|
PHP - If String Exists In Current Url Echo $_get
Hi all - I'm trying to echo $_GET something from the URL, and display a short message to the user if the echo $_GET fails - but I'm new to PHP and the code I've whipped up doesn't work. It always displays the message even if the information is present in the url and the $_GET should work. Here's the code I've got:
<h3>
<?php
$qset = strpos($_SERVER['SCRIPT_NAME'], 'qtitle');
if ($qset === false) {
echo "You haven't added any questions yet.";
} else {
echo $_GET['qtitle'];
}
?>
</h3>
The URL will contain "qtitle=(something)" if they've filled out a form on the prior page.
Can someone tell me what I'm doing wrong? I have a feeling I've overcomplicated things...
Thanks again!
Similar TutorialsOk, here's my code: How do i make it so that it outputs a maximum of only 5 results from the query where the img file exists. When I add LIMIT to the sql query it doesnt work so I guess its something else, but I have no clue. Can anyone help? $query = mysql_query("SELECT * FROM table WHERE date >= '$now' ORDER BY max(date) desc"); while ($row = mysql_fetch_assoc($query)) { $cid = $row['cat_id']; $title = $row['name']; $seoname = $row['seourl']; $img = 'images/'.$seoname.'.jpg'; if (!file_exists($img)) { $img = ''; } else { $img = 'images/'.$seoname.'.jpg'; } if (!empty($img)) { echo '<a href="images/'.$seoname.'/"><img src="'.$img .'" style="width:528px;" alt="" /></a>' . "\n"; } } Thanks. Hello, I just wanna know if any such commands are available in php for making a variable as such like - $variable = " blah blah .. . . . index.php?X=<?php echo $_GET['x']; ?>..........blah"; thank you I'm a total noob trying to figure out how to get this function to work right. I want to echo for each Code: [Select] '<OPTION value="'.$SKUCAPS.$skunum.$size.'">'.$size.'</OPTION>' for each size in the $skus[$type][$skunum]['sizes'] array. and if no size exists echo Code: [Select] '<input value="'.$SKUCAPS.$skunum.'" type=hidden" name="item">' Code: [Select] <?php $BANDNAME="Band Name"; $BANDCAPS="BANDNAME"; $BANDLOWER="bandname"; $SKUCAPS="BND"; $SKULOWER="bnd"; $skus = array( 'shirts' => array( '165' => array( 'name' => 'World Khaos Tour <br> Limited Edition Tour Track Jacket.', 'price' => '70.00', 'sizes' => array('M', 'L', '1X' ) ), '139' => array( 'name' => 'KHAOS LEGIONS ALBUM COVER', 'price' => '15.95', 'sizes' => array('S', 'M', 'L', '1X' ) ), ), //end product type 'misc' => array( '603' => array( 'name' => 'Ring Button', 'price' => '3.00', 'sizes' => array('none') ), '602' => array( 'name' => 'Logo Button', 'price' => '3.00', 'sizes' => array('none') ) ) //end product type ); //end skus function makeProduct($type){ global $skus; foreach ( $skus[$type] as $skunum => $value) { $price = $skus[$type][$skunum]['price']; $name = $skus[$type][$skunum]['name']; echo ' <!-- PRODUCT BEGIN --> <li class="product" > <a href="images/'.$SKULOWER.$skunum.'lg.jpg" rel="lightbox"><img src="product_files/'.$SKULOWER.$skunum.'.png"></a><br> <strong>'.$name.'</strong><br>'.$SKUCAPS.$skunum.'<br>$'.$price.'<br> <form name="'.$SKUCAPS.$skunum.'" method="GET" target="_blank" action="http://www.jsrdirect.com/cgi-bin/Make-a-Store.cgi"> <input type="hidden" name="band" value="'.$BANDCAPS.'"> <input type="hidden" name="back" value="http://www.jsrdirect.com/bands/'.$BANDLOWER.'/index.html"> <strong>Qty:</strong> <input type="text" name="quantity" size="1" value="1" > <strong>Size:</strong> <SELECT name="item">'.makeSizes(). '</SELECT> <br><br> <input class="css3button" value="Add To Cart" type="image"> </form> </li> <!-- Product End -->'; } } ?> any help would be greatly appreciated I know this one is probably super easy for you programmer types.. but I just need to know.. If a string ends with a dash (and not all of them will), how do I remove it? Thanks! I'm doing a cURL post to a server and it returns "true No_Error Data was accepted 10356546 3770 false 0 " Form --> Method=Post --> submit.php (this is the page that's doing the cURL post and the server returns data that appears on this page). How do I take this and put it into a string? I need to echo out some string variables in a form. I also want to add some validation for Name, email etc. I think I have the code right or close, but I can an error on the index.php page which is. "Fatal error: Call to undefined function form_row_class() in index.php on line 14" here is the code for the form <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>String Tester</title> <link rel="stylesheet" type="text/css" href="main.css"/> </head> <body> <div id="content"> <h1>String Tester</h1> <form action="submit.php" method="post"> <table> <tr class="<?php echo form_row_class("name") ?