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PHP - How Long Do I Have To Update My Code To Mysqli
I have several registration systems that were designed some time ago running mysql. How long do I have until I have to competely move to mysqli? I am working on recoding them, but it is taking some time. Does anyone know when it will become an issue?
Similar TutorialsDear Sir/Madame I am making a website where user can insert data and wait for the admin to approve/reject the form. Now i am stuck with the update status where an admin can submit with a click pending to approval or reject with comments. I am new to PHP programming. Can somebody help me with the issue. Part 1 is inserting the data and part two is fetching the data but i am unable to solve the status approve/reject and comment at the same time on the view.php? page. Kindly help. Thank you.
<?php
$host="localhost";
$username="root";
$pass="";
$db="ems1";
$conn=mysqli_connect($host,$username,$pass,$db);
if(!$conn){
die("Database connection error");
}
// insert query for register page
if(isset($_REQUEST['proposal']))
{
$details=$_POST['details'];
$location=$_POST['location'];
$date=$_POST['date'];
$time=$_POST['time'];
$status="Pending";
$comment=$_POST['comment'];
$query="INSERT INTO `proposal` (`details`,`location`,`date`,`time`,`status`,`comment`) VALUES ('$details','$location','$date','$time','$status','$comment')";
$res=mysqli_query($conn,$query);
if($res){
$_SESSION['success']="Not Inserted successfully!";
header('Location:');
}else{
echo "Leave not Applied, please try again!";
}
}
?>
<div class="col-xs-6 col-xs-push-3 well">
<form class="form-horizontal" method="post" action="" >
<input type="hidden" name="proposal" value="">
<fieldset>
<legend>New Proposals </legend>
<!----left box----------->
<!----right box----------->
<div class="col-xs-9">
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Details:</b></label>
<div class="col-lg-9">
<input type="text" name="details" class="form-control">
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Location:</b></label>
<div class="col-lg-9">
<input type="text" name="location" class="form-control" >
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Date:</b></label>
<div class="col-lg-9">
<input type="date" name="date" class="form-control">
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Time:</b></label>
<div class="col-lg-9">
<input type="time" name="time" class="form-control" >
</div>
</div>
<div class="col-lg-9">
<input type="hidden" name="status" class="form-control" >
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b></b></label>
<div class="col-lg-9">
<input type="hidden" name="comment" class="form-control">
</div>
</div>
</div>
<div class="form-group">
<div class="col-lg-12">
<button type="reset" class="btn btn-default">Cancel</button>
<button type="submit" class="btn btn-primary">Submit</button>
</div>
</div>
</fieldset>
</form>
</div>
</div>
<body>
<h2 style="text-align:center; color:orangered;">
DASHBOARD
</h2>
<table>
<h3>
<tr style="background-color:#E4EBC5; color:orangered;">
<th>ID</th>
<th>Details</th>
<th>Location</th>
<th>Status</th>
<th>Comment</th>
</tr>
</h3>
</table>
<?Php
////////////////////////////////////////////
require "dbconfig.php"; // MySQL connection string
$count="SELECT id,details,location,time,status,comment FROM proposal";
if($stmt = $connection->query($count)){
while ($nt = $stmt->fetch_assoc()) {
echo "
<body>
<table>
<tr>
<td><a href=view.php?id=$nt[id]>$nt[id]</a></td>
<td>$nt[details]</td>
<td>$nt[location]</td>
<td>$nt[status]</td>
<td>$nt[comment]</td>
</tr>
</table>
</body>
";
}
}else{
echo $connection->error;
}
?>
Hi, I am having trouble coding for mysqli update. Please, somebody tell me the correct way. I'm trying to update the "lastused" (current date) field in "emailtbl". Somebody please tell the best way to code this. Below is the message and following, the current code: Fatal error: Call to undefined function curdate() in C:\xampp\htdocs\home\lastused.php on line 14
$db = new mysqli('localhost', 'root', 'pass', 'mydb');
if($db->connect_errno > 0)
{die('Unable to connect to database [' . $db->connect_error . ']');}
$sql = <<<SQL
SELECT *
FROM `emailtbl`
WHERE `id` = '$id'
SQL;
if(!$result = $db->query($sql))
{die('There was an error running the query [' . $db->error . ']');}
$lastused = $_POST['lastused'];
$lastused = curdate();
echo "last date accessed is ".$data['lastused'];
$result->free();
$db->escape_string('This is an unescape "string"');
$db->close();
?>
$update
