Learn VBA & Macros in 1 Week!

PHP - My Update And Add Isn't Working/..

Full Excel VBA Course - Beginner to Expert

My Update And Add Isn't Working/..	View Content

Hey guys been asking a bunch of my friends that know some php to try and help me with this issue im having with no success .. so i come here hoping to get answers i need. The delete function works but add and update dont work.

<?php session_start(); require 'approve.php'; ?>
<!DOCTYPE html>
<html>
<head>
  <meta http-equiv="content-type" content="text/html; charset=UTF-8">
  <title>Contacts</title>
  
  <!-- Include jQuery -->
  <script type='text/javascript' src='https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js'></script>
  
  <style type='text/css'>

    body {
   background-color: #333;  
   color: #999;
   font: 12px/1.4em Arial,sans-serif;
}
#wrap {
   margin: 10px auto;        
   background: #666;
   padding: 10px;
   width: 1024px;
}
#header {
   background-color: #666;
   color: #FFF;
}
#logo {
   font-size: 30px;  
   line-height: 40px;    
   padding: 5px;
}
#navWrap {
   height: 30px;
}
#nav {
   padding: 5px;
   background: #999;    
}
#nav ul {
   margin: 0;
   padding: 0;    
}
#nav li {
   float: left;
   padding: 3px 8px;
   background-color: #FFF;
   margin: 0 10px 0 0;
   color: #F00;
   list-style-type: none;
}
#nav li a {
   color: #F00;  
   text-decoration: none;    
}
#nav li a:hover {
   text-decoration: underline;   
}
br.clearLeft {
   clear: left;        
}â€‹

  </style>
  


<script type='text/javascript'>
//<![CDATA[ 

  $(function() {
    // Stick the #nav to the top of the window
    var nav = $('#nav');
    var navHomeY = nav.offset().top;
    var isFixed = false;
    var $w = $(window);
    $w.scroll(function() {
        var scrollTop = $w.scrollTop();
        var shouldBeFixed = scrollTop > navHomeY;
        if (shouldBeFixed && !isFixed) {
            nav.css({
                position: 'fixed',
                top: 0,
                left: nav.offset().left,
                width: nav.width()
            });
            isFixed = true;
        }
        else if (!shouldBeFixed && isFixed)
        {
            nav.css({
                position: 'static'
            });
            isFixed = false;
        }
    });
});

//]]>  
</script>


</head>
<body>

<div id="wrap">
    
    <!-- The header code, including the menu -->
    <div id="header">
        <div id="logo">Contacts<br /></div>
        <div id="navWrap">
            <div id="nav">
                <ul>
                    <li><a href="#" class="smoothScroll"><a href="export.php">Export Contacts</a></a></li>
                </ul>    
                <br class="clearLeft" />
            </div>
        </div>
    </div>
    
<?php

$separate = '';

ini_set('display_errors', 'On');
ini_set("xdebug.var_display_max_depth", -1);
ini_set("xdebug.var_display_max_children", -1);
ini_set("xdebug.var_display_max_data", -1);
$con = mysql_connect("66.150.xxx.xxx","contact","xxx");
if (!$con){
die("Can not connect: " . mysql_error());
}
mysql_select_db("zadmin_contact",$con);
 
if (isset($_POST['update'])){
$UpdateQuery = "UPDATE contact SET ID='$_POST[id]',Title='$_POST[title], First Name='$_POST[firstname]', Last Name='$_POST[lastname]', Company='$_POST[company]', Job Title='$_POST[jobtitle]', Business Phone='$_POST[businessphone]',Home Fax='$_POST[homefax]', Home Phone='$_POST[homephone]', Mobile Phone='$_POST[mobilephone]', E-mail Address='$_POST[email]' WHERE Name='$_POST[hidden]'";
mysql_query($UpdateQuery, $con);
};
 
if (isset($_POST['delete'])){
$DeleteQuery = "DELETE FROM contact WHERE ID='$_POST[hidden]'";
mysql_query($DeleteQuery, $con);
};
 
 
if (isset($_POST['add'])){
$AddQuery = "INSERT INTO contact (ID, Title, First Name, Last Name, Company, Job Title, Business Phone, Home Fax, Home Phone, Mobile Phone, E-mail Address) VALUES ('$_POST[uid]','$_POST[utitle]', '$_POST[ufirstname]', '$_POST[ulastname]', '$_POST[ucompany]', '$_POST[ujobtitle]', '$_POST[ubusinessphone]', '$_POST[uhomefax]', '$_POST[uhomephone]', '$_POST[umobilephone]', '$_POST[uemail]')";
mysql_query($AddQuery, $con);
};
 
 
 
$sql = "SELECT * FROM contact";
$myData = mysql_query($sql,$con);
echo "<table border=1 bgcolor=#FFFFFF align=center>
<tr>
<th>ID</th>
<th>Title</th>
<th>First Name</th>
<th>Last Name</th>
<th>Company</th>
<th>Job Title</th>
<th>Business Phone</th>
<th>Home Fax</th>
<th>Home Phone</th>
<th>Mobile Phone</th>
<th>E-mail Address</th>
</tr>";
while ($record = mysql_fetch_array($myData))
{
echo "<form action=\"dashboard.php\" method=\"post\">";
echo "<tr>";
echo "<td>" . "<input type=\"text\" name=\"id\" value=\"" . $record['ID'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"title\" value=\"" . $record['Title'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"firstname\"  value=\"" . $record['First Name'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"lastname\"  value=\"" . $record['Last Name'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"company\"  value=\"" . $record['Company'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"jobtitle\"  value=\"" . $record['Job Title'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"businessphone\"  value=\"" . $record['Business Phone'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"homefax\"  value=\"" . $record['Home Fax'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"homephone\"  value=\"" . $record['Home Phone'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"mobilephone\"  value=\"" . $record['Mobile Phone'] . "\"> </td>";
echo "<td>" . "<input type=\"text\" name=\"email\"  value=\"" . $record['E-mail Address'] . "\"> </td>";
echo "<input type=\"hidden\" name=\"hidden\" value=\"" . $record ['ID'] . "\">";
echo "<td>" . "<input type=\"submit\" name=\"update\" value=\"update\"> </td>";
echo "<td>" . "<input type=\"submit\" name=\"delete\" value=\"delete\"> </td>";
echo "</tr>";
echo "</form>";
}
echo "<form action=\"dashboard.php\" method=\"post\">";
echo "<tr>";
echo "<td><input type=\"text\" placeholder=\"ID\" name=\"uid\"></td>";
echo "<td><input type=\"text\" placeholder=\"Title\" name=\"utitle\"></td>";
echo "<td><input type=\"text\" placeholder=\"Fist Name\" name=\"ufirstname\"></td>";
echo "<td><input type=\"text\" placeholder=\"Last Name\" name=\"ulastname\"></td>";
echo "<td><input type=\"text\" placeholder=\"Company\" name=\"ucompany\"></td>";
echo "<td><input type=\"text\" placeholder=\"Job Title\" name=\"ujobtitle\"></td>";
echo "<td><input type=\"text\" placeholder=\"Business Phone\" name=\"ubusinessphone\"></td>";
echo "<td><input type=\"text\" placeholder=\"Home Fax\" name=\"uhomefax\"></td>";
echo "<td><input type=\"text\" placeholder=\"Home Phone\" name=\"uhomephone\"></td>";
echo "<td><input type=\"text\" placeholder=\"Mobile Phone\" name=\"umobilephone\"></td>";
echo "<td><input type=\"text\" placeholder=\"E-mail Address\" name=\"uemail\"></td>";
echo "<td>" . "<input type=\"submit\" name=\"add\" value=\"add\"></td>";
echo "</form>";
echo "</table>";
 
 
 
mysql_close($con);

?>
<p>Copyright &copy; <?php echo date("Y"); ?> Kuro. All rights reserved.</p>

Edited by syntax556, 15 July 2014 - 08:04 AM.

