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PHP - Update Multi Row With For Schleife
Hello everebody,
i have code to updare many rows at once using "for". when i click submit button nothing happens, where is the error in my code? thank you very much for your help
<?php
$hoster="db.mkq.de";
$username="dbxxxxxx";
$password="xxxxxx";
$db_name="xxxxxx";
mysql_connect("$hoster", "$username", "$password")
or die("cannot connect");
mysql_select_db("$db_name")
or die("cannot select DB");
$sql="SELECT * FROM gbook";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
?>
<table width="500" border="0" cellspacing="1" cellpadding="0">
<form name="form1" method="post" action="">
<tr>
<td>
<table width="500" border="0" cellspacing="1" cellpadding="0">
<tr>
<td align="center"><strong>Id</strong></td>
<td align="center"><strong>www</strong></td>
<td align="center"><strong>email</strong></td>
<td align="center"><strong>pwd</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td align="center">
<input name="id[]" type="text" id="id" value="<? echo $rows['id']; ?>">
</td>
<td align="center">
<input name="www[]" type="text" id="www" value="<? echo $rows['www']; ?>">
</td>
<td align="center">
<input name="email[]" type="text" id="email" value="<? echo $rows['email']; ?>">
</td>
<td align="center">
<input name="pwd[]" type="text" id="pwd" value="<? echo $rows['pwd']; ?>">
</td>
</tr>
<?php
}
?>
<tr>
<td colspan="4" align="center"><input type="submit" name="submit" id="submit" value="update"></td>
</tr>
</table>
</td>
</tr>
</form>
</table>
<?php
if($submit)
{
for($i=0;$i<$count;$i++)
{
$sql1="UPDATE gbook SET www='$www[$i]', email='$email[$i]', pwd='$pwd[$i]' WHERE id='$id[$i]'";
$result1=mysql_query($sql1);
}
}
if($result1)
{
header("location:editmulti3.php");
}
mysql_close();
?>
Similar TutorialsHi all, I have a data base with the following table: ---member_data--- id ^ mid ^fieldname^ fieldvalue 1 - 2 - applicant - Seth Smith 2 - 4 - firstname - Chris 3 - 4 - lastname - Cooper 4 - 7 - full_name - Joey Jones 5 - 7 - occupation - Programmer 6 - 7 - phone - 800-555-1212 And below is a snippet that I use to display the selected members data for editing ------------------------------- <table> <tr> <td>Name:</td> <td>Value:</td> </tr> <?php $query = "SELECT * FROM member_data WHERE mid='$mid'"; $result= mysql_query($query); while($row = mysql_fetch_array($result)) { $fieldname = $row["fieldname"]; $fieldvalue = $row["fieldvalue"]; ?> <tr> <td><input type="text" name="<?php echo $fieldname;?>" value="<?php echo $fieldname;?>"></td> <td><input type="text" name="<?php echo $fieldvalue;?>" value="<?php echo $fieldvalue;?>"></td> <?php } ?> </tr> </table> ------------------------------- My question is: - using the Db example above: - lets say Ive selected mid#7 (member id 7) to edit which is displayed using the snippet code from above. - once displayed how do I edit mid#7 given the fact that mid#7 is located on 3 seperate rows from the same table? Thank you, Dave *ALSO - I tried the snippet below which did Not work. foreach($_POST as $key => $val) { $sql = "UPDATE member_data SET fieldname='$key', fieldvalue='$val' WHERE mid='$mid'"; $result = mysql_query($sql); } i have a form per row with an update button my problem is to update each row at a time so i created a unique update button per row, not working Code: [Select] <table cellspacing="0" cellpadding="0" border="1"> <col width="75" span="5" /> <tr> <td width="75">Proposal</td> <td width="75"> </td> <td width="75">Supplier</td> <td width="75">Downpayment</td> <td width="75">Payment Method</td> <td width="75">Status</td> <td width="75"> </td> </tr> <?php do { ?