PHP - Mysql Insert Error

Code: [Select]
$date = date('m-d-y');
$ip = $_SERVER['REMOTE_ADDR'];

mysql_query("INSERT INTO users VALUES ($username, $password, 0, $ip, $date)") or die(mysql_error());

Error:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.60.116, 03-06-11)' at line 1


I'm not sure why I get this error. :/

Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh!

<?php
  $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'";
  $results = mysqli_query($cxn, $query);
  $row_cnt = mysqli_num_rows($results);
  echo $row_cnt . " Total Records in Query.<br /><br />";
  if (mysqli_num_rows($results)) {
      while ($row = mysqli_fetch_array($results)) {
          $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error();
          $insert = mysqli_query($cxn, $insert_city_query);
          if (!$insert) {
              echo "INSERT is NOT working!";
              exit();
          }
          
          echo $row['City'] . "<br />";
          
          echo "<pre>";
          echo print_r($row);
          echo "</pre>";
      }
      //while ($rows = mysqli_fetch_array($results))
      
      } //if (mysqli_num_rows($results))
      
      else {
          echo "No results to get!";
      }
?>

Here is my all_illinois INSERT table structu

CREATE TABLE IF NOT EXISTS `all_illinois` (
  `state_id` varchar(255) NOT NULL,
  `city_name` varchar(255) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

Here is my source table geo_cities structu

CREATE TABLE IF NOT EXISTS `1` (
  `CityId` varchar(255) NOT NULL,
  `CountryID` varchar(255) NOT NULL,
  `RegionID` varchar(255) NOT NULL,
  `City` varchar(255) NOT NULL,
  `Latitude` varchar(255) NOT NULL,
  `Longitude` varchar(255) NOT NULL,
  `TimeZone` varchar(255) NOT NULL,
  `DmaId` varchar(255) NOT NULL,
  `Code` varchar(255) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated

I am trying to use text boxes to insert numbers into the database based on what is inputed.
If I have a string, like this for example:
$variable = 09385493;

And I want to insert it into the database like this:
mysql_query("INSERT INTO integers(number)
VALUES ('$variable')");

When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as
9385493

Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too.

Thanks

Can anyone see something wrong with this? It's driving me crazy and throwing up an error

Quote

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''user_name', 'user_email', 'user_credit', 'fname', 'lname', 'hous' at line 3


Code: [Select]
$sql_insert = ("INSERT INTO users
  (
'user_name',
'user_email',
'user_credit',
'fname',
'lname',
'house_num',
'addr',
'addr2',
'county',
'postcode',
'pwd',
'dobDay',
'dobMonth',
'dobYear',
'tel',
'date',
'users_ip',
'avatar'
)
    VALUES
    (
'".$user_name."',
'".$usr_email."',
'0.00',
'".$fname."',
'".$lname."',
'".$house_num."',
'".$addr."',
'".$addr2."',
'".$county."',
'".$postcode."',
'".$sha1pass."',
'".$dobDay."',
'".$dobMonth."',
'".$dobYear."',
'".$tel."',
'".$date."',
'".$user_ip."',
'/images/default/avatar.png'
)");
echo $sql_insert;
mysql_query($sql_insert,$link) or die(mysql_error());
I can't see what i wrong with it, i removed all the blank entries (ones with the value 'null',) but it didn't make any difference

i am currently in the process of creating a registration page for my website, i have managed to make it work and it adds the user to my main table user_info, however i also have other tables that i want the system to insert the user into when they join, such as a log for their ip address, the problem is i thought it would be a simple cas of selecting the user info and then inserting the fields into the ip_address table, but i keep getting the error

"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'terminated')' at line 1"

Anyway here is the code that i just added that created the error

Code: [Select]
$sql_id = ("SELECT * FROM user_info WHERE username = '$username'");

$result = mysql_query($sql_id);
$sql_result = mysql_fetch_array($result);

$sql = mysql_query("INSERT INTO ip_log (id, ip_log) VALUES ('$id', '$ipaddress'") or die (mysql_error());
And the code below is the code for the whole registration page.

