PHP - Problem Compiling Apache, Mysql Or Php From Source Code Inside A Container.
Hey guys,
I'm facing an issue compiling the above stack from a source code inside lxc using centos 6.5 as a domain OS.
[lxc@lxc1 httpd-2.4.9]$ ./configure --with-included-apr
checking for chosen layout... Apache checking for working mkdir -p... yes checking for grep that handles long lines and -e... /bin/grep checking for egrep... /bin/grep -E checking build system type... x86_64-unknown-linux-gnu checking host system type... x86_64-unknown-linux-gnu checking target system type... x86_64-unknown-linux-gnu configu configu Configuring Apache Portable Runtime library... configu configuring package in srclib/apr now checking build system type... x86_64-unknown-linux-gnu checking host system type... x86_64-unknown-linux-gnu checking target system type... x86_64-unknown-linux-gnu Configuring APR library Platform: x86_64-unknown-linux-gnu checking for working mkdir -p... yes APR Version: 1.5.1 checking for chosen layout... apr checking for gcc... gcc checking whether the C compiler works... yes checking for C compiler default output file name... a.out checking for suffix of executables... checking whether we are cross compiling... configu error: in `/home/lxc/httpd-2.4.9/srclib/apr': configu error: cannot run C compiled programs. If you meant to cross compile, use `--host'. See `config.log' for more details configure failed for srclib/apr This problem has been detected by me when I replaced my desktop machine with new one and installed a centOS again. This such a problem never happened before using my old machine with the same version of OS and libvirt. Just to be clear, a new selinux policy into a "domain machine" has been created to be able to use the "dbus daemon" to all containers and if I try to complile this stack from source using the "domain os" this problem never happens at all. All "Development tools" is installed to this particular container, in case someone asks me why I get the following error message - "configu error: cannot run C compiled programs" Any ideas? Edited by jazzman1, 08 June 2014 - 01:37 PM. Similar TutorialsHow can I insert PHP code inside MySQL DB? I have mixed HTML and PHP code like this: <div class="rightpanel"> <div class="hltred"> <div class="hlthead"> <p><?php echo $pages->naslov; ?></p> </div> <div class="hltcontent"> <p> ovde treba da ide loop sa svi podlinkovi za taj glavni koji je aktivan</p> </div> </div> </div>, but when i insert it into DB i get this code (I use htmlspecialchars function to store): <div class="rightpanel"> <div class="hltred"> <div class="hlthead"> <p> <!--?php echo $pages---> naslov; ?></p> </div> <div class="hltcontent"> <p> ovde treba da ide loop sa svi podlinkovi za taj glavni koji je aktivan</p> </div> </div> </div> Hello, I have a php code within a javascript. The javascript gets invoked on button click. The php code withing javascript never gets executed. I don't face the same problem in other browsers. Any help is much appreciated! Regards, Cole Hi guys, I've just started using xampp for php. My friend sent me the files i've attached below to see if apache is working for me, but i don't understand why they won't work together. Basically the .html file opens a simple login which works fine. When the password is typed in it should direct me to some links, but for some reason it doesn't. It does however look like the apache server is working fine - it could be something with the code i'm really not to sure. When i try to log in these are one set of the errors it gives me: Warning: file_get_contents(listlinks.array) [function.file-get-contents]: failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/test1/userlinks.php on line 8 Warning: sqlite_open() [function.sqlite-open]: unable to open database: /Applications/XAMPP/xamppfiles/htdocs/Test1/userlinks.sqlite in /Applications/XAMPP/xamppfiles/htdocs/test1/userlinks.php on line 16 Warning: sqlite_query() expects parameter 1 to be resource, string given in /Applications/XAMPP/xamppfiles/htdocs/test1/userlinks.php on line 20 Warning: sqlite_fetch_array() expects parameter 1 to be resource, null given in /Applications/XAMPP/xamppfiles/htdocs/test1/userlinks.php on line 21 Warning: Cannot modify header information - headers already sent by (output started at /Applications/XAMPP/xamppfiles/htdocs/test1/userlinks.php: in /Applications/XAMPP/xamppfiles/htdocs/test1/userlinks.php on line 25 Warning: sqlite_close() expects parameter 1 to be resource, boolean given in /Applications/XAMPP/xamppfiles/htdocs/test1/userlinks.php on line 61 I've literally just started learning web scripting so i apologise for over-looking anything simple. The login.php file is also supposed to be .html aswel - i just changed it to upload. Thanks in advance, Josh. This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=333987.0 This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=352845.0 I am using apache web server on linux. I am using php for coding. My php code is not able to read the files from /var/tmp folder. If apache itself creates some files in /var/tmp folder then php code is able to read it. Why this permission denied issues are there though full access permissions are given to each file?
