PHP - I Need Help With My Select On My Search Box
So basically my select is giving me results that I don't want , please take a look at it , if you can help me I would appreciate it thank you.
Im searching for something with the letter j in it , be it the user or the nome_proprio row
it gives me this:
heres the code aswell
As you can see I just want where user LIKE '$procura' , i had the ,OR nome_proprio LIKE '$procura' , but it just gives more posts come from here :
If you need something more like the code itself , i can provide it Thank you for your time and help:D Edited June 15 by ribeiroSimilar Tutorialshi all, in mysql, how can i extract 100 words before and 100 words after my search key? example: "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nulla est nibh, mattis eu mattis id, pulvinar eu augue. Duis ut sem nisi. Sed id ante sed orci vestibulum lacinia ac id nibh. Donec cursus, elit eget auctor semper, ipsum eros laoreet quam, nec ullamcorper" vestibulum is my search key Hi, I have a search form where users can search by age and country. Users can also save their search so they can go back and do it again but the problem is when they reload their saved search, I need it to select the country that has been saved in the drop down. So if someone searched the United Kingdom, I need it to show United Kingdom in the select drop down instead of (Select Country). Is there any easy and quick way around this? Many Thanks Hello, I had 8 select boxes(dropdowns) in a form. Its like a search kind of implementation in the website. I don't know what the user selects, he may choose different select boxes, any number of select boxes. So, based upon the user selection, I need to generate the data. The data fields to be generated would be almost same. So, How would I know what the user selection is and how many select boxes has been selected and how could I generate different data based upon selected boxes. I had to make a small note abt this, that the data generation fields may change for some of the user select combinations, but most of the result fields would be same. so, can you please help me out, how to do, how to make different combination data generations, because, i had 8 fields, i had to make 8! combinations, that would result in a big code. The result pages is supposed to have pagination like google help me please
I require a page to be added to my website. This page will facilitate a refined search via Google, Bing and Yahoo search engine simultaneously , show the top 5 of each engine. Is this possible using php ? Thank's hirealimo.com.au/code1.php this works as i want it: Quote SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1 but apparelty selecting * is not a good thing???? but if I do this: Quote SELECT priceID, price FROM price INNER JOIN vehicle....etc it works but i lose the info from the vehicle table. but how do i make this work: Quote SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc so that i am specifiying which colums from which tables to query?? thanks Hello, Does anyone know a tutorial I can follow to create my own search engine over the items I have in my SQL database? I find a lot of tutorials but they are all 'one word searches' which means if you type two words you will get all results that contain either word (too many hits). If the search engine tutorial displays result with AJAX even better. Thanks for help. df Hello. I am working on a php script for searching a database table. I am really new to this, so I used the this tutorial http://www.phpfreaks.com/tutorial/simple-sql-search I managed to get all the things working the way I wanted, except one important and crucial thing. Let me explain. My table consist of three columns, like this: ID(bigint20) title(text) link (varchar255) ============================= ID1 title1 link-1 ID2 title2 link-2 etc... Like I said, I managed to make the script display results for a search query based on the title. Want I want it to do more, but I can't seem to find the right resource to learn how, is to place a "Download" button under each search result with its corresponding link from the table. Here is the code I used. <?php $dbHost = 'localhost'; // localhost will be used in most cases // set these to your mysql database username and password. $dbUser = 'user'; $dbPass = 'pass'; $dbDatabase = 'db'; // the database you put the table into. $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error()); mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error()); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 3) { $error[] = "Search terms must be longer than 3 characters."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT title, link FROM db WHERE title LIKE '%{$searchTermDB}%'"; $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } ?