PHP - Delete With Join

I'm trying to set it so that it will delete an entire populated directory based upon a value in the database then after finishing that to go back and delete that row in the database.  my current code is

Code: [Select]
<?php $page_title = "Central Valley LLC | Photo Addition" ?>
<?php include("header.php"); ?>
<?php include("nav.html"); ?>
<div id="content">
<form action="delprod.php" method="post" enctype="multipart/form-data">
<label for="which">Choose A Product To Remove:</label>
<?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("phoenixi_cvproducts", $con);
$result = mysql_query("SELECT * FROM Products");
echo "<select name=\"which\">";
while($row = mysql_fetch_array($result))
   {
echo "<option ";
echo "value=\"" . $row['id'] . "\">";
echo $row['Name'] . "</option>";
}
echo "</select>";
mysql_close($con);
?>
<br />
<input type="submit" name="submit" value="Submit" />
</form>
</div><!--#content-->
<?php include("footer.html") ?>

and the delete script

Code: [Select]
<?php
$con = mysql_connect("localhost","phoenixi_cv","centraladmin");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("phoenixi_cvproducts", $con);
$result = mysql_query("SELECT id FROM Products WHERE id=$_POST['which']");
$row = mysql_fetch_array($result)


chdir('assets');
chdir('images');
$mydir = $row . '/';
$d = dir($mydir);
while($entry = $d->read())
{
if($entry!="." && $entry!="..")
{
unlink($_POST['which'] . '/' . $entry);
}
}
rmdir($mydir);
$result = mysql_query("DELETE * FROM Producs WHERE id=$_POST['which']");
?>
Thank you in advance for all your help.  any easier ways of approaching this will be welcome as well

Hi

I want to know I can select which ID I get from an inner join?

Not sure If I should post here or in the MYSQL forum, but as it's using OOP I posted here.


Code: [Select]
$sql = "SELECT * FROM area_county INNER JOIN area_country ";
$sql .= "ON area_county.country_id = area_country.id ";
$sql .= "ORDER BY area_country.country, area_county.county ASC ";
$sql .= "LIMIT {$per_page} ";
$sql .= "OFFSET {$pagination->offset()}";
$list = Area_county::find_by_sql($sql);

foreach($list as $lists){
$ID = $lists->id;
$country_id = $lists->country_id;
$county = ucwords($lists->county);
        $country = ucwords($lists->country);

echo $ID;
}


I want it to show the ID of the county, NOT the id of the country.
both tables in the database have the ID column called id.

I know this can be done, but not to sure how.


Thanks

First off Please bear with me. I am newbie.

Here is a table name 'Employes' and has following Columns.
ID(PK) | FirstName | LastName | SecurityLicence | CrowdLicence | DriversLicence | Password |

And through form all the values are assigned to these columns and user gets registered.
I have done it using this code and its working fine.
Code: [Select]
<?php
session_name('YourVisitID');
session_start();
if(!isset($_SESSION['FirstName']))
        {
                header("Location: http://" . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . "/index.php");
                exit();
        }
else
{
$page_title = 'Register';
include('templates/header.inc');
if(isset($_POST['submit']))
{
        require_once('mysql_connect.php');
        // connect to the db
        
        //Create a function for escaping the data.
        function escape_data($data)
        {
                global $con; // need connection
                if(ini_get('magic_quotes_gpc'))
                {
                        $data = stripslashes($data);
                }
                return mysql_real_escape_string($data, $con);
        }
        $message = NULL;
        if(empty($_POST['firstName']))
        {
                $fn = FALSE;
                $message .= '<p>you forgot to enter your first name!</p>';
        }
        else
        {
                $fn = escape_data($_POST['firstName']);
        }
        
