PHP - Inserting Csv Records Into A Mysql Table
I'm sorry to be back so soon, but I'm up against another mystery. I'm using the code below to enter a bunch of css data from a spreadsheet into a mysql table. I think the data file is OK. The array created by the script checks out with print_r. (There are many more records than shown. I truncated it to save space.) The problem is that I get this error regarding my sql statement, not the data or anything else: Fatal error: Uncaught PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'check, name, phone, email, entry_fee, print_fee, image_name, description, med...' at line 1 in /Users/studio/Sites/BannerProject/b-as/_test_site/csv_to_array.php:242 Stack trace: #0 /Users/studio/Sites/BannerProject/b-as/_test_site/csv_to_array.php(242): PDO->prepare('INSERT INTO tbl...') #1 {main} thrown in /Users/studio/Sites/BannerProject/b-as/_test_site/csv_to_array.php on line 242 I've typed it in a dozen times to make sure there are no errors and keep getting the same error. I tried running a test file and gradually increasing the number of placeholders and at some point I always end up getting the same error, I can delete the most recent addition and it works again. Then I can add another placeholder exactly as before and it works the second time. It feels like a ghost in the machine. Any idea what I am doing wrong? An I typing something I don't see? <?php require '__classes/Db.php'; $csvData = '1,FALSE,Carol Lettko,,,TRUE,FALSE,Carol_Lettko-DSC_3022.jpg,Baby Herons/Brickyard,photo,,, ,,,925-285-0320,cjl164@aol.com,,,Carol_Lettko-DSC_0164.JPG,Heron/Brickyard,photo,,, ,,,,,,,Carol_Lettko-IMG_5723.jpg,Kayaker/Brickyard,photo,,, ,,,,,,,,,,,, 2,FALSE,Louise Williams,,,TRUE,FALSE,Louise_Williams-BirdsOfAFeatherAOPR.jpg,Alligator with Words,Book Excerpt,,, ,,,510-232-9547,lkw@louisekwilliams.com,,,Louise_Williams-Hope-TheFairyChickenAOPR.jpg,Hope The Fairy Chicken,,,, ,,,The d exatrfrfvct/.*tygrvurr,,,,,,,,, ,,,,,,,,,,,, 3,TRUE,Dorothy Leeland,,lelanddorothy@gmail.com,TRUE,FALSE,DJ_Lee-bridge at dusk 700px width.jpg,Bridge,photo,,, ,,,,,,,DJ_Lee-friends 700px width.jpg,Friends,photo,,, ,,,,,,,DJ_Lee-hybiscus 700 px wide.jpg,Hibiscus,photo,,, ,,,,,,,,,,,, 4,FALSE,Rita Gardner,,,TRUE,FALSE,Rita_Gardner-Explosion - Gardner photo.JPG,Explosion,photo,,, ,,,,tropicrita@msn.com,,,Rita_Gardner-Ferry Point tables and chair - Gardner.JPG,Ferry Point Tables,photo,, , ,,,,,,,Rita_Gardner-Forks - Gardner photo.JPG,Forks,photo,,, ,,,,,,,,,,,, '; $lines = explode(PHP_EOL, $csvData); $array1 = array(); foreach ($lines as $line) { $array1[] = str_getcsv($line); } $stmt = $pdo->prepare("INSERT INTO tbl_person_data (number, check, name, phone, email, entry_fee, print_fee, image_name, description, medium, select, orient, site) VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?)"); foreach ($array1 as $row) { $stmt->execute('$row'); } echo '<pre>'; print_r($array1); echo '</pre>'; ?>
Similar TutorialsHi I'm using this code to insert multiple records. The code executes but nothing is entered into my database. This usually happens when there's a mismatch in data types.
How do I ensure that description goes in as text which in sql is wrapped in single quotes, but also make sure the other variables go in as numeric.
// an array items to insert $array = array( 'theid' => $theid, 'descr' => $descr, 'costperunit' => $costperunit, 'quantity' => $quantity, 'costperlot' => $costperlot ); // begin the sql statement $sql1 = "INSERT INTO descriptions (jobid, description, costperunit, quantity, costperlot) VALUES "; $it = new ArrayIterator( $array ); // a new caching iterator gives us access to hasNext() $cit = new CachingIterator( $it ); // loop over the array foreach ( $cit as $value ) { // add to query $sql1 .= "('".$cit->key()."','" .$cit->current()."')"; if( $cit->hasNext() ) { $sql1 .= ","; } } I want to pull some records plus unique key from one mysql table and then use them as questions in a form/questionnaire. The post form will have six radio buttons to the right of the fields pulled with the key posted but hidden and will wirte to another table. I guess this is a templating question- as I've successfully retrieved the table 1 records via a query - I just can't seem to use them in the form. Below is the code I'm using to view table "PCM1" <?php // query.php require_once 'login.php'; $db_server = mysql_connect($db_hostname, $db_username, $db_password); if (!$db_server) die("Unable to connect to MySQL: " . mysql_error()); mysql_select_db($db_database) or die("Unable to select database: " . mysql_error()); $query = "SELECT * FROM pcm1"; $result = mysql_query($query); if (!$result) die ("Database access failed: " . mysql_error()); $rows = mysql_num_rows($result); for ($j = 0 ; $j < $rows ; ++$j) { echo 'RID: ' . mysql_result($result,$j,'mcde') ; echo 'Statement: ' . mysql_result($result,$j,'oppclub') . '<br />'; ; } How do you do this? Thanks in advance. Hello, me again. I have created a little forum - very very basic. main_forum.php : Code: [Select] <?php $host="localhost"; // Host name $username="yvonnedp"; // Mysql username $password="yvonne"; // Mysql password $db_name="forum"; // Database name $tbl_name="forum_question"; // Table name // Connect to server and select databse. mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name ORDER BY id"; // OREDER BY id DESC is order result by descending $result=mysql_query($sql); ?> <table width="90%" border="0" align="center" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td width="6%" align="center" bgcolor="#E6E6E6"><strong>#</strong></td> <td width="53%" align="center" bgcolor="#E6E6E6"><strong>Topic</strong></td> <td width="15%" align="center" bgcolor="#E6E6E6"><strong>Views</strong></td> <td width="13%" align="center" bgcolor="#E6E6E6"><strong>Replies</strong></td> <td width="13%" align="center" bgcolor="#E6E6E6"><strong>Date/Time</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ // Start looping table row ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><a href="view_topic.php?id=<? echo $rows['id']; ?