Thanks

Code: [Select]
<?php
if (isset ($_POST['firstname'])){
 
 $firstname = $_POST['firstname'];
 $lastname = $_POST['lastname'];
 $username = preg_replace('#[^A-Za-z0-9]#i', '', $_POST['username']); // filter everything but letters and numbers
     $email = $_POST['email'];
     $password = $_POST['password'];
     $cpassword = $_POST['cpassword'];
 $paypal_email = $_POST['paypal_email'];
 $country = $_POST['country'];
 $kingdom_name = $_POST['kingdom_name'];
 $kingdom_motto = $_POST['kingdom_motto'];
 $referal = $_POST['referal'];
 
     $email = stripslashes($email); 
     $password = stripslashes($password); 
     $cpassword = stripslashes($cpassword); 
 
     $email = strip_tags($email);
     $password = strip_tags($password);
     $cpassword = strip_tags($cpassword);

     // Connect to database
     include_once "connect_to_mysql.php";
     $emailCHecker = mysql_real_escape_string($email);
 $emailCHecker = str_replace("`", "", $emailCHecker);
 // Database duplicate username check setup for use below in the error handling if else conditionals
 $sql_uname_check = mysql_query("SELECT username FROM user_info WHERE username='$username'"); 
     $uname_check = mysql_num_rows($sql_uname_check);
     // Database duplicate e-mail check setup for use below in the error handling if else conditionals
     $sql_email_check = mysql_query("SELECT email FROM user_info WHERE email='$emailCHecker'");
     $email_check = mysql_num_rows($sql_email_check);

     // Error handling for missing data
     if ((!$firstname) || (!$lastname) || (!$username) || (!$email) || (!$password) || (!$cpassword) || (!$paypal_email) || (!$kingdom_name) || (!$kingdom_motto)) { 

     $errorMsg = 'ERROR: You did not submit the following required information:<br /><br />';
  
     if(!$firstname){ 
       $errorMsg .= ' * Firstname<br />';
     } 
     if(!$lastname){ 
       $errorMsg .= ' * Lastname<br />';
     } 
 if(!$username){ 
       $errorMsg .= ' * Username<br />';      
     }
 if(!$email){ 
       $errorMsg .= ' * Email<br />';        
     } 
 if(!$password){ 
       $errorMsg .= ' * Password<br />';        
     } 
 if(!$cpassword){ 
       $errorMsg .= ' * Password Check<br />';      
     }
 if(!$paypal_email){ 
       $errorMsg .= ' * Paypal Email<br />';        
     } 
 if(!$kingdom_name){ 
       $errorMsg .= ' * Kingdom Name<br />';      
     }
 if(!$kingdom_motto){ 
       $errorMsg .= ' * Kingdom Motto<br />';        
     } 

     } else if ($password != $cpassword) {
              $errorMsg = 'ERROR: Your Password fields below do not match<br />';  
     } else if (strlen($username) < 4) {
           $errorMsg = "<u>ERROR:</u><br />Your User Name is too short. 4 - 20 characters please.<br />"; 
     } else if (strlen($username) > 20) {
           $errorMsg = "<u>ERROR:</u><br />Your User Name is too long. 4 - 20 characters please.<br />"; 
     } else if ($uname_check > 0){ 
              $errorMsg = "<u>ERROR:</u><br />Your User Name is already in use inside of our system. Please try another.<br />"; 
     } else if ($email_check > 0){ 
              $errorMsg = "<u>ERROR:</u><br />Your Email address is already in use inside of our system. Please use another.<br />"; 
     } else { // Error handling is ended, process the data and add member to database
     ////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

     $email = mysql_real_escape_string($email);
     $password = mysql_real_escape_string($password);
 
     // Add MD5 Hash to the password variable
     $db_password = md5($password); 
 

     // GET USER IP ADDRESS
     $ipaddress = getenv('REMOTE_ADDR');

     // Add user info into the database table for the main site table
     $sql = mysql_query("INSERT INTO user_info (firstname, lastname, username, email, password, country, sign_up_date) 
     VALUES('$firstname','$lastname','$username','$email','$password', '$country', now())")  
     or die (mysql_error());
 
