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PHP - Create Dropdown From One Table And Set Focus Based On Entry In Another ..
Hi all,
firstly apologies as this is a cross post from another forum and we have hit a block.. I am hoping that opening this up to another set of gurus we can get a resolution. What I am trying to achieve is this... I have 2 tables Main and FinancialYear. Main holds all data which I use a form to post the data to it..(all works fine). I use this code to create a drop down in the insert.php form. again this works. Code: [Select] <tr><td>Financial Year: xxxx/xxxx</td><td> <!-- pulls the data from the table variable to populate the dropdown menu --> <?php $database = 'Projects_Main'; $fintable = 'FinancialYear'; if (!mysql_connect($db_host, $db_user, $db_pwd)) die("Can't connect to database 'cos somethin' is wrong"); if (!mysql_select_db($database)) die("Can't select database"); $result = mysql_query("SELECT FinancialYear_id, FinancialYear FROM {$fintable} order by FinancialYear"); $options=""; while ($row=mysql_fetch_array($result)) { //$id=$row["FinancialYear_id"]; $thing=$row["FinancialYear"]; $options.="<OPTION VALUE=\"$thing\">".$thing.'</option>'; } ?> <SELECT NAME="FinancialYear"> <OPTION VALUE=0>Choose</OPTION> <?=$options?> </SELECT> </td></tr> What I have done is built another form which list all records in the database and creates an update url for every record that passes the field Project_id where i use $_get to retrieve the Project_id to retrieve the relevant data into the update.php form. I am able to populate the form with all the correct information BUT I am looking to introduce some dropdowns to aid updating the data and provide consistency to the data. . Code: [Select] // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db('Projects_Main')or die("cannot select DB"); // get value of id that sent from address bar $Project_id=$_GET['Project_id']; //define vars $FinancialYear=$_POST['FinancialYear']; // other vars defined here also.. about 30 // Retrieve data from database $sql="SELECT * FROM Main WHERE Project_id='$Project_id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> //update_record_ac.php posts the data to the dbase. <form name="form1" method="post" action="update_record_ac.php"> <center> <table> <tr><td><b>Store Details<b></td></tr> <tr><td>Financial Year:</td><td> // takes the data from $rows and present to form <input name="FinancialYear" type="text" id="FinancialYear" value="<?php echo $rows['FinancialYear']; ?>"> // this is where I need to create the drop down.. see my other comments in the post..... </td></tr> the financialYear table consists if the following; financialyear_id - pri, auto inc. ---- data format is 2010/2011, 2011/2012.... financialyear the main table contains 30 fields .. won't list em all... Project_id - pri, auto inc financialyear I need the drop down to pull the data from the financialyear table and then to present or focus on the currently stored data... so if the store value in the table Main is 2010/2011 if Ii was to select the update url in the list_record.php it will pull all the relevant data into update_record.php form. the financialyear field in the form should be a dropdown with all the financial years listed but the 2010/2011 is selected or focused. I still need to be able to change the entry and post this back to the table Main..... So the dropdown contains the list of years from the financialyear table but when the record is pulled from table main the year that is stored in table Main should be highlighted in the dropdown and I should be able to select a new record and post back to the table Main.. any thoughts... please don't slate for the cross post, I haven't sanatised the data at any stage. I know i'm open to injection attacks. and yes my code is a little dirty... all these will be rectified as i finalise the process and ensure the consept works. Thanks for taking the time to read and hopefully you are able to understand the requirement and are able to assist. thanks Balgrath Similar TutorialsHello all,
For the UPDATE portion of my CRUD WebApp what I would like to do is to bring in (and display) the values (of a selected row) from my transaction table.
This is working just fine for all fields which are of the "input type". The problem I'm having is with two fields which are of the "select type" i.e. dropdown listboxes.
For those two fields, I would like to bring in all the valid choices from the respective lookup/master tables, but then have the default/selected value be shown based on what's in the transaction table. The way I have it right now, those two fields are showing (and updating the record with) the very first entry's in the two lookup tables/select query.
The attached picture might make things a little bit clearer. You'll notice in the top screenshot that the first row (which is the one I'm selecting to update) has a "Store Name" = "Super Store" and an "Item Description" = "Old Mill Bagels". Now, when I click the "update" botton and I'm taken to the update screen, the values for those two fields default to the very first entries in the SELECT resultset i.e. "Food Basics" and "BD Cheese Strings". Cricled in green (to the top-left of that screenshot) is the result of an echo that I performed, based on the values that are in the transaction record.