>"><? echo $rows['topic']; ?></a><BR></td> <td align="center" bgcolor="#FFFFFF"><? echo $rows['view']; ?></td> <td align="center" bgcolor="#FFFFFF"><? echo $rows['reply']; ?></td> <td align="center" bgcolor="#FFFFFF"><? echo $rows['datetime']; ?></td> </tr> <?php // Exit looping and close connection } mysql_close(); ?> create_topic.php : Code: [Select] <table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form id="form1" name="form1" method="post" action="add_topic.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3" bgcolor="#E6E6E6"><strong>Create New Topic</strong> </td> </tr> <tr> <td width="14%"><strong>Topic</strong></td> <td width="2%">:</td> <td width="84%"><input name="topic" type="text" id="topic" size="50" /></td> </tr> <tr> <td valign="top"><strong>Detail</strong></td> <td valign="top">:</td> <td><textarea name="detail" cols="50" rows="3" id="detail"></textarea></td> </tr> <tr> <td><strong>Name</strong></td> <td>:</td> <td><input name="name" type="text" id="name" size="50" /></td> </tr> <tr> <td> </td> <td> </td> <td><input type="submit" name="Submit" value="Submit" /> <input type="reset" name="Submit2" value="Reset" /></td> </tr> </table> </td> </form> </tr> </table> add_topic.php : Code: [Select] <?php $host="localhost"; // Host name $username="yvonnedp"; // Mysql username $password="yvonne"; // Mysql password $db_name="forum"; // Database name $tbl_name="forum_question"; // Table name // Connect to server and select database. mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get data that sent from form $topic=$_POST['topic']; $detail=$_POST['detail']; $name=$_POST['name']; $datetime=date("d/m/y h:i:s"); //create date time $sql="INSERT INTO $tbl_name(topic, detail, name, datetime)VALUES('$topic', '$detail', '$name', '$datetime')"; $result=mysql_query($sql); if($result){ echo "Successful<BR>"; echo "<a href=main_forum.php>View your topic</a>"; $email_from = "forums@thenewme.co.za"; $email_to = "info@thenewme.co.za"; $email_subject = "The New Me - New Forum Topic"; $email_message = "A new topic has been posted on the Forum!\n"; $email_message .= "Check it out : http://www.thenewme.co.za/forum/main_forum.php"; $headers = 'From: '.$email_from."\r\n"; 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); } else { echo "ERROR"; } mysql_close(); ?> add_answer.php : Code: [Select] <?php $host="localhost"; // Host name $username="yvonnedp"; // Mysql username $password="yvonne"; // Mysql password $db_name="forum"; // Database name $tbl_name="forum_answer"; // Table name // Connect to server and select databse. mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Get value of id that sent from hidden field $id=$_POST['id']; // Find highest answer number. $sql="SELECT MAX(a_id) AS Maxa_id FROM $tbl_name WHERE question_id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); // add + 1 to highest answer number and keep it in variable name "$Max_id". if there no answer yet set it = 1 if ($rows) { $Max_id = $rows['Maxa_id']+1; } else { $Max_id = 1; } // get values that sent from form $a_name=$_POST['a_name']; $a_answer=$_POST['a_answer']; $datetime=date("d/m/y H:i:s"); // create date and time // Insert answer $sql2="INSERT INTO $tbl_name(question_id, a_id, a_name, a_answer, a_datetime)VALUES('$id', '$Max_id', '$a_name', '$a_answer', '$datetime')"; $result2=mysql_query($sql2); if($result2){ echo "Successful<BR>"; echo "<a href='view_topic.php?id=".$id."'>View your answer</a>"; // If added new answer, add value +1 in reply column $tbl_name2="forum_question"; $sql3="UPDATE $tbl_name2 SET reply='$Max_id' WHERE id='$id'"; $result3=mysql_query($sql3); $email_from = "forums@thenewme.co.za"; $email_to = "info@thenewme.co.za"; $email_subject = "The New Me - New Forum Answer"; $email_message = "A new answer to a forum topic has been posted on the Forum!\n"; $email_message .= "Check it out : http://www.thenewme.co.za/forum/main_forum.php"; $headers = 'From: '.$email_from."\r\n"; 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); } else { echo "ERROR"; } mysql_close(); ?> view_topic : Code: [Select] <?php $tbl_name2="forum_answer"; // Switch to table "forum_answer" $sql2="SELECT * FROM $tbl_name2 WHERE question_id='$id'"; $result2=mysql_query($sql2); while($rows=mysql_fetch_array($result2)){ ?> <table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td><table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td bgcolor="#F8F7F1"><strong>ID</strong></td> <td bgcolor="#F8F7F1">:</td> <td bgcolor="#F8F7F1"><? echo $rows['a_id']; ?></td> </tr> <tr> <td width="18%" bgcolor="#F8F7F1"><strong>Name</strong></td> <td width="5%" bgcolor="#F8F7F1">:</td> <td width="77%" bgcolor="#F8F7F1"><? echo $rows['a_name']; ?></td> </tr> <tr> <td bgcolor="#F8F7F1"><strong>Answer</strong></td> <td bgcolor="#F8F7F1">:</td> <td bgcolor="#F8F7F1"><? echo $rows['a_answer']; ?></td> </tr> <tr> <td bgcolor="#F8F7F1"><strong>Date/Time</strong></td> <td bgcolor="#F8F7F1">:</td> <td bgcolor="#F8F7F1"><? echo $rows['a_datetime']; ?></td> </tr> </table></td> </tr> </table><br> <? } $sql3="SELECT view FROM $tbl_name WHERE id='$id'"; $result3=mysql_query($sql3); $rows=mysql_fetch_array($result3); $view=$rows['view']; // if have no counter value set counter = 1 if(empty($view)){ $view=1; $sql4="INSERT INTO $tbl_name(view) VALUES('$view') WHERE id='$id'"; $result4=mysql_query($sql4); } // count more value $addview=$view+1; $sql5="update $tbl_name set view='$addview' WHERE id='$id'"; $result5=mysql_query($sql5); mysql_close(); ?