> <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?> <form method="GET" action="search?" name="searchForm"> Search for title: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" /> <input type="submit" name="submit" value="Search" /> </form> <?php echo (count($results) > 0)?"Rezultate lucrari de licenta sau disertatie pentru {$searchTerms} :<br /><br />" . implode("", $results):""; ?> $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; I would like the results to be displayed like this Results for SearchItem: Result 1 Download | Other link Result 2 Download | Other link etc.... or something like this. So, how do I add the data from the link row into a text(Dowload), within an <a href> tag (well, at least I guess it would go this way) ? My first tries (fueled by my lack of knowledge) where things like $results[] = "{$row['title']}<br /> <a href="{$row['link']}">Download</a> <br /> "; but I keep getting lots of errors, and then I don't know much about arrays and stuff (except basic notions); So there it is. I am really stuck and can't seem to find any workaround for this. Any suggestions? (examples, documentation, anything would do, really) Thanks, Radu Friends, I want to extract the Search Keyword from the URL, a visitor came from. I am using a PHP CMS and want to show the Keyword on my Blog. So if they search "abcd" from google, i want to extract "abcd" and echo on my blog. Here is the coding i could got hold of, but its not working, not echoing anything <?php function pk_stt2_function_get_delimiter($ref) { $search_engines = array('google.com' => 'q', 'go.google.com' => 'q', 'images.google.com' => 'q', 'video.google.com' => 'q', 'news.google.com' => 'q', 'blogsearch.google.com' => 'q', 'maps.google.com' => 'q', 'local.google.com' => 'q', 'search.yahoo.com' => 'p', 'search.msn.com' => 'q', 'bing.com' => 'q', 'msxml.excite.com' => 'qkw', 'search.lycos.com' => 'query', 'alltheweb.com' => 'q', 'search.aol.com' => 'query', 'search.iwon.com' => 'searchfor', 'ask.com' => 'q', 'ask.co.uk' => 'ask', 'search.cometsystems.com' => 'qry', 'hotbot.com' => 'query', 'overture.com' => 'Keywords', 'metacrawler.com' => 'qkw', 'search.netscape.com' => 'query', 'looksmart.com' => 'key', 'dpxml.webcrawler.com' => 'qkw', 'search.earthlink.net' => 'q', 'search.viewpoint.com' => 'k', 'mamma.com' => 'query'); $delim = false; if (isset($search_engines[$ref])) { $delim = $search_engines[$ref]; } else { if (strpos('ref:'.$ref,'google')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.atomz.')) $delim = "sp-q"; elseif (strpos('ref:'.$ref,'search.msn.')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.yahoo.')) $delim = "p"; elseif (preg_match('/home\.bellsouth\.net\/s\/s\.dll/i', $ref)) $delim = "bellsouth"; } return $delim; } /** * retrieve the search terms from search engine query * */ function pk_stt2_function_get_terms($d) { $terms = null; $query_array = array(); $query_terms = null; $query = explode($d.'=', $_SERVER['HTTP_REFERER']); $query = explode('&', $query[1]); $query = urldecode($query[0]); $query = str_replace("'", '', $query); $query = str_replace('"', '', $query); $query_array = preg_split('/[\s,\+\.]+/',$query); $query_terms = implode(' ', $query_array); $terms = htmlspecialchars(urldecode(trim($query_terms))); return $terms; } /** * get the referer * */ function pk_stt2_function_get_referer() { if (!isset($_SERVER['HTTP_REFERER']) || ($_SERVER['HTTP_REFERER'] == '')) return false; $referer_info = parse_url($_SERVER['HTTP_REFERER']); $referer = $referer_info['host']; if(substr($referer, 0, 4) == 'www.') $referer = substr($referer, 4); return $referer; } $referer = pk_stt2_function_get_referer(); if (!$referer) return false; $delimiter = pk_stt2_function_get_delimiter($referer); if( $delimiter ){ $term = pk_stt2_function_get_terms($delimiter); } echo $term; ?> May someone help? Natasha T Hi all How do I modify the below code to search multiple tables in mySQL database? $query = "select * from store_items where description like \"%$trimmed%\" or title like \"%$trimmed%\" or dimensions like \"%$trimmed%\" order by id ASC"; $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); It is for a search function and I need it to search another table called 'about_text' and 'faq_text' Thanks Pete I am developing a intranet forum in Php and MySQL and I am using ajax to display searched results on the same page but right now I am using query LIKE text% to search in database which is slower. but I want to make it fast search engin which can parse *,+ and show result. Since I am using ajax i am not able to use free search engin,so if possible pls provide a complete solution I have code to search a database of members, I can search by lastname but having a little problem. I want to be able to search by lastname starting with the first letter. (ie: a or b or c or d and so on). As it is right now I can only search by first letter of last name if I add % to the search (ie: a% b% c%) will give me all members with the last names starting with the approiate letter designation. I'm not sure how to handle this, any help would be appreciated. Thanks. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <center><table cellspacing="10" cellpadding="10" width="750" border="0"> <h4>Search</h4> <form name="search" method="post" action="<?php $PHP_SELF?>"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="lname">Last Name</option> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <?php // check to see if anything is posted if (isset($_POST['find'])) {$find = $_POST['find'];} if (isset($_POST['searching'])) {$searching = $_POST['searching'];} if (isset($_POST['field'])) {$field = $_POST['field'];} //This is only displayed if they have submitted the form if (isset($searching) && $searching=="yes") { echo "<h4>Results</h4><p>"; // If they did not enter a search term we give them an error if (empty($find)) { echo "<p>You forgot to enter a search term"; exit; } // Otherwise we connect to our Database mysql_connect("localhost", "root", "1910") or die(mysql_error()); mysql_select_db("cmc_member") or die(mysql_error()); // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); // Now we search for our search term, in the field the user specified $results = mysql_query("SELECT * FROM members WHERE upper($field) LIKE'$find'"); // And we display the results if($results && mysql_num_rows($results) > 0) { $i = 0; $max_columns = 3; while($row = mysql_fetch_array($results)) { // make the variables easy to deal with extract($row); // open row if counter is zero if($i == 0) echo "<tr>"; // make sure we have a valid product ALIGN='CENTER' if($fname != "" && $fname != null) echo "<td ALIGN='CENTER'><FONT COLOR='red'><b>$fname $lname</b></FONT><br> $address <br> $city $state $zip <br>$phone<br><a href=\"mailto: $email\">$email</a><br></td>"; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo "</tr>"; $i=0; } // end if } // end while } // end if results // clean up table - makes your code valid! if($i < $max_columns) { for($j=$i; $j<$max_columns;$j++) echo "<td> </td>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches = mysql_num_rows($results); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </tr> </table></center> </body> </html> Hello, I'm developing a website that asks the user to submit a keyword for a search. The results should display matches for this keyword, but also show matches for related keywords (in order of relevenace!). I'm planning on building up a library of which search terms users use in the same sessions (e.g. if someone searches for "it jobs" and "php jobs", I'll know the terms are correlated), and I'll also measure the click-through rates of the items on the results list. I've been spending all weekend trying to map out the design for this but it's proving incredibly complicated and I think the solution is likely to be on the internet somewhere already?! Please could someone point me in the right direction if you've come accross this problem before? Thanks a million, Stu Hello All, I have 2 queries that I want to join together to make one row
Dear All, I wish to have 2 drop down boxes, Country Select Box and Locality Select Box. The locality select box will be affected by the value chosen in the country select box. All is working fine except that the locality select box is not being populated. I know that the problem is in the sql statement WHERE country_id='$co' because i am having an error that $co is an undefined variable. All the rest works fine because i have replaced the $co variable directly with a number (say 98) for a particular country id and it worked fine. In what way can i define this variable $co so that it is accepted by my sql statement? Thank you for your help in advance. MySQL Tables indicated below: CREATE TABLE countries( country_id INT(3) UNSIGNED NOT NULL AUTO_INCREMENT, country_name VARCHAR(30) NOT NULL, PRIMARY KEY(country_id), UNIQUE KEY(country_name), INDEX(country_id), INDEX(country_name)) ENGINE=MyISAM; CREATE TABLE localities( locality_id INT(10) UNSIGNED NOT NULL AUTO_INCREMENT, country_id INT(3) UNSIGNED NOT NULL, locality_name VARCHAR(50), PRIMARY KEY (locality_id), INDEX (country_id), INDEX (locality_name)) ENGINE=MyISAM; Extract PHP script included below: // connect to database require_once(MYSQL); if(isset($_POST['submitted'])) { // trim the incoming data /* this line runs every element in $_POST through the trim() function, and assigns the returned result to the new $trimmed array */ $trimmed=array_map('trim',$_POST); // clean the data $co=mysqli_real_escape_string($dbc,$trimmed['country']); $lc=mysqli_real_escape_string($dbc,$trimmed['locality']); } ?