= mysqli_query($dbconnect, "UPDATE emailtbl SETlastused = curdate() WHERE id ='$id'"); if($update == false) { die("UPDATE FAILED: ".mysqli_error($dbconnect)); } echo "$lastused is the last date this account was accessed"; Hi All, Long question but I hope someone will be able to point me in the right direction. At the moment I am writing a cricket management game and and each hour each team is updated with the code Code: [Select] <?php #Players MUST be updated from this screen so they cna get team bonuses $teamUpdateTime=$team['teamUpdateTime']; #This is the time that the team is updated $teamMorale=$team['morale']; #Get the teams morale while($teamUpdateTime<$updateTime) { #Keep looping through this until we are up to date echo "<BR>".$team['name']; #Work out changes to team morale if($teamMorale>1000) $teamMorale -= mt_rand(0, 3); #If team morale is high then lower it if($teamMorale<1000) $teamMorale += mt_rand(0, 5); #If team morale is low then increase it $moraleBonus=0; #Reset the variable $confidenceBonus=0; #Reset the variable $injuryBonus=0; #Reset the variable $energyBonus=0; #Reset the variable $teamUpdateTime += 3600; #Add an hour to the time include("hourly_update_player.php"); #Do players now } #Save the team $sqlTeam = "UPDATE teams SET morale='$teamMorale', teamUpdateTime='$teamUpdateTime' WHERE teamID='{$team['teamID']}'"; if(!mysql_query($sqlTeam, $sqldb)) die('Error: ' . mysql_error()); //Update the record, if there is an error then show it ?> the line include("hourly_update_player.php"); #Do players now then activates the following code Code: [Select] <?php #Playeres will have to be updated with the team because we have to check for team medic $players = mysql_query("SELECT playerID, name, injuryTime, energy, morale, confidence, fitness FROM players WHERE teamPlayedFor='$team[teamID]'"); #Get all the players of the team while($player = mysql_fetch_array($players)) { #Go through all the players of the team echo "<BR>".$player['name']; # Do all the updating of player stats here. I won't put the full code here as it is not needed for the question on phpfreaks. $sqlPlayer = "UPDATE players SET energy='$energy', confidence='$confidence', morale='$morale', injuryTime='$injuryTime' WHERE playerID='{$player[playerID]}'"; #Update player if(!mysql_query($sqlPlayer,$sqldb)) die('Error: ' . mysql_error()); //Update the record, if there is an error then show it } ?> Each team has around 25 players to update. With ten teams (250 players all up) in the game (the game is still pre-alpha) to test it all this takes 8 seconds to go through all the teams and their players. Unfortunately in this 8 seconds nobody else can use the database as it locks it up. I tried to have the players update by itself (so it only has to go through the players database once) but cannot work out how to have team affects on the player - for example if the team has a specialist batting coach then the player gets an extra batting point each hour so it needs to go through the teams first. MY QUESTIONS A) How can I speed this up? When the game goes into the public domain I would like to see around 1-5 thousand teams, this could take up to 800-4,000 seconds - waaaay to long. B) When it is updating the database I can't play the game, it simply says loading until the updates are finished and then continues as normal; with thousands of teams I do expect a bit of delay but how can I keep parts of the database open that aren't being used? C) Each time I go through a team the players database is reloaded, can JOINS fix this? Or is there another way of doing this? Hi, i have a user update function in my code so I can easily change user fields int he database public function updateUser ($username, $value, $what) { $q = "UPDATE `users` SET ? = ? WHERE username = ?"; if ($stmt = $this->db_connection->prepare($q)) { $stmt->bind_param("sis", $what, $value, $username); $stmt->execute(); } } The database is connected successfully, but say i run a updateUser('blaine0002', 'blah', 'password'); nothing would get updated and no errors are thrown. Am i doing something wrong? Thank you! Hi folks, This has been wrecking my brain. I did do a google a few times to see if I can find a solution but nothing unfortunately. I want to be able to update the details on a page without having to reupload a new image each time. But if I don't open a new image for upload, I cannot update any of the other details. Below is the code and form etc for this particular thing... Please note this is just a project and will not be going live. I know there are vulnerabilities and I will work on those at a later stage. Thanks for any help with this current issue.