Full Excel VBA Course - Beginner to Expert

Mysql Update Not Working For 1 Value, But Working With Other Values

Similar Tutorials

View Content

When I echo the POST, it echoes the correct value.
The MySQL portion seems to just ignore it all together.
I've tried changing the dropdown option to just a text field, same thing occurred.
I have text fields right above this particular one that update just fine with the SAME exactly scripting.
if POST, update query, done. Works.

This one for some reason will not.

MySQL portion:
if ($_POST['bUpdate']){
mysql_query("UPDATE `Patients` SET `b` = '$_POST[bUpdate]' WHERE `id` = '".$_GET['id']."'");
}
echo $_POST['bUpdate'];

Form Portion:
Code: [Select]
<tr onmouseover="color(this, '#baecff');" onmouseout="uncolor(this);">
<td width="310" colspan="2" align="center"><span class="fontoptions">Postcard Status </span><br />
<?
if ($data['b'] == 1){
echo '<select name="bUpdate"><option value="1" selected>Yes</option><option value="0">No</option></select>';
} else {
echo '<select name="bUpdate"><option value="1">Yes</option><option value="0" selected>No</option></select>';
}

?>
</td>
</tr>

Update Not Working

Similar Tutorials

View Content

Anyone have any idea why this is not wokring?

if ($_POST[partsyes] == 'yes'){
$sql10="insert into tbl_partsordered (col_ticketid, col_price, col_orderedfrom, col_part, col_date) values ($_SESSION[ticketid], '$_POST[pprice]', '$_POST[pfrom]', '$_POST[part]', CURDATE( ))";
$result10=mysql_query($sql10) or die ('Error: '.mysql_error ());
//get tech comments so we can add our parts ordered to them.
$sql11="SELECT col_techcomments FROM tbl_ticket where id = $_SESSION[ticketid]";
$result11=mysql_query($sql11) or die ('Error: '.mysql_error ());
while($row11 = mysql_fetch_array($result11)) {
$newtechcomments = $row11[col_techcomments] . " " . "Ordered Parts" . " " .$_POST[part] . " " .$_POST[pprice] . " " . "From:" .$_POST[pfrom] . " ". $today;
$sql12="update tbl_ticket set col_techcomments='$newtechcomments' where id = $_POST[ticketid]";
$result12=mysql_query($sql12) or die ('Error: '.mysql_error ());
}

}

The first query pull data out of the database. then concatenates that string with other strings.

The update query never runs? If I add echo $sql2; and copy the sql that is displayed on the screen and paste it into phpadmin it updates just fine.

I tried putting a typo in on the query just to see if it failed. It does. so I know its running the query

This is driving me nuts. I know it's gotta be a typo somewhere.

Also don't make fun of my code.. I know It's gotta be bad.

Update Php/sql Not Working.

Similar Tutorials

View Content

Hello all, I have tried the following syntax to update a record from the $_POST method, and I cannot get it to update the record. Can anyone spot where I'm going wrong in my code

Code: [Select]
<?php
$idstudent = $_POST["idstudent"];
$childname = $_POST["childname"];
$parentname = $_POST["parentname"];
$dated = $_POST["dated"];
$datem = $_POST["datem"];
$datey = $_POST["datey"];
$dob = $datey ."-". $datem ."-".$dated;
$age = $_POST["age"];
$lastupdate = date("Y\-m\-d");
$gender = $_POST["gender"];
$address1 = $_POST["address1"];
$address2= $_POST["address2"];
$city = $_POST["city"];
$postcode = $_POST["postcode"];
$phone = $_POST["phone"];
$mobile = $_POST["mobile"];
$email = $_POST["email"];
$pass= $_POST["password"];
$height = $_POST["height"];
$neck = $_POST["neck"];
$chest = $_POST["chest"];
$hips = $_POST["hips"];
$waist = $_POST["waist"];
$insideleg = $_POST["insideleg"];
$dress = $_POST["dress"];
$shoe = $_POST["shoes"];
$haircolour = $_POST["haircolour"];
$hairlength = $_POST["hairstyle"];
$eyes = $_POST["eyecolour"];
$ethnicity = $_POST["ethnicity"];
$image = $_POST["image"];
$approve = "0";
$actor = $_POST["actor"];
$standin = $_POST["standin"];
$voiceover = $_POST["voiceover"];
$stagecombat = $_POST["stagecombat"];
$daballet = $_POST["daballet"];
$dasalsa = $_POST["dasalsa"];
$dabreak = $_POST["dabreak"];
$dadisco = $_POST["dadisco"];
$dahiphop = $_POST["dahiphop"];
$dajazz = $_POST["dajazz"];
$damodern = $_POST["damodern"];
$dastreet = $_POST["dastreet"];
$datap = $_POST["datap"];
$dacontemp = $_POST["dacontemp"];
$dafreestyle = $_POST["dafreestyle"];
$daswing = $_POST["daswing"];
$dawaltz = $_POST["dawaltz"];

include ('../../source/db_config.php');
$db = mysql_connect($host,$username,$password) or die(mysql_error());
mysql_select_db($database, $db) or die(mysql_error());
$update = "UPDATE 'students' SET 'childname'='$childname', 'parentname'='$parentname', 'dob'='$dob', 'age'='$age',
'lastupdate'='$lastupdate', 'gender'='$gender', 'address1'='$address1', 'address2'='$address2', 'city'='$city',
'postcode'='$postcode', 'phone'='$phone', 'mobile'='$mobile', 'email'='$email', 'password'='$pass',
'height'='$height', 'neck'='$neck', 'chest'='$chest', 'hips'='$hips', 'waist'='$waist', 'insideleg'='$insideleg',
'dress'='$dress', 'shoe'='$shoe', 'haircolour'='$haircolour', 'hairlength'='$hairlength', 'eyes'='$eyes',
'ethnicity'='$ethnicity', 'actor'='$actor', 'standin'='$standin', 'stagecombat'='$stagecombat', 'daballet'='$daballet',
'dasalsa'='$dasalsa', 'dabreak'='$dabreak', 'dadisco'='$dadisco', 'dahiphop'='$dahiphop', 'dajazz'='$dajazz',
'damodern'='$damodern', 'dastreet'='$dastreet', 'datap'='$datap', 'dacontemp'='$dacontemp',
'dafreestyle'='$dafreestyle', 'daswing'='$daswing', 'dawaltz'='$dawaltz' WHERE 'id'='$idstudent'";
mysql_query($update);
?>
Don't worry about the password either.. it is passed through md5 encryption.

