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PHP - Rss Feed Wont Show
Hey everyone,
Calling all web devs, so here is my problem from the gecko. I am currently using a free flux theme. The problem is that it has a rss feed news box. I have phpbb forums and i used the link and it wont show. I'm not sure why i did alot of research and it seems it happens because my forums use a php based feed. I do not know how to merge it with the default rsslib.php file that is already there or how to even begin to edit it so it displays correctly on the page. Below is the theme I'm currently using along with a screenshot of the coding for the rsslib.php.
Theme used - Free Flux Green Theme
Screenshots
The index.php importing the rsslib.php coding Spoiler Similar Tutorialseverything seems to be working fine except the form wont show up. the site is here http://davisgutierrez.com/testing_area/form.php <?php if($_POST['formSubmit'] == "Submit") { if(empty($_POST['formName'])) { $errorMessage .= "<li>You forgot to enter your Name.</li>"; } if(empty($_POST['address'])) { $errorMessage .= "<li>You forgot to enter your address.</li>"; } if(empty($_POST['city'])) { $errorMessage .= "<li>You forgot to enter your city.</li>"; } if(empty($_POST['state'])) { $errorMessage .= "<li>You forgot to enter your state.</li>"; } if(empty($_POST['zip'])) { $errorMessage .= "<li>You forgot to enter your zip code.</li>"; } if(empty($_POST['phone'])) { $errorMessage .= "<li>You forgot to enter your phone number.</li>"; } if(empty($_POST['email'])) { $errorMessage .= "<li>You forgot to enter your email.</li>"; } } $varformName = $_POST['formName']; $varaddress = $_POST['address']; $varcity = $_POST['city']; $varstate = $_POST['state']; $varzip = $_POST['zip']; $varphone = $_POST['phone']; $varemail = $_POST['email']; //generated by fatcow $link = mysql_connect(''); if (!$link) { die('Could not connect: ' . mysql_error()); } echo 'Connected successfully'; $db_selected = mysql_select_db("learnphp"); if (!$db_selected) { die(' blast!' . mysql_error()); } if(!empty($errorMessage)) { echo("<p>There was an error with your form:</p>\n"); echo("<ul>" . $errorMessage . "</ul>\n"); } $fs = fopen("memberdata.csv","a"); fwrite($fs,$varformName . ", " . $varAddress . ", " . $varCity . "," . $varState . "," . $varZip . "," . $varPhone . "," . $varEmail . "," . "/n"); fclose($fs); //header("Location: thankyou.html"); exit; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> <head> <title>membership test</title> </head> <body> <?php if(!empty($errorMessage)) { echo("<p>There was an error with your form:</p>\n"); echo("<ul>" . $errorMessage . "</ul>\n"); } ?> <form action="form.php" method="post" name="ohta_membership_application" > Name: <input type="text" name="formName" maxlenghth="45" value="<?=$varformName;?>" /> Address: <input type="text" name="address" maxlenghth="4" value="<?=$varAddress;?>" /> City: <input type="text" name="city" maxlenghth="4" value="<?=$varCity;?>" /> State: <input type="state" name="state" maxkength="2" value="<?=$varState;?>"> Zip: <input type="text" name="zip" maxlenghth="4" value="<?=$varZip;?>" /> Phone: <input type="text" name="phone" maxlenghth="4" value="<?=$varPhone;?>" /> Email: <input type="text" name="email" maxlenghth="4" value="<?=$varEmail;?>" /> <input type="submit" name="formSubmit" value="Submit" /> <input type="reset" name="reset" value="Reset" > </form> </body> </html> Hi, I just cannot seem to get this to work, have been testing and searching all morning and not getting anywhere. I have a form with a series of checkboxes which populates the MySqL database, this works fine. Trying to print the results from the form if the row is empty show an unchecked checkbox, if there is a value show a checked checkbox. I have tested my if statement and can echo correctly wether empty or not empty, just cannot get the checkbox to be unticked if there is no value in the row Code: [Select] while ($row = mysql_fetch_array($qry, MYSQL_BOTH)) { // show total fields for debugging // $totalfields = mysql_num_fields($qry); // print ($totalfields) ; // if ( ! empty ( $row ['acid_wash'] ['neutralise'] ['clean'] ) ) { if ( ! empty ( $row ['clean'] ) ) { ///if it's 1 (true) then we add 'checked' to a variable we will use in the input //to cause it to be checked $checked = 'checked'; // test if row has data echo "full"; }else{ //if the value is 0 (false) we set the variable to be empty, not checked $checked = ''; // test for no value echo "empty" ; } To Display Result: <tr> <td>High Pressure Clean <input style='font-size:10px;' name='clean[]' type='checkbox' checked='$checked'></td> </tr> The empty and full test echos do seem to work, showing me the if statement works. The problem is even when the row is empty the checkbox shows checked.... Thanks. i need help trying to get this delete feature to work its not deleting from the database (by the way i took out my database names and passwords at the top of the file) is it possible someone could help me, ive been working on this for like a week and cant figure out the problem. thanks! you can email me at spr_spng@yahoo.com picture 2.png is showing what it looks like Code: [Select] <?php $host="localhost"; // Host name $username="username"; // Mysql username $password="password"; // Mysql password $db_name="database_name"; // Database name $tbl_name="table_name"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); $count=mysql_num_rows($result); ?