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PHP - Php Help Specifying Date Then Echoing Html?
Hi. I'm trying to achieve a calendar that only uses PHP and CSS. I registered today to ask for help (because I'm not a coder; I'm just another clueless musician).
My goal is to just skip the database, altogether. I've already, so far, skipped the Javascript, as well. I have an HTML non-functioning mockup HERE that's a bit "off" cosmetically, but I'm just using it as an example. It has a made-up "event" on August 16. I'm just using a little "tooltip" CSS. (I have no idea how it works in IE, it's just me and my MacBook here, but still... you get the idea of the function.) Or I might use THIS to get it to work for IOS, but that needs a little aesthetic work. Not tinkering with all that today.
Now... my PHP created calendar, that I will actually be using, is HERE. All the structure of the calendar is echoed in PHP so there is no actual HTML hard coding of table cells. In fact, the only HTML within the body is <body></body> So, I can't very well just pick a date and type in some tags and be off. My question is this (and because I don't really know correct PHP jargon to formulate a question, I'm not being successful at Googling): Is it possible to use PHP to isolate a specific date, say, in this case, August 16 2014, and then, based upon that date existing, echo what I have hard-coded into the mockup example: <div class="has-tooltip"> Event <span class="tooltip">Concert In The Park<br /> 123 City Park Drive<br /> AnyTown, STATE 00000<br /> <a href="http://example.com" target="_blank">More Info</a><br /> or call 555.123.4567<br /></span> </div>I realize that this means that there's always a great chance of error, but this wouldn't be a calendar with any other users inserting dates; it's nothing more than an occasional event and then it's over, and I would be the one posting the events, so I'd be able to test it before publishing it. Possible? And if so, would you advise as how to get PHP to isolate a particular date and then echo the HTML and, of course, have it reside in the date-appropriate table cell? (I've managed to echo HTML to build the calendar structure, but I've never created an echo in conjunction with calling for a specific date. I'd appreciate any help and thanks so much. PHP: <?php Similar TutorialsFolks, I want to echo an HTML tag in PHP. Code: [Select] <td width="300" bgcolor="#ffffff" align="center" onmouseout="style.backgroundColor='#ffffff'" onmouseover="style.backgroundColor='#e8e8e8';" style="word-wrap: break-word; border: 1px solid rgb(238, 238, 238); font-size: 12px; background-color: rgb(255, 255, 255);"> So what i am doing is; Code: [Select] echo '<td width="300" bgcolor="#ffffff" align="center" onmouseout="style.backgroundColor='#ffffff'" onmouseover="style.backgroundColor='#e8e8e8';" style="word-wrap: break-word; border: 1px solid rgb(238, 238, 238); font-size: 12px; background-color: rgb(255, 255, 255);">'; And its now working because this tag already has ' (Single Quotes) & ; (Semicolon) so its conflicting. Any work around for this friends? Cheers N Hi all, I have a html form list box that needs to show all the types of products that are for sale and have a number in the list box saying how many of that type are for sale. eg. If the mysql database looks like this productType | productDetails chair | outdoor large chair table | 2m x 1m chair | indoor chair chair | childs chair I would want the form list box to show the values inside as: chair (3) table (1) could someone give me the heads up on how to do this Thanks Hello guys, I currently have a problem with echoing text coming from an external site, using file_get_contents. I won't consider myself a great PhP programmer, so I'll gladly appraciate any help! The code I am using is very simple: <?php $homepage = file_get_contents('http://www.live365.com/scp/web/stn/playlist.html?station=kolonku'); echo $homepage; ?> However, the result comes out blank. If I change the link to a page made out of HTML, the code works, but the text here is a tracklist of a Live365 radio station. It changes dynamically according to what song is currently playing. I guess the code behind all this is formidable, to say the least, and I can't tell if it's made out of Javascript or PhP, or something else. Is there any way that I can solve this? I was thinking of getting the contents, then have the function updating every 10 seconds or so, so that the text is up to date most of the time. The current problem however, is getting something at all in the first place! Link to the site I want to get the contents from (it updates atomatically! The source code won't give me a clue to what's going on..): http://www.live365.com/scp/web/stn/playlist.html?station=kolonku Hi there,
I am trying to wrap some content in a div, but when I render it, it is outputting the actual HTML. This is the line I have:
add_filter( 'woocommerce_product_description_heading', 'rename_product_description_heading', 10, 1 );
function rename_product_description_heading( $heading ) {
return __( '<div class="myclass">Additional Information</div>', 'woocommerce' );
}
which is outputting: <div class="myclass">Additional Information</div> rather than wrapping it in the div.