> <tr><form id="form1" name="form1" method="post" action=""> <td><?php echo $row_RsDownPayment['RequestID']; ?>-<?php echo $row_RsDownPayment['ProposalID']; ?></td> <td><?php echo $row_RsDownPayment['CustomerLastName']; ?></td> <td><?php echo $row_RsSupplier['SupplierName']; ?></td> <td><?php echo $row_RsDownPayment['PREPAYMENT2SUPPLIER']; ?></td> <td><select name="PaymentMethod" id="PaymentMethod"> <option value="0">Choose</option> <option value="Bank Transfer">Bank Transfer</option> <option value="CreditCard">CreditCard</option> <option value="Cash">Cash</option> <option value="PayPal">PayPal</option> </select></td> <td><?php echo $row_RsStatus['StatusLabel']; ?></td> <td><input name="<?php echo $U='Update'.$row_RsDownPayment['ProposalID'];?>" type="submit" value="Update" /> </td></form> </tr> <?php $con = mysql_connect("host","db","db"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_query("SET NAMES 'utf8'"); mysql_select_db("db", $con); if (isset($_POST['Update121'])) { $query=mysql_query("UPDATE proposals SET StatusID='$_POST[StatusID]' WHERE ProposalID = '$row_RsDownPayment[ProposalID]'"); exit; } ?> <?php } while ($row_RsDownPayment = mysql_fetch_assoc($RsDownPayment)); ?> </table> Hi there, hope have some help. I have a form where a user select time and days of the week (monday, tuesday..) that he is available. The insert script works fine, it insert and the days of week he checked in the table, the only problme is when i try to update each of them.
I used this code above, but is not working, instead of updating/inserting days that is selected is inserting multi-records with the same day of the week value.
here it is:
foreach($weekDay as $DaysofWeek){
$sql_days = "UPDATE available SET day_time = '$day_time', week_day = '$DaysofWeek' WHERE user_id = '$id_user'";
$update_availability = mysql_query($sql_days);
}
hi all i have a problem here, Iv got a form that uploads images to a folder and updates the db with the name of that image, that work ok but if one of the upload field are left blank then the script updates the db with empty values how can i get it to only update the db with only submitted form field data???? here is the form Code: [Select] <?php if (isset($_GET['id'])) { $id = $_GET['id']; } ?> <form action="ud_image.php?id=<? echo "$id"?>" method="post" enctype="multipart/form-data" name="form1" id="form1"> <table class="udp"> <tr> <th>Thumbnail:</th> <td><input type="hidden" name="MAX_FILE_SIZE" value="1029120" /> <input name="ufile[]" type="file" id="ufile[]" size="50" /></td> </tr> <tr> <th>Image 1:</th> <td><input type="hidden" name="MAX_FILE_SIZE" value="1029120" /> <input name="ufile[]" type="file" id="ufile[]" size="50" /></td> </tr> <tr> <th>Image 2:</th> <td><input type="hidden" name="MAX_FILE_SIZE" value="1029120" /> <input name="ufile[]" type="file" id="ufile[]" size="50" /></td> </tr> <tr> <th>Image 3:</th> <td><input type="hidden" name="MAX_FILE_SIZE" value="1029120" /> <input name="ufile[]" type="file" id="ufile[]" size="50" /></td> </tr> <tr> <th>Image 4:</th> <td><input type="hidden" name="MAX_FILE_SIZE" value="1029120" /> <input name="ufile[]" type="file" id="ufile[]" size="50" /><input type="submit" name="Submit" value="Upload" /></td> </tr> </table> </form> and here is the processing page <?php include("protect/password_protect.php"); error_reporting(E_ALL); include ("../includes/db_config.php"); $con = mysql_connect($db_hostname,$db_username,$db_password); @mysql_select_db($db_database) or die( "Unable to select database"); $path1= "../thumbnails/".$_FILES['ufile']['name'][0]; $path2= "../images/".