        if(empty($_POST['lastName']))
        {
                $ln = FALSE;
                $message .= '<p>You forgot to enter your last name!</p>';
        }
        else
        {
                $ln = escape_data($_POST['lastName']);
        }
        if(empty($_POST['licenceId']))
        {
                $li = FALSE;
                $message .='<p>You Forgot enter your Security Officer Licence Number!</p>';
        }
        else
        {
                $li = escape_data($_POST['licenceId']);
        }
        if(empty($_POST['crowdLicenceNo']))
        {
                $cln = FALSE;
                $message .='<p>You Forgot to enter your Crowd Controller Licence Number!</p>';
        }
        else
        {
                $cln = escape_data($_POST['crowdLicenceNo']);
        }
        if(empty($_POST['driverLicenceNo']))
        {
                $dln = FALSE;
                $message .='<p>You forgot to enter your Driving Licence Number!</p>';
        }
        else
        {
                $dln = escape_data($_POST['driverLicenceNo']);
        }
        if(empty($_POST['password']))
        {
                $p = FALSE;
                $message .='<p>You forgot to enter your password!</p>';
        }
        else
        {
                        if($_POST['password'] == $_POST['password2'])
                                {
                                        $p = escape_data($_POST['password']);
                                }
                        else
                                {
                                        $p = FALSE;
                                        $message .='<p>Your password did not match the confirmed password</p>';
                                }
        }
        if($fn && $ln && $li && $cln && $dln && $p)
        {
                                
                $query = "SELECT ID FROM Employes WHERE SecurityLicence='$li'";
                $result = @mysql_query($query);
                if(mysql_num_rows($result) == 0)
                { 
                
                
                $query = "INSERT INTO Employes (FirstName, LastName, SecurityLicence, CrowdLicence, Driverslicence, Password)
                VALUES ('$fn', '$ln', '$li', '$cln', '$dln', PASSWORD('$p'))";
                $result = @mysql_query($query);
                        if($result)
                                {
                                        echo '<p>You have been registered</p>';
                
                                }
                        else
                        {
                                $message = '<p>We apologise there is a system error.</p><p>' . mysql_error(). '</p>';
                        }
                } 
                else 
                {
                        $message = '<p>That Security Licence is already registered</p>';
                }
                        mysql_close();
        }
        else
        {
                $message .='<p>Please try again</p>';
        }
}

//print the message if there is one
if (isset($message))
{
        echo '<font color="red">', $message, '</font>';
}
}
?>
<script type="text/javascript">
function validate_form()
{
        var f = document.forms["regForm"]["firstName"].value;
                if(f==null || f=="")
                        {
                                alert("First Name must be filled out");
                                return false;
                        }
        var l = document.forms["regForm"]["lastName"].value;
                if(l==null || l=="")
                        {
                                alert("Last Name must be filled out");
                                return false;
                        }
        var sl = document.forms["regForm"]["licenceId"].value;
        var s = /^\d{5,}$/g.test(sl);
        var sll = sl.length;
                if(s==false)
                        {
                                alert("Security Licence No must be filled out in digits");
                                return false;
                        }
                else if(sll>=7)
                        {
                                alert("Invalid Security Licence No");
                                return false;
                        }
        var csl = document.forms["regForm"]["crowdLicenceNo"].value;
        var k = /^\d{5,}$/g.test(csl);
        var csll = csl.length;
                if(k==false)
                        {
                                alert("Crowd Controller Licence No must be filled out in digits");
                                return false;
                        }
                else if(csll>=7)
                        {
                                alert("Invalid Crowd Controller Licence No");
                                return false;
                        }
        var d = document.forms["regForm"]["driverLicenceNo"].value;
        var v = /^\d{6,}$/g.test(d);
        var dl = d.length;
                if(v==false)
                        {
                                alert("Driver's Licence No must be filled out in digits");
                                return false;
                        }
                else if(dl>=11)
                        {
                                alert("Invalid Driver's Licence No");
                                return false;
                        }
       
}
</script>


<h3>Employment Registration Form</h3>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" name="regForm" method="post" onsubmit="return validate_form()">
<fieldset>
<legend>Enter informations in the form below</legend>
<table>
<tr><th>First Name:</th><td><input type="text" name="firstName" /></td></tr>
<tr><th>Last Name:</th><td><input type="text" name="lastName" /></td></tr>
<tr><th>SO Licence No:</th><td><input type="text" name="licenceId" size="5" /></td></tr>
<tr><th>CC Licence No:</th><td><input type="text" name="crowdLicenceNo" size="5" /></td></tr>
<tr><th>Driver's Licence No:</th><td><input type="text" name="driverLicenceNo" size="10" /></td></tr>
<tr><th>Create Password:</th><td><input type="password" name="password" size="10" /></td></tr>
<tr><th>Confirm Password:</th><td><input type="password" name="password2" size="10" /></td></tr>
</table>
<input type="submit" name="submit" value="Register" />
<input type="reset" value="Reset" />
</fieldset>   
</form>

