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PHP - Dependable Dropdownlist Php/mysql/ajax
Hi all,
I'm trying to code a dependable dropdownlist with php/mysql/ajax.
Goal is to select one thing in the first dropdown and depending on that option (and without reloading the page) enabling the second and add the options to the second, dependant on the first.
This is the index :
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/dbconnect.php');
?>
<script type="text/javascript" src="http://ajax.googleapis.com/
ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$(".country").change(function()
{
var id=$(this).val();
var dataString = 'id='+id;
$.ajax
({
type: "POST",
url: "edit_form.php",
data: dataString,
cache: false,
success: function(html)
{
$(".city").html(html);
}
});
});
});
</script>
<?php
$id_test=$_POST['selector'];
$N = count($id_test);
for($i=0; $i < $N; $i++)
{
$result = mysqli_query($conn, "SELECT * FROM cloud where id='$id_test[$i]'");
while($row = mysqli_fetch_array($result))
{
$id_bird = $row['id'];
?>
<div style="margin:80px">
<label>Country :</label> <select name="country" class="country">
<option selected="selected">--Select Country--</option>
<?php
$sql=mysqli_query($conn, "SELECT category.id AS cat_id, category.name, category.type, cloud.id
FROM cloud,category,link_category_cloud
WHERE link_category_cloud.cloud_id = cloud.id
AND link_category_cloud.category_id = category.id
AND cloud.id='$id_test[$i]'");
while($row=mysqli_fetch_array($sql))
{
$id_test=$row['cat_id'];
$data=$row['name'];
echo '<option value="'.$id_test.'">'.$data.'</option>';
} ?>
</select>
<br/>
<br/>
<label>City :</label> <select name="city" class="city">
<option selected="selected">--Select City--</option>
</select>
</div>
<?php
}
}
?>
And this is the edit_form.php part :
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/dbconnect.php');
$cat_id = $_GET['cat_id'];
$cloud_id = $_GET['id'];
if($_POST['id_test'])
{
$id_test=$_POST['id_test'];
$data=$_POST['data'];
$sql=mysqli_query($conn, "SELECT * FROM link_category_cloud WHERE category_id={$cat_id}");
$data=$row['cloud_id'];
$id_test=$_POST['id_test'];
echo '<option value="'.$id_test.'">'.$id_test.' '.$data.'</option>';
//}
}
?>
Now, it does not work. I'm not only tring to pass through ID to 'edit_form.php', but also $data and $id_test[i]. Any idea how I can do this?
Thank you very much, all help is so appreciated!!
Similar TutorialsThis topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=308756.0 Hello fellow programmers I recently bought a chat site without investigating (i know stupid me). this chat is made in Php / Mysql language and ajax, My question is, is there a possibility to convert the mysql to an IRC server. I dont know how to explane it 100% but is it possible to make the webchat thats coded in ajax & mysql work for a IRC server I have knowledge of mysql / php only is this above my level. My problem is that mysql is no option for chats, I need this webchat work with IRC but I have no idea where i should start. Maby someone can kick me in the right direction Thanks for your time & help Greets BTW this is the chatsite more people bought (this aint my site) but 100% the same : http://tinyurl.com/kk4gchd Edited by Remco, 26 November 2014 - 03:32 AM. i was working on a mini project that imports csv file to the database through ajax and it's working fine
<?php
if(!empty($_FILES["marks_file"]["name"]))
{
$connect = mysqli_connect("localhost", "root", "", "dbname");
$output = '';
$allowed_ext = array("csv");
$extension = end(explode(".", $_FILES["marks_file"]["name"]));
if(in_array($extension, $allowed_ext))
{
$file_data = fopen($_FILES["marks_file"]["tmp_name"], 'r');
fgetcsv($file_data);
while($row = fgetcsv($file_data))
{
$name = mysqli_real_escape_string($connect, $row[0]);
$Physics = mysqli_real_escape_string($connect, $row[1]);
$Maths = mysqli_real_escape_string($connect, $row[2]);
$Chemistry = mysqli_real_escape_string($connect, $row[3]);
$Biology = mysqli_real_escape_string($connect, $row[4]);
$SST = mysqli_real_escape_string($connect, $row[5]);
$query = "
INSERT INTO csv
(name, Physics, Maths, Chemistry, Biology, SST)
VALUES ('$name', '$Physics', '$Maths', '$Chemistry', '$Biology' , '$SST')
";