<?php
include_once('includes/header.php');
if(isset($_POST['new']) && $_POST['new']==1){
if (isset($_POST['submit'])) {
if(!empty($_FILES['image']['name'])) {
// Get image name
$image = $_FILES['image']['name'];
$image = mysqli_real_escape_string($con, $_FILES['image']['name']);
$slide_text = mysqli_real_escape_string($con, $_POST['slide_text']);
$youtube = mysqli_real_escape_string($con, $_POST['youtube']);
$vid_text = mysqli_real_escape_string($con, $_POST['vid_text']);
// image file directory
$target = "uploads/".basename($image);
if($_POST['image'] = ""){
$sql = "UPDATE slide SET slide_text='".$slide_text."', image='".$image."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
else{
$sql = "UPDATE slide SET slide_text='".$slide_text."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
$result = mysqli_query($con, $sql);
if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
$msg = "Image uploaded successfully";
}else{
$msg = "Failed to upload image";
}
if(!$result){
die('Error: ' . mysqli_error($con));
} else{
$message = ' - <i class="fa fa-check success"> Record Updated!</i>';
}
}
}
}
$sql = "SELECT * FROM slide";
$result = $con->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
?>
<!-- Header-->
<div class="breadcrumbs">
<div class="col-sm-4">
<div class="page-header float-left">
<div class="page-title">
<h1>Slide Show</h1>
</div>
</div>
</div> <div class="col-sm-8">
</div>
</div>
<div class="content mt-3">
<div class="animated fadeIn">
<div class="row">
<div class="col-lg-12">
<div class="card">
<div class="card-header"><strong>Image </strong><small>Slide</small></div>
<div class="card-body card-block">
<form role="form" method="post" action"" enctype="multipart/form-data">
<input type="hidden" name="new" value="1" />
<div class="modal-body">
<div class="row form-group">
<div class="col-6">
<div class="form-group"><label for="image" class=" form-control-label">Image</label>
<input type="file" id="image" name="image" value="<?php echo $row['image']; ?>" class="form-control">
</div>
</div>
<div class="col-6">
<div class="form-group"><label for="name" class=" form-control-label">Uploaded Image</label>
<img src="uploads/<?php echo $row['image']; ?>" width="150" height="150" class="img-fluid hover-shadow" />
</div>
</div>
</div>
<div class="row form-group">
<div class="col-6">
<div class="form-group"><label for="youtube" class=" form-control-label">Video</label>
<input type="text" id="youtube" name="youtube" value="<?php echo $row['youtube']; ?>" placeholder="Enter Video URL" class="form-control">
</div>
</div>
<div class="col-6">
<div class="form-group"><label for="vid_text" class=" form-control-label">Video Text</label>
<input type="text" id="vid_text" name="vid_text" value="<?php echo $row['vid_text']; ?>" placeholder="Video Text" class="form-control">
</div>
</div>
</div>
<div class="form-group"><label for="slide_text" class=" form-control-label">Text Overlay</label>
<textarea is="slide_text" name="slide_text" class="form-control"><?php echo $row['slide_text']; ?></textarea>
</div>
<div class="modal-footer">
<button type="submit" name="submit" id="submit" class="btn btn-primary">Confirm</button>
</div>
</form>
</div>
</div>
</div><!-- .animated -->
</div><!-- .content -->
<?php
}
}
?>
</div><!-- /#right-panel -->
<!-- Right Panel -->
<script src="assets/js/vendor/jquery-2.1.4.min.js"></script>
<script src="assets/js/popper.min.js"></script>
<script src="assets/js/plugins.js"></script>
<script src="assets/js/main.js"></script>
<script src="assets/js/lib/data-table/datatables.min.js"></script>
<script src="assets/js/lib/data-table/dataTables.bootstrap.min.js"></script>
