance that another query could be executed in between the break, causing two id's to be the same. Since mysql_query can only execute a single query I am a bit stuck.

I thought about possibly using CGI, but then again I have never used it, so I don't know its limitations. Can anyone suggestion anything to me for this problem, as to how I can execute two query strings in the same query.

Hi there,

This is what I need to do, blow that is the code I have knocked up to do it but it doesn't seem to work. The main problem is the query that matches the atc callsigns to the pilots destinations.. can't fathom it myself.

1. Pull all the records from my database.
2. Assign their unique user id's, callsigns and destinations.
3. Execute a query in which you: SELECT * FROM CLIENTS WHERE (The 'clienttype' = 'ATC') AND match the callsign of the ATC users to the 'planned_destairport' of the 'clienttype' = 'PILOT'.

For example if three people are going to Heathrow, then it would return 3 results.
4. Then do a mysql_num_rows of the result.
5. Lastly, execute a query that would update the 'atcarrivals' collumn in the database with the count number using the unique 'cid' as the identifier.

All in a loop of course.


// Selects all of the ATC Records.
$atc_arrivals_selectquery = mysql_query ("SELECT * FROM CLIENTS");

// Starts the loop for fetching the records of the previous query.
while($atc_arrivals_row = mysql_fetch_array($atc_arrivals_selectquery)){

// Sets the users cid, planned_destairport and callsign.
$atc_cid = $atc_arrivals_row['cid'];
$atc_destinations = $atc_arrivals_row['planned_destaiport'];
$atc_callysign = $atc_arrivals_row['callsign'];

// Searches the database and selects all records where the callsign is LIKE the destination airport.
$atc_arrivals_check = mysql_query("SELECT * FROM CLIENTS WHERE clienttype = 'ATC' AND callsign LIKE '%$atc_destinations'");

// Counts previous query results.
$atc_arrivals_count = mysql_num_rows($atc_arrivals_check);

// Updates the atcarrivals column with the count..
$atc_arrivals_updatequery = mysql_query("UPDATE CLIENTS SET atcarrivals = '$atc_arrivals_count' WHERE cid = '$atc_cid' AND clienttype = 'ATC'");

// End loop.
}


Concerned columns are these:
"cid" - Unique client id.
"atcarrivals" - Number of arrivals from count. (This is the problem.)
"planned_destairport" - Destination airport of pilot. Usually four letters long. IE. EGLL = Heathrow.

Thanks.

According to http://www.phpfreaks.com/forums/index.php?topic=350872.0:

Is this a correct usage of what I am trying to create?

Code: [Select]
<?php

$connect = mysql_connect("mysql12.000webhost.com","***","***") or die(mysql_error());
mysql_select_db("***") or die(mysql_error());


$id = mysql_real_escape_string($_GET['id']);
$extract = mysql_query("SELECT * FROM webclientcreate WHERE id='$id' LIMIT 1 WHERE ip='$ip' WHERE port='$port' WHERE name='$name' WHERE background='$background'");
?> Code: [Select]
<applet name=client width=765 height=503 archive='<?php echo $jars; ?>' code='client.class'>

 <PARAM name='java_arguments' value='-Xmx700m'>

 <PARAM name='server_name' value='<?php echo $name; ?>'>

 <PARAM name='detail' value='low'>

 <PARAM name='ip' value='<?php echo $ip; ?>'>

 <PARAM name='port' value='<?php echo $port; ?>'>

 <PARAM name='background_image' value='<?php echo $background; ?>'>

 <PARAM name='headicons' value=''>

I've tried several types of the query line such as :
Code: [Select]
webclientcreate WHERE id='$id' LIMIT 1, WHERE ip='$ip', WHERE port='$port' Code: [Select]
webclientcreate WHERE id='$id' LIMIT 1, ip='$ip', port='$port' Code: [Select]
webclientcreate WHERE id='$id' LIMIT 1 ip='$ip' port='$port'Without any success 

I appreciate any help I can get!

What I am trying to do is create a search box to search for a specific piece of information in my client database, say last name, or account number, invoice number, etc. is there a way i can use the keyword to match the query to multiple columns?

here is my code, the script works if i use the $query to select just 1 column. but how do i add other columns to match it to?

I know its  where "different columns" LIKE search  my problem is this line basically.

Code: [Select]
mysql_select_db("terra_elegante_operations", $con);



$searchfor = $_GET['search_term'];


$query = "select * from client_information where name_last like \"%$searchfor%\"";

$result = mysql_query($query) or die("Couldn't execute query");

$row = mysql_fetch_array($result);

echo $row['0'];

$query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' users.username='$username'");


How do I get it so it selects data from the table tickets where id='$existing', but I also want to get a user's (who is viewing the ID) position (rank). $username is a session. So, any thoughts on how I would do so?