> <style> /*table affects look of the whole table look */ table { margin-left: auto; margin-right: auto; border: 1px solid #330000; border-collapse:collapse; width:70%; border-width: 5px 5px 5px 5px; border-spacing: 1px; border-style: outset outset outset outset; border-color: #330000 #330000 #330000 #330000; border-collapse: separate; background-color: #330000; #800517 f535aa #330000 school color #9A0000 school color2 #991B1E school color3 #CCCC99 school color4 #9A0000 } /*th is table header */ th { text-align: left; height: 2.5em; background-color: #330000; color: #FC0; font-size:1.5em; } /*td is table data or the cells below the header*/ td { text-align: left; height:1.0em; font-size:1.0em; vertical-align:bottom; padding:10px; border-width: 5px 5px 5px 5px; padding: 8px 8px 8px 8px; border-style: outset outset outset outset; border-color: #9A0000 #9A0000 #9A0000 #9A0000; background-color: #CCCC99; -moz-border-radius: 0px 0px 0px 0px; } </style> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td><form name="form1" method="post" action=""> <table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td bgcolor="#FFFFFF"> </td> <td colspan="4" bgcolor="#FFFFFF"><strong>Pick Which Rows you want to delete, Then press delete.</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Name</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Lastname</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF">delete</td></tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['name']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['lastname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <? // Check if delete button active, start this // edited if($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysql_query($sql); } // if successful redirect to delete_multiple.php if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">"; } } mysql_close(); ?> </table> </form> </td> </tr> </table> I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith. The cookie doesn't show if I go to that url page. But it does show up once I reload the page. So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page? Here is my code.
// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);
if(!empty($url_ref_name)) {
$number_of_days = 365;
$date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
setcookie( "ref", $url_ref_name, $date_of_expiry,"/");
} else if(empty($url_ref_name)) {
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
}
} else {}
// This is for the sign up form
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
?>
<fieldset>
<label>Referred By</label>
<div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
<input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
</fieldset>
<?php
}
I'm lost on this one. This code works fine in Firefox, but not my IE8. I think it has something to do with the <?php echo '<?xml version="1.0" encoding="utf-8"?>'; ?> line, but i'm not sure. IE says "Internet Explorer cannot display this feed" and "A name contained an invalid character. Line: 7 Character: 701." Any ideas? <?php header('Content-Type: text/xml'); ?> <?php echo '<?xml version="1.0" encoding="utf-8"?>'; ?> <?php include('../vars.php'); ?> <rss version="2.0"> <channel> <title>Newsfeed</title> <description>News and Updates</description> <link>http://www.example.com</link> <language>en-us</language> <?php require_once("../conn.php"); $query = "SELECT * FROM news"; $data = mysqli_query($db, $query); while ($row = mysqli_fetch_array($data)) { echo '<item>'; echo ' <title>' . $row['title'] . ' - ' . substr($row['content'], 0, 32) . '...</title>'; echo ' <link>http://www.example.com/new.php?newsid=' . $row['newsid'] . '</link>'; //echo ' <pubDate>' . $row['date'] . '</pubDate>'; echo ' <description>' . $row['content'] . '</description>'; echo '</item>'; } ?> </channel> </rss> Hi I get an error when trying to add a link to my rss feed Code: [Select] <link>http://www.jobjar.co.uk/jobdetails.php?keywords=lon0014&page=1</link>Something to do with the last part of the link because when I remove the page=1 it then works. How can I resolve this? Also, will I have to manually update my xml file for rss feeds or can it be updated automatically? If so how? Thanks Hi All, I'm trying to incorporate a BBC Sport RSS Feed into my website. The following code will show me the news feeds as text and I can include the url's as text also but want to turn this into a clickable url. How do I do this, I cant work it? please help. $feed_url = "http://newsrss.bbc.co.uk/rss/sportonline_uk_edition/football/teams/s/shrewsbury/rss.xml"; // Get data from feed file $response = file_get_contents($feed_url); // Insert XML into structure $xml = simplexml_load_string($response); // Browse structure foreach($xml->channel->item as $one_item) echo $one_item->title."<BR>"; I am displaying rows from a database onto a page using: while($row=mysql_fetch_array($query)){ echo $row['name']; } I need to figure out how to limit the rows shown to the page to 100. And if there are 100 rows on the page, a link will be displayed at the bottom, that says "Next 100". Then this will display the next 100 rows. Can you give an example how to do this please? Thanks Hello all That forum is my last desperate attemp to do what i want to do. Ok here is the story I want to create a simple rss feed in conjuction with php and mysql. I dont want admin areas ect , i just want when i insert a new listing to my database to be able shown up to my (future) rss subscribers. To be more technically specific i want to show to my surfers updates about 2 tables in my database not all the tables. The example i found so far were about only 1 