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PHP - How Do I Use A Variable From A Different Php File
I'm new to php and i have a html form with 2 forms and 2 submit buttons, 1 of the forms is solely for uploading an image i downloaded the php script as i don't understand the code well enough to write it myself.
The second form asks for your name and email then when you click submit it writes a new html file with the included information. I have managed to upload a file successfully and write the html document with the information successfully but i can't get the image to write into the html document. My file_upload.php script contains the variable for the image name, now how would i get the variable string from file_upload.php and use that name in compile.php. Here's my code. -------------- Form.html -------------- <!DOCTYPE html> <html lang="en"> <head> <title></title> </head> <body> <form action="compile.php" method="post"> <p>input name:<input type="text" name="name"/></p><br /> <p>email:<input type="text" name="email" /></p><br /> </form> <br /> <form enctype="multipart/form-data" method="post" action="file_upload.php"> Choose your file he <input name="file1" type="file" /><br /><br /> <input type="submit" value="Upload It" /> </form> </body> </html> ------------- compile.php ------------- <?php $name = $_POST['name']; $price = $_POST['price']; $desc = $_POST['desc']; $file = "new.html"; $handle = fopen($file,'w'); $data = "<!DOCTYPE html> <html> <head> <title></title> </head> <body> <table style='border-radius:8px;'> <tr> <td style='border-radius:8px;'> <h1>$name</h1> </td> </tr> </table> <table> <tr> <td> <ul> <lh>Product name: $name</lh> <br><br> <li>Price: $price</li><br> <li>Description: $desc</li><br> </ul> </td> <td> <img src='uploads/$fileName' width='' height='' alt='' title='' /> </td> </tr> </table> </body> </html>"; fwrite($handle, $data); print "data written"; fclose($handle); ?> ------------ file_upload.php ------------ <?php // Set local PHP vars from the POST vars sent from our form using the array // of data that the $_FILES global variable contains for this uploaded file $fileName = $_FILES["file1"]["name"]; // The file name $fileTmpLoc = $_FILES["file1"]["tmp_name"]; // File in the PHP tmp folder $fileType = $_FILES["file1"]["type"]; // The type of file it is $fileSize = $_FILES["file1"]["size"]; // File size in bytes $fileErrorMsg = $_FILES["file1"]["error"]; // 0 for false... and 1 for true // Specific Error Handling if you need to run error checking if (!$fileTmpLoc) { // if file not chosen echo "ERROR: Please browse for a file before clicking the upload button."; exit(); } else if($fileSize > 5000000000) { // if file is larger than we want to allow echo "ERROR: Your file was larger than 5mb in file size."; unlink($fileTmpLoc); exit(); } else if (!preg_match("/.(gif|jpg|png)$/i", $fileName) ) { // This condition is only if you wish to allow uploading of specific file types echo "ERROR: Your image was not .gif, .jpg, or .png."; unlink($fileTmpLoc); exit(); } // Place it into your "uploads" folder mow using the move_uploaded_file() function move_uploaded_file($fileTmpLoc, "uploads/$fileName"); // Check to make sure the uploaded file is in place where you want it if (!file_exists("uploads/$fileName")) { echo "ERROR: File not uploaded<br /><br />"; echo "Check folder permissions on the target uploads folder is 0755 or looser.<br /><br />"; echo "Check that your php.ini settings are set to allow over 2 MB files, they are 2MB by default."; exit(); } // Display things to the page so you can see what is happening for testing purposes echo "The file named <strong>$fileName</strong> uploaded successfuly.<br /><br />"; echo "It is <strong>$fileSize</strong> bytes in size.<br /><br />"; echo "It is a <strong>$fileType</strong> type of file.<br /><br />"; echo "The Error Message output for this upload is: <br />$fileErrorMsg"; ?