PHP - Changed Php Version Now Php Scripts Not Working?
I have just upgraded PHP on my ISP server and none of the php scripts work.
I was using 5.2. And I am now on 5.4. Why would the scripts stop working? Are there and patches or changes I need to make to make them work? I need an answer urgently! Similar TutorialsHi all, I created a page template at http://www.durgeshsound.com/gallery/ Here my pagination buttons are not working. this issue arises when permalink format is http://www.example.com/sample-post/ But when I set permalink format to default (www.example.com/?p=123) then it starts to work and creates a working pagination link like this http://www.durgeshso...e_id=81&paged=2. I want this format http://www.example.com/sample-post/ in the links. Please help. Hi everyone, would be grateful if anyone can help me. I recently changed my hosting package and didnt realize that the new package uses PHP 5. There is no option to use an earlier version but my thumbnail script that worked on PHP 4 just shows a red cross where the thumbnail should be. Can anyone tell me why the script below would not work with PHP 5. I have a basic understanding of how scripts work but I am not an expert so if you could make any replies easy to understand I have checked and the new server does have GD library version 2.0.34 installed - not sure if there is anything else I need to check ? script called: uktn.php Code: [Select] <? $maxwidth = 200; $maxheight = 200; $image_path = $_GET['im']; $ext = explode('.', $image_path); $i = count($ext)-1; if ($ext[$i] == 'jpg' || $ext[$i] == 'jpeg' || $ext[$i] == 'JPG' || $ext[$i] == 'JPEG' ) { $img = @imagecreatefromjpeg($image_path); } else if ($ext[$i] == 'png' || $ext[$i] == 'PNG') { $img = @imagecreatefrompng($image_path); } else if ($ext[$i] == 'gif' || $ext[$i] == 'GIF') { $img = @imagecreatefromgif($image_path); } if ($img) { $width = imagesx($img); $height = imagesy($img); $scale = min($maxwidth/$width, $maxheight/$height); if ($scale < 1) { $new_width = floor($scale*$width); $new_height = floor($scale*$height); $tmp_img = imagecreatetruecolor($new_width, $new_height); imagecopyresized($tmp_img, $img, 0, 0, 0, 0, $new_width, $new_height, $width, $height); imagedestroy($img); $img = $tmp_img; } } if (!$img) { exit ("You must specify an image!"); } header("Content-type: image/png"); imagepng($img,'',100); ?> Many thanks, Dave I have had a problem with some scripts I wrote (Screenscrapers) that worked great in PHP4, but stopped working the minute I upgraded to PHP5. I can change all of my filenames to have the .PHP4 extension and this solves the problem, but since this encompasses a number of sites, internal links and hundreds of files, this is not my first choice solution. Here is the scraper, what it does, is it takes items from the zazzle Results Page by category, strips out the formatting, adds my affiliate ID and then I can present these items on my page. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Test of scrape</title> <link rel="stylesheet" type="text/css" href="/css/scraper.css" /> <script type='text/javascript' src='http://www.zazzle.com/js/logging/omniture/s_code.zjs/r-52.78223/site-zazzle.js'></script> </head> <body> <div class="gridCell " id="page_productsGrid_assetCell1"> <?php $page = file_get_contents("http://www.zazzle.com/cool+smiley+gifts"); //comment out the <span> tags completely $page = preg_replace('/<span/', "<!-- <span", $page); $page = preg_replace('/<\/span>/', "<\/span> -->", $page); $page = preg_replace('/<a /', "<a rel=\"nofollow\" ", $page); $rf_id="238219236805025733"; // Regular expression to parse "&rf=" and the $rf_id into the existing link $page=preg_replace("/(.*?)(href\s*=+\s*[\"\'])(.*?)([\"\'])(.*?)/is","$1$2$3?rf=$rf_id$4$5",$page); $test = explode('<div style="position:relative" class="clearfix">',$page); for($t=1;$t<=count($test)-2;$t++){ print "<div class=\"gridCellInfo\" id=\"page_products\">"; print $test[$t]; } ?> </body> </html> This works find in PHP4; not at all in PHP5. My ideal solution would be an .htaccess file that I could put in any directory under PHP5 to make it default to php4. I have tried this, to no avail (.htaccess): Code: [Select] <IfModule mod_rewrite.c> RewriteEngine On AddType text/html .php4 AddHandler php4-script .php .html php5 </IfModule> I have also tried a few alternatives... this appears to be a common problem and I have scoured the web and found no solution. Here are the two pages in PHP4 and PHP5: php4: http://www.killersmiley.com/test/cool-smiley.php4 php5: http://www.killersmiley.com/test/cool-smiley.php Hi all, But of a PHP newbie so treat me nice but this one is driving me nuts I have the exact same login.php file running on two different servers and they have slightly different versions of PHP installed as follows: 1. PHP Version 5.0.4 - version http://www.trafficpaymaster.com/tpm/phpversion.php 2. PHP Version 5.2.15 - version http://www.dentistsinflorida.org/tpm/phpversion.php The login works fine on the first server from he http://www.trafficpaymaster.com/tpm/login.php Email: test@test.com Pwd: test