mysqli_query($connect, $query);
}
$select = "SELECT * FROM csv ORDER BY id DESC";
$result = mysqli_query($connect, $select);
$output .= '
<table class="table table-bordered">
<tr>
<th width="25%" >name</th>
<th width="15%" >Physics</th>
<th width="15%" >Maths</th>
<th width="15%" >Chemistry</th>
<th width="15%" >Biology</th>
<th width="15%" >SST</th>
</tr>
';
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td>'.$row["name"].'</td>
<td>'.$row["Physics"].'</td>
<td>'.$row["Maths"].'</td>
<td>'.$row["Chemistry"].'</td>
<td>'.$row["Biology"].'</td>
<td>'.$row["SST"].'</td>
</tr>
';
}
$output .= '</table>';
echo $output;
}
else
{
echo 'errorx';
}
}
else
{
echo "errory";
}
?>
however the imported csv files inserts null values in the tables because the format of all csv files assigned to me are in the exact same format: ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,Fields,Physics~75,Maths~50,Chemistry~65,Bio~85,SST~100 ,,,Name1,10,25,35,42,62 ,,,Name2,80,45,45,45,25 ,,,Name3,63,25,63,36,36 ,,,Name4,82,36,75,48,42 ,,,Name5,45,45,78,25,24 ,,,Name6,36,36,15,75,36 ,,,Name7,99,45,24,24,45 ,,,Name8,45,85,85,85,96 i changed my code a bit modified the functions to espace blank spaces and not return null values in the data tables
while (($row = fgetcsv($file_data, 1000, ",")) !== FALSE)
{
if ((string) $row[0] != '0' and empty($row[0]))
{
continue;
}
$name = mysqli_real_escape_string($connect, $row[0]);
$Physics = mysqli_real_escape_string($connect, $row[1]);
$Maths = mysqli_real_escape_string($connect, $row[2]);
$Chemistry = mysqli_real_escape_string($connect, $row[3]);
$Biology = mysqli_real_escape_string($connect, $row[4]);
$SST = mysqli_real_escape_string($connect, $row[5]);
$query = "
INSERT INTO csv
(name, Physics, Maths, Chemistry, Biology, SST)
VALUES ('$name', '$Physics', '$Maths', '$Chemistry', '$Biology' , '$SST')
";
mysqli_query($connect, $query);
}
But it doesn't work with the specified csv files i think the ajax call breaks and that's why nothing happens.However it works fine with csv files without blank spaces Edited March 19, 2019 by zetastreak Let's say I grab all the user's information from the users table. It's stored into a variable as an array: $pun_user. Now, to get access this user data, it selects all the data each refresh and sets it to $pun_user for extraction later. My idea: Create a $_SESSION['user_id'] = $pun_user['user_id'] And then when using updating stuff via ajax requests, I can just do SELECT blah from users where where user_id = $_SESSION['user_id'] instead of: calling the main query to enter all the data into $pun_user, then do that query AGAIN and do SELECT blah from users where user_id = $pun_user['user_id'] Is the $_SESSION way going to take a performance hit on the server? Or is the MYSQL way a more detrimental approach? Which way is faster, and less intrusive on the server? Edited by Monkuar, 22 January 2015 - 10:35 PM. I wonder whether someone can help me please. I've found http://www.plus2net.com/php_tutorial/ajax-listbox.php tutorial to create a drop down menu using mySQL table data, which, in turn returns a list of results on the page. Following this tutorial I've put together the tables in my database and the required scripts as shown in the tutorial with the one exception, the "z_db.php" file, which I've assumed to be: Code: [Select] <?php mysql_connect("host", "user", "password")or die(mysql_error()); mysql_select_db("database"); ?> The problem I have, is that when I try and run this, I receive the following error: Quote Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /homepages/2/d333603417/htdocs/development/catsearch.php on line 91 which is this line in the search form: echo "</head><body onload="ajaxFunction()";>";. I must admit I've guessed as to the structure of the 'z_db.php' file should look like because this is not shown so perhaps this is the problem. I just wondered wether someone could perhaps take a look at this please and let me know where I've gone wrong. Many thanks and kind regards
//my controller
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use DB;
class homeController extends Controller
{
public function index() {
$employee = DB::table('employee')->orderBy('id','desc')->get();
