PHP - Why This Err Coming On Page Execution
Warning: mysql_query() [function.mysql-query]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\page\verify_security.php on line 170
earlier the code has been running fine and now it is showing error to me , can you tell something more about it ???
Similar TutorialsMy error: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key FROM applications WHERE key = '0188f'' at line 1 Code: function randomNum() { $random = substr(md5(rand(5000,300000)), -5); $query = mysql_query("SELECT key FROM applications WHERE key = $random") or die(mysql_error()); //make sure it doesn't already exist if(mysql_num_rows($query) > 0) { randomNum(); } else { return $random; } } I simply cannot seem to figure out what is happening...I've tried many solutions, but all seem to fail. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> </head> <?php // Connect to database================================================== include("connect_db.php"); // sending query =========================================================== $result = mysql_query("SELECT * FROM members Order By last") or die(mysql_error()); if (!$result) { die("Query to show fields from table failed"); } echo "<br />"; echo "<p>MEMBERS LIST</p>"; echo "<table border='10' cellpadding='3' cellspacing='2'>"; echo "<tr><th>First Name</th><th>Last Name</th>><th>Phone</th><th>Email</th></tr>"; // keeps getting the next row until there are no more to get ================ while($row = mysql_fetch_array( $result )) { // Print out the contents of each row into a table ========================== echo "<tr><td>"; echo $row['first']; echo "</td><td>"; echo $row['last']; echo "</td><td>"; echo $row['phone']; echo "</td><td>"; echo $row['email']; echo "</td></tr>"; } echo "</table>"; ?> </body> </html> This is the output. MEMBERS LIST > First Last Phone Email data data data data ect............................................................... I cannot find where the > (greater than) sign is coming from. There is a space after MEMBERS LIST but I could not get it to work in this display. Okay, so, I'm trying to pull the info from my `shop` table where the `users` table matches at x, y, z, and plane. Instead, I'm getting this: Resource id #22 Where is this coming from? I only have 1 row in my shop table, and it has: id = 7 name = admin shop x = 1 y = 0 z = admin plane = batai I'm standing in the shop right now (as my character, so my users table has the exact same x, y, z, plane)... Any help would be appreciated! $q1 = mysql_query("SELECT * FROM `shop` WHERE `x`='".$x["x"]."' AND `y`='".$x["y"]."' AND `z`='".$x["z"]."' AND `plane`='".$x["plane"]."'") or die("qry failed: ".mysql_error()); Variables: $x = $x = $player->username; (so it's pulling my username, which it is doing correctly ==> i echoed out $x and it came up with my username) Hi, I just started learning PHP... Below is my first programme infact.. Out put is not coming when i type some thing in input boxes... Can somebody suggest where is the error... Index.php <html> <head> <title>Welcome to our site</title> </head> <body> <form method="POST" action="submit.php"> <label for ="business_name">Business name</label> <input type="text" id="business_name" \><br/> <label for ="contact_person">Contact person</label> <input type="text" id="contact_person" \><br/> <label for ="Telephone">Telephone</label> <input type="text" id="Telephone" \><br/> <label for ="FAX">FAX</label> <input type="text" id="FAX" \><br/> <label for ="Mobile">Mobile</label> <input type="text" id="Mobile" \><br/> <label for ="Addres_line_1">Addres_line_1</label> <input type="text" id="Addres_line_1" \><br/> <label for ="Addres_line_2">Addres_line_2</label> <input type="text" id="Addres_line_2" \><br/> <label for ="Addres_line_3">Addres_line_3</label> <input type="text" id="Addres_line_3" \><br/> <label for ="Addres_line_4">Addres_line_4</label> <input type="text" id="Addres_line_4" \><br/> <label for ="City">City</label> <input type="text" id="City" \><br/> <label for ="Pin_code">Pin_code</label> <input type="text" id="Pin_code" \><br/> <label for ="State">State</label> <input type="text" id="State" \><br/> <label for ="email">email</label> <input type="text" id="email" \><br/> <input type="submit" value="Please submit the details" name="submit"/> </form> </body> </html> submit.php <head><title>Your submission details</title></head> <body> <H3>YOU HAVE SUBMITTED THE FOLLOWING DETAILS</H3> <?php $business_name= $_POST["business_name"]; $contact_person = $_POST["contact_person"]; $Telephone = $_POST["Telephone"]; $fax = $_POST["FAX"]; $mobile = $_POST["Mobile"]; $address1 = $_POST["Addres_line_1"]; $address2 = $_POST["Addres_line_2"]; $address3 = $_POST["Addres_line_3"]; $address4 = $_POST["Addres_line_4"]; $city = $_POST["City"]; $pincode = $_POST["Pin_code"]; $state = $_POST["State"]; $email = $_POST["email"]; echo "Your business name".