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PHP - Code I Have Incorrect...
I have a small bit of jquery code that is not working:
$(function() {
$(‘’[name=\'pet_type\']”).change(function() {
$(‘’[name=\'breed\']”).removeAttr(‘disabled’);
$(‘’[name=\'breed\']”).children(‘data-pet-type[name!=\'’ + $(this).val() + ‘\']’).hide();
$(‘’[name=\'breed\']”).children(‘data-pet-type[name=\'’ + $(this).val() + ‘\']’).show();
});
});
My javascript is not good at all, so cannot spot errors?
Any help would be much appreciated!
Thanks
Similar TutorialsThe password ARE correct. My code keeps saying that the password is INCORRECT. The password is MD5'ed once a user registers, and when they type in a password at the login (as shown), the password is also MD5'ed. Why is it that it's output is incorrect password? <?php session_start(); include("includes/mysql.php"); include("includes/config.php"); ?> <title><?php echo $title; ?></title> <?php if(!$_SESSION['user']) { $username = $_POST['username']; $password = $_POST['password']; $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); if(!$password || !$username) { echo ' <h1>Login</h1> <center><p><form action="login.php" method="POST"> <table border="0"> <tr><th>Username:</th> <td><input type="text" name="username" maxlength="20"><br/></td></tr> <tr><th>Password:</th> <td><input type="password" name="password" maxlength="30"><br/></td></tr> <tr><th></th><td><input type="submit" value="Login"></td></tr> </table></form></p></center> </div> '; } else { $query = mysql_query("SELECT COUNT(username),password,username FROM users WHERE username='$username'"); $check = mysql_fetch_assoc($query); $db_username = $check['username']; $password = md5($password); if($check['COUNT(username)'] < 1) { echo ' <p>No account exists with this username. Please go back.</p> '; } elseif($check['password']==$password && $db_username==$username) { echo ' <h1>Login Successful</h1> <p>You have successfully logged in! Return home.</p> '; $_SESSION['user']=$username; } else { echo ' <p>The password you have enetered in is incorrect. Please go back.</p> '; } } } else { echo ' <p>Your already logged in!</p> '; } ?> Ever since I switched over to pagination, the ranks for the sites have been off. I use to have an $i++ increment that kept the ranks, but now with pagination, it just ranks those on the current page. Is there a way to bypass this? public function grabSites() { //amount of sites $amount = mysql_num_rows(mysql_query("SELECT * FROM sites")); if($amount > 0) { //amount per page $p_page = 13; //track page $start = $_GET['page']; //max_pages $max_pages = $amount / $p_page; //set default if(!$start) $start = 0; //new query $query = mysql_query("SELECT id,title,description,votes,date,outl,site_url FROM sites ORDER BY votes DESC LIMIT $start, $p_page"); while($fetch = mysql_fetch_assoc($query)) { ++$i; $i = $i + $p_page; echo " <div id='post-1' class='post'> <h2 class='title'><font color='white'>#". $i." ".$fetch['title'] ."</font></h2> <div class='entry'> <b>". $fetch['title'] ." currently has ". $fetch['votes'] ." votes. <a href='vote.php?id=". $fetch['id'] ."'>Vote now</a>.</b> <br/><br/> <p>". nl2br(stripslashes($fetch['description'])) ."</p> </div> <p class='meta'><a href='". $fetch['site_url'] ."'>Visit</a></p> </div> "; } //set back and forth variables $previous = $start - $p_page; $next = $start + $p_page; ?> <hr> <center> <?php if(!($start<=0)) echo "<a href='index.php?page=". $previous ."'><<</a>"; $i = 1; for($x = 0; $x < $amount; $x = $x + $p_page) { echo "<a href='index.php?page=". $x ."'> ". $i ." </a>"; $i++; } if(!($start>=$amount-$p_page)) echo "<a href='index.php?page=". $next ."'>>></a></center>"; ?> </center> <?php } else { echo " <div id='post-1' class='post'> <h2 class='title'><a href='#'>Oh NOEZ!</a></h2> <h3 class='date'>". date("M-d-Y") ."</h3> <div class='entry'> <p>There are currently no sites to display!</p> </div> <p class='meta'>View</p> </div> "; } } Hi all My site is build using php includes. the index.php file contains code like <?php if(@$_GET['page'] == "web-design"){ include("includes/web-design.php"); } else if(@$_GET['page'] == "hosting"){ include("includes/hosting.php"); } else { include("includes/home.php"); } ?> I have created a sub domain blog.maplewebdesign.co.uk and a sub dircetory named blog. The link to this part of my site doesn't use includes, I want it to link directly to that sub directories index.php page. This works fine, but then when I click on a different link anywhere on the site my url is as follows www.maplewebdesign.co.uk/blog/index.php?page=home For some reason it is keeping the blog/ in the URL If you want to see go to http://www.maplewebdesign.co.uk/blog/ then click on a differnt link and check out the URL What am I doing wrong? Thanks Adi It's been a while since I've used my queries, can anyone tell me what's wrong with this mysql query? Code: [Select] $query = mysql_query("SELECT * FROM `chicken_names` WHERE `gender` = 'Hen' AND `name` LIKE '%$s_terms%' ORDER BY `likes` DESC") or die(mysql_error()); So I am trying to make an incorrect password message but the message never appears.