I cannot (for the life of me) figure out how to get those values to be used as default/selected values for the two dropdown's...so that if a user does not touch those two dropdown fields, the values in the transaction table will not be changed.
Your help will be greatly appreciated.
Here's a portion of the FORM code:
<form class="form-horizontal" action="update.php?idnumber=<?php echo $idnumber?>" method="post">
<?php
// Connect to Store_Name (sn) table to get values for dropdown
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "SELECT DISTINCT store_name FROM store_master ORDER BY store_name ASC";
$q_sn = $pdo->prepare($sql);
$q_sn->execute();
$count_sn = $q_sn->rowCount();
$result_sn = $q_sn->fetchAll();
Database::disconnect();
// Connect to Item_Description (id) table to get values for dropdown
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "SELECT DISTINCT product_name FROM product_master ORDER BY product_name ASC";
$q_id = $pdo->prepare($sql);
$q_id->execute();
$count_id = $q_id->rowCount();
$result_id = $q_id->fetchAll();
Database::disconnect();
foreach($fields AS $field => $attr){
$current_store_name = $values['store_name'];
$current_item_description = $values['item_description'];
//Print the form element for the field.
if ($field == 'store_name')
{
echo $current_store_name;
echo '<br />';
echo $current_item_description;
echo '<div class="control-group">';
echo "<label class='control-label'>{$attr['label']}: </label>";
echo '<div class="controls">';
//Echo the actual input. If the form is being displayed with errors, we'll have a value to fill in from the user's previous submission.
echo '<select class="store-name" name="store_name">';
// echo '<option value="">Please select...</option>';
foreach($result_sn as $row)
{
echo "<option value='" . $row['store_name'] . "'>{$row['store_name']}</option>";
}
// $row['store_name'] = $current_store_name;
echo "</select>";
echo '</div>';
echo '</div>';
}
elseif ($field == 'item_description')
{
echo '<div class="control-group">';
echo "<label class='control-label'>{$attr['label']}: </label>";
echo '<div class="controls">';
echo '<select class="item-desc" name="item_description">';
// echo '<option value="">Please select...</option>';
foreach($result_id as $row)
{
echo "<option alue='" . $row['product_name'] . "'>{$row['product_name']}</option>";
}
echo "</select>";
echo '</div>';
echo '</div>';
}
else
{
echo '<div class="control-group">';
echo "<label class='control-label'>{$attr['label']}: </label>";
echo '<div class="controls">';
//Echo the actual input. If the form is being displayed with errors, we'll have a value to fill in from the user's previous submission.
echo '<input type="text" name="'.$field.'"' . (isset($values[$field]) ? ' value="'.$values[$field].'"' : '') . ' /></label>';
echo '</div>';
echo '</div>';
}
And here's some other declarations/code which I think might be required.
$fields = array(
'store_name' => array('label' => 'Store Name',
'error' => 'Please enter a store name'),
'item_description' => array('label' => 'Item Description',
'error' => 'Please enter an item description'),
'qty_pkg' => array('label' => 'Qty / Pkg',
'error' => 'Please indicate whether it\'s Qty or Pkg'),
'pkg_of' => array('label' => 'Pkg. Of',
'error' => 'Please enter the quantity'),
'price' => array('label' => 'Price',
'error' => 'Please enter the price'),
'flyer_page' => array('label' => 'Flyer Page #',
'error' => 'Please enter the flyer page #'),
'limited_time_sale' => array('label' => 'Limited Time Sale',
'error' => 'Please enter the days for limited-time-sale'),
'nos_to_purchase' => array('label' => 'No(s) to Purchase',
'error' => 'Please enter the No. of items to purchase')
);
...
...
....
{
// If [submit] isn't clicked - and therfore POST array is empty - perform a SELECT query to bring in
// existing values from the table and display, to allow for changes to be made
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "SELECT * FROM shoplist where idnumber = ?";
$q = $pdo->prepare($sql);
$q->execute(array($idnumber));
$values = $q->fetch(PDO::FETCH_ASSOC);
if(!$values)
{
$error = 'Invalid ID provided';
}
Database::disconnect();
}
If there's anything I've missed please ask and I'll provide.
Thanks
This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=323045.0 Hi This should be pretty simple but I can't figure it out.
I want to create and simple forward to different URL based on the user entry.
For example.. If they enter ABC in the box they go to www.11.com if they enter ZXC in the box they go to www.22.com if they enter CCC they go to www.33.com If they enter anything else they get an error message.
