PHP - Get Info From One Table And Placing It Into Another One
I have two different tables and I am trying to condense them into one table.
The structure of the tables is
cc
-- ci
-- cc
-- cn
-- alpha_2
countries
-- id
-- cn
-- alpha_2
-- alpha_3
What I want to do is place the info from the column alpha_2 in the countries table into the alpha_2 column in the cc table.
I have tried inner joins, left joins, Insert and Select index. Everything that I have tried gives me an error message. I do not know what I am doing wrong and I was hoping that someone would be able to give me a hand.
I forgot to mention that I want the placement of the alpha_2 column to be based on the cn columns in both tables. So that the information in the alpha_2 column lines up with the right name in the cn column
Edited by mdmartiny, 09 August 2014 - 01:07 PM. Similar TutorialsThink I made a post about this earlier but doesn't show so dont think it posted successfully but if it did, my bad haha. Basicly I have a form which sends info to my database table after submitted. I added some form validation so when the user didn't enter a required field, text appears stating that the field needs to be entered. However, whether the field is entered or not, if the user submits the info still goes to the database. How do I fix it so that it only sends the info to the database once the required fields are entered? Do I go about it with an if statement? Heres my code up until now: Code: [Select] <?php if (isset($_POST['submit'])) { // forms inputs set to variables $cname = mysql_real_escape_string($_POST['cname']); $sname = mysql_real_escape_string($_POST['sname']); $init = mysql_real_escape_string($_POST['init']); $fname = mysql_real_escape_string($_POST['fname']); $title = mysql_real_escape_string($_POST['title']); $msname = mysql_real_escape_string($_POST['msname']); $dob = mysql_real_escape_string($_POST['dob']); $sex = mysql_real_escape_string($_POST['sex']); $lang = mysql_real_escape_string($_POST['lang']); $idno = mysql_real_escape_string($_POST['idno']); $telh = mysql_real_escape_string($_POST['telh']); $telw = mysql_real_escape_string($_POST['telw']); $cell = mysql_real_escape_string($_POST['cel']); $fax = mysql_real_escape_string($_POST['fax']); $email = mysql_real_escape_string($_POST['email']); $address = mysql_real_escape_string($_POST['address']); $errorstring =""; //default value of error string if (!$sname) $errorstring = $errorstring . "Surname<br>"; if (!$fname) $errorstring = $errorstring . "First name<br>"; if (!$title) $errorstring = $errorstring . "title<br>"; if (!$dob) $errorstring = $errorstring . "date of birth<br>"; if (!$sex) $errorstring = $errorstring . "sex<br>"; if (!$idno) $errorstring = $errorstring . "id number<br>"; if (!$email) $errorstring = $errorstring . "email address<br>"; if (!$address) $errorstring = $errorstring . "address<br>"; if ($errorstring!="") echo "Please fill out the following fields:<br>$errorstring"; else { //run code die("success!"); } // query $sql = "INSERT INTO student (sno, cname, sname, init, fname, title, msname, dob, sex, lang, idno, telh, telw, cel, fax, email, address ) VALUES ('', '$cname', '$sname', '$init', '$fname', '$title', '$msname', '$dob', '$sex','$lang', '$idno', '$telh', '$telw', '$$cell', '$fax', '$email', '$address')"; mysql_query($sql) or die('Error:' . mysql_error()); } mysql_close($link); ?> It's a project, first time I'm attempting form validation so this is rather new for me. With that being said, please feel free to give any tips and criticism as this is a learning curve for me. Also I'm probably going to add some security later for sql injection etc. so if anyone has some tips on that it would be great. Almost done with that damn project, thanks in advance Hi, okee so I'm new to everything that has to do with scripting, especially when it comes to PHP and stuff, but what is the best way to display information from a table on a page? I'm creating this site where users can post their events, but I want the Location to be based on the Location they inserted during the registration process, so that the location will be displayed directly. How am I able to do that? I've already got an login script, it looks like this: Code: [Select] <?php ob_start(); $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="whats_happening_db"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Define $myusername and $mypassword $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; // To protect MySQL injection (more detail about MySQL injection) $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $myusername and $mypassword, table row must be 1 row if($count==1){ // Register $myusername, $mypassword and redirect to file "login_success.php" session_register("myusername"); session_register("mypassword"); header("location:membersarea.php?user=$myusername"); } else { echo "Wrong Username or Password"; } ob_end_flush(); ?