My code:
<?
require "./includes/config.php";
$LS->init();
if(isset($_POST['act_login'])){
$user=$_POST['login'];
$pass=$_POST['pass'];
if($user=="" || $pass==""){
$msg=array("Error", "Username / Password Wrong !");
}
else
{
if(!$LS->login($user, $pass)){
$msg=array("Error", "Username / Password Wrong !");
}
}
}
?>
hello in the attached code, how do i add another field to the query? ie, i have all the code to create the result and would like to add further values such as $dept? what is the correct way to code query? i must stress that i am using php 4.4.7 so json_encode is out. the code is working but just need to find a way to add the $dept to the qeury? many thanks $dept = array(); $box = array(); while ($row = mysql_fetch_array($result)) { $dept[] = $row['department']; $box[] = $row['custref']; } /*$items = rtrim($_POST['items'],","); $sql = "UPDATE `boxes` SET status = 'Out' WHERE Id IN ($items)"; $result = runSQL($sql);*/ $total = count(explode(",",$items)); $result = runSQL($sql); $total = mysql_affected_rows(); /// Line 18/19 commented for demo purposes. The MySQL query is not executed in this case. When line 18 and 19 are uncommented, the MySQL query will be executed. header("Expires: Mon, 26 Jul 1997 05:00:00 GMT" ); header("Last-Modified: " . gmdate( "D, d M Y H:i:s" ) . "GMT" ); header("Cache-Control: no-cache, must-revalidate" ); header("Pragma: no-cache" ); header("Content-type: text/x-json"); $json = ""; $json .= "{\n"; $json .= "box: [\"". implode('","', $box) ."\"]\n"; $json .= "}\n"; echo $json; $sql = "INSERT INTO `act` (`item`) VALUES ('". implode("'),('", $box) . "')"; $result = runSQL($sql); I have a register page that MD5 Hash's the users password and a login which also does this. However, no matter what I try it always says incorrect password. Even when I remove the MD5. Register Code: Code: [Select] <?php error_reporting (E_ALL ^ E_NOTICE); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Member System - Register</title> </head> <body> <?php if ( $_POST['registerbtn'] ){ $getuser = $_POST['user']; $getemail = $_POST['email']; $getpass = $_POST['pass']; $getretypepass = $_POST['retypepass']; if ($getuser){ if ($getemail){ if ($getpass){ if ($getretypepass){ if ( $getpass === $getretypepass ){ if ( (strlen($getemail) >= 7) && (strstr($getemail, "@")) && (strstr($getemail, ".")) ){ require("./connect.php"); $query = mysql_query("SELECT * FROM users WHERE username='$getuser'"); $numrows = mysql_num_rows($query); if ($numrows == 0){ $query = mysql_query("SELECT * FROM users WHERE email='$getemail'"); $numrows = mysql_num_rows($query); if ($numrows == 0){ $password = md5(md5("kjfiufj".$password."Fj56fj")); $date = date("F d, Y"); $code = md5(rand()); mysql_query("INSERT INTO users VALUES ( '', '$getuser', '$password', '$getemail', '0', '$code', '$date' )"); $query = mysql_query("SELECT * FROM users WHERE username='$getuser'"); $numrows = mysql_num_rows($query); if ($numrows == 1){ $site = "http://c3221281.web44.net/"; $webmaster = "Simon <admin@simon.com>"; $headers = "From: $webmaster"; $subject = "Activate Your Account"; $message = "Thanks for registering. Click the link below to activate your account.\n"; $message .= "$site/activate.php?user=$getuser&code=$code\n"; $message .= "You must activate your account to login."; if ( mail($getemail, $subject, $message, $headers) ){ $errormsg = "You have been registered. You must activate your account from the activation link sent to <b>$getemail</b>."; $getuser = ""; $getemail = ""; } else $errormsg = "An error has occueed. Your activation email was not sent."; } else $errormsg = "An error has occured. Your account was not created."; } else $errormsg = "There is already a user with that email."; } else $errormsg = "There is already a user with that username."; mysql_close(); } else $errormsg = "You must enter a valid email address to register."; } else $errormsg = "Your passwords did not match."; } else $errormsg = "You must retype your password to register."; } else $errormsg = "You must enter your password to