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PHP - Nobody Never Fixed This Code!
hi there is this game i play and i am trying to accomplish a code which adds items coming from the games xml.
the game is called zwinky and i'm having a small problem which can maybe be easily fixed.
Here are the codes:
http://paste.ee/p/JHMow
http://paste.ee/p/pIEUt
they are written differently. Okay So the problem is a little message when used on my webhost comes up on browser saying :
"HTTP/1.1 100 Continue HTTP/1.1 200 OK Date: Sat, 24 May 2014 22:52:31 GMT Server: Apache/2.2.11 (Unix) mod_ssl/2.2.11 OpenSSL/0.9.8c DAV/2 mod_jk/1.2.28 Cache-Control: max-age=0, must-revalidate Expires: Thu, 01 Jan 1970 00:00:00 GMT Set-Cookie: anx="os=-&g=-&oc=-&sn=dfprdzwinky4&od=none&op=-&fv=1400971951270&ob=-&om=-&lv=1400971951270&ok=-&nv=1"; Version=1; Domain=.zwinky.com; Max-Age=7776000; Expires=Fri, 22-Aug-2014 22:52:31 GMT; Path=/ Content-Language: en-US Content-Length: 92 Connection: close Content-Type: application/xml;charset=UTF-8 User not signed in"
as you can see it says "user not signed in" yet i am signed in into the game.. So i believe somewhere in the code the cookies are wrong or the code doesn't have the necessary elements to show that you are being logged in. to get the cookies/ login info you need to create a game account which takes 10-20 seconds: http://registration..../register.jhtml
and then using fiddler/charles or any other method displaying the accounts cookies it should show them up.
I don't know what is needed to add to the code to make it work
here our other topics on this issue never solved which might help:
http://forum.ragezon...44/help-920369/
http://www.webdevelo...129-php-execute
if anyone could help please! it's not hard making the game accounts and viewing the cookies, please and thank you!!!!
Similar Tutorialshi there is this game i play and i am trying to accomplish a code which adds items coming from the games xml.
the game is called zwinky and i'm having a small problem which can maybe be easily fixed.
Here are the codes:
http://paste.ee/p/JHMow
http://paste.ee/p/pIEUt
they are written differently. Okay So the problem is a little message when used on my webhost comes up on browser saying :
"HTTP/1.1 100 Continue HTTP/1.1 200 OK Date: Sat, 24 May 2014 22:52:31 GMT Server: Apache/2.2.11 (Unix) mod_ssl/2.2.11 OpenSSL/0.9.8c DAV/2 mod_jk/1.2.28 Cache-Control: max-age=0, must-revalidate Expires: Thu, 01 Jan 1970 00:00:00 GMT Set-Cookie: anx="os=-&g=-&oc=-&sn=dfprdzwinky4&od=none&op=-&fv=1400971951270&ob=-&om=-&lv=1400971951270&ok=-&nv=1"; Version=1; Domain=.zwinky.com; Max-Age=7776000; Expires=Fri, 22-Aug-2014 22:52:31 GMT; Path=/ Content-Language: en-US Content-Length: 92 Connection: close Content-Type: application/xml;charset=UTF-8 User not signed in"
as you can see it says "user not signed in" yet i am signed in into the game.. So i believe somewhere in the code the cookies are wrong or the code doesn't have the necessary elements to show that you are being logged in. to get the cookies/ login info you need to create a game account which takes 10-20 seconds: http://registration..../register.jhtml
and then using fiddler/charles or any other method displaying the accounts cookies it should show them up.
I don't know what is needed to add to the code to make it work
here our other topics on this issue never solved which might help:
http://forum.ragezon...44/help-920369/
http://www.webdevelo...129-php-execute
if anyone could help please! it's not hard making the game accounts and viewing the cookies, please and thank you!!!!
Hi ,
I try to change a PHP code for a booking program without succes. Now the time set is from 00.00 - 24.00hours but it must be fixed on 15.00H ( dropoff) and 11.00H (pick-up). Can someone help me please ?
Big thanks in advance !