Thanks for any help!!
Hello. I'm not a php programmer. I just play one on the internet. Point being that I know enough to make small things happen and can slop some code together for little ideas. For my newest idea, I'm trying to have a user submitted form that requires admin approval. I know how to create a form and do the mysql insert, but how I do create a "hold" on the data being sent from a form, so that I can require approval? I'm looking for the easiest way.. If I need to approve directly through mysql (instead of creating an admin.php page), then that would be fine. I don't anticipate a lot of submissions. Just wasn't sure how this is usually handled. Thanks! I'm looking at shared hosting provided by GoDaddy. On the shared hosting they offer, entry process limitations range from 100 to 125.
I was also told this by customer support:
Entry Processes are the number of connections your account can process simultaneously. Understanding what constitutes a connection is important, though, because it's not as straightforward as "the number of visitors on your website." Here's what constitutes as a connection: Your website delivering data via HTTP Your hosting account transferring data via SSH A Cron job processing However, the connections are only counted while they're processing. As soon as they've finished, they no longer count as processes. For an example, if a visitor comes to your site and your home page takes .1 seconds to load and generates only one HTTP connection, that visitor counted as one process for .1 seconds. Even though that visitor is still "viewing your site," they no longer count as a connection until they do something else that generates another connection, like move to a new page. So what is an average user count that I can conclude? I don't want to think that "it's not possible" I just need to know what limitations I'm looking at. I'm also curious what kind of error would be generated if more than 100 or 125 people tried to access the server simulataneously. Or perhaps employ an access delay of some sort. Edited by moose-en-a-gant, 10 January 2015 - 09:59 PM. Hey guys, I am wanting to select a dropdown value based on the value of 'level' in the row of the user select by a $_GET. It will house the ranks of the user. Here is my script. RANK <?php mysql_connect("localhost","root","") or die(mysql_error()); mysql_select_db("chat"); $result = mysql_query("SELECT * FROM users WHERE user_id = '$_GET[id]'"); $row = mysql_num_rows($result); ?> <form id="main_form" name="main_form" method="post" action=""> <select name="rank"> <option value="0" <?php if($row['level']=="0") { echo "selected"; }?>>Unactivated</option> <option value="1" <?php if($row['level']=="1") { echo "selected"; }?>>Banned</option> <option value="2" <?php if($row['level']=="2") { echo "selected"; }?>>Regular User</option> <option value="3" <?php if($row['level']=="3") { echo "selected"; }?>>Donator</option> <option value="4" <?php if($row['level']=="4") { echo "selected"; }?>>Moderator</option> <option value="5" <?php if($row['level']=="5") { echo "selected"; }?>>Administrator</option> <option value="6" <?php if($row['level']=="6") { echo "selected"; }?>>Owner</option> </select> <input type="submit" id="main_submit" name="main_submit" value="submit" /> </form> It is not selecting for some reason at all. Can someone tell me what I am doing wrong? Hello, i'm trying to query mysql to show table contents, my code so far is this: Code: [Select] mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM codes"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); to show content: Code: [Select] <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"id"); $f2=mysql_result($result,$i,"code"); $f3=mysql_result($result,$i,"secret"); $f4=mysql_result($result,$i,"date"); $f5=mysql_result($result,$i,"ip"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> </tr>Now this shows all the content from the table, what i want to have is 2 scripts which should work like this: Script1 to show table contents: ID1, ID2, ID4, ID5, ID7, ID8 and so on. Script2 to show table contents: ID3, ID6, ID9 and so on. Basically one that shows only every 3rd and skips 1 and 2, and another one that skips every 3rd. Is this possible ? Thanks ! how do i this? i have no idea....i need to incorporate it on an html form pleas help? i will get the data from this line and must be able to select one from the dropdown and get the id/name from the one selected [COLOR="Red"]$supplier_names = LpmAdnetworkPeer::getByName($catcher_id);[/COLOR] thank you Looking for tutorials, but maybe the forum's quicker. Can anybody give me a loose idea how to do this? I have a sequence of pages that the user goes through to enter information. I need