<?php
include('templates/footer.inc'); 
?>
 

Here is another Table "Jobs", with the following columns.
JobID(PK) | ID(FK) | JobDate | JobStart | JobFinish | JobLocation | RequestedBy |

For Example I am the owner of the company and want to assign jobs to my registerd workers using a form.
I assign JobDate=12/12/12 JobStart=1900 JobFinish=2300 JobLocation=Perth Requestedby=John. And I do it using form. JobID will be incremented automatically.
Now what i dont understand is how do I assign ID(FK) to it?? I am newbie this question may sound stupid to many of you but hey please help.
Or should I replace ID(FK) with the SecurityLicence of the worker, Like this
JobID(PK) |ToSecurityLicence | JobDate | JobStart | JobFinish | JobLocation | RequestedBy |

What I want is when the workers signs in He should see the job assigned to him. Can I do it using inner join??? if so how to right PHP code for comparing these two tables???
I am way too much confused.

Too many of you I have made a fool of myself asking this question. But I believe a person who doesnt ask the question is fool foreva.

If somebody could Help I would really really aprreciate it.

Thanks.

I'm an amateur PHP/mySQL person, trying to learn some more things, and I've hit a snag trying to do something I haven't done before.

Okay, here's what I'm trying to do. I have 3 tables:

Items (which includes `id` as the primary key) and a TON of information about each item.
Shop (which includes `id` as the primary key) and shop name and location.
Sale which has shop_id and item_id.

So, what I'm trying to do is have a form where someone can input in an item name and a shop name and have that item then added to the shop. This is where the Sale table comes into play too, as that's going to house each of the items and what shop it's in.

I currently have the following queries:


       $query5 = $db->execute("SELECT id FROM items LEFT JOIN sale ON items.id=sale.item_id");
       $query6 = $db->execute("SELECT id FROM shop LEFT JOIN sale ON shop.id=sale.shop_id");


I have the following form:


        if ($name == "") { $errors++; $errorlist .= "Name is required.<br />"; }
        if ($location == "" ) { $errors++; $errorlist .= "Location is required.<br />"; }
if (!isitem($itemname)) die("That item does not exist."); }

        if ($errors == 0) { 
            $query = doquery("INSERT INTO `sale` SET `item_id`=`$item`");
            admindisplay("New Item Added.","Add Items");

$page = <<<END

<b><u>Add Item</u></b><br /><br />
<form action="create_shop.php?do=additem" method="post">
<table width="90%">
<tr><td width="20%">Name:</td><td><input type="text" name="itemname" size="30" maxlength="255" value="" />**Be sure the item is already in the database and matches it IDENTICALLY.</td></tr>
<tr><td width="20%">Location:</td><td><input type="text" name="location" size="30" maxlength="55" value="" /><br /><span class="small">Where is the item obtained (unique shop name, please!)</span></td></tr>
</table>
<input type="submit" name="submit" value="Submit" /> <input type="reset" name="reset" value="Reset" />
</form>


What next steps do I need to take? Am I even on the right path?

Thanks for any and all help anyone provides!! I really appreciate it!

Im currently working on a new feature called 'Request Player'. Basically what this does is allows managers to request players within their club for a upcoming fixture. There a multiple teams within a club (Senior As, Senior Bs, Colts U21s). Each team is controlled by a manager. And then they can add players as they need.

Anyway, I'm having problems with the sql JOIN.

I have currently got this:

$check = "SELECT u.* FROM users AS u LEFT JOIN requests AS r ON (u.id = r.player_id) WHERE (u.id = r.player_id)";


I have got two tables.

users - all the managers and players.
requests - all the requests the managers make to other teams within their club.

In the request table i have got this:

id
player_id - the players that has been requested.
fixture_id - the fixture the manager wants to have that player for.
accepted - if he has been accepted or not. This comes later on.

At the moment i have got it working so that it inserts this data, although the code is working but i want to have a mysql query that checks if a manager has any incoming requests from other teams within the club. BUT only request that has been made to his team....

Could someone please help me out?

I'm trying to figure out the best way to do this if I'm doing it right with my for loop. With how many numAnswers there are for the selected poll its going to put the div with the label and text box for each of those but its giong to go and tie in each of those pollAnswers with what ID of the pollAnswer to the pollAnswer table.