> Sorry if my English is terrible haha. Dante. Hello, me again. I have created a little forum - very very basic. main_forum.php : Code: [Select] <?php $host="localhost"; // Host name $username="yvonnedp"; // Mysql username $password="yvonne"; // Mysql password $db_name="forum"; // Database name $tbl_name="forum_question"; // Table name // Connect to server and select databse. mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name ORDER BY id"; // OREDER BY id DESC is order result by descending $result=mysql_query($sql); ?> <table width="90%" border="0" align="center" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td width="6%" align="center" bgcolor="#E6E6E6"><strong>#</strong></td> <td width="53%" align="center" bgcolor="#E6E6E6"><strong>Topic</strong></td> <td width="15%" align="center" bgcolor="#E6E6E6"><strong>Views</strong></td> <td width="13%" align="center" bgcolor="#E6E6E6"><strong>Replies</strong></td> <td width="13%" align="center" bgcolor="#E6E6E6"><strong>Date/Time</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ // Start looping table row ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><a href="view_topic.php?id=<? echo $rows['id']; ?>"><? echo $rows['topic']; ?></a><BR></td> <td align="center" bgcolor="#FFFFFF"><? echo $rows['view']; ?></td> <td align="center" bgcolor="#FFFFFF"><? echo $rows['reply']; ?></td> <td align="center" bgcolor="#FFFFFF"><? echo $rows['datetime']; ?></td> </tr> <?php // Exit looping and close connection } mysql_close(); ?> create_topic.php : Code: [Select] <table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form id="form1" name="form1" method="post" action="add_topic.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3" bgcolor="#E6E6E6"><strong>Create New Topic</strong> </td> </tr> <tr> <td width="14%"><strong>Topic</strong></td> <td width="2%">:</td> <td width="84%"><input name="topic" type="text" id="topic" size="50" /></td> </tr> <tr> <td valign="top"><strong>Detail</strong></td> <td valign="top">:</td> <td><textarea name="detail" cols="50" rows="3" id="detail"></textarea></td> </tr> <tr> <td><strong>Name</strong></td> <td>:</td> <td><input name="name" type="text" id="name" size="50" /></td> </tr> <tr> <td> </td> <td> </td> <td><input type="submit" name="Submit" value="Submit" /> <input type="reset" name="Submit2" value="Reset" /></td> </tr> </table> </td> </form> </tr> </table> add_topic.php : Code: [Select] <?php $host="localhost"; // Host name $username="yvonnedp"; // Mysql username $password="yvonne"; // Mysql password $db_name="forum"; // Database name $tbl_name="forum_question"; // Table name // Connect to server and select database. mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get data that sent from form $topic=$_POST['topic']; $detail=$_POST['detail']; $name=$_POST['name']; $datetime=date("d/m/y h:i:s"); //create date time $sql="INSERT INTO $tbl_name(topic, detail, name, datetime)VALUES('$topic', '$detail', '$name', '$datetime')"; $result=mysql_query($sql); if($result){ echo "Successful<BR>"; echo "<a href=main_forum.php>View your topic</a>"; $email_from = "forums@thenewme.co.za"; $email_to = "info@thenewme.co.za"; $email_subject = "The New Me - New Forum Topic"; $email_message = "A new topic has been posted on the Forum!\n"; $email_message .= "Check it out : http://www.thenewme.co.za/forum/main_forum.php"; $headers = 'From: '.$email_from."\r\n"; 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); } else { echo "ERROR"; } mysql_close(); ?> add_answer.php : Code: [Select] <?php $host="localhost"; // Host name $username="yvonnedp"; // Mysql username $password="yvonne"; // Mysql password $db_name="forum"; // Database name $tbl_name="forum_answer"; // Table name // Connect to server and select databse. mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Get value of id that sent from hidden field $id=$_POST['id']; // Find highest answer number. $sql="SELECT MAX(a_id) AS Maxa_id FROM $tbl_name WHERE question_id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); // add + 1 to highest answer number and keep it in variable name "$Max_id". if there no answer yet set it = 1 if ($rows) { $Max_id = $rows['Maxa_id']+1; } else { $Max_id = 1; } // get values that sent from form $a_name=$_POST['a_name']; $a_answer=$_POST['a_answer']; $datetime=date("d/m/y H:i:s"); // create date and time // Insert answer $sql2="INSERT INTO $tbl_name(question_id, a_id, a_name, a_answer, a_datetime)VALUES('$id', '$Max_id', '$a_name', '$a_answer', '$datetime')"; $result2=mysql_query($sql2); if($result2){ echo "Successful<BR>"; echo "<a href='view_topic.php?id=".$id."'>View your answer</a>"; // If added new answer, add value +1 in reply column $tbl_name2="forum_question"; $sql3="UPDATE $tbl_name2 SET reply='$Max_id' WHERE id='$id'"; $result3=mysql_query($sql3); $email_from = "forums@thenewme.co.za"; $email_to = "info@thenewme.co.za"; $email_subject = "The New Me - New Forum Answer"; $email_message = "A new answer to a forum topic has been posted on the Forum!