Can anyone help me with wrapping the "Additional Information" text in a div? Thank you :) Say I have the following text stored in a MySQL database... Code: [Select] <b>Classic Quote from movie</b> and I retrieve it into a variable called $text, how do I properly echo that so that it keeps the bold tags and actually display the text "Classic quote from movie" in BOLD? I'm doing something wrong somewhere along the line (simply doing "echo $text;") because it displays on the page as... Code: [Select] <b>Classic Quote from movie</b> Instead of... Classic Quote from movie Any info on properly storing and echoing back HTML would be very appreciated. Hi all I have a field in mySQL table called dimensions. It has the double quote in in for inches - " When I echo the result from the mySQL query on the item page (Customer facing) it's fine. However, I have built a form so that the administrator can edit the dimensions in the admin panel and when I echo it out in to the form field it stops when it gets to the double quotes? Pete Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack Hello, I have a PHP page (below) that is suppose to update a field in my database. For some reason it does not update. I am trying to echo that sql with this script. Any help would be greatly appreciated. Thanks JR Code: [Select] $p = (100-$_POST[$c])/100; $sql = "delete from products_groups where customers_group_id = ".$sppc['customers_group_id']; echo $sql; tep_db_query($sql); $sql = "insert into products_groups select '". $sppc['customers_group_id'] ."' as customers_group_id, ( " . $p . " * p.products_price) as customers_group_price, p.products_id from products p"; echo $sql; tep_db_query($sql); Below is the complete code, Code: [Select] <?php require('includes/application_top.php'); ?> <!DOCTYPE html public "-//W3C//DTD HTML 4.01 Transitional//EN"> <html <?php echo HTML_PARAMS; ?>> <head> <meta http-equiv="Content-Type" content="text/html; charset=<?php echo CHARSET; ?>"> <title><?php echo TITLE; ?></title> <link rel="stylesheet" type="text/css" href="includes/stylesheet.css"> <script language="javascript" src="includes/general.js"></script> </head> <body marginwidth="0" marginheight="0" topmargin="0" bottommargin="0" leftmargin="0" rightmargin="0" bgcolor="#FFFFFF" onload="SetFocus();"> <div id="popupcalendar" class="text"></div> <!-- header //--> <?php require(DIR_WS_INCLUDES . 'template_top.php'); ?> <!-- header_eof //--> <?php if (isset($_POST['Update'])) { $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { if ($sppc["customers_group_name"] != "Retail"){ //$sppc['customers_group_id'] $c = "CG_".$sppc['customers_group_id']; $tmp = $_POST[$c]; if ($tmp != 0) { $p = (100-$_POST[$c])/100; tep_db_query("delete from products_groups where customers_group_id = ".$sppc['customers_group_id']); tep_db_query ("insert into products_groups select '". $sppc['customers_group_id'] ."' as customers_group_id, ( " . $p . " * p.products_price) as customers_group_price, p.products_id from products p"); } //if not 0 } //if not Retail } } ?> <!-- body //--> <table border="0" width="100%" cellspacing="2" cellpadding="2"> <tr> <td width="<?php echo BOX_WIDTH; ?>" valign="top"><table border="0" width="<?php echo BOX_WIDTH; ?>" cellspacing="1" cellpadding="1" class="columnLeft"> </table></td> <!-- body_text //--> <td width="100%" valign="top"><table border="0" width="100%" cellspacing="0" cellpadding="2"> <tr> <td width="100%"><table border="0" width="100%" cellspacing="0" cellpadding="0"> <tr> <td class="pageHeading"><?php echo "Special Pricing Discount Setup"; ?