This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=333523.0 I'm trying to run a process using shell_exec, however the program i'm trying to run must communicate with a process that is not a system process, and everytime i run it, it fails, does anyone know how to make a apache server run active windows not in the system process? Does any one have a better idea to protect PHP files so that you can distribute a 'release' without the customer being able to read the source files. There are tools on the internet which costs money, BUT your are dependant on their software and if its not open source, its not trustworthy. What I've done so far is writing an ISAPI DLL in borland cpp and installed it under iis6. Basically you call this isappi dll and it decrypts the encrypted php files and executes them respectively. It is thread safe (as is php). There are other methods available on the net that you use to encrypt your pages, BUT the decryption algorithm is found in your main php file and duh, if you can read the main file, you can easily decrypt all other files, so that is a bad idea. Any other ideas? Possibly to write a PHP extension perhaps but I have not been able to get that working on borland cpp. So I am completely done with my forum after several posts here and a lot of time. But crap! I just realized that the way my avatar system works it will give away the password! I REALLY don't want to redo that system because truth is it is about 40 percent of the entire sites coding. It works by making pictures in a directory named the usersname.thepassword . Whatever filesystem. Now when I echo the path everyone can see the password and username in the source code! And thy can click it to see the picture! Is there a way to hide the paths or the source codeM thanks! looking for a way to view the PHP source code of any PHP page on the web. Looking for a way to obtain PHP source code in order to help me with a certain issue. Advise. So I am completely done with my forum after several posts here and a lot of time. But crap! I just realized that the way my avatar system works it will give away the password! I REALLY don't want to redo that system because truth is it is about 40 percent of the entire sites coding. It works by making pictures in a directory named the usersname.thepassword . Whatever filesystem. Now when I echo the path everyone can see the password and username in the source code! And thy can click it to see the picture! Is there a way to hide the paths or the source codeM thanks!
How to edit my source code so the output prints correctly ?
Currently testing a site thats almost built, am going to be including php on a sidebar on all pages so thought it'd be easier to just make all pages .php, however when i upload and try and view, in Firefox it just displays the source code on screen! It does it on other computers, but works fine in IE! ARRGGGHH Anyone have a clue? Kind Regards, Chris Hello all, i have a feeling im doing something wrong, but i have no idea what. being server-side code, php should not show when you 'view page source' in your browser (or rather it should display as html), correct ? why, then am i seeing php code when i view page source? see attached image I have whiled my way through any number of forums and help pages so far. However, since I am not quite comfortable yet with PHP, I am not sure which option I have been given would be the right one. What I am trying to do: Create the source for a set of drop-down menus. The dropdown menu has columns, and then a H2 and P that go in each column, in varied numbers, so you have column1, h2 p; h2 p; h2 p column2, h2 p; h2 p etc....make sense? I am using an MySQL table as source so I can have a little CMS dashboard where I can change these and other values on the fly. So I have a MySQL table where I have a field that identifies the column (page name), and then values to fill the h2 and p tags. I.E.: page_name, content_title, content_text The idea, therefore, is to use PHP to figure out what the column names (that are repeated) in the mysql table and then create the dropdown based on the value in the subsidiary fields. Output is as a string in a variable value that is output via return (); My best estimation