$pickhdeftime = !empty($places[$indvrcplace]['defaulttime']) ? ((int)$places[$indvrcplace]['defaulttime'] / 3600) : ''; I'm having trouble with this emailing script. As you can see it clearly sets the contect typw to text/html but when you read the email it's not in HTML like intended $to=$email; $subject='Activate your account.'; $message=" <html> <head> <title>Activate your account that doesn't show in HTML damn it -.-</title> </head> <body> <p>Nothing here.</p> </body> </html> "; // To send HTML mail, the Content-type header must be PROPERLY set $headers = 'MIME-Version: 1.0' . '\r\n'; $headers .= 'Content-type: text/html; charset=iso-8859-1' . '\r\n'; // Additional headers $headers .= 'To: $fname <$email>' . '\r\n'; $headers .= 'From: **************' . '\r\n'; $headers .= 'Reply-To: ******************' . '\r\n'; $headers .= 'X-Mailer: PHP/' . phpversion(); // Mail it $mail=mail($to, $subject, $message, $headers); Can someone help me solve why it's sending as plain text and not HTML this is getting annoying Thanks in advance, hi,
I am using fixed-header code for my table on vertical scroll, its working fine for all column name except last two (balance and pay status) because they are going out side page (horizontally). and when i scroll from bottom to see the last two columns values , the fixed header only show the columns till advance, fixed header not showing last two remaining columns that go out side page horizontally.
Check the screen shots for better understanding.
image-1 you can see all column till pay status.
[ATTACH=CONFIG]64973[/ATTACH]
image -2 you can see vertical scroll working fine till advance column.
[ATTACH=CONFIG]64974[/ATTACH]
Image -3 but in this you can see after full horizontal scroll towards right side, it only showing column till advance, instead of balance and pay status.
[ATTACH=CONFIG]64975[/ATTACH]
Here is the full code
Untitled Document
$(document).ready(function()
{
function moveScroll(){
var scroll = $(window).scrollTop();
var anchor_top = $("#maintable").offset().top;
var anchor_bottom = $("#bottom_anchor").offset().top;
if (scroll>anchor_top && scroll
Please check this and if found give me the solution for this.
thanks in Advance
Attached Files
image-2.jpg 218.01KB
0 downloadsThis isn't for anything practical, I'm just fiddling. Anyways, I'm wondering if there's anyway to make this more efficient since at higher lengths it could become really heavy. $l is length of the number. function fixed_random($l) { $number = ""; do { $r = mt_rand(0, $l); $number .= $r; } while (strlen($number) < $l); return $number; } Hey, I'm getting an undefined index in my final test and would like to know that this is fixed and I don't have to worry about any troubles.. here is what's going on Notice: Undefined index: register in C:\wamp\www\unitedsticks\insert.php on line 6 Registered! Return Notice: Undefined index: class in C:\wamp\www\unitedsticks\insert.php on line 58 1 record added Now...It Registers and does everything it's meant to, I just want the undefined index gone...here's my coding: THIS IS insert.php Code: [Select] <?php session_start(); mysql_connect("localhost", "root", ""); // Server connection mysql_select_db("myfirstdatabase"); // Database selection $page = $_POST['register']; // Setting the page value $user = $_POST['username']; // Setting the user value $pass = $_POST['password']; // Setting the pass value if($page == 1) { //This means that the page is the register form so the register form code goes here $query = mysql_query("select * FROM userdata WHERE username = '$user'"); // Queries the Database to check if the user already exists if(mysql_num_rows($query) !== 0) // Checks if there is any rows with that user { echo "THIS USER IS ALREADY TAKEN!"; // Stops there } else { mysql_query("INSERT INTO userdata (username, password) VALUES('$user', '$pass')"); // Inserts into the database. echo "REGISTERED! <BR> <a href='index.php'>Go to the login page</a>"; //Link and text to go to the login } } ?> <?php if($page == 0) { //This means that the page is the login form so the register form code goes here $query = mysql_query("SELECT username FROM userdata WHERE username = '$user'"); // Queries the Database to check if the user doesn't exist if(mysql_num_rows($query) == 0) // Checks if there is any rows with that user { echo "User doesn't exist"; // Stops there } $query = mysql_query("SELECT username FROM userdata WHERE username = '$user' AND password = '$pass'"); if(mysql_num_rows($query) !== 0) // Checks if there is any rows with that user and pass { echo "Registered!<BR> <a href='index.php'>Return</a>"; //Link and text to go to the login $_SESSION['LOGGEDIN'] = 1; } } ?> <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("database", $con); $sql="INSERT INTO register (username, password, class) VALUES ('$_POST[username]','$_POST[password]','$_POST[class]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ?> And my other coding: Code: [Select] <html> <body> <center><p><p><!-- Main Table(You can define padding accordingly) --> <table width="50%" border="0" cellspacing="0" cellpadding="5"> <td width="50%"> <!