></td> <td class="specialPrice" align="right"> </td> </tr> </table></td> </tr> <tr> <td><table border="0" width="100%" cellspacing="0" cellpadding="0"> <tr> <td valign="top"><table border="0" width="100%" cellspacing="2" cellpadding="2"> <tr class="dataTableHeadingRow"> <td class="dataTableHeadingContent" align="left"> <?php if (isset($_POST['Update'])) { echo "<center>Updated!</center>"; } ?> </td> </tr> <?php $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { ?> <tr class="dataTableRow" onmouseover="rowOverEffect(this)" onmouseout="rowOutEffect(this)"> <td class="dataTableContent" align="left"> <?php if ($sppc["customers_group_name"] != "Retail"){ echo $sppc["customers_group_name"]; } if (isset($_POST['Update'])) { if ($sppc["customers_group_name"] != "Retail"){ $c = "CG_".$sppc['customers_group_id']; $tmp = $_POST[$c]; echo " Current Discount is $tmp%" ; } } ?> </td> </tr> <?php } ?> </table></td> </tr> <tr> <td valign="top"> <form action="" method="post"> <table border="0" width="40%" cellspacing="0" cellpadding="2"> <tr> <td class="smallText" align="left"> </td> <td> </td> </tr> <?php $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { if ($sppc["customers_group_name"] != "Retail"){ ?> <tr> <td class="smallText" align="left">Set New Percentage (%) Discount for <?=$sppc["customers_group_name"]?> :</td> <td><input name="CG_<?=$sppc['customers_group_id']?>" type="text" size="5" value="0"></td> </tr> <?php } } ?> <tr> <td colspan="2" align="center"><input type="submit" name="Update" value="Update"></td> </tr> </table> </form> </td> </tr> </table></td> <!-- body_text_eof //--> </tr> </table> <!-- body_eof //--> <!-- footer //--> <?php require(DIR_WS_INCLUDES . 'footer.php'); ?> <!-- footer_eof //--> </body> </html> <?php require(DIR_WS_INCLUDES . 'application_bottom.php'); ?> Hello guys, I want to get the values of 3rd level of my referral but it did not echo any value but if i put the ref id directly on the code, it will echo the values. why is it so? or am i doing it the wrong way? in my database i have a table test_referral id acct_name ref_id refer_id 1 john J1234 0 2 bull B3456 J1234 3 doe D5567 J1234 4 frank F7788 J1234 5 jimmy J9990 J1234 6 tommy T6784 F7788 7 tom T9988 F7788 8 girly G8866 D5567 9 fred F0099 J9990 10 ronaldo R7722 B3456 thanks
$stmt= $pdo->query("SELECT * FROM test_referral WHERE acct_name='Chidi Okafor'");
$parent = $stmt->fetch(PDO::FETCH_LAZY);
echo "<ul><li>";
echo $parent['acct_name'];
$ref_id = $parent['ref_id'];
echo "</li><ul>";
$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$ref_id'");
$child_count = $stmt->rowCount();
while($child = $stmt->fetch(PDO::FETCH_LAZY)){
echo "<li>";
echo $child['acct_name'];
$ref_ids = $child['ref_id'];
echo "</li>";
}
//$reff = "F7788";
//$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$F7788'");
$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$ref_ids'");
$child_count2 = $stmt->rowCount();
while($children = $stmt->fetch(PDO::FETCH_LAZY)){
echo "<ul><li>";
echo $children['acct_name'];
echo "</li></ul>";
}
Edited by Mr-Chidi, 25 December 2014 - 05:34 AM. This problem is existing on a few pages so I'll be in the clear if I can figure out to solve it on one page. Problem is on form submission its still echoing back that sortorder variable which makes it hard for it to compare on the success function to display the right message because the message should be good, bad1, bad2, ... . So is there anyway around that or do I need to do something on the client side of the form page. <?php // Include the database page require ('../inc/dbconfig.php'); if ( isset( $_POST['menuid'] ) ) { $menuid = (int)$_POST['menuid']; $query = "SELECT COUNT(sortorder) AS numOrder FROM `menuitems` WHERE `menu_id` = '".