     $id = mysql_insert_id();
 
 // Create directory(folder) to hold each user's files(pics, MP3s, etc.)
     mkdir("members/$id", 0755);
 
 ////////////////////////////////////////////////////////////////////////
 ///////////////BUILDING THE USER PROFILES///////////////////////////////
 
 $sql_id = ("SELECT * FROM user_info WHERE username = '$username'");
 
 $result = mysql_query($sql_id);
 $sql_result = mysql_fetch_array($result);
 
 $sql = mysql_query("INSERT INTO ip_log (id, ip_log) VALUES ('$id', '$ipaddress'") or die (mysql_error());
 
   include_once 'registration_success.php';

    
   exit();

   } // Close else after duplication checks

} else { // if the form is not posted with variables, place default empty variables so no warnings or errors show
  
  $errorMsg = "";
      $firstname = "";
  $lastname = "";
  $username = "";
  $email = "";
  $password= "";
  $cpassword = "";
  $paypal_email = "";
  $kingdom_name = "";
  $kingdom_motto = "";
  $referal = "";
}

?>

I don't understand where the empty value is. I've substituted the variables for text and still have the same problem.

Code:
Code: [Select]
$sql = "INSERT INTO courses (course#, name, subject, semester, ap)VALUES('$courseNum', '$courseName', '$subject', '$semester', '$ap')";
Error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

well this is truely embarrising...i have a insert statement which works within phpmyadmin but when using mysqli_query it returns a error.

INSERT INTO users (username, timestamp) VALUES ('test', UTC_TIMESTAMP())

  Unknown column 'timestamp' in 'field list'   i've been playing about with this for a few hours now ...tried changing the column name (timestamp), adding ` around column names as well as table name.   the column exists which is the strangest part, and ive even checked there is no space after the column name in the db.   whats going on please?  

I need help badly!

What I want to do is insert into database the value from the selected radio group buttons.. All of them. There are 10 radio groups total (they can be less, but not more).

Thanks!
Code: [Select]
<?php
   require_once('Connections/strana.php'); 
 mysql_select_db($database_strana, $strana);
 
 ?>
<link href="css/styles.css" rel="stylesheet" type="text/css" />

<table width="100%" height="100%" style="margin-left:auto;margin-right:auto;" border="0">
<tr>
<td align="center">
<form action="" method="post" enctype="multipart/form-data" name="form1">
<table>
<?php
$tema = mysql_query("SELECT * from prasanja where tip=2")or die(mysql_error());

function odgovor1($string)
{
$string1 = explode("/", $string);
echo $string1[0];
}
function odgovor2($string)
{
$string1 = explode("/", $string);
echo $string1[1];
}


while ($row=mysql_fetch_array($tema))
{
$id=$row['prasanje_id'];
$prasanje=$row['prasanje_tekst'];
$tekst=$row['odgovor'];
?>
    <tr>
    <td>
    </td>
    </tr>
    <tr>
    <td class="formaP">
 <?php echo $prasanje?>
   </td>
   </tr>
   <tr>
   <td class="formaO">
      <p>
        <label>
          <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor1($tekst) ?>"  />
          <?php odgovor1($tekst) ?></label>
        <br />
        <label>
          <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor2($tekst) ?>" />
          <?php odgovor2($tekst) ?></label>
        <br />
      </p></td>
</tr>
<tr>
<td>
<br />

</td>
</tr>
<?php 




}
?>
</table>
<input align="left"type="submit" name="submit"
value="Внеси" >
</form>
</td>
</tr>
</table>
prasanje = question
tekst/odgovor = answer

The answer table:
id - primary
question_id - the questions ID whose answer is selected in the radio group
user_id - cookie takes care of this
answer - the value from radio group
date - automatic

Hi guys

I have a registration form working fine, my database is as below:

userid
username
email
password
repeatpassword


I have added another column which is "name", users can update their profile once they have logged in so I have created updateprofile.php and when I login-->go to update profile and insert my name nothing adds to mysql name column

this is my code below:

<?php

include ("global.php");