register."; } else $errrosmg = "You must enter your email to register."; } else $errormsg = "You must enter your username to register."; } $form = "<form action='./register.php' method='post'> <table> <tr> <td></td> <td><font color='red'>$errormsg</font></td> </tr> <tr> <td>Username:</td> <td><input type='text' name='user' value='$getuser' /></td> </tr> <tr> <td>Email:</td> <td><input type='text' name='email' value='$getemail' /></td> </tr> <tr> <td>Password:</td> <td><input type='password' name='pass' value='' /></td> </tr> <tr> <td>Retype:</td> <td><input type='password' name='retypepass' value='' /></td> </tr> <tr> <td></td> <td><input type='submit' name='registerbtn' value='Register' /></td> </tr> </table> </form>"; echo $form; ?> </body> </html> Login Code: Code: [Select] <?php error_reporting (E_ALL ^ E_NOTICE); session_start(); $userid = $_SESSION['userid']; $username = $_SESSION['username']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Member System - Login</title> </head> <body> <?php if ($username && $userid){ echo "You are already logged in as <b>$username</b>. <a href='./member.php'>Click here</a> to go to the member page."; } else{ $form = "<form action='./login.php' method='post'> <table> <tr> <td>Username:</td> <td><input type='text' name='user' /></td> </tr> <tr> <td>Password:</td> <td><input type='password' name='password' /></td> </tr> <tr> <td></td> <td><input type='submit' name='loginbtn' value='Login' /></td> </tr> <tr> <td><a href='./register.php'>Register</a></td> <td><a href='./forgotpass.php'>Forgot your password?</a></td> </tr> </table> </form>"; if ($_POST['loginbtn']){ $user = $_POST['user']; $password = $_POST['password']; if ($user){ if ($password){ require("connect.php"); $password = md5(md5("kjfiufj".$password."Fj56fj")); // make sure login info correct $query = mysql_query("SELECT * FROM users WHERE username='$user'"); $numrows = mysql_num_rows($query); if ($numrows == 1){ $row = mysql_fetch_assoc($query); $dbid = $row['id']; $dbuser = $row['username']; $dbpass = $row['password']; $dbactive = $row['active']; if ($password == $dbpass){ if ($dbactive == 1){ // set session info $_SESSION['userid'] = $dbid; $_SESSION['username'] = $dbuser; echo "You have been logged in as <b>$dbuser</b>. <a href='./member.php'>Click here</a> to go to the member page."; } else echo "You must activate your account to login. $form"; } else echo "You did not enter the correct password. $form"; } else echo "The username you entered was not found. $form"; mysql_close(); } else echo "You must enter your password. $form"; } else echo "You must enter your username. $form"; } else echo $form; } ?> </body> </html> Many thanks for your time and help, i am writing this script for use as an include in joomla and the directphp plugin so in my joomla article i have: Code: [Select] <?php include 'test/conducttest.php'; conducttest(); ?> Ok now my issue! the form in this function is passing only the values for the last item in the loop rather than for the selected radio item when submitted. so when say for example the radio selected is: ID TEST TYPE UNIQUE TEST ID AVAILABLE 5 Adolescent Clinical 50021629 1 and the last item in the list is: ID TEST TYPE UNIQUE TEST ID AVAILABLE 4 Adult Clinical 12341629 1 When the form is submitted even if the 1st item is selected, it returns the value for the second one. I am sorta new to php so any suggestions will be appreciated. Here is my full code: Code: [Select] <?php function conducttest() { //GET JOOMLA USER ID & USERNAME FOR LOGGED USER $user =& JFactory::getUser(); $userID = $user->id; //GET JOOMLA DATABASE OBJECTS $db =& JFactory::getDBO(); //NEW TESTS QUERY (what purchased test are available for use with 'item_available' == '1' {unused test} and matching current 'user_id') $new_query = " SELECT * FROM crt_transactionHistory WHERE user_id = ".$userID." AND item_available = '1' ORDER BY item_name, id "; $db->setQuery($new_query); $new = $db->loadAssocList(); //OPEN TESTS QUERY (what purchased test are available for use with 'item_available' == '2' {resume test} and matching current 'user_id') $resume_query = " SELECT * FROM crt_transactionHistory WHERE user_id = ".