> the problem is. With add_answer, I am not able to insert an answer. This has worked for the very first question, but all subsequent questions, I am unable to add answers. It keeps telling me ERROR. This is where the live forum is : http://www.thenewme.co.za/forum/main_forum.php Can it be an issue with the field that gets autmatically incremented? i have echo'd the data which get entered in when someone types in an answer, and everything is perfect! Can anyone help me? Hi, I need to compare records in a table based on the 'datetime' field, like if the difference between time is less than 15min. need to combine the records(rows) as a single resultant row until the time difference between them is less than 15min and when a record's time difference is >15min that should return as another row and so on. Please find following sample table and the required output format Sample Table: Code: [Select] ID NAME DATETIME 1 aaa 2011-10-10 06:30:00 2 bbb 2011-10-10 06:33:00 3 ccc 2011-10-10 06:38:00 4 ddd 2011-10-10 06:40:00 5 eee 2011-10-10 07:10:00 6 ffff 2011-10-10 07:14:00 7 sss 2011-10-10 08:16:00 8 jjj 2011-10-10 08:26:00 9 kkk 2011-10-10 08:28:00 10 mm 2011-10-10 09:46:00 11 ppp 2011-10-10 09:49:00 12 qqq 2011-10-10 09:52:00 Output Needed : Code: [Select] IDs START DATETIME END DATETIME 1,2,3,4 2011-10-10 06:30:00 2011-10-10 06:40:00 5,6 2011-10-10 07:10:00 2011-10-10 07:14:00 7,8,9 2011-10-10 08:16:00 2011-10-10 08:28:00 10,11,12 2011-10-10 09:46:00 2011-10-10 09:52:00 You can see 1st row in the output table having IDs 1,2,3,4 coz the time difference between them is less than 15minutes (it doesn't means time difference between start and end; it is actually the time difference between current record and previous one ; ie; ID-1 and ID-2 have difference less than 15min and ID-2 & ID-3 have difference less than 15min and ID-3 & ID-4 have difference less than 15min, so those 4 records combine together as a single row also shows their start time and end time. Then you can see diff between ID-4 and ID-5 is greater than 15 min so it should display as new row, and so on) How can I acheive above Output with mysql query ?? Please help.. Hello there! I've been banging my head on this for a while and I just can't seem to get it to work properly. I have a dropdown menu which selects information from table1 using a select statement (this table is called 'lid'). It selects the firstname, lastname and member id from this table and shows it in the dropdown menu. I'm glad I got that part working but the hard thing is inserting the data that the user selects into another table. So when you select the id member from this dropdown menu it only inserts a blank row into table2 (which is called 'teamlid'). Can you guys help me? How can I insert the id member into my table2? What am I doing wrong here? Thanks a million! This is my first post so if I'm doing anything wrong, let me know and I'll fix it asap! My code: <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Boast & Drive</title> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css"> <style type="text/css"> .wrapper{ width: 650px; margin: 0 auto; } .page-header h2{ margin-top: 0; } table tr td:last-child a{ margin-right: 15px; } </style> </head> <body> <div class="container-fluid"> <div class="row"> <div class="col-md-12"> <div class="page-header clearfix"> <h2 class="pull-left">Teamleden</h2> <div class="btn-toolbar"> <a href="read.php" class="btn btn-primary btn-lg pull-right">Terug</a> </div> </div> <?php mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); error_reporting(E_ALL); //Verbinding maken met de database require_once "login.php"; $sql = "SELECT tl.teamnaam, tl.tl_ID, tl.lidnummer, l.voornaam, l.achternaam FROM teamlid tl JOIN lid l ON tl.lidnummer = l.lidnummer ORDER BY tl.teamnaam;"; if($result = mysqli_query($conn, $sql)) { if(mysqli_num_rows($result) > 0) { echo "<table class='table table-bordered table-striped'>"; echo "<thead>"; echo "<tr>"; echo "<th>Teamnaam</th>"; echo "<th>Tl_ID</th>"; echo "<th>Lidnummer</th>"; echo "<th>Voornaam</th>"; echo "<th>Achternaam</th>"; echo "</tr>"; echo "</thead>"; echo "<tbody>"; while($row = mysqli_fetch_array($result)){ echo "<tr>"; echo "<td>" . $row['teamnaam'] . "</td>"; echo "<td>" . $row['tl_ID'] . "</td>"; echo "<td>" . $row['lidnummer'] . "</td>"; echo "<td>" . $row['voornaam'] . "</td>"; echo "<td>" . $row['achternaam'] . "</td>"; echo "<td>"; echo "<a href='update.php?id=". $row['lidnummer'] ."' title='Gegevens wijzigen' data- toggle='tooltip'><span class='glyphicon glyphicon-pencil'></span></a>"; echo "<a href='delete.php?id=". $row['lidnummer'] ."' title='Lid verwijderen' data- toggle='tooltip'><span class='glyphicon glyphicon-trash'></span></a>"; echo "</td>"; echo "</tr>"; } echo "</tbody>"; echo "</table>"; mysqli_free_result($result); } else{ echo "<p class='lead'><em>Er zijn geen gegevens om weer te geven.</em></p>"; } } else{ echo "De volgende fout is gevonden: " . mysqli_error($conn); } ?> <form name="dropdown" method="post"> <div class="page-header clearfix"> <h2 class="pull-left">Teamlid toevoegen</h2> </div> <p>Selecteer hieronder met behulp van het dropdown menu een lid welke je aan bovenstaand team wilt toevoegen</p> <div class="container-fluid"> <div class="row"> <?php // Variabelen aanmaken en tonen met lege waardes $teamnaam = $lidnummer = ''; // Code voor dropdown. Selecteert voornaam, achternaam en lidnummer van tabel lid) $sql = "SELECT voornaam, achternaam, lidnummer FROM lid ORDER BY achternaam"; $result = mysqli_query($conn, $sql); echo "<select id='teamLid' name='teamLid'>"; echo "<option>--Selecteer Lid--</option>"; while ($row = mysqli_fetch_array($result)) { echo "<option value='" . $row['lid'] . "'>" . $row['voornaam'] . " " . $row['achternaam'] . " " . $row['lidnummer'] . "</option>"; } echo "</select>"; if (isset($_POST["id"]) && !empty($_POST["id"])) { $id = $_POST["teamLid"]; $stmt = $conn->prepare("INSERT INTO teamlid (teamnaam, lidnummer) VALUES (?,?)"); $stmt->bind_param('si', $param_teamnaam, $param_lidnummer); $param_teamnaam = $teamnaam; $param_lidnummer = $lidnummer; $stmt->execute(); } // Verbinding sluiten mysqli_close($conn); ?> <div> <input type="hidden" name="id" value="<?php echo $id; ?>" /> <input type="submit" name="submit" class="btn btn-primary" value="Toevoegen"> </div> </div> </div> </form> </div> </div> </body> </html>