> Similar TutorialsI am trying to get an swf to upload an image along with user information. I was able to get the upload and variables send working individually, but together it stops with no visible errors. The following is a link: http://jarrodverhagen.com/upload/swfindex.htm to a tutorial that is using almost identical code to mine, and has been used by others, but still will not work on my site. Is there a reason supposedly correct code wouldn't work on my site? The original link for the tutorial is: http://www.developphp.com/Flash_tutoria ... sh_and_AS3 Hi, I have a variable named $siteName stored in the server.php file in the data directory data/server.php Now in the header.php page I want to retrieve the $siteName variable so it can be used in the header information. This is what I have but it isnt working. server.php Code: [Select] <?php $siteName = 'My+Test+Site'; ?><?php $adminEmail = 'pwithers2009@hotmail.co.uk'; ?><?php $sendmailLoc = '/usr/sbin/sendmail'; ?><?php $imgdir = 'http://www.tropicsbay.co.uk/images/'; ?><?php $imgdirbase = '/home/tropicsb/public_html/images/'; ?> header.php Code: [Select] <?php include("data/server.php"); $siteName = $_GET['siteName']; echo ' <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>$siteName Admin Panel</title> <link rel="stylesheet" href="admin.css" type="text/css" /> </head> <div id="pagehead"> <div id="navigation"> <img alt="" src="images/leftNav.gif" height="32" width="4" id="leftNav" /> <img alt="" src="images/rightNav.gif" height="32" width="4" id="rightNav" /> <div id="globalLink"> <a href="admin.php?cmd=manage&username=admin&password=$adminpw" id="gl1" class="glink" onmouseover="ehandler(event,menuitem1);">Users</a><a href="admin.php?cmd=editTemplate&username=admin&password=$adminpw" id="gl2" class="glink" onmouseover="ehandler(event,menuitem2);">Templates</a><a href="admin.php?cmd=mysqlBackup&username=admin&password=$adminpw" id="gl3" class="glink" onmouseover="ehandler(event,menuitem3);">Database</a><a href="admin.php?cmd=paymentLog&username=admin&password=$adminpw" id="gl4" class="glink" onmouseover="ehandler(event,menuitem4);">Payment</a><a href="admin.php?cmd=profileFields&username=admin&password=$adminpw" id="gl5" class="glink" onmouseover="ehandler(event,menuitem5);">Setup</a><a href="admin.php?cmd=changeAdminpw&username=admin&password=$adminpw" id="gl6" class="glink" onmouseover="ehandler(event,menuitem6);">Preferences</a><a href="admin.php?cmd=logout&username=admin&password=$adminpw" id="gl7" class="glink" onmouseover="ehandler(event,menuitem6);">Logout</a></div> </div></div> <div id="pagelayout"> <img alt="" src="images/leftCurve.gif" height="6" width="6" id="left" /> <img alt="" src="images/rightCurve.gif" height="6" width="6" id="right" /> <div id="pageName"> <h2>$siteName Admin Panel<h2> </div>'; ?> Any ideas on how to do this, it seems to work ok in one of my other scripts. Thanks Alright I am so close but can not figure this out, thanks in advance for any help.
So what I am trying to do is take the input variables from a form and have them load a specific PDF .
<html>
<body>
<?php
if( $_GET["startpoint"] || $_GET["endpoint"])
{
$a = $_GET["startpoint"];
$b = $_GET["endpoint"];
echo "Your Startpoint is:". $_GET["startpoint"]. "<br />";
echo "Your Endpoint is: ". $_GET["endpoint"]. "<br />";
echo $a,$b,".pdf";
}
?>
</body>
</html>
This is what I have and it works to display what the two points are what the final pdf file should be.
The final echo generates the PDF name
echo $a,$b,".pdf";How can I get it to load a file using this as a variable or the name it generates, thanks. when tyring to pass a variable to a extenal javascript file it just shows up as a sting and the variable isnt beening executed
var timezone_offset = <?= $timezone_offset ?>;im guessing its probably down to the fact the variable is being passed from my framework controller... so im wondering how do you send a variable to a external javascript file when using a framework?
