PHP - Most Efficient Way To Set Php Variable Through A Link

Hy,

How can I put a link to a variable without doing like:
Code: [Select]
<a href='#'>$var</a>
I heard that can be other ways.

Thanks

I have a page that lists out some basic information about each quiz this particular student has taken (call it "quiz summary"). I am creating another page that will have all details of a particular quiz by itself (call it "quiz detail").

If I have a link for each quiz on the "quiz summary" page, how do I tell the "quiz detail' page which link they clicked on? Or which quiz they have selected.

I was thinking it would work if I assigned a session variable to each link and then the "quiz detail" page could verify which returns true still and show details for that quiz. Would this logic work? Npot sure how to do it anyone though.

thanks for any help!

Hi.
I have a sort of security script which checks a few things, how can i save the url of the link that was clicked, so i can pass it through the script then if all is good, continue on to the url, if not send them somewhere else

let me try to explain better with a little text picture

user clicks link ----------------------> link goes to my security script --------------------> if the check passes, continue to original links url

so basically i just need to know how to save the links url as a variable

ive done a page that works fine but id like to add links to the results so i can view the models.
working page here http://sts.hostei.com/dsgi/list_records.php
in the make column i want a link that will only show the make clicked.

if this was a fixed page i no how to do it but i cannot figure out to make it from the way ive discribed.

i know i have to alter this line
<td><div align="center"><?php echo $rows['make']; php?></div></td>
but no idea how to do this.
do i create a new page for the query? if so how do i pass the $var?
is it possable to do this from the same page? ie appear undr the main table.

Thanks

<?php
include("config.php"); 

// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

$sql = "SELECT make, COUNT(*) AS total, SUM(IF(comments = \'pass\', 1, 0)) AS withComments FROM dsgi_serval GROUP BY make ORDER BY COUNT(*) DESC"; 
$result=mysql_query($sql);
php?>

<table width="319" border="1"><tr>
      <td colspan="4"><font size="4" face="Verdana">
         <strong><div align="center">Validation Total's </div></strong></font> </td>
   </tr>
    <tr>
       <td width="137" align="center"><strong>Make</strong></td>
       <td width="85" align="center"><strong>Total</strong></td>
       <td width="75" align="center"><strong>Validated</strong></td>
    </tr>
<?php
while($rows=mysql_fetch_array($result)){
php?>
    <tr>
        <td><div align="center"><?php echo $rows['make']; php?></div></td>
        <td><div align="center"><?php echo $rows['total']; php?></div></td>
        <td><div align="center"><?php echo $rows['withComments']; php?></div></td>
     </tr>
<?php
}
php?>
     <tr>

         <td><div align="center">Totals</div></td>
         <td> <div align="center">
         
           <?php
// counts all rows
           $query = "SELECT make, COUNT(make) FROM dsgi_serval "; 
           $result1 = mysql_query($query) or die(mysql_error());

           // Print out result
           while($row1 = mysql_fetch_array($result1)){
           echo $row1['COUNT(make)'];
}
?>
        </div></td>
        <td><div align="center">
       
<?php
 
 // counts passes
           $query = "SELECT make, COUNT(make) FROM dsgi_serval where comments like 'pass'"; 
           $result2 = mysql_query($query) or die(mysql_error());
           while($row2 = mysql_fetch_array($result2)){
           echo $row2['COUNT(make)'];

}
?>
       </div></td>
      </tr>
</table>



<?php
mysql_close();
php?>

trying to post a link to the database
Code: [Select]
$amessage ="<a href="link.php">this is a link </a>";

then return that link later on another page.