My updated code:


<?php
session_start();
include("../includes/mysql.php");
include("../includes/config.php");

?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<link href="../style.css" rel="stylesheet" type="text/css" />
<title><?php echo $title; ?></title>
</head>

<body>
<div id="container">
<div id="content">
<div id="left">
<div class="menu">
<?php include("../includes/navigation.php"); ?>
<div class="menufooter"></div>
</div>
<?php include("../includes/menu.php"); ?>
</div>
<div id="middle">
<?php
$existing = $_POST['existing'];
$ip = $_SERVER['REMOTE_ADDR'];
$username = $_SESSION['user'];

$query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' OR users.username='$username'");
$get = mysql_fetch_assoc($query);

if(!$existing)
{
echo 
'
<div class="post">
<div class="postheader"><h1>Error</h1></div>
<div class="postcontent">
<p>You have not enetered in a ticket ID. Please go back and do so.</p>
</div>
<div class="postfooter"></div>
</div>
';
}
elseif($get['COUNT(id)'] < 1)
{
echo 
'
<div class="post">
<div class="postheader"><h1>Error</h1></div>
<div class="postcontent">
<p>The ticket ID you are trying to use doesnt exist. Please go back or submit another ticket.</p>
</div>
<div class="postfooter"></div>
</div>
';
}
elseif($get['tickets.ip']==$ip || $get['user.position'] >= 1)
{
$status["tickets.status"]["0"] = "Waiting for support...";
$status["tickets.status"]["1"] = "Waiting for user...";
$status["tickets.status"]["2"] = "Ticket Closed...";
$status["tickets.status"]["3"] = "Ticket Opened...";

echo 
'
<div class="post">
<div class="postheader"><h1>View Ticket Status - ID '. $get["id"] .'</h1></div>
<div class="postcontent">
<p>Title: '. $get["tickets.title"] .' - Posted on: '. $get["tickets.date"] .'</p>
<p>Ticket Status: '. $status[$get["tickets.status"]] .'</p>
<p>Question: '. nl2br($get["tickets.question"]) .'</p>
</div>
<div class="postfooter"></div>
</div>
';

}
else
{
echo 
'
<div class="post">
<div class="postheader"><h1>Error</h1></div>
<div class="postcontent">
<p>This is not your ticket. You only have permission to view your tickets. Please go back.</p>
</div>
<div class="postfooter"></div>
</div>
';
}
?>
</div>
</div>
</div>
</body>
</html>

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=315554.0

Hello,

I have a drop down box that filters my table data by City and displays the results. It works! Now I am trying to add a second drop down menu to filter by name. When name is selected AND city is selected, the display should be the same names that live in the same city. Can anyone ties these 2 drop downs together for me?

Here is my table:
Code: [Select]
CREATE TABLE IF NOT EXISTS `data` (
  `id` int(11) NOT NULL auto_increment,
  `from_date` date NOT NULL,
  `to_date` date NOT NULL,
  `full_name` varchar(250) NOT NULL,
  `email` varchar(250) NOT NULL,
  `city` varchar(250) NOT NULL,
  PRIMARY KEY  (`id`)
)

And here is the html and PHP in one file:
Code: [Select]
<?php

error_reporting(0);
include("config.php");
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>MySQL table search</title>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js"></script>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/jquery-ui.min.js"></script>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<style>
BODY, TD {
font-family:Arial, Helvetica, sans-serif;
font-size:12px;
}
</style>
</head>

<body>

<form id="form1" name="form1" method="post" action="search.php">
<label>Name</label>
<select name="name">
<option value="">--</option>
<?php
$sql = "SELECT * FROM ".$SETTINGS["data_table"]." GROUP BY full_name ORDER BY full_name";
$sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql);
while ($row = mysql_fetch_assoc($sql_result)) {
echo "<option value='".$row["full_name"]."'".($row["full_name"]==$_REQUEST["full_name"] ? " selected" : "").">".$row["full_name"]."</option>";
}
?>
</select>&nbsp;&nbsp;
<label>City</label>
<select name="city">
<option value="">--</option>
<?php
$sql = "SELECT * FROM ".$SETTINGS["data_table"]." GROUP BY city ORDER BY city";
$sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql);
while ($row = mysql_fetch_assoc($sql_result)) {
echo "<option value='".$row["city"]."'".($row["city"]==$_REQUEST["city"] ? " selected" : "").">".$row["city"]."</option>";
}
?>
</select>
<input type="submit" name="button" id="button" value="Filter" />
  </label>
  <a href="search.php">
  reset</a>
</form>
<br /><br />
<table width="700" border="1" cellspacing="0" cellpadding="4">
  <tr>
    <td width="90" bgcolor="#CCCCCC"><strong>From date</strong></td>
    <td width="95" bgcolor="#CCCCCC"><strong>To date</strong></td>
    <td width="159" bgcolor="#CCCCCC"><strong>Name</strong></td>
    <td width="191" bgcolor="#CCCCCC"><strong>Email</strong></td>
    <td width="113" bgcolor="#CCCCCC"><strong>City</strong></td>
  </tr>
<?php