$business_name.'<br/>'; echo "Contact person".$contact_person.'<br/>'; echo "Telephone no.".$Telephone.'<br/>'; echo "Fax No.".$fax.'<br/>'; echo "Mobile No.".$mobile.'<br/>'; echo "Address line one".$address1.'<br/>'; echo "Address line two".$address2.'<br/>'; echo "Address line three".$address3.'<br/>'; echo "Address line four".$address4.'<br/>'; echo "Your City".$city.'<br/>'; echo "Your Pincode".$pincode.'<br/>'; echo "Your State".$state.'<br/>'; echo "Your email".$email.'<br/>'; ?> <a href=index.php>Home</a> </body> </html> Hi everyone reading this, I have used PHP before as a hobby programmer but recently my boss asked me to make a webpage to accept worker's hours and store them in a database. So I realize that in the last few years object oriented style has been added into PHP. I have learnt OOP (C++) about a decade ago and understand the fundamentals of it. If I am writing this website code, am I going to be better off spending the time to get familiar with the new OOP stuff in PHP and use that or would it be better to just use an old sequential style of programming? I know this may seem like apples and oranges and that it varies based on opinion, but maybe there can be reasons for me to use OOP over sequential. For instance, if I write this code to be flexible enough that I can do a basic "worker times" table first, then I might be able to add additional functionality later, like worker details and qualifications, all of which could be brought up with the click of a button. Will it generally be easier to add onto code using OOP? if any body copy and paste anything from word to editor some unwanted css also coming with that pasting. when we request the data same css also coming with that. so how to clean data when we request $desc =$_request['contents']; how to solve this issue. please help me. hello, I have a search that matches users ISBN with two databases....code is below $query_search_exact_match = mysql_query("SELECT nvc_site.title, nvc_site.id, nvc_site.description, nvc_site.search_text, nvc_site.image, nvc_site.date, nvc_site.price, nvc_site.location_city, nvc_site_ads_extra.name, nvc_site_ads_extra.value, nvc_site_ads_extra.classified_id FROM nvc_site,nvc_site_ads_extra WHERE name = 'ISBN%3A' AND live=1") or die(mysql_error()); then i take the ISBN that the user entered and match that with the isbn's in the DB while ($fetch_extra = mysql_fetch_array($query_search_exact_match)) { $value = ereg_replace( "[^0-9]", "", $fetch_extra['value'] ); $to_find_isbn = mysql_real_escape_string(ereg_replace( "[^0-9]", "",$_POST['szs'])); if($value == $to_find_isbn) { echo "Match Found"; } else { echo "No Match Found"; } //ELSE doesn't work here.....it displays both the if and else at the same time } i need it to display no match found if there was no match found.....I am soo lost right now!! please help thank you Hello all, I am trying to create a PHP CLi Script that will help me setup new config and server files / directories for every new web project i get instead of me having to manually create everything with each project. The script accepts the project name, and y/n for whether i want to create subdomains for css, jss and image files. After it has that, it must create a new http config file under sites-available (in Linux), by pasting the config file text. Problem : If I output regular text to the file, it displays exactly in the format that I write the string variable. But when I use a printf, or try to use variables directly in the config text, it starts formatting the text in the config file in a strange way. I just want the variables to just be replaced and the text to appear in the exact format below. The text displays perfectly as i typed below in the config file if I don't use any variables. $subDomainConfig .