But any help will be greatly appreciated

Update A Profile Not Working

Similar Tutorials

View Content

ok, so I have found this code to edit profiles online, only problem is that the data is not being posted to the database, there are no errors, just basically refreshes the page. could you take a look and see if you can help me?
Code: [Select]
<?php
}
//action: edit user -----------------------------------------------------------------------------
if (isset($_GET['edit']) && isset($_GET['id'])) {
$userid = (int) $_GET['id'];
if ($userid == 0) {
die("Invalid ID provided.");
}
//execution when completed the edit user form and pressed submit button ---------------------
if (isset($_POST['editUser'])) {
//validate data ------------------------------------------------------------------------
//check empty fields
//passwords won't be checked, as they are not required
foreach ($_POST as $k=>$v) {
if ($v == "" && !in_array($k,$notRequired)) {
$error[$k] = "<strong>This field is empty</strong>";
}
}
//escape string
$name = mysql_real_escape_string($_POST['name']);
$phone = mysql_real_escape_string($_POST['phone']);
$address = mysql_real_escape_string($_POST['address']);
$city = mysql_real_escape_string($_POST['city']);
$state = mysql_real_escape_string($_POST['state']);
$zip = mysql_real_escape_string($_POST['zip']);
$cell = mysql_real_escape_string($_POST['cell']);
$email = mysql_real_escape_string($_POST['email']);
$username = mysql_real_escape_string($_POST['username']);
$badges = mysql_real_escape_string($_POST['badges']);
$rank = mysql_real_escape_string($_POST['rank']);
$accounttype = mysql_real_escape_string($_POST['accounttype']);

//check email validation, the function is available at config.php
if (!check_email($_POST['email'])) {
$error['email'] .= " <strong>Email is not valid!</strong>";
}
//check email exists in database
$res = mysql_query("SELECT email FROM members WHERE email='".$email."' AND userid != '".$userid."'");
if (mysql_num_rows($res) == 1) {
$error['email'] .= " <strong>Email already existst in database!</strong>";
}
//check username exists in database
$res = mysql_query("SELECT username FROM members WHERE username='".$username."' AND username != '".$username."'");
if (mysql_num_rows($res) == 1) {
$error['username'] .= " <strong>Username already existst in database!</strong>";
}
//check both passwords are the same when password fields are not empty

//end validate data ---------------------------------------------------------------------

//save to database when no errors are detected ------------------------------------------
if (count($error) == 0) {
$query = "UPDATE members SET username='".$username."', email='".$email."',name='".$name."', phone='".$phone."',address='".$address."', city='".$city."',state='".$state."', zip='".$zip."',cell='".$cell."', accounttype='".$accounttype."',badges='".$badges."', rank='".$rank."' ";

$query .= "username='".$username."', email='".$email."',name='".$name."', phone='".$phone."',address='".$address."', city='".$city."',state='".$state."', zip='".$zip."',cell='".$cell."', accounttype='".$accounttype."',badges='".$badges."', rank='".$rank."' WHERE userid='".$userid."'";

//update username session if you edit yourself
if ($userid == $_SESSION['auth_admin_userid']) {
$_SESSION['auth_admin_username'] = $username;
}

if (mysql_query($query)) {
echo "<p><strong>User has been edited and saved to the database.</strong></p>";
} else {
echo "<strong>User has NOT been edited and saved into the database. ".mysql_error()."</strong>";
}
}
}
//get user from the database and put data into $_POST variables.
$rs = mysql_query("SELECT name, username, phone, address, city, state, zip, cell, email, badges, rank, accounttype FROM members WHERE userid = ".$userid."");
if (mysql_num_rows($rs) == 0) {
die("User does not exists!");
}
$row = mysql_fetch_assoc($rs);
$_POST['name'] = $row['name'];
$_POST['username'] = $row['username'];
$_POST['phone'] = $row['phone'];
$_POST['address'] = $row['address'];
$_POST['city'] = $row['city'];
$_POST['state'] = $row['state'];
$_POST['zip'] = $row['zip'];
$_POST['cell'] = $row['cell'];
$_POST['email'] = $row['email'];
$_POST['badges'] = $row['badges'];
$_POST['rank'] = $row['rank'];
$_POST['accounttype'] = $row['accounttype'];

//if is admin, then $_POST['admin'] exists

?>

<div id="TabbedPanels1" class="TabbedPanels">
<ul class="TabbedPanelsTabGroup">
<li class="TabbedPanelsTab" tabindex="0">My Info</li>
<li class="TabbedPanelsTab" tabindex="0">Merit Badges</li>
<li class="TabbedPanelsTab" tabindex="0">Scout Rank</li>
</ul>
<div class="TabbedPanelsContentGroup">
<div class="TabbedPanelsContent">
<form action="admin.php?edit&id=<?php echo $userid;?>" method="post">
<table align="center" cellpadding="8" cellspacing="8">
<tr>
<td><div align="right">Name:</div></td>
<td> <p><input type="text" name="name" value='<?php echo $_POST['name'];?>' />
<?php echo(isset($error['name']))?$error['name']:"";?></p></td>
</tr>
<tr>
<td>Phone Number:</td>
<td><input type="text" name="phone" value='<?php echo $_POST['phone'];?>' />
<?php echo(isset($error['phone']))?$error['phone']:"";?></td>
</tr>
<tr>
<td><div align="right">Address:</div></td>
<td><input type="text" name="address" value='<?php echo $_POST['address'];?>' />
<?php echo(isset($error['address']))?$error['address']:"";?></td>
</tr>
<tr>
<td><div align="right">City:</div></td>
<td><input type="text" name="city" value='<?php echo $_POST['city'];?>' />
<?php echo(isset($error['city']))?$error['city']:"";?></td>
</tr>
<tr>
<td><div align="right">State:</div></td>
<td><input type="text" name="state" value='<?php echo $_POST['state'];?>' />
<?php echo(isset($error['state']))?$error['state']:"";?></td>
</tr>
<tr>
<td><div align="right">Zip Code:</div></td>
<td><input type="text" name="zip" value='<?php echo $_POST['zip'];?>' />
<?php echo(isset($error['zip']))?$error['zip']:"";?></td>
</tr>
<tr>
<td><div align="right">Email:</div></td>
<td>
<p>
<input type="text" name="email" value='<?php echo $_POST['email'];?>' />
<?php echo(isset($error['email']))?$error['email']:"";?></p></td>
</tr>
<tr>
<td><div align="right">Cell Phone:</div></td>
<td><input type="text" name="cell" value='<?php echo $_POST['cell'];?>' />
<?php echo(isset($error['cell']))?$error['cell']:"";?></td>
</tr>
<tr>
<td class="aaaaaaa" align="right">Username:</td>
<td><label for="username"></label>
<input type="text" name="username" value='<?php echo $_POST['username'];?>' />
<?php echo(isset($error['username']))?$error['username']:"";?></p>
</td>
</tr>