$menuid."'"; $result = mysqli_query ($dbc, $query); $row = mysqli_fetch_array( $result, MYSQL_ASSOC ); $sortorder = $row[ 'numOrder' ] + 1; echo $sortorder; } if (isset($_POST['submitmenuitem'])) { $menuid = mysqli_real_escape_string($dbc, $_POST['menuid']); $itemname = mysqli_real_escape_string($dbc, $_POST['itemname']); $itemurl = mysqli_real_escape_string($dbc, $_POST['itemurl']); $sortorder = mysqli_real_escape_string($dbc, $_POST['sortorder']); $contentpage = mysqli_real_escape_string($dbc, $_POST['contentpage']); $newscategory = mysqli_real_escape_string($dbc, $_POST['newscategory']); $application = mysqli_real_escape_string($dbc, $_POST['application']); $query = "SELECT * FROM `menuitems` WHERE (`itemname` = '".$itemname."') OR (`itemurl` = '".$itemurl."') OR (`contentpage_id` = '".$contentpage."') OR (`application_id` = '".$application."') OR (`newscategory_id` = '".$newscategory."') AND `menu_id` = '".$menuid."'"; $result = mysqli_query ( $dbc, $query ); // Run The Query $rows = mysqli_num_rows($result); if ($rows == 0) { $query = "INSERT INTO `menuitems` (menu_id, itemname, itemurl, sortorder, contentpage_id, newscategory_id, application_id, creator_id, datecreated, enabled) VALUES ('".$menuid."','".$itemname."','".$itemurl."','".$sortorder."','".$contentpage."', '".$newscategory."', '".$application."', 1, NOW(), 0)"; mysqli_query($dbc, $query); echo "good"; } else { $row = mysqli_fetch_array($result); if (($row['itemname'] == $itemname) && ($row['newscategory_id'] == $newscategory)) echo 'bad9'; elseif (($row['itemname'] == $itemname) && ($row['application_id'] == $application)) echo 'bad8'; elseif (($row['itemname'] == $itemname) && ($row['contentpage_id'] == $contentpage)) echo 'bad7'; elseif (($row['itemname'] == $itemname) && ($row['itemurl'] == $itemurl)) echo 'bad6'; elseif ($row['newscategory_id'] == $newscategory) echo 'bad5'; elseif ($row['application_id'] == $application) echo 'bad4'; elseif ($row['contentpage_id'] == $contentpage) echo 'bad3'; elseif ($row['itemurl'] == $itemurl) echo 'bad2'; elseif ($row['itemname'] == $itemname) echo 'bad1'; } } if (isset($_POST['deletemenuitem'])){ $menuitemID = (int)$_POST['menuitemID']; $query = "UPDATE `menuitems` SET `enabled` = '1' WHERE `id` = '".$menuitemID."' LIMIT 1"; mysqli_query($dbc,$query); } ?> $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); $users = explode('" id="r4_', $lastfm); $users = explode('">', $users[1]); var_dump($users[0]); that is only echoing one ID http://www.last.fm/group/Rishloo/members 1 id for each member it should be echoing.. any idea why it isnt? $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); $grab_id=explode('" id="r4_', $lastfm); for($b=1; $b<count($grab_id); $b++){ $getid=explode('">', $grab_id[$b]); echo count($getid[0]); } that echos all 1's.. any help is appreciated.. thanks thanks I want to echo the contents of column 4 for my username only, and it doesn't show anything. I can do if ($memberQuery->fetchColumn(4) < 2)() though. Code: [Select] $host = 'localhost'; $database = ''; $db_username = ''; $db_password = ''; if (($db = new PDO("mysql:host=$host;dbname=$database", $db_username, $db_password)) == NULL) { echo $db->getMessage(); } $memberQuery = $db->prepare("SELECT * FROM members WHERE username=:username"); $memberQuery->execute(array(':username' => $_SESSION['username'])); $result = $memberQuery->fetchColumn(4); echo "$result"; I am having issue creating a checkbox that uses a onClick() js method. I believe this might be due to the fact that I am echoing the html but if any one could help id appreciate it. echo "<tr><td>WrkComp</td><td><input type='checkbox'" ?