$this->view->timezone_offset = "test"; // in my controller
// passing varibales to template in my view
if (preg_match("/\.html$/i", $file_name))
{
extract($this->_variables);
require_once PRIVATE_DIRECTORY . 'application' . DS . 'views' . DS . $file_name;
}
thanks guys
Hi Guys, I'm working on an image resizer, to create thumbnails for my page. The resizer works on principle of include a DIRECT link to the image. But what I want to do is put in the PHP Variable in the URL string, so that it points to that file and resizes it accordingly. My code is as follows : Code: [Select] <img src="thumbnail.php?image=<?php echo $row_select_property['image_url']; ?> Image Resize : Code: [Select] <?php // Resize Image To A Thumbnail // The file you are resizing $image = '$_GET[image_url]'; //This will set our output to 45% of the original size $size = 0.45; // This sets it to a .jpg, but you can change this to png or gif header('Content-type: image/jpeg'); // Setting the resize parameters list($width, $height) = getimagesize($image); $modwidth = $width * $size; $modheight = $height * $size; // Creating the Canvas $tn= imagecreatetruecolor($modwidth, $modheight); $source = imagecreatefromjpeg($image); // Resizing our image to fit the canvas imagecopyresized($tn, $source, 0, 0, 0, 0, $modwidth, $modheight, $width, $height); // Outputs a jpg image, you could change this to gif or png if needed imagejpeg($tn); ?> What I am trying to do is pass on the variable "image=<?php echo $row_select_property['image_url']; ?>" to the Thumbnail script. At the moment I am passing it through the URL string, but it doesnt seem to load the graphic. I'll try expand on this more, should you have questions as I am finding it a little difficult to explain. Thanks in advance. I am trying to use the variable $RATETHESE to include an array into file A. The array is in file B. PhP File A include_once(dirname(__FILE__) . '/PhpFileB.php'); global $RATETHESE; $VALID_RATING_IDS = $RATETHESE; Php File B $RATETHESE = "array("1", "2");" For some reason it is printing the array on the page, and the array is not being used to run the script. Did i do anything wrong? My catalog uses a template file to list product details. One part of it is responsible for putting these details into nifty little tabs: <?php $template = '{magictabs style=black_rounded, tabwidth=110px}'; $template .= 'Technical Specifications'; $template .= '::'; $template .= '<table colspan="3"><tr><td>'; $template .= $details; $template .= '</td></tr></table>'; $template .= '||||'; ?> I don't want it to output $details, I want it to output a separate script instead. How do I include this separate file as a variable? I want this: <?php include('specs.php'); ?> to replace the $details variable. can i add php variables into a js file? i have tried this: document.location = <?php echo $_SESSION['fwd_page']; ?>; but it doesnt work. Hi, I need to pass value of variable to another php file. I thought it is possible to do it as following: <form action="products.php"> <INPUT TYPE=hidden NAME='id' . VALUE='$id'> </form> But the problem is like that. The php file inside which I want to write above html code has not using <form> tag and it has no buttons. So how to initiate the transfer of variable into another php file? Is the above idea is not the good idea? Are there any another ways? I want to save an image with a unique name that is created from a hash function. How can I cretae the path with the variable... Code: [Select] $hash=$_GET['hash']; $path ="/Applications/MAMP/htdocs/test_upload/images/imagename2.png"; //becomes $path ="/Applications/MAMP/htdocs/test_upload/images/'.$hash.'.png";? As you can see here I have the following code Code: [Select] <?php session_start(); session_register('hazard2'); //INITIALIZE ERROR VARIABLES $errorFound = false; $errorIcon['hazard2'] = ''; if (isset($_POST['submitbutton'])) { //SET SESSION VARIABLES $_SESSION['hazard2'] = $_POST['hazard2']; //TEST FORM INFORMATION if(count($_POST['hazard2']) != 3) { $errorFound = true; $errorIcon['hazard2'] = 'Error Question 2'; } //IF NO ERRORS WERE FOUND, CONTINUE PROCESSING if (!$errorFound) { header( "Location: hazardresult.php" ); } } ?> It's lazy I know, but the script is on a file called hazard2.php, is there anyway to have all of the hazard2's in the code come from the file name. So when I make hazard3, I don't have to change all the hazard2's to hazard3's Thank you Hi, I wrote this to retrieve a file based on a POST value. For some reason it will not retrieve the file content and display it at all. I get this message: Warning: fopen(18.txt) [function.fopen]: failed to open stream: No such file or directory in /home/content/x/y/z/path/html/includes/different.php The 18 is the correct POST value. So that is a positive There is a file named 18.txt in /home/content/x/y/z/path/html/includes/18.txt Thanks. <?php $id5 = $_POST[id]; //Display Text File $myFile = $id5; $myFile .= ".txt"; $fh = fopen($myFile, 'r'); $theData = fgets($fh); fclose($fh); echo $theData; ?