But try it on the second server he http://www.dentistsinflorida.org/tpm/login.php Using the same email and password (which is correct) it just loops round not letting the user into the main script at index.php Question: Why? What have I got wrong for that later version of PHP? Many thanks guys. Alright guys.. I need some advice, some recommendations and definitely some help. I've got a submission form for users to upload an image and some basic personal information. The client wanted the information to be divided by the North America (specifically N.A. and not U.S.) and Europe.. so I created a database table with the typical structu a row for the user's name, email, etc. I also added a row labeled "regionid" in which "1" would equal North America and "2" would equal Europe. This "regionid" row would obviously organize the submission by their country. The client specifically wanted to label North America but mentioned only users from the States would probably only submit images, etc. Users could choose if they were submitting a form for US or Europe and "regionid" would be filled by which form was chosen. Recently, the client threw a curveball and now wants Canada as part of the North America submission form. Now, I don't want to add Canada as another option for my "regionid" row because it does belong under North America. However, I need to alter the structure of the database I currently have so that it can now organize if under North America or Europe, and if under North America, if the submission falls under the United States or Canada. I was thinking of adding a drop down menu under the North America form with the options US or Canada. Do you guys have any advice or other directions you would take to solve this problem.. that is, if my situation is even understandable? I found it pretty difficult to explain! Apologies! Hello everybody,
I have a form like that:
<form method="post" action="x.php"> <input type="hidden" name="pubid" value="<?php echo $_SESSION["public_id"][$a]; ?>" /> <input type="submit" name="update" />The public id is an id that every user have and that I use for get and post, imagine that this form is in a php "for" that print all this forms with public_id. Then I have a code like that: if(isset($_POST["update])){ if($_POST["pubid"]!==(There are some checks to avoid mysql injection)){ mysql_query=update from xxx set x=1 where pubid=$_POST["pubid"])(EXEMPLE) }}I want to avoid any change of form, because if someone change the value of the hidden input can modify information of mysql, someone know any method to do that? A friend told me to use js to compare form fields, but the user can modify js too I think, then I need to check it with php I think, correct me if Im wrong. Someone help me please. I have an upload script that has been working just fine for months now.. I didn't change a thing,, now people are saying they are getting a internal server error... I checked it myself and I am getting the same thing. There is no error number,, so I can't look it up.. My upload script is good for 30mb's and has been just fine up til now.. Any ideas? Could GoDaddy just be having probs? The error is only shown after the upload is started.. the upload starts, then about 30 seconds later, it appears. Ive created a process which automatically creates a form for all of the "courses" that are listed in a database. This table shows the name, the course code, the current program the course is under and an option to delete the course. I have created a drop down menu for the user to select any of the current programs to switch the course into. My problem is I have X amount of select fields and radio buttons and I dont know how to tell which one has been changed below is my code, appreciate the help!: case "ep": if (isset ($_GET['id'])){ $id = $_GET['id']; echo "Below lists all of the current courses under this program. Once you have made all of the changes click the submit button at the bottom of the page. <br><br><br>"; $query = "SELECT * FROM courses WHERE cid = $id"; $result = mysql_query($query) or die (mysql_error()); echo "<form action=\"course_process.php\" method=\"post\">"; echo "<table><tr><td><strong>Course Name</strong></td><td><strong>Course Code</strong></td><td><strong>Change Course Program</strong></td><td><strong>Delete</strong></td></tr>"; $i = 0; while ($row = mysql_fetch_assoc($result)){ $r = $row['id']; $query2 = "SELECT * from catagories"; $result2 = mysql_query($query2) or die (mysql_error()); echo "<tr><td> ". $row['name']. " </td><td> ".$row['code']." </td><td><select name=\"".$row['id']."\">"; while ($row2 = mysql_fetch_assoc($result2)){ echo "<option value=".$row2['id'].">".$row2['name']. "</option>"; } echo "</select></td><td><input name=\"".$row['id']."\" type=\"radio\" value=\"Click to delete\" /></td></tr>"; } echo "<tr><td></td><td></td><td></td><td><input name=\"submit\" type=\"submit\" value=\"Commit Changes\" /> </td></tr></table></form>"; }else{ echo "Invalid action request. ERROR CODE 1"; } break; Hey Guys,
I'm doing some coding and I've managed to snip something off....