$userID." AND item_available = '2' ORDER BY item_name, id "; $db->setQuery($resume_query); $resume = $db->loadAssocList(); //DISPLAY use_test FORM if(!isset($_POST['test'])) { //SELECT FORM: WHICH TEST WOULD YOU LIKE TO USE? echo ' <fieldset> <table> <form method="post" action="'.$PHP_SELF.'">'; if (empty($new)) { echo ' <th colspan="3"align="left">NO NEW TESTS AVAILABLE</th>'; } else { echo ' <th colspan="3"align="left">NEW TESTS AVAILABLE</th> <tr> <td width="75px">SELECT</td> <td width="50px">ID</td> <td width="150px">TEST TYPE</td> <td width="150px">UNIQUE TEST ID</td> <tr>'; foreach ($new as $result1) { echo ' <tr> <td><input type="radio" value="' .$result1['id']. '" name="test_id"></td> <td>'.$result1['id'].'</td> <td><input type="hidden" value="'.$result1['item_name'].'" name="item_name">'.$result1['item_name'].'</td> <td><input type="hidden" value="'.$result1['item_number'].'" name="item_number">'.$result1['item_number'].'</td> <input type="hidden" value="'.$result1['item_available'].'" name="item_available"> <input type="hidden" value="'.$userID.'" name="userID"> <tr>'; } } echo ' </table> <hr /> <table>'; if (empty($resume)) { echo ' <th colspan="3"align="left">NO TESTS TO RESUME</th>'; } else { echo ' <th colspan="3"align="left">RESUME TEST</th> <tr> <td width="75px">SELECT</td> <td width="50px">ID</td> <td width="150px">TEST TYPE</td> <td width="150px">UNIQUE TEST ID</td> <tr>'; foreach ($resume as $result2) { echo ' <tr> <td><input type="radio" value="' .$result2['id']. '" name="test_id"></td> <td>'.$result2['id'].'</td> <td><input type="hidden" value="'.$result2['item_name'].'" name="item_name">'.$result2['item_name'].'</td> <td><input type="hidden" value="'.$result2['item_number'].'" name="item_number">'.$result2['item_number'].'</td> <input type="hidden" value="'.$result2['item_available'].'" name="item_available"> <input type="hidden" value="'.$userID.'" name="userID"> <tr>'; } } echo ' </table> </fieldset> <input type="submit" name="test" value="Conduct Test" /> </form> '; } //NOW A TEST HAS BEEN SELECTED FOR USE if(isset($_POST['test'])) { $test_id = $_POST['test_id']; $item_name = $_POST['item_name']; $item_number = $_POST['item_number']; $item_available = $_POST['item_available']; $userID = $_POST['userID']; echo $test_id.'<br />'; echo $item_name.'<br />'; echo $item_number.'<br />'; echo $item_available.'<br />'; echo $userID.'<br />'; //IF THIS IS A NEW TEST... if ($item_available == "1") { echo 'new test'; } //IF WE ARE RESUMING A TEST... elseif ($item_available == "2") { echo 'resume test'; } } } ?> Currently I have 5 entries in my table. Entring this query displays all five in the correct order. Code: [Select] SELECT * FROM products ORDER BY count DESC LIMIT 16 However, using this code, the first result is omitted and the last four are displayed. $query="SELECT * FROM products ORDER BY count DESC LIMIT 16"; $result = mysql_query($query); $row = mysql_fetch_array($result); echo '<div>'; while ($row = mysql_fetch_array($result)) { echo '<div>'.$row[product].'</div> <div>'.$row[count].'</div>'; } echo '</div>'; Can someone help me find my error? Thanks Hello folks, I've got a problem with a search script. It's searching a db containing various properties (as in buildings) and it's not quite returning the correct results. The search form asks that you select a house type (4 options, all of which are tick boxes) and then the last part of the form is select how many bedrooms you'd like (which is a drop-down list featuring numbers 2-5) What should happen is someone selects one or more of the tick boxes and then the number of bedrooms and it returns all the house types that were ticked but only those with the number of bedrooms that were specified in the original search. Currently the results are correct in that they're showing the correct house types, but the number of bedrooms isn't right. e.g. if you chose 2 bedrooms in the search it