PHP - Simple Problem: Class Syntax Error Results In Parsing Error

Code: [Select]
<?php
if (!isset($_POST['submit'])) {
?>
 <h2>Todays Special</h2>
<p>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<select name="day">
<option value="1">Monday/Wednesday
<option value="2">Tuesday/Thursday
<option value="3">Friday/Sunday
<option value="4">Saturday
</select>
input type="submit" name="submit" value="Go">
</form>
<?php
// get form selection
$day = $_POST['day'];
// check value and select appropriate item
switch ($day) {
    case 1:
        $special = 'Chicken in oyster sauce';
        break;
    case 2:
        $special = 'French onion soup';
        break;
    case 3:
        $special = 'Pork chops with mashed potatoes and green salad';
        break;
    default:
        $special = 'Fish and chips';
       break;
}
?>

Hello all,   Appreciate if you folks could pls. help me understand (and more importantly resolve) this very weird error:     Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ASC, purchase_later_flag ASC, shopper1_buy_flag AS' at line 3' in /var/www/index.php:67 Stack trace: #0 /var/www/index.php(67): PDO->query('SELECT shoplist...') #1 {main} thrown in /var/www/index.php on line 67   Everything seems to work fine when/if I use the following SQL query (which can also be seen commented out in my code towards the end of this post) :  

$sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name
           FROM shoplist, store_master, item_master
           WHERE     shoplist.store_id = store_master.store_id
                   AND shoplist.item_id = item_master.item_id";

  However, the moment I change my query to the following, which essentially just includes/adds the ORDER BY clause, I receive the error quoted above:

$sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name 
		FROM shoplist, store_master, item_master 
		ORDER BY purchased_flag ASC, 
				purchase_later_flag ASC, 
				shopper1_buy_flag ASC, 
				shopper2_buy_flag ASC, 
				store_name ASC) 
		WHERE 	shoplist.store_id = store_master.store_id 
				AND shoplist.item_id = item_master.item_id";

In googling for this error I came across posts that suggested using "ORDER BY FIND_IN_SET()" and "ORDER BY FIELD()"...both of which I tried with no success.   Here's the portion of my code which seems to have a problem, and line # 67 is the 3rd from bottom (third last) statement in the code below:  

                    <?php
                        /*
                        $sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name
                                FROM shoplist, store_master, item_master
                                WHERE     shoplist.store_id = store_master.store_id
                                        AND shoplist.item_id = item_master.item_id";
                        */
                    
                        $sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name
                                FROM shoplist, store_master, item_master
                                ORDER BY FIND_IN_SET(purchased_flag ASC,
                                                 purchase_later_flag ASC,
                                                 shopper1_buy_flag ASC,
                                                 shopper2_buy_flag ASC,
                                                 store_name ASC)
                                WHERE     shoplist.store_id = store_master.store_id
                                        AND shoplist.item_id = item_master.item_id";
                        $result = $pdo->query($sql);                        
                        
                        // foreach ($pdo->query($sql) as $row) {
                        foreach ($result as $row) {
                            echo '<tr>';
                                print '<td><span class="filler-checkbox"><input type="checkbox" name="IDnumber[]" value="' . $row["idnumber"] . '" /></span></td>';

    Thanks  

Parse error: syntax error, unexpected T_STRING in C:\xampp\htdocs\mywork\unique.php on line 15


<html>
<head>
<title>

</title>
</head>
<body bgproperties="fixed">
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$con = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');
$dbname = 'mywork';
mysql_select_db($dbname, $con);
$sql=mysql_query(insert into users (regno,name,gender,date,month,year,emailid,cell,paddress,caddress,incometype,incomeamt,dad,fyes,dadocup,mom,myes,momocup,password) VALUES ('$_POST[regno]','$_POST[name]','$_POST[gender]','$_POST[date]','$_POST[month]','$_POST[year]','$_POST[emailid]','$_POST[cell]','$_POST[paddress]','$_POST[caddress]','$_POST[incometype]','$_POST[incomeamt]','$_POST[dad]','$_POST[fyes]','$_POST[dadocup]','$_POST[mom]','$_POST[myes]','$_POST[momocup]','$_POST[password]')");
$sql1=mysql_fetch_array($sql);
$result = @mysql_query($SQl1);
$result="SELECT * FROM users WHERE regno='$regno'";
while($row = mysql_fetch_array($result))
{
    //echo $row['regno']."regno<br>";
//echo $row['name']."name<br>";
//echo $row['gender']."gender<br>";
//echo $row['date']."date<br>";
//echo $row['month']."month<br>";
//echo $row['year']."year<br>";
//echo $row['emailid']."emailid<br>";
//echo $row['cell']."cell<br>";
//echo $row['paddress']."paddress<br>";
//echo $row['caddress']."caddress<br>";
//echo $row['incometype']."incometype<br>";
//echo $row['incomeamt']."incomeamt<br>";
//echo $row['dad']."dad<br>";
//echo $row['fyes']."fyes<br>";
//echo $row['dadocup']."dadocup<br>";
//echo $row['mom']."mom<br>";
//echo $row['myes']."myes<br>";
//echo $row['momocup']."momocup<br>";
//echo $row['password']."password<br>";

}
echo "Thanks for Register!";
if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }
echo "1 record added";
mysql_close($con);
?>
<form name="security" action="index.php" method="post">

<input type="submit" value="click here to login">
</form>
</body>
</html>

This is absolutely stupid. I'm debugging PHP in Eclipse PDT with XDebug and XAMPP on Windows 7. A section of code has been working for weeks. Suddenly I'm told the following is a syntax error (line 226)

$forumtitle = $forum['title'];
$threadtitle = $thread['title'];

Eclipse matches bracket and normally clipse would highlight [ when I put the cursor behind ]. Not here.

On similar statements before this I changed ' (single quote) to  (double quote)".  The brackets [ and ] highlighted correctly but the " produced a louder syntax error.. 

Then I simply removed the single quotes. No syntax error. Brackets match. But I will probably get a syntax error.

Usually stupidity like this indicates a quote problem somewhere before this code.  After looking very hard, I see none. It feels like something is wrong with the Eclipse editor and something has to be reset. But what?

I would appreciate any help.