>" > <th><label for="first_name">Name</label></th> <td> <input name="first_name" id="first_name" type="text" value="<?php echo h($_POST['name']); ?>" /> <?php echo error_for('name') ?> </td> </tr> <tr class="<?php echo form_row_class("email") ?>"> <th><label for="email">Email Address</label></th> <td> <input name="email" id="email" type="text" value="<?php echo h($_POST['email']); ?>" /> <?php echo error_for('email') ?> </td> </tr> <tr> <th></th> <td><input type="submit" value="submit" /></td> </tr> </table> </form> <h2>Message:</h2> <?php echo "<table>"; echo "<tr><td>"; echo $name; echo "</td></tr>"; echo "<tr><td>"; echo $email; echo "</td></tr>"; echo "<tr><td>"; echo $phone; echo "</td></tr>"; echo "</table>"; ?> </div> </body> </html> and the submit portion <?php // If request is a form submission if($_SERVER['REQUEST_METHOD'] == 'POST'){ // Validation // Check first_name is non-blank if(0 === preg_match("/\S+/", $_POST['name'])){ $errors['name'] = "Please enter a name."; } // Check email is valid (enough) if(0 === preg_match("/.+@.+\..+/", $_POST['email'])){ $errors['email'] = "Please enter a valid email address."; } // validate a phone number if( !preg_match("/^([1]-)?[0-9]{3}-[0-9]{3}-[0-9]{4}$/i", $phone) ) { echo 'Please enter a valid phone number'; } // If no validation errors if(0 === count($errors)){ // Sanitize first, last, and email $name = mysql_real_escape_string($_POST['name']); $email= mysql_real_escape_string($_POST['email']); $email= mysql_real_escape_string($_POST['phone']); } // Helpers function form_row_class($name){ global $errors; return $errors[$name] ? "form_error_row" : ""; } function error_for($name){ global $errors; if($errors[$name]){ return "<div class='form_error'>" . $errors[$name] . "</div>"; } function h($string){ return htmlspecialchars($string); } ?> probably something simple I am missing. Hi all, how would I write a string like this in an echo statement so the javascript runs? <a href="javascript:ajaxpage('test.php', 'content');">test</a> how do i get the image to show as the code i have is echoing what i have been told is binary, not confirmed. and not the images. all images are .jpg Code: [Select] $allowed_types = array('png','jpg','jpeg','gif'); $imgdir = '/home/mysite/ftpfolder'; $imgFilesArray = scandir($imgdir); foreach ($imgFilesArray as $imgkey => $imgvalue) { $imgInfo = pathinfo($imgdir . '/' . $imgvalue); $imgExtension = $imgInfo['extension']; if(in_array($imgExtension, $allowed_types)) { readfile($imgdir . '/' . $imgvalue); //echo '<img src = "'. $imgdir .'/'. $imgInfo['basename'].'" alt="" />'; } } images are FTP'd to the ftpfolder and can not be placed anywhere else but this folder due to security reasons. Could someone help me crack this issue. I am trying to insert a variable into an flash object echo string's src. I've try many variations but can't figure it out. Below is the code. cheers ray <?php $var = 'map.swf'; echo ' <OBJECT ID="map" CLASSID="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" CODEBASE="http://active.macromedia.com/flash2/cabs/swflash.cab#version=2,0,0,0" WIDTH="50%" HEIGHT="50%"> <PARAM NAME="Movie" VALUE="map.swf"> <PARAM NAME="Play" VALUE="false"> <PARAM NAME="Quality" VALUE="best"> <PARAM NAME="swLiveConnect" VALUE="true"> <PARAM NAME="loop" VALUE="false"> <EMBED NAME="slav" SRC=" map.swf " swLiveConnect="true" WIDTH="50%" HEIGHT="50%" mayscript="mayscript" quality="best" play="false" LOOP="false" pluginspage="http://www.macromedia.com/shockwave/download/index.cgi?P1_Prod_Version=ShockwaveFlash2"> </EMBED> </OBJECT>'; echo "<br/>"; echo $var; echo "<br/>"; ?