//username session
$_SESSION['username']=='$username';
$username=$_SESSION['username'];

//welcome messaage
echo "Welcome, " .$_SESSION['username']."!<p>";

  if ($_POST['register'])
    {
     //get form data
     $name = addslashes(strip_tags($_POST['name']));

$update = mysql_query("INSERT INTO users (name) VALUES ('$_POST[name]') WHERE username='$username'");
   
}

?>

    <form action='updateprofile.php' method='POST'>
    Company Name:<br />
    <input type='text' name='name'><p />
 
    <input type='submit' name='register' value='Register'>
    </form>


can you please tell me where in this code is wrong? Im new in php so please excuse me if I have silly mistakes.

thanks in advance
 

I have this code: <?php
$con = mysql_connect("localhost","hhh","hhh");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("hhh", $con);

// --------------------
// Avatar insert check
// --------------------

session_start();

$name = $_POST[name];
$group = $_POST[group];
$age = $_POST[age];
$usernameid = $_SESSION[id];

$result = mysql_query("SELECT * FROM avatars WHERE name='$_POST[name]'");

$num = mysql_numrows($result);

if ($num == 0) {
mysql_query("INSERT INTO avatars (id, usernameid, name, group, age, xp)
VALUES ('', '$usernameid', '$name', '$group', '$age', '0')");

header( 'Location: me/' ) ;
}
else echo 'Sorry, please pick a new name';
?> And it does everything but put the data into the datebase. If I add a session befor and after '$request' they both run, but the sql doesn't. No error returns, if just redirects to the other page. Any help?

Hi,
I am working on a script that will add 3 sets of information to a MySQL table. I had a script that had the fields of username password and password2. It worked just fine when password2 was used for verification to make sure you typed it right.
But now I want to take password and turn it into a new data field that is submitted into the new row with the other information.
The problem is it wont add the row. The script says it worked just fine but i check the db and no new row.
here it is:
<?php // Connects to your Database 
 mysql_connect("//", "//", "//") or die(mysql_error()); 
 mysql_select_db("//") or die(mysql_error()); 
 //This code runs if the form has been submitted
 if (isset($_POST['submit'])) { 
 
 //This makes sure they did not leave any fields blank
 if (!$_POST['username'] | !$_POST['pass'] | !$_POST['pass2'] ) {
  die('You did not complete all of the required fields');
  }
 
 // checks if the username is in use
  if (!get_magic_quotes_gpc()) {
  $_POST['username'] = addslashes($_POST['username']);
  }
 $usercheck = $_POST['username'];
 $check = mysql_query("SELECT username FROM users WHERE username = '$usercheck'") 
 or die(mysql_error());
 $check2 = mysql_num_rows($check);
 
 //if the name exists it gives an error
 if ($check2 != 0) {
  die('Sorry, the username '.$_POST['username'].' is already in use.');
  }
 // this makes sure both passwords entered match
  if ($_POST['pass'] != $_POST['pass']) {
  die('Your passwords did not match. ');
  }
 
  // here we encrypt the password and add slashes if needed
  $_POST['pass'] = md5($_POST['pass']);
  if (!get_magic_quotes_gpc()) {
  $_POST['pass'] = addslashes($_POST['pass']);
  $_POST['username'] = addslashes($_POST['username']);
  $_POST['pass2'] = addslashes($_POST['pass2']);
  }
 
 // now we insert it into the database
  $insert = "INSERT INTO users (username, password, Human-Readable)
  VALUES ('".$_POST['username']."', '".$_POST['pass']."', '".$_POST['pass2']."')";
  $add_member = mysql_query($insert);
  ?>
 
 <h1>Registered</h1>
 <p>Thank you, you have registered - you may now login</a>.</p>
 <?php } 
 else {  ?>
 <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
 <table border="0">
 <tr><td>Username:</td><td>
 <input type="text" name="username" maxlength="60">
 </td></tr>
 <tr><td>Password:</td><td>
 <input type="password" name="pass" maxlength="10">
 </td></tr>
 <tr><td>HR:</td><td>
 <input type="password" name="pass2" maxlength="10">
 </td></tr>
 <tr><th colspan=2><input type="submit" name="submit" 
value="Register"></th></tr> </table>
 </form>
 <?php
 } ?> 
And incase you want to see it here is the original:
<?php // Connects to your Database 
 mysql_connect("//", "//", "//") or die(mysql_error()); 
 mysql_select_db("//") or die(mysql_error()); 
 //This code runs if the form has been submitted
 if (isset($_POST['submit'])) { 
 