<script src="assets/js/lib/data-table/dataTables.buttons.min.js"></script>
<script src="assets/js/lib/data-table/buttons.bootstrap.min.js"></script>
<script src="assets/js/lib/data-table/jszip.min.js"></script>
<script src="assets/js/lib/data-table/pdfmake.min.js"></script>
<script src="assets/js/lib/data-table/vfs_fonts.js"></script>
<script src="assets/js/lib/data-table/buttons.html5.min.js"></script>
<script src="assets/js/lib/data-table/buttons.print.min.js"></script>
<script src="assets/js/lib/data-table/buttons.colVis.min.js"></script>
<script src="assets/js/lib/data-table/datatables-init.js"></script>
<script src="https://cdn.tiny.cloud/1/sw6bkvhzd3ev4xl3u9yx3tzrux4nthssiwgsog74altv1o65/tinymce/5/tinymce.min.js" referrerpolicy="origin"></script>
<script>
tinymce.init({
selector: 'textarea',
plugins: 'advlist autolink lists link image charmap print preview hr anchor pagebreak',
toolbar_mode: 'floating',
});
</script>
<script type="text/javascript">
$(document).ready(function() {
$('#customer-table').DataTable();
} );
</script>
</body>
</html>
As you can see I am trying to use an If clause if the image field in the form is empty then I just want to update the other details. Else, if I fill the image field with a file, then update the lot.
if($_POST['image'] = ""){
$sql = "UPDATE slide SET slide_text='".$slide_text."', image='".$image."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
else{
$sql = "UPDATE slide SET slide_text='".$slide_text."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
This doesn't work. Any ideas, besides give up?
<?php
//COOKIE CHECKER
if (isset($_COOKIE["person"])){
if (filter_var($_COOKIE["person"], FILTER_VALIDATE_INT)){
$user_id = $_COOKIE["person"];
//DATABASE CONNECTION VARIABLES
$myserver ="localhost";
$myname = "username";
$mypassword = "password";
$mydb ="dbname";
/*SQL CONNECTION*/
// Create connection
$conn = new mysqli($myserver, $myname, $mypassword, $mydb);
// Check connection
if ($conn->connect_error) {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>
<H1>Decline of the Han - Three Kingdoms</H1>';
die("Connection failed: " . $conn->connect_error);
echo '</BODY>
</HTML>';
}
else {
//COUNT USER
$cquery = "SELECT COUNT(*) AS usercheck FROM Players WHERE ID = ?";
$cid = $conn->prepare($cquery);
$cid->bind_param('i', $user_id);
$cid->execute();
$cid->bind_result($usercheck);
$cid->fetch();
if ($usercheck ==1){
if (isset($_POST["profile"])){
if(!filter_var($_POST["profile"], FILTER_SANITIZE_STRING)){
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">Unable to filter bio <a href="biography.php">return</a></P>';
echo '</BODY>
</HTML>';
}
else {
$profile = $_POST["profile"];
$sql = "UPDATE Player_Data SET Bio =? WHERE ID=?";
$q = $conn->prepare($sql);
$q->bind_param("si", $profile, $user_id);
$q->execute();
echo '<P>Biography altered <a href="biography.php">return</a></P>';
//close connection
$conn->close();
}
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">'.$usercheck.' '.$user_id.'</P>';
echo '<P class="error">No such user found!</P>';
//close connection
$conn->close();
//foot
echo '</BODY>
</HTML>';
}
//end connection check
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">ERROR invalid cookie!</P>';
echo '</BODY>
</HTML>';
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">No cookie detected!<br><a href="login.php">login</a></P>';
echo '</BODY>
</HTML>';
}
?>
I have an error in the update, but I am not seeing where I made it. Its annoying because the update won't execute and anything beyond the update isn't visible in the html source code in the browser, so it is likely to be a syntax error, but where?