-- Table on left side --> <table width="90%" height="100%" border="1" cel1pacing="0" cellpadding="0" BORDERCOLOR="#007FFF"> <body style="background-color:;"> <td><h3><center><h3 style="background: blue; color: white;">Create Account Here<br></font></center></h2><p> <h4><p>Login Information</h4></p> <form action="insert.php" method="post"> Username: <input type="text" name="username" /><br> Password: <input type="password" name="password" /> <h3>Choose your Class</h2> <table width="100%" border="1"> <tr> <p> <label> <input type="radio" name="class" value="Clubber" id="SC" /> Clubber</label> <br /> <label> <input type="radio" name="class" value="Pastamancer" id="PM" /> Pastamancer</label> <br /> <label> <input type="radio" name="class" value="" id="" /><br> <center><input type="submit" /></center> </label> <br /> </p></td> </tr> </table> </form> </body> </html> Thanks for any help... Brent. HI All I have created a large html dynamic table using jquery . Now my query is here , How to make a fixed html table header while scrolling . can any one please hepl me how to solve ?? I have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this? <?php include ("includes/includes.php"); $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo "<p class='postnote'>" . $post->post . "</p"; echo "<span class='footer'>Posted By: " . $post->author . "</span>"; echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>"; echo "<span class='footer'>Tags: " . $post->tags . "</span>"; echo ' <div class="addthis_toolbox addthis_default_style "> <a class="addthis_button_facebook_like" fb:like:layout="button_count"></a> <a class="addthis_button_tweet"></a> <a class="addthis_counter addthis_pill_style"></a> </div> <script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script> <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>'; echo "</div>"; } ?> Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code. $sql="select * from Profile where username = '$username'; $result = mysql_query( $sql, $conn ) or die( "ERR: SQL 1" ); if(mysql_num_rows($result)!=0) { process form } else { echo "That username already exist!"; } the current code of the form <?PHP //session_start(); require_once "formvalidator.php"; $show_form=true; if (!isset($_POST['Submit'])) { $human_number1 = rand(1, 12); $human_number2 = rand(1, 38); $human_answer = $human_number1 + $human_number2; $_SESSION['check_answer'] = $human_answer; } if(isset($_POST['Submit'])) { if (!isset($_SESSION['check_answer'])) { echo "<p>Error: Answer session not set</p>"; } if($_POST['math'] != $_SESSION['check_answer']) { echo "<p>You did not pass the human check.</p>"; exit(); } $validator = new FormValidator(); $validator->addValidation("FirstName","req","Please fill in FirstName"); $validator->addValidation("LastName","req","Please fill in LastName"); $validator->addValidation("UserName","req","Please fill in UserName"); $validator->addValidation("Password","req","Please fill in a Password"); $validator->addValidation("Password2","req","Please re-enter your password"); $validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!"); $validator->addValidation("email","email","The input for Email should be a valid email value"); $validator->addValidation("email","req","Please fill in Email"); $validator->addValidation("Zip","req","Please fill in your Zip Code"); $validator->addValidation("Security","req","Please fill in your Security Question"); $validator->addValidation("Security2","req","Please fill in your Security Answer"); if($validator->ValidateForm()) { $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error()); mysql_select_db("beatthis_beatthis") or die(mysql_error()); $FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file $LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file $UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file $Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file $Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file $email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file $Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file $Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file $Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file $Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file $sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; //echo $sql; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } else{ mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body); echo "<h3>Your profile information has been submitted successfully.</h3>"; } mysql_close($con); $show_form=false; } else { echo "<h3 class='ErrorTitle'>Validation Errors:</h3>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<p class='errors'>$inpname : $inp_err</p>\n"; } } } if(true == $show_form) { ?> hey gurus, i am a newbie php coder.. i am learning by example. what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage) ---------------------------------------------------------------- the table structure that will be used is as follows: user.bonus_credit user.ID bonus_credit.bonusCode bonus_credit.qty bonus_credit.value bonus_credit_usage.bonusCode bonus_credit_usage.usedBy ---------------------------------------------------------------- so lets say, in bonus_credit i have the following bonusCode = 'facebook' (this is the code they have to type to redeem the bonus qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once) value = '5' (this is the amount of bonus_credit for each qty) Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit ----------------------- i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code. if(isset($_REQUEST['btnBonus'])) { $bonus_credit = addslashes($_REQUEST['bonusCode']); $query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'"; echo "<script>window.location='myreferrals.php?msgs=2';</script>"; mysql_query($query) or die(mysql_error()); } Advance thank you. Can you help please. The error..... Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24 code. Code: [Select] <?php //database connection. $DB = mysql_connect("localhost","root") or die(mysql_error()); if($DB){ //database name. $DB_NAME="mysql"; //select database and name. $CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name"); // if connection. }if($CON){ //show tables. $mysql_show="SHOW TABLES"; //select show and show. $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())"; } //if allowed to show. if($mysql_select2){ //while it and while($data=mysql_fetch_assoc($mysql_select2)){ //show it. echo $data; } } ?> This topic has been moved to Apache HTTP Server. http://www.phpfreaks.com/forums/index.php?topic=343321.0 Can I combine also HTML code in PHP function? For example, can a PHP function include HTML form and the PHP code to handle this form? If yes, this will make my main code much more smaller and readable. If not, is there a way to define an "external macro" like, which allow me to replace pre-defined lines of code with short alias? Can you help me integrate this code :
<form method="post" action="submit.php"> <input type="checkbox" class="required" /> Click to check <br /> <input disabled="disabled" type='submit' id="submitBtn" value="Submit"> </form>In to this Contact Form code, please? <form action="../page.php?page=1" method="post" name="contact_us" onSubmit="return capCheck(this);"> <table cellpadding="5" width="100%"> <tr> <td width="10" class="required_field">*</td> <td width="80">Your Name</td> <td><input type="text" name="name" maxlength="40" style="width:400px;/></td> </tr> <tr> <td class="required_field">*</td> <td>Email Address</td> <td><input type="text" name="email" maxlength="40" style="width:400px;/></td> </tr> <tr> <td></td> <td>Comments:</td> <td><textarea name="comments" style="width: 400px; height: 250px;"></textarea></td> </tr> </table> </form I use this type of a code to send automatic emails from my website: Code: [Select] $headers = ; $headers .= ; $to = ; Click here to go to Google. ", $headers); I am having hard time figuring out how to do hyperlink on words (like here). If I do something like this: Code: [Select] <a href='http://www.google.com'>here</a> it spits out that exact thing out. Thanks you for your input Hi, Look at this code below: Code: [Select] <?php function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ""; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n"; $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = round($markTotal / $weightSession * 100); if ($markGrade >= 70) { $grade = "A"; } else if ($markGrade >= 60 && $markGrade <= 69) { $grade = "B"; } else if ($markGrade >= 50 && $markGrade <= 59) { $grade = "C"; } else if ($markGrade >= 40 && $markGrade <= 49) { $grade = "D"; } else if ($markGrade >= 30 && $markGrade <= 39) { $grade = "E"; } else if ($markGrade >= 0 && $markGrade <= 29) { $grade = "F"; } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n"; return $moduleHTML . $sessionsHTML; } $output = ""; $studentId = false; $courseId = false; $moduleId = false; while ($row = mysql_fetch_array($result)) { if($studentId != $row['StudentUsername']) { //Student has changed $studentId = $row['StudentUsername']; $output .= "<p><strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']})\n"; } if($courseId != $row['CourseId']) { //Course has changed $courseId = $row['CourseId']; $output .= "<br><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Course Mark</strong> <strong>Grade</strong> <br><strong>Year:</strong> {$row['Year']} </p>\n"; } if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } //Get output for last module $output .= outputModule($moduleId, $moduleName, $sessionsAry); //Display the output echo $output; } } } ?> This code allallows me to make calculations and display a student's course and linked with it the course the modules in the course and linked with modules are all the sessions. It is able to display what marks each student have got for each module and session. Now look at code below, it is able to display modules and in those modules the sessions that link to those modules: Code: [Select] <?php if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } What I want to know is how can I do something similar for course so that it picks out the right modules depending on the course it displays. There maybe some code that needs to be added in the function. Hi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Michael Feathers coined the term Legacy Code as being code without automated tests.
Still however Legacy Code evokes a vision in me that it is code that is ugly, old, runs on mainframes, and is probably 3000 lines long, uses globals and questionable code practices.
But say we take this ugly nasty code, and put it very nicely under test, but without doing any refactoring, other than that necessary to be able to put it under test in the first place.
Now that code is under test. But it it still ugly. How would you call ugly code under test?
Would you make a differentiation between old & ugly and modern & pretty code if both are under test?
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