 //This makes sure they did not leave any fields blank
 if (!$_POST['username'] | !$_POST['pass'] | !$_POST['pass2'] ) {
  die('You did not complete all of the required fields');
  }
 
 // checks if the username is in use
  if (!get_magic_quotes_gpc()) {
  $_POST['username'] = addslashes($_POST['username']);
  }
 $usercheck = $_POST['username'];
 $check = mysql_query("SELECT username FROM users WHERE username = '$usercheck'") 
 or die(mysql_error());
 $check2 = mysql_num_rows($check);
 
 //if the name exists it gives an error
 if ($check2 != 0) {
  die('Sorry, the username '.$_POST['username'].' is already in use.');
  }
 // this makes sure both passwords entered match
  if ($_POST['pass'] != $_POST['pass2']) {
  die('Your passwords did not match. ');
  }
 
  // here we encrypt the password and add slashes if needed
  $_POST['pass'] = md5($_POST['pass']);
  if (!get_magic_quotes_gpc()) {
  $_POST['pass'] = addslashes($_POST['pass']);
  $_POST['username'] = addslashes($_POST['username']);
  }
 
 // now we insert it into the database
  $insert = "INSERT INTO users (username, password)
  VALUES ('".$_POST['username']."', '".$_POST['pass']."')";
  $add_member = mysql_query($insert);
  ?>
 
 <h1>Registered</h1>
 <p>Thank you, you have registered - you may now login</a>.</p>
 <?php } 
 else {  ?>
 <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
 <table border="0">
 <tr><td>Username:</td><td>
 <input type="text" name="username" maxlength="60">
 </td></tr>
 <tr><td>Password:</td><td>
 <input type="password" name="pass" maxlength="10">
 </td></tr>
 <tr><td>Confirm Password:</td><td>
 <input type="password" name="pass2" maxlength="10">
 </td></tr>
 <tr><th colspan=2><input type="submit" name="submit" 
value="Register"></th></tr> </table>
 </form>
 <?php
 } ?> 

Many Thanks in advanced

<?php
//$passwordVerify = password_verify($userInput, $passwordInput);
    $con = mysqli_connect("127.0.0.1","root","");     if (!$con)     {         die('Could not connect: ' . mysqli_error());     }       /*if($con){           die('Database connected successfuly.');       }*/     $sql="CREATE DATABASE IF NOT EXISTS 'itech3108_30124248_a1'";               $runquery = mysqli_query($con,$sql);     if(!mysqli_select_db($con, "itech3108_30124248_a1"))     {         die('Database not connected: ' . mysqli_error());     }
    session_start();
    if(isset($_POST['register']))
    {    
        //for image uploading......................
        $files = $_FILES['file'];
        $filename = $files['name'];
        $filrerror = $files['error'];
        $filetemp = $files['tmp_name'];
        $fileext = explode('.', $filename);
        $filecheck = strtolower(end($fileext));
        $fileextstored = array('png' , 'jpg' , 'jpeg');

        if(in_array($filecheck, $fileextstored)){

            $destinationfile = 'img/'.$filename;
            move_uploaded_file($filetemp, $destinationfile);
        }
        $name = $_POST['username'];
        $email = $_POST['email'];
        $confirm = $_POST['confirm'];
        $profile=$_POST['profile'];
       /*$file_ext= null;
        if(isset($_FILES['image'])){
            $errors= array();
            $file_name = $_FILES['image']['name'];
            $file_size =$_FILES['image']['size'];
            $file_tmp =$_FILES['image']['tmp_name'];
            $file_type=$_FILES['image']['type'];
            $file_ext=strtolower(end(explode('.',$_FILES['image']['name'])));
           
