PHP - Very, Very Simple Code Question
I'm messing around with unconventional coding practices, just to .... practice. The following code isn't being used for any amazing projects or anything, it's just me messing around with things getting practice. It's a simple code but it keeps telling me the constants are undefined. //defining the variables through an array $db['db_host'] = "localhost"; $db['db_user'] = "root"; $db['db_pass'] = ""; $db['db_name'] = "cms"; //fancy way of making them constants foreach($db as $key => $value) { define(strtoupper($key), $value); } $conn = mysqli_connect(DB_HOST, DB_USER, DB_PASS, DB_NAME); if($conn) { echo "We are connected"; } Simple, simple, very simple but can someone tell me why it's not creating the constants? All of them in $conn are coming back as undefined. Similar TutorialsHi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Hey! I have a drop down field for my "register" form, but this is clearly easy to edit, I just used tamperdata for firefox and yeah...pretty easy, is there any way that you could prevent tampering with the values when submitting this form!? hello all I'm VERY new to php and I just have a simple question how do I bold the output text of this string echo $row['name']."<BR>"; Hello there fellow programmers, I was just wondering if there was any difference between doing this: Code: [Select] echo "Say Something Here"; and this Code: [Select] echo "Say "; echo "Something "; echo "Here"; Thank you in advance. Notice: I am aware of the fact that they will output the same thing, my question is regarding resources. I've seen this, Code: [Select] <?php } ?> in a lot of scripts at the very end of the script. What does this piece of code do? Lets say I have: $var=5; What would an output look like to get me: 1<br> 2<br> 3<br> 4<br> 5<br> Im at a complete loss! Thanks! Hi. I have an ID in md5 format but in the database its not. I pass the md5 ID to a page and then I am trying to load the correct record via a look up in the database of that ID. Im wondering is this code possible? <?php $query = mysql_query("SELECT * FROM table WHERE ".md5(tableID)." = $ID"); ?> Thanks Hi, I'm working on a product page and I got it to list all the products in one column of a table, but when I add a second column it just duplicates the first column. What do I need to change? Code: [Select] <?php require_once("functions.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <style type="text/css"> td { border-top-style: solid; border-right-style: solid; border-bottom-style: solid; border-left-style: solid; border-top-color: #30C; border-right-color: #30C; border-bottom-color: #30C; border-left-color: #30C; } </style> </head> <body> <form action="" method="post" name="catalog"> <?php DatabaseConnection(); $query = "SELECT * FROM treats"; $result_set = mysql_query($query) or die(mysql_error()); $output = "<table>"; while ($row = mysql_fetch_array($result_set)) { $output .= (" <tr> <td width=\"400px\">" . $row['product_title']."<br /> ".$row['product_Description']."<br />" .$row['price'] . "<br /> Quantity: <input name=\"quantity\" type=\"text\" size=\"2\" /> </td> <td width=\"400px\">" . $row['product_title']."<br /> ".$row['product_Description']."<br />" .$row['price'] . "<br /> Quantity: <input name=\"quantity\" type=\"text\" size=\"2\" /> </td> </tr> "); } $output .= "</table>"; echo $output; ?> </form> </body> </html> Hi,
I am trying to convert a php function into perl and need to understand the following line in red :
function pagination($query, $per_page = 10,$page = 1, $url = '?'){ $query = "SELECT COUNT(*) as `num` FROM {$query}"; $row = mysql_fetch_array(mysql_query($query)); $total = $row['num']; $adjacents = "2"; $page = ($page == 0 ? 1 : $page); $start = ($page - 1) * $per_page; $prev = $page - 1; $next = $page + 1; $lastpage = ceil($total/$per_page); $lpm1 = $lastpage - 1; $pagination = ""; if($lastpage > 1) { ......................................... What will be the output of this line above in red. Thank you very much. Regards. Tonya Hi guys, this function below is for card validation, however anycard i enter i get the invalid card number, this is not connected to any gateways, this is just an Luhn card validation demonstration. can you tell me please why i get that? <?php if ($_POST['pay']) { $cardNo = addslashes(strip_tags($_POST['cardNo'])); function luhnCheck($cardNo) { $cardNo = str_replace(" ", "", trim($cardNo)); if(!is_numeric($cardNo) or strlen($cardNo)>19) return false; $skip = $newNum = $total = 0; for($i=0;$i<=(strlen($cardNo)-1);$i++) { if($skip ==0) { $tmpNum = ($cardNo[$i]*2); $total += (strlen($tmpNum)==2 ? (substr($tmpNum, 0, 1)+substr($tmpNum, 1)) : $tmpNum); $skip = 1; }else{ $total += $cardNo[$i]; $skip = 0; } } return (($total % 10) == 0); } /* Example Usage */ if(luhnCheck($_GET['cc'])) { echo("Valid Number."); }else{ echo("Invalid Number."); } } ?