= '<VirtualHost *:80> ServerAdmin webmaster@%1$s ServerName %1$s.%2$s ServerAlias %1$s.%2$s # Indexes + Directory Root. DirectoryIndex index.html index.php DocumentRoot /var/www/%2$s/public_html/ # CGI Directory ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Location /cgi-bin> Options +ExecCGI </Location> # Logfiles ErrorLog /var/www/%2$s/logs/apache/error.log CustomLog /var/www/%2$s/logs/apache/access.log combined </VirtualHost> '.PHP_EOL; $httpConfigFileText = sprintf($subDomainConfig, $subDomain, $shortProjectName); The above code outputs text in this way in the file : <VirtualHost *:80> ServerAdmin webmaster@images ServerName images.mysite ServerAlias images.mysite # Indexes + Directory Root. DirectoryIndex index.html index.php DocumentRoot /var/www/mysite /public_html/ # CGI Directory ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Location /cgi-bin> Options +ExecCGI </Location> # Logfiles ErrorLog /var/www/mysite /logs/apache/error.log CustomLog /var/www/mysite /logs/apache/access.log combined </VirtualHost> Hi i need help iv create an event upload on the back-end of a website where a user can enter name, location and date of an event into sql database which works fine, the problem is that i want to display only current and up and coming events and not display the events that have passed if anyone can help that would be great Is there a way in php to not execute the whole script if there is error on the script? For example: Code: [Select] <?php execute script here; .......... ........... [b] error encounter here[/b]. -> error is not logical execute script ............. ............. ?> I don't want to execute the above script... tnx everyone. I am using the classic Code: [Select] ini_set("display_errors","2"); ERROR_REPORTING(E_ALL); but I am getting a notice that is posting on my page. I preffer not to remove the reporting yet since the site is still new and is there any way I can hide the notice but keep the fail errors the error is Code: [Select] Notice: Undefined index: HTTPS in /var/www/website/visitors.php on line 20 line 20 is Code: [Select] if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} Hi I have a form that is popluated from the database now I am trying to get the switch case to be based on the option the user selects is this possible to make a case a variable popluated by the drop down if so can someone show me what am i missing? the value I am trying to get from the form to the switch case is the ( $val->slug) but the value not been set help please here the form Code: [Select] <form method="post"> <select name="deal-locations" onChange="this.form.submit()"> <?php while(list($key,$val) = each($locations)) { ?><option value="<?php echo $val->slug; ?>"><?php echo $val->slug; ?></option><?php } ?> </select> <input type="submit" value="submit"> </form> Here the switch case Code: [Select] switch ($_POST['deal-locations']) { case " $val->slug": echo "<h3>deal-locations: ASC</h3>"; $args = array( 's' => $_GET['s'], 'post_type' => 'deals', 'deal-locations' => ' $val->slug', 'where' => ' $val->slug', 'paged' => 'paged' ); break; } 0
What is the best way to store this data coming from the api into a csv file to later put into the db. Output: rank, level, xp, rank, level, xp, etc. This api produces about 60 rows of data per name ran and x that by about roughly 300 names that equals a lot of data. Pretty much with my current code I am pretty much creating a endless loop almost that would take a long time to execute so updating said data would be a nightmare i would think. Is there a way to accomplish the same thing without the loop or I am not sure how to go about this. My current code is a mess that much I know I am gonna be told. This code works, just not efficiently. I am thinking there may be a better way to do this. $query = $conn->prepare("SELECT name FROM users LIMIT 1"); $query->execute(); while($row = $query->fetch(PDO::FETCH_ASSOC)){ $name = $row['name']; $url = 'https://secure.runescape.com/m=hiscore/index_lite.ws?player='. $name . '';//api that the csv data is coming from $highscores = file_get_contents($url); $fields = array("Name", "Rank", "Level", "Xp");//this is to add the headers // for the csv files $implode1 = implode($fields, ",");//turn into csv format, not sure this is //even needed $implode1 .