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PHP - Pass Values Through Url

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Pass Values Through Url	View Content

Hello there, I have 2 questions: 1) Look he http://www.hellastra...ooking/taxi.php I have a form and i want to pass values from URL to fields. So, for example to pass a value to Prefered driver ID field you write this: http://www.hellastra...?drivercode-123 and the value 123 is passed to that field. I did this with this code:

<?php $sDriverCode = $_REQUEST['drivercode']; ?>
             <input style="width:100px;" name="drivercode" id="drivercode" value="<?=$sDriverCode?>" data-mini="true" />

At the same form i have some radio-type fields. Its the one you see at Type of Vehicle (Standard, Premium etc). When i try to do the same, i cannot get this to work. What i am trying to do is this:

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Learn VBA & Macros for Excel in 1 Week!

How To Pass All Three Php Values From One Window To Another

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hey guys,i'm back with a new prob..
i have an image here that when clicked using onclick, will open a window and sort of pass the php values to the window.
okay,it's confusing but perhaps this will help you understand. let me break it down.
this is what the image code looks like. i have placed this inside the php echo.

Code: [Select]
<img src="images/edit.png" alt="Edit rooms" width="16" height="16" onclick="window.open(\'edit.php?course='.$row['c_name'].'&year='.$row['year'].'&block='.$row['block'].'\',\'width=300, height=200, menubar=yes\')"/>
now my problem is i can't seem to get all three of the values, c_name,year and block to be posted on the window..
here's the code on edit.php:
Code: [Select]
<?php
include("dbcon.php");
$course = $_GET['c_name'];
$year = $_GET['year'];
$block = $_GET['block'];
?>
<html>
<body>
Course:<input type="text" name="course" value="<?php echo $course;?>"><br>
Year:<input type="text" name="year" value="<?php echo $year;?>"><br>
Block:<input type="text" name="block" value="<?php echo $block;?>"><br></html>

i have already used $_GET as you can see but only year and block appear on the form. i get a notice saying that c_name is an undefined index. i am really confused and i don't know what the problem is. i hope you guys can help me..

How To Pass Session Values To Table ?

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I am under developing PHP add to cart without DB, so that i am using SESSION, actually get data from fetch_data.php data to my_cart.php using the POST method, successfully retun the values,

After receiving the post data how can i convert to display like a table.

workout:

fetch_data.php return values.

https://snag.gy/IASCMZ.jpg

& values received

https://snag.gy/ojWxHe.jpg

Here is my my_cart.php :

// FYI -> Here i am using only two fields :  voice_sku & voice_name 

<table width="100%" cellpadding="6" cellspacing="0">
 <thead>
 <tr>
 <th>Voice Sku</th>
 <th>Voice Name</th>
 <th>Remove</th>
 </tr>
 </thead>

 <tbody>

 <?php
 session_start();
 $voice_sku = '';
 $voice_name = '';

 if(isset($_POST['voice_sku'])&& isset($_POST['voice_name']))
            {
 // print_r($_POST);
 // die();
 
 $voice_sku = $_POST['voice_sku'];
 $voice_name = $_POST['voice_name'];
 $_SESSION['voice_sku'] = $voice_sku;
 $_SESSION['voice_name'] = $voice_name;
 
 
            }   
 var_dump($_SESSION);    
 ?>

 <tr>
 <td colspan="5">
 <span style="float:right;text-align: right;">
 <!--  -->
 </span>
 </td>
 </tr>
 <tr>
 <td colspan="5">
 <a href="index.php" class="button">Add More Items</a>
 <button type="submit">Update</button>
 </td>
 </tr>

 </tbody>
</table>

Pass Values Array Into Form

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Hi,
I'm trying to pass values from an array into a form. As a newbie, I've came up with the code underneath, but I want to pinpoint all the first values toward 1 selection list in the form. Any suggestions how to accomplish this?
Thanks in advance.

Ruud
<html>
<head>
<title>Test formulier</title>
</head>
<body>
<h2>Test formulier</h2>
<form action="test.php" method="post">

<p>
<?php
$prijzen = array(
array("01", "125","150", "A" => true,"B" => true),
array("02", "125","150", "A" => true,"B" => true),
array("03", "125","150", "A" => true,"B" => false),
array("04", "125","150", "A" => true,"B" => true)
);
?>

</P>
<select name="prijzen[]" id="prijzen" multiple="multiple" size="7" class="none">

<?php
while(list($key, $val) = each($prijzen)){
while(list($key2, $val2) = each($val)){
echo '<option value="'.$key2.'">'.$val2.'</option>'.PHP_EOL;

}
}
?>

</select>
</body>
</html>

Pass Html Field Values To Php Script

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Pass Checkbox Values In Url To Download Page

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First,
I will select checkbox then click generate report then it displays the items with download link