This is the original code
<form method="post" action="{$systemsslurl}cart.php?a=add&domain=register"> <table class="table table-striped table-framed"> <thead> <tr> <th></th> <th>{$LANG.domainname}</th> <th class="textcenter">{$LANG.domainstatus}</th> <th class="textcenter">{$LANG.domainmoreinfo}</th> </tr> </thead> <tbody> {foreach from=$availabilityresults key=num item=result} <tr> <td class="textcenter">{if $result.status eq "available"}<input type="checkbox" name="domains[]" value="{$result.domain}" {if $num eq "0" && $available}checked {/if}/><input type="hidden" name="domainsregperiod[{$result.domain}]" value="{$result.period}" />{else}X{/if}</td> <td>{$result.domain}</td> <td class="textcenter {if $result.status eq "available"}domcheckersuccess{else}domcheckererror{/if}">{if $result.status eq "available"}{$LANG.domainavailable}{else}{$LANG.domainunavailable}{/if}</td> <td class="textcenter">{if $result.status eq "unavailable"}<a href="http://{$result.domain}" target="_blank">WWW</a> <a href="#" onclick="popupWindow('whois.php?domain={$result.domain}','whois',650,420);return false">WHOIS</a>{else}<select name="domainsregperiod[{$result.domain}]">{foreach key=period item=regoption from=$result.regoptions}<option value="{$period}">{$period} {$LANG.orderyears} @ {$regoption.register}</option>{/foreach}</select>{/if}</td> </tr> {/foreach} </table> <p align="center"><input type="submit" value="{$LANG.ordernowbutton} »" class="btn btn-danger" /></p> </form>and I've changed it to: <form method="post" action="{$systemsslurl}cart.php?a=add&domain=register"> {foreach from=$availabilityresults key=num item=result} {if $result.status eq "available"} <div style="width: 400px; color: #339933; font-size:14px;"><img src="/templates/dj/yes.jpg" style="float:left" />{$tld}<br />Available</div> <div style="width: 100px;" >{$name}<p style="color: #339933;">{$tld}</p></div> <div style="width: 200px;" ><select name="domainsregperiod[{$result.domain}]">{foreach key=period item=regoption from=$result.regoptions}<option value="{$period}">{$period} {$LANG.orderyears} @ {$regoption.register}</option>{/foreach}</select> <input type="submit" value="{$LANG.ordernowbutton} »" class="btn btn-danger" /></div> {/if} {if $result.status eq "unavailable"} <div style="width: 400px; color: #cc0000; font-size:14px;"><img src="/templates/dj/no.jpg" style="float:left" />{$tld}<br />Taken</div> <div style="width: 100px;" >{$domain}<p style="color: #cc0000;">{$tld}</p></div> <div style="width: 200px;" ><a href="http://{$result.domain}" target="_blank">WWW</a> <a href="#" onclick="popupWindow('whois.php?domain={$result.domain}','whois',650,420);return false">WHOIS</a></div> {/if} {/foreach}</form>The original code works fine and add to my cart, the new "updated" version fails... What have I done wrong? I have no idea if this is possible or not, but I've got a form that searches a DB for a record. If that record is found, it displays a form that people can edit the record. Now, if that person wants to change (for example) 1 record out of 16 called "status" from "lost" to "found" but leave all the rest as they are, how would I go about this? Basically, I need to check all the fields ON SUBMIT if they're different from the original values in the DB and only update if they are. Any help would be appreciated. Cheers, Dave After switching from PHP 5.3 on Windows Server 2003 to PHP 7.4.3 on Linux Mint 19.3 (Tricia Cinnamon), I find that the output of print_r() has changed. If we look at the documentation (https://www.php.net/manual/en/function.print-r.php), the provided example output is as it was on my earlier machine: <pre> Array ( [a] => apple [b] => banana [c] => Array ( [0] => x [1] => y [2] => z ) ) </pre> However, on the second machine, the output is: <pre> Array ( [a] => apple [b] => banana [c] => Array ( [0] => x [1] => y [2] => z ) <blank line> ) </pre> Note the unexpected new line after each recursed array's closing parenthesis. The new line is not present after the outermost array closing parenthesis. Also to note, there is a newer version of XDebug installed. My question is: Is this a bug? (Follow-on question: if possible to determine at which version the output changed, what version would that be?) This difference is causing existing code to not be able to correctly parse that output. OK I'm 98% new to PHP. I'm trying to do my own website and my idea will work something like this: index.php ____________________ Header + Nav {PHP INCLUDE} Footer ____________________ The content will reside in another *.php page If you look at www.avlscotland.com/test 'temporary' It loads default.php when you go to the page which is perfect. I have it working in basic form although only the hyperlinks HOME - ABOUT AVL - DEAD LINK are active at this moment. So it works this way with everything in the same directory, but I want it to load the content from a subdirectory /test/pages/content.php This is the PHP code I am using <?php // Check if page has been requested if (!isset($_GET['content'])) { // Page has not been requested, show default page $content = 'default.php'; } else { // Page has been requested, validate page exists, show page $content = $_GET['content'].'.php'; } // End if page has been requested // Check to see if page exists if (file_exists($content)) { // Page exists // Show page include("$content"); } else { // Page doesn't exist echo '<br>'; echo '<br>'; echo '<br>'; echo 'Sorry, the page that you are trying to access does not exist.<br>'; echo 'Please return to <a href="http://www.avlscotland.com/test/index.php">AVL Scotland</a><br>'; echo '<br>'; echo 'Thank you.<br>'; } // End if page exists ?> I'm accessing the pages using links like <a class="menuactive" href="test/index.php?content=avl">Home</a> What I'm struggling to do is make the PHP look for the content files in a sub-directory. Look forward to any help you can offer. Thanks, Ross I have 3 set of pages. The first html page only contains a search textbox and a submit button which then call up the second page search.php which populate html table with search result. The third page is update.php which allows to update the records populated by search.php. The problem is that it when it update the records it automatically updates all rows in the table making all records look the same. I do not know where I have made a mistake please help. When I use phpadmin to update the records no problem as I can specifically input the cf_id number directly. Search.php code Code: [Select] <?php if(isset($_POST['submit'])){ if(isset($_GET['go'])){ if(preg_match("^/[A-Za-z]+/", $_POST['name'])){ $name=$_POST['name']; } } else{ echo "<p>Please enter a search query</p>"; } } //connect to the database $con = mysql_connect("localhost","dbusrn","dbpwd"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydb", $con); $name = $_POST['name']; $result = mysql_query ("select * from Customer_Registration where Firstname like '%$name%' or lastname like '%$name%' "); $row = mysql_fetch_row($result); $cf_uid = $row[0]; $Firstname = $row[6]; $lastname = $row[7]; $Address = $row[8]; $Postcode = $row[9]; $Phone = $row[10]; $Email = $row[11]; $Customer_Type = $row[12]; $Computer_type = $row[13]; $Computer_maker = $row[14]; $Model = $row[15]; $OS = $row[16]; $Appointment_date = $row[17]; $Problem = $row[18]; $Solution = $row[19]; $Comment = $row[20]; ?> <form action="updatecus.php" method="post"> <table width="100%" border="2" cellspacing="0" cellpadding="8"> <tr><td width="45%" class="FormText">Customer ID:</td> <td width="55%"><?php echo $row[0];?