            $extensions= array('jpeg','jpg','png');
           
            if(in_array($file_ext,$extensions)=== false){
               $errors[]='extension not allowed, please choose a JPEG or PNG file.';
            }
           
            if($file_size > 2097152){
               $errors[]='File size must be excately 2 MB';
            }
           
            if(empty($errors)==true){
               move_uploaded_file($file_tmp,'img/'.$file_name);
               //echo 'Success';
            }else{
               print_r($errors);
            }
         }
        //$passwordhash = null;
        /*
        if (CRYPT_BLOWFISH == 1)
        {
            $passwordhash = password_hash($password ,PASSWORD_BCRYPT);
        }
        else
        {  
            echo '<script>alert('Blowfish DES not supported.');
            window.location='reg.php';</script>';
        }...............................................................*/
       // die('photo url='. $destinationfile.'name='.$name.'email='.$email.'password='.$password.'profile='.$profile);
        $sql = "INSERT INTO user ('name','email','password','profile') SET ('$name','$email','$confirm','$profile,'$destinationfile')" ;
       // $query="INSERT INTO 'user' ('id','name','email','password','profile','photo') VALUES( ?,?,?,?,?,?) ";
       // $stmt = mysqli_prepare($con, $query) or die(mysqli_error($con));
       // $stmt->bind_param($stmt,'Null',$name,$email,$confirm,$profile,$destinationfile);
        //$stmt->execute();

        //$stmt = mysqli_prepare($con, "INSERT INTO 'user' ('name','email','password','profile','photo') VALUES( ?,?,?,?,?) ");
       // mysqli_stmt_bind_param($stmt, $name,$email,$confirm,$profile,$destinationfile);
       // mysqli_stmt_execute($stmt);
               
        $runquery = mysqli_query($con,$sql);
        //echo 'query'.$runquery;
        if(!$runquery)
        {
           
             die( mysqli_error($con));
        }
        else
        {
            echo '<script>alert("User successfully registered.");
            window.location="login.php";</script>';
        }
    }
    //mysqli_query.close();
    if(isset($_SESSION['name']))
    {
        header('Location:profilepage.php');
    }
?>

<!DOCTYPE html>
<html>
<head>
    <title>Sign Up Page</title>
    <link href='https://fonts.googleapis.com/css?family=Lobster|Montserrat' rel='stylesheet'>
    <link rel='stylesheet' type='text/css' href='stylesheet/register.css'>
</head>

    <header>
        <nav>
            <h1>find Your Love</h1>
            <ul id='navli'>
                <li><a class='homeblack' href='home.php'>Home</a></li>
            </ul>
        </nav>
    </header>
    <style>
        body{
            background-image: url('img/love.jpg');
            background-repeat: no-repeat;
            background-attachment: fixed;
            background-size: cover;}
    </style>
    <div class='divider'></div>
   
        <div class='loginbox'>
        <img src='img/love2.jpg' class='avatar'>
            <h1>Signup </h1>
            <form action='reg.php' method='POST'enctype='multipart/form-data'>
                <p>User Name</p>
                <input type='text' id='username' name='username' placeholder='Enter Username' required='requiored'></p>
               
                <p>Email</p>
                <input type='Email' id='email' name='email' placeholder='Enter email' required='required'>
               
                <p>Password</p>
                <input type='password' id='password' name='password' placeholder='Enter password' required='required'>

                <p>Confirm Password</p>
                <input type='password' id='confirm' name='confirm' placeholder='re-enter password' required='required'>

                <p> upload Image</p>
                <input class="input--style-1" type="file" placeholder="file" name="file">

                <p>Your Words</p>
                <input type='textbox' id='profile' name='profile' placeholder=' your words to describe your self' required='required'>
   
                <input type='submit' name='register' value='Sign Up'>

                <div class='divider'></div>
                <h6><a href='login.php'>Already Have Account ? </a></h6>
            </form>  
        </div>
    </body>
</html>

 

I am having an error with this code

You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ''name','email','password','profile') SET ('Sasural','kill@1234.com','kill','ANDK' at line 1

I am stuck with this for last 5hrs