shows those, as well as 3, 4 and 5 bedrooms in the results. Can't figure it out but it will be something to do with && and OR in my search script. Can anyone suggest a tweak to this that might work? (I'm using the $_GET function because the search form is in a Flash movie) $Result = mysql_query("select * from property_names where TownHouse = '$_GET[TownHouse]' OR Apartment = '$_GET[Apartment]' OR Detached = '$_GET[Detached]' OR SemiDetached = '$_GET[SemiDetached]' && visible= 'Yes' && bedrooms = '$_GET[Bedrooms]' && bedrooms = '$_GET[Bedrooms]'") As expected when a die statement is triggered, my script is exited and ALL of the fields that have been filled in on my form are wiped clean. This however is proving to be annoying for users making mistakes. Is there a way to keep the data in the correctly filled in fields, and to just wipe or highlight the incorrectly filled in fields? Code: [Select] <?php function checkPostcode (&$toCheck) { $alpha1 = "[abcdefghijklmnoprstuwyz]"; $alpha2 = "[abcdefghklmnopqrstuvwxy]"; $alpha3 = "[abcdefghjkstuw]"; $alpha4 = "[abehmnprvwxy]"; $alpha5 = "[abdefghjlnpqrstuwxyz]"; $pcexp[0] = '^('.$alpha1.'{1}'.$alpha2.'{0,1}[0-9]{1,2})([0-9]{1}'.$alpha5.'{2})$'; $pcexp[1] = '^('.$alpha1.'{1}[0-9]{1}'.$alpha3.'{1})([0-9]{1}'.$alpha5.'{2})$'; $pcexp[2] = '^('.$alpha1.'{1}'.$alpha2.'[0-9]{1}'.$alpha4.')([0-9]{1}'.$alpha5.'{2})$'; $pcexp[3] = '^(gir)(0aa)$'; $pcexp[4] = '^(bfpo)([0-9]{1,4})$'; $pcexp[5] = '^(bfpo)(c\/o[0-9]{1,3})$'; $Postcode = strtolower($toCheck); $Postcode = str_replace (' ', '', $Postcode); $valid = false; foreach ($pcexp as $regexp) { if (ereg($regexp,$Postcode, $matches)) { $toCheck = strtoupper ($matches[1] . ' ' . $matches [2]); $toCheck = ereg_replace ('C\/O', 'c/o ', $toCheck); $valid = true; break; } } if ($valid){return true;} else {return false;}; } if(isset($_POST['submit'])) { $drop = mysql_real_escape_string($_POST['drop_1']); $tier_two = mysql_real_escape_string($_POST['Subtype']); $Name = mysql_real_escape_string($_POST["Name"]); $Phone = mysql_real_escape_string($_POST["Phone"]); $Email = mysql_real_escape_string($_POST["Email"]); $Postcode = mysql_real_escape_string($_POST["Postcode"]); $Website = mysql_real_escape_string($_POST["Website"]); if($Name == '') { die ("<div class=\"form\">You did not complete the name field, please try again</div>"); } elseif ($Phone == '' or (preg_match("/^([1]-)?[0-9]{3}-[0-9]{3}-[0-9]{4}$/i", $Phone))) { die("<div class=\"form\"> You completed the telephone field incorrectly, please try again</div>"); } elseif ($Email == '' or (!filter_var($Email, FILTER_VALIDATE_EMAIL))) { die("<div class=\"form\"> You completed the Email field incorrectly, please try again</div>"); } elseif ($Postcode == '' or (!checkPostcode($Postcode))) { die("<div class=\"form\"> You did not complete the Postcode field correctly, please try again</div>"); } elseif ($Website == '' or (!preg_match("~^[a-z0-9.-]+\.(com|org|net|edu|co.uk)~i", $Website))) { die("<div class=\"form\">You completed the website field incorrectly, please try again</div>"); } else { echo("<div id=\"formtwo\">Thankyou for submiting your details, you will be added to our directory shortly</div>"); } $query = ("INSERT INTO business (`id`, `Name`, `Type`, `Subtype`, `Phone`, `Email`, `Postcode`, `WebAddress`, `Confirmed`) VALUES ('NULL', '$Name', '$drop', '$tier_two' , '$Phone', '$Email', '$Postcode', '$Website', 'Yes')"); mysql_query($query) or die ( "<br>Query: $query<br>Error: " .mysql_error()); } ?