</table>
<p>  </p>

<input name="submit" type="submit" value="Save" />

</form>
</div>
<div class="TabbedPanelsContent">
<label for="badges"></label>
<input name="badges" type="text" id="badges" value="<?php echo "$badges"; ?>" />
</div>
<div class="TabbedPanelsContent">
<input name="badges2" type="text" id="badges2" value="<?php echo $rank; ?>" />
</div>
</div>
</div> <script type="text/javascript">
var TabbedPanels1 = new Spry.Widget.TabbedPanels("TabbedPanels1");
</script>
<?php
}
?>

Update Query Not Working

Similar Tutorials

View Content

Hi, i am currently designing a new website and am testing a few different compnents of it. One part gathers two variables of the url using the GET method and selects the relevant data from the database. It then performs an UPDATE of a field called balance before INSERTING a new record. Everything works and gets inserted except for the UPDATE.

Here is the code

Code: [Select]
<?php
include ("connect.php");

$id = "";
$offerid = "";

$id = $_GET['user_id'];
$offerid = $_GET['offer_id'];

$sql_user = mysql_query("SELECT * FROM user_info WHERE id = $id");

$sql_offer = mysql_query("SELECT * FROM offers WHERE offerid = $offerid");

$balance += $payout;

mysql_query("UPDATE user_info SET balance = $balance WHERE id = $id");

mysql_query ("INSERT INTO offer_credited (id, offerid, date_credited, payout_to_user) VALUES ('$id', '$offerid', CURDATE(), '$payout')") or die(mysql_error());

echo "Your Offer has been recorded and Updated"
?>
The balance field is a float that i want to increase by the amount of the payout variable which is from the offers table. However, the balance never gets updated and remains at 0.

Any ideas what it could be, i am thinking it is something to do with,

Code: [Select]
$balance += $payout;
But i can't think of what else to do.

Hopefully this isn't too confusing.

Thanks for the help

Why Is This Not Working? Update Statement

Similar Tutorials

View Content

I have

<?php

/**

This file is responsible for processing all the add and modify requests
for the movies, games and customer section of the admin page.
The various functions here can be called into the pages we need inorder
to make code management cleaner and easier to handle.

**/

include('databaseconfig.php');

//Add a new customer to the data base.
$query = mysql_query("update customer set customer_id = '" .$_POST['cust_id'] . "', first_name = '" .$_POST['fname'] . "', last_name = '" .$_POST['lastname'] . "', adress = '" .$_POST['address'] . "', postal_code= '" .$_POST['postalcode'] . "', phone_number= '" .$_POST['phonenumber'] . "', user_name = '" .$_POST['fname'] . "', user_pass = '" .$_POST['lastname'] . "'");

echo("<h1>Output</h1>");
echo($query);

echo("<h1>Possible Errors</h1>");
//Echo errors
echo mysql_errno($query) . ": " . mysql_errno($query);

?>

Which should get the information from the forum feilds and insert that into the data base, throwing errors if I left feilds null.

But when I run it and leave everything blank and hit submit or even actually enter the required data all I get is a page that states

Code: [Select]
Output

Possible Errors
:

Update Is Not Working In An If Statement

Similar Tutorials

View Content

Believe me!! I have looked and tried so many snippets of code I am exausted!

TableName: keywords
Row: id productid keywords

Good morning...
I have been struggling with update, I dont know why... it seems easy eneough and it dosent look that different than a simple insert. Would someone please take a look at the if statement below, more specificly the update section. I am getting an error (Parse error: syntax error, unexpected T_STRING in...... ).

Code: [Select]
<?
$keywd = substr(implode(",", array_keys($arr_tem)),0,200);
$productid = intval($_GET['product_id']);

// Make a MySQL Connection
mysql_connect("localhost", "xxxxxxxxx", "xxxxxxxxx") or die(mysql_error());
mysql_select_db("xxxxxxxxx") or die(mysql_error());

$get = "SELECT * FROM keywords WHERE productid = $productid";
$SQ_query = mysql_query($get) or die("Query failed: $get\n" . mysql_error());
$fetch = mysql_fetch_array($SQ_query);

$id = $fetch['productid'];
$key = $fetch['keywords'];

// Evaluates to true because $var is empty
if (empty($id)) {
mysql_query("insert into keywords
(productid, keywords) VALUES('$productid','$keywd')");
}
else{
if (isset($id)) {
echo '$var is set even though it is empty';

$mysql_query = mysql_query(UPDATE keywords
SET keywords = '$keywd'
WHERE productid = '$productid');

// $mysql_query = mysql_query(UPDATE keywords set keywords = "$keywd" WHERE productid = "$productid");

}
endif;
?>

Update Query Not Working ... Please Help

Similar Tutorials

View Content

I would like to edit a record that I already have in my database but my query is not working for some reason. Hope someone can help.

The errors i get are
Notice: Undefined variable: first_name in C:\chemicaluser\www\editinfo.php on line 40
Notice: Undefined variable: last_name in C:\chemicaluser\www\editinfo.php on line 40
Notice: Undefined variable: log_number in C:\chemicaluser\www\editinfo.php on line 40

.... line 40 = my query
$query = "UPDATE table1 SET first_name = '$first_name', last_name = '$last_name' WHERE log_number = '$log_number' ";

Very simple database, 1 table w/ 2 fields
table name = table1
fields = first_name, last_name

my php file
Code: [Select]
<?php
  require ('/menu.php');
  require_once('sqlconnect.php');

  if (isset($_GET['log_number']) && isset($_GET['first_name']) && isset($_GET['last_name']) ) {
    $log_number = $_GET['log_number'];
    $first_name = $_GET['first_name'];
    $last_name = $_GET['last_name'];
  }
  else if
     (isset($_POST['log_number']) && isset($_POST['first_name']) && isset($_POST['last_name']) ) {
  $log_number = $_POST['log_number'];
  $first_name = $_POST['first_name'];
  $last_name = $_POST['last_name'];
  }

if (isset($_POST['submit'])) {
$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$query = "UPDATE table1 SET first_name = '$first_name', last_name = '$last_name' WHERE log_number = '$log_number' ";
$result = mysqli_query($dbc, $query)
or die ('Error querying database');
mysqli_close($dbc);
}

?>

my form
Code: [Select]
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<label for="first_name">First name</label>
<input type="text" id="first_name" name="first_name" value="<?php if (!empty($first_name)) echo $first_name; ?>"/>
<label for="last_name">Last Name</label>
<input type="text" id="last_name" name="last_name" value="<?php if (!empty($last_name)) echo $last_name; ?>" />
<input type="submit" value="Edit Information" name="submit" />
</form>