$department = DB::table('department')->orderBy('id','desc')->get();
return view('index', ['employee' => $employee , 'department' => $department]);
}
}
//my routes
Route::get('index','homeController@index');
//my view using blade temmplating engine
@foreach($employee as $emp)
<div class="employee">
<b>{{ $emp->name }} </b>
<a href="employee/{{ $emp->id }}">
<p class="intro">{{ substr($emp->intro ,0, 50) }}...</p>
</a>
</div>
@endforeach
@foreach($department as $dep)
<div class="department">
<b>{{ $dep->name }} </b>
<a href="department/{{ $dep->id }}">
<p class="desc">{{ substr($dep->description ,0, 100) }}...</p>
</a>
</div>
@endforeach
I want to fetch using ajax, how can i do it, teach/help me This topic has been moved to Beta Test Your Stuff!. http://www.phpfreaks.com/forums/index.php?topic=342258.0 I am having a problem making this work. It adds and deletes but it does it by passing the date directly to the PHP files and refreshing the screen. I want it to do it through the jquery Ajax script. This should work according to what I have read but no mater what I try the jquery script does not work.
<html> <head> <script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.11.0/jquery-ui.min.js"></script> </head> <body> <script type="text/javascript"> $(document).ready(function(){ $('MySignform').submit(function(e) { e.preventDefault(); $.ajax({ type: 'POST', url: $('MySignform').prop('action'), data: $('MySignform').serialize(), success: function() { alert("It worked!"); } }); }); }); </script> <script type="text/javascript"> $(document).ready(function(){ $('DelForm').submit(function(e) { e.preventDefault(); $.ajax({ type: 'POST', url: $('DelForm').prop('action'), data: $('DelForm').serialize(), success: function() { alert("It worked!"); } }); }); }); </script> <br /> <br /> <br /> <center> <form name="MySignform" action="addsigningfee.php" method="post"> <label>Signing fee</label> <input name="signingfee" type="text" id="signingfee"/> <input name="pid" type="hidden" value="7"/> <p></p> <button id="form-submit" type="submit">Save</button> </form> <br /> <div id="result"></div> <br /> <form name="DelForm" action="delsigningfee.php" method="post"> <select name="signingfee"> <?php require_once("connect.php"); foreach ($db->query("SELECT signingfee,id FROM options WHERE signingfee <> '' AND pid = '7'") as $row) { echo "<option value=" . $row['id'] . ">" . $row['signingfee'] . "</option>"; } ?> </select> <p></p> <button type="submit" >Delete</button> </form> </center> </body> </html> Adding and Deleteing mysql date using jquery Ajax I am having a problem making this work. It adds and deletes but it does it by passing the date directly to the PHP files and refreshing the screen. I want it to do it through the jquery Ajax script. This should work according to what I have read but no mater what I try the jquery script does not work. Some help getting me In the right direction would be great. Code: This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=347691.0 Hello everyone, I begin in everything web related but I have been programming for years. I tried to code something simple : small Mysql DB (works fine) and to begin a search bar to browse data. I adapted a code that I understood provided here : https://www.cloudways.com/blog/live-search-php-mysql-ajax/. Base principle is simple : as you type in your query, it will pass the text to script.js that will forward this request to ajax.php file. In the ajax.php, a javascript function named “fill()” will pass the fetched results. This function will also display the result(s) into “display” div in the “search.php” file. The problem is that when I type anything it displays, below the search bar, at the moment I type a character: Quote
'; //Fetching result from database. while ($Result = MySQLi_fetch_array($ExecQuery)) { ?> ")'>
instead of the actual answer from my database (no error in the browser console). I tested the SQL query + the user I provide and everything seems fine. Any clue what could be the root cause ? I strongly suspect a mistake in the code as I already corrected one (script.js instead of scripts.js) but I really cannot figure out where. Thanks in advance,
problematic code (ajax.php):
<?php
//Including Database configuration file.