> <script>onClick="show()" </script> <? "name='WrkComp[]' value='DEP' '.$checked.' '.$Disabled.'/></td>"; i am having issues checking which value is checked in a form. here is my code for it: Code: [Select] <input type="radio" name="accountActivation" id="no" value="no" checked=" <? if (isset($register_errors)) { if (($_POST['accountActivation']) == "no") { echo "checked"; } } ?> " /> when i first open the page, no is checked. why is this, when there should be no errors, and the radio should not even be checked in the first place? Okay, I am having trouble. My script is not echoing the errors on the page/nor logging me in. If I check the browser source code it shows the error. here are my pages please help this is stupid ha index.php Code: [Select] <?php session_start(); include("includes/config.php"); if($_POST['submit']) { include("includes/action/".strtolower($_POST['submit']).".php"); } if (isset($_SESSION['SecureUid'])) { echo "Welcome Member!"; } else { echo $_SESSION['SecureUid']; $Larray = array ( "Username" => array("text","LoginUsername"), "Password" => array("password","LoginPassword"), "Hidden" => array("hidden","SecureHidden"), "Login" => array("submit","Login"), ); if ($LoginErrors) { foreach ($LoginErrors as $val) { echo "{$val}<br />"; } $Site->ClearErrors(); } $CreateForm = $Site->CreateForm("Login","{$_SERVER['PHP_SELF']}","post",$Larray); echo $CreateForm; } ?> includes/config.php Code: [Select] <?php ini_set( "display_errors", true ); date_default_timezone_set( "America/Phoenix" ); define( "CLASS_PATH", "includes/classes" ); //define( "TEMPLATE_PATH", "templates" ); define( "HOMEPAGE_NUM_ARTICLES", 5 ); function handleException( $exception ) { echo "Sorry, a problem occurred. Please try later."; error_log( $exception->getMessage() ); } set_exception_handler( 'handleException' ); include(CLASS_PATH."/class.database.php"); include(CLASS_PATH."/class.actions.php"); $Site = new Actions; $Site->connect(); $Site->setDatabase("ccloyd_rigid"); ?> includes/actions/login.php Code: [Select] <?php //log user in if ($_POST['SecureHidden']) { $Login = $Site->LoginUser(array("Username" => $_POST['LoginUsername'], "Password" => $_POST['LoginPassword'])); if ($Login) { $_SESSION['SecureUid'] = $Site->Uid; $_SESSION['SecureLevel'] = $Site->getLevel($Site->Uid); } else { $LoginErrors = $Site->ReturnErrors("Login"); } } ?> includes/classes/class.actions.php Code: [Select] <?php class Actions extends Database { public $Uid; //Login Vars private $Username; private $Password; //Errors Array private $Errors = array(); public function LoginUser($info, $admin = NULL) { //ugh //startover foreach ($info as $key => $val) { $this->{$key} = mysql_real_escape_string($val); } $this->Password = $this->EncryptPass($this->Password); if ($this->Username == '' || $this->Password == '') { $this->Errors["Login"] = array('Invalid Credentials!'); return false; } $Check = $this->select("users","`id`","username = '{$this->Username}' AND password = '{$this->Password}'"); if ($Check) { $Result = $this->getResult(); $id = $Result[id]; $this->Uid = $id; return true; } else { $this->Errors["Login"] = array('Invalid Credentials!'); return false; } } } ?> Hi all, ive got a script witch im wanting to echo all the selected users in a table.. It selects and echos the users but just dosent add on to the table. <?php $themembers = mysql_query("SELECT * FROM users WHERE crew = '$user->crew'"); $ammoutmembers = mysql_num_rows($themembers); ?