Then i click download link to download the selected checkbox values in pdf

I want to download the selected checkbox items by clicking download link

Now i am getting all check box items in the pdf download

How to download only the selected check box items

Code: [Select]
<?php
session_start();
$_SESSION['pidd'] = 2;
$sessvar = $_SESSION['pidd'];
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Untitled Document</title>
<link rel="stylesheet" type="text/css" href="css/style.css" />
<style type="text/css" media="print">
DIV#noprint{visibility:hidden;}
INPUT#printbutt{visibility:hidden;}
#downloadlink{visibility:hidden;}
</style>
<script type="text/javascript">
function gen() {

var st1=document.getElementById("ckbox1").checked;

var st2=document.getElementById("ckbox2").checked;

var st3=document.getElementById("ckbox3").checked;

var st4=document.getElementById("ckbox4").checked;

if(st1 == true) {
document.getElementById('g1').style.display = 'block';

}

if(st2 == true) {

document.getElementById('g2').style.display = 'block';

}

if(st3 == true) {

document.getElementById('g3').style.display = 'block';

}

if(st4 == true) {
document.getElementById('g4').style.display = 'block';

}

document.getElementById('p_info').style.display = 'none';

document.getElementById('histree').style.display = 'none';

document.getElementById('insurence').style.display = 'none';
document.getElementById('billin').style.display = 'none';
}

function showuser() {

document.getElementById('g1').style.display = 'none';

document.getElementById('g2').style.display = 'none';

document.getElementById('g3').style.display = 'none';

document.getElementById('g4').style.display = 'none';

var str1=document.getElementById("ckbox1").checked;

var str2=document.getElementById("ckbox2").checked;

var str3=document.getElementById("ckbox3").checked;

var str4=document.getElementById("ckbox4").checked;

if(str1 == true) {

document.getElementById('p_info').style.display = 'block';

}

else

document.getElementById('p_info').style.display = 'none';

if(str2 == true) {

document.getElementById('histree').style.display = 'block';

}

else

document.getElementById('histree').style.display = 'none';

if(str3 == true) {

document.getElementById('insurence').style.display = 'block';

}

else

document.getElementById('insurence').style.display = 'none';

if(str4 == true) {

document.getElementById('billin').style.display = 'block';

}

else

document.getElementById('billin').style.display = 'none';

}

function checkByParent(aId, aChecked) {
var collection = document.getElementById(aId).getElementsByTagName('INPUT');
for (var x=0; x<collection.length; x++) {
if (collection[x].type.toUpperCase()=='CHECKBOX')
collection[x].checked = aChecked;
}
}
</script>
</head>
<body>
<div id="main_content">
<div id="left">
<div id="noprint">
<h4>Patient Report</h4>
<a id="check_all" href="#" style="text-decoration:none" onClick="checkByParent('checkboxes', true); return false;">check all</a>     <a id="uncheckall" href="#" style="text-decoration:none" onClick="checkByParent('checkboxes', false); return false;">uncheck all</a> <br>
<br>
<form method="post" name="myform" action="">
<div id="checkboxes">
<div id="cb_id1">
<input id="ckbox1" name="cbox1" type="checkbox" <? if(isset($_REQUEST['cbox1'])) echo 'checked="checked"' ; ?> value="p_info" />
Patient Info </div>
<div id="cb_id2">
<input id="ckbox2" name="cbox2" type="checkbox" <?php if(isset($_REQUEST['cbox2'])) echo 'checked="checked"' ; ?> value="histree" />
History </div>
<div id="cb_id3">
<input id="ckbox3" name="cbox3" type="checkbox" <?php if(isset($_REQUEST['cbox3'])) echo 'checked="checked"' ; ?> value="insurance" />
Insurence </div>
<div id="cb_id4">
<input id="ckbox4" name="cbox4" type="checkbox" <?php if(isset($_REQUEST['cbox4'])) echo 'checked="checked"' ; ?> value="billin" />
Billing </div>
</div>

<br>
<input id="vuprint" name="view" type="button" value="View" onClick="showuser();">
<hr/>
<label for="docs"> Documents:<br>
<br>
</label>
<input name="sub" type="button" value="Generate report" onclick="gen();">
<hr/>
</form>
<input id="printbutt" name="prt" type="button" value="Print" onClick="javascript:window.print();">
</div>