include "db.php";
//Getting value of "search" variable from "script.js".
if (isset($_POST['search'])) {
//Search box value assigning to $Name variable.
$Name = $_POST['search'];
//Search query.
$Query = "SELECT Name FROM search WHERE Name LIKE '%$Name%' LIMIT 5";
//Query execution
$ExecQuery = MySQLi_query($con, $Query);
//Creating unordered list to display result.
echo '
<ul>
';
//Fetching result from database.
while ($Result = MySQLi_fetch_array($ExecQuery)) {
?>
<!-- Creating unordered list items.
Calling javascript function named as "fill" found in "script.js" file.
By passing fetched result as parameter. -->
<li onclick='fill("<?php echo $Result['Name']; ?>")'>
<a>
<!-- Assigning searched result in "Search box" in "search.php" file. -->
<?php echo $Result['Name']; ?>
</li></a>
<!-- Below php code is just for closing parenthesis. Don't be confused. -->
<?php
}}
?>
</ul>
I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though. My code for the select form including AJAX code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>AJAX Example</title> <link rel="stylesheet" type="text/css" href="Form.css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("tr:odd").addClass("odd"); }); </script> <script type="text/javascript"> function showPlayers(str) { var xmlhttp; if (str=="") { document.getElementById("DataDisplay").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); else {// code for IE6, IE5 } xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","Query.php?category_id="+str,true); xmlhttp.send(); } </script> </head> <body> <h1">AJAX Example</h1> <?php #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "You did not successfully connect to the DB!" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Error connecting to the database test!"); ?> <form name="sports" id="sports"> <legend>Select a Sport</legend> <select name="category_id" onChange="showPlayers(this.value)"> <option value="">Select a Sport:</option> <?php $sql = "SELECT category_id, sport FROM sports ". "ORDER BY sport"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n "; } ?> </select> </form> <br /> <div id="DataDisplay"></div> </body> </html> Query.php <?php #get the id $id=$_GET["category_id"]; #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "Error connecting to MySQL" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Could not select that particular Database"); #$id="category_id"; #create the query $sql ="SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '".$id."'"; echo $sql; #execute the query $rs = mysql_query($sql,$conn); #start the table code echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>"; #write the data while( $row = mysql_fetch_array( $rs) ) { echo ("<tr><td>"); echo ($row["category_id"] ); echo ("</td>"); echo ("<td>"); echo ($row["sport"]); echo ("</td>"); echo ("<td>"); echo ($row["first_name"]); echo ("</td>"); echo ("<td>"); echo ($row["last_name"]); echo ("</td></tr>"); } echo "</tr></table>"; mysql_close($conn); ?> I think the problem is either with this part in the AJAX Code: [Select] xmlhttp.open("GET","Query.php?category_id="+str,true); or most likely in my Query.php code when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work. When I echo out the SQL the result is Code: [Select] SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '' so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN. All I am trying to do is add a record on a page without the page refreshing. For that ajax is used. Here is the code.