Code: [Select]
$pollsQuery = "
    SELECT
        polls.question,
        polls.statusID,
        polls.numAnswers,
        DATE_FORMAT(polls.dateExpires, '%m/%d/%Y') AS dateExpires
    FROM
        polls
    WHERE
        polls.ID = '" . $pollID . "'";
$pollsResult = mysqli_query ( $dbc, $pollsQuery ); // Run The Query
$row = mysqli_fetch_array ( $pollsResult, MYSQL_ASSOC );

$pollAnswers = "
    SELECT
        pollAnswers.ID,
        pollAnswers.answer
    FROM
        pollAnswers
    WHERE
        pollAnswers.pollID = '" . $pollID . "'";
$pollAnswersResult = mysqli_query ( $dbc, $pollAnswers ); // Run The Query

Code: [Select]
<fieldset class="answerLeg">
        <legend>Edit Poll Answers</legend>
        <?php for ( $j = 0; $j <= $numAnswers; $j++) { ?>
            <div class="field required answers">
                <label for="answer<?php $j?>">Answer <?php $j?></label><input type="text" class="text" name="answer<?php $j?>" id="answer<?php $j?>" title="Answer <?php $j?>"/>
                <span class="required-icon tooltip" title="Required field - This field is required, it cannot be blank, and must contain something that is different from emptyness in order to be filled in. ">Required</span>     
            </div>
        <?php } ?>
    </fieldset>

Not sure if it is because it is too early in the morning but I am having a problem.

Code: [Select]
$mpid = #

$query = "SELECT table1.title, table2.* ".
 "FROM table1, table2 ".
"WHERE table1.mpid = table2.mpid";

How do I only show the info from the 2 tables where mpid=#

Hello everyone,   I am hopping someone can help me sort out a query.   I have two tables, one table is a players table, and a second table is a player_vitals data that stores heights and weight changes.  I want to list all the players showing the latest height and weight change.   this query will not fetch the latest height and weight   SELECT a.player_id, a.player_first_name,a.player_last_name, b.player_height, b.player_weight

I'm trying to pull from my database every spell or attack that is equal to `All`, but it doesn't seem to be working. All it is doing is pulling all the spells, regardless of class = `All`, and also 0 of the attacks. It should be producing a single attack that is = to `All` as no spells are = `All`.

Any help would be greatly appreciated! Thanks! (This is my first attempt at a JOIN statement...)


$query = "SELECT attacks.id, attacks.name, attacks.price, attacks.class, attacks.descript, spells.id, spells.name, spells.price, spells.class, spells.descript ".
"FROM attacks, spells ".
"WHERE attacks.class = 'All' || spells.class = 'All' order by attacks.name, spells.name asc";

When I have more than one table i don't know how to echo out a field if it is the same in both fields.  here's my code and I want to echo out the id from the people table:


$query =  "SELECT * FROM people INNER JOIN ratings ON people.id = ratings.rater_id AND ratings.event_id = '$eventid' AND ratings.complete = 'n' "; 

$result = mysql_query($query);
while ($row=mysql_fetch_assoc($result)){
echo $row['people.id'];
}


I tried  $row['people.id'] but it was blank. 

Hi guys,

Would like to check if I have done my INNER JOIN function correctly, as I have received and an error msg

Warning: mysqli_error() expects exactly 1 parameter, 0 given in D:\inetpub\vhosts\111.com\httpdocs\111.com\registration3.php on line 598.

Thanks


<?php
   $dbc = mysqli_connect('localhost', '111', '111', '111')
   or die(mysqli_error());
   $query = "SELECT sl.subject_level_id, sl.level_id, sl.subject_id, tl.name AS level_name, ts.name AS subject_name " .
    "FROM tutor_subject_level AS sl " .
    "INNER JOIN tutor_level AS tl USING (level_id) " .
    "INNER JOIN tutor_subject AS ts USING (subject_id) ";
   $sql = mysqli_query($dbc, $query);
   
   echo'<table><tr>'; // Start your table outside the loop... and your first row
   $count = 0; // Start your counter
      while($data = mysqli_fetch_array($sql)) {
         /*    Check to see whether or not this is a *new* row
            If it is, then end the previous and start the next and restart the counter.
         */
         if ($count % 5 == 0) {
            echo "</tr><tr>"; $count = 0;
         }
         echo '<td><input name="subject_level[]" type="checkbox" id="'.$data['subject_level_id'].'" value="'.$data['subject_level_id'].'"/>';
         echo '<label for="'.$data['subject_name'].'">'.$data['subject_name'].'</label></td>';
         $count++; //Increment the count
      }
   echo '</tr></table><br/><br/>'; //Close your last row and your table, outside the loop
   