</div>

<div id="side">
<div id="p_info">
<?php require("db_conn.php");
$pinfo = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='".$sessvar."' ");
while($fet = mysqli_fetch_array($pinfo)) {
echo "<h4>Patient Info</h4>";
echo "<b>Name: </b>" . $fet["P_Fname"] . " " . $fet["P_Lname"]. "<br>";
echo "<b>Dob:</b> " . date("d-m-Y",strtotime($fet["P_Dob"]))."<br>";
echo "<b>Age:</b> " . $fet["P_Age"]."<br>";
echo "<b>Gender:</b> " . $fet["P_Gender"]."<br>";
echo "<b>Marital Status:</b> " . $fet["P_Mstatus"]."<br>";
echo "<b>Blood: </b>" . $fet["P_Blood"]."<br>";
echo "<b>Height: </b>" . $fet["P_Height"] . $fet["P_Hval"]."<br>";
echo "<b>Weight: </b>" . $fet["P_Weight"] . $fet["P_Wval"];
}
?>
</div>
<div id="histree">
<?php
$his = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='".$sessvar."' ");
while($hisrow = mysqli_fetch_array($his,MYSQLI_ASSOC)) {
echo "<h4>Patient Histroy</h4>";
echo "<b>P_Idate: </b>" . date("d-m-Y",strtotime($hisrow["P_Idate"]))."<br>";
echo "<b>P_Edate: </b>" . date("d-m-Y",strtotime($hisrow["P_Edate"]))."<br>";
echo "<b>D_Ddate: </b>" . date("d-m-Y",strtotime($hisrow["D_Ddate"]));
} ?>
</div>

<div id="insurence">
<?php
$insu = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='".$sessvar."' ");
while($insrow = mysqli_fetch_array($insu,MYSQLI_ASSOC)) { ?>
<?php
echo "<h4>Insurence</h4>";
echo "<b>P_Isname: </b>" . $insrow["P_Isname"]."<br>";
// echo $insow[""];
} ?>
</div>
<div id="billin">
<?php
$bilrow = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' ");
while($bill = mysqli_fetch_array($bilrow,MYSQLI_ASSOC)) { ?>
<?php
echo "<h4>Billing</h4>";
echo "<b>P_Fbill: </b>" . $bill["P_Fbill"]."<br>";
echo "<b>Fees: </b>" . $bill["fees"];
} ?>
</div>
</div>

<div id="generatereport">
<div id="g1" style="display:none; clear:both;">
<label for="Gen_reports">Generaterd reports</label>
<br />
<br />
<?php
$pinfo = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' ");
while($fet = mysqli_fetch_array($pinfo,MYSQLI_ASSOC)) {

$new_dob = date("d-m-Y",strtotime($fet["P_Dob"])); ?>
<?php echo "<h4>Patient Info</h4>";

echo "<b>Patient Id:</b> ". $fet["P_Id"]."<br>";

echo "<b>Name:</b> " . $fet["P_Fname"] . " " . $fet["P_Lname"]."<br>";

echo "<b>Dob:</b> " . $new_dob ."<br>";

echo "<b>Age:</b> " .$fet["P_Age"]."<br>";

echo "<b>Gender:</b> " . $fet["P_Gender"]."<br>";

echo "<b>Marital Status:</b> " . $fet["P_Mstatus"]. "<br>";

echo "<b>Blood:</b> " . $fet["P_Blood"] . "<br>";

echo "<b>Height:</b> " . $fet["P_Height"] . $fet["P_Hval"]. "<br>";

echo "<b>Weight:</b> " . $fet["P_Weight"] . $fet["P_Wval"]. "<br>";

}
echo "*************************************************************************************************************************";

?> </div>
<div id="g2" style="display:none">
<?php

$his = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' ");

while($secrow = mysqli_fetch_array($his,MYSQLI_ASSOC)) {

echo "<h4>Patient Histroy</h4>";

echo "<b>P_Idate:</b> " . date("d-m-Y",strtotime($secrow["P_Idate"])) ."<br>";

echo "<b>P_Edate:</b> " . date("d-m-Y",strtotime($secrow["P_Edate"])) ."<br>";

echo "<b>D_Ddate:</b> " . date("d-m-Y",strtotime($secrow["D_Ddate"])) ."<br>";

}
echo "*************************************************************************************************************************";
?>
</div>
<div id="g3" style="display:none">
<?php

$insu = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' ");

while($insrow = mysqli_fetch_array($insu,MYSQLI_ASSOC)) {

echo "<h4>Insurence</h4>";

echo "<b>P_Isname:</b>" . $insrow["P_Isname"]."<br>";

}
echo "*************************************************************************************************************************";
?>
</div>
<div id="g4" style="display:none">
<?php

$bilrow = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' ");

while($bill = mysqli_fetch_array($bilrow,MYSQLI_ASSOC)) {

echo "<h4>Billing</h4>";

echo "<b>P_Fbill:</b> " . $bill["P_Fbill"]."<br>";

echo "<b>Fees:</b> " . $bill["fees"];
}

?>
</div>
<?php
$infochk = 'p_info';
$hischk = 'histree';
$insuchk = 'insurance';
$billchk = 'billin';
?>
<a id="downloadlink" href="download_pdf2.php?info=<?php if(isset($infochk)) echo $infochk; ?>&hist=<?php if(isset($hischk)) echo $hischk; ?>&insu=<?php if(isset($insuchk)) echo $insuchk; ?>&billin=<?php if(isset($billchk)) echo $billchk; ?>">Download</a> </div>