\n"; $email_message .= "Check it out : http://www.thenewme.co.za/forum/main_forum.php"; $headers = 'From: '.$email_from."\r\n"; 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); } else { echo "ERROR"; } mysql_close(); ?> view_topic : Code: [Select] <?php $tbl_name2="forum_answer"; // Switch to table "forum_answer" $sql2="SELECT * FROM $tbl_name2 WHERE question_id='$id'"; $result2=mysql_query($sql2); while($rows=mysql_fetch_array($result2)){ ?> <table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td><table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td bgcolor="#F8F7F1"><strong>ID</strong></td> <td bgcolor="#F8F7F1">:</td> <td bgcolor="#F8F7F1"><? echo $rows['a_id']; ?></td> </tr> <tr> <td width="18%" bgcolor="#F8F7F1"><strong>Name</strong></td> <td width="5%" bgcolor="#F8F7F1">:</td> <td width="77%" bgcolor="#F8F7F1"><? echo $rows['a_name']; ?></td> </tr> <tr> <td bgcolor="#F8F7F1"><strong>Answer</strong></td> <td bgcolor="#F8F7F1">:</td> <td bgcolor="#F8F7F1"><? echo $rows['a_answer']; ?></td> </tr> <tr> <td bgcolor="#F8F7F1"><strong>Date/Time</strong></td> <td bgcolor="#F8F7F1">:</td> <td bgcolor="#F8F7F1"><? echo $rows['a_datetime']; ?></td> </tr> </table></td> </tr> </table><br> <? } $sql3="SELECT view FROM $tbl_name WHERE id='$id'"; $result3=mysql_query($sql3); $rows=mysql_fetch_array($result3); $view=$rows['view']; // if have no counter value set counter = 1 if(empty($view)){ $view=1; $sql4="INSERT INTO $tbl_name(view) VALUES('$view') WHERE id='$id'"; $result4=mysql_query($sql4); } // count more value $addview=$view+1; $sql5="update $tbl_name set view='$addview' WHERE id='$id'"; $result5=mysql_query($sql5); mysql_close(); ?> the problem is. With add_answer, I am not able to insert an answer. This has worked for the very first question, but all subsequent questions, I am unable to add answers. It keeps telling me ERROR. This is where the live forum is : http://www.thenewme.co.za/forum/main_forum.php Can it be an issue with the field that gets autmatically incremented? i have echo'd the data which get entered in when someone types in an answer, and everything is perfect! Can anyone help me? Hello I'm trying to set up a user area for my site where it displays the current logged in users ranking and other information in the future. <? ini_set('display_errors', 1); require_once "header.php"; $sql = "SELECT * FROM users WHERE username = ?"; if($stmt = mysqli_prepare($link, $sql)){ mysqli_stmt_bind_param($stmt, 's', $_SESSION['username']); if(mysqli_stmt_execute($stmt)){ $info = mysqli_fetch_array($stmt); echo "Current rank:" . $info['rank']; } else { echo "Can't find user"; } } mysqli_stmt_close($stmt); ?> That's the code I currently have but it gives me the error "but get an error message of mysqli_fetch_array() expects parameter 1 to be mysqli_result" How can i use single quote for values? $qry='insert into tablename values('a','b');'; Hi all, I have a number of tables within a mysql database and I'm stuck on how to pull information from one based on the results being displayed by another. The site shows items for sale where by all the product information is held in tablea, when an individual item is being displayed I need to be able to pull a manufacturer profile from tableb based on the manufacturer name stored in tablea column profile. The manufacturer name is already being called into the page by existing code as the site has always shown the manufacturer name, I just can't work out out to pull the new profile information in as well from the new table. Any help appreciated Iain well I know the standard way of retrieving mysql data was through the following codes: Code: [Select] $query = "SELECT * FROM {$tablename} WHERE columnmame = '{$var}'"; $result = mysql_query($query); $row = mysql_fetch_array($result); This will return all properties inside a table row by an associative array indexed by column names. I am, however, wondering if there is an easier way to retrieve database info from more than one table. For now, what I am doing is: Code: [Select] $result = mysql_query( "SELECT * FROM {$tablename} WHERE columnmame = '{$var}'"); $row = mysql_fetch_array($result); $result2 = mysql_query( "SELECT * FROM {$tablename2} WHERE columnmame2 = '{$var2}'"); $row2 = mysql_fetch_array($result2); which is a bit tedious and can cause problems when two or more coders work on the same project(it will be difficult to tell what is $row1, $row2 and $row3...). Is there away to write a simpler code than the one above? I mean, if it is possible to run mysql_fetch_array only once and retrieve database info from multiple tables? Hi.. been a while since I have touched php and need some help. What I am trying to do is have my links pull text from separate php files, and load them into main table. Here is my old php code..used to work.. I had my index.php with my website template on it. In the table I want my info to appear i put this code. <?php /* START MAIN AREA HERE */ if($news) include("news.php"); elseif($bio) include("bio.php"); elseif($draw) include("draw.php"); elseif($pic) include("pic.php"); else include("news.php"); /* END HERE */?> My link looks like this. <A HREF="?news=x" ONMOUSEOVER="changeImages('home', 'images/home-over.gif'); return true;" ONMOUSEOUT="changeImages('home', 'images/home.gif'); return true;"> <IMG NAME="home" SRC="images/home.gif" WIDTH=69 HEIGHT=31 BORDER=0 ALT=""></A> Any help much appreciated! Hi there, I have a database with table column called EXPAMOUNT