It does not add the record to mysql table. Can anyone tell me what I am doing wrong?
record.php
<!DOCTYPE HTML>
<html lang="en">
<head>
<script type="text/javascript" src="js/jquery-1.11.0.min.js"></script>
<script type="text/javascript" >
$(function() {
$(".submit_button").click(function() {
var textcontent = $("#content").val();
var name = $("#name").val();
var dataString = 'content='+ textcontent + '&name='+name;
if(textcontent=='')
{
alert("Enter some text..");
$("#content").focus();
}
else
{
$("#flash").show();
$("#flash").fadeIn(400).html('<span class="load">Loading..</span>');
$.ajax({
type: "POST",
url: "action.php",
data: dataString,
cache: true,
success: function(html){
$("#show").after(html);
document.getElementById('content').value='';
$("#flash").hide();
$("#content").focus();
}
});
}
return false;
});
});
</script>
</head>
<body>
<?php
$record_id = $_GET['id']; // getting ID of current page record
?>
<form action="" method="post" enctype="multipart/form-data">
<div class="field">
<label for="title">Name *</label>
<input type="text" name="name" id="name" value="" maxlength="20" placeholder="Your name">
</div>
<div class="field">
<label for="content">content *</label>
<textarea id="content" name="content" maxlength="500" placeholder="Details..."></textarea>
</div>
<input type="submit" name="submit" value="submit" class="submit_button">
</form>
<div id="flash"></div>
<div id="show"></div>
</body>
</html>
action.php
if(isset($_POST['submit'])) {
if(empty($_POST['name']) || empty($_POST['content'])) {
$error = 'Please fill in the required fields!';
} else {
try {
$name = trim($_POST['name']);
$content = trim($_POST['content']);
$stmt = $db->prepare("INSERT INTO records(record_id, name, content)
VALUES(:recordid, :name, :content");
$stmt->execute(array(
'recordid' => $record_id,
'name' => $name,
'content' => $content
));
if(!$stmt){
$error = 'Please fill in the required fields.';
} else {
$success = 'Your post has been submitted.';
}
} catch(Exception $e) {
die($e->getMessage());
}
}
}
I have created a registration page to access my website. After the user registrate himself should appear an alert saying that the registration was OK and a redirect to main.php page... however for some reason if I create an insert statement the alert and the redirect don't appear... If I remove the insert the alert and the redirect works... why? This is part of the code of my 3 files: registration.php (ajax call) $('#submit').click(function() {var username2 = $('#uname2').val(); var password2 = $('#psw2').val(); $.ajax({ url: 'ajax/response.php', type: 'GET', data: {username2 : username2, password2: password2}, success: function(data) { if(data === 'correct') { alert("Username and Password have been created!"); //don' work with the insert location.replace("main.php"); //don' work with the insert } else { alert("Username or password are not correct... please register yourself!"); } } }); }); response.php (answer to ajax call) if(isset($_GET['username2']) && isset($_GET['password2'])) {$username2 = $_GET['username2']; $password2 = $_GET['password2']; if (checkUser($pdo, $username2) === true) { echo 'duplicate'; } else { insertUserPwd($pdo, $username2, $password2); //including this line the redirect and the alert doesn't work... the insert is OK echo 'correct'; } } data_access.php (the function works but doesn't permit alert