PHP - Closing Php Tag In Function To Write Html Good Practice?

Hi   I have a self calling script which does the following:   Stage 1: First run, it detects that $_POST is empty, and so displays a chunk of html which prompts for a password. Stage 2: When resubmitted, it detects $_POST and displays another chunk of html which prompts the user for some values Stage 3; When resubmitted the second time, $_POST is detected, along with the user values and some php is executed and a menu displayed.   So, question is this, what is the best method to output the html at stage 1 and stage 2? I have tried using echo statements and wrapping each chunk in a function = messy.  I have tried using HEREDOCS (<<<VARNAME), better but ties my HTML to my script which is a pain I am thinking to use file_get_contents("../html/chunk1.htm") this seems quite elegant and allows me to get someone else on our team to design the HTML keeping it out of my script   Thoughts and suggestions?   Thanks as ever   p.s. who pays for this site, are donation accepted?

Hello,

I'm working on a page where users can add articles by writing text in textareas with a WYSIWYG editor. When they submit the form it's saved in a database.
As a summary of the article i grab the first 800 characters of the article, but as you could imagine there might occur html tags like <div> or <span> in the summary which are not closed. To prevent this from ruining my page layout when their articles are posted on the wegbsite I could use strip_tags but I'd like to keep the format, also this would delete images.
I couldn't think of another solution then a function which checks for open tags and if so; add closing tags at the end of the summary.
I already made a similar function a while back, but that one only checks for <div> and <span>, as those are the worst.. The nasty part is that I kind of deleted that function accidentally, and I can't fully remember how I wrote that..

So what I would like to have is a function that checks for all unclosed html tags and add the associated closing tags, in the right order, at the end of the summary. Any help getting on the right track is appreciated.

Hi there, I am currently using the in_array() function to check the user's country with the country in the ShippingProfile table.

I have a function that returns the shipment profile info from the table.

$myshipProfile = filter_shippingprofile(array(......)); 

And in the $myshipProfile I get the profile info with the countryID. Now I can check the user's country in the array:

 if(in_array($_SESSION['userCountryId'], $myshipProfile))

      {

        print "yes country is found";

      } 

I works fine so far. But there is a slight problem to it.

I did a quick:

print_r($myshipProfile); 

And the output was:

Array ( [shippingprofileID] => 14 [supplierId] => 66 [shippingprofilename] => ProfName1 [shippingto] => CustomCountries [ShipRegionCountries] => 66 [shippingcost] => 10

Notice the supplierId and the ShipRegionCountries has the same value. And now when I try to perform in_array() it will return true every time even if the ShipRegionCountries is not 66 because as supplierID is 66.

You see the conflict.

Therefore, can we write like this:

 if(in_array($_SESSION['userCountryId'], $myshipProfile['ShipRegionCountries']))

                    {

                        print "yes country is found";

                    } 



I get no ouput for this. Whats the correct way to check only the 'ShipRegionCountries' in the array?

Thank you

I have a form that users input user name, password, and email... all writes to csv fine.  My problem is I need to concatenate a a string with a variable and some html code will preserving the html when written to the csv..

I need the csv to be this

username,password,email,user,category,text with http://sub.domain..com/splash/,something,something

here's what i have

Code: [Select]
<?php
if($_POST['formSubmit'] == "Submit")

$varUserName = $_POST['username'];
$varPW = $_POST['PW'];
$varEmail = $_POST['email'];
{
$fs = fopen("testcsv.csv","a");
fputcsv($fs, array($varUserName,$varPW,$varEmail,"user","title",",category","some text '<a href="http://$varUserName.url.com/splash/>site.com</a>',));
fclose($fs);

exit;
}
?>
and of course I'm getting

Parse error: syntax error, unexpected T_STRING, expecting ')' on line 9

Hello:
I have this snippet of code that will write the current year onto a page if it's embedded on the page itself:
Code: [Select]
<?php echo date("Y") ?>

Works fine.

But, when I include it in an included file and pull it onto the page with a function, it does not work.

Like this:
MyNav.php
Code: [Select]
<?php

function spFooter() {
$spFooter =
"
   <p>
   
   &copy; <?php echo date(\"Y\") ?>
 
   </p>

";

return $spFooter;
}
?>

MyPage.php
Code: [Select]
<?php
include('include/myNav.php');
?>
<html>
...

<?php echo spFooter(); ?>

...
</html>

What is the proper way to do this, and also what are the basic rules for properly nesting PHP scripts like this?

Thanks for the help.