> <form name="confirm" method="post" action=""> <input type="text" name="cardNo"> <input type="submit" name="pay" value="Pay Now"> </form> I know it could be a issue with this line if(luhnCheck($_GET['cc'])) { but im wondering where should and how put this cc in my form? regards if someone can help me out with this, its quite simple but I can't seem to get it to work.. Basically, this is the code I have for now, the issue is if I have 0 product or items, I don't want the sorting option to show up on the page, from the code below, what line can I add tosay that if there is no products in a category, not to show the SORT feature. thanks in advance if anyone can help. {if isset($orderby) AND isset($orderway)} <!-- Sort products --> {if isset($smarty.get.id_category) && $smarty.get.id_category} {assign var='request' value=$link->getPaginationLink('category', $category, false, true)} {elseif isset($smarty.get.id_manufacturer) && $smarty.get.id_manufacturer} {assign var='request' value=$link->getPaginationLink('manufacturer', $manufacturer, false, true)} {elseif isset($smarty.get.id_supplier) && $smarty.get.id_supplier} {assign var='request' value=$link->getPaginationLink('supplier', $supplier, false, true)} {else} {assign var='request' value=$link->getPaginationLink(false, false, false, true)} {/if} <form id="productsSortForm" action="{$request|escape:'htmlall':'UTF-8'}"> <select id="selectPrductSort" onchange="document.location.href = $(this).val();"> <option value="{$link->addSortDetails($request, $orderbydefault, $orderwaydefault)|escape:'htmlall':'UTF-8'}" {if $orderby eq $orderbydefault}selected="selected"{/if}>{l s='--'}</option> {if !$PS_CATALOG_MODE} <option value="{$link->addSortDetails($request, 'price', 'asc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'price' AND $orderway eq 'asc'}selected="selected"{/if}>{l s='Price: lowest first'}</option> <option value="{$link->addSortDetails($request, 'price', 'desc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'price' AND $orderway eq 'desc'}selected="selected"{/if}>{l s='Price: highest first'}</option> {/if} <option value="{$link->addSortDetails($request, 'name', 'asc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'name' AND $orderway eq 'asc'}selected="selected"{/if}>{l s='Product Name: A to Z'}</option> <option value="{$link->addSortDetails($request, 'name', 'desc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'name' AND $orderway eq 'desc'}selected="selected"{/if}>{l s='Product Name: Z to A'}</option> {if !$PS_CATALOG_MODE} <option value="{$link->addSortDetails($request, 'quantity', 'desc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'quantity' AND $orderway eq 'desc'}selected="selected"{/if}>{l s='In-stock first'}</option> {/if} </select> <label for="selectPrductSort">{l s='Sort by'}</label> </form> <!-- /Sort products --> {/if} what does the # symbol do in php(e.x index.php?cat=1#privacy)? How can i use it? From what i 've seen you use it for changing a whole div without reloading the page like tabs.. Hello to everyone I would like to ask for this simple question.. Im trying to put if and else condition on my php code. However this condition is not working.. Code: [Select] if($file == #3#){ echo "No results found"; }else{ echo "results has been found"; } This variable $file is the result after i used an API.. If the API does not see any results they would return #3# as the result. This means they returned a transaction code of 3 which you can see here http://developer.textapp.net/WebService/TransactionCodes.aspx means that there was nothing to return. The condition does not function well even if i make 3 or #3# as part of the condition. Can you help me guys? thanks I can't figure out why im getting an error with this code. if ($notif = mysql_query("SELECT * FROM notifications_1 WHERE recieverid='". $_SESSION['id']."' ORDER BY read ASC, id DESC") or die (mysql_error())); { Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'read ASC, id DESC' at line 1 Hello everyone! I am a new user and I have a simple question. How do I set a password for a user to log in to my site with PHP? I have no MySQL database just a iOS code/host app. I know this isn’t secure but only me and my friends are on the site. Any help is appreciated. I'm teaching myself php and mysql -- and my coding is a little rough. But what i'm trying to do is display information from a mysql table in another table on a website. I can do this just fine simply displaying the table, but i want a little something different. I am only displaying one column of the table, instead of displaying it all in one column, i want to display the information in 5 columns. for example..... the table from mysql has names scott, john, james, mary, simon. with the code I have i can make it display like this: scott scott scott scott scott john john john john john james james james james james mary mary mary mary mary simon simon simon simon simon i want it to diplay like this: scott john james mary simon new names will continue down here is my code: <?php require ("connectigb.php"); $result = mysql_query ("SELECT pledgeName FROM pledgewall"); $fields_num = mysql_num_fields($result); echo "<center> <h1>TSA It Gets Better Pledge Wall</h1>"; echo "<table border='1' align='center' style='width:960px;'><tr>"; while($row = mysql_fetch_row($result)) { echo "<tr>"; // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row as $cell) if ($cell != "") { for ($j=0; $j<5; $j++) { echo "<td>$cell</td>"; } } echo "</tr>\n"; } mysql_free_result($result); echo "</table></center>"; ?