PHP - Update Data Where Id Exist , Insert If Not Exist Id
i have error where my code should update existing data where id exist, it get updated ..but the others data is disappeared .only the data updated is remained $sql1 ="select*from semakan_dokumen where email='$stdEmail'"; $sqlsearch1 = mysqli_query($dbconfig,$sql1); $resultcount1 = mysqli_num_rows($sqlsearch1); if($resultcount1 > 0){ $query1=("UPDATE semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3',sijil_sekolah= '$fileName4', sijil_dip= '$fileName5',sej_julai='$fileName6',bm_julai='$fileName7',muet='$fileName8', mid1='$fileName9',yuran= '$fileName10',umpa_bend1= '$fileName11',umpa_bend2='$fileName12',bpkp='$fileName13', penaja='$fileName14',kesihatan= '$fileName15', jhepa='$fileName16' where email= '$stdEmail' "); }else{ //filezip $query1 = "INSERT INTO semakan_dokumen (email,surat_tawaran,ic,sijil_lahir,sijil_spm,sijil_sekolah,sijil_dip,sej_julai,bm_julai,muet,mid1,yuran,umpa_bend1,umpa_bend2,bpkp,penaja,kesihatan,jhepa) VALUES ('$stdEmail','$fileName','$fileName1','$fileName2','$fileName3','$fileName4','$fileName5','$fileName6','$fileName7','$fileName8','$fileName9','$fileName10','$fileName11','$fileName12','$fileName13','$fileName14','$fileName15','$fileName16')"; }
Similar TutorialsI need to insert data into a table if it doesn't exist or update if it does. Can someone give me an example of this code. im using mySQL 5.1.42 im using phpMyAdmin 3.1.o //database create table mydata ( id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT, fname varchar(20), phoneno int(12) NOT NULL /*......*/ ); //class my data php <?php include('connect.php'); class InsertMydata { public function insertnow($fname, $phoneno) { $connect = new Connect; $insrt = $db -> prepare('INSERT INTO mydata (fname, phoneno) VALUES (?,?)'); $insrt -> execute(array($fname, $phoneno)); } } ?> //insernow validate form <?php include('../classs/mydata.php'); //Declare data and error arrays $errors = []; $mydara = []; if(!preg_match('/^[a-zA-Z]{4,15}$/', $_POST['fname'])) { $errors['fname'] = 'Enter full name!'; } //this block not working even the phone exist $connect = new Connect; $phoneno = $_POST['phoneno']; $checkiexist = $connect -> prepare('SELECT * FROM mydata WHERE phoneno = ?'); $checkiexist -> execute([$phoneno]); if($checkiexist->rowCount() > 0) { $errors['phonenoexist'] = 'Try another phone number!'; } if(!empty($errors)){ $data['success'] = false; $data['errors'] = $errors; }else{ $data['success'] = true; $data['message'] = 'success message!'; $mydata = new InsertMydata; $mydata -> insertnow($fname, $phoneno); } echo json_encode($data); ?> //my ajax $("#insertbtn").click( function(e) { var fname = $('#fname').val(), phoneno = $('#phoneno').val(), $.ajax({ url: 'insertnow.php', type: 'POST', data: {fname:fname, phoneno:phoneno}, dataType: "JSON", encode: true, }).done( function (data) { if (data.success == false) { if (data.errors.fname) { $('#fname').append('<p class="text-danger">' + data.errors.fname + '</p>'); } if (data.errors.phonenoexist) { $('.card-header').append('<div class="alert alert-info alert-dismissible" role="alert"> <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.errors.phonenoexist+'</div>'); } } else { $('.card-header').append('<div class="alert alert-success alert-dismissible" role="alert"><button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.message+'</div>'); } }); e.preventDefault(); }); //the problem is, the code insert data even if the phone exist why? the problem is, the code insert data even if the phone exist why? Edited April 8 by mahendai wanting users to be able to update there email address and check to see if the new email already exists. if the email is the same as current email ignore the check. i have no errors showing up but if I enter a email already in the db it still accepts the new email instead of bringing the back the error message. Code: [Select] // email enterd from form // $email=$_POST['email']; $queryuser=mysql_query("SELECT * FROM members WHERE inv='$ivn' ") or die (mysql_error()); while($info = mysql_fetch_array( $queryuser )) { $check=$info['email']; // gets current email // } if($check!=$email){ // if check not equal to $email check the new email address already exists// $queryuser=mysql_query("SELECT * FROM members WHERE email='$email' "); //$result=mysql_query($sql); $checkuser=mysql_num_rows($queryuser); if($checkuser != 0) { $error= "0"; header('LOCATION:../pages/myprofile.php?id='.$error.''); } } cheers if so how would they be used in a mysql query? hi, i have a select which gets todays schedule for each user. sometimes that user doesnt have anything for todays date and it will display the info from the user above him. how can i make it so it stays blank if there is no record? Gud pm!! So i made this script to check if a username and password exist but it kinda fails me. It gives me a database connection error from my confirm_query() which means it returned false? so here's my code: Code: [Select] function check_if_exist($username, $password) { global $connection; $query = "SELECT username, hashed_password"; $query .