</div>

</body>
</html>

Json_encode() Is not A Security Feature (or: How To Pass Php Values To Javascript)

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Since there have been some debates about how to safely pass PHP values to JavaScript, I hope I can clarify a few things. One suggestion that kept recurring was to simply run the value through json_encode() and then inject the result into a script element. The JSON-encoding is supposed to (magically?) prevent cross-site scripting vulnerabilities. And indeed it seemingly works, because naïve attacks like trying to inject a double quote will fail. Unfortunately, this approach doesn't work at all and is fundamentally wrong for several reasons: json_encode() was never intended to be a security function. It simply builds a JSON object from a value. And the JSON specification doesn't make any security promises either. So even if the function happens to prevent some attack, this is implementation-specific and may change at any time. JSON doesn't know anything about HTML entities. The encoder leaves entities like " untouched, not realizing that this represents a double quote which is dangerous in a JavaScript context. The json_encode() function is not encoding-aware, which makes it extremely fragile and unsuitable for any security purposes. Some of you may know this problem from SQL-escaping: There used to be a function called mysql_escape_string() which was based on a fixed character encoding instead of the actual encoding of the database connection. This quickly turned out to be a very bad idea, because a mismatch could render the function useless (e. g. the infamous GBK vulnerability). So back in 2002(!), the function was abandoned in favor of mysql_real_escape_string(). Well, json_encode() is like the old mysql_escape_string() and suffers from the exact same issues. Any of those issues can be fatal and enable attackers to perform cross-site scripting, as demonstrated below. 1) The entire “security” of json_encode() is based on side-effects. For example, the current implementation happens to escape forward slashes. But the JSON standard doesn't mandate this in any way, so this feature could be removed at any time (it can also be disabled at runtime). If it does get disabled, then your application is suddenly wide open to even the most trivial cross-site scripting attacks:

<?php

header('Content-Type: text/html; charset=UTF-8');

$input = '</script><script>alert(String.fromCharCode(88, 83, 83));</script><script>';

?>
<!DOCTYPE HTML>
<html>
    <head>
        <meta charset="utf-8">
        <title>XSS</title>
    </head>
    <body>
        <script>
            var x = <?= json_encode($input, JSON_UNESCAPED_SLASHES) ?>;
        </script>
    </body>
</html>

2) In XHTML, a script element works like any other element, so HTML entities like " are replaced with their actual characters (in this case a double quote). But JSON does not recognize HTML entities, so an attacker can use them to bypass json_encode() and inject arbitrary characters:

<?php

header('Content-Type: application/xhtml+xml; charset=UTF-8');

$input = "&quot;;alert('XSS');&quot;";

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <title>XSS</title>
        <meta http-equiv="content-type" content="text/html; charset=UTF-8" />
    </head>
    <body>
        <script type="text/javascript">
            var x = <?= json_encode($input) ?>;
        </script>
    </body>
</html>

3) json_encode() blindly assumes that the input and the output should always be UTF-8. If you happen to use a different encoding, or if an attacker manages to trigger a specific encoding, you're again left with no protection at all:

<?php

header('Content-Type: text/html; charset=UTF-7');

$input = '+ACIAOw-alert(+ACI-XSS+ACI)+ADsAIg-';

?>
<!DOCTYPE HTML>
<html>
    <head>
        <meta charset="utf-7">
        <title>XSS</title>
    </head>
    <body>
        <script>
            var x = <?= json_encode($input) ?>;
        </script>
    </body>
</html>

(This particular example only works in Internet Explorer.) I hope this makes it very clear that json_encode() is not a security feature in any way. Relying on it is conceptually wrong and simply a very bad idea. It's generally not recommended to inject code directly into a script element, because any mistake or bug will immediately lead to a cross-site scripting vulnerability. It's also very difficult to do it correctly, because there are special parsing rules and differences between the various flavors of HTML. If you try it, you're asking for trouble. So how should one pass PHP values to JavaScript? By far the most secure and robust approach is to simply use Ajax: Since Ajax cleanly separates the data from the application logic, the value can't just “leak” into a script context. This is essentially like a prepared statement. If you're into micro-optimization and cannot live with the fact that Ajax may need an extra request, there's an alternative approach by the OWASP: You can JSON-encode the data, HTML-escape the result, put the escaped content into a hidden div element and then parse it with JSON.parse():

<?php

header('Content-Type: text/html; charset=UTF-8');

$input = 'bar';

