PHP - Create Html Table From Category And Subcategory

Hello,

I have been searching and trying all sorts of ways to get my sub categories drop down to show the correct info after selecting a category from the main drop down but im getting stuck.

It's pulling the categories and sub categories from the mysql database fine but no matter which main category i pick it keeps showing the same result in the sub category.

My brother said i need to use some sort of onchange do this so the sub category list refreshs but everything i have tried doesn't work..


PLEASE could some one help.

MANY MANY THANKS


This is the category form
Code: [Select]
  <select name="job_cats" style="width:165px">
    <?PHP

$query1 = "SELECT * FROM job_cats";
$result1 = mysql_query($query1) or die ("query 1 failed");
$count1 = mysql_num_rows($result1);

for ($i = 0; $i < $count1; $i++) {
$row1 = mysql_fetch_array($result1);
$job_cats_title1 = $row1['title'];
$job_cats_id1 = $row1['id'];


echo '<option value="'.$job_cats_id1.'">'.$job_cats_title1.'</option>';

echo $job_cats_id1;
}
    ?>
    </select>
this would echo this in the main category list:

cat1
cat2
cat3
cat4




this is the sub category form
Code: [Select]
  <select name="job_sub_cats" style="width:165px">
 
    <?PHP
$query1 = "SELECT * FROM job_sub_cats WHERE job_cats_id = $job_cats_id1";

$result1 = mysql_query($query1) or die ("query 1 failed");
$count1 = mysql_num_rows($result1);


for ($i = 0; $i < $count1; $i++) {
$row1 = mysql_fetch_array($result1);

$sub_cats_id1 = $row1['id'];
$sub_cats_title1 = $row1['subTitle'];
$cats_id1 = $row1['job_cats_id'];

echo '<option value="'.$sub_cats_id1.'">'.$cats_id1.'</option>';

}
    ?>
    </select>


this should echo this:

1
2
3
4

but it keeps echoing just the number 4.


THANKS
PLEASE HELP

ricky

This topic has been moved to HTML Help.

http://www.phpfreaks.com/forums/index.php?topic=323045.0

I have a table in my database for users. On the registration page I want to create another table with the id of the user as the table name.

$sql = "CREATE TABLE IF NOT EXISTS `id_prod` (
)

how do i modify this line so that it takes the id from the user table and creates a new table with id as name followed by prod.

For the life of me I can not figure out why this is not creating the table in the database.  Second set of eyes would be great.

 

function install_kudos() {
 	
 	    global $wpdb;
        $table_name = $wpdb->prefix . 'acikudosnew';
 
        if ($wpdb->get_var('SHOW TABLES LIKE ' .$table_name) != $table_name) 
        {
	    $sql = "CREATE TABLE $table_name (
		kudoid int(9) NOT NULL AUTO_INCREMENT,
        kudomsg text NOT NULL,
        kudoagent text NON NULL,
        kudocust text NOT NULL,
        kudoacct int(16) NOT NULL,
        kudoclient varchar(100) NOT NULL,
        kudoloc text NOT NULL,
        kudoentry TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
        kudoadmin text NOT NULL,
		kudopic varchar(55) DEFAULT '' NOT NULL,
		PRIMARY KEY  (kudoid) )";
	       
	require_once( ABSPATH . 'wp-admin/includes/upgrade.php' );
	dbDelta( $sql );
	}
 	
 }
  
register_activation_hook(__FILE__, 'install_kudos');

 

 

Hello,
 
please let me know how to write xml file, i read somewhere we can use psql.....anyone knows please help!
 
Thanks

I want to show a table with a max of three columns.
I am using an if statement to count the rows and then start a new row (after 3 cols),
I cant see my error. The output just gice one col with all the data in it.
Any help appreciated.
Code: [Select]


<form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST" id="cover" enctype="multipart/form-data">
            <table width="700"><?php
            /* display picture and radio button */
            //add counter for more than 3 images
            $i=0;
            $size=3;
            while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
              {
                
               $coverID=$row['coverID'];

                echo"<tr>";
                
                echo "<td>";
                echo"<img src=\"/wordpress_3/wp-content/plugins/Authors2/jackets/{$row['pix']}\" />";
                
                echo "<input type = 'radio' name ='cover' value= '$coverID'/>";
                ?>
                <br />
                <input type="submit" value="submit">
                <?php
                echo"</td>";
                $i++;
                        if($i==$size)
                    {
                        echo "</tr><tr>";