> <form action="form.php" method="post"> <p>Country <select name="country"> <option>Select Country</option> <?php $q="SELECT country_id, country_name FROM countries"; $r=mysqli_query($dbc,$q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); while($row=mysqli_fetch_array($r)) { $country_id=$row[0]; $country_name=$row[1]; echo '<option value="' . $country_id . '"'; if(isset($trimmed['country']) && ($trimmed['country']==$country_id)) echo 'selected="selected"'; echo '>' . $country_name . '</option>\n'; } ?> </select> </p> <p>Locality <select name="locality"> <option>Select Locality</option> <?php $ql="SELECT locality_id, country_id, locality_name FROM localities WHERE country_id='$co' ORDER BY locality_name"; $rl=mysqli_query($dbc,$ql) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); while($row=mysqli_fetch_array($rl)) { $locality_id=$row[0]; $country_id=$row[1]; $locality_name=$row[2]; echo '<option value="' . $locality_id . '"'; if(isset($trimmed['locality']) && ($trimmed['locality']==$locality_id)) echo 'selected="selected"'; echo '>' . $locality_name . '</option>\n'; } // close database connection mysqli_close($dbc); ?> </select> </p> <p><input type="submit" name="submit" value="Submit" /></p> <input type="hidden" name="submitted" value="TRUE" /> </form> I want to know how to display results from mysql database by filling in a form. but i have found a tutorial which shows typing in a text box which displays results. if i follow this tutorial will it help me to understand and create php coding to display results for my form? Need some help I have 2 tables in a database and I need to search the first table and use the results from that search, to search another table, can this be done? and if it can how would you recommend that I go about it? Thanks For Your Help Guys! hi. just started a website talkietaco.com and at the momment my code selects the first row and displays it. this is all well and good but when i add a new row to the table it gos to the bottom. I want to be able to select the last row and echo it out. Any ideas? would i need to add an id row or something? Heres the code and thank you in advance for any help people can offer. Code: [Select] <?php $con = mysql_connect("localhost","",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mainbase", $con); $result = mysql_query("SELECT * FROM matteroffact"); echo "<table border='0'> <tr> <th></th> </tr>"; $row = mysql_fetch_array($result) or die(mysql_error()); echo "<tr>"; echo "<td><strong>" . $row['question']. "</strong> ". $row['answer']; "</td>"; echo "<tr>"; echo "</table>"; ?> Hi, I'm trying to make a 3 page registration form. On the 3rd page I want it to echo back all the options they have selected. I can get the input type to work but having problems with the selects. First Page Code: [Select] <form action="choose.password.php" method="post"> eMail: <input type="text" name="eMail" /><br /> Forename: <input type="text" name="fname" /><br /> Surname: <input type="text" name="lname" /><br /> Date of Birth: <input type="text" name="dob" /><br /> Gender: <select name="gender"> <option value="male">Male</option> <option value="female">Female</option> </select> <br /> I am not a lawyer: <input type="checkbox" name="lawyer" value="lawyer"> <br /> <br /> <input type="submit" value="Next" /> </form> Second Page Code: [Select] <form action="confirm.details.php" method="post"> <p>email address: <?php echo $_POST["eMail"]; ?></p> <p>password: <input type="password" name="eMail" /></p> <p>Confirm Password: <input type="password" name="eMail" /></p> <p>Hint: <input type="text" name="hint" /></p> <p>My email is correct, I am happy to be sent occassional emails, and i am not a family lawyer. <input type="checkbox" name="lawyer" value="lawyer"></p> <input type="hidden" name="fname" value="<?php echo ($_POST["fname"]); ?>" /> <input type="hidden" name="eMail" value="<?php echo ($_POST["eMail"]); ?>" /> <input type="hidden" name="lname" value="<?php echo ($_POST["lname"]); ?>" /> <input type="hidden" name="dob" value="<?php echo ($_POST["dob"]); ?>" /> <select style="display:none;" name="gender" <?php echo ($_POST["gender"]); ?> /> <p><input type="submit" value="Next" /></p> Third page Code: [Select] <p>Please confirm your details are correct to register.</p> <p>Email Address: <?php echo $_POST["eMail"]; ?> <p>Forename: <?php echo $_POST["fname"]; ?></p> <p>Surname: <?php echo $_POST["lname"]; ?></p> <p>Date of Birth: <?php echo $_POST["dob"]; ?></p> <p>Gender: <?php echo $_POST["gender"]; ?></p> How can I make the select work and echo it back on the third page? Thanks |