Hi. When a record is added its done via a form and processed via inserts.php. I need to use the same form but to recall the data (by id) so it can be editted. Cant work it out though. Help would be well appreciated! edit.php: <CENTER><B>Update a Vehicle</B></CENTER> <BR> <?php $query="SELECT * FROM cars"; $result=mysql_query($query); $i=0; while ($i < $num) { $carname=mysql_result($result,$i,"CarName"); $cartitle=mysql_result($result,$i,"CarTitle"); $carprice=mysql_result($result,$i,"CarPrice"); $carmiles=mysql_result($result,$i,"CarMiles"); $cardesc=mysql_result($result,$i,"CarDescription"); ?> <form action="showroomedit.php" method="post"> <CENTER>Vehicle Name:</CENTER> <CENTER><input type="text" name="CarName" value="<?php echo $carname; ?>"></CENTER> <br> <CENTER>Vehicle Type:</CENTER> <CENTER><input type="text" name="CarTitle" value="<?php echo $cartitle; ?>"></CENTER> <br> <CENTER>Vehicle Price:</CENTER> <CENTER><input type="text" name="CarPrice" value="<?php echo $carprice; ?>"></CENTER> <br> <CENTER>Vehicle Mileage:</CENTER> <CENTER><input type="text" name="CarMiles" value="<?php echo $carmiles; ?>"></CENTER> <br> <CENTER>Vehicle Description:</CENTER> <CENTER><textarea name="CarDescription" rows="10" cols="30" value="<?php echo $cardesc; ?>"></textarea></CENTER> <br> <CENTER><input type="Submit"></CENTER> </form> </TD> cant work out why it isnt working... I have a customer registration form up and running, the form allows customers to complete the forms and the data is then inserted into mysql db table via php form. I want to prevent duplicates records from already existing customers from creating a new records instead I want the customers to update their existing records in the backend. That is allow them to complete the form as normal, once they hit the submit button, the code should check if the customer first name and last name is already in the database if yes then it should update their records and if not it should insert new record to the table. I do not want to alert the customer that their records already exist. I do not know where to start. Please help Thank you so much in advance for your help. It's pretty simple to see what I am trying to do here. For some reason all results in the table are the same exact cityName replacing all existing records. The echoed results are correct. I've include a small dump of my table as well. $query = "SELECT cityName FROM sys_city_dev_2"; $resource = mysqli_query($cxn, $query) or die("MySQL error: " . mysqli_error($cxn) . "<hr>\nQuery: $query"); while($result = mysqli_fetch_assoc($resource)) { $nox = $result['cityName']; $toUpper = ucfirst($nox); echo "$toUpper" . "<br />"; $setString = "UPDATE sys_city_dev_2 SET cityName = '" . $toUpper ."' WHERE cityName != ''"; mysqli_query($cxn,$setString); } 100 Records of table dump (pre running my script above): -- -- Table structure for table `sys_city_dev_2_backup` -- CREATE TABLE IF NOT EXISTS `sys_city_dev_2_backup` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Mid` int(11) NOT NULL DEFAULT '0', `cityName` varchar(30) NOT NULL DEFAULT '', `forder` int(4) NOT NULL DEFAULT '0', `disdplay` int(4) NOT NULL DEFAULT '0', `cid` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=113970 ; -- -- Dumping data for table `sys_city_dev_2_backup` -- INSERT INTO `sys_city_dev_2_backup` (`ID`, `Mid`, `cityName`, `forder`, `disdplay`, `cid`) VALUES (84010, 1, 'dothan', 0, 0, 0), (84011, 1, 'alabaster', 0, 0, 0), (84012, 1, 'birmingham', 0, 0, 0), (84013, 2, 'flagstaff', 0, 0, 0), (84014, 1, 'auburn', 0, 0, 0), (84015, 1, 'florence', 0, 0, 0), (84016, 1, 'gadsden', 0, 0, 0), (84017, 1, 'huntsville', 0, 0, 0), (84018, 1, 'mobile', 0, 0, 0), (84019, 1, 'montgomery', 0, 0, 0), (84020, 1, 'tuscaloosa', 0, 0, 0), (84021, 2, 'mohave valley', 0, 0, 0), (84022, 2, 'phoenix', 0, 0, 0), (84023, 2, 'prescott', 0, 0, 0), (84024, 2, 'sierra vista', 0, 0, 0), (84025, 2, 'tucson', 0, 0, 0), (84026, 2, 'yuma', 0, 0, 0), (84027, 3, 'bakersfield', 0, 0, 0), (84028, 3, 'chico', 0, 0, 0), (84029, 3, 'fresno / madera', 0, 0, 0), (84030, 3, 'gold country', 0, 0, 0), (84031, 3, 'humboldt county', 0, 0, 0), (84032, 3, 'imperial', 0, 0, 0), (84033, 3, 'inland empire', 0, 0, 0), (84034, 3, 'los angeles', 0, 0, 0), (84035, 3, 'alhambra', 0, 0, 0), (84036, 3, 'merced', 0, 0, 0), (84037, 49, 'fayetteville', 0, 0, 0), (84038, 49, 'fort smith', 0, 0, 0), (84039, 49, 'jonesboro', 0, 0, 0), (84040, 49, 'little rock', 0, 0, 0), (84041, 49, 'arkadelphia', 0, 0, 0), (84042, 49, 'texarkana', 0, 0, 0), (84043, 3, 'modesto', 0, 0, 0), (84044, 3, 'alta sierra', 0, 0, 0), (84045, 3, 'alpine', 0, 0, 0), (84046, 3, 'pedley', 0, 0, 0), (84047, 3, 'redding', 0, 0, 0), (84048, 3, 'alondra park', 0, 0, 0), (84049, 3, 'sacramento', 0, 0, 0), (84050, 4, 'canon city', 0, 0, 0), (84051, 3, 'san luis obispo', 0, 0, 0), (84052, 3, 'santa barbara', 0, 0, 0), (84053, 3, 'stockton', 0, 0, 0), (84054, 3, 'aliso viejo', 0, 0, 0), (84055, 3, 'visalia', 0, 0, 0), (84056, 3, 'yuba city', 0, 0, 0), (84057, 4, 'boulder', 0, 0, 0), (84058, 4, 'colorado springs', 0, 0, 0), (84059, 4, 'denver', 0, 0, 0), (84060, 4, 'applewood', 0, 0, 0), (84061, 