PHP - Php Gd Image Graphing Problem With Color Running Out

Hi people

I'm trying to show all my data in my database, and I'm trying to make the font color change after 7 days to yellow and after 14 days it should show up red. But it does not work, could someone see any error in the code?

It turns up green all the time..


Code: [Select]
while($row = mysql_fetch_array($result)) {

    $postTime = $row['date'];
    $thisTime = time();
    $timeDiff = $thisTime-$postTime;

    if($timeDiff <= 604800) { // Less than 7 days[60*60*24*7]
      $color = '#D1180A';
    } else if($timeDiff > 604800 && $timeDiff <= 1209600) { // Greater than 7 days[60*60*24*7], less than 14 days[60*60*24*14]
      $color = '#D1B30A';
    } else if($timeDiff > 1209600) { // Greater than 14 days[60*60*24*14]
      $color = '#08C90F';
    }

    echo '<tr style="color: '.$color.';">';

    echo '<td>'. $row['id'] .'</td>';

    echo '<td>'. date("d.m.y", strtotime($row["date"])) .' </td>';

    echo '<td><a href="detaljer.php?view='. $row['id'] .'">'. $row['Navn'] .'</a></td>';
 
    echo '<td>'. $row['Telefon'] .'</td>';

    echo '<td>'. $row['Emne'] .'</td>';

    echo '</tr>';

  }

  echo '</table>';

I want to reduce a picture size from 600px * 500px to 60px * 50px size, then crop it become 50px *50px. I have two groups of codes, 1 is to reduce the size of image, other 1 is to crop the image. The problem is they works separately, how to combine this two groups of codes to make them work together? Below is my codes :

Code: [Select]
<?php
//codes of group A - Reduce the size of image from 600px * 500px to 60px * 50px   
    $save2 = "images/users/" . $image_name_2; //This is the new file you saving
    list($width2, $height2) = getimagesize($file) ; 
    $modwidth2 = 50; 
    $diff2 = $width2 / $modwidth2;
    $modheight2 = $height2 / $diff2; 
    $tn2 = imagecreatetruecolor($modwidth2, $modheight2) ; 
    $image2 = imagecreatefromjpeg($file) ; 
    imagecopyresampled($tn2, $image2, 0, 0, 0, 0, $modwidth2, $modheight2, $width2, $height2) ; 
    imagejpeg($tn2, $save2, 100) ; 

//codes of group B - Crop the image from 60px * 50px to 50px * 50px 
    $save3 = "images/users/" . $image_name_3;  
    list($width3, $height3) = getimagesize($file) ; 
    $modwidth3 = 60;  
    $diff3 = $width3 / $modwidth3;
    $modheight3 = $height3 / $diff3; 

    $left = 0; 
    $top = 0;

    $cropwidth = 50; //thumb size
    $cropheight = 50;

    $tn3 = imagecreatetruecolor($cropwidth, $cropheight) ; 
    $image3 = imagecreatefromjpeg($file) ; 
    imagecopyresampled($tn3, $image3, 0, 0, $left, $top, $cropwidth, $cropheight, $modwidth3, $modheight3) ; 
    imagejpeg($tn3, $save3, 100) ; //save the cropped image
?>
As you can see from 2 groups of codes above, 1st group resize the pic then save it to a folder. 2nd group of codes crop the pic then save it into the folder too. My question is ... After 1st group of codes resize the picture, is it necessary to save it into folder before I can crop it? If it is necessary, then I need to write new lines of codes to retrieve the resized pic from the folder for 2nd group of codes to crop it? If it is not necessary, after resizing the pic, how do I pass the pic to 2nd group of codes to crop it?
php image-resizing

Hello everyone!

I need a little help to get functions names from the GD library.
first i want to say i have a little knowledge with GD library like create image with words and etc.

So , what i'm trying to do is to take image and than
take the color of the first pixel on the top left than do some function work and than
set this pixel on the top left to another color.

now , i know how the algorithm should look like , i just don't know what function i need to use to:
take specific pixel color from the image
set new color for pixel on specific place

i'll be glad if you could help me with that ,
regards , Mor.

So I've coded this to run the while loop once for every server within the the table, there is currently two rows within the table and the while loop wont stop running it just keeps on running until I restart Apache, its producing the same effect as what "while(1)" would do, could anybody tell me what the problem could be?, thanks for your time in advance.


class bot_restart
{
function __construct( )
{
while($CurrentServers = mysql_fetch_array(mysql_query("SELECT * FROM xhost_boxs")))
{
echo $CurrentServers['box_id'];
}
}
}

Hi,

I have a PHP script which I want to run from a different IP on my server.

Example of what I want to do:
My main ip: 4.5.6.7
Have several IP's on server.
I want my PHP script (running from CLI) to use cURL with another IP, ay 4.5.6.9

Is this possible to do?

Help would be greatly appreciated!

I want to run a php file which contains a long process and takes time. If I simply run the file on browsers, the process will be interrupted by any perturbation in the internet connection or closing the browser. How I can force the php process to continue running without connection to my local PC (server side controlling)? I am looking for something like what cron job does (but only one time, not periodically).

ok.  this may make now sense at all, I will try to explain as best as I can.  anyways, what I need is for a mysql query to run that will pull all data from table payment between certain days.  Then all the rows will show, but I want only one row with each cart_id(there will be multiple) to show.  After it does that, in a new column on a table, all the payment types with the amount will show with a slash between each one. 
I want all of this in a table generated from a php loop.

maybe a visual represenation will be better.
 I hope the picture I attached makes a bit more sense.