and redirect to appear) function insertUserPwd(PDO $pdo, $usr, $pwd){ $data = [ 'id' => '', 'user' => $usr, 'password' => $pwd ]; $sql = "INSERT INTO users (id, user, password) VALUES (:id, :user, :password)"; $stmt= $pdo->prepare($sql); $stmt->execute($data); } Can someone help me to fix the code? hi friends! this code Code: [Select] foreach ( $users as $key => $value ) { $user_ids = implode(',', $value); echo "$key - $user_ids<br />"; } sends this output: Code: [Select] user one - 376,373 user charlie - user beta - 372 I need the $user_ids are shown in a DropDownList, of course only if the $user_ids is not empty. How can I do? thanks! Hi. I got this code below, which makes a dropdownlist. the value is passed in a string to a URL. The value EXAMPLE: is 13:30pm, but what reaches the URL is 13 If i add the mysql_real_escape_string, the full value is passed to the URL. BUT so is the "mysql_real_escape_string".. what is wrong with this code? this example does not work period: $query = "SELECT DISTINCT timeslot_start FROM #__profile_rates ORDER BY timeslot_start ASC"; $dropDownList ="<select class=\"inputbox\" name=\"timeslotstart\">"; $timeslotstarts =doSelectSql($query); foreach ($timeslotstarts as $timelotstart) { $timeslot_start=mysql_real_escape_string($timelotstart->timeslot_start); $dropDownList .= "<option value=$timeslot_start>".$timeslot_start."</option>"; } $dropDownList.="</select>"; $output['TIMESLOTSTART']=$dropDownList; but if i change to this it works but gives the "mysql_real_escape_string" in the url foreach ($timeslotstarts as $timelotstart) { $timeslot_start=$timelotstart->timeslot_start; $dropDownList .= "<option value=mysql_real_escape_string($timeslot_start)>".$timeslot_start."</option>"; } //Url looks like www.xxxx.com/xxx/x//xxxx/timeslotstart=mysql_real_escape_string(13%3A30pm), Everything is correct except the mysql_real_escape_string and the "(" and ")" should not be passed. how can i write this? Hey guys, i'm new to this site and would need some help with coding. So i'm making a car part website which should has brand/model search. It's a dropdown search which will get the brand / model from database and should display all the parts for that exact model, from folder. Database structure which i have is id, master, name. ( Here's some pictures to clear out what i'm doing. http://imgur.com/a/7XwVd ) So the problem is that it does not get the images from folder named ex: *_audi_a3.jpg. And link to codes what have been written already. Parts.php: http://pastebin.com/q6vdypge Update.php: http://pastebin.com/DymhGQ17 Search_images.php: http://pastebin.com/LF5Q0i8f Core.js: http://pastebin.com/bgc0y4TS I don't know what's wrong with it sadly. One thing i noticed when i used firebug it gives error on category when searching error:true. Hope you guys understand what i mean here, and also all help is appreciated. And move this post if it's in wrong place. Thanks! Edited by aeonius, 17 October 2014 - 12:15 PM. Right now I redirect to index page after I delete a record. However I am looking to make it so that I can delete a record without redirecting the page. I know this can be accomplised using Ajax. I have spent countless hours before trying to make it work, but it did not work.
So here is a basic setup I created. Can you please update it with ajax code so that I can see how it's done properly?