<?php
//COOKIE CHECKER
if (isset($_COOKIE["person"])){
if (filter_var($_COOKIE["person"], FILTER_VALIDATE_INT)){
$user_id = $_COOKIE["person"];
//DATABASE CONNECTION VARIABLES
$myserver ="localhost";
$myname = "username";
$mypassword = "password";
$mydb ="dbname";
/*SQL CONNECTION*/
// Create connection
$conn = new mysqli($myserver, $myname, $mypassword, $mydb);
// Check connection
if ($conn->connect_error) {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>
<H1>Decline of the Han - Three Kingdoms</H1>';
die("Connection failed: " . $conn->connect_error);
echo '</BODY>
</HTML>';
}
else {
//COUNT USER
$cquery = "SELECT COUNT(*) AS usercheck FROM Players WHERE ID = ?";
$cid = $conn->prepare($cquery);
$cid->bind_param('i', $user_id);
$cid->execute();
$cid->bind_result($usercheck);
$cid->fetch();
if ($usercheck ==1){
if (isset($_POST["profile"])){
if(!filter_var($_POST["profile"], FILTER_SANITIZE_STRING)){
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">Unable to filter bio <a href="biography.php">return</a></P>';
echo '</BODY>
</HTML>';
}
else {
$profile = $_POST["profile"];
$sql = "UPDATE Player_Data SET Bio =? WHERE ID=?";
$q = $conn->prepare($sql);
$q->bind_param("si", $profile, $user_id);
$q->execute();
echo '<P>Biography altered <a href="biography.php">return</a></P>';
//close connection
$conn->close();
}
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">'.$usercheck.' '.$user_id.'</P>';
echo '<P class="error">No such user found!</P>';
//close connection
$conn->close();
//foot
echo '</BODY>
</HTML>';
}
//end connection check
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">ERROR invalid cookie!</P>';
echo '</BODY>
</HTML>';
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">No cookie detected!<br><a href="login.php">login</a></P>';
echo '</BODY>
</HTML>';
}
?>
I have an error in the update, but I am not seeing where I made it. Its annoying because the update won't execute and anything beyond the update isn't visible in the html source code in the browser, so it is likely to be a syntax error, but where?
I have a very weird problem on my PHP5.3/Apache/MySQL based system on WinXp Pro. I have written php script which basically scans every directory in my local hard disc, checks which files are images, sets a counter of the number of images found per folder and saves this count in a MySQL table. To put you in the picture, we are talking about 1000 folders with about 8-10pics each on average 9000 files. On the previous PHP 5.1 / IIS system, (same PC) this used to work moderately well (took a nice 6 mins) and I had to include the command set_time_limit of about 3seconds in the looping to avoid execution timeout failures. (also worked by setting a high value of 10mins before the loopping) ANyway, now I run the exact same script on the new Php5.3 and have the problem that the code starts operating quite fast and gradually it slows and slows until eventually it is dead slow and have to quit internet explorer. For exampe, the first 3000 files are scanned in just 60seconds, then the next 1000 in the next 4 mins, and eventually drops to about 100files or less files per minute. I also noticed that the CPU consumption of iexplorer.exe is 90-99%, and the window of Internet explorer is very slugish with a temp '(not responding)' messages on the top window bar. WHat can I do and test? Is it the code itself, the PHP5.3 or something in php.ini or apache conf. file? Buffers? memory? WHat? gonna crazy! basically, the code scans a dir (location of dir taken from Mysql) puts file contents in an array, analyse the array for .jpg/.gif (and other parameters specific to pics, counts the valid pic files in a variable, puts this in a MySql databse, loops for next folder. The code is a kind of tool to have a count of my pics in my folders and never used remote server/online but only local. Thanks for your time On the mainpage I am getting this error:
Fatal error: Call to a member function query() on a non-object in C:\xampp\htdocs\page\controller\function.php on line 393
$result = $db->query($query);And on the admin section: Notice: Undefined index: role in C:\xampp\htdocs\page\admin\header.php on line 7 Notice: Undefined index: role in C:\xampp\htdocs\page\admin\header.php on line 7 Fatal error: Undefined class constant 'site_url' in C:\xampp\htdocs\page\admin\header.php on line 8
if ($_SESSION['role'] !== 'admin' and $_SESSION['role'] !== 'moderator'){header( 'Location:'.config::site_url.'index.php' );
how to update the record of one table in which condition is that the it should similar to the other table feild only. e.g field of table1 will update only when the feild1 of table1 is equal to field2 of table2 in php?? while im using following command mysql_select_db("db1",$con); $query = "SELECT table2.feild1 , table2.feild1 " . "FROM table2, table1 " . "WHERE table1.feild2 = table2.feild1 "; $data = mysql_query($query) or die(mysql_error()); $sql="UPDATE table2 SET feild2='$_POST[value2]', feild3='$_POST[value3]' WHERE table1.feild2 = $data "; Hi
I just finished this tutorial('http://www.startutor...torial-part-3/)
and everything was working fine until I decided to add last names to the application.
