PHP - Sqlite: Join Syntax Creates "no Such Table" Error

It's been a while since I sat down to build some pages and teach myself php. So now that I've started back up, I'm at a loss for what I've done. I deleted a file, and have to rebuild from an old broken version:

I have a form that submits a query to the database, but the results pages is giving me this error:

Code: [Select]
Oops, my query failed. The query is:
SELECT COUNT 'descriptors'.* ,'plantae'.* FROM 'descriptors' LEFT JOIN 'plantae' ON ('descriptors'.'plant_id' = 'plantae'.'plant_name') WHERE 'leaf_shape' LIKE '%auriculate%' AND 'leaf_venation' LIKE '%%' AND 'leaf_margin' LIKE '%%'
The error is:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.* ,'plantae'.* FROM ' at line 2
But I'm not seeing what the syntax error is.

Here's the code:
Code: [Select]
<?php 
require ('connection.php');

$display = 2;
// it's intentionally only 2 for the moment

if (isset($_GET['np'])) {
   $num_pages = $_GET['np'];
} else { 
$data = "SELECT COUNT
                        'descriptors'.*
                        ,'plantae'.*
                    FROM
                        'descriptors'
                    LEFT JOIN
                        'plantae' ON ('descriptors'.'plant_id' = 'plantae'.'plant_name')
                    WHERE
                        'leaf_shape' LIKE '%$s1%'
                        AND 'leaf_venation' LIKE '%$s3%'
                        AND 'leaf_margin' LIKE '%$s4%'";
$result = mysql_query ($data);

if (!$result) {
    die("Oops, my query failed.  The query is: <br>$data<br>The error is:<br>".mysql_error());
}

$row = mysql_fetch_array($result, MYSQL_NUM);

$num_records = $row[0];

if ($num_records > $display) {
   $num_pages = ceil ($num_records/$display);
} else {
$num_pages = 1;
}
}
if (isset($_GET['s'])) {
   $start = $_GET['s'];
} else {
    $start = 0;
}

if(isset($_POST[submitted])) {
// Now collect all info into $item variable
$shape = $_POST['s1'];
$color = $_POST['s2'];
$vein = $_POST['s3'];
$margin = $_POST['s4'];




// This will take all info from database where row tutorial is $item and collects it into $data variable 

$data = mysql_query("SELECT
                        'descriptors'.*
                        ,'plantae'.*
                    FROM
                        'descriptors'
                    LEFT JOIN
                        'plantae' ON ('descriptors'.'plant_id' = 'plantae'.'plant_name')
                    WHERE
                        'leaf_shape` LIKE '%$s1%'
                        AND 'leaf_venation' LIKE '%$s3%'
                        AND 'leaf_margin' LIKE '%$s4%'
                    ORDER BY 'plantae'.'scientific_name` ASC LIMIT $start, $display");



//chs added this in... 
echo '<table align="center" cellspacing="0" cellpading-"5">
<tr>
<td align="left"><b></b></td>
<td align="left"><b></b></td>
<td align="left"><b>Leaf margin</b></td>
<td align="left"><b>Leaf venation</b></td>
</tr>
';
//end something chs added in 

// This creates a loop which will repeat itself until there are no more rows to select from the database. We getting the field names and storing them in the $row variable. This makes it easier to echo each field.

while($row = mysql_fetch_array($data)){
echo '<tr>
<td align="left"> <a href="link.php">View plant</a> &nbsp; &nbsp;</td>
<td align="left"> <a href="link.php">unknown link</a>&nbsp; &nbsp;</td>
<td align="left">' . $row['scientific_name'] . '</td>
<td align="left">' . $row['common_name'] . '</td>
<td align="left">' . $row['leaf_shape'] . '</td>
</tr>';
}
echo '</table>';
// row 95
}
if ($num_pages > 1) {
echo '<br /><p>';
$current_page = ($start/$display) + 1;
// row 100
if ($current_page != 1) {
echo '<a href="leafsearch2a.php?s=' . ($start - $display) . '&np=;' . $num_pages . '">Previous</a> ';
}

for ($i = 1; $i <= $num_pages; $i++) {
if($i != $current_page) {
echo '<a href="leafsearch2a.php?s=' . (($display * ($i - 1))) . '$np=' . $num_pages . '">' . $i . '</a>';
} else {
echo $i . ' ';
}
}


if ($current_page != $num_pages) {
 echo '<a href="leafsearch2a.php?s=' . ($start + $display) . '$np=' . $num_pages . '"> Next</a>';
}
} 
//added curly
?>

I have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you   

 
<title>Inputing Travel Detials</title>
 
<header>
  <h1 align="center"> Adding Travel Detials </h1>
  
 
  <body>
    <p>  <center><img  src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center>
        <table border="1">
          <tr>
            <td><a href="index.php"> Home Page </a></td>
            <td><a href="administratorhomepage.html">Administrator Home Page </a></td>
            <td><a href="viewhomepage.html">View Home Page </a></td>
            <td><a href="Inputhomepage.html">Input Home Page </a></td>
            <td><a href="traveldetials.html">Enter More Travel Detials </a></td>
        </table>
    </p>
 