= "\n";/*this is to add a line break so that the explode below will properly put it into its own element*/ //otherwise data starts joining togather $extra_data = array("$name");/*This is to add the name that the data pertains too*/ $implode2 = implode($extra_data, ",");//turn into csv format $highscores = $implode1 . $implode2 . $highscores;//join as one array $highscores = explode("\n", $highscores);//turn each csv into an element of //its own element a bunch of unsets to remove unwanted data. Omitted them to condense the code $i = 1; header('Content-Type: text/csv'); header('Content-Disposition: attachment; filename="name.csv"'); $data = $highscores; $fp = fopen('highscores/' . $name . '.csv', 'wb'); foreach ( $data as $line ) { $val = explode(",", $line); fputcsv($fp, $val); } fclose($fp); The pdo part I was gonna include but the way I have it setup now wouldn't work. I was thinking that I would use mysql's LOAD DATA INFILE to insert the csv data to database. The end goal here is to be able to search for player stats and to use said data to keep track of xp earned during a xp competition. I PRAY that i have included enough info... I would really appreciate any feedback if possible. Hi,
I have this code:
<div id="pics"> <?php if (count($itemRow['pics']) == 0) { ?> <img src="<?php h("{$www_base}/none.jpg"); ?>" class="pic active" /> <?php } else { ?> <?php for ($i = 0; $i < count($itemRow['pics']); $i++) { ?> <img src="<?php h(getThumbnail($itemRow['site'], $itemRow['pics'][$i])); ?>" class="thumbnail<?php if ($i == 0) e(" active"); ?>" picnum="<?php h($i); ?>" /> <?php } ?> <div style="clear:both;"></div> <br /> <?php for ($i = 0; $i < count($itemRow['pics']); $i++) { ?> <a target="_blank" href="<?php h(getPicture($itemRow['site'], $itemRow['pics'][$i])); ?>"> <img src="<?php h(getPicture($itemRow['site'], $itemRow['pics'][$i])); ?>" class="pic<?php if ($i == 0) e(" active"); ?>" /> </a> <?php } ?> <?php } ?> </div>This code practically take a picture and post it on my website, but the problem is that is also take the superfish advertisement, that I can see only in the html source. <div id="similarproducts_inimg" class="__similarproducts similarproducts_inimg generic generic" style="left:15px; top:465px;"><div class="container"><div class="explore_button _open_full_ui" style="height:100px; background-image: url('http://www.superfish.com/ws/images/inimg2/explore_en.png');" data-report-action="explore click"><div class="label"></div></div><a class="item free_shipping _merchant_click" target="_blank" href="http://www.........................</div></div>How I can block a specific DIV to be created. I try some java-script and no success until now. Some other solutions? i wanna put condition that if ($signupbonus > 0.00) then following should not be executed <font size="3" color="red"><b>Referral bonus: <font color="green" size="4">$<? echo $signupbonus; ?></font></b></font><br><br> please help Hello, I am developing an account manager for our local network and I want people to be able to login to my website and change their UNIX & Mailbox password. These people have SSH access so that is why the UNIX passwd should also be changed. So what I want to do is get the values $username, $currentpwd , $newpwd and $newpwdcnfrm from the HTML form and execute the following shell commands : Quote su -l $username passwd Enter current UNIX Passwd : $currentpwd Enter new UNIX Passwd : $newpwd Confirm UNIX Passwd : $newpwdcnfrm The problem here is, passwd takes old and new passwords as input, not as command parameters. So I cant just do shell_exec("passwd $currentpwd $newpwd $newpwdcnfrm") ; Do you guys know how to give input to the command? thanks. Btw : Please do not argue about the security issues. I am aware of everything and I am perfectly sure that the script will run securely. hey guys... below is my code... when i hit the "submit" button the browser displays the php file rather than writing to the db... can anyone see what im doing wrong .. thanks Code: [Select] <table width="300" border="0" align="center" cellpadding="0" cellspacing="1"> <tr> <td><form name="form1" method="post" action="insert_ac.php"> <table width="100%" border="0" cellspacing="1" cellpadding="3"> <tr> <td