I got everything working on all the other pages except the Update page.
This is my php code.
As you can see, this array is setting each colorvalue to each idvalue. Code: [Select] <?php include("config.php"); include("db.php"); $arrid=$_POST['id']; $arrcolor=$_POST['color']; foreach ($arrid as $idvalue) { foreach ($arrcolor as $colorvalue) { $sql = "UPDATE colors SET color='$colorvalue' WHERE id = '$idvalue'"; mysql_query($sql) or die("Error: ".mysql_error()); echo $sql; } } header("Location: " . $config_basedir . "adminhome.php"); ?> This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=317142.0 hello i had a look here its prety simple example
http://www.formget.com/php-checkbox/
i wish something like this but with many more check boxes about 100,
the senario ls like this
there will be many users in a system,
each user profile will have these kind of questions
for example
Hobby :
tenis []
badminton[]
footbal[]
carrom[]
programming language :
perl[]
python[]
cobol[]
as3[]
favorit biscuit :
bakers[]
subana[]
ect[]
ect ect
these checkbox need to reflect for diferent users.
administrator can add new category [ ie hobby , programming language]
under each category he can add more options such as football, tenis ect
he should be able to have an interface to modify the options entered by user when a user request a change
what is a good way to implement this in php mysql
I'd like to write - or acquire - code that displays a simple table (name, phone number, email address, plus a comments field) on a web page in a password-protected page and allows a user to add his own information, update it or delete it. I figure hundreds of people and companies have written something like this so I'd like to find either an example I can imitate or even an existing package that I can simply customize to the specifics for my own table. Can anyone help me with that? Or am I going to have to reinvent the wheel for the gazillionth time and write it myself? Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete":
if(isset($_POST['highlight-purchased']))
{
// ****** Setup customized query to obtain only items that are checked ******
$sql = "SELECT * FROM shoplist WHERE";
for($i=0; $i < count($_POST['checkboxes']); $i++)
{
$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
}
$sql= rtrim($sql, "or");
$statement = $conn->prepare($sql);
$statement->execute();
// *** fetch results for all checked items (1st query) *** //
$result = $statement->fetchAll();
$statement->closeCursor();
// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";
$statementSetToN = $conn->prepare($sqlSetToN);
$statementSetToY = $conn->prepare($sqlSetToY);
/*** loop through the results/collection of checked items ***/
foreach($result as $row)
{
if ($row["purchased"] != "Y")
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToY = $statementSetToY->fetch();
foreach($resultSetToY as $row)
{
$statementSetToY->execute();
}
}
else
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToN = $statementSetToN->fetch();
foreach($resultSetToN as $row)
{
$statementSetToN->execute();
}
}
}
break;
}
CRUD Queston.png 20.68KB
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Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. Hi All, I am trying to call a javascript pop-up window via a link by echoing out the html via php but keep getting parse errors: Parse error: syntax error, unexpected ')', expecting ',' or ';' Here is the code in question: Code: [Select] echo "<td class=\"today\"> <a href=\"javascript:statusWindow('status.php?month=".$month."&day=".$day."&year=$year');\">"$day_num</a> </td>\n"; And here is the javascript function: Code: [Select] <script type="text/javascript"> function statusWindow(url){ status_popupWin = window.open(url, 'status', 'resizable=yes, scrollbars=yes, toolbar=no,width=400,height=400'); status_popupWin.opener = self; } </script> Any help is appreciated. Thanks, kaiman |
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