> any ideas on what i can do here, i'm sure this is a simply fix. i just haven't come across it yet. thanks for the help in advance. Having an issue with this code, there are 3 parts and it is a simple guestbook type thing. But my problem is that it worked the first time I signed the guestbook but now its saying Unable to create the table. Error code 1050: Table 'visitors' already exists << I know it already exists but WHY is it trying to create it again? << Heres the code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Guest Book</title> </head> <body> <?php if (empty($_GET['first_name']) || empty($_GET['last_name'])) die("<p>You must enter your first and last name! Click your browser's Back button to return to the Guest Book form.</p>"); $DBConnect = @mysqli_connect("localhost", "***********", "***********") Or die("<p>Unable to connect to the database server.</p>" . "<p>Error code " . mysqli_connect_errno() . ": " . mysqli_connect_error()) . "</p>"; $DBName = "guestbook"; if (!@mysqli_select_db($DBConnect, $DBName)) { $SQLstring = "CREATE DATABASE $DBName"; $QueryResult = mysqli_query($DBConnect, $SQLstring) Or die("<p>Unable to execute the query.</p>" . "<p>Error code " . mysqli_errno($DBConnect) . ": " . mysqli_error($DBConnect)) . "</p>"; echo "<p>You are the first visitor!</p>"; mysqli_select_db($DBConnect, $DBName); } $TableName = "visitors"; $SQLstring = "SELECT * FROM $TableName"; if (!$QueryResult) { $SQLstring = "CREATE TABLE $TableName (countID SMALLINT NOT NULL AUTO_INCREMENT PRIMARY KEY, last_name VARCHAR(40), first_name VARCHAR(40))"; $QueryResult = mysqli_query($DBConnect, $SQLstring) Or die("<p>Unable to create the table.</p>" . "<p>Error code " . mysqli_errno($DBConnect) . ": " . mysqli_error($DBConnect)) . "</p>"; } $LastName = addslashes($_GET['last_name']); $FirstName = addslashes($_GET['first_name']); $SQLstring = "INSERT INTO $TableName VALUES(NULL, '$LastName', '$FirstName')"; $QueryResult = mysqli_query($DBConnect, $SQLstring) Or die("<p>Unable to execute the query.</p>" . "<p>Error code " . mysqli_errno($DBConnect) . ": " . mysqli_error($DBConnect)) . "</p>"; echo "<h1>Thank you for signing our guest book!</h1>"; mysqli_close($DBConnect); ?> </body> </html> Can someone please point my to the right direction. Getting frustrated and I am assuming it is something quite simple i am overlooking. Thanks in advance. my php array knowledge is still basic and i can't seem to get this code to yield an answer in the form i want. i would like to be able to get at $m and $b separately so I can manipulate them. how, for example do i just print $m? Code: [Select] <?php var_dump( linear_regression(array(1, 2, 3, 4), array(1.5, 1.6, 2.1, 3.0)) ); /** * linear regression function * @param $x array x-coords * @param $y array y-coords * @returns array() m=>slope, b=>intercept */ function linear_regression($x, $y) { // calculate number points $n = count($x); // ensure both arrays of points are the same size if ($n != count($y)) { trigger_error("linear_regression(): Number of elements in coordinate arrays do not match.", E_USER_ERROR); } // calculate sums $x_sum = array_sum($x); $y_sum = array_sum($y); $xx_sum = 0; $xy_sum = 0; for($i = 0; $i < $n; $i++) { $xy_sum+=($x[$i]*$y[$i]); $xx_sum+=($x[$i]*$x[$i]); } // calculate slope $m = (($n * $xy_sum) - ($x_sum * $y_sum)) / (($n * $xx_sum) - ($x_sum * $x_sum)); // calculate intercept $b = ($y_sum - ($m * $x_sum)) / $n; return array("m"=>$m, "b"=>$b); } ?> Hello. I have a newbie question regarding arrays: How can I echo an element's subsequent arrays and elements? For example Code: [Select] $pers = array("Steve" => array("eyes" => "green", "age" => "43", "race" => "caucasian")); and if I echo $pers["Steve"] to make it display: green 43 caucasian. Thanks. Hi, I just wanted to know how posting works?. i know how to sort of post and get info.. What i want to know is: is it possible to post something from a folder structure like so: http://wwww.xxx.com/postfolder1/postfolder2/postfolder3/postfolder4/form.php // this is the file that posts.. lets say! a username. to http://www.xxx.com/notpostfolder1/notpostfolder2/notpostfolder3/notpostfolder4/index.php // the file that gets the post : The username.. or is a php database the only answer to transfer the information? i also just discovered that in cookies if i ad path/ the cookie is valid through out the site.. is ther something like this for Post and get?? |