> Goal <?php $var = 'map.swf'; echo ' <OBJECT ID="map" CLASSID="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" CODEBASE="http://active.macromedia.com/flash2/cabs/swflash.cab#version=2,0,0,0" WIDTH="50%" HEIGHT="50%"> <PARAM NAME="Movie" VALUE=" $var "> <PARAM NAME="Play" VALUE="false"> <PARAM NAME="Quality" VALUE="best"> <PARAM NAME="swLiveConnect" VALUE="true"> <PARAM NAME="loop" VALUE="false"> <EMBED NAME="slav" SRC=" $var " swLiveConnect="true" WIDTH="50%" HEIGHT="50%" mayscript="mayscript" quality="best" play="false" LOOP="false" pluginspage="http://www.macromedia.com/shockwave/download/index.cgi?P1_Prod_Version=ShockwaveFlash2"> </EMBED> </OBJECT>'; ?> The below might be a noob question but, I concatenate two spaces in the below string $new_hebrew_date_string = $hebrewMonthName . ' ' . $hebrewDay . "%"; yet when I execute echo "<br />new_hebrew_date_string is $new_hebrew_date_string<br />"; printf("hebrew_date_string is: %s <br />", $new_hebrew_date_string); Only one space is output in between $hebrewMonthName and $hebrewDay regardless of how many spaces I pad the string with. Strangely enough, the string $new_hebrew_date_string is correctly padded w/spaces when I pass it as a parameter to a mySQL stored procedure. Any ideas anyone? Thank you. i get this error Warning: current() [function.current]: Passed variable is not an array or object.. for this Code: [Select] $lastblock = current( ${"s".$row} ); print_r($lastblock); when i change to this it works.. Code: [Select] $lastblock = current( $s0 ); print_r($lastblock); The problem is i won't know the $row seeing as it is in a while loop. Solution? A few months ago, and a good amount of time before that, I had people telling me to use isset() instead of performing to see if the variable is empty, such as: !$_GET[''] I know the differences in the function and what they do, but when could isset() be used in a situation where it's better/more efficient then: !$_GET[''] I do use isset(), though. Hi, I'm wanting to find rows whose date is within the next week of the current month of the current year. The format of the date is, for example: 2010-10-28 Any ideas guys? Thanks lots! Hello - I've come to an issue with something I'm working on and have searched around with no luck. When editing user accounts I want it to not be able to change the e-mail address into existing ones on other rows, but when submitting the form it takes into account that this particular rows email address is the same as the one which was sent via $_POST and throws up the error. The desired behaviour I want is for it to ignore the ID of the row which was posted, but take into account every other row. Here's the code as it stands at the moment: $email = $_POST['email']; $checkemail = mysql_query("SELECT email FROM users WHERE email='$email'"); } if (mysql_num_rows($checkemail) > 0) { return $this->error("The e-mail address you provided is already associated with an account."); } Hi i have this drop down list current the year is 2010 and downwards but i want to change the list to 2010 upwards u can notice on the 50-- so shows current year minus so current is 2010 to 61 how can i change 2010 to 2030 or sunfin?? echo '<select name="year_of_birth">',"\n"; $year = date("Y"); for ($i = $year;$i > $year-50;$i--) { if($i == $thisYear) { $s = ' selected'; } else { $s=''; } echo '<option value="' ,$i, '"',$s,'>' ,$i, '</option>',"\n"; } echo '</select>',"\n"; OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas? So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! Hi community,i creating a simple website and description i analyzed my code about 3days...2hours a day. if i get the point in my head.then its say Website url is in use..but not..ok maybe i give the code below. so if you can explain whats wrong.thanks Code: [Select] <?php include_once ('connect.php'); $url= mysql_real_escape_string($_POST['url']); $desc=mysql_real_escape_string($_POST['desc']); if ($id == "krauti") { if (empty($_POST['url']) && empty($_POST['desc'])) { die('<br><center>Both Empty!.<center/><br/>'); } if (empty($_POST['url'])) { die('<br><center>URL Empty!.<center/>'); } if (empty($_POST['desc'])) { die('<br><center>desc empty fill it!.<center/>'); } $url = htmlspecialchars( stripslashes( strip_tags($_POST['url'] ) ) ); $aprasymas = htmlspecialchars( trim($_POST['desc'] ) ); $query = mysql_query("SELECT * FROM linkai WHERE url = '$url' AND 'desc' = '$desc'"); if( mysql_num_rows( $query ) == 1 ) { "INSERT INTO linkai ". "(id, url, desc) ". "VALUES('','$_POST[url]','$_POST[desc]')"; echo "Yes!."; } else if (mysql_num_rows($query) == 0 ){ echo "No!!"; } } ?> |
|||||||