> I have the following query: $getVideos = mysql_query("SELECT catergory, COUNT(catergory) as 'catCount' FROM videos GROUP BY catergory"); Using this in PHPMyAdmin returns the correct results of: catergory | catCount 0 | 7 1 | 1 10 | 2 How would get those results into a PHP array or what not...I have done this before but along time ago and cannot for the life of me remember how to do it. Hopefully someone can point me in the right direction? Regards, PaulRyan. this is the query: $query = "INSERT INTO kamerleden VALUES ('', '$twitter_id', '$name', '$nickname', '$fraction', '$residence', '$age', '$gender', '', '', '', '')"; it used to work but i switched to a different hosting. The first '' is the id which gives this error: query failed: Incorrect integer value: '' for column 'id' at row 1 in the database id is a int, with a length of 2 and with auto increment. How can i fix it? Incorrect login attempt 1 \/ Incorrect login attempt 2 \/ Incorrect login attempt 3 -->> ?forgot your login details? What's the most effecient way of achieving this? Is it to: 1. create a session for the user who hasn't logged in 2. the user login fails once, session['fail']=1 3. the user login fails twice, session['fail']=2 4. the user login fails for a third time pushing the session['fail'] count to three: this triggers an 'if' on the index.php prompting the user to retrieve their details through the "forgot login details system" However if the session['fail'] count never reaches 3 then this temp session is destroyed and the proper one created allowing the user into the site?? As usual any pointers into the correct direction here would be very much appreciated (and i try to repay by answering other peoples questions [where i can ]) Hi people, I really hope you guys can help me out today. I'm just a newbe at php and i'm having real trouble. Bassically all I want to do is have a user type in a company name in a html form. If what the user types in the form matches the company name in my php script i want the user to be sent to another page on my site. If what the user types in the form doesnt match the company name in my php script i want the user to be sent to a differnt page like an error page for example. this is my html form: Code: [Select] <form id="form1" name="form1" method="post" action="form_test.php"> <p>company name: <input type="text" name="company_name" id="company_name" /> </p> <p> <input type="submit" name="button" id="button" value="Submit" /> </p> </form> And this is the php code I'm trying to process the information on: Code: [Select] <?php $comp_name = abc; if(isset ($_POST["company_name"])){ if($_POST["company_name"] == $comp_name){ header("Location: http://www.hotmail.com"); exit(); } else{ header("Location: http://www.yahoo.com"); exit(); } } ?> The thing is i'm getting this error when i test it: Warning: Cannot modify header information - headers already sent by (output started at D:\Sites\killerphp.com\form_test.php:10) in D:\Sites\killerphp.com\form_test.php on line 17 Please can some one help me out, i'm sure this is just basic stuff but i just cant get it to work Cheers. Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this? <?php include ("includes/includes.php"); $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo "<p class='postnote'>" . $post->post . "</p"; echo "<span class='footer'>Posted By: " . $post->author . "</span>"; echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>"; echo "<span class='footer'>Tags: " . $post->tags . "</span>"; echo ' <div class="addthis_toolbox addthis_default_style "> <a class="addthis_button_facebook_like" fb:like:layout="button_count"></a> <a class="addthis_button_tweet"></a> <a class="addthis_counter addthis_pill_style"></a> </div> <script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script> <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>'; echo "</div>"; } ?> I have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. hey gurus, i am a newbie php coder.. i am learning by example. what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage) ---------------------------------------------------------------- the table structure that will be used is as follows: user.bonus_credit user.ID bonus_credit.bonusCode bonus_credit.qty bonus_credit.value bonus_credit_usage.bonusCode bonus_credit_usage.usedBy ---------------------------------------------------------------- so lets say, in bonus_credit i have the following bonusCode = 'facebook' (this is the code they have to type to redeem the bonus qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once) value = '5' (this is the amount of bonus_credit for each qty) Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit ----------------------- i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code. if(isset($_REQUEST['btnBonus'])) { $bonus_credit = addslashes($_REQUEST['bonusCode']); $query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'"; echo "<script>window.location='myreferrals.php?msgs=2';</script>"; mysql_query($query) or die(mysql_error()); } Advance thank you. Can you help please. The error..... Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24 code. Code: [Select] <?php //database connection. $DB = mysql_connect("localhost","root") or die(mysql_error()); if($DB){ //database name. $DB_NAME="mysql"; //select database and name. $CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name"); // if connection. }if($CON){ //show tables. $mysql_show="SHOW TABLES"; //select show and show. $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())"; } //if allowed to show. if($mysql_select2){ //while it and while($data=mysql_fetch_assoc($mysql_select2)){ //show it. echo $data; } } ?> Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code. $sql="select * from Profile where username = '$username'; $result = mysql_query( $sql, $conn ) or die( "ERR: SQL 1" ); if(mysql_num_rows($result)!=0) { process form } else { echo "That username already exist!"; } the current code of the form <?PHP //session_start(); require_once "formvalidator.php"; $show_form=true; if (!isset($_POST['Submit'])) { $human_number1 = rand(1, 12); $human_number2 = rand(1, 38); $human_answer = $human_number1 + $human_number2; $_SESSION['check_answer'] = $human_answer; } if(isset($_POST['Submit'])) { if (!isset($_SESSION['check_answer'])) { echo "<p>Error: Answer session not set</p>"; } if($_POST['math'] != $_SESSION['check_answer']) { echo "<p>You did not pass the human check.</p>"; exit(); } $validator = new FormValidator(); $validator->addValidation("FirstName","req","Please fill in FirstName"); $validator->addValidation("LastName","req","Please fill in LastName"); $validator->addValidation("UserName","req","Please fill in UserName"); $validator->addValidation("Password","req","Please fill in a Password"); $validator->addValidation("Password2","req","Please re-enter your password"); $validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!"); $validator->addValidation("email","email","The input for Email should be a valid email value"); $validator->addValidation("email","req","Please fill in Email"); $validator->addValidation("Zip","req","Please fill in your Zip Code"); $validator->addValidation("Security","req","Please fill in your Security Question"); $validator->addValidation("Security2","req","Please fill in your Security Answer"); if($validator->ValidateForm()) { $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error()); mysql_select_db("beatthis_beatthis") or die(mysql_error()); $FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file $LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file $UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file $Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file $Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file $email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file $Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file $Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file $Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file $Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file $sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; //echo $sql; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } else{ mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body); echo "<h3>Your profile information has been submitted successfully.</h3>"; } mysql_close($con); $show_form=false; } else { echo "<h3 class='ErrorTitle'>Validation Errors:</h3>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<p class='errors'>$inpname : $inp_err</p>\n"; } } } if(true == $show_form) { ?> |
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