                        $i=0;
                    }
                
               }
                ?></table>

                </form><?php

Code: [Select]
<?
$link = mysql_connect($dbhost,$dbuser,$dbpass) or die ('Could not connect: ' . mysql_error());
mysql_select_db($dbname) or die ('Error connecting to database');
$sql = "SELECT * FROM papers WHERE ctitle='May 2012'";
$result = mysql_query($sql);
$num = mysql_num_rows($result); //number of entry
$data = mysql_query("select * from papers where ctitle='May 2012' ORDER BY id ASC");

$Wrd = new COM("Word.Application");
$Wrd->Application->Visible = False;
$DocName = "MyDoc/MyWord.doc";

$WrdDoc = $Wrd->Documents->Add();
$WTable = $WrdDoc->Tables->Add($Wrd->Selection->Range, 2, $num); // Colums, Rows

while($info=mysql_fetch_array($data))
{ $i=1;
$WTable->Cell($i,1)->Range->Text = $info['title'];
$WTable->Cell($i,2)->Range->Text = $info['name'] $info['surname'] $info['institution'] $info['country'];
$i++;
        }
$Wrd->ActiveDocument->SaveAs(realpath($DocName));
$Wrd->Application->Quit;
$Wrd = null;
?>
Word Created <a href="<?=$DocName?>">Click here</a> to Download.

php script is not working. Can someone please help me to detect the errors?

i want create a table in ms word file for all entry in my database... "2 columns, number of rows"

Cell(1,1)  Cell(1,2)
Cell(2,1)  Cell(2,2)
etc...
Cell(3,1)  Cell(3,2)

Had some great help yesterday, but I'm stuck using <?php ?> on every line, thanks to Joomla

Anyway, I'm trying to create a table, and it doesn't seem to be working, to create it, what is the correct format?

 <?php <table width='400px' border ='1'>; ?>   ??

output will be put out on a per line within a if statement, which works, just the framing of the table and tr and td seem to be eluding me.

Thanks

Im messing around with functions and arrays but cant seem to get this to work. It basically creates a simple table with the parameters you specify. The array however doesnt go into the table properly.


function asf_create_table($rows, $cols, $border=1, $padding=5, $td_border=1, $contents)
{
$table = "<table style=\"border: {$border}px solid; padding:{$padding}px;\">";

for ($t_rows=0; $t_rows<$rows; $t_rows++)
{
$table .= "<tr>";
}

for ($t_cols=0; $t_cols<$cols; $t_cols++)
{
for ($i=0; $i<$cols; $i++)
{
$table .= "<td style=\"border: {$td_border}px solid;\">";
$table .= $contents[$i];
$table .= "</td>";
}
}

for ($t_rows=0; $t_rows<$rows; $t_rows++)
{
$table .= "</tr>";
}


$table .= "</table>";

echo $table;
}



$t_contents = array("Cell 1", "Cell 2", "Cell 3", "Cell 4");

asf_create_table("4", "4", "1", "5", "1", $t_contents);


instead of 4 cells each with Cell # in them i get 16 cells with the cell #. the 4 displayed 4 times.

i'm trying to achive this results layout: 

example:
                     catagory
                           comment
                           comment
                           comment
                     catagory
                     catagory
                     catagory
                           comment

what is being pulled now is if their is 2 comments two 1 catagory then 2 catagorys are being returned with the same id. what i want is to return one cataogry with many comments.

thanks in advance for your help.

Code: [Select]
<?php require_once('Connections/Del_Comments.php'); ?>
    <?php 
    $all_ids = array();
    $str_ids = "";
     
    // first parent query
    $maxRows_sourceType = 10;
    $pageNum_sourceType = 0;
    if (isset($_GET['pageNum_sourceType'])) {
      $pageNum_sourceType = $_GET['pageNum_sourceType'];
    }
    $startRow_sourceType = $pageNum_sourceType * $maxRows_sourceType;
     
    mysql_select_db($database_Del_Comments, $Del_Comments);
    $query_sourceType = "SELECT a.Id, a.Type, 
a.Dates, 
a.UIdFk, 
b.Id as Did, 
b.comment, 
b.dates as Day, 
b.sfk as Sfk ,
c.sfk as sfk1, 
d.Memo as memo
FROM 
asstatusupdate as a   
left join asstatusdata as b 
on a.id = b.sfk 
left join asmanystatusupdate as c
on b.sfk = c.sfk
left join ascomments as d
on d.id = c.cfk
where a.uidfk='1'
 order by Dates asc";
    $query_limit_sourceType = sprintf("%s LIMIT %d, %d", $query_sourceType, $startRow_sourceType, $maxRows_sourceType);
    $sourceType = mysql_query($query_limit_sourceType, $Del_Comments) or die(mysql_error());
    $row_sourceType = mysql_fetch_assoc($sourceType);
     
    if (isset($_GET['totalRows_sourceType'])) {
      $totalRows_sourceType = $_GET['totalRows_sourceType'];
    } else {
      $all_sourceType = mysql_query($query_sourceType);
      $totalRows_sourceType = mysql_num_rows($all_sourceType);
    }
    $totalPages_sourceType = ceil($totalRows_sourceType/$maxRows_sourceType)-1;
     