> This is a continuation of my previous post. I would like to be able to read the second column of a tab delimited txt file into a variable as a string. let's say i have: Code: [Select] somegarbage_here readthisinto$file I'm looking for this but all tuts seem to be about importing it to arrays and what not. I just want to import the second column. There is always one line. Hello All, I have two php files original.php and return.php retrun.php file returns a variable after I pass $channel_name to it Code: [Select] return $return_variable; I want to assign this return variable to a variable in original.php Something like this Code: [Select] $results = include ('return.php?channel='.$channel_name.'');I am not sure how to do the above code. When I call the return.php from a browser it works properly. Thanks for any help This code uploads a file to the server then renames it to the next id number from the database and adds the extension .jpg to the file name. index.php - I need .jpg to be a variable that will append .gif if it's a gif file or .png if it's a png file. Currently, if the file is a .jpg, .gif, or .png, the files are given the extension .jpg. <?php copy($_FILES['banner']['tmp_name']['file'], './banners/'.$photo_id.'.jpg'); ?> _photo.php - I want to replace .jpg in this code with the variable from above. <a href="<?php echo safe_output($photo['web_url']); ?>" target="_blank" class="bannerImg"><img src="banners/<?php echo $photo['id']; ?>.jpg"/></a> Say I have an installation file, and they type in all their database information & click submit. How would I get that information to open up a file called config.php, and write to the $db_host, $db_pass, $db_user, and $db variables only? Is this possible? Thanks! Have page#1 with thumbs view_thumbs.php , when a thumb is clicked thumb link goes to page#2 which is the video_play.php page(which must play embed codes from xml sheet) Using GET method to identify incoming link from page#1. QUESTION is how can i retrieve file(embed code) from xml to play on page#2 with incoming GET info from page#1? (embeds not you only from you tube, so no youtube solutions only, just retrieve file) I somehow have to fill play video div on page#2/video_play.php according to GET data from page#1/view_thumbs.php Hi all, I have my whole script working only the name of the upload file won't pass to the process.php page. Any help much appreciated. Prob just some silly mistake that i made but i can't for the life of me see it. form Code: [Select] <form enctype="multipart/form-data" action="process.php" method="POST" name="books" title="Santa_Book"> <img src="images/book/Enter_your_details.png" width="400" height="60" /><br /> <ul id="inline_list"> <input type="text" name="first_name" id="first_name" value="Text to be displayed here" onfocus="if(this.value==this.defaultValue)this.value='';" onblur="if(this.value=='')this.value=this.defaultValue;"/> <label for="sur_name" class="inside">Name</label> <input name="sur_name" type="text" id="sur_name" class="inside" /> <label for="sname">Surname</label> <br /> Sex <select name="sex" id="sex"> <option selected="selected">Please Select....</option> <option value="girl">Girl</option> <option value="boy">Boy</option> </select> <label for="age">Age</label> <input type="text" name="age" id="age" /> <br /> <label for="house_no">House No.</label> <input type="text" name="house_no" id="house_no" /> <br /> <label for="street">Street Name</label> <input type="text" name="street" id="street" /> <br /> <label for="town">Town</label> <input type="text" name="town" id="town" /> <br /> <br /> <select name="bscf1" id="bscf1"> <option selected="selected">Please Select...</option> <option value="Brother1">Brother</option> <option value="Sister1">Sister</option> <option value="Cousin1">Cousin</option> <option value="Friend1">Friend</option> </select> <label for="bscf_name1">Friend / Sibling</label> <input type="text" name="bscf_name1" id="bscf_name1" /> <br /> <select name="bscf2" id="bscf2"> <option>Please Select...</option> <option value="Brother2">Brother</option> <option value="Sister2">Sister</option> <option value="Cousin2">Cousin</option> <option value="Friend2">Friend</option> </select> <label for="bscf_name2">Friend / Sibling</label> <input type="text" name="bscf_name2" id="bscf_name2" /> <br /> <label for="from_name">This book is from...</label> <input type="text" name="from_name" id="from_name" /> <br /> <input name="uploadedfile" type="file" id="uploadedfile" value="Upload Image" /> <br /> </ul> <br /> <input type="submit" value="Continue" /> </form> process.php page Code: [Select] <?php // Database connect $con = mysql_connect("mysql1.myhost.ie","admin_book","root123"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("book_test", $con); //Parse Values from Coupon.php Form $first_name = mysql_real_escape_string(trim($_POST['first_name'])); $sur_name = mysql_real_escape_string(trim($_POST['sur_name'])); $sex = mysql_real_escape_string(trim($_POST['sex'])); $age = mysql_real_escape_string(trim($_POST['age'])); $house_no = mysql_real_escape_string(trim($_POST['house_no'])); $street = mysql_real_escape_string(trim($_POST['street'])); $town = mysql_real_escape_string(trim($_POST['town'])); $bscf1 = mysql_real_escape_string(trim($_POST['bscf1'])); $bscf_name1 = mysql_real_escape_string(trim($_POST['bscf_name1'])); $bscf2 = mysql_real_escape_string(trim($_POST['bscf2'])); $bscf_name2 = mysql_real_escape_string(trim($_POST['bscf_name2'])); $from_name = mysql_real_escape_string(trim($_POST['from_name'])); $uploadedfile = mysql_real_escape_string(trim($_POST['name'])); if ($sex == 'girl') { $his_her = 'her'; } else { $his_her = 'his'; } if ($sex == 'girl') { $him_her = 'her'; } else { $him_her = 'his'; } $sql="INSERT INTO details (first_name, sur_name, sex, age, house_no, street, town, bscf1, bscf_name1, andy, bscf2, bscf_name2, his_her, him_her, from_name, uploadedfile) VALUES ('$first_name','$sur_name','$sex','$age','$house_no','$street','$town','$bscf1','$bscf_name1','and','$bscf2','$bscf_name2','$his_her','$him_her','$from_name','$uploadedfile')"; // Where the file is going to be placed $target_path = "uploads/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); $target_path = "uploads/"; $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } echo 'Thank you '. $first_name . ' for entering your details bro.<br />'; echo 'surname is : '. $sur_name . '.<br />'; echo 'sex is : '. $sex . '.<br />'; echo 'age is: '. $age . ' .<br />'; echo 'bscf friend 1 is : '. $bscf1 . '.<br />'; echo 'bscf name 1 is : '. $bscf_name1 . '.<br />'; echo 'bscf friend 2 is : '. $bscf2 . '.<br />'; echo 'bscf name 2 is : '. $bscf_name2 . '.<br />'; echo 'his_her is : '. $his_her . ' .<br />'; echo 'him_her is : '. $him_her . '.<br />'; echo 'From Name is : '. $from_name . '.<br />'; echo 'Uploaded file is : '. $uploadedfile . '.<br />'; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } ?>
Hi! The file login.php and the config file containing the db connection are in the model folder and the login_view is in view folder. I am trying to make a login form am display some error messages to the user, but I don't get the error messages. Can you help me figure it out? PS: the connection to the db works fine! Thx!
LOGIN.PHP
<?php
//start the session
session_start();
foreach (glob("model/*.php") as $filename) {
include $filename;
}
//form defaults
$error["alert"]= "";
$error["user"]= "";
$error["pass"]= "";
$input["user"]= "";
$input["pass"]= "";
if(isset($_POST["submit"]))
{
//process form
if($_POST["username"] == "" || $_POST["password"] == ""){
//display errors
if($_POST["username"] == ""){$error["user"] = "required";}
if($_POST["password"] == ""){$error["pass"] = "required";}
$error["alert"] = "Please fill in the required fields";
//get the values for the username and password
$input["user"]= $_POST["username"];
$input["pass"]= $_POST["password"];
include("../views/login_view.php");
}
}else{
include("../views/login_view.php");
}
LOGIN_VIEW.PHP
<?php
session_start();
foreach (glob("model/*.php") as $filename) {
include $filename;
}
?>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" rel="stylesheet" id="bootstrap-css">
<script src="//maxcdn.bootstrapcdn.com/bootstrap/4.0.0/js/bootstrap.min.js"></script>
<script src="//cdnjs.cloudflare.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<!------ Include the above in your HEAD tag ---------->
<!--author:starttemplate-->
<!--reference site : starttemplate.com-->
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<meta name="keywords"
content="unique login form,leamug login form,boostrap login form,responsive login form,free css html login form,download login form">
<meta name="author" content="leamug">
<title>Unique Login Form | Bootstrap Templates</title>
<link href="/styles/style.css" rel="stylesheet" id="style" type="text/css">
<!-- Bootstrap core Library -->
<link href="//netdna.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css" rel="stylesheet" id="bootstrap-css">
<script src="//netdna.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"></script>
<script src="//code.jquery.com/jquery-1.11.1.min.js"></script>
<!-- Google font -->
<link href="https://fonts.googleapis.com/css?family=Dancing+Script" rel="stylesheet">
<!-- Font Awesome-->
<link href="//maxcdn.bootstrapcdn.com/font-awesome/4.2.0/css/font-awesome.min.css" rel="stylesheet">
</head>
<body>
<!-- Page Content -->
<div class="container">
<div class="row">
<div class="col-md-offset-5 col-md-4 text-center">
<h1 class='text-white'>Login Form</h1>
<form action ="" method="POST">
<div class="form-login"></br>
</br>
<?php
if($error["alert"] != ''){
echo "<div class='alert'>".$error["alert"]."</div>";
}
?>
<div>
<input type="text" name ="username" id="userName" class="form-control input-sm chat-input" placeholder="Username" value= "<?php echo $input['user'] ?>" required/>
<?php echo $error['user'] ?>
</div>
</br></br>
<input type="text" name ="password" id="userPassword" class="form-control input-sm chat-input" placeholder="Password" value= "<?php echo $input['password'] ?>" required/>
<div class="error"> <?php echo $error['pass'] ?>
</br></br>
<div class="wrapper">
<input type="submit" class="btn btn-primary" value="submit">
</div>
</div>
</div>
</form>
</div>
</div>
</body>
</html>
Edited October 28, 2020 by Alexa |
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