></td></tr> <tr><td width="45%" class="FormText">First name:</td> <td width="55%"><input name="Firstname" type="text" value="<?php echo $Firstname;?>"?> </td></tr> <tr><td width="45%" class="FormText">Last name:</td> <td width="55%"><input name="lastname" type="text" value="<?php echo $lastname;?>"?> </td></tr> <tr><td width="45%" class="FormText">Address:</td> <td width="55%"><input name="Address" type="text" value="<?php echo $Address; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Postcode:</td> <td width="55%"><input name="Postcode" type="text" value="<?php echo $Postcode; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Phone:</td> <td width="55%"><input name="Phone" type="text" value="<?php echo $Phone; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Email:</td> <td width="55%"><input name="Email" type="text" value="<?php echo $Email; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Customer:</td> <td width="55%"><input name="Customer_Type" type="text" value="<?php echo $Customer_Type; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Computer :</td> <td width="55%"><input name="Computer_type" type="text" value="<?php echo $Computer_type; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Manufactural:</td> <td width="55%"><input name="Computer_maker" type="text" value="<?php echo $Computer_maker; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Model:</td> <td width="55%"><input name="Model" type="text" value="<?php echo $Model; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Operating System:</td> <td width="55%"><input name="OS" type="text" value="<?php echo $OS; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Appointment:</td> <td width="55%"><input name="Appointment_date" type="text" value="<?php echo $Appointment_date; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Problem:</td> <td width="55%"><textarea name="Problem" rows="10" cols="20" ><?php echo $Problem; ?></textarea></td></tr> <tr><td width="45%" class="FormText">Solution:</td> <td width="55%"><textarea name="Solution" rows="10" cols="20" ><?php echo $Solution; ?></textarea></td></tr> <tr><td width="45%" class="FormText">Comment:</td> <td width="55%"><textarea name="Comment" rows="10" cols="20" ><?php echo $Comment; ?></textarea></td></tr> <td width="55%"><input name="submit" value="submit" type="submit" <br> <input type="Submit" value="Cancel"</br></td> </form> <?php ?> update.php code Code: [Select] <?php //connect to the database $con = mysql_connect("localhost","dbusrn","dbpwd"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydb", $con); //if (isset($_POST['submit'])) { $cf_id = $_POST['cf_id']; $Firstname = $_POST['Firstname']; $lastname = $_POST['lastname']; $Address = $_POST['Address']; $Postcode = $_POST['Postcode']; $Phone = $_POST['Phone']; $Email = $_POST['Email']; $Customer_Type = $_POST['Customer_Type']; $Computer_type = $_POST['Computer_type']; $Computer_maker = $_POST['Computer_maker']; $Model = $_POST['Model']; $OS = $_POST['OS']; $Appointment_date = $_POST['Appointment_date']; $Problem = $_POST['Problem']; $Solution = $_POST['Solution']; $Comment = $_POST['Comment']; if (isset($_POST['submit'])) { $query ="UPDATE Customer_Registration SET Firstname='$Firstname',lastname='$lastname',Address='$Address',Postcode='$Postcode',Phone='$Phone',Email='$Email',Customer_Type='$Customer_Type',Computer_type='$Computer_type',Computer_maker='$Computer_maker',Model='$Model',OS='$OS', Appointment_date='$Appointment_date',Problem='$Problem',Solution='$Solution',Comment='$Comment' WHERE cf_id=cf_id"or die (mysql_error()); echo $query; mysql_query($query) or die(mysql_error()); //mysql_close($con); echo "<p>Congrats Record Updated</p>"; } ?> Thank you in advance for your help I'm trying to get some code to work that will update a field to show a checkbox either checked or not checked.
