PHP - Check If String Is Integer Problem
Hello guys, I have a form where you can select a score between 0 and 10(only integers).
I want to check if the value that I recive, is integer.
Im using this code(exemple):
$integer = intval($_POST["p1"]); if(is_int($integer)){ echo 'INT'; } else { echo 'NO INT'; }My problem is that if it recive letters, the conversion converts it to 0, and it says that it is integer. So with this method I should discard the 0. You guys know a method to avoid that? Thank you guys Similar TutorialsHey, Im trying make a way to check an input to make sure it only consists of "1,2,3,4,5,6,7,8,9,0 and . " I thought i could explode the number and check it to an array that has "1,2,3,4,5,6,7,8,9,0 and . " I havent worked with arrays before so i dont quite know how they work or to go about this? Any ideas cause im sure im not the first to ask for something like this Thanks I am making a online Bible with search function. I was able to do the boolean search for text keywords without much trouble. Now I want a user to be able to type in an exact verse into search form and have that verse display in results. IE: User types in John 3:16 and search result displays that verse. The following works if the user types John:3:16. I cannot figure out how to do this without requiring the user to type a : after book name. Code: [Select] if($search_type=='verse'){ $query2 = explode(":", $query); $bookquery = $query2[0]; $chapterquery = $query2[1]; $versequery = $query2[2]; $result4 = $db->sql_query("select * FROM Bible$version WHERE book = '$bookquery' AND chapter= '$chapterquery' AND verse ='$versequery'"); while ($row = $db->sql_fetchrow($result4)) { $book = $row['book']; $chapter = $row['chapter']; $verse = $row['verse']; $scripture = $row['scripture']; echo "<b><a href=\"modules.php?name=Bible&call=chapter&viewbook=$book&viewchapter=$chapter&version=$version\">$book</a> $chapter:$verse</b>"; echo "<br>"; echo "$scripture"; echo "<hr>"; } if(!$query){ echo "<b>You did NOT enter any keywords.</b><br>"; } if(!$scripture){ echo "<b>No results found.</b>"; } } } Is there a function to find first integer in the string and insert a : before it? how can i convert string type into integer like when using parseInt in javascript...however i use (int)$string but not working i have this $string1="10"; $string2="5"; and i wish to add both string ....using (int) still treat $string1 and $string2 as string so i get 105 as a result instead of 15 $showCountSql = "select cad_count from counteraccountdtl WHERE cad_userid =".$_SESSION['UID']." LIMIT 1"; $showCountresult = mysql_query($showCountSql); $showCountrow = mysql_fetch_array($showCountresult); $newCount = $showCountrow[cad_count]; if(is_int($newCount)) echo "Value is Integer"; else echo "Value not Integer"; i m fetching value by Mysql "cad_count integer(5)" and feild then i cheak this value is interger or not it show the "Value not Integer". What is wrong in it ??? Hi, When I run the following code... <?php if ($_GET['view']) { echo 'test'; } .. and then navigate to index.php?view=1 the above code outputs 'test', as intended. The same goes for any non-zero value after the ?view= However, navigating to index.php?view=0 does not work as intended because it assumes that the 0 is FALSE. So if I modify the code, like this: <?php if ($_GET['view'] || $_GET['view'] == 0) { echo 'test'; } ... it outputs 'test' even when view is not set, i.e. when I navigate to index.php without the ?view=. Is there an easy way to force the value to behave as an integer instead of boolean? I have tried putting (int) before, as well as the intval() function, but neither seem to work. Thanks. I want to perform a query which returns a subset of the fields in a table. One particular mySQL field is VARCHAR I have a query like this: $query = mysql_query("SELECT * FROM table WHERE code LIKE '3%') ; It's my understanding this should return all values which begin with "3", but it only returns about a dozen of the values 3, 30-39, 300-399, etc. (It works with string fields, but this field contains numerals.) Any help appreciated. thanks, Tom <?php $temp = "01"; $temp = (int)temp; echo $temp; ?> I am using above code to convert string to integer variable but i am getting incorrect output.. somehow casting chopping values in the string. for example, above code should give me output 01 but actual output is 0. any pointer? i am new to php... Thanks, Rajesh How can i check if a string is URL encoded or not using PHP Hey, I have an if statement that requires to check a $_POST to make sure its an integer not a string but cant remember how to do this. Anyone able to assits Thanks Hello, I'm working on an error form, and I want to check if the user inserted a number into the name field, and if so return an error. I thought this might of worked, but it doesn't: Code: [Select] if(is_int($_POST['name'])){ $arrErrors['name'] = 'Invalid name, remove numbers.'; } Many thanks How do you find out how many character within a String ?? for example: $temp = "apple"; I want to return "5" for $temp as it has 5 characters. Thanks! Hi, How can i check if a string is a multiple of 0.1 without anything being left over? like 1.6 = true, 1.46 = false I want to allow Alphabetical strings, Numeric strings, and Alphanumeric strings. For example "Bob", "1234", "bob1234" are all valid. I want to check if the string has invalid characters, return true if it does (or false, which ever method works). How can I do it? I want to check if a string has any of words listed in array; Code: [Select] $array=array('word1', 'word2', 'word3'); $string="This is a sentence containing word2"; Now I want to make an 'if else' to check if the string contains any of the words listed in the array. Thanks Hi all, i've got a string ($currentcatid) which contains one number which changes dependant on which page the visitor is on.. ie it may be perhaps "23" or "17" . I need to do a check against this string to see if it contains any of the following values .. 31,32, 1, 24 . I cant remember how i did it before but i think it was with pipes.. something along the lines of if ($currentcatid =="31"||"32"||"1"||"24") { action } can anyone help? Thanks I was wondering if anyone knows a good way to check for an even number of each character in a string. For example if the string is "abbacc" then it will return true as there are two of each character. However if the string is "ababc" it will return false as there is only 1 c. Thanks for any help Hey. I been using a function to check if a string contains only letters which is: ctype_alpha But i would like to change it to allow numbers 0 to 9 and the letters is there a function to do that in PHP i can't find it. I have an array of $fl By using values of this array, i want to create a new string. I need string size will be maximum 200 characters. When i try below code snipped, $f value is added to string two times. How can i add $f to array only one time, with checking size of string. Thank you Code: [Select] $fl=getsomelist(); // gives an array $userList=''; foreach ($fl as $f) { if ( strlen($userList .= $f) <= (200) ) { $userList .= $f; } else { break; } } This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=327134.0 I have a web server which contains a public site and a private site. I want to be able to test for public or private using the page title and return the appropriate header which contains a different banner, css etc. Firstly - the syntax below seems to be incorrect because it doesnt work correctly. More importantly how do I add all the values to an array and than iterate through it to check for a matching page title? Code: [Select] public function publicSite() { if ($this->getTitle()== 'Home' || 'About Us'||'Registration' || 'Sitemap' || 'Contact Us' || 'Useful Links' || 'Feedback') { return true; } return false; } Then later on I would have: Code: [Select] if ($this->publicSite()) { require($ROOT.'interface/pages/publicheader.php'); } else { require($ROOT.'interface/pages/privateheader.php'); } Thanks heaps! |