I'm trying to include a routine to catch an error but it doesn't seem to write to a text file within a function. just using the following simple code, even if I simply try to write a letter it doesn't work

 

if ($http_status == 200) {
        return $response;

    } else {


$myfile = fopen("ErrorData.txt", "a+") or die("Unable to open file!");

$txt =  date("H:i:sa d-m-Y")." / Error data- / ".json_encode($response)."\r\n";
fwrite($myfile, $txt);
fclose($myfile);


}

 

 

Edited September 13, 2019 by Dvae56
Added code

This is my error:
Code: [Select]
Fatal error: Can't use function return value in write context in /home/a8152576/public_html/SecretSanta.html on line 41
confused about why.
This is the line 41:
if(isset($_POST('submit')){

this is the php of my page (without the mysql data):

<?php
class functions{
public static function chooseGiftee($SS){
     $done = false;
        while($done=false){
     $sqllink= mysql_connect($mysql_host,$mysql_user,$mysql_password);
     if(!$sqllink){
     echo "Could not connect! Please Try Again";
         mysql_close($sqllink);
     } else {
     $selectGiftee = "SELECT * FROM SecretSantas ORDER BY RAND() LIMIT 0,10;";
             while($row=mysql_fetch_array($result)){
                 $results = mysql_query($selectGiftee);
              if(!$row['Gifter']=''){
                  $done=false;
                 } else {
              $gifteeResults = $row['Name'];
                        $addSS = "INSERT INTO SecretSantas (Gifter) VALUES ('" .$SS. "')";
                        $done=true;
              return $gifteeResults;
                 }
             }
     }
            mysql_close($sqllink);
        }
    }
}

if(isset($_POST('submit')){
$echoName = functions::chooseGiftee($_POST['gifterName']);
echo $echoName;
}
?>

This is html:

<form id="form1" name="form1" method="post" action="">
  <p>
    <label>Your Name:
      <input type="text" name="gifterName" id="gifterName" />
    </label>
    <input type="submit" name="submit" id="submit" value="Submit" />
  </p>
  <p>&nbsp;</p>
</form>


Confused about the issue, first time using functions.
Thanks in advance,
Brandon

Hi,
I have some strange issues with my code:

Code: [Select]
<?PHP
session_start();
$loginid = $_SESSION["valid_id"];
// First check if we are guest or user.
if (!$_SESSION["valid_email"])
{
$visitor = "yes";
}
else
{
$visitor = "no";
$email = $_SESSION['valid_email'];
$userid = $_SESSION['valid_id'];
}
//Load Header (blue menu)
require("./inc/header.php");
//Load Sub-acc (silver account menu)
require("./inc/sub-group.php");
//Load nav-group (Tabs)
require("./inc/nav-group.php");
//Load Config file
require("./inc/config.php");
//Set & get profile ID
$getid = $_GET["id"];
//check ID
$result = mysql_query("SELECT * FROM profiles WHERE id=('$getid')  LIMIT 1");
$row = mysql_fetch_array($result);

IF (mysql_num_rows($result) != 1)
{
 exit("Invalid ID");
}

//If we are guest, do we allow anon access to the profile
IF ($row["privacy"] <= 10 && $visitor = "yes")
{
exit("You may not view this profile as a visitor, due to the users privacy settings");
}
//Let's check if we are friends
ELSEIF ($visitor = "no")
{
$result2 = mysql_query("SELECT * FROM profiles_friends WHERE user=('$getid') AND target=('$loginid')  LIMIT 1");
$row2 = mysql_fetch_array($result2);
$friends = $row2["status"];
if (mysql_num_rows($result2) = 0)
{
$friends = "no";
}
}

//If we are friend, do we allow access to the profile
IF ($row["privacy"] >= 9 && $friends != 1)
{
exit("You may not view this profile because of the privacy settings.");
}

$row = mysql_fetch_array($result);
$memgroup = $row["group"];
IF ($row["activated"] != 1)
{
 exit("This account is suspended and cannot be viewed.");
}


//Check what group member is in.
$result2 = mysql_query("SELECT * FROM profiles_groups WHERE id=('$memgroup')  LIMIT 1");
$row2 = mysql_fetch_array($result);

?>

Alright, so the error: Fatal error: Can't use function return value in write context in C:\xampp\htdocs\prog\profile.php on line 45
Code: [Select]
42. $result2 = mysql_query("SELECT * FROM profiles_friends WHERE user=('$getid') AND target=('$loginid')  LIMIT 1");
43. $row2 = mysql_fetch_array($result2);
44. $friends = $row2["status"];
45. if (mysql_num_rows($result2) = 0)
Alright, this is one thing that bothers me, the other is:
Code: [Select]
//check ID
$result = mysql_query("SELECT * FROM profiles WHERE id=('$getid')  LIMIT 1");
$row = mysql_fetch_array($result);

IF (mysql_num_rows($result) != 1)
{
 exit("Invalid ID");
I tried to put an invalid ID, and already here the script should have died/exited before executing the parts of the code that doesn't work.
I tested my code on another page and it works flawlessly, perhaps this error is just generated before it actually exists i dunno..