    // add the array
    while ($row_source = mysql_fetch_assoc($sourceType)) {
     
        $all_ids[] = $row_source['Sfk'];
     
        $str_ids .= $row_source['Sfk'].',';
     
     }
     
            // remove the array
         $str_ids = (substr($str_ids,-1) == ',') ? substr($str_ids, 0, -1) : $str_ids;
    
echo $str_ids;
    //echo $all_ids;

//second child query
        $maxRows_sourceComments = 10;
    $pageNum_sourceComments = 0;
    if (isset($_GET['pageNum_sourceComments'])) {
      $pageNum_sourceComments = $_GET['pageNum_sourceComments'];
    }
    $startRow_sourceComments = $pageNum_sourceComments * $maxRows_sourceComments;
     
    mysql_select_db($database_Del_Comments, $Del_Comments);
    $query_sourceComments = "SELECT 
c.sfk as sfk1,
d.Memo as memo
FROM 
asmanystatusupdate as c
left join ascomments as d
on d.id = c.cfk
where c.uidfk0='1' and c.sfk in ($str_ids)";
    $query_limit_sourceComments = sprintf("%s LIMIT %d, %d", $query_sourceComments, $startRow_sourceComments, $maxRows_sourceComments);
    $sourceComments = mysql_query($query_limit_sourceComments, $Del_Comments) or die(mysql_error());
    $row_sourceComments = mysql_fetch_assoc($sourceComments);
     
    if (isset($_GET['totalRows_sourceComments'])) {
      $totalRows_sourceComments = $_GET['totalRows_sourceComments'];
    } else {
      $all_sourceComments = mysql_query($query_sourceComments);
      $totalRows_sourceComments = mysql_num_rows($all_sourceComments);
    }
    $totalPages_sourceComments = ceil($totalRows_sourceComments/$maxRows_sourceComments)-1;
     
     
     
    $resultComments = @mysql_query($query_sourceComments, $Del_Comments);
    $numComments = @mysql_num_rows($resultComments);
     
     
    $result = @mysql_query($query_sourceType, $Del_Comments);
     
    $num = @mysql_num_rows($result);
     
    // column count for parent
        $thumbcols = 1;
     
            // column count for parent query
        $thumbrows = 1+ round($num / $thumbcols);
     
                // column count for child query    $thumbrowsComments = 1+ round($numComments/$thumbcols);
     
                // header
                print '<br />';
                print '<table align="center" width="500" border="3" cellpadding="0" cellspacing="0">';
     
                if (!empty($num)) {
                    print '<tr><td colspan="3" align="center"><strong>Returned Num of Record Sets: ' .$num. ' and comments count' .$numComments. '</strong></td></tr>';    
     
                }
     
        // table layout for parent query        

function display_table() {
     
    // global variables
    global $num, $result, $thumbrows, $thumbcols, $resultComments, $numComments, $thumbrowsComments ;
     
    // row count for parent
     for ($r=1; $r<=$thumbrows; $r++) {
     
         // print table row
             print '<tr>';
     
    //format the columns
    for ($c=1; $c<=$thumbcols; $c++) {
     
    print '<td align="center" valign="top">';
     
        $row = @mysql_fetch_array($result);
$row1 = @mysql_fetch_array($resultComments);
     
        $Id = $row['Id'];
        $Type = $row['Type'];
        $Dates = $row['Dates'];
$Comment = $row['Comment'];
$Sfk1 = $row['sfk1'];
$Memo = $row['memo'];


    // test if not empty show record sets            
        if (!empty($Id)) {
     
                                // print output from parent query
     
                       
                                        // grab type dates comment and format for there column
     
                                        echo '<td valign="top" align="center">'; 
                                        echo "$Type"; echo '&nbsp;&nbsp;'; echo "$Dates"; echo '<br />';echo '<br />';echo '<br />';
                                        echo "$Comment"; echo '</td>';
                                        echo '<td>'; echo "$Id"; echo '</td>';
                                        echo '<td>'; echo "$str_ids"; echo '</td>';