to move a page up to pull data before inputting to the database - to prevent some dropped entries and errors. Before, it was using info in the database to loop through and generate data. I want to do it just based on the info in an array: I want array(217 => 1, 215 => 2); to loop generate a form that loops through to create something like: Code: [Select] <form> Student one, Class 217<br> First name: <input type="text" name="fname[]" id="fname" onfocus="this.className='reg_live';" onblur="this.className='reg_off';" /> Last name: <input type="text" name="fname[]" id="fname" onfocus="this.className='reg_live';" onblur="this.className='reg_off';" /> <br><hr><br> Student one, Class 215<br> First name: <input type="text" name="fname[]" id="fname" onfocus="this.className='reg_live';" onblur="this.className='reg_off';" /> Last name: <input type="text" name="fname[]" id="fname" onfocus="this.className='reg_live';" onblur="this.className='reg_off';" /> <br><br> Student one, Class 215<br> First name: <input type="text" name="fname[]" id="fname" onfocus="this.className='reg_live';" onblur="this.className='reg_off';" /> Last name: <input type="text" name="fname[]" id="fname" onfocus="this.className='reg_live';" onblur="this.className='reg_off';" /> <br><hr><br> and so on. <input type="submit" value="Register" /></form> Preferably using PHP, I'd like to create X number of colors based on X number of items and using a predefined color range. For example: ITEM VALUE 1 1,234,567,890 2 234,567,890 3 34,567,890 4 4,567,890 5 567,890 Color Range red = largest value green = medium value blue = smallest value Example Item 1 gets color red Item 2 gets whatever color naturally comes between red and green Item 3 gets color green Item 4 gets whatever color naturally comes between green and blue Item 5 gets color blue Requirements The code should be able to handle any number of items. 5 items was just an easy example. Some Thoughts - Number of items = number of colors - How to divide a color range into number of items? - Colors can be represented in decimal format: red=255,000,000 blue=000,000,255 - Can a formula be created, based on the color decimal format, to solve this problem? I think it's the math portion of the problem that I'm stuck on right now. Thanks for your help, Nick Hi, I am hoping someone can help me out with a slight issue I have with php and mySQL. I have an ajax-powered form with a select (dropdown) field populated through a php function. Based on the user-selected values in this field, data is displayed on the webpage; i.e. selected value 1 returns values x and y on the page. I am now trying to call additional data (value z) from a different table in the same database, and as before, use the selected values from the dropdown to display the data. For some reason, value z is not changing according to the user-selected value. This is my code: [The function to populate the select field] Code: [Select] function kfl_get_funds_names() { $result = array(); $result['CDF'] = 'Crosby Dragon Fund'; $result['CPF'] = 'Crosby Phoenix Fund'; $result['AMZPIF'] = 'AMZ Plus Income Fund'; $result['KASBIIF'] = 'KASB Islamic Income Opportunity'; $result['KASBCPGF'] = 'KASB Capital Protected Gold Fund'; $result['KASBLF'] = 'KASB Income Opportunity Fund'; $result['KASBCF'] = 'KASB Cash Fund'; $result['KASBBF'] = 'KASB Asset Allocation Fund'; $result['KASBSMF'] = 'KASB Stock Market Fund'; return $result; } [the code calling and using the function to interact with the database] Code: [Select] $funds_to_display = kfl_get_funds_names(); $current_symbol = key( $funds_to_display ); $current_nav_rates = kfl_get_latest_rates( $current_symbol ); [the code calling additional data, value z, from the database, and using the info in the select field to filter it] Code: [Select] $cutoff = kfl_cutoff( $current_symbol ); The display of each of these items is as follows: Code: [Select] <?php echo $current_nav_rates['nav_date']; ?> <?php echo $funds_to_display[$current_symbol]; ?> <?php echo $cutoff['cutoff']; ?> I can't get the $cutoff code to display the correct values. It picks up the first symbol to display and doesn't change with user selection. The code for the selection box, by the way: Code: [Select] <select id="dailynav-funds" autocomplete="off" name="dnf"> <?php foreach ($funds_to_display as $fund_symbol => $fund_name) { echo '<option'; if( $fund_symbol == $current_symbol ) { echo ' selected="selected"'; } echo ' value="' . $fund_symbol . '">'; echo $fund_name; echo '</option>'; } ?> </select> I've tried to get data using $_GET['dnf'] into the cutoff code, but that throws up parse errors. What am I doing wrong, and how can I resolve this issue? Thanks in advance! How to create Dependent Dropdown List?