?>


Wilson

Hello:

I am writing this code:
Code: [Select]
<?php

include('include/myConn.php');
include('include/myCodeLib.php');

$zip_id = $_REQUEST['zip_id'];

$query=mysql_query("SELECT zip_id,city,full_state,zip FROM zip_codes WHERE zip_id = $zip_id") or die("Could not get data from db: ".mysql_error());

while($result=mysql_fetch_array($query))
{
  $zip_id=$result['zip_id'];
  $city=$result['city'];
  $full_state=$result['full_state'];
  $zip=$result['zip'];
}

?>

<!DOCTYPE HTML>

<head>

<title></title>

</head>

<body>

<?php echo $city; ?>, <?php echo $full_state; ?> <?php echo $zip; ?>

</body>

</html>


It works fine as far as writing out the "City, State Zipcode", but I wanted to see if there is a way to "join" the 3 statements together so it can be written as just 1 statement. Like:
Code: [Select]
<?php echo $city, $full_state $zip; ?>

What is the trick to doing this?

Thanks in advance.

Hi guys,   I’m really hoping someone can help with this query. I'm sure it must use join somehow but i cant work out exactly how to do it.   I have two tables (‘booking_slots’ and ‘booking_reservation’). ‘booking_slots’ has ‘slot_date’ and ‘slot_id’ fields. ‘booking_reservation’ has a number of fields including ‘slot_id’ but not ‘slot_date’.   I want to run a query to delete all records between a certain date range in BOTH tables (say for example 01 Jan 2012 to 01 Jan 2013). To do this I want to find and delete all records using ‘slot_date’ in ‘booking_slots’ and use the corresponding ‘slot_id’ of the deleted records to delete the records with the same ‘slot_id’ in ‘booking_reservation’.   Any help with this would be very greatly appreciated.   Thanks

Hello, I'm trying to get a join with 2 tables but cannot get it to work. It's a contentsystem with an ID for the author. Another table tells the name of the author. Now I want to join these things. This is what i've coded so far:

<?
$query = "SELECT rmnl_content.content_aid, COUNT(rmnl_content.content_id), rmnl_crew.crew_id, rmnl_crew.crew_name

FROM rmnl_content, rmnl_crew" "where rmnl_content.content_aid = rmnl_crew.crew_id";
   
$result = mysql_query($query) or die(mysql_error());

// Print out result
while($row = mysql_fetch_array($result)){
   echo " <b>". $row['COUNT(rmnl_content.content_id)'] ."</b> posted messages by ". $row

['crew_rmnl.crew_name'] ."</td> .";
   echo "<br />";
}
?>

I need to get the friends password and insert it into the table so the friend can delete it later can some one help me do a table join
<?php
//include the connect script
include "../../../../connect.php";

//Post variables from flash
$username = $_POST['username'];
$password = $_POST['password'];
$status = $_POST['status'];
$friend = $_POST['friend'];

$username = stripslashes($username);
$password = stripslashes($password);
$status = stripslashes($status);
$friend = stripslashes($friend);
$username = mysql_real_escape_string($username);
$password = mysql_real_escape_string($password);
$status = mysql_real_escape_string($status);
$friend = mysql_real_escape_string($friend);

$sql = mysql_query("SELECT * FROM user_declined_list  WHERE username = '$username' and password = '$password' and friend = '$friend' and status ='$status'");
$rows = mysql_num_rows($sql);
$your_username=$rows['username'];



if($rows > 0)
{
echo "&msgTextFriendShipRejected= RESEND NEW FRIEND REQUEST SUCCESSFULLY!";

// ok they are now our friend but we are not thier friend so lets insert the friendship in reverse and set the status to 1 on both ends
// Problem i see is this if the user wishs to remove the friend later he will neen his password set to delete from this table.
// so i need to do a join table again where friend password gets inserted here..
$insertnewfriend = mysql_query("INSERT INTO user_friends_list (username,password,friend,status) VALUES ('$friend','$password','$username','0')") or die(mysql_error());
//ok lets update the request and set the friend to be a friend becuase we said yes be my friend.
$deleteuserfriend = mysql_query("DELETE FROM user_declined_list  WHERE username = '$username' and password = '$password' and friend = '$friend' and status ='0'");
return;
}


?>