$_FILES['ufile']['name'][1]; $path3= "../images/".$_FILES['ufile']['name'][2]; $path4= "../images/".$_FILES['ufile']['name'][3]; $path5= "../images/".$_FILES['ufile']['name'][4]; //copy file to where you want to store file copy($_FILES['ufile']['tmp_name'][0], $path1); copy($_FILES['ufile']['tmp_name'][1], $path2); copy($_FILES['ufile']['tmp_name'][2], $path3); copy($_FILES['ufile']['tmp_name'][3], $path4); copy($_FILES['ufile']['tmp_name'][4], $path5); ?> <html> <head> <title>Update Project Images</title> <link rel="stylesheet" type="text/css" href="../../project/backend/style.css" /> </head> <body> <table class="udip"> <tr> <th><? echo "<img src=\"$path1\" width=\"150\" height=\"150\">";?></th> <th><? echo "<img src=\"$path2\" width=\"150\" height=\"150\">";?></th> <th><? echo "<img src=\"$path3\" width=\"150\" height=\"150\">";?></th> <th><? echo "<img src=\"$path4\" width=\"150\" height=\"150\">";?></th> <th><? echo "<img src=\"$path5\" width=\"150\" height=\"150\">";?></th> </tr> <tr> <td><? echo "File Name :".$_FILES['ufile']['name'][0]."<BR/>";?></td> <td><? echo "File Name :".$_FILES['ufile']['name'][1]."<BR/>";?></td> <td><? echo "File Name :".$_FILES['ufile']['name'][2]."<BR/>";?></td> <td><? echo "File Name :".$_FILES['ufile']['name'][3]."<BR/>";?></td> <td><? echo "File Name :".$_FILES['ufile']['name'][4]."<BR/>";?></td> </tr> <tr> <td><?echo "File Size :".$_FILES['ufile']['size'][0]."<BR/>";?></td> <td><?echo "File Size :".$_FILES['ufile']['size'][1]."<BR/>";?></td> <td><?echo "File Size :".$_FILES['ufile']['size'][2]."<BR/>";?></td> <td><?echo "File Size :".$_FILES['ufile']['size'][3]."<BR/>";?></td> <td><?echo "File Size :".$_FILES['ufile']['size'][4]."<BR/>";?></td> </tr> <tr> <td><? echo "File Type :".$_FILES['ufile']['type'][0]."<BR/>";?></td> <td><? echo "File Type :".$_FILES['ufile']['type'][1]."<BR/>";?></td> <td><? echo "File Type :".$_FILES['ufile']['type'][2]."<BR/>";?></td> <td><? echo "File Type :".$_FILES['ufile']['type'][3]."<BR/>";?></td> <td><? echo "File Type :".$_FILES['ufile']['type'][4]."<BR/>";?></td> </tr> </table> </body> </html> <? $filesize1=$_FILES['ufile']['size'][0]; $filesize2=$_FILES['ufile']['size'][1]; $filesize3=$_FILES['ufile']['size'][2]; $filesize4=$_FILES['ufile']['size'][3]; $filesize5=$_FILES['ufile']['size'][4]; if($filesize1 && $filesize2 && $filesize3 && $filesize4 && $filesize5 != 0) { echo "We have recieved your files<p>"; } else { echo "Error in you images check and try again Database has been updated to blank images so no images will be shown on details page."; } $query = "UPDATE $db_table SET thumbnail = '".$_FILES['ufile']['name'][0]."', image1 = '".$_FILES['ufile']['name'][1]."', image2 = '".$_FILES['ufile']['name'][2]."', image3 = '".$_FILES['ufile']['name'][3]."', image4 = '".$_FILES['ufile']['name'][4]."' WHERE id = '".$_GET['id']."'"; if (!mysql_query($query,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ?> Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. I created this code to upload a member's main picture on his member page on website. I'll only include the query part of the code since that's what is relevant to my problem. The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page. If a picture already exists, then the script replaces the old picture with the new one upon upload. But for whatever reason I don't understand, when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select] $query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { //Update the image $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); $_SESSION['error'] = "File updated successfully."; //really should be session success message. header("Location: member.php"); exit; } else { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); $_SESSION['error'] = "File uploaded succussfully."; //really should be session success message. header("Location: member.php"); } So can anyone tell me what the problem is? Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup? Appreciate your responses in advance. I'm new to PHP and I was able to figure out how to populate data from my database into my text fields. I am trying to add the update information to the same php file; however, I am now receiving errors within the data I was able to populate,
Notice: Undefined variable: stmt in C:\xampp\htdocs\Cust_App\update.php on line 47 and errors with the Update statement
Notice: Undefined variable: stmtupdate in C:\xampp\htdocs\Cust_App\update.php on line 96 I had defined the customerID variable above in the code, but it isn't being captured from here. I tried setting up this query like the one which gathered the data, but I'm off by a little bit. I would like the option to be able to update all fields. Any help is appreciated. I'm trying to learn as I may get asked to update other forms in the future. (new boss asks a lot)
<?php
require_once('database.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<!-- the head section -->
<head>
<title>My Guitar Shop</title>
<link rel="stylesheet" type="text/css" href="main.css" />
</head>
<!-- the body section -->
<body>
<div id="page">
<div id="header">
<h1>SportsPro Technical Support</h1>
<p>Sports management software for the sports enthusiast.</p></h1>
</div>
<div id="main">
<h1>View/Update Customer</h1>
<form action="update.php" method="get" >
<?php
if(isset($_GET['customerID'])) {
$customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT);
$sql = "SELECT * FROM customers WHERE customerID =$customerID ";
$stmt = $db->query($sql);
}
?>
<div id="content">
<!-- display a table of products -->
<h2>Customers</h2>
<form method = "edit">
<?php foreach ($stmt as $cust) { ?>
<div>
<label>First Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['firstName']; ?>">
</div><br>
<div>
<label>Last Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['lastName']; ?>">
</div><br>
<div>
<label>Address</label>
<input type="text" name="address" class ="form-control" value ="<?php echo $cust['address']; ?>">
</div><br>
<div>
<label>City</label>
<input type="text" name="city" class ="form-control" value ="<?php echo $cust['city']; ?>">
</div><br>
<div>
<label>State</label>
<input type="text" name="state" class ="form-control" value ="<?php echo $cust['state']; ?>">
</div><br>
<div>
<label>Country</label>
<input type="text" name="countryCode" class ="form-control" value ="<?php echo $cust['countryCode']; ?>">
</div><br>
<div>
<label>Zip Code</label>
<input type="text" name="postalCode" class ="form-control" value ="<?php echo $cust['postalCode']; ?>">
</div><br>
<div>
<label>Email </label>
<input type="text" name="email" class ="form-control" value ="<?php echo $cust['email']; ?>">
</div><br>
<div>
<label>Phone Number </label>
<input type="text" name="phone" class ="form-control" value ="<?php echo $cust['phone']; ?>">
</div><br>
<div>
<label>Password </label>
<input type="text" name="password" class ="form-control" value ="<?php echo $cust['password']; ?>">
</div><br>
<div>
<?php }
?>
<input type="Submit" name="Update_Data" value="Update Data"></input>
<?php
$sql2 = "UPDATE customers SET firstName = ". $stmtupdate['firstName']." WHERE customerID =$customerID ";
$stmtupdate = $db->query($sql2);
?>
</div>
</div>
<div id="footer">
<p>
© <?php echo date("Y"); ?> SportsPro, Inc.