<div class="form-group">
<label class="control-label col-sm-2" for="i_have">I have :</label>
<div class="col-sm-10">
<select id="old" class="form-control" placeholder="Select I have" name="i_have">
<option value = "select_option">Select Option</option>
<option value = "three_compact">3 Compact</option>
<option value = "three_regular">3 Regular</option>
<option value = "three_triple">3 Triple</option>
<option value = "five_compact">5 Compact</option>
<option value = "five_regular">5 Regular</option>
<option value = "five_triple">5 Triple</option>
<option value = "seven_compact">7 Compact</option>
<option value = "seven_regular">7 Regular</option>
<option value = "seven_triple">7 Triple</option>
<option value = "nine_compact">9 Compact</option>
<option value = "nine_regular">9 Regular</option>
<option value = "nine_triple">9 Triple</option>
</select>
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-2" for="i_want">I want :</label>
<div class="col-sm-10">
<select id="new" class="form-control" placeholder="Select I want" name="i_want">
<option value = "select_option">Select Option</option>
<option value = "three_compact">3 Compact</option>
<option value = "three_regular">3 Regular</option>
<option value = "three_triple">3 Triple</option>
<option value = "five_compact">5 Compact</option>
<option value = "five_regular">5 Regular</option>
<option value = "five_triple">5 Triple</option>
<option value = "seven_compact">7 Compact</option>
<option value = "seven_regular">7 Regular</option>
<option value = "seven_triple">7 Triple</option>
<option value = "nine_compact">9 Compact</option>
<option value = "nine_regular">9 Regular</option>
<option value = "nine_triple">9 Triple</option>
</select>
</div>
</div>
If the first dropdown "3 Compact " is selected second dropdown should not be able to select "3 Compact" & if first dropdown "5 Regular" is selected second dropdown should not be able to select below values of 5 Regular like "3 Compact, 3 Regular, 3 Triple, 5 Compact. The logic is, if first dropdown value selects like 5, second dropdown value must select above 5 not 4 or 3 or 2 or 1. I'm attempting to create a dropdown hover menu by following the instructions on the Suckerfish site. The list that is supposed to dropdown simply stays visible all the time. Is there anything in the code that seems to be the apparent cause of the problem? You will be able to tell that I'm new to PHP. Any suggestions would be appreciated. The following is my CSS and PHP code: CSS: Code: [Select] #nav, #nav ul{ padding: 0; margin: 0; list-style: none; } #nav a{ display: block; width: 10em; } #nav li{ float: left; width: 10em; } #nav li ul{ position: absolute; width: 10em; left: -999em; } #nav li: hover ul{ left: auto; } #nav li:hover ul, #nav li.sfhover ul{ left: auto; } PHP/JavaScript: Code: [Select] function draw_app_menu() { // draw the application menu ?> <!-- left - background-color: #cdeb8b - lime --> [color=blue]<script type="text/javascript"> shHover = function() { var sfEls = document.getElementByID("nav").getElementsByTagName("LI"); for (var i=0; i<sfEls.length;i++) { sfEls[i].onmouseover=function() { this.className+=" sfhover"; } sfEls[i].onmouseout=function() { this.className=this.className.replace(new RegExp(" sfhover\\b"), ""); } } } if (window.attachEvent) window.attachEvent("onload",sfhover); </script>[/color] [color=green]<ul id = "nav">[/color] <?php session_start(); if (isset($_SESSION['selected_app'])) { // echo '<p> selected_app was set </p>'; foreach ($_SESSION['application_list'] as $app_list) { if (($app_list[5] == 'A') && ($app_list[0] == $_SESSION['selected_app'])) { $_SESSION['current_link'] = $app_list[2]; } if (($app_list[0] == $_SESSION['selected_app']) && (($app_list[5] == 'M') || ($app_list[5] == 'S'))) { if ($app_list[5] == 'M') { ?> [color=green]<li><a href="<?php echo $_SESSION['current_link'].'?id='.$_SESSION['selected_app'].'&modid='.$app_list[3].'&func='.$app_list[6];?>"><?php echo $app_list[1];?></a></li>[/color] <?php $_SESSION['selected_mod'] = $_GET['modid']; $_SESSION['app_function'] = $_GET['func']; } ?> [color=green] <ul>[/color] <?php if ($app_list[5] == 'S') { ?> [color=green]<li><a href="<?php echo $_SESSION['current_link'].'?id='.$_SESSION['selected_app'].'&modid='.$app_list[3].'&submodid='.$app_list[4].'&func='.$app_list[6];?>"><?php echo $app_list[1];?></a></li>[/color] <?php $_SESSION['selected_mod'] = $_GET['modid']; $_SESSION['selected_submod'] = $_GET['submodid']; $_SESSION['app_function'] = $_GET['func']; } ?> [color=green]</ul> </li>[/color] <?php } } } ?> [color=green]</ul>[/color] <script src="sfhover.js" type="text/javascript"></script> <?php } Hi,
I am a bit of a MYSQL newbie so please bear with me. I have a database created about football/soccer stats. The database at the moment contains the following tables but more maybe added:
Players
Clubs
Seasons
Competitions
I will create php pages for these tables that add, edit and delete records for each. But the problem I can't get my head around is how to add a record that uses data from other tables, for example we would add a...