4, 'pueblo', 0, 0, 0), (84062, 4, 'air force academy', 0, 0, 0), (84063, 5, 'avon', 0, 0, 0), (84064, 5, 'hartford', 0, 0, 0), (84065, 5, 'new haven', 0, 0, 0), (84066, 5, 'ansonia', 0, 0, 0), (84067, 5, 'fairfield', 0, 0, 0), (84068, 7, 'daytona beach', 0, 0, 0), (84069, 7, 'sebastian', 0, 0, 0), (84070, 5, 'wallingford center', 0, 0, 0), (84071, 8, 'belvedere park', 0, 0, 0), (84072, 7, 'sarasota springs', 0, 0, 0), (84073, 7, 'sandalfoot cove', 0, 0, 0), (84074, 7, 'san carlos park', 0, 0, 0), (84075, 7, 'st. augustine', 0, 0, 0), (84076, 7, 'tallahassee', 0, 0, 0), (84077, 7, 'safety harbor', 0, 0, 0), (84078, 7, 'ruskin', 0, 0, 0), (84079, 8, 'athens-clarke county', 0, 0, 0), (84080, 8, 'atlanta', 0, 0, 0), (84081, 8, 'augusta-richmond county', 0, 0, 0), (84082, 8, 'brunswick', 0, 0, 0), (84083, 8, 'columbus', 0, 0, 0), (84084, 8, 'americus', 0, 0, 0), (84085, 8, 'acworth', 0, 0, 0), (84086, 8, 'valdosta', 0, 0, 0), (84087, 10, 'boise', 0, 0, 0), (84088, 10, 'ammon', 0, 0, 0), (84089, 10, 'moscow', 0, 0, 0), (84090, 10, 'blackfoot', 0, 0, 0), (84091, 10, 'twin falls', 0, 0, 0), (84092, 10, 'meridian', 0, 0, 0), (84093, 10, 'jerome', 0, 0, 0), (84094, 10, 'idaho falls', 0, 0, 0), (84095, 11, 'addison', 0, 0, 0), (84096, 10, 'garden city', 0, 0, 0), (84097, 10, 'eagle', 0, 0, 0), (84098, 10, 'chubbuck', 0, 0, 0), (84099, 10, 'caldwell', 0, 0, 0), (84100, 12, 'bloomington', 0, 0, 0), (84101, 12, 'evansville', 0, 0, 0), (84102, 12, 'fort wayne', 0, 0, 0), (84103, 12, 'indianapolis', 0, 0, 0), (84104, 12, 'muncie / anderson', 0, 0, 0), (84105, 12, 'lafayette / west lafayette', 0, 0, 0), (84106, 12, 'south bend / michiana', 0, 0, 0), (84107, 12, 'terre haute', 0, 0, 0), (84108, 12, 'northwest indiana', 0, 0, 0), (84109, 13, 'ames', 0, 0, 0); Hi everyone, I have the task of building a PHP page where users can enter or remove as many records as they like into different categories. This then makes the number of records entered unknown, and therefore it becomes more complicated. To make this clearer, I have attached an image of what I am trying to do. Two questions: - Before submitting the form, how can each record entry be matched with the correct category? (maybe hidden form fields somehow?) - What is the best way of inserting each record (and it's associated category) into a MySQL database table from a single form submit? I want to try and keep this as simple as possible as the data will later be updated, removed etc. I'm experiencing a brain fart and just cannot picture the best way of going about this Any help and advice is much appreciated! Thanks in advance. Code: [Select] Basic table schema example... CATEGORY TABLE ---------------------------- | catid | category | ---------------------------- | 1 | Category A | | 2 | Category B | etc. etc. ---------------------------- DATA ENTRY TABLE ---------------------------- dataid | catid | data | -------------------------------- | 1 | 2 | data xyz | | 2 | 1 | data zyx | etc. etc etc. -------------------------------- Hi guys, I am trying to UPDATE some records on a mySQL database but can't seem to find out why it is not working. This is my code. Code: [Select] <?php $latitude = $_POST['lat_location']; $longitude = $_POST['long_location']; $unique_ID = $_POST['unique_ID']; include('connect2.php'); $query = mysql_query("SELECT * FROM user_location WHERE unit = '$unique_ID'"); $numrows = mysql_num_rows($query); if ($numrows == 1) { $query2="UPDATE user_location SET lat = '$latitude', long = '$longitude' WHERE unit = '$unique_ID'"; mysql_query($query2); $test = "matches"; } else { mysql_query("INSERT INTO user_location VALUES ('','$unique_ID','$latitude','$longitude')"); $test = "not match"; } echo $test . "<br />"; echo $numrows; ?> The script receives the data via the POST method and assigns it to variables. Then I query the database for one of those variables and check how many results are found. If 0 results are found then a new record is created on the database, but if there is 1 record found then the record that is found has to be UPDATED. When the result is 0 the scripts creates the new record fine, but if the result is 1 it doesn't update. I just can't figure out why. Any help will be greatly appreciated. Thanks in advanced, Hello all, I am new to php coding and have a couple of problems with editing records in my database! I have two files below one test.php and edit.php. In the test.php the code outputs the records into a table. The problem is with the edit link as when it is selected I wish to be able to edit a record by a form, which is on edit.php. I am trying bring up the movie's information on the form to be edited. Currently on the form i get; Quote Movie: movie Gen Genre Year: year Any ideas how I can edit the record and then return to the test.php page? Code: [Select] test.php <html> <body style="background-color:#669999;"> <table width="490"border=0><tr> <td colspan="2" style="background-color:#FFA500;"> <div id="header" <h3 style="color:black">This is my first web-page! Below is a database of some of my favourite movies! </h3> </td> </tr> <?php //connecting to server $con = mysql_connect("localhost","root","NYOXAkly"); if (!$con) { die('could not connect: ' . mysql_error()); } //selecting movie database mysql_select_db("my_mov",$con); //Check if add button is active, start this if(isset($_REQUEST['add'])) { echo "<meta http-equiv=\"refresh\"content=\"0;URL=form.php\">"; } $result = mysql_query("SELECT * FROM Films ORDER BY filmID"); ?> <!