</p>
</div>
</div><!-- end page -->
</body>
</html>
Hi Guys, I want my UPDATE function from the code below to only update those fields that are NOT empty - if they are empty on submit then do not update or change any values from that field. I know that sounds odd, but with my file fields, when I submit to change something else at a later date it will overwrite the photo, download1,2 & 3 values and as a result I loose my files from the mysql table. Cheers, S <?php include('config.php'); if (isset($_GET['Ter']) ) { $ter = (int) $_GET['Ter']; if (isset($_POST['submitted'])) { //Photo & Document Upload Upload $timestamp_photo = time(); $timestamp_download1 = time(); $timestamp_download2 = time(); $timestamp_download3 = time(); //This is the directory where the files will be saved //Photos $photo_target = "images/"; $photo_target = $photo_target .$timestamp_photo. basename( $_FILES['photo']['name']); //Documents $download_target = "documents/"; $download_target1 = $download_target .$timestamp_download1. basename( $_FILES['download1']['name']); $download_target2 = $download_target .$timestamp_download2. basename( $_FILES['download2']['name']); $download_target3 = $download_target .$timestamp_download3. basename( $_FILES['download3']['name']); //This gets all the other information from the form $photo = ($_FILES['photo']['name']); $download1 = ($_FILES['download1']['name']); $download2 = ($_FILES['download2']['name']); $download3 = ($_FILES['download3']['name']); //Pause Photo/Document Upload foreach($_POST AS $key => $value) { $_POST[$key] = mysql_real_escape_string($value); } $sql= "UPDATE `ter` SET `Ter` = '{$_POST['Ter']}' , `BranchName` = '{$_POST['BranchName']}' , `BranchAddress` = '{$_POST['BranchAddress']}' , `BranchTel` = '{$_POST['BranchTel']}' , `BranchEmail` = '{$_POST['BranchEmail']}' , `BranchLink` = '{$_POST['BranchLink']}' , `Theme` = '{$_POST['Theme']}' , `LocalInfo` = '{$_POST['LocalInfo']}' , `BranchInfo` = '{$_POST['BranchInfo']}' , `photo` = '$timestamp_photo{$_FILES['photo']['name']}' , `download1` = '$timestamp_download1{$_FILES['download1']['name']}' , `download1name` = '{$_POST['download1name']}' , `download2` = '$timestamp_download2{$_FILES['download2']['name']}' , `download2name` = '{$_POST['download2name']}' , `download3` = '$timestamp_download3{$_FILES['download3']['name']}' , `download3name` = '{$_POST['download3name']}' WHERE `Ter` = '$ter' "; mysql_query($sql) or die(mysql_error()); //Unpause Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $photo_target)) { echo "<br />The file ".$timestamp_photo. basename( $_FILES['photo']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download1']['tmp_name'], $download_target1)) { echo "<br />The file ".$timestamp_download1. basename( $_FILES['download1']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download2']['tmp_name'], $download_target2)) { echo "<br />The file ".$timestamp_download2. basename( $_FILES['download2']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download3']['tmp_name'], $download_target3)) { echo "<br />The file ".$timestamp_download3. basename( $_FILES['download3']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload echo (mysql_affected_rows()) ? "<br />Edited Branch.<br />" : "<br />Nothing changed. <br />"; } $row = mysql_fetch_array ( mysql_query("SELECT * FROM `ter` WHERE `Ter` = '$ter' ")); ?> Good morning. I am looking fo some help with an update script to update all rows in a table. This is what I have for a form and all looks well. form.php <?php // run the query and put the results in an array variable called $result $result = mysql_query("SELECT * FROM table ORDER BY 'id', 'title', 'text', 'number'"); print "<form method='post' action='update.php'> <table width='100%' border='0' cellspacing='1' cellpadding='1'><tr> <td align='center'><strong>ID</strong></td> <td align='center'><strong>Title</strong></td> <td align='center'><strong>text</strong></td> <td