                             echo '<tr>';
echo '<td>'; echo "$Sfk1"; echo '</td>';
echo '<td>'; echo "$Memo"; echo '</td>';
echo '</tr>';

} // closing the $id loop
     


                                                    else {
                                                            print '&nbsp;&nbsp;';
                                                        }
                                print '</td>'; //closing the table data
                            } //closing the rows
                                print '</tr>';
                 } // closing the outter loop
                //} //closing fk id loop
                                print '</td>'; //closing the table data
                    } //closing the rows
                                print '</tr>';    
              
        //} // closing the main loop
     
                    // call the main table
                display_table() ;
                    print '</table>';
     
     
    ?>
     
     
     <?php
var_dump(substr('a', 1)); // bool(false)
?>

Hi, I need a quick tip. I want this script to produce an output of "Table created" if it succesfully creates a table.

<?php
$con = mysql_connect("localhost","****","****");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

// Create table
mysql_select_db("my_db", $con);
$sql = "CREATE TABLE People
(
FirstName varchar(15),
LastName varchar(15),
Age int
)";

// Execute query
mysql_query($sql,$con);

mysql_close($con);
?> 

I tried to do it on my own, but I guess I'm still completely new to php 
I tried:
<?php
$con = mysql_connect("localhost","****","****");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

// Create table
if (mysql_select_db("my_db", $con))
  {
  echo "Table created";
  }
else
  {
  echo "Error creating Table: " . mysql_error();
  }
$sql = "CREATE TABLE People
(
FirstName varchar(15),
LastName varchar(15),
Age int
)"


// Execute query
mysql_query($sql,$con);

mysql_close($con);
?> 

It gave me an error with the last two lines
mysql_query($sql,$con);

mysql_close($con);

 I removed them and it really did give the output "Table created" yet it didn't create the table in the database. I'm having a feeling that I need to add an "if" statement, something of the sort.

if (sql(CREATE TABLE Persons))

But I'm also getting the feeling something there is wrong, I still haven't tried it. 

Help?

Dear All,

As I would like to create json as below format 

{
    "data": [
        {
            "title": "After getting a COVID-19 Vaccine",
            "content": [
                {
                    "list": "You may have some side effects, which are normal signs that your body is building protection."
                },
                {
                    "list": "Following symptoms can take place, and it usually resolves within 2 to 3 days."
                },
                {
                    "list": "Common Side Effects pain, redness, swelling, warmth, nausea, muscle pain, tiredness, headache"
                }
            ]
        },
        {
            "title": "After getting a COVID-19 Vaccine",
            "content": [
                {
                    "list": "You may have some side effects, which are normal signs that your body is building protection."
                },
                {
                    "list": "Following symptoms can take place, and it usually resolves within 2 to 3 days."
                },
                {
                    "list": "Common Side Effects pain, redness, swelling, warmth, nausea, muscle pain, tiredness, headache"
                }
            ]
        }
    ]
}

The information is from  mysql select command:

SELECT (tb_helpinfo.title_eng) as title,(tb_helpdetail.content_eng) as content FROM tb_helpinfo INNER JOIN tb_helpdetail ON tb_helpinfo.id = tb_helpdetail.helpinfo_id

 

How could I make json like that from mysql information?

i m tryin to create table from mysql coding and when i run the script its runs without any errors and just show that its created table but whn i chk into phpmyadmin i cnt find my table there and also when i use some copy paste from some website its just do the same thing but this time table is created but i cant find any difference between my table and the website table but still my script wont work please help me where is the mistake

$connection=mysql_connect("127.0.0.1","root","");
$db=mysql_select_db("addressbook",$connection);
if($db){


$SQL="CREATE TABLE address_data_new
{
ID int(7) NOT NULL auto_increment,
First_name varchar(50) NOT NULL,                  ################## MY SCRIPT################
Last_name varchar(50) NOT NULL,
email varchar(50) NOT NULL,
PRIMARY KEY (ID),
UNIQUE Id (ID)
 }";

 /*
 $SQL="create table address_data
 {
ID int(7) NOT NULL auto_increment,                                          ############# working script############
First_Name varchar(50) NOT NULL,
Surname varchar(50) NOT NULL,
email varchar(50),
PRIMARY KEY (ID),
UNIQUE id (ID)
 )";
 
 */


mysql_query($SQL);
mysql_close($connection);
echo "table added successfully";
}
else {
echo "database not found";
}
?>