?>
<!DOCTYPE HTML>
<html>
    <head>
        <meta charset="utf-8">
        <title>XSS</title>
        <style>
            .hidden {
                display: none;
            }
        </style>
    </head>
    <body>
        <div id="my-data" class="hidden">
            <?php
                $json_object = json_encode(array(
                    'foo' => $input,
                ));

                // HTML-escape the JSON object
                echo htmlspecialchars($json_object, ENT_QUOTES | ENT_SUBSTITUTE | ENT_HTML5, 'UTF-8');
            ?>
        </div>
        <script>
            var data = JSON.parse(document.getElementById('my-data').innerHTML);
            
            alert('The following value has been safely passed to JavaScript: ' + data.foo);
        </script>
    </body>
</html>

Html Php 3 Submit Button To Pass Values To 3 Different Pages

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I have a page that contains a List box containing a list of categories taken from a mysql database, 4 iframe elements and 4 submit button (code to follow) When an item is selected from the List box the onchange event submits the page to jobs.php and loads it into the joblist iframe. Once the iframe is loaded and visible it makes the "Add Job To Category" submit button visible. This all works great When I click the "Add Job To Category" Submit button it loads Jobnew.php into the jobed iframe this is working but I can not seem to figure out how to pass the selected item from the List box using this submit button I hope I am clear in my question if not please advise any help is very much appreciated.... Jobtask.php

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Job Configuration</title>
<head>
</head>
<body>
<div style="position:absolute;left:5px;top:0px;width:1345px;height:50px;z-index:0;">
<img src="images/img0001.png" id="Shape1" alt="" style="border-width:0;width:1345px;height:50px;"></div>
<span style='position:fixed;left:525px;top:8px;font-family:Arial;font-size:32px;width:275px;'>Job Configuration</span>
<form action='index.html' target='' method='post'>
 <div style="position:absolute;left:205px;top:55px;width:1345px;height:50px;z-index:0;">
  <Input type="submit" action="index.html" Target="_top" method='post'Value="Main Menu">
 </div>
</form>
<form style=position:fixed;left:200px;top:82px;>    
 <iframe name='joblist' id='joblist' style=position:fixed;left:200px;top:px;visibility:hidden;z-index:10 src='' height="475" width="1150" scrolling='yes' frameBorder='0' ></iframe>    
 <iframe name='job' id='job' style=absolute:fixed;left:200px;top:0px;visibility:hidden;z-index:0 src='' height="475" width="1150" scrolling='yes' frameBorder='0' ></iframe>    
 <iframe name='jobed' id='jobed' style=position:fixed;left:460px;top:150px;visibility:hidden;z-index:10 src='' height="217" width="350" scrolling='no' frameBorder='0' ></iframe>   
 <iframe name='newcat' id='newcat' style=position:fixed;left:460px;top:150px;visibility:hidden;z-index:10 src='' height="125" width="350" scrolling='no' frameBorder='0' ></iframe> 
</form>
<?php
error_reporting(E_ALL);
include('dbcon/dbconnect.php');
$con=mysqli_connect($host,$user,$password,$db);
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if (isset($_POST['id'])) {
  $insql= "INSERT INTO catagory (Catagory) VALUES ('$_REQUEST[newcat]')";
  $con->query($insql);
  }
$Catresult = mysqli_query($con, "SELECT CatID, Catagory FROM catagory");

echo "<div id='wb_CatSel' style='position:absolute;z-index:0;text-align:center;'bgcolor='#00b0e6';>";
echo "<span style='position:fixed;left:10px;top:82px;font-family:Arial;font-size:15px;background-color:#00b0e6;width:175px;'>Select Category</span></div>";
echo "<form action='jobs.php' target='joblist' style='position:fixed;left:10px;top:101px;'></td>";

echo "<select name='cat' size='11' style='width: 175px;' onchange='this.form.submit()'>";

while($row = mysqli_fetch_array($Catresult))
{ 
  echo "<option value=\"".$row['CatID']."\">".$row['Catagory']."</option>\n  ";
}

echo "</select>";

echo "</form>";

echo "<form action='Jobnew.php' target='jobed' method='post'>";
echo "<div style='position:absolute;left:10px;top:285px;width:1345px;height:50px;z-index:0;'>";
echo "<Input type='hidden' id='id1'><Input type='submit' id='sbtn' style='width:175px;visibility:hidden;'   Value='Add Job To Category'></div></form>";

echo "<form action='Jobtask.php' target='' method='post'>";
echo "<div style='position:absolute;left:10px;top:310px;width:1345px;height:50px;z-index:0;'>";
echo "<Input type='submit' style='width:175px;' action='Jobtask.php' Target='_top' method='post'  Value='Reset Form'></div></form>";

echo "<form action='newcat.php' target='newcat' method='post'>";
echo "<div style='position:absolute;left:10px;top:335px;width:1345px;height:50px;z-index:0;''>";
echo "<Input type='submit' style='width:175px;'' action='newcat.php' Target='newcat' method='post'  Value='Add New Category'></div></form>";

?>

</body>
</html>

How To Get Values From Check Boxes And Pass It To A Php Controller Action?