align='center'><strong>Number</strong></td> </tr>\n"; // start a loop to print all of the courses with their book information // the mysql_fetch_array function puts each record into an array. each time it is called, it moves the array counter up until there are no more records left while ($Update = mysql_fetch_array($result)) { // start displaying the info; the most important part is to make the name an array (notice bookinfo[$i]) print "<td align='center'><p>{$Update['id']}</p></td>\n"; print "<td align='center'><input type='text' name='title' value='{$Update['title']}' /></td>"; print "<td align='center'><input type='text' size='40' name='text' value='{$Update['text']}' /></td>\n"; print "<td align='center'><input type='text' size='40' name='number' value='{$Update['number']}' /></td>\n"; print "</tr>\n"; // add 1 to the count, close the loop, close the form, and the mysql connection } print "<tr> <td colspan='4' align='center'><input type='submit' value='submit' />"; print "</td> </tr> </table> </td> </tr> </form> </table>"; print "</tr>\n"; ?><br /><br /> My question is. How do I update this info into the database with the proper info. ie. Update.php? As the title says I need help with multiple update system.. Can't really get it to work at all >.< Here's some code: $selectt = mysql_query("SELECT * FROM exercises WHERE user='" . $_SESSION["user"] . "' AND exname='" . $_GET["edit"] . "'"); echo '<form method="POST" action="exercises.php?edited">'; echo '<div id="newexx">'; while($raw = mysql_fetch_array($selectt)) { echo '<input type="text" name="up[' . $raw["id"] . ']" value="' . $raw["swe"] . '">'; echo '<input type="text" name="up1[' . $raw["id"] . ']" value="' . $raw["eng"] . '"><br>'; echo '<input type="hidden" name="id[' . $raw["id"] . ']">'; } echo '</div>'; echo '<input type="submit" value="Update Exercise">'; echo '</form>'; if(isset($_GET["edited"])) { $swe = $_POST["up"]; $eng = $_POST["up1"]; $id = $_POST["id"]; foreach($id as $value => $index) { $update = "UPDATE exercises SET swe='".$swe."', eng='".$eng."' WHERE id='".$index."'"; mysql_query($update); } Would be thankful for reply! Hi all, I have a script that is supposed to upload an image and then update a field in the table with the image's path in it. The image uploads okay but the details do not UPDATE in the table... any ideas? I have echoed after the sql statement which doesn't appear upon submitting but it shows the query printed out doing the right thing (I think) Quote UPDATE `fleet` SET `fleetimage4` = '../fleet/last.JPG' WHERE `fleetref` = '9' LIMIT 1 Code: [Select] <?php $ref = (!empty($_GET['ref']))?trim($_GET['ref']):""; $image = (!empty($_GET['image']))?trim($_GET['image']):""; $idir = "../fleet/"; // Path To Images Directory if (isset ($_FILES['fupload'])){ //upload the image to tmp directory $url = $_FILES['fupload']['name']; // Set $url To Equal The Filename For Later Use if ($_FILES['fupload']['type'] == "image/jpg" || $_FILES['fupload']['type'] == "image/jpeg" || $_FILES['fupload']['type'] == "image/pjpeg") { $file_ext = strrchr($_FILES['fupload']['name'], '.'); // Get The File Extention In The Format Of , For Instance, .jpg, .gif or .php $copy = copy($_FILES['fupload']['tmp_name'], "$idir" . $_FILES['fupload']['name']); // Move Image From Temporary Location To Permanent Location } } if (isset($_POST['submit'])){ //$fleetref=$_POST["fleetref"]; $fleetimage1 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); $fleetimage2 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); $fleetimage3 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); $fleetimage4 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); # setup SQL statement if ($image == "1") { $query = sprintf("UPDATE `fleet` SET `fleetimage1` = '$fleetimage1' WHERE `fleetref` = '$ref' LIMIT 1"); } else if ($image == "2"){ $query = sprintf("UPDATE `fleet` SET `fleetimage2` = '$fleetimage2' WHERE `fleetref` = '$ref' LIMIT 1"); } else if ($image == "3"){ $query = sprintf("UPDATE `fleet` SET `fleetimage3` = '$fleetimage3' WHERE `fleetref` = '$ref' LIMIT 1"); } else if ($image == "4"){ $query = sprintf("UPDATE `fleet` SET `fleetimage4` = '$fleetimage4' WHERE `fleetref` = '$ref' LIMIT 1"); } #execute SQL statement echo "before exe"; $result = mysql_db_query($db,$query,$cid) or die($query."