PHP - Preg_match() - Wrong Match To The Regular Expression Given In Pattern

Can anyone help me. I have very little knowledge about programming and coding and php, but I am tutoring myself on these.

I want to write a code that will search for a movie in this website search =>
http://myandyourface.com/DELETE/imdb-poster.php. NOTE: in searching for the movie, the movie name with more than one word can be type in in combination form by using the + sign. For example, the movie "the vow", typing that into the search box will be so => the+vow.

As an example, I got the result as show below:

{"Title":"The Vow","Year":"2012","Rated":"PG-13","Released":"10 Feb 2012","Genre":"Drama, Romance","Director":"Michael Sucsy","Writer":"Jason Katims, Abby Kohn","Actors":"Rachel McAdams, Channing Tatum, Sam Neill, Jessica Lange","Plot":"A car accident puts Paige (McAdams) in a coma, and when she wakes up with severe memory loss, her husband Leo (Tatum) works to win her heart again.","Poster":"http://ia.media-imdb.com/images/M/MV5BMjE1OTU5MjU0N15BMl5BanBnXkFtZTcwMzI3OTU5Ng@@._V1_SX320.jpg","Runtime":"N/A","Rating":"N/A","Votes":"N/A","ID":"tt1606389","Response":"True"}

So, this is what I wanted to do,
I wanted to write a php code expression that will search for a specific movie and provide the result as above,and then using the regex and str_replace, and others, I will be able to remove all the above detail information and have ONLY the image link as in above, which is => http://ia.media-imdb.com/images/M/MV5BMjE1OTU5MjU0N15BMl5BanBnXkFtZTcwMzI3OTU5Ng@@._V1_SX320.jpg

I will appreciate any help in creating a code for this

Thanks!

Hey

I'm pretty new to regular expression, so I might have made a silly mistake. I want to check if there are any symbols/special characters (not letters or numbers) in a string. I have the code below.


function validateKeywords($kw) {
if (preg_match("/[^A-Za-z0-9]/", $kw)) {
echo 'validation of keywords failed<br />';
return false; // String contains symbols (not letters or numbers) - incorrect format!
}
else {
echo 'validation of keywords succeeded<br />';
return true; // Correct format
}
}

// Testing
validateKeywords('some random string I wrote for testing purposes'); // should succeed
validateKeywords('some random 10 string I wrote for testing purposes 2010'); // should succeed
validateKeywords('some random, string, I wrote for 19 testing purposes'); // should fail
validateKeywords('some, random, string I wrote, for testing purposes'); // should fail


The problem is that all 4 calls return false and print that the validation failed. So, where did I mess up?

Thanks!

Hi people,  i need to find 16x150gr in Dried Pomegranate Arils16x150gr but the format can vary from Mt Ceder Balsamic Vinegar 12x250ml to Mt Ceder Balsamic Vinegar 2x2ltr to Dried Kalamata Olives 4x1kg. i guess you got the drift i tried something like : '/[1-9]+x[1-9]+[a-z]+/' but i am so useless at regex.   Thank you!

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Hi,

I've got a form where the user submits a date as a text field (as 12-12-2012 for example) called closing. The form submits fine without my regular expression validation, but whenever I try to validate it, it returns the error message I wrote for if no results turn up. Ive tried:
Code: [Select]
<?php if (!preg_match ("[0-9]{2}-[0-9]{2}-[0-9]{4}", $_POST["closing"]))
  {

                $_SESSION["report"] = "<b>Error:</b> Date is in the wrong format. It must be dd-mm-yyyy<br />";
$_SESSION["reportcount"] = 0; 

        }
?>

and Code: [Select]
<?php
if (!preg_match ("\d{2}-\d{2}-\d{4}", $_POST["closing"]))
  {

                $_SESSION["report"] = "<b>Error:</b> Date is in the wrong format. It must be dd-mm-yyyy<br />";
$_SESSION["reportcount"] = 0; 

        }
?>
Any ideas?

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Hi; i would like to search for a regular expression to grab all printf occurences including the folowing senarios :

   printf("something");

   printf("something", variables);

   printf("something", variables, 
       variables);

   printf("something);something",
       variables, variables);

To simplify the third and fourth cases, the regex should start from printf(" and go intil it find ); with a white space after it. But i didn't realise how to do it. This trick should work also for the first and second case. Thanks
Edited by Dareros, 26 September 2014 - 01:27 PM.

Hi

i want to match $ symbol from the string. I am using the following script

Code: [Select]
$str="ckj";
if(preg_match("/^$/",$str))
{
echo "Dollar is found";
}
else
{
echo "Not Found";
}

Its not working fine. Can anyone help me out please.

<?php
$user = $_GET['user'];
$request_url ="http://www.domain.com/logs.shtml";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $request_url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);

//THIS NEEDS CHANGED!!!!!
$regex='|$user - (.*?) - $user|';

preg_match_all($regex,$result,$parts);
$logs=$parts[1];
foreach($logs as $log){
echo "<B>".$log."</B><br>";
}
curl_close($ch);
?>

The logs file looks like

username - log info - log info - log info - username

For a URL like

http-//www.domain.com/view-logs.php?user=strago

I want it to spit out just the lines from the log file that got

strago - log info - log info - log info - strago

I have a field called full_name and it has John Smith as a value.
I want to take John and put it to the first_name field and Smith to the last_name field.

How do I do this, knowing that the first and last name are separateed by a space?

Here's a query I did that does the same thing when they are separated by a COMMA, but I am not familiar with regular expressions enough to modify it to include  space instead :-)


$newlastname = $row['full_name'];
if (preg_match('/^[^,]+(?=,)/', $row['full_name'], $match)) {
     $newlastname = $match[0];
}

list($newlastname,$newfirstname) = explode(',',$row['full_name']);