Pls Help My Update Command Isn't Working

Similar Tutorials

View Content

Hello people,

At the moment I am really desperate. I've done this script over 20 times now, always with the same script but all of a suddon, it doesn't work anymore. heres the problem:

I made a very simple "patient database" for a doctor. Where he can upload patients, alter and delete them. The script to add the patients works fine. now im trying to make a script where he can alter the variables agian, using the UPDATE command. but instead of updating the variables it cleares all the date in the row.

can someone help me? here s the entire code:

Code: [Select]
<?PHP
include'connect.php';
?>
<?PHP
$SQL = mysql_query("SELECT * FROM leys_patienten WHERE patientid='".$_REQUEST['patientid']."'");
while ($row = mysql_fetch_array($SQL))
{
?>
<?PHP
if ($_POST[submit]) {
if (!$_POST[volgnummer]) {
echo "<font size=\"2\" color=\"#990000\"><b>--> Vul een volgnummer in a.u.b. <--</b></font>";
}
elseif (!$_POST[naam])
{
echo "<font size=\"2\" color=\"#990000\"><b>--> Vul een naam in a.u.b. <--</b></font>";
}
elseif (!$_POST[voornaam])
{
echo "<font size=\"2\" color=\"#990000\"><b>--> Vul een voornaam in a.u.b.! <--</b></font>";
}
else {

mysql_query("UPDATE leys_patienten SET volgnummer='$volgnummer',naam='$naam',voornaam='$voornaam',adres='$adres',postcode='$postcode',plaats='$plaats',telefoon='$telefoon',email='$email',geboortedatum='$geboortedatum',geboorteplaats='$geboorteplaats',opmerkingen='$opmerkingen' WHERE patientid='".$_REQUEST['patientid']."'")
or die(mysql_error());

echo "Het patientendossier is succesvol gewijzigd, let op doorschakeling.";?>
<meta http-equiv="Refresh" content="1; url=patient.php?patientid=<?PHP echo $row['patientid']?>" />
<?
}
}
?></p>

<form action="<?$PHP_SELF?>" method="post" name="post" id="post">
<table width="805" border="0" align="center" cellpadding="0" cellspacing="0">
<tr>
<td class="table_forms">Volgnummer*</td>
<td class="table_forms"><label><input name="volgnummer" type="text" id="volgnummer" value="<?PHP echo $row['volgnummer']?>" size="40" /></label></td>
</tr>
<tr>
<td width="146" class="table_forms">Naam*</td>
<td width="659" class="table_forms"><label><input name="naam" type="text" id="naam" value="<?PHP echo $row['naam']?>" size="40" /></label></td>
</tr>
<tr>
<td class="table_forms">Voornaam*</td>
<td class="table_forms"><font color="#FFFFFF" size="2">
<label><input name="voornaam" type="text" id="voornaam" value="<?PHP echo $row['voornaam']?>" size="40" /></label>
</font></td>
</tr>
<tr>
<td class="table_forms">Adres </td>
<td><font color="#FFFFFF" size="2">
<label><input name="adres" type="text" id="adres" value="<?PHP echo $row['adres']?>" size="40" /></label>
</font></td>
</tr>
<tr>
<td class="table_forms">Postcode</td>
<td><font color="#FFFFFF" size="2">
<label><input name="postcode" type="text" id="postcode" value="<?PHP echo $row['postcode']?>" size="6" /></label>
</font></td>
</tr>
<tr>
<td class="table_forms">Plaats</td>
<td><font color="#FFFFFF" size="2">
<label><input name="plaats" type="text" id="plaats" value="<?PHP echo $row['plaats']?>" size="40" /></label>
</font></td>
</tr>
<tr>
<td class="table_forms">Telefoon</td>
<td><font color="#FFFFFF" size="2">
<label><input name="telefoon" type="text" id="telefoon" value="<?PHP echo $row['telefoon']?>" size="40" /></label>
</font></td>
</tr>
<tr>
<td class="table_forms">E-mail</td>
<td><font color="#FFFFFF" size="2">
<label><input name="email" type="text" id="email" value="<?PHP echo $row['email']?>" size="40" /></label>
</font></td>
</tr>
<tr>
<td class="table_forms">Geboortedatum</td>
<td><font color="#FFFFFF" size="2">
<label><input name="geboortedatum" type="text" id="geboortedatum" value="<?PHP echo $row['geboortedatum']?>" size="40" /></label>
</font></td>
</tr>
<tr>
<td class="table_forms">Geboorteplaats</td>
<td><font color="#FFFFFF" size="2">
<label><input name="geboorteplaats" type="text" id="geboorteplaats" value="<?PHP echo $row['geboorteplaats']?>" size="40" /></label>
</font></td>
</tr>
<tr>
<td valign="top" class="table_forms">Opmerkingen</td>
<td><font color="#FFFFFF" size="2">
<label><textarea name="opmerkingen" cols="40" rows="4" id="opmerkingen"><?PHP echo $row['opmerkingen']?></textarea></label>
</font></td>
</tr>
<tr>
<td valign="top" class="table_forms"> </td>
<td><span class="body_tekst">
<input type="submit" id="submit" name="submit" value="verstuur" />
</span></td>
</tr>
</table>
<p class="body_tekst"> </p>
</form>
<?
}
?>

Update Php Mysql Using Fancybox Not Working Please Help

Similar Tutorials

View Content

view_leader.php

Update Mysql Database Not Working, Help Please

Similar Tutorials

View Content

Hi everyone, I have been trying to get this code working but no matter what I try it will not work, I am trying to allow a user to update their personal details when they login to my website. I have created a form and submit button, the code is shwn below:

<?php
echo $_SESSION['myusername'];
?>
<br><br>
<form action="updated.php" method="post">
Firstname: <input type="text" name="firstname" /><br><br>
Surname : <input type="text" name="surname" /><br><br>
Date Birth: <input type="text" name="dob" /><br><br>
Total Wins: <input type="text" name="wins" />
Total Loses: <input type="text" name="loses" /><br><br>
Email Add: <input type="text" name="email" /><br><br>
Country : <input type="text" name="born" /><br><br>
Other Info: <input type="text" name="other" /><br><br>
<input type="submit" name="Submit" value="Update" align="right"></td>
</form>

The updated.php file

<?php
mysql_connect ("localhost","root","")
or die("Cannot connect to Database");
mysql_select_db ("test");

$sql=mysql_query("UPDATE memberdetails SET firstname='{$_POST['firstname']}', surname='{$_POST['surname']}', dob='{$_POST['dob']}', totalwins='{$_POST['wins']}', totalloses='{$_POST['loses']}', email='{$_POST['email']}', country='{$_POST['born']}', info='{$_POST['other']} WHERE username=$_SESSION['myusername']);

if (!mysql_query($sql))
{
die('Error: ' . mysql_error());
}
echo "Details Updated";

?>

This is the error i recieve:

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\wamp\www\website\updated.php on line 45

Line 45 is $sql=mysql_query line

If anybody can help it will be very much appreciated!