> <html> <head> <title>Crew Members || SD</title> </head> <body> <?php if ($crewstuff->boss == $username || $crewstuff->coowner == $username || $crewstuff->underboss == $username){ ?> <table width='80%' align='center' class='table' cellpadding='0' cellspacing='0' border='1'> <tr> <td class='header' colspan='3' align='center'>Current Crew Members</td> </tr> <tr> <td class='omg' align='center' width='40%'>Username</td><td class='omg' align='center' width='30%'>Rep</td><td class='omg' width='30%' align='center'>Kick</td> </tr> <?php if ($ammoutmembers != "0"){ while ($member11 = mysql_fetch_object($themembers)){ ?> <tr> <td width='40%'><?php echo("<a href='profile.php?viewuser=$member11->username' target='mainFrame'>$member11->username</a>"); ?></td><td width='30%'><?php echo ("".number_format($member11->rep).""); ?></td><td width='30%'><?php echo("<a href='?action=members&kick=$member11->username'>Kick</a>"); ?></td> </tr> <tr> <td colspan='3' class='omg' align='center'>Any member kicked is logged.</td> </tr> </table> <?php } // $member11 }// $ammoutmembers }elseif ($crewstuff->member == $username){ echo ("Your not being here , without being staff."); } ?> Is there way I can make it so it will be something like this layout: Username | Rep | Kick ---------------------------------- username | 0 | Kick username | 0 | kick For each user thats echoed? Thanks for help given Hi all, On my website I have a Functions file which holds information about the user for the game, but earier on today I added ranks which are for the users money. So for the ammout of money they have gives them a different money rank. Heres what ive got: function wealthrank(){ if (($info->money >= "0") && ($info->money < "10000")){ $wealth = "Poor (£0 - £10,000)"; $done="1"; } elseif (($info->money >= "10000") && ($info->money < "500000")){ $wealth = "Won The Lottery (£10,000- £500,000)"; $done="1"; } elseif (($info->money >= "500000") && ($info->money < "5000000")){ $wealth = "Too Much (£500,000 - £5,000,000)"; $done="1"; } elseif (($info->money >= "5000000") && ($info->money < "20000000")){ $wealth = "Millionare (£5,000,000 - £20,000,000)"; $done="1"; } elseif (($info->money >= "20000000") && ($info->money < "75000000")){ $wealth = "Owns The Streets (£20,000,000 - £75,000,000)"; $done="1"; } elseif (($info->money >= "75000000") && ($info->money < "100000000")){ $wealth = "Won The Euro Millions (£75,000,000 - £100,000,000)"; $done="1"; } elseif (($info->money >= "100000000") && ($info->money < "300000000")){ $wealth = "Multi millionare (£100,000,000 - £300,000,000)"; $done="1"; } elseif (($info->money >= "300000000") && ($info->money < "700000000")){ $wealth = "Owns A Bank (£300,000,000 - £700,000,000)"; $done="1"; } elseif (($info->money >= "700000000") && ($info->money < "1500000000")){ $wealth = "Rather Rich (£700,000,000 - £1,500,000,000)"; $done="1"; } elseif (($info->money >= "1500000000") && ($info->money < "5000000000")){ $wealth = "Billionare (£1,500,000,000 - £5,000,000,000)"; $done="1"; } elseif (($info->money >= "5000000000") && ($info->money < "70000000000")){ $wealth = "Owner Of The Land (£5,000,000,000 +)"; $done="1"; } elseif ($info->money >= "100000000000"){ $wealth = "Nearly As Rich As NoName (Hidden!)"; $done="1"; } if (!$done){ $done="0"; } if ($done == "1"){ mysql_query("UPDATE users SET wealthrank='$wealth' WHERE username='$username'"); }} wealthrank(); For some reason its not echoing the correct wealth rank, even at that its only echoing the defult wealth rank. Here is what I done to test it. <?php session_start(); include ("includes/functions.php"); include ("includes/config.php"); logincheck(); $username = $_SESSION['username']; $get = mysql_query ("SELECT * FROM users WHERE username='$username'"); $fetch = mysql_fetch_object($get); ?