-------------------------------creating table------------------------------------------------------------------------------------> <table width="490" border="0" cellspacing="1" cellpadding="0"> <tr> <td> <form name="test1" method="post" action="test.php"> <table width="490" border="10" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"><tr> <td bgcolor="#FFFFFF"></td> <td align="center" colspan="6" bgcolor="#FFFFFF">Movie Database</td></tr> <td align="center" bgcolor="#FFFFFF">filmID</td> <td align="center" bgcolor="#FFFFFF">Movie</td> <td align="center" bgcolor="#FFFFFF">Genre</td> <td align="center" bgcolor="#FFFFFF">Year</td> <td align="center" bgcolor="#FFFFFF">Edit</td> <td align="center" bgcolor="#FFFFFF">Delete</td> </tr> <?php while($rows=mysql_fetch_array($result)) { ?> <tr> </td> <td bgcolor="#FFFFFF"><? echo $rows['filmID']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['movie']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['genre']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['year']; ?></td> <td bgcolor="#FFFFFF"> <a href="edit.php?filmID=<?php echo 'filmID';?>">Edit</a> <td bgcolor="#FFFFFF"> <a href="delete.php?filmID=<?php echo 'filmID';?>">Delete</a> </td> </tr> <?php } echo print_r(error_get_last()); mysql_close(); ?> <!--add button--> <tr> <td colspan="15" align="left" bgcolor="#FFFFFF"> <input name='add' type="submit" filmID="add" value="Add A New Record" action="form.php?"> </td> </tr> </table> </form> <br/> By C.M.D.W <br/> <?php echo date("Y/m/d") . "<br />"; ?> </body> </html> Code: [Select] edit.php <html> <body style="background-color:#669999;"> <!------------------Creates a form ----------------------> <br /> <form action="" method="post"> <fieldset> <legend>Enter your movies into database here!</legend> Movie: <input type ="text" name="movie" value="<?php echo 'movie';?>"> <br /> Gen <input type ="text" name="genre" value="<?php echo 'genre';?>"/> <br /> Year: <input type ="text" name="year" value="<?php echo 'year';?>"/> <br /> <input type="submit" name="name" value="Submit" /> </fieldset> </form> <?php //connecting to server $con = mysql_connect("localhost","root","NYOXAkly"); if (!$con) { die('could not connect: ' . mysql_error()); } //selecting movie database mysql_select_db("my_mov",$con); if (isset($_POST['submit'])) { // confirm that the 'id' value is a valid integer if (is_numeric($_POST['filmID'])) // get form data $filmID = $_POST['filmID']; $movie = mysql_real_escape_string(htmlspecialchars($_POST['movie'])); $genre = mysql_real_escape_string(htmlspecialchars($_POST['genre'])); $year = mysql_real_escape_string(htmlspecialchars($_POST['year'])); // check that fields are filled in if ($movie == '' || $genre == '' || $year == '') { // generate error message $error = 'ERROR: Please fill in all required fields!'; } else { // save the data to the database } mysql_query("UPDATE players SET movie='$movie', genre='$genre', year='$year' WHERE filmID='$filmID'") or die(mysql_error()); // once saved, redirect back to the view page header("Location: test.php"); } } if (isset($_GET['filmID']) && is_numeric($_GET['filmID']) && $_GET['filmID'] > 0) { // query db $id = $_GET['filmID']; $result = mysql_query("SELECT * FROM Films WHERE filmID=$FilmID") or die(mysql_error()); $row = mysql_fetch_array($result); // check that the 'id' matches up with a row in the databse if($row) { // get data from db $movie = $row['movie']; $genre = $row['genre']; $year = $row['year']; }} ?> <br/> <br/> <a href="test.php">Return To Home Page</a> <br/> <br/> By C.M.D.W <br/> <?php echo date("Y/m/d") . "<br />"; ?> </body> </html> Thanks Chris Hello, This is driving me crazy, as I cannot get it working. I have a database that has a table called 'categories'. I need to retrieve all categories with category_id != '1,2,3'. For this, I can this query: Code: [Select] $q = "SELECT * FROM categories WHERE category_id NOT IN (1,2,3)"; The query executes fine. I need this categories retrieved, to be passed to a Smarty Template Engine powered page. I have: Code: [Select] $q = "SELECT * FROM categories WHERE category_id NOT IN (1,2,3)"; $res = mysql_query($q); while($row=mysql_fetch_array($res)) { Assign('categories',$row); } But when retrieving the array in the Smarty page, with a loop, I only see the last item of the array (the last category). If I go back to the while loop, and add a Code: [Select] print_r($row);, I see two arrays (I have two categories). But the question is: How can I work with those two categories, as I need to use them individually outside the while loop? Any help is appreciated. Best Regards, Richi Hi guys, I need your help. I am checking on a database as I want to see if the records have been updated or not. Code: [Select] <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbuser'); define('DB_PASSWORD', 'mydbpass'); define('DB_DATABASE', 'mydbtable'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $test = clean($_GET['test']); $public = clean($_GET['public']); if (isset($_GET['user']) && (isset($_GET['pass']))) { if($username == '' || $password == '') { $errmsg_arr[] = 'username or password are missing'; $errflag = true; } } elseif (isset($_GET['user']) || (isset($_GET['test'])) || (isset($_GET['public']))) { if($username == '' || $test == '' || $public == '') { $errmsg_arr[] = 'user or others are missing'; $errflag = true; } } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $qry="SELECT * FROM members WHERE username='$username' AND passwd='$password'"; $result=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error()); if ($username && $password) { if(mysql_num_rows($result) > 0) { $qrytable1="SELECT images, id, test, links, Public FROM user_channel_list WHERE username='$username'"; $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); while ($row = mysql_fetch_array($result1)) { echo "<p id='test'>"; echo $row['test'] . "</p>"; echo '<p id="images"> <a href="images.php?test=test&id='.$row['id'].'">Images</a></td> | <a href="http://' . $row["links"] . '">Link</a> </td> | <a href="delete.php?test=test&id='.