PHP - How To Make A Table Print Out Only The Same Columns Within A Database

I'm working on a site where I've implemented a simple back end wysiwyg editor for content on a page. Then on the public page I run a php query to pull that content and display it. But doing this cancels out the css I have been using to split content into two columns. Is there a way to do this in php, or is there a way to circumvent the problem?  ( also tried echoing the entire css style along with the query result - that didn't work either)

The <p id='container_sub'> is what is split into two columns. I tried it outside of the query, and inside the query around where I echo results. Neither worked.
Here's the basic php code, and further down the css that makes two columns:
Code: [Select]
<?php

$pageid = '2';
  
// Formulate Query
// This is the best way to perform an SQL query
// For more examples, see mysql_real_escape_string()
$query = sprintf("SELECT content FROM tbl_pages WHERE page_id='%s'",
     mysql_real_escape_string($pageid));

// Perform Query
$result = mysql_query($query);

// Check result
// This shows the actual query sent to MySQL, and the error. Useful for debugging.
if (!$result) {
    $message  = 'Invalid query: ' . mysql_error() . "\n";
    $message .= 'Whole query: ' . $query;
    die($message);
}

// Use result
// Attempting to print $result won't allow access to information in the resource
// One of the mysql result functions must be used
// See also mysql_result(), mysql_fetch_array(), mysql_fetch_row(), etc.
while ($row = mysql_fetch_assoc($result)) {
    echo "<p id='container_sub'>".$row['content']."</p>";

}

// Free the resources associated with the result set
// This is done automatically at the end of the script
mysql_free_result($result);
      
?>

The css....
Code: [Select]
#container_sub {-moz-column-count: 2;
-moz-column-gap: 25px;
-webkit-column-count: 2;
-webkit-column-gap: 20px;
column-count: 2;
column-gap: 20px;}

#container_sub2 {-moz-column-count: 2;
-moz-column-gap: 25px;
-webkit-column-count: 2;
-webkit-column-gap: 20px;
column-count: 2;
column-gap: 20px;}

Code: [Select]
$notes = 'ABOUT ME SECTIOn HERE';
$signature = 'SIGNATURE STUFF HERE';
$friends = 'friends INFO HERE';
$middle=array ( "0"  => array ( "section" => $notes,
                                "hide" => $display['1'],
                                 "left" => "0",
                                 "right" => "0",
                                 "middle" => "0"
                                     ),
                  "1" => array ("section" => $signature,
                                "hide" => $display['2'],
                                  "left" => "0",
                                 "right" => "0",
                                 "middle" => "0"
                                     ),




                  "2"   => array ("section" => $friends,
                                  "hide" => $display['4'],
                                   "left" => "0",
                                 "right" => "0",
                                 "middle" => "0"
                                     ),
                );

$order = array(0,1,2);
foreach ($order as $index)
{
if ($middle[$index]['hide'] != 1)
echo '<br>'.$middle[$index]['section'];
}


Okay, so  this code right here works fine, but how would I make the left/right/middle stuff correspond to right side of my table columns, middle or left? Do I need to add another demi array to make 3 in 1? or am I doing it okay with just the multi with the "left" "middle"  "right" ?

if 0 means false, will change them to 1 if true.

the second database found on the cloud

 

i try to get JSON data but how to insert and update  them to another online database with the same table

my php script to return json data 

<?php        

 include_once('db.php');

        $users = array();

        $users_data = $db -> prepare('SELECT id, username FROM  users');

        $users_data -> execute();

        while($fetched = $users_data->fetch()) {

            $users[$fetchedt['id']] = array (

                'id' => $fetched['id'],

                'username' => $fetched['name']

            );

        }

        echo json_encode($leaders);

 

 

 

 

i get

 

{"1":{"id":1,"username":"jeremia"},"2":{"id":2,"username":"Ernest"}}

 

Edited March 24 by mahenda

so this is my code


Code: [Select]

<?
$b=$_GET['b'];
$m=$_GET['m'];
$y=$_GET['y'];

if  ($b <> '' && $m <> '' && $y <> '') {

$branch=$b;
$leavemonth=$m;
$leaveyear=$y;
}
else
{
$branch=$_POST['branch'];
$leavemonth=$_POST['leavemonth'];
$leaveyear=$_POST['leaveyear'];
}



$connection=mysql_connect("$server", "$username", "$password")
or die("Could not establish connection");
mysql_select_db($database_name, $connection)
or die ("Could not select database");


   
    $query="SELECT * from tblworkgroup";
    $result=mysql_query($query);?>


        &nbsp;&nbsp;Branch&nbsp;
        <select name="branch" >
<option value="all">ALL Branches</option>       
        <? while($row=mysql_fetch_array($result)) { ?>       
    <option value= "<?=$row['WorkGroupID']?>" <? if ($branch==$row['WorkGroupID']){ echo 'selected'; } ?> ><?=$row['WorkGroupName']?></option>
     <? } ?>
        </select>
           </td>
          </tr>
       <br><br><br>
  &nbsp;&nbsp;Month &nbsp;&nbsp;
<select name="leavemonth" >
<option value = "1" <? if ($leavemonth==1){ echo 'selected'; } ?>>January</option>
<option value = "2" <? if ($leavemonth==2){ echo 'selected'; } ?>>February</option>
<option value = "3" <? if ($leavemonth==3){ echo 'selected'; } ?>>March</option>
<option value = "4" <? if ($leavemonth==4){ echo 'selected'; } ?>>April</option>
<option value = "5" <? if ($leavemonth==5){ echo 'selected'; } ?>>May</option>
<option value = "6" <? if ($leavemonth==6){ echo 'selected'; } ?>>June</option>
<option value = "7" <? if ($leavemonth==7){ echo 'selected'; } ?>>July</option>
<option value = "8" <? if ($leavemonth==8){ echo 'selected'; } ?>>August</option>
<option value = "9" <? if ($leavemonth==9){ echo 'selected'; } ?>>September</option>
<option value = "10" <? if ($leavemonth==10){ echo 'selected'; } ?>>October</option>
<option value = "11" <? if ($leavemonth==11){ echo 'selected'; } ?>>November</option>
<option value = "12" <? if ($leavemonth==12){ echo 'selected'; } ?>>December</option>
</select>