The field either uses a Y or N. Y is checked, N not checked. A code that I have tried displays the correct result for the box either checked or not checked.
input type="checkbox" name="obcDisplay" value="Y" <?=($r['obcDisplay'] == 'Y') ? 'checked="checked"' : ''; ?>/>But I want the ability to change when the form is submitted. so if I bring up a page and the checkbox is checked (Y) and I submint, I want the database to update to N and the other way around. Hey all, I would like to know the best way to determine whether a value has been changed in a multi select transfer. For example, I have two select fields. User clicks on button to add an item to the right select element with id of select2 from the left select element with an id of select1. When they click update, it posts to a php method. This is where I am uncertain what to do. How can I check that they indeed added or removed items from the right select element and if they did, determine which ones were removed or added to make the reflected changes in the database? This is what I have, but it's bad solution because it deletes all related records before it adds the ones it finds to the right select element: Code: [Select] public function update(){ $subcategory = new Category(); $subcategory->where('id',$this->uri->segment(4))->get(); $subcategory->delete($subcategory->related_category->get()->all); $new_parents = $this->input->post('catupload'); $parent_category = new Category(); $parent_category->where_in('controller',$new_parents)->get(); $subcategory->save($parent_category->all); } This is what the form elements look like: Code: [Select] echo "You can add or remove one or many parents associated with this category:"; echo "<div class='multiselect-transfer'>"; echo form_multiselect('catadd[]',$other_cats,'','id="select1"'); echo anchor('#','add >>','id="add"'); echo "</div>"; echo "<div class='multiselect-transfer'>"; echo form_multiselect('catupload[]',$default_cats,'','id="select2"'); echo anchor('#','<< remove','id="remove"'); echo "</div>"; echo form_submit('submit','Update'); echo form_close(); $other_cats variable holds array of categories that have not been asssociated with the current category being updated when this category was first created. The $default_cats variable holds an array of categories that have been associated with the current category being updated when this category was first created. And the javascript: Code: [Select] $().ready(function() { $('#add').click(function() { return !$('#select1 option:selected').remove().appendTo('#select2'); }); $('#remove').click(function() { return !$('#select2 option:selected').remove().appendTo('#select1'); }); }); Thanks for response. Hello, I'm using curl to grab a new solar image once an hour or so from the Solar Dynamics Observatory (example below). I'm trying to archive new images and am struggling with that. If I download an image, the filetime() function returns the current time since I downloaded it and wrote it to a fresh file. The result is that the file is always "new", even if the image hasn't changed on the SDO website. Do you have an idea on how to check the last modified time of a file through curl or other means so that I'm not downloading duplicate images? Thanks a ton! //fetch image $ch = curl_init("http://www.somewebsite.com/theimage.jpg"); curl_setopt($ch,CURLOPT_FOLLOWLOCATION,1); $file = "../images/latest/theimage.jpg"; $fp = fopen($file, "w"); curl_setopt($ch, CURLOPT_FILE, $fp); curl_setopt($ch, CURLOPT_HEADER, 0); curl_exec($ch); curl_close($ch); fclose($fp); //this part is no good... //get last modified date if (file_exists($file)) { $filetime = filemtime($file); } Hi all,
is it possible to install php version 5.2.3 on windows server 2012R2 ?
will it work ? are they any security issues ?
Best regards,
Amit menasahe
HI, I've upgraded from PHP version 5.2 to PHP version 5.4 and are not able to load / find mssql extension ? How do I use MSSQL in version 5.4 ?? Is MSSQL not supported in this version or am I (hopingly) missing something ??? Regards Dieter This may sound like a really stupid question, but this is really bugging me.
If i code something in PHP 5.5.11 and upload it to a server that is running PHP 5.4, would the code work correctly? I didnt think there was a super amount of difference between the two versions. Perhaps im wrong.
The reason i asked is because someone has given me a project to help them with. Im running php 5.5.11. I coded it, tested in in xampp, working great. I upload it to his website, which he told me is currently running 5.4 (i tried phpinfo() but they have disabled it) and a majority of the functions i coded are no longer working. Things are not writing to the database, things collected from the database either dont show up on the website or they only show up when something gets posted after it, in which case the something posted after it doesnt show e.c.t.
Is the difference that much it can break code?
Thanks!
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