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I have a list of checkboxes, like e.g each checkbox has a value as ResumeID,
now question is/are;

1) how to get the values of the checkboxes using jQuery ?
2) when I got the values of the checkboxes using jQuery, how to pass those values to a PHP Controller action ?

Moved: In Magento Shoping Cart How To Pass The Variable Values To A Jsp Page?

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This topic has been moved to PHP Applications.

http://www.phpfreaks.com/forums/index.php?topic=357747.0

When Passing Parameters, Do I Pass Only What I Need Or Do I Pass Entire Parent Object?

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I work with a large codebase and I have this situation come up fairly often: the legacy class has large objects such as:

$design->motor->dimensions->a;
$design->motor->dimensions->bd;
$design->specifications->weight;
$design->data->height;
//etc

When I create a new class, that class sometimes operates on the specific data, so say:

class MyClass
{
    public function compute($weight, $height, $a)
    {
        //stuff
    }
}

//and I call this for example as such:
(new MyClass())->compute($design->specifications->weight, $design->data->height, $design->motor->dimensions->a);

CONS: Potential issue: if design specs change and I need to change things parameters in "compute" function, I need to "re-key" the variables I pass to the function, and adjust things accordinly in MyClass as wel. PROS: only the exact data is being passed, and this data can come from anywhere it is viable, so in effect the function is fairly well separated, I think. Alternative option for me is to pass the entire design object, i.e

class MyClass
{
    public function compute(&$design) //can also be done via DI through a setter or constructor.
    {
         print $design->specifications->weight;
         print ($design->data->height + $design->motor->dimensions->a);
        //stuff
    }
}

(new MyClass())->compute($design);

PROS: In this case when things change internally in which variables are needed and how things are computed, I only need to change the code in compute function of the class itself. CONS: MyClass now needs to be aware of how $design object is constructed. When it comes to this parameter passing, and Dependency Injection like this in general, does Computer Science advocate a preference on this issue? Do I pass the entire object, or do I pass only the bits and pieces I need?

Display One Thing First Loop Pass And Something Else Second Pass

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I'm trying to get a simple table to display and am not sure how to make it happen. Table will have just 2 columns. A TIME and an EVENT. What I want to have happen is for the first row to show the TIME and next to that, the EVENT. If a TIME has more than one event going I want the next row to show an empty first cell and then the second event below the first.

If I set up the loop the only way I know how (so far) it would also output the TIME value again and again as many times as there were events for that same time. For example what I don't want is:

9:15 Sunday School
9:15 Nursery Available

What I do want is:

9:15 Sunday School
Nursery Available

Thanks.

How To Insert Two Input Values And Multi Data Textarea Values In One Query?

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Dear All Members

here is my table data..

(4 Columns/1row in mysql table)

id order_no order_date miles
310 001 02-15-2020 MI,108.53
Oh,194.57
PA,182.22
WA,238.57

How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.

(5 Columns in mysql table)
------------------------------------------------------------------------------------

id order_no order_date state miles

310 001 02-15-2020 MI 108.53

310 001 02-15-2020 Oh 194.57

310 001 02-15-2020 PA 182.22

310 001 02-15-2020 WA 238.57

------------------my php code -----------

<?php
//invoice.php
include('../includes/config.php');

if(isset($_POST["add"]))
{
$order_no=$_GET['order_no'];
$order_date=$_GET['order_date'];
$miles=$_POST['miles'];

$miles = explode("\r\n", $_POST["miles"]);
$newdata = "'" . implode("','", $_POST["miles"]) . "'";
$sql ="INSERT INTO tble_states_miles(order_no,order_date, miles) VALUES(:order_no, :order_date, :newdata)";

$query = $dbh->prepare($sql);
$query-> bindParam(':order_no', $order_no, PDO::PARAM_STR);
$query-> bindParam(':order_date', $order_date, PDO::PARAM_STR);
$query-> bindParam(':miles', $newdata, PDO::PARAM_STR);

$lastInsertId = $dbh->lastInsertId();
if($lastInsertId)
{
echo "<script type='text/javascript'>alert('Added Sucessfull!');</script>";
echo "<script type='text/javascript'> document.location = 'ifta_miles_calculationlist_added.php'; </script>";
}
else
{
$error="Something went wrong. Please try again";
}

if($query->execute()) {

$sql = "update tis_invoice set flag='1' where order_no=:order_no";
$query = $dbh->prepare($sql);
$query-> bindParam(':order_no', $order_no, PDO::PARAM_STR);

$query->execute();