Update Multiple Rows Not Working

Similar Tutorials

View Content

can anyone see anything wrong here?? it wont update the Ships table..

i should of gone bed hours ago but its bugging me:

<?php
$sql="SELECT * FROM ships ORDER BY auction='Yes' DESC";
$result=mysql_query($sql);

// Count table rows
$count=mysql_num_rows($result);
?>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<form name="form1" method="post" action="">
<tr>
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">

<tr>
<td align="center"><strong>Active?</strong></td>
<td align="left"><strong>typeID</strong></td>
<td align="left"><strong>Item Name</strong></td>
<td align="left"><strong>Base Price</strong></td>
<td align="left"><strong>Market Price</strong></td>
<td align="center"><strong>Auction</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<?php
if ($rows['auction'] != "Yes") { ?>
<td align="center"><img src="../images/site/delete.png" /></td>
<?php }
else { ?>
<td align="center"><img src="../images/site/accept.png" /></td>
<? } ?>
<td align="left"><span class="isk">
<? $typeID[]=$rows[typeID]; ?>
<? echo $rows['typeID']; ?></span></td>
<td align="left"><span class="eveyellow"><? echo $rows['typeName']; ?></span></td>
<td align="left"><span class="normal"><?php echo number_format($rows['basePrice'])?> isk</span></td>
<td align="left"><input name="marketPrice[]" type="text" size="10" id="marketPrice" value="<? echo $rows['marketPrice']; ?>"> <span class="credits">(<?php echo number_format($rows['marketPrice']/1000000, 2)?> m)</span></td>
<td align="center"><input name="auction[]" type="text" size="6" id="auction" value="<? echo $rows['auction']; ?>"></td>
</tr>
<?php
}
?>
<tr>
<td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td>
</tr>
</table>
</td>
</tr>
</form>
</table>
<?php
// Check if button name "Submit" is active, do this
if($Submit){
for($i=0;$i<$count;$i++){
$sql1="UPDATE ships SET marketPrice='$marketPrice[$i]', auction='$auction[$i]' WHERE typeID='$typeID[$i]'";
$result1=mysql_query($sql1);
}
}

if($result1){
header("location:ship.php");
}
mysql_close();
?>

typeID is my primary key in the table and i only want to update "marketPrice" and "auction" upon submit. its a update multiple rows form by the way.

thank you so much for helping me... again.. would be lost without phpfreaks.

Update Query Not Working Properly

Similar Tutorials

View Content

$db->query( "UPDATE user_resources, user_buildings, user_units_nonbattle SET user_resources.uGold=user_resources.uGold+(user_buildings.uTownCenterLevel*(user_units_nonbattle.uMiner*10))" );

When the cron runs, it updates everyone the same regardless. Any idea what i'm doing wrong?

Php Mysql Update Record Not Working ...help!!

Similar Tutorials

View Content

hi -
i'm trying to update mysql databse but not working... any ideas???

Code: [Select]
[php]
<?php ob_start();
require_once('../xconfig.php');
if(isset ($_GET['quote'])&& $_GET['quote']!=""){
$quote_id=$_GET['quote'];
mysql_select_db($database, $makeconnection);
$sql_find_quote = "SELECT * FROM tbl_quote WHERE quote_id = $quote_id";
$find_quote = mysql_query($sql_find_quote, $makeconnection) or die(mysql_error());
$row = mysql_fetch_assoc($find_quote);
$totalRows = mysql_num_rows($find_quote);
$quote_author = $_POST['quote_author'];
$quote_desc = $_POST['quote_desc'];

if (isset($_POST['submitted'])&&($_POST['submitted'] == "yes")) {
$register_query = "SELECT quote_desc FROM tbl_quote WHERE quote_desc='$quote_desc'";

mysql_select_db($database, $makeconnection);
   $register_check=mysql_query($register_query, $makeconnection);
    $register_found_quote = mysql_num_rows($register_check);

if($register_found_quote>1){
header ("Location: quote_modify.php?error=quoteexists&quote=$quote_id");
}else{
$sql_modify = "UPDATE tbl_quote SET
quote_desc = '$quote_desc'
quote_author = '$quote_author'
WHERE quote_id = '$quote_id'";
}
mysql_select_db($database, $makeconnection);
   $Result1 = mysql_query($sql_modify, $makeconnection) or die(mysql_error());
header ("Location: quote.php");
}
}
ob_flush();
?>
[/php]
here's my HTML form

Code: [Select]
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1">
<p>
<input name="quote_author" type="text" class="active-field" id="quote_author" value="<? echo $row['quote_author'];?>"/>
<br />
<input name="quote_desc" type="text" class="active-field" id="quote_desc" value="<? echo $row['quote_desc'];?>" />
<br />
<input name="submitted" type="hidden" id="submitted" value="yes" />
<input name="submit" type="submit" id="submit" class="submit-button" value="modiy"/>
<br />
</p>
</form>

Mysqli Update Function Not Working

Similar Tutorials

View Content

Hi, i have a user update function in my code so I can easily change user fields int he database
public function updateUser ($username, $value, $what) {
$q = "UPDATE `users` SET ? = ? WHERE username = ?";
if ($stmt = $this->db_connection->prepare($q)) {
$stmt->bind_param("sis", $what, $value, $username);
$stmt->execute();
}
}

The database is connected successfully, but say i run a updateUser('blaine0002', 'blah', 'password'); nothing would get updated and no errors are thrown.
Am i doing something wrong? Thank you!

Cms Update/edit Function Not Working

Similar Tutorials

View Content

I am trying to create a CMS management website, but I can't seem to get the update function to work. Everything else works fine but not the update function. Can anyone please tell me why or what the problem is? I have spent too long trying to fix it and have failed. It is correctly linked to the database when I hit the edit button all i get is UPDATE_CONTENT_FORM($_GET['ID'])?>where the text boxes should be is . Please help, I am really stuck. (sorry about spelling )
code in CMS_Class.php

Class modernCMS{

var $host='localhost';
var $username='lmcmanus13';
var $password='k0gl0zfh3g1ccm4v';
var $db='lmcmanus13';

function connect(){
$con = mysql_connect($this->host, $this->username, $this->password);
mysql_select_db($this->db,$con);
}

function get_content($id =''){

if ($id != ""):
$id = mysql_real_escape_string($id);//helps to protect database from beening hacked 
$sql = "SELECT * FROM `CMS_Content` WHERE id ='$id'";

else:
$sql = 'SELECT * FROM `CMS_Content` WHERE 1';

endif;

//$query = 'SELECT * FROM `CMS_Content` WHERE 1';
$result = mysql_query($sql) or die(mysql_error());

if (mysql_num_rows($result)!=0):
while($row= mysql_fetch_assoc($result)){
echo '<h1><a href="Animals.php?id=' . $row['id'] . '">' . $row['Title'] . '</h1>';
echo '<p>' . $row['Body'] . '</p>';
}
else:
echo '<p> we are sorry there seems to be a problem with your request</p>';
endif;
echo $return='<p><a href ="Animals.php">Back</a></p>';