of how to do this is to use php to create a multidimensional array from the query result, where the first column is the page_name, followed by an array, the array being the remainder of the information. Based on information scrounged from other sources, I have come up with this so far: $query = "SELECT * FROM tbl_mainmenu WHERE mainmenu_type = '$mmtype'"; // what the query is $result = mysql_query ($query, $dbc); // connect to database and run query, setting the the result to dummy array variable '$result' // establish the multidimensional array $mmcontent_array = array (); //create the array where the values are content page and associated values in an array per each content page while ($result = mysql_fetch_assoc ()) { $page_name = $result['content_page']; $mmcontent_array['content_page'] = $result; } foreach ($mmContent_array[] as $key=>$value) { foreach () { $tmpelements[] = '<div class="col_2"><h2>' . $element[content_title] . "</h2>\n<p>" . $element[content_text] . "</p>\n</div>"; $elements = implode("\n",$tmpelements) . "\n" } $tmp[] = '<li><a href="#" class="drop">Products</a><!-- Begin Products Item -->\n<div class="dropdown_2columns"><!-- Begin 2 columns container -->' . $elements . 'whatever tags will close this') } Am I even in the ballpark? I am not sure which way to nest the foreach ()'s. The example I was working from used echo ()'s, and I am not sure if using $variable = implode () makes the task different. As a start, I am just wondering if I am creating the multidimensional array correctly? well basically im trying to do that the 'subject says. ive done my homework and had around 10 examples of using curl, but none of them worked in my case. this is the final code i'm using <?php $cookiefile = '/temp/cookies.txt'; #2 ways ive tried doing #$data = array('edit[username]' => 'REMOVED', 'edit[password]' => 'REMOVED', 'edit[submit]' => 'Login'); $data = array('username] => 'REMOVED', 'password' => 'REMOVED', 'submit' => 'Login'); $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, 'http://pokerrpg.com'); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookiefile); curl_setopt($ch, CURLOPT_COOKIEJAR, $cookiefile); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $data); curl_exec($ch); curl_setopt($ch, CURLOPT_URL, 'http://pokerrpg.com/furniture_store.php'); $contents = curl_exec($ch); $headers = curl_getinfo($ch); echo $contents; curl_close($ch); unlink($cookiefile); ?> im not sure about the cookie file, but i just made a txt file to that location. and empty txt file. hope it's fine. the page i'm trying is http://pokerrpg.com, you can even look the source code that both of these fields do exist. when i run it, the output is a login page without logging in, so it does not log in. I've been developing a php application that runs my entire company for the last 4 years. One of the things I never thought of until now is that the server guys or anyone else could copy the source code and db and be able to start up another company which brings up my question to you.... How would you protect your application? My thought is to create one small php file that is encrypted with something that is required to make the entire site run (not sure at this point what it would be that they couldn't just rebuild). Then if this file sees it's on a different domain/ip it requests data from my site which logs the info for me to look at. If I find out it's something not approved, it would then not allow the program to run and will give a error. What is your idea? Hi, I need to extract the integers from the source code:
<span class=CatLevel1><a onclick="Javascript:ShowMeu('21');">Arts</a> (9768)</span> <span class=CatLevel1><a onclick="Javascript:ShowMeu('271');">Industrial Products</a> (9321)</span> <span class=CatLevel1><a onclick="Javascript:ShowMeu('1273');">Baby</a> (11407)</span>What are the pattern that I can use to retrieve all the integer in the bracket (9768, 9321, 11407)? This is my php code: <!DOCTYPE html> <html> <body> <?php $file_string = file_get_contents('http://www.lelong.com.my/'); preg_match('/<title>(.*)<\/title>/i', $file_string, $title); //pattern $title_out = $title[1]; echo $title_out; ?> </body> </html>Thanks Edited by Raex, 22 August 2014 - 12:49 AM. |