 
<?php
 
include "connection.php";
 
$Applicant_ID = $_POST["Applicant_ID"];
$Method_Of_Travel = $_POST["Method_Of_Travel"];
$Cost = $_POST["Cost"];
$ETA = $_POST["ETA"];
$Main_Gate_Advised = $_POST["Main_Gate_Advised"];
 
$query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'");
   
 
$result = mysqli_query($dbhandle, $query) 
    or die(mysqli_error($dbhandle));
 
if($result){ echo "Success!"; }
 
  else{ echo "Error."; }
 
 
// successfully insert data into database, displays message "Successful".
 if($query){
  echo "Successful";
}
 
  else {
  echo "Data not Submitted";
}
 
 
//closing the connection
   mysqli_close($dbhandle)
   
 
 
 
 
?>

Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.     <?php

         $con = mysqli_connect("localhost","user","password","part_inventory");
    // Check connection
if (mysqli_connect_errno()) {
  printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
} else {
    
    $result = mysqli_query($con, "SELECT * FROM amp20 ");
    
    $amp20ptid = $_POST['amp20ptid'];                // escape variables for security
    $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']);
    
    mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'");
      
    
if (!mysqli_query($con, $amp20ptid));

{
 die('Could not delete data: ' . mysqli_error($con));    
}
 echo "Part has been deleted to the database!!!\n";
    mysqli_close($con);
}
?>

Hi guys   I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?   <?php $con = mysql_connect("localhost:3306","root","password"); if (!$con)   {   die('Could not connect: ' . mysql_error());   } mysql_select_db('sfapp', $con); $sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')   VALUES ('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')"; if (!mysql_query($sql,$con))   {   die('Error: ' . mysql_error());   }   ?> <?php //if "email" variable is filled out, send email   if (isset($_REQUEST['pe_add']))  {     //Email information     $admin_email = $_REQUEST['pe_add'];   $forename = $_REQUEST['forename_add'];   $email = "autoreply@testing.com";   $subject = "Application";   $desc =   "Dear $forename   Thank you for submitting your online application, we will be in touch shortly. " ;       //send email   mail($admin_email, "$subject", "$desc", "From:" . $email);     //Email response   echo "Thank you for contacting us!";   }     //if "email" variable is not filled out, display the form   else  { ?> If you are seeing this, you need to go back and fill out the Personal Email section! <?php   }   header("location:complete.php"); mysql_close($con) ?>     Thanks in advance.

Hello all,   Appreciate if you folks could pls. help me understand (and more importantly resolve) this very weird error:     Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ASC, purchase_later_flag ASC, shopper1_buy_flag AS' at line 3' in /var/www/index.php:67 Stack trace: #0 /var/www/index.php(67): PDO->query('SELECT shoplist...') #1 {main} thrown in /var/www/index.php on line 67   Everything seems to work fine when/if I use the following SQL query (which can also be seen commented out in my code towards the end of this post) :  

$sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name
           FROM shoplist, store_master, item_master
           WHERE     shoplist.store_id = store_master.store_id
                   AND shoplist.item_id = item_master.item_id";

  However, the moment I change my query to the following, which essentially just includes/adds the ORDER BY clause, I receive the error quoted above:

$sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name 
		FROM shoplist, store_master, item_master 
		ORDER BY purchased_flag ASC, 
				purchase_later_flag ASC, 
				shopper1_buy_flag ASC, 
				shopper2_buy_flag ASC, 
				store_name ASC) 
		WHERE 	shoplist.store_id = store_master.store_id 
				AND shoplist.item_id = item_master.item_id";

In googling for this error I came across posts that suggested using "ORDER BY FIND_IN_SET()" and "ORDER BY FIELD()"...both of which I tried with no success.   Here's the portion of my code which seems to have a problem, and line # 67 is the 3rd from bottom (third last) statement in the code below:  

                    <?php
                        /*
                        $sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name
                                FROM shoplist, store_master, item_master
                                WHERE     shoplist.store_id = store_master.store_id
                                        AND shoplist.item_id = item_master.item_id";
                        */
                    
                        $sql = "SELECT shoplist.*, store_master.store_name, item_master.item_name
                                FROM shoplist, store_master, item_master
                                ORDER BY FIND_IN_SET(purchased_flag ASC,
                                                 purchase_later_flag ASC,
                                                 shopper1_buy_flag ASC,
                                                 shopper2_buy_flag ASC,
                                                 store_name ASC)
                                WHERE     shoplist.store_id = store_master.store_id
                                        AND shoplist.item_id = item_master.item_id";
                        $result = $pdo->query($sql);                        
                        
                        // foreach ($pdo->query($sql) as $row) {
                        foreach ($result as $row) {
                            echo '<tr>';
                                print '<td><span class="filler-checkbox"><input type="checkbox" name="IDnumber[]" value="' . $row["idnumber"] . '" /></span></td>';

    Thanks