}

function add_content($_POST){

$Title= mysql_real_escape_string($_POST['Title']);
$Body= mysql_real_escape_string($_POST['Body']);

if(! $Title || ! $Body):
if(!$Title=""):
echo"<p>The Title is required<p>";
endif;
if(!$Body=""):
echo"<p>The Body is required<p>";
echo '<a href="add-content.php">Try Again</a>';
endif;
else:
$sql="INSERT INTO `CMS_Content`(`id`, `Title`, `Body`) VALUES ('null','$_POST[Title]','$_POST[Body]')";
$result = mysql_query($sql) or die(mysql_error());
echo "<meta http-equiv='refresh' content='0;url=added.php'>";
endif;
} 

function manage_content (){
echo '<div id ="manage">';
$sql = 'SELECT * FROM `CMS_Content`';
$result = mysql_query($sql) or die(mysql_error());
while ($row = mysql_fetch_assoc($result)):
echo '<h1><a id=' . $row['id'] . '">' . $row['Title'] . '</h1>'
?>
<div>
<span ><a href="update-content.php?id=<?php= echo= $row['id']?>">Edit</a>|<a href="?delete=<?php echo $row['id']; ?>">Delete</a></a></span>
</div>

<?php
endwhile;
echo '</div>';//closes the manages div
}

Function delete_content($id){

if(!$id){
return false;
}else{
$id=mysql_real_escape_string($id);
$sql="DELETE FROM CMS_Content WHERE id='$id'";
$result = mysql_query($sql) or die(mysql_error());
echo "<meta http-equiv='refresh' content='0;url=deleted.php'>";
}
function update_content_form($id) {
$id = mysql_real_escape_string($id);
$sql = "SELECT * FROM CMS_Content WHERE id = '$id'";
$res = mysql_query($sql) or die(mysql_error());
$row = mysql_fetch_assoc($res) 
?>
<form action="Animals.php" method="post" > 
<input type="hidden" name="update" value="true" />
<input type="hidden" name="id" value="<?php=$row['id']?>" />
<div>
<label for="title">Title:</label>
<input type="text" name="Title" id="Title" value="<?php=$row['Title']?>" />
</div>
<div>
<label for="body">Body:</label>
<textarea name="body" id="body" rows="8" cols="40"><?php=$row['Body']?></textarea>
</div>
<input type="submit" name="submit" value="Update content" />
</form>
<?php

function update_content($p) {
$title = mysql_real_escape_string($s['title']);
$body = mysql_real_escape_string($s['body']);
$id = mysql_real_escape_string($p['id']);

if(!$title | !$body):

if(!$title):
echo "<p>The Title is Required</p>";
endif;
if(!$body):
echo "<p>The body is Required</p>";
endif;
echo '<p><a href=" update_content.php?id=' . $id . '">Try Again</a></p>';
else:
$sql = "UPDATE CMS_Content SET title = '$title', body = '$body' WHERE id = '$id'";
$res = mysql_query($sql) or die(mysql_error());
echo "Updated Successfully!";
endif;
}
}
}//end of class
}
?>

code in Animals.php

<h1> Our Animals </h1>



<ul>
<li><a href="manage-content.php">Manage Content</a></li>
<li><a href="add-content.php">Add Content</a></li>
</ul>

<?php 
if(isset($_POST['add'])):
$obj->add_content($_POST);
elseif(isset($_POST['update'])):
$obj->update_content_form($_POST);
endif; 
?>
Code in update-content.php
<h1> Our Animals j,j</h1>
<h1> Update Content </h1> 
<?=$obj->update_content_form($_GET['id']) ?>

Edited by Ch0cu3r, 10 December 2014 - 11:47 AM.
Added code tags

Mysql Update Query Not Working

Similar Tutorials

View Content

Hi guys need some help.I created a simple Update Customer Details page Where you Enter the Customer ID ,The Customer Details Get Displayed inside a Form and you make changes within the Form.But the update query I wrote is not working as it should be.It Executes the Query ,when I hardcode the Customer ID inside the Update query but fails when I need to Enter the Customer ID directly from the form using post.In This Code I tried to Update only the Customer's Firstname.Thanks
Here Is The Code
Code: [Select]
<?php
$db=mysql_connect("localhost","root","") or die('Unable to Connect To Database.Please check the Database Parameters');
mysql_select_db('ecommerce') or die(mysql_error());

if(isset($_POST['enterid']))
{
$_POST['inputid'];
}

$query="SELECT * FROM customer WHERE Cid='$_POST[inputid]'";
$result=mysql_query($query) or die(mysql_error());
$row=mysql_fetch_array($result);
$new_cid=$row['Cid'];
$new_firstname=$row['Cfname'];
$new_lastname=$row['Clname'];
$new_email=$row['Email_id'];
$new_address=$row['Address'];
$new_pincode=$row['Pincode'];
$new_payment=$row['Mode_of_payment'];
$new_city=$row['City'];
$new_state=$row['State'];
$new_phone=$row['Phone'];

$html1=<<<HTML1
<form action="updatecustomer.php" method="post">
<p class="inputidentifier">Please Enter The Customer's ID</p><input type="text" style="width:375px;height:40px;font-size:30px;" name="inputid" size="20"><br><br>
<input type="submit" name="enterid" style="height:40px">
HTML1;

print($new_cid);

if(isset($_POST['update']))
{
  $query1="UPDATE customer SET Cfname='$_POST[firstname]' WHERE Cid='$_POST[inputid]'";
  mysql_query($query1) or die(mysql_error());
  if(mysql_affected_rows()==1)
  print("Query sucessful");
  else
  print("Something went wrong");
}
?>
<html>
<head>
<style type="text/css">
.inputtext {width:300px; height:40px;font-size:30px;}
.inputidentifier{font-size:25px;font-family:"Arial"}
.h1type{font-family:"Arial"}
</style>
<title>Test</title>
</head>
<body>
<?php print($html1); ?>
<h1 align="center" class="h1type">Update Customer Details</h1>
<form action="updatecustomer.php" method="POST">
<table align="center" cellspacing="10" cellpadding="10" border="0" width="60%">
<tr>
<td align="right" class="inputidentifier">First Name</td>
<td align="left"><input type="text" class="inputtext" name="firstname" placeholder="eg:Kevin" value="<?php print($new_firstname) ?>"></td>
</tr>
<tr>
<td align="right" class="inputidentifier">Last Name</td>
<td><input type="text" class="inputtext" name="lastname" placeholder="eg:Aloysius" value="<?php print($new_lastname) ?>"></td>
</tr>
<tr>
<td align="right" class="inputidentifier">E-mail</td>
<td align="left"><input type="email" style="width:500" class="inputtext" name="email" placeholder="yourname@email.com" value="<?php print($new_email) ?>">
</tr>
<tr>
<td align="right" class="inputidentifier">Phone Number</td>
<td align="left"><input type="text" class="inputtext" name="phone" placeholder="How Do We Call You?" value="<?php print($new_phone) ?>"></td>
</tr>
<tr>
<td align="right" class="inputidentifier">Address</td>
<td><textarea style="width:500;height:150" wrap="virtual" class="inputtext" name="address" placeholder="Where is your Crib?"><?php print($new_address) ?></textarea></td>
</tr>
<tr>
<td align="right" class="inputidentifier">State</td>
<td align="left"><input type="text" style="width:500" class="inputtext" name="state" placeholder="State" value="<?php print($new_state) ?>">
</tr>
<tr>
<td align="right" class="inputidentifier">City</td>
<td align="left"><input type="text" class="inputtext" name="city" placeholder="City" value="<?php print($new_city) ?>">
</tr>
<tr>
<td align="right" class="inputidentifier">Pin Code</td>
<td><input type="text" class="inputtext" name="pincode" placeholder="Mulund 400080" maxlength="6" value="<?php print($new_pincode) ?>"></td>
</tr>
<tr>
<td align="right" class="inputidentifier">How do Pay for your Bling?</td>
<td align="left">
<input type="text" class="inputtext" name="payment" value="<?php print($new_payment)?>">
</tr>
<tr>
<td></td>
<td><input type="submit" name="update" value="Update!" style="width:100px;height:60px;"></td>
</tr>
</table>
</form>
</body>
</html>