&nbsp;&nbsp;
Year &nbsp;&nbsp;
<select name="leaveyear" >
<option value = "2010" <? if ($leaveyear==2010) { echo 'selected';} ?>>2010</option>
<option value = "2011" <? if ($leaveyear==2011) { echo 'selected';} ?>>2011</option>
<option value = "2012" <? if ($leaveyear==2012) { echo 'selected';} ?>>2012</option>
<option value = "2013" <? if ($leaveyear==2013) { echo 'selected';} ?>>2013</option>
<option value = "2014" <? if ($leaveyear==2014) { echo 'selected';} ?>>2014</option>
<option value = "2015" <? if ($leaveyear==2015) { echo 'selected';} ?>>2015</option>
<option value = "2016" <? if ($leaveyear==2016) { echo 'selected';} ?>>2016</option>
<option value = "2017" <? if ($leaveyear==2017) { echo 'selected';} ?>>2017</option>

</select>


  &nbsp;&nbsp;

<input type='submit' name='submit' value='Preview' Class="button" onclick='return validate()'>
   
   </div>

</form>


<br /><br />

<div id="box" valign="top">
                <h3>&nbsp;<strong>Leave Application Details</strong>&nbsp;&nbsp</h3>
<br><br>
<FORM name="printbutton" method="post" align="left" action="report_print.php" target="_blank">
<input type="hidden" name="leavemonth" value="<?php echo $leavemonth; ?>">
<input type="hidden" name="leaveyear" value="<?php echo $leaveyear; ?>">
<input type="hidden" name="branch" value="<?php echo $branch;?>">
<Input type = "Submit" Name = "Submit1" Class="button" VALUE = "Print Leave Details">
</form>
                <table width="80%" align="center" >
<thead>
<tr>
<th width="700px" align="left">Name</a></th>
                           
<th width="500px" align="center"></a>Application Date</th>

<th width="500px" align="center"></a> </th>
                           
<th width="500x" align="right"></a>Reason</th>
</tr>
</thead>
<tbody>
<?
/*echo "branch:".$branch.'<br />';
echo "leavemonth:".$leavemonth.'<br />';
echo "leaveyear:".$leaveyear.'<br />';*/
//--------------------------------------------------
if ($leavemonth =='' ||  $leaveyear =='' || $branch == '') {
// one value missing, so don't display
}
else
{
// start display data
$branchtracker = '';

if ($branch=='all'){
$branch = '%';
}

$rs = mysql_query( " call vwleavereport('$leavemonth', '$leaveyear', $branch, 0);");
$query="SELECT *,
MONTH(tblleaveapplication.DateFrom) as DFMonth,
MONTH(tblleaveapplication.DateTo) as DTMonth,
YEAR(tblleaveapplication.DateFrom) as DFYear
FROM `tblleaveapplication`
LEFT JOIN `tblemployee`
ON tblleaveapplication.employeeid = tblemployee.id
WHERE WorkGroupID LIKE '".$branch."'
AND (
(MONTH(tblleaveapplication.DateFrom)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.")
OR
(MONTH(tblleaveapplication.DateTo)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.")
)
ORDER BY WorkGroupID
";

$result = mysql_query($query);
while($row=mysql_fetch_array($result))
{
if ($branchtracker<>$row['WorkGroupID']){
echo '<tr><td colspan=4 style="background-color: #e8e8e8; font-weight: bold;">'.$row['WorkGroupID'].'</td></tr>';
$branchtracker = $row['WorkGroupID'];
}
echo '<tr>';
echo '<td>'.$row['EmployeeName'].'</td>';
echo '<td>'.$row['DateFrom'].'</td>';
echo '<td>'.$row['DateTo'].'</td>';
echo '<td>'.$row['Purpose'].'</td>';
echo '</tr>';
}

}
?>


the problem is i want the print button only appear when there is output..

Let's assume this is my table

Name           Amount            Gender

Stone Cold.  1245.                 Male

Kingsley.       500                    Male.

Stone Cold   2367                  Male

Stone Cold.  5678.                  Male

Now I want to print stone cold rows. Which is row 1,3 and 4 just exactly the same format with he above table. How do I get to do that.

My code is   

<?php
                       $id = $_SESSION['login'];
                        $sqlB = "SELECT * FROM activities WHERE username=? ORDER BY No  DESC LIMIT 10";
$stmtB = $connection->prepare($sqlB); 
$stmtB->bind_param('s', $id);
$stmtB->execute();
$resultB = $stmtB->get_result();

while($rowB = $resultB->fetch_all(MYSQLI_ASSOC)){
 foreach ($rowB as $out) {
 
    echo implode(' ', $out) . "<br>";
    exit;
}
    }
     //print_r($rowB);

// exit; 
 ?>

 

 

I don't understand how to put each row for stone cold into HTML row. Please don't be annoyed by my question, I know its a simple stuff but I've tried several stuffs, I can't get what I need still. If I print $rowB I get all want from the database in arrays. Thanks!!!