}
}
?>

----------------- my form code ------------------

<?php
               $order_no=$_GET['order_no'];
       $sql = "SELECT * from tis_invoice where order_no = :order_no";
       $query = $dbh -> prepare($sql);
       $query->execute(
array(
':order_no' => $_GET["order_no"]
)
);
       $result = $query->fetchAll();
       foreach($result as $row)
?>

<form method="post">
<table align="center" style="width: 55%">
                       <tr><td>Invoice Number</td></tr>
                       <tr><td><input type="text" name="order_no" value="<?php echo $row["order_no"]; ?>" readonly=""></td></tr>
                       <tr><td>Invoice Date</td></tr>
                       <tr><td><input type="text" name="order_no" value="<?php echo $row["order_date"]; ?>" readonly=""></td></tr>
                       <tr><td>
<textarea name="miles" class="form-control" rows="10" placeholder="" required></textarea>
</td></tr>
                       <tr><td>

<input type="submit" name="add" class="btn btn-primary" value="Add" />
</td></tr></table>
</form>

-- Can any one help how to correct my code..present nothing inserted on table

Thank You

Edited February 8, 2020 by karthicbabu

Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell

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Hi,

My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck.

The HTML/PHP code is below:

<table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%">

<thead>

<tr>

<th>ID</th>

<th>FirstName</th>

<th>LastName</th>

<th>Username</th>

<th>Phone #</th>

<th>Location</th>

<th>Title</th>

<th>Role</th>

<th>Actions</th>

</tr>

</thead>

<tbody>

<?php

//QUERY TO SELECT ALL USERS FROM DATABASE

$query = "SELECT * FROM users";

$select_users = mysqli_query($connection,$query);

// SET VARIABLE TO ARRAY FROM QUERY

while($row = mysqli_fetch_assoc($select_users)) {

$user_id = $row['user_id'];

$user_firstname = $row['user_firstname'];

$user_lastname = $row['user_lastname'];

$username = $row['username'];

$user_phone = $row['user_phone'];

$user_image = $row['user_image'];

$user_title_id = $row['user_title_id'];

$user_role_id = $row['user_role_id'];

// POPULATES DATA INTO THE TABLE

echo "<tr>";

echo "<td>{$user_id}</td>";

echo "<td>{$user_firstname}</td>";

echo "<td>{$user_lastname}</td>";

echo "<td>{$username}</td>";

echo "<td>{$user_phone}</td>";

//PULL SITE STATUS BASED ON SITE STATUS ID

$query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} ";

$select_site = mysqli_query($connection, $query);

while($row = mysqli_fetch_assoc($select_site)) {

$site_name = $row['site_name'];

echo "<td>{$site_name}</td>";

}

echo "<td>{$user_title_id}</td>";

echo "<td>{$user_role_id}</td>";

echo "<td class='table-action'>

<a href='#'><i class='align-middle' data-feather='edit-2'></i></a>

<a href='#'><i class='align-middle' data-feather='trash'></i></a>

</td>";

//echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>";

echo "</tr>";

}

?>

<tr>

<td>ID</td>

<td>FirstName</td>

<td>LastName</td>

<td>Username</td>

<td>Phone #</td>

<td>Location</td>

<td>Title</td>

<td>Role</td>

<td class="table-action">

<a href="#"><i class="align-middle" data-feather="edit-2"></i></a>

<a href="#"><i class="align-middle" data-feather="trash"></i></a>

</td>

</tr>

</tbody>

<tfoot>

<tr>

<th>ID</th>

<th>FirstName</th>

<th>LastName</th>

<th>Username</th>

<th>Phone #</th>

<th>Location</th>

<th>Title</th>

<th>Role</th>

</tr>

</tfoot>

</table>

Mysql Values Clause, Variable Values From File

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Hi all,

Just curious why this works:

Code: [Select]
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){
$import="INSERT into $prodtblname ($csvheaders1) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]')";
}
And this does not:

$headdata_1 = "'$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]'";
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){
$import="INSERT into $prodtblname ($csvheaders1) values($headdata_1)";
}it puts $data[#'s] in the database fields instead of the actual data that '$data[0]','$data[1]'... relates to.

I wrote a script to create the values in $headdata_1 based on the number of headers in $csvheaders1 but can't seem to get it working in the sql statement.

Thanks

Searching Multidimensional For Values, Then Outputting Other Values In Array

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Hi all,

I'm a first time poster here and I would really appreciate some guidance with my latest php challenge! I've spent the entire day googling and reading and to be honest I think I'm really over my head and need the assistance of someone experienced to advise the best way to go!

I have a multi dimensional array that looks like (see below); the array is created by CodeIgniter's database library (the rows returned from a select query) but I think this is a generic PHP question as opposed to having anything to do with CI because it related to working with arrays.

I'm wondering how I might go about searching the array below for the key problem_id and a value equal to a variable which I would provide. Then, when it finds an array with a the matching key and variable, it outputs the other values in that part of the array too.