if EXPAMOUNT value was £5.50 My code at moment echo “Total Expenses   £” . $row[‘SUM(EXPAMOUNT)’]. “ Hi, I have a project, where i want to place a text over the image dynamically, just like if it is sold, i want to make it as SOLD text over the image Looking for idea to implement this, Thanks, Hi, $_POST['arr_name']; I want to make the search so that am getting the array values and oputting in IN(val1, val2, val3) Thanks Okay, I would like to redirect my page within a specific time using java script: <meta http-equiv="Refresh" content="3;url=<?PHP echo 'progress.php?user=';$session->username?>"> Basically, I would like it to redirect to this: progress.php?user=$session->username. But it redirects to: progress.php?user= Please help, thanks ... I believe the solution the my problem should be simple I feel that it's staring me right in the face. I have a Cron Job that sends an email message to users who's bill "due date" falls on the current date. I want to make the email more personalized and say:
Dear John Doe:
You have the following bills due today:
Rent
Cable
Internet
Please login to pay your bills
Thanks,.
Here's my following PHP code
<?php header("Content-type: text/plain"); // OPEN DATA BASE define("HOSTNAME","localhost"); define("USERNAME",""); define("PASSWORD",""); define("DATABASE",""); mysql_connect(HOSTNAME, USERNAME, PASSWORD) or die("Connetion to database failed!"); mysql_select_db(DATABASE); joinDateFilter(); // BILL QUERY function joinDateFilter(){ $query = mysql_query("SELECT bills.billname, bills.duedate, bills.firstname, bills.email, bills.paid FROM bills JOIN users ON bills.userid=users.userid WHERE DATE(bills.duedate) = CURDATE() AND bills.PAID != 'YES'"); $mail_to = ""; while ($row = mysql_fetch_array($query)){ echo $row['firstname']." - ".$row['email']."\n"; $mail_to = $row['email'].", "; } if (!empty($mail_to)){ sendEmail($mail_to); } } // SEND EMAIL function sendEmail($mail_to) { $from = "MyEmail@myemail.com"; $message = "Dear " . $row['firstname'].", <br><br>" ."You have the following bills due today.<br><br>" .$row['billname']. "<br><br>" ."Please login to pay your bills"; $headers = 'From: '.$from."\r\n" . 'Reply-To:'.$_POST['email']."\r\n" . "Content-Type: text/html; charset=iso-8859-1\n". 'X-Mailer: PHP/' . phpversion(); mail($mail_to, "Today is your due date", $message, $headers); } ?> Edited by demeritrious, 26 December 2014 - 07:21 PM. Hi There, I want to be able to populate 2 variables, $previousmon and $previousfri with 2 dates, being the previous Monday and the previous Friday to the week you are on. So for example, if it is Monday 31st Jan, then $previousfri would be 28/01/2011 and $previousmon would be 24/01/2011. Is this easy enough to do? Cheers Matt Hi Guys, I'm going to try and watermark my uploaded images with a small logo (placed onto the original image) so they are all watermarked, is there any tutorials anyone can recommend to do this? i can't seem to find any online. thanks for any help guys Graham Hi There, I would like to place the last for month names into an variable- for example: February 2011 January 2011 December 2010 November 2010 But I would like them to all have the same variable ($date) - so when I use it in a mssql_fetch_assoc - it increments with every instance of $date, as there will be one instance of $date for every row returned, getting older with every row. Hope that is enough info? Cheers Matt I want a div at the bottom of another div, and I want it centered, just using css not javascript.
HTML <div id="parent"> <div id="bottom_element">test</div> </div> CSS #parent {height:100% width:100%} #bottom_element {position:absolute; bottom:5px; width:200px; margin:0 auto}So the issue is that position absolute and margin auto do not seem to work together. What is an alternative without javasript? Basically i have a folder with 100+ images they are NOT all the same extension, what im wanting to do is use PHP to find all the images and put them all in a database. how would i go about doing this? thanks Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! Hey guys, It's been awhile since I've coded in PHP and I can not for the life of me remember how to do this. Say I have http://www.example.com/search.php?name=joe&size=small What the PHP code to grab the ?name=joe&size=small part? thanks |