if ($_REQUEST["city"]<>'') {
$search_city = " AND city='".mysql_real_escape_string($_REQUEST["city"])."'";
}

if ($_REQUEST["from"]<>'' and $_REQUEST["to"]<>'') {
$sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE from_date >= '".mysql_real_escape_string($_REQUEST["from"])."' AND to_date <= '".mysql_real_escape_string($_REQUEST["to"])."'".$search_string.$search_city;
} else if ($_REQUEST["from"]<>'') {
$sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE from_date >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string.$search_city;
} else if ($_REQUEST["to"]<>'') {
$sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE to_date <= '".mysql_real_escape_string($_REQUEST["to"])."'".$search_string.$search_city;
} else {
$sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE id>0".$search_string.$search_city;
}

$sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql);
if (mysql_num_rows($sql_result)>0) {
while ($row = mysql_fetch_assoc($sql_result)) {
?>
  <tr>
    <td><?php echo $row["from_date"]; ?></td>
    <td><?php echo $row["to_date"]; ?></td>
    <td><?php echo $row["full_name"]; ?></td>
    <td><?php echo $row["email"]; ?></td>
    <td><?php echo $row["city"]; ?></td>
  </tr>
<?php
}
} else {
?>
<tr><td colspan="5">No results found.</td>
<?php
}
?>
</table>

</body>
</html>

I have this form

<form action="" method="get" name="size"> Størrelse <hr><label><input type="radio" value="9" name="size" onchange="this.form.submit()">92 (2år)</label>


<label><input type="checkbox" value="147" name="size" onchange="this.form.submit()">68 (6-9 mdr.)
</label><label><input type="checkbox" value="150" name="size" onchange="this.form.submit()">86 (18-24 mdr.)</label>
<input type="checkbox" value="149" name="size" onchange="this.form.submit()">80 (12-18 mdr.)</label>
<label><input type="checkbox" value="148" name="size" onchange="this.form.submit()">74 (9-12 mdr.)</label>


</form>

I want to make it so that when the user clicks one checkbox for example size 68 and then checks size 80 I want both sizes to be in the URL query string. But every time the user clicks a new checkbox, the query string changes accordingly. Maybe with a separator like ?size=4:23 and then I will handle it with the DB stuff.   Please tell me how to add multiple elements in the query string with this form, thank you!
Edited by Stefany93, 21 May 2014 - 08:03 AM.

Hi guys,
 I have a php file that will go to a site and scrape the data I need. However this site is setup to use pagination so when I try to scrape all the players names I have to do separate queries to search each page. Is there a way to find out by using code how many pages there are and query all the pages at same time?

I use  this code
Code: [Select]
<?php //first page

//turn error reporting on
libxml_use_internal_errors(true);

//get data from this page
$dom = new DOMDocument;
$dom->loadHTMLFile('http://www.gametracker.com/server_info/76.73.3.42:1716/top_players/?searchipp=50#search');
$xpath = new DOMXPath($dom);

// Get the total player count
$rows2 = $xpath->query('//div[@class="block774"]/div');

// Get the rows from the search list
$rows = $xpath->query('//table[@class="table_lst table_lst_spn"]/tr');


for ($i=1; $i<$rows->length-1; $i++) {
    $row = $rows->item($i);

    // Get the columns for a row
    $cols = $row->getElementsByTagName('td');

// Get the player rank (1st column)
    echo 'Rank:'.trim($cols->item(0)->textContent).PHP_EOL;

    // Get the player name (2nd column)
    echo 'Name:'.trim($cols->item(1)->textContent).PHP_EOL;

// Get the player score (3rd column, actually 4th but number 3 is hidden)
    echo 'Sco '.trim($cols->item(3)->textContent).PHP_EOL;

echo "<br />";
}
?>





<?php //secondpage

//turn error reporting on
libxml_use_internal_errors(true);

//get data from this page
$dom = new DOMDocument;
$dom->loadHTMLFile('http://www.gametracker.com/server_info/76.73.3.42:1716/top_players/?searchipp=50&searchpge=2#search');
$xpath = new DOMXPath($dom);

// Get the rows from the search list
$rows = $xpath->query('//table[@class="table_lst table_lst_spn"]/tr');


for ($i=1; $i<$rows->length-1; $i++) {
    $row = $rows->item($i);

    // Get the columns for a row
    $cols = $row->getElementsByTagName('td');

// Get the player rank (1st column)
    echo 'Rank:'.trim($cols->item(0)->textContent).PHP_EOL;

    // Get the player name (2nd column)
    echo 'Name:'.trim($cols->item(1)->textContent).PHP_EOL;

// Get the player score (3rd column)
    echo 'Sco '.trim($cols->item(3)->textContent).PHP_EOL;
echo "<br />";
}

?>
I also have to go to that website first to see how many pages there are so I can have enough queries.