For example, using the sample data below. How would you recommend that I search the array for all the arrays that have the key problem_id and the value 3 and then have it output the value of the key problem_update_date and the value of the key problem_update_text. Then keep searching to find the next occurrence?

Thanks in advance, as above, I've been searching really hard for the answer and believe i'm over my head!

Output of print_r($updates);

CI_DB_mysql_result Object
(
    [conn_id] => Resource id #30
    [result_id] => Resource id #35
    [result_array] => Array
        (
        )

    [result_object] => Array
        (
        )

    [current_row] => 0
    [num_rows] => 5
    [row_data] =>
)

Output of print_r($updates->result_array());

Array
(
    [0] => Array
        (
            [problem_update_id] => 1
            [problem_id] => 3
            [problem_update_date] => 2010-10-01
            [problem_update_text] => Some details about a paricular issue
            [problem_update_active] => 1
        )

    [1] => Array
        (
            [problem_update_id] => 4
            [problem_id] => 3
            [problem_update_date] => 2010-10-01
            [problem_update_text] => Another update about the problem with an ID of 3
            [problem_update_active] => 1
        )

    [2] => Array
        (
            [problem_update_id] => 5
            [problem_id] => 4
            [problem_update_date] => 2010-10-12
            [problem_update_text] => An update about the problem with an ID of four
            [problem_update_active] => 1
        )

    [3] => Array
        (
            [problem_update_id] => 6
            [problem_id] => 4
            [problem_update_date] => 2010-10-12
            [problem_update_text] => An update about the problem with an ID of 6
            [problem_update_active] => 1
        )

    [4] => Array
        (
            [problem_update_id] => 7
            [problem_id] => 3
            [problem_update_date] => 2010-10-12
            [problem_update_text] => Some new update about the problem with the ID of 3
            [problem_update_active] => 1
        )

)

How To Pass The Value In Php

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Code: [Select]
$col = 0;
if ($num_products_count > 0) {
while (!$specials_index->EOF) {
$list_box_contents[$row][$col] = array('params' =>'<a href="#">' .zen_image(..). '</a>'),
$col ++;
}
}

now i want to pass some values<img src="1.jpg">,<img src="1.jpg">,<img src="2.jpg">,<img src="3.jpg">,<img src="4.jpg">,<img src="5.jpg"> to zen_image(..). how should i do? namely, if there are five loops.i want to change zen_image(..) output result to (<img src="1.jpg">,<img src="1.jpg">,<img src="2.jpg">,<img src="3.jpg">,<img src="4.jpg">,<img src="5.jpg">)

Pass Variables In Url

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i hav this url n whenever i click on this url i get som mssg send on my mobile
i hav a form whose code is
Code: [Select]
<form action="formprocess.php method="post">
telephone<input type="text name="telephone>
<input type="submit" name="submit">
</form>

i want to send telephone as parameter to this url so whenever user enters his telephone he gets d mssg
after clicking on submit.....but i hav no idea how to do tht...help me somone plssssssss

http://www.abc.in/smsapi/sendsms.php?sendto=9987234123&msg=your

How Do I Pass Vars?

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Trying to pass VARS $URL1 and $type to header location.Heres the code.

Code: [Select]
$URL1 = $_POST['url'];
$type = $_POST['type_request'];

session_start();
$string = strtoupper($_SESSION['string']);
$userstring = strtoupper($_POST['userstring']);
session_destroy();

if (($string == $userstring) && (strlen($string) > 4)) {
header("Location: $success");
exit();
The VARS come from a FORM and then go to this script for checkind data. I need to have them continue to the next page.

Pass Value To Php Variable

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I have researched all over forums from past day. Not getting correct solution. I have 2 textboxes and a button. First box is to enter value and i will click button, i need to get the value. Here is the code, that works without input box 1 In this code i want to modify my web address, at the end after ky= i want add my first textbox value, then click event and output in second textbox, let me know where i messed.

<script type="text/javascript">
function Assign() 
{
<?php
$html = file_get_contents("http://geoportaal.maaamet.ee/url/xgis-ky.php?ky=79401:006:0812" );
preg_match_all('(<li.*?>.*?</li>)', $html, $matches);
$one=$matches[0][0];


?>
document.getElementById("OutputField").value = "<?=$one?>";
}
</script>




<input id="InputField" type="text" style="width:200px"/>
<input type="submit" value="Assign Value" onclick="Assign()"/>
<input id="OutputField" type="text" style="width:200px"/>

How To Pass A Php Value To A Javascript Pop Up

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how can i do this ? i have a number of links , when i click one a pop up is displayed, i need to run a php script depending upon which link is clicked. Or can i run a javascript function once a query string is passed in the url Please advice.
Edited by chauhanRohit, 12 July 2014 - 04:10 AM.