Hey Guys,

I have a DB with two tables, one is field names, the other is the data.

So for example, I log in and I am user ID 1..... I need to query the DB to show all fields where user_id = 1

Field1 - Data1
Field2 - Data2

etc etc...

This is what I have so far, but I dont get any output...

    $sql = "SELECT * FROM ".WPSC_TABLE_DATA." WHERE `user_id` == .$cu. ORDER BY id DESC";
    $user= $wpdb->get_row($sql);

while($user) {

echo $user->name .' : '. $user->value .'<br />';

}

Can you help please?

I am using MAMP on my MacBook and don't understand why MAMP and my code in NetBeans will not run if I am offline?

If I am trying to execute PHP files locally on my laptop, why should MAMP or Apache of NetBEans care if I do not have an Internet connection?! 

I wanted to show someone something at work where there is no Internet access, but that won't work as it currently stands. 



TomTees

Hi,

actually the problem is i have been modifying a website, which has been already built and working. so i have all the code and everything, i need to keep it running to make changes. But i m facing problems like above

Warning: require_once(../../global-inc.php) [function.require-once]: failed to open stream: No such file or directory in C:\\Apache2.2\htdocs\login.php on line 2

Fatal error: require_once() [function.require]: Failed opening required '../../global-inc.php' (include_path='.;C:\php5\pear') in C:\\Apache2.2\htdocs\login.php on line 2


please let me know what to do ...

and the other thing is i need to execute the entire file of code at a time .....can u please tell me the process of doing it ..........


thanks in advance

shiva

shiva

Hi,

Im trying to create a really simple password protected page that is fairly secure but when the user doesnt enter a password the wrong error is displayed. Can anyone see a problem?

Also could someone please check that im properly compairing the hash password of 2135fa0dd7fb99d167b420b7ff34ec98
with what the user entered when its hashed?

login.php

<?php
  session_start();
?>
<?php
  $submit = $_POST['submit'];
  $password = md5($_POST['password']);
  if ($submit)
  {

    if ($password)
    {
      if ($password == '2135fa0dd7fb99d167b420b7ff34ec98')
        {
          $_SESSION['user'] = logged;
          header('Location: page.php'); 
        }
        else
        {
  header('Location: index.php?id=1');
        }
    }
    else
    {
      header('Location: index.php?id=2');
    }
  }
  else
  {
  header('Location: index.php?id=1');
  }
?>

index.php
<?php
  $id=$_REQUEST['id'];
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html lang="EN" dir="ltr" xmlns="http://www.w3.org/1999/xhtml">
  <head>
    <meta http-equiv="content-type" content="text/xml; charset=utf-8" />
    <title>Keys</title>
    <link rel = "stylesheet"
          type = "text/css"
          href = "css/layout.css" />
  </head>
 
  <body>


      <div id="header">
        <h1>Keys</h1>
      </div>

  
      <div id="secondheader">
    
      </div>

  
      <div id="main">
    <form method="POST" action="login.php">
          Password: <input type="password" name="password" onfocus="selected(this)" onblur="notselected(this)">
          <input type="submit" name="submit" value="Login">
        </form>
<br/>
<?php
          if ($id==1)
  {
    echo "Invalid password. Please try again";
  }
  elseif ($id==2)
  {
    echo "Please enter a password";
  }
        ?>

      </div>

  
      <div id="footer">
        
      </div>
  
      <div id="left">
    
      </div>


  </body> 
</html> 

Thanks in advance.

Hi i was wondering what im doing wrong, im trying to insert a query for submit button, it works if i run it straight in mysql, but not working when linked through php. Im just doing it for testing purpose right now only, so when i see that it works i will use another query.

here it is

Code: [Select]
<?php 
include('config.php');
if($_SESSION['username']){
if(isset($_POST['ASubmit'])){
$query3=("update country set Status='test1' where Uname='Mclovin'");}

echo '<td><form name="test" method="post" form id="form1"><label for="test">Status</label>
<select name="Status">
<option value="">-----</option>
<option value="In process" '.(($row['Status']=='In process')?'selected="selected"':'').'>In process</option>
<option value="Approved" '.(($row['Status']=='Approved')?'selected="selected"':'').'>Approved</option>
<option value="Denied" '.(($row['Status']=='Denied')?'selected="selected"':'').'>Denied</option>
        </select><input name="ASubmit" type="submit" value="Update">'; echo $row{'Status'}.'</td></form>';
}
?>

I am trying to display a js dialog box when someone wants to delete something.  Currently I have it all with buttons and PHP in the background.  When they click the delete icon, I want a dialog box to appear with OK or Cancel.  On cancel, return back to the same page, If OK, I want it to run the PHP/mysql code that deletes the record from the DB.  Once deletes, I want the box to appear again saying it was deleted successfully.

I found this but now sure how to make it work.

function show_confirm()
{
var r=confirm("Press a button");
if (r==true)
  {
  alert("You pressed OK!");
  }
else
  {
  alert("You pressed Cancel!");
  }
}

I have a php script that calls another script. It seems that the 2nd script times out or something. I have tried setting max_execution_time to 120 seconds. how can I fix this? I open to anything.

Thanks

I am running some php via a cron and I was after the best way to achieve this. Currently I am doing it as follows:-

Code: [Select]
0 * * * * lynx -dump http://www.domain.com/script.php
This works fine but I don't want anybody being able to run the script by pointing their browser to the file.

Any advice on the best method? Cheers.