PHP - Strange Date Format, Covert Help?

  Code: [Select]
$date =date("d F Y");
It will display 18 October 2011.
If I need it to display 2011-10-18. How do it go about coding it?

What Date Format is this...
Code: [Select]
echo '<div class="date">Published: ' . date('F j, Y', strtotime($publishedOn)) . '</div>';
And where can I find a listing of the different Date and Time Formats that will work with this?

(I would like to display my date as "2012-02-26  2:40pm" for what it is worth...)

Thanks,


Debbie

Anyone know what's up with this?


<?php
    $days = floor($posts['timestamp'] / (60 * 60 * 24));
    $remainder = $posts['timestamp'] % (60 * 60 * 24);
    $hours = floor($remainder / (60 * 60));
    $remainder = $remainder % (60 * 60);
    $minutes = floor($remainder / 60);
    $seconds = $remainder % 60;
           
    if($days > 0) {
    echo date("d/m/y", $posts['timestamp']);
    echo " at ";
    echo date("H:i", $posts['timestamp']);
    }elseif($days == 0 && $hours == 0 && $minutes == 0) {
    echo "few seconds ago";
    }elseif($days == 0 && $hours == 0) {
    echo $minutes.' minutes ago';
    }elseif($days == 0 && $hours > 0){
    echo $hours.' hour ago';
    }else{
    echo "few seconds ago";
    }
    ?>

Hi Guys,

I'm sure i have done this before, is there a way to shorten dates like:

December 16, 2010 to Dec 16, 2010    

and

January 16, 2010 to Jan 16, 2010

etc, i have used $dateFormatted2 = date("F j, Y", strtotime($d2)); to get the date format i have now.

any help would be appreciated

thansk guys

Graham

I can't seem to get the syntax correct

I want my date outputted as January 1st.

Code: [Select]
<span class="goal_head f_right mrm"><?php echo date($goal['complete_date'], 'F j'); ?></span>

I have a date field in the database table of this format 2012-02-08.
Now I want to select fields from the database where date >= $currentdate.
Do I have to do someting like
$currentdate=time();
//Then convert it into YYYY-MM-DD format?

Hi Guys

Could somebody tell me how i would put a line break into the code below

i.e:
1.07 <br />
2010


<?php echo date('d.m.Y',strtotime($news['created_at']));?>


Thanks for your help

I'm trying to format a date to use in a mysql query and was wondering about the best way to do it.

the form returns: mm/dd/yyyy and I need to format it to yyyy-mm-dd, any help would be greatly appretitaed, thanks in advance!

Hi guys I have this date script below which displays like so: 16/09/2011.

Its fine but I now like it to display like this: 16 September 2011

Please I need help in twicking the code to do this Thanks!

<?php
//check to see if passing variable is set i.e. if true get day, month, year.
if(isset($_GET['day'])){
$day = $_GET['day'];
} else{
//Get today's date and put them in date, month, year
$day = date("d");
}
if(isset($_GET['month'])){
$month = $_GET['month'];
} else{
$month = date("m");
}
if(isset($_GET['year'])){
$year = $_GET['year'];
} else{
$year = date("Y");
}

echo $day."/".$month."/".$year;

?>

Hi,
I'm working on an application which interacts with an embedded device. Here I'm sending the time in EDT. The following code is used to send the time:
Code: [Select]
$time = date_format(date_create(null, timezone_open("EDT")), "s,i,H,d,m,Y,w");

Here 'm' is from 01 to 12. But at the receiving end the firmware expects the month to be in the range 0-11 (C-style).

Yes I can explode the "$time" and subtract 1 from month. But is there any better way to do that..?

Thanks,

Girish

Hi i've been trying to change the format of the date which comes from the database row [ news-date ]
this what i tried but di not work help please

$query = "SELECT * FROM news, date_format [news_date](date,'%M %d, %Y') AS news_date
 "; 
$result = mysql_query($query); 

// see if any rows were returned 
if (mysql_num_rows($result) > 0) { 
 // yes so print them one after another 
  echo "<table cellpadding=10 border=1>"; 

  while($row = mysql_fetch_array($result))  {
  
   
  

     echo "<tr>"; 
     echo "<td>".$row["news_id"]."</td>"; 
     echo "<td>".$row["subject"]."</td>"; 
     echo "<td>" .$row['news_date']. "</td>";
 
     echo "<td>".$row["news_artical"]."</td>";
 echo "<td><a href=delete2.php?id=".$row["id"].">Delete</a></td>"; 
 echo "<td><a href=modifyform.php?id=".$row["id"].">Modify</a></td>";
 echo "<td><a href=add.php?id=".$row["id"].">Add Row</a></td>";
     echo "</tr>"; 
   } //End While
   echo "</table>"; 
} //End if rows 

   echo "<p> <strong>{news.SUBJECT} </strong></p>"; 



?> 

I'm trying to make $time be a variable with the current time and I want it to have the same format as mysql.  I can't figure out what I am doing wrong here

Wrror: Warning: date_format() expects parameter 1 to be DateTime, integer given

Code: [Select]
$time = date_format(time(),'Y-m-d H:i:s');

when trying to get the date

var visitors_time = new Date();

i'll being back a result like

Mon Oct 27 2014 20:54:55 GMT+0000 (GMT Standard Time)

my issue is, is there a way of getting the end part with the brackets to not show up? ie. format the date?...ive googled but doesnt seem no simple solution like php to actually format the date to the way you'd like it   thank you guys

i need a javascript date picker that will put a date in a text flied in the format of Y-m-d so that it can be posted to mysql also i need some kind of php to validite this

Hey, I am grabbing a date from a row in my table which is currently formatted as:
date("Y-m-d")
2010-09-29

So in my code I have something like this:

$row['date'];

How do I use this to rearrange the date to look like:

09-29-2010

I looked at the formatting tutorials, but they explain how to format it for the date you are currently setting into a variable.