$row['id'].'">Delete</a> </td> | <span id="test">'.$row['Public'].'</td>'; } } else { echo "user not found"; } } elseif($username && $test && $public) { $qry="SELECT * FROM members WHERE username='$username'"; $result1=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error()); if(mysql_num_rows($result1) > 0) { $qrytable1="SELECT Public FROM user_channel_list WHERE username='$username' && test='$test'"; $result2=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); if(mysql_num_rows($result2) > 0) { $row = mysql_fetch_row($result2); mysql_query("UPDATE user_list SET Public=('$_GET[public]') WHERE username='$username' AND test='$test'"); echo "update!"; } else { echo "already updated!"; } } else { echo "user not found"; } } } ?> When I run debug the code on my php, if i input the data in a url bar while the records are the same as the data that I enter in the url, i should get the print out on my php "already updated", but I keep getting "update!". Do you know how i can check on mysql database to see if the records have been updated or not?? I have a problem . I 've been trying for a long time to make an update for php mysql to change the data. but every time I do not manage to make it work with a form. but it works if I only if I put this ($ sql = "UPDATE users SET username = 'value' WHERE id = 10 " ; ) so it only works when I put the value of the id. but I want in an html form to indicate what I want to change and what id goes. but I have tried so long that I do not feel like I so want someone help me. make the same database and same as my records and make the code and test it if it works show me please my database name : web test my table called : users my records are called : id int ( 11) AUTO_INNCREMENT username , varchar ( 255 ) password , varchar ( 255 ) first_name , varchar ( 255 ) last_name , varchar ( 255 ) email, varchar ( 255 ) Age, int ( 11) Look, my update.php is like this now <?php $servername = "localhost"; $username = "root"; $password = "....."; $dbname = "webtest"; $conn = new mysqli($servername, $username, $password, $dbname); if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "UPDATE users SET password='cotton candy' WHERE id=10"; if ($conn->query($sql) === TRUE) { echo "Record updated successfully"; } else { echo "Error updating record: " . $conn->error; } $conn->close(); ?> but now i have still have to go into the php file to change the valeu or the id but i looked on site and youtube how to put it in a simple html form but it still does not work. i want it in a html from. I want that when I enter the ID that the data of the user appears and that I can change any valeu separately. Hi,I'm hoping someone can help me:). When I add foreign keys to the database in MySQL I CAN change the primary key field and the corresponding indexed field will automatically change giving me the same value which is exactly what i want. The issue is when I try to insert the values using my php code i get the 'cannot update child error'. I have not selected a value for the unique_id field as I want it to inherit the value from the primary key. Here's my code as simplified as I could do it. <?php //this calls the class productupload and instantiates the function insert_form to insert values into the db. $product = new productUpload(); $product->insert_form();?> //This calls the insert_form function and inserts info into tables <?php class productUpload extends DatabaseObject{ protected static $table_name="itm_details"; protected static $db_fields =array('id','unique_id','itm_cat','itm_make','itm_model','itm_desc','itm_cond','itm_date_from','itm_date_to','itm_add_date'); public $id; public $unique_id; public $itm_cat; public $itm_make; public $itm_model; public $itm_desc; public $itm_cond; public $itm_date_from; public $itm_date_to; public $itm_add_date; Heres the function insert_form which grabs the form submitted data. Note I have not defined a value for $unique_id public function insert_form(){ global $database; //set the object attributes to the form the parameters if(isset($_POST['submit'])) { $result = array( $this->itm_cat =(!empty($_POST['itm_cat'])) ? trim($_POST['itm_cat']) : NULL, $this->itm_make =(!empty($_POST['itm_make'])) ? trim($_POST['itm_make']) : NULL, $this->itm_model = (!empty($_POST['itm_model'])) ? trim($_POST['itm_model']) : NULL, $this->itm_desc =(!empty($_POST['itm_desc'])) ? trim($_POST['itm_desc']) : NULL, $this->itm_cond =(!empty($_POST['itm_cond'])) ? trim($_POST['itm_cond']) : NULL, $this->itm_date_from =(!empty($_POST['itm_date_from'])) ? trim($_POST['itm_date_from']) : NULL, $this->itm_date_to =(!empty($_POST['itm_date_to'])) ? trim($_POST['itm_date_to']) : NULL, $this->itm_add_date = date("Y-m-d H:m:s")); //check date is numeric //if(is_numeric($_POST['itm_date_from'])) { //$this->itm_date_from = $_POST['itm_date_from']; //} //check date is numeric //if(is_numeric($_POST['itm_date_to'])) { //$this->itm_date_to = $_POST['itm_date_to']; //} if($result){ $result = $this->create(); } } } //here's the create function referred to above which sanitises the posted data and inserts it into the db. public function create() { global $database; $attributes = $this->sanitised_attributes(); $sql = "INSERT INTO ".self::$table_name."("; $sql .= join(", ", array_keys($attributes)); $sql .= ") VALUES ('"; $sql .= join("', '", array_values($attributes)); $sql .= "')"; if($database->query($sql)) { $this->id = $database->insert_id(); return true; } else { return false; } } Hi all, I am having difficulty getting my UPDATE script to work. Basically the info is being pulled from a form and then being UPDATED, but it doesn't actually update and I am presented with no errors. It finds the record correctly and displays in the fields in the form as it should, just no update! Any ideas? Thanks in advance... Code: [Select] <?php error_reporting (E_ALL ^ E_NOTICE); $usr = "fdgdg"; $pwd = "dgdg"; $db = "dgdg"; $host = "dgdg.ddg.dg.50dgdg /***********************Get Record***********************/ $ref = (!empty($_GET['ref']))?trim($_GET['ref']):""; # connect to database $cid = mysql_connect($host,$usr,$pwd); if (!