<!DOCTYPE HTML> <html lang="en"> <head> <meta charset="UTF-8"> <title>Home Page</title> </head> <body> <div class="record" > <a href="record.php?id=<?php echo $record_id ?>"><?php echo $record_name; ?></a> <div class="delete-record"> <a href="delete.php">Delete Record</a> </div> </div> </body> </html> Edited by man5, 18 August 2014 - 08:55 PM. Now I'm having this strange issue with my website I'm currently working on a tester system and I've encountered a problem that I'm unable to find the issue, tho I'm thinking my ajax php part of the script to be the thing causing it even tho it seems strange that it would cause it. The first part which is connected to where the problem occurs is the echo"<form>"; and from there, It should take you to index.php?page=tester&select=answer, now that is where it in the browser goes there tho it still shows the page stuff from the last page which is index.php?page=tester&select=applications, so it's like showing both &select=answer and &select=applications on the same page. <?php $q=$_GET["q"]; include'../config/connection.php'; $result = mysql_query("SELECT * FROM applications WHERE id = '$q'"); echo "<center><table border='1'> <tr> <th>Account Name</th> <th>Character Name</th> <th>Gender</th> <th>Skin Color</th> </tr>"; $row = mysql_fetch_array($result); echo "<tr>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['charactername'] . "</td>"; echo "<td>" . $row['gender'] . "</td>"; echo "<td>" . $row['race'] . "</td>"; echo "</tr></table></center>"; echo"<br/>"; echo"<table><tr> <th>Description</th> <th>Metagaming</th> <th>Powergaming</th></tr>"; echo"<tr>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['description']."</textarea></td>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['mg']."</textarea></td>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['pg']."</textarea></td>"; echo"</tr></table><table><br/><center><h1>Answer</h1><br/><form action='index.php?page=tester&select=answer' method='post'>"; echo"<textarea name='why' style='height:10em; width:60em;'></textarea><br/>"; echo"<input type='submit' name='answer' value='Accept' /><a/>"; echo"<input type='submit' name='answer' value='Decline' /></center>"; echo"<input type='hidden' name='id' value='$q'/>"; echo"</form></table>"; ?> Now on &select=answer it included a page which the script of that include consist of the stuff below, it outputs that the query was successfully, and all that. <? if(!empty($_POST['why'])) { $why = mysql_real_escape_string($_POST['why']); $answer = trim($_POST['answer']); $id = $_POST['id']; if($answer == "Accept") { $query1 = mysql_query("UPDATE characters SET accepted = '1' WHERE id = '".$id."'"); echo"Successfully accepted"; $answer = 1; } elseif($answer == "Decline") { echo"Successfully declined"; $answer = 0; } $query = mysql_query("UPDATE applications SET answer = '$why' AND tester = '".$_COOKIE['Username']."' AND accepted = '$answer' AND answered = '1' WHERE cid = '".$id."'") or die('Could not connect: ' . mysql_error()); if($query) { echo"<br/>Query went through without problems"; header("Refresh: 5;url=index.php?page=tester"); } } ?> This is the ajax part javascript of it which gets the information for index.php?page=tester&select=applications Code: [Select] <script type="text/javascript"> function showApplication(str) { if (str==""||str==0) { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","tester/applications.php?q="+str,true); xmlhttp.send(); } </script>If you need any more information feel free to ask for it. Thanks in advance. Hi, I need to call to this text to add a all with value "blank/empty" or "0" to the dropdownlist code below.. it should be inserted int the first position in the dropdownlist and have a value blank and call to this text from the language files: $searchAll = gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false); example is: ratestitle=>0 gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false); the words it calls is "ALL" when the user selects or leaves the "ALL" in the list the value remains empty this allows the search to search everything.. basically im stuck how to get it in the dropdown list as the first default position: can anyone help? here is my code://this is a search function which calls to the field rate_title the text from the select box is matched to the database table and the search pages shows the search option is the search is successful.. I have 5 of these types of searches but cant give a broader search option to my users as the values must be selected to search--- i need the option "ALL" to have a "EMPTY" value or no value.... if (in_array("ratestitle",$searchOptions)&& $showSearchOptions ) { if (empty($sch->filter['ratestitle']) ) $selectOption=$output['LANGUAGE_SEARCH_RATESTITLE']; else $selectOption=$sch->filter['ratestitle']; $showButton=true; $query = "SELECT DISTINCT rate_title FROM #__rates_table ORDER BY rate_title ASC"; $dropDownList ="<select class=\"inputbox\" name=\"ratestitle\">"; $ratesitles =doSelectSql($query); foreach ($ratesitles as $ratetitle) { $selected=""; $rate_title=$ratetitle->rate_title; if ($ratetitle==".$sch->filter['ratestitle'].") $selected="selected"; $dropDownList .= "<option ".$selected." value=\"".$rate_title."\">".$rate_title."</option>"; } $dropDownList.="</select>"; $output['RATESTITLE']=$dropDownList; } |
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