<br>".mysql_error()); echo "after exe"; # check for error if (!$result){ echo("ERROR: " . mysql_error() . "\n$SQL\n"); }} ?> <div class="controls_left"> <FORM NAME="fa" ACTION="<?php echo "fleet_edit_image.php?ref=$ref&image=$image"; ?>" METHOD="POST" enctype="multipart/form-data"> <input type = "hidden" name="MAX_FILE_SIZE" value = "1000000"> Select image: <input type = "file" name = "fupload"> <p>Copyright note: Please only use photographs either that you have taken yourself or that you have permission to use as we will not be held responsible for any Copyright infringement.</p> <input name="submit" type="submit" value="Edit image" /> </FORM> </div> <div class="image_right"><?php if ($image == "1") { $imageprint = "$fleetimage1"; } else if ($image == "2") { $imageprint = "$fleetimage2"; } else if ($image == "3") { $imageprint = "$fleetimage3"; } else if ($image == "4") { $imageprint = "$fleetimage4"; } echo "<div class=\"image_right\"><img src=\"../$imageprint\" alt=\"Edit image\" width=\"293\" height=\"218\"></div>"; ?> Please help me with this: been doing this for 2 days and still cannot solve it. it won't update... I have attached my file: <?php include('connect-database.php'); if (isset($_POST['submit']) AND $_POST['submit'] == 'update') { $error = false; extract($_POST); if (empty($full_name)) $error = true; if (!$error) { $update = "UPDATE users SET full_name = '$full_name', WHERE id=$id "; mysql_query($update) or die(mysql_error() . "<br><br>" . $update); $full_name = ''; $message = "Record successfully updated."; } else { $message = "There is an error in your entry"; } } else { $id = intval(isset($_GET['id']) ? $_GET['id'] : 0); } if ($id == 0) { echo "<div style='margin-bottom:10px'>Invalid ID.</div>"; exit; } $query = "SELECT * FROM users WHERE id=$id"; $result = mysql_query($query) or die(mysql_error() . "<br><br>" . $query); if (mysql_num_rows($result) == 0) { echo "<div style='margin-bottom:10px'>Record Not Found in Database!</div>"; exit; } $row = mysql_fetch_array($result); extract($row); ?> <div id="mainContent" class="tab_container"> <div id="tab1" class="tab_content"> <h1>Edit Personal Data</h1> <div style="color:red;font-weight:bold"><? echo $message; ?></div> <form name="submit" action="" method="post"> <ul> <li><b>ID # :</b> <?php echo $id?></li> <li><b>Name :</b> <input type="text" name="full_name" id="" size="30" value="<?php echo $full_name ?>" /></li> <li><b>Address :</b> <input type="text" name="address" id="" size="55" maxlength="100" value="<?php echo $address ?>" /></li> <li><b>Contact Number :</b> <input type="text" name="contact_number" id="" size="11" value="<?php echo $contact_number ?>" /></li> <li><b>Email Address :</b> <input type="text" name="user_email" id="" size="30" value="<?php echo $user_email ?>" /></li> <li><b>Status :</b> <input type="text" name="status" id="" size="10" value="<?php echo $status ?>" /></li> <li><b>Nationality :</b> <input type="text" name="nationality" id="" size="20" value="<?php echo $nationality ?>" /></li> <li><b>Religion :</b> <input type="text" name="religion" id="" size="20" value="<?php echo $religion ?>" /></li> </ul> <h2>Self Description</h2> <p><textarea rows="9" cols="40" name="self_description" ><?php echo $self_description ?></textarea></p> <input type="hidden" name="id" value="<?php echo $id; ?>" /> <input type="submit" name="submit" value="update" /> </form> </div> hi , i want to make 5 forms with 1 submit button , how i do that? thanks , Mor. How i can delete record from table `order` and move it to `order2`
the table `order2` structure is exactly like table `order`.here is the code that i made.
<?