= "FROM users "; $query .= "WHERE username = '$username' "; $query .= "AND hashed_password = '$password' "; $query .= " LIMIT 1"; $result_set = mysql_query($query, $connection); confirm_query($result_set); if(mysql_num_rows($result_set) == 1) { return true; } else { return false; } } my confirm_query(): Code: [Select] function confirm_query($result) { if(!$result) { die("Database connection failure ". mysql_error()); } } I have a another script to check if the email exist and it works perfectly, i dunno why this won't work properly.. maybe another simple mistake.. Any ideas or Violent reaction? Thanks! Hi all, I want to make a script that identifies if an image JPG file exists. Would somthing like this work? <?php $file = "images/image.jpg"; if ($file > 0) { echo "file exists"; } else { echo "no file"; } ?> Basically this gets a number from a table on my DB, and displays the content relevent to that number...the second part checks for that number and gets other information according to that number... what i want to do is make sure that the number from the first query exists in the table from the query, and if it doesn't print out and error saying "there is no information" or whatever.. anyone have an idea? hopefully this makes sense Code: [Select] <?php require_once('Connections/myConnect.php'); $detnum = $_GET['Details']; $detinfo = mysql_query("SELECT* FROM `Agency Stores - Table 1` WHERE F11=".$detnum); $det = mysql_fetch_array($detinfo); $salesnum = $det['F3']; $salesinfo = mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum); $sales = mysql_fetch_array($salesinfo); if(mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum)){ } ?> Does the concept of a "Namespace" exist in PHP? If so, how do you use them? This is a snippet from ASP.NET that made me ask this question... Quote <%@ Import Namespace="System.Data" %> <%@ Import Namespace="System.Data.SqlClient" %> TomTees hello, i am having an issue with tables using incorrect data. i have 2 columns, first is employee name, second is location if the employee doesnt have a location for the current day, it is telling me he is at the same location as the guy in the row above him. i need this to be blank. is this possible? Hi.. So what i want to do is basicly to check if id XX exist in my database. How can this be done? Im thinking of something like: if(xx exist){do this} else{do this} Iv'e tried google etc before i posted here, but couldent really find anything where i found a soutable answer.. Hope someone can help! (: hi, im having trouble adding a get variable to a url if one already exists. eg current url = http://www.example.com/index.php?var1=something i want to be able to change this to new url = http://www.example.com/index.php?var1=something&var2=another even so i can have a few get variable there. I can add the first var through a form or link, but how would i add more through a link or through the header function? I am positivly stuck. Thanks Hi all - I have a form that let's a user upload an image to their specified folder. The folder is determined by the "password" the user inputs. The "password" is really just the folder name on my server, so if "michael83" was entered as a password, the directory would be "images/uploaded/michael83". That works great now, thanks to a forum user, litebearer. Thanks again. Here's my second question: I'm working on a "history" page so that a user can input their "password" and view their upload history. The form works right now. If you enter a "password" (folder name) that exists, the code will spit out the contents / files. So, now I'm looking for two things: (1) if a user enters a "password" (folder name) that exists, but there are no files in the folder, "There are no files in the $dir directory." will be echoed; and (2) if a "password" (folder name) is entered that does NOT exist, "The directory $dir does not exist." will be echoed. Here's my code so far (minus the if statements I'm looking for): $dir = $_POST['password']; $path = "images/uploaded/". $dir; $dir_handle = @opendir($path); while ($file = readdir($dir_handle)) { if($file == "." || $file == ".." ) continue; if(isset($_POST['Submit'])) $url = "http://www.mysite.com/". $path . "/" . $file; { echo "<a href=\"$url\">$url</a><br />"; }} closedir($dir_handle); As always, many thanks in advance for any help on this. I have a field in a table named flights I hope to find a 1 line statement to bypass inserting a new row if $flight_no is already in the field flight_no btw flight_no is the primary key and won't allow a duplicate anyway but I want to avoid the error message this is what I tried but doesn't work if(SELECT * FROM flights WHERE flight_no !LIKE %$flight_no%) { Is it possible to check if multiple rows exist at the same time. For example, if a row with the id "1" and another row with id "2" exists, and return something like true then false if only the first exists?