player -> club-season-competition
Lets say we want create a player called 'Joe Bloggs' and want to add his details, we need somehow for the page to display an option for club, season and competition. Maybe they can be drop down boxes but how does one fill those drop down boxes with records that are already added in the database for each table?
Thanks
I have 10 tables in my database. I want load these 10 table names into a drop-down list. If a user selects a value form the drop-down list, a form should be displayed with related to the table. (form fields should be appropriate table's column headers) When user fill the form and submitted, data should be saved in the selected table. Give me a code example to do this. I'm new to this form and php/mysql so sorry if this isn't the right place to post this. This is what is in the first dropdown box. Code: [Select] $selValues['john'] = "a, b, c, d, e"; These are the different lists I want it to put in the second drop down box depending on what they choose in the first. Code: [Select] $selValues['list1']= " a1, a2, a3, a4, a5"; $selValues['list2']= " b1, b2, b3, b4, b5"; This is how I made an attempt to make it work before posting here. Along with plently of other ways. Code: [Select] if ($selValues['john']=a) { $chan_input = selectBuilder($selValues['$list1'] }; else if ($selValues['john']=b) { $chan_input = selectBuilder($selValues['$list2'] }; Basicly how I need it to work is there are two drop down boxes. First they will chose between a,b,c,d,e. If they chose a then on the second drop down box I only want them to be able to select a1,a2,a3,a4,a5. Hello there, I'm trying to show a picture based on the value that was chosen in the dropdown menu of the page before the submit. Let's say i'm having a drop down form with 3 values: Porsche, BMW, Audi, the form also consists of a button to submit form and some other text fields but these aren't really relevant. So what i want is, you choose whatever car, let's say BMW, fill in all the other data of the form, hit submit, and on the next page it should show a Picture which i define for each car. I hope i explained that somehow understandable. Thanks in advance, Sabine Newbie here, I am actually a math teacher working on creating a simulated store front for my students where they keep up with inventory, budgeting etc. Everyday my students will have to look at how much product is in stock, how much product was sold, and then input how much should be ordered for the next day. I am working on an answer key that will be used to validate students input but the 'quantity' and 'sold' fields will be relative to the most recent post. Right now the code below pulls all the rows under 'quantity', but I need it to only pull the most recent post. I have done my best to search the forum and try to find how to do this, but admittedly I am not even really sure what to be searching for. Any help would be great. Code: [Select] <?php $con = mysql_connect("localhost","user","pass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("myDatabase", $con); $result = mysql_query("SELECT * FROM myTable"); while($row = mysql_fetch_array($result)) { $quantity = $row['quantity']; $sold = $row['numbersold']; $needed = $row['remaining']; echo $needed-($quantity-$sold); } mysql_close($con); ?> Hi all, here's my code: Code: [Select] <?php foreach ($_SESSION['topping'] as $value) { echo "<tr><td width='30%'>Topping</td><td width='50%'>$value</td><td width='20%'><select name='notopping'>"; foreach ($_SESSION['cupcake'] as $number) { '<option name="notoppings[]" value="'.$number.'">".$number."</option>'; } echo "</select></td></tr>"; } ?> $_SESSION['cupcake'] is a value from either 6, 12, 24 or 36. What I want to do is put them into a drop down box (second foreach) as the value and the displayed value - counting up from 1 (so 1,2,3,4,5,6 or up to 12,24 etc). Also by creating this as an array, does this mean than for each topping (say Vanilla and Chocolate) the value dynamically created can be used on the next page by using $_POST['notoppings'] to display each type (two different numbers - one for Vanilla and one for Chocolate). Does that make sense? Thanks! Jason I have the following code which works (thanks to PHP Freaks members)
foreach ($swap["sims"] as $swap)
{
echo $swap['voice'] . "</br>";
}
But I can't figure out why the following doesn't work
<select name="sim_for_swap[]">
<?php
foreach ($swap["sims"] as $swap)
{
?>
<option value="<?php echo $swap['voice'];?>"><?php echo $swap['voice'];?></option>
<?php
}
?>
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