include("connection.php");
$id_product=$_GET["pid"];
$sql_delete="DELETE FROM `order` WHERE id_product='$id_product'";
$result=mysql_query($sql_delete) or die("Error in sql due to ".mysql_error());
if ($result)
header("Location: order_list.php");
?>
hello, is there a way to insert something 17 times into a database and change the 3rd field one at a time (from 1-17)? Code: [Select] $sql = "INSERT INTO picks VALUES ( NULL, '" . mysql_real_escape_string($userid) ."', '" . mysql_real_escape_string($weekid) ."', '" . mysql_real_escape_string($pickid) ."' )"; mysql_query($sql) or die('Error, Check you fields and try again.'); Hi Chaps, I'm trying to put together a Nested Set Model (Hierarchical Data), but I have having problems when it comes to deleting/updating the 'nested' table. I'm using this as a guide: http://dev.mysql.com/tech-resources/articles/hierarchical-data.html But when trying to run a query, such as: SELECT @myLeft := lft, @myRight := rgt, @myWidth := rgt - lft + 1 FROM nested_category WHERE name = 'GAME CONSOLES'; DELETE FROM nested_category WHERE lft BETWEEN @myLeft AND @myRight; UPDATE nested_category SET rgt = rgt - @myWidth WHERE rgt > @myRight; UPDATE nested_category SET lft = lft - @myWidth WHERE lft > @myRight; I get a MySQL syntax error. This code works fine in something such as Windows Command Prompt, but not in PHP. Is there a special way to run multiple queries in 1 PHP script? Many thanks common.php Code: [Select] <?php session_start(); header('Cache-control: private'); // IE 6 FIX if(isSet($_GET['lang'])) { $lang = $_GET['lang']; // register the session and set the cookie $_SESSION['lang'] = $lang; setcookie("lang", $lang, time() + (3600 * 24 * 30)); } else if(isSet($_SESSION['lang'])) { $lang = $_SESSION['lang']; } else if(isSet($_COOKIE['lang'])) { $lang = $_COOKIE['lang']; } else { $lang = 'en'; } switch ($lang) { case 'en': $lang_file = 'lang.en.php'; break; case 'de': $lang_file = 'lang.de.php'; break; case 'el': $lang_file = 'lang.el.php'; break; default: $lang_file = 'lang.en.php'; } include_once 'languages/'.$lang_file; ?> ip2locationlite.class.php Code: [Select] <?php final class ip2location_lite{ protected $errors = array(); protected $service = 'api.ipinfodb.com'; protected $version = 'v3'; protected $apiKey = ''; public function __construct(){} public function __destruct(){} public function setKey($key){ if(!empty($key)) $this->apiKey = $key; } public function getError(){ return implode("\n", $this->errors); } public function getCountry($host){ return $this->getResult($host, 'ip-country'); } public function getCity($host){ return $this->getResult($host, 'ip-city'); } private function getResult($host, $name){ $ip = @gethostbyname($host); if(preg_match('/^(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:[.](?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}$/', $ip)){ $xml = @file_get_contents('http://' . $this->service . '/' . $this->version . '/' . $name . '/?key=' . $this->apiKey . '&ip=' . $ip . '&format=xml'); try{ $response = @new SimpleXMLElement($xml); foreach($response as $field=>$value){ $result[(string)$field] = (string)$value; } return $result; } catch(Exception $e){ $this->errors[] = $e->getMessage(); return; } } $this->errors[] = '"' . $host . '" is not a valid IP address or hostname.'; return; } } ?> index.php Code: [Select] <?php include_once('ip2locationlite.class.php'); //Set geolocation cookie if(!$_COOKIE["geolocation"]){ $ipLite = new ip2location_lite; $ipLite->setKey('*****************'); $visitorGeolocation = $ipLite->getCountry($_SERVER['REMOTE_ADDR']); if ($visitorGeolocation['statusCode'] == 'OK') { $data = base64_encode(serialize($visitorGeolocation)); setcookie("geolocation", $data, time()+3600*24*7); //set cookie for 1 week } }else{ $visitorGeolocation = unserialize(base64_decode($_COOKIE["geolocation"])); } var_dump($visitorGeolocation); ?> im using this http://ipinfodb.com/ in index.php i got this message array(5) { ["statusCode"]=> string(2) "OK" ["statusMessage"]=> string(0) "" ["ipAddress"]=> string(13) "94.68.211.211" ["countryCode"]=> string(2) "GR" ["countryName"]=> string(6) "GREECE" } how to switch automatic if GR go to index.php?lang=el if DE go to index.php?lang=de etc... hello all, i have been sitting here googleing and googling but i can't seem to find what im looking for. i am tring to create a personal site that lets me note services i do for my cars. I have multiple tables (cars, color, mfg, ...) in the main table cars i insted of putting the color black i put and int(11) of 1 which is suppose to "if statement" to the table colors and produce the correct color. same for mfg. although nothing i have tried has helped i always just have the else of the if echoed out. i have heard of union and join left right i am so unsure of what is need any insite would be useful. thanks in advance. |
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