I have a file that provides tens of thousands to check and it takes forever. I know this sounds bad off the start, but it's not something that is run normally. Only to update my database with new additions.
Is there any good way to check a lot at once? I know you can insert many at a time and save a lot of time.
Here is my code so far (I say it's PDO but it pretty much isn't. What is the object here? The database connection? LOL!); $sql = " SELECT SUM(IF(`sent` != 'N' , 1 , 0 )) as 'Emails Sent', SUM(IF(`completed` NOT IN('N','paper') , 1 , 0 )) as 'Completed Electronically', SUM(IF(`completed` = 'paper' , 1 , 0 )) as 'Completed Manually', SUM(IF(`completed` != 'N' , 1 , 0 )) as 'Total Number Completed', SUM(IF(`remindercount` = '1' , 1 , 0 )) as 'Reminder Sent Once', SUM(IF(`remindercount` = '2' , 1 , 0 )) as 'Reminder Sent Twice', SUM(IF(`remindercount` = '3' , 1 , 0 )) as 'Reminder Sent Thrice' FROM `tokens_$survey_id` "; $statement = $dbh->prepare($sql); $statement->execute(); $result = $statement->fetch(PDO::FETCH_OBJ); foreach($result as $key => $value) { echo "<tr> <td>$key</td> <td>$value</td> </tr>"; }This is all well and good if the tokens_$survey_id table is actually there. Sometimes, for a genuine reason, there won't be a tokens table for that particular survey. How do I account for this? At the moment I get an error.. Warning: Invalid argument supplied for foreach() in /var/www/html/index.php on line 149I tried this but I am not satisfied this is correct; if(!$result) { die(); }I don't want the code to die! If I take out the die() statement then this if is ignored for some reason I don't understand. hi, im getting the error Quote Fatal error: Call to undefined function notification() in C:\xampp\htdocs\xampp\index.php on line 21 after including the functions.php file i wrote. It does include it but the data isnt being recognised from it. If i copy/paste the notification() function into index.php it works. Can someone tell me why so i can fix it? Working with authorize.net script that is included in my php. Trying to figure out how to use a variable beyond the 'case' I can do just about anything... inside the case... But I need to use the variable outside of there. Code: [Select] //several cases above case 5: $this->approval_code = $pstr_trimmed; break; // case 7 is the authorize.net transaction ID - This is the one I want to work with case 7: echo "Transaction ID: "; echo $pstr_trimmed; $trans_id_test = $pstr_trimmed; break; // but this below won't work. I can't use the variable anywhere outside of the case. echo "the new variable is now...".$trans_id_test; I'm writing a dropdown menu of countries states/regions, that pulls from an xml file... but some countries don't have a specific state/region (IE Antarctica). If they don't, then the XML file isn't formatted in the same way There is more to this, but the relevant part is he echo "<select name=\"statename\">\n"; echo "<option value=\"\">Select a state</option>\n"; $statexml = simplexml_load_file($state); foreach ($statexml->geoname as $statelink) { if($statelink) { echo "<option value='{$statelink->name}'>{$statelink->name}</option>\n"; } else { echo "<option value='none'>none</option>\n"; } } echo "</select>"; A state xml with results looks like this: Code: [Select] <?xml version="1.0" encoding="UTF-8" standalone="no"?> <geonames style="MEDIUM"> <totalResultsCount>51</totalResultsCount> <geoname> <name>Alabama</name> ...etc, etc </geoname> <geoname> <name>Alaska</name> ...etc, etc </geoname> </geonames> And an xml with no results looks like this: Code: [Select] <?xml version="1.0" encoding="UTF-8" standalone="no"?> <geonames> <status message="no children for Antarctica 6697173" value="15"/> </geonames> Saying the if($statelink) isn't working, as any country without a state simply doesn't display the 'none' selection. Code: [Select] <select name="statename"> <option value="">Select a state</option> </select> Any help?? Hello, i want to check whether image exist or not, but i can't get any data about it. I have tried everything: getimagesize, file_exist, filesize, etc. <? $info = @getimagesize('http://jargames.eu/ic.php?lf=files/All phone/240x320/007-quantum_of_solace_240x320.jar'); if(isset($info['mime'])){echo 'Image exist';} else{echo 'Image doesnt exist';} ?> Ty, for your help. |