table, plus i was encounting errors to my script. I would like some ideas, directions if someone is kind enough to help a sad developer Thanks in advance! I have a php script that saves some data as a .xml document. When I view this in my browser I can subscribe to the feed (I am using firefox). However I asked someone else to see if they could subscribe (they were using IE) but the couldn't. Therefore how can users subscribe to my feed? Will only some be able to subscribe? Thanks for any help. Hello! I'm trying to develop some kind of RSS news aggregator and I want to show only feeds younger than 1day. I figured i could transform RSS pubDate to timestamp (strtotime()), but there are some feeds without timestamp (like: http://izklop.com/xmldata/rsslinks.xml). Is there any other way to do it, so I could find timestamp from those feeds without pubdate? If there isn't any other way, do You think it is ok, to just show last 5 feeds? I hope I made my self clear, and please forgive me for my English I'm been searching and can't seem to figure this out. I want to take an RSS feed from a news site and display it on my site. any help? Hi, I have a small piece of code that creates an RSS feed using a mysql database. The issue is the page itself is blank however if I right click and view source I can see all the feed there. I convert the dat time field into a standard RSS date field. The web address is http://vinovote.com/news/feed.php My code is as follows Code: [Select] <?php echo '<?xml version="1.0" encoding="UTF-8"?>'; ?> <rss version="2.0"> <channel> <title>Vinovote.com</title> <description>The Latest News And Views From Around The Web</description> <link>http://www.vinovote.com/</link> <copyright>Your copyright information</copyright> <?php require_once('../Connections/connection.php'); mysql_select_db($database_vinovotedb, $vinovotedb); $doGet = mysql_query("SELECT feed_content.feed_content_id, feed_content.feed_id, feed_content.url, feed_content.title, feed_content.content, feed_content.item_time, Date_FORMAT(feed_content.item_time,'%a, %d %b %Y %T') AS pubDate FROM feed_content order by item_time desc LIMIT 50 ", $vinovotedb) or die(mysql_error()); while($result = mysql_fetch_array($doGet)){ ?> <item> <title> <?php echo $result['title']; ?></title> <description> <?php echo $result['content'];?></description> <link><?php echo $result['url'];?></link> <pubDate> <?php echo $result['pubDate']; ?></pubDate> </item> <?php } ?> </channel> </rss> I'm not sure you can do this but i would like to grab the image gif from the rss feed of yahoo weather. For instance http://weather.yahooapis.com/forecastrss?p=77056 I pulled this script from a tutorial online and it works great for displaying the temperature and condition and i realize those values are located within the xml. But i would like to grab the image located between the <description> tags (if you look at the source of the rss feed). I don't know if this is possible or not. Thanks. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Yahoo! Weather API RSS</title> <?php function retrieveYahooWeather($zipCode="92832") { $yahooUrl = "http://weather.yahooapis.com/forecastrss"; $yahooZip = "?p=$zipCode"; $yahooFullUrl = $yahooUrl . $yahooZip; $curlObject = curl_init(); curl_setopt($curlObject,CURLOPT_URL,$yahooFullUrl); curl_setopt($curlObject,CURLOPT_HEADER,false); curl_setopt($curlObject,CURLOPT_RETURNTRANSFER,true); $returnYahooWeather = curl_exec($curlObject); curl_close($curlObject); return $returnYahooWeather; } $localZipCode = "77056"; // Houston, Tx $weatherXmlString = retrieveYahooWeather($localZipCode); $weatherXmlObject = new SimpleXMLElement($weatherXmlString); $currentCondition = $weatherXmlObject->xpath("//yweather:condition"); $currentTemperature = $currentCondition[0]["temp"]; $currentDescription = $currentCondition[0]["text"]; ?> </head> <body> <h1>Houston, TX</h1> <ul> <li>Current Temperatu <?=$currentTemperature;?>°F</li> <li>Current Description: <?=$currentDescription;?></li> </ul> </body> </html> Does anybody have any recommendations for PHP scripts to pull in a Twitter feed? I've tried several but each seem to just give me error messages! I basically just need a PHP alternative so that the tweets can be read by search engines. Thanks. Hi, I am reading a feed with this code foreach ($xml->channel->item as $item) { echo $item->title; echo '<br>'; } and outputs Code: [Select] title 1 title 2 title 3 .... and so on until 10 I wants in reverse order to output last rss feed first like: Code: [Select] title 10 title 9 title 8 .... and so on until 1, how can i do it? i tried with rsort($xml->channel->item) butt getting this error: Quote Warning: rsort() expects parameter 1 to be array, object given in Thanks for help hi i want to add some content to my site using xml rss i have a feed i want to show, and the only thing i can find to show it on my page or widgets but they dont look like i want it to look, so i want to make a php script that reads the xml file and then parses it into my website dont know if this is even possible ... but if its possible, is it also possible to filter the feed on certain keywords? I have tried sitemap.org and a few others but have not found anything that will give the results I am after. I have a blog site that has a URL and a Description for the URL and wish to have the description show as the anchor text which is linked to the URL, all data is taken from MySQL. Does anyone have a code that will generate something like this ? |
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