> Testing something: <?php echo ($username); ?><br /> Wealth Rank: <?php echo ($fetch->wealthrank); ?><br /> Is there something wrong with the way im fetching it from the Database or something wrong with the code? Thanks for any help given. Hi, I am trying to insert a variable in the body of an email lik so: Code: [Select] $message = "Dear Administrator,\n\nthe following distributor\n\n'.$row_admin_login_RS['distributor_company_name'].'\n\nHas modified his Distributor information record.\n\"; I know it must be a syntax error...but I can't figure it out. Thanks I have a login form at http://cloydprojects.com you can login with username: test password test If you login the script works correctly, but if you type in the wrong info my session is not showing here is that I have. my login script Code: [Select] <?php session_start(); ?> <link href="signUp.css" rel="stylesheet" type="text/css" /> <?php include("db.php"); include("classes/class.account.php"); $Acc = new account; $u = $Acc->clean($_REQUEST['usernameLogin']); $password = $Acc->clean($_REQUEST['passwordLogin']); $p = md5($password); $get = mysql_query("SELECT * FROM users WHERE username = '".$u."' and password = '".$p."'"); $find = mysql_num_rows($get); if ($find == 1) { $info = mysql_fetch_assoc($get); $_SESSION['LoggedIn'] = $info['uID'].'.'.$info['username'].'.'.$info['email']; } else { $_SESSION['LoggedFailed'] = '<div id="ErrorBox">Incorrect username/password!</div>'; } //there is more just not showing it here is my index script where the error should be showing! Code: [Select] <div class="stylized"> <?php if(isset($_SESSION['LoggedIn'])) { echo '<h1> Welcome! </h1>'; echo '<a href="logout.php">logout!</a>'; } else { echo $_SESSION['LoggedFailed']; session_destroy(); ?> <form id="instantform" name="form" action="loginUser.php" method="post"> <h1>Login</h1> <label>Username <span class="small">The username you created!</span></label> <input type="text" name="usernameLogin" id="usernameLogin" /> <label>Password <span class="small">Case sensitive!</span></label> <input type="password" name="passwordLogin" id="passwordLogin" /> <button type="submit">Login</button></div> <div class="spacer"></div> </form> <?php } ?> </div> I am probably making a dumb mistake...but heres the code... $gif = '.gif'; $jpg = '.jpg'; $jpeg = '.jpeg'; $png = '.png'; $jpeg1 = 'jpeg'; $gif1 = 'gif'; $jpg1 = 'jpg'; $png1 = 'png'; $max_file_size = '1048576'; $new_avatar = $_FILES['uploaded_avatar']['name']; $avatar_ext = end(explode('.', $new_avatar)); if (isset($_POST['change_submit1'])) { if ($_SESSION['logged_in'] != '1') { echo 'You need to be logged in!'; } elseif ($_POST['change_box1'] != 'CHANGE') { echo 'You must fill in the "CHANGE" box!'; } elseif (($uploaded_a_file == '1') && ($avatar_ext != $jpg1) && ($avatar_ext != $png1) && ($avatar_ext != $gif1) && ($avatar_ext != $jpeg1)) { echo 'File format not supported!'; } elseif ($uploaded_a_file != '1') { echo 'No file selected!'; } elseif ($_FILES["uploaded_avatar"]["size"] > $max_file_size) { echo 'File is too big!'; } } this is the code that should be echoing my avatar upload errors. Ive checked all the if statements ive changed the order around. still nothing. all of them work other than file format not supported. I can get this one to work...but at the cost of no file selected not working...help! |
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