Sql Update Is Not Working, Can You Check My Syntax?

Similar Tutorials

View Content

Hi, I joined new here, and I am really having hard time figuring out what's wrong with the code below which isn't working.

    if (isset($_POST['privacy_submit'])) {
if (($_SERVER['REQUEST_METHOD'] == "POST"))
{
    $privacy_upd = mysql_query("UPDATE clf_privacy_terms SET
            'p_bannerads' = '".$_POST['p_bannerads']."',
            'p_shareinfo' = '".$_POST['p_shareinfo']."',
         'p_crossmarketing' = '".$_POST['p_crossmarketing']."',
            'p_tacking' = '".$_POST['p_tacking']."',
            'p_sendcommunication' = '".$_POST['p_sendcommunication']."',
         'p_under13' = '".$_POST['p_under13']."',
            'p_internationally' = '".$_POST['p_internationally']."',
            'p_discloselegal' = '".$_POST['p_discloselegal']."',
         'p_server_country' = '".$_POST['p_server_country']."',
            'p_forums' = '".$_POST['p_forums']."',
            'p_newslettermodule' = '".$_POST['p_newslettermodule']."',
            'p_membershipmodule' = '".$_POST['p_membershipmodule']."'
            ") or die(mysql_error());

        $msg="Successfully Updated!";
}
    }
else    {
        $msg="<font color=\"red\">Incorrect method of submission.</font> Please try again.";
}

?>

<h2>Privacy Policy</h2>

<?php if ($privacy_upd) { echo ($msg); } ?>

<form class="box" name="privacy_upd" action="gen.php" method="post">
.........................................................................................
........................

MySQL Error returns the following:

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''p_bannerads' = 'do not', 'p_shareinfo' = 'do not', 'p_cross' at line 2
Let me know if any of your guys can solve it for me, I would appreciate since I am not able to solve it for last two days already.

Thank you...

Php With Sql Update Command Not Working For Numbers > 2

Similar Tutorials

View Content

This is the weirdest thing ever. I've been programming php for years yet I have been pulling my hair out for hours over something that seems so simple!

I have a table in my db named last_num_used with 2 fields: id, num which are both type int.
It only has one row, so I don't need to use WHERE to update

when I execute the command via php:
Code: [Select]
$sql = "UPDATE last_num SET num='4'";
echo $sql;
if (!mysql_query($sql)) {die('Error: ' . mysql_error());}everything works fine and I see the echoed command UPDATE last_num SET num='4'

But, when I have a variable $var and try to update it, it will only update properly if $var=1 or $var=2. If $var equals a value greater than 2, then for some reason it updates the column so that num=1. Note the exact problem in example 3 below.

Example 1:
Code: [Select]
$var=1;
$sql = "UPDATE last_num SET num='$var'";
echo $sql;
if (!mysql_query($sql)) {die('Error: ' . mysql_error());}Result:   echoed to screen: UPDATE last_num SET num='1'
      database updated and num=1

Example 2:
Code: [Select]
$var=2;
$sql = "UPDATE last_num SET num='$var'";
echo $sql;
if (!mysql_query($sql)) {die('Error: ' . mysql_error());}Result:   echoed to screen: UPDATE last_num SET num='2'
      database updated and num=2

Example 3:
Code: [Select]
$var=3;
$sql = "UPDATE last_num SET num='$var'";
echo $sql;
if (!mysql_query($sql)) {die('Error: ' . mysql_error());}Result:   echoed to screen: UPDATE last_num SET num='3'
      database updated and num=1

Mysql Update Followed By Select Query Not Working

Similar Tutorials

View Content

Hi there,

I'm having a problem with updating a record with an UPDATE mysql query and then following that query with a SELECT query to get those values just updated.

This is what I'm trying to do...I'd like a member to be able to complete a recommended task and upon doing so, go to a page in their back office where they can check off that task as "Completed". This completed task would be recorded in their member record in our database so that when they return to this list, it will remain as "Completed". I'm providing the member with a submit button that will call the same page and then update depending on which task is clicked as complete.

Here is my code:
Code: [Select]
$memberid = $_SESSION['member'];

// Check if form has been submitted
if(isset($_POST['task_done']) && $_POST['task_submit'] == 'submitted')
{
$taskvalue = $_POST['task_value'];
$query = "UPDATE membertable SET $taskvalue = 'done' WHERE id = $memberid";
$result = mysqli_query($dbc, $query);
}

$query ="SELECT task1, task2, task3 FROM membertable WHERE id = $memberid";
$result = mysqli_query($dbc, $query);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);

$_SESSION['task1'] = $row['task1'];
$_SESSION['task2'] = $row['task2'];
$_SESSION['task3'] = $row['task3'];
?>
<h4>Task List</h4>
<table>

<form action="" method="post">
<tr>
<td>Task 1</td>
<td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
</tr>
<input type="hidden" name="task_value" value="task1" />
<input type="hidden" name="task_submit" value="submitted" />
</form>

<form action="" method="post">
<tr>
<td>Task 1</td>
<td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
</tr>
<input type="hidden" name="task_value" value="task2" />
<input type="hidden" name="task_submit" value="submitted" />
</form>

<form action="" method="post">
<tr>
<td>Task 1</td>
<td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
</tr>
<input type="hidden" name="task_value" value="task3" />
<input type="hidden" name="task_submit" value="submitted" />
</form>

</table>

The problem that I am having is that the database is not updated with the value "done" but after submission, the screen displays "Completed" instead of "Mark As Completed". So the value is being picked up as "done", but that is why I have the SELECT after the UPDATES, so that there is always a current value for whether a task is done or not. Then I refresh and the screen returns the button to Mark As Complete. Also, when I try marking all three tasks as, sometimes all three are updated, sometimes only one or two and again, I leave the page or refresh and the "Marked As Completed" buttons come back. Bizarre. If anyone can tell me where my logic is going wrong, I would appreciate it.