colspan="3"><strong>Insert Data Into mySQL Database </strong></td> </tr> <tr> <td width="71">Name</td> <td width="6">:</td> <td width="301"><input name="name" type="text" id="name"></td> </tr> <tr> <td>Lastname</td> <td>:</td> <td><input name="lastname" type="text" id="lastname"></td> </tr> <tr> <td>Email</td> <td>:</td> <td><input name="email" type="text" id="email"></td> </tr> <tr> <td colspan="3" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </form> </td> </tr> </table> Code: [Select] <?php $host="localhost"; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="test_mysql"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Get values from form $name=$_POST['name']; $lastname=$_POST['lastname']; $email=$_POST['email']; // Insert data into mysql $sql="INSERT INTO $tbl_name(name, lastname, email)VALUES('$name', '$lastname', '$email')"; $result=mysql_query($sql); // if successfully insert data into database, displays message "Successful". if($result){ echo "Successful"; echo "<BR>"; echo "<a href='insert.php'>Back to main page</a>"; } else { echo "ERROR"; } // close connection mysql_close(); ?> Code: [Select] <?php //Start session session_start(); //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect($hostname, $username, $password); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db($dbname); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; if( isset($_SESSION['ERRMSG_ARR']) && is_array($_SESSION['ERRMSG_ARR']) && count($_SESSION['ERRMSG_ARR']) >0 ) { echo '<ul class="err">'; foreach($_SESSION['ERRMSG_ARR'] as $msg) { echo '<li>',$msg,'</li>'; } echo '</ul>'; unset($_SESSION['ERRMSG_ARR']); } session_write_close(); header("location: index.php"); exit(); } //Create query $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_field($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: member-index.php"); exit(); }else { //Login failed header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?> This is my login execution script and when i run it, i get this - Fatal error: Cannot use object of type stdClass as array in /home/a8029060/public_html/login-exec.php on line 75 Please any help :/ I have this one issue. While logging in into our system, we call a routine called getToken(). This calls a routine on another server (used to be able to securely access documents). The issue we have is if that other server goes down, this call fails, and the user isn't able to login. I want to make it so that even if the other server goes down, users can still login and access our system (just not documents). I know that I can't prevent fatal errors or even ignore them, correct (even with set_error_handler)? Any thoughts? It's a simple call, here's all it is: require_once('include/utils.php'); $token=getToken(); Guys, why the following mysql stored procedure taking much more time comparing with firebird one?
1. MySQL stored procedure
CREATE DEFINER=`lxc`@`::1` PROCEDURE `insertData`(IN it INT) BEGIN declare i int Default 0; declare str char(4); declare p_hash int; myloop: loop set p_hash = round(rand() * 999); set str='book'; insert into test.users (name,password) VALUES (concat(str,'_',i+1),PASSWORD(p_hash)); set i = i+1; if (i = it) then leave myloop; end if; end loop myloop; endObject info: Table: users Columns: id int(10) UN PK AI name varchar(45) password char(41)Time: mysql> call insertData(10000); Query OK, 1 row affected (9 min 38.22 sec)2. Firebird Stored Procedure SET TERM ^ ; CREATE PROCEDURE INSERDATA ( IT integer ) --iteration number AS DECLARE VARIABLE i integer; BEGIN i = 0; while ( i < it ) do begin INSERT INTO PRODUCT( CODE,NAME,PASS) VALUES(:i, 'jazz_' || :i, fb_hash(round(rand() * 999))); i = i + 1; end END^ SET TERM ; ^ COMMIT;Object Info: Table: product columns CODE integer, NAME varchar(45), PASS CHAR(41)Time: ( for 10 000 records it takes less than 1 sec for execution) Executing statement... Statement executed (elapsed time: 0.063s). 31464 fetches, 11084 marks, 0 reads, 0 writes. 10000 inserts, 0 updates, 0 deletes, 5 index, 0 seq. Delta memory: 24264 bytes. PRODUCT: 10000 inserts. 0 rows affected directly. Total execution time: 0.151s Script execution finished.Do you see something wrong in mysql stored procedure code? jazz. Edited by jazzman1, 31 July 2014 - 03:21 PM. |