Any way, any help is much appreciated
}

This topic has been moved to Website Critique.

http://www.phpfreaks.com/forums/index.php?topic=355553.0

I would like to be able to use this 

<img src="user/<?=$log_username. '/' . $main_image;?>" width="130" height="150" id="pic5"/>

to work within php and i am having a had time doing so  . Any ideas?  $log_username refers to the users specific username folder within the main users folder         html source code looks like this  ,but i need to reference this within  a PHP  code block not html

<img src="user/lexi/pic.png" width="130" height="150" id="pic5">

any ideas? thanks guys

I have a table that has a cell that I've made editable:

echo "<td contenteditable='true'>" . $row['Comments'] . "</td>";

Which is cool I guess, but it doesn't go anywhere from there.  I'd like to make it so that upon changing, it links back to an SQL UPDATE query that I define.  Is this possible through some sort of onChange function?

There are two pieces to this- The HTML Form and the resulting php. I can't seem to make the leap, from the code to having the form produce the php page so others can view it until the form is again submitted overwriting the php, thus generating new content.

The environment I am working in is limited to IIs 5.1 and php 5.2.17 without mySQL or other DB

I'm new to php, this isn't homework,or commercialization,  it's for children.  I am thinking perhaps fwrite / fread but can't get my head around it.

Code snipets below. Any help, please use portions of this code in hopes I can understand it

Thanks

Code snipet from Output.php
Code: [Select]
<?php
$t1image = $_POST["t1image"];
$t1title = $_POST["t1title"];
$t1info = $_POST["t1info"];
$t2image = $_POST["t2image"];
$t2title = $_POST["t2title"];
$t2info = $_POST["t2info"];
?>
...
<tbody>
    <tr><!--Headers-->
      <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Animal</td>
      <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Image thumb<br>
      </td>
      <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Date<br>
      </td>
      <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Information<br>
      </td>
    </tr>
    <tr>
      <td style="vertical-align: top; text-align: center;">Monkey
      </td>
      <td style="vertical-align: top; text-align: center;"><img src="<?php echo $t1image.'.gif'; ?>"><!--single image presented selected from radio buttons-->
      </td>
      <td style="vertical-align: top; text-align: center;"><?php echo date("m/d/Yh:i A"); ?><!--time stamp generated when submitted form populates all fields at once-->
      </td>
      <td style="vertical-align: top; text-align: center;"><a href="#monkey" rel="facebox"><?php echo $t1title ?></a><!--Link name provided by "Title 1", that links to hidden Div generated page with content from "Info1" field-->
  <div id="Monkey" style="display:none">
<?php echo $t1info; ?>
</div>
      </td>
    </tr>
    <tr>
      <td style="vertical-align: top; text-align: center;">Cat<br>
      </td>
      <td style="vertical-align: top; text-align: center;"><img src="<?php echo $t2image.'.gif'?>"></td>
      <td style="vertical-align: top; text-align: center;"><?php echo date("m/d/Yh:i A"); ?></td>
      <td style="vertical-align: top; text-align: center;"><a href="#Cat" rel="facebox"><?php echo $t2title ?></a>
  <div id="Cat" style="display:none">
<?php echo $t2info; ?>
</div>
      </td>
    </tr>
    <tr>

This replicates several times down the page around 15-20 times ( t1### - t20###)


Code Snipet from HTML Form
Code: [Select]
<form action="animals.php" method="post">
<div style="text-align: left;"><big
style="font-family: Garamond; font-weight: bold; color: rgb(51, 51, 255);"><big><big><span>Monkey</span></big></big></big><br>
<table style="text-align: left; width: 110px;" border="0"
cellpadding="2" cellspacing="0">
<tbody><tr>
<td style="vertical-align: top;">Image thumb<br>
<input type="radio" name="t1image" value="No opinion" checked><img src="eh.gif" alt="Eh">
<input type="radio" name="t1image" value="Ok"><img src="ok.gif" alt="ok">
<input type="radio" name="t1image" value="Like"><img src="like.gif" alt="Like">
<input type="radio" name="t1image" value="Dont"><img src="dont.gif" alt="Don't Like">
<input type="radio" name="t1image" value="Hate"><img src="hate.gif" alt="Hate">
<input type="radio" name="t1image" value="Other"><img src="other.gif" alt="Other">
<br>
Why Title:<input type="text" name="t1title" size="45" value="..."/></td>
<td style="vertical-align: top;">
Explain:<br>
<textarea name="t1info" cols=45 rows=3 value="..."></textarea>
</td></tr></table>
<br>
<!--Next-->

How do I get the Form data to save to the php page for others to view?

mysql_query("INSERT INTO people (company, lname) VALUES ('clean($_POST[Company])', 'clean($_POST['lname'])' ");

using a clean function in the query instead of doing it before hand?

Hi,    I study a php book and every thing is going fine, the problem is that I dont know how to practice what I study...   iv'e searched alot in the internet of exercise and found few but not every thing there is the same as what I study and sometimes they ask me to do things that I dont know yet..   some people saying that you need to think about a project and start building it but I dont have enough knowledge so start build something on my own..   right now I know about if/else, loops, operators, functions and objects, arrays, date and time, and file handling.   so most of the exercise I find involving mysql that I dont know yet.   can someone give me tips maybe how he started to study php?    it will help me alot and im sure it will help to more people.     thakns in advance,   guy.