$cid){ echo("ERROR: " . mysql_error() . "\n"); } $db_selected = mysql_select_db(database, $cid); $query = sprintf("SELECT * FROM fleet where fleetref like '%s' LIMIT 1","%".mysql_real_escape_string($ref)."%"); $result = mysql_query($query) or die($query."<br>".mysql_error()); $record = mysql_fetch_assoc($result); if(mysql_num_rows($result) > 0) { echo "<strong>Updating fleet vehicle</strong>"; $fleetref=$record["ref"]; $fleetmake=$record["fleetmake"]; $fleetmodel=$record["fleetmodel"]; $fleetberth=$record["fleetberth"]; $fleetyear=$record["fleetyear"]; $fleetlength=$record["fleetlength"]; $fleetchassis=$record["fleetchassis"]; $fleetengine=$record["fleetengine"]; $fleetlayout=$record["fleetlayout"]; $fleettype=$record["fleettype"]; $fleetcomments=$record["fleetcomments"]; $pricelow=$record["pricelow"]; $pricemid=$record["pricemid"]; $pricehigh=$record["pricehigh"]; $fleetof=$record["fleetof"]; }else{ echo "<div id=\"pages\"><strong>Record not found</strong> - Edit Directory</div>"; $fleetmake=""; $fleetmodel=""; $fleetberth=""; $fleetyear=""; $fleetlength=""; $fleetchassis=""; $fleetengine=""; $fleetlayout=""; $fleettype=""; $fleetcomments=""; $pricelow=""; $pricemid=""; $pricehigh=""; $fleetof=$record["fleetof"]; } if ($fleetof == $account) { /***********************Save Record***********************/ # this is processed when the form is submitted # back on to this page (POST METHOD) if (isset($_POST['submit'])){ $fleetmake=$_POST["fleetmake"]; $fleetmodel=$_POST["fleetmodel"]; $fleetberth=$_POST["fleetberth"]; $fleetyear=$_POST["fleetyear"]; $fleetchassis=$_POST["fleetchassis"]; $fleetengine=$_POST["fleetengine"]; $fleetlayout=$_POST["fleetlayout"]; $fleetlength=$_POST["fleetlength"]; $fleettype=$_POST["fleettype"]; $fleetcomments=$_POST["fleetcomments"]; $pricelow=$_POST["pricelow"]; $pricemid=$_POST["pricemid"]; $pricehigh=$_POST["pricehigh"]; # setup SQL statement $query = sprintf("UPDATE `fleet` SET `fleetmake` = '%s',`fleetmodel` = '%s',`fleetberth` = '%s',`fleetyear` = '%s',`fleetchassis` = '%s',`fleetengine` = '%s',`fleetlayout` = '%s',`fleetlength` = '%s',`fleettype` = '%s',`fleetcomments` = '%s',`pricelow` = '%s',`pricemid` = '%s',`pricehigh` = '%s' WHERE `fleetref` ='%s' LIMIT 1", mysql_real_escape_string($fleetmake),mysql_real_escape_string($fleetmodel),mysql_real_escape_string($fleetberth),mysql_real_escape_string($fleetyear),mysql_real_escape_string($fleetchassis),mysql_real_escape_string($fleetengine),mysql_real_escape_string($fleetlayout),mysql_real_escape_string($fleetlength),mysql_real_escape_string($fleettype),mysql_real_escape_string($fleetcomments),mysql_real_escape_string($pricelow),mysql_real_escape_string($pricemid),mysql_real_escape_string($pricehigh),mysql_real_escape_string($fleetref)); #execute SQL statement $result = mysql_db_query($db,$query,$cid) or die($query."<br>".mysql_error()); # check for error if (!$result){ echo("ERROR: " . mysql_error() . "\n$SQL\n"); } echo "<P>Fleet vehicle updated</P>\n"; } } else {echo "Sorry, you are not authorised to edit this vehicle, please contact the system administrator for further help.";} ?> I wonder whether someone can help me please. I've found http://www.plus2net.com/php_tutorial/ajax-listbox.php tutorial to create a drop down menu using mySQL table data, which, in turn returns a list of results on the page. Following this tutorial I've put together the tables in my database and the required scripts as shown in the tutorial with the one exception, the "z_db.php" file, which I've assumed to be: Code: [Select] <?php mysql_connect("host", "user", "password")or die(mysql_error()); mysql_select_db("database"); ?> The problem I have, is that when I try and run this, I receive the following error: Quote Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /homepages/2/d333603417/htdocs/development/catsearch.php on line 91 which is this line in the search form: echo "</head><body onload="ajaxFunction()";>";. I must admit I've guessed as to the structure of the 'z_db.php' file should look like because this is not shown so perhaps this is the problem. I just wondered wether someone could perhaps take a look at this please and let me know where I've gone wrong. Many thanks and kind regards Hi, I'm new to the forum so this could go in the MySQL section but I'm not sure. I am trying to make a page that will list all records from a column in HTML table and have a delete button to remove a specific record. I have got to the part where I have listed the records in a table. Note: Only records from a specific column ('links') are printed. Here is the code: Code: [Select] $con = mysql_connect("localhost","***","***"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("***", $con); $result = mysql_query("SELECT * FROM main"); echo "<table border='1'> <tr> <th>Current links</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['links'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); How would I go about adding a delete button next to each record to delete that specific record? Thanks for any help. Code: [Select] <?php require "db/config.php"; $fname = $_POST['fname']; $lname = $_POST['lname']; $country = $_POST['country']; $state = $_POST['state']; $city = $_POST['city']; $zcode = $_POST['zcode']; $address = $_POST['address']; $ppemail = $_POST['ppemail']; $pnumber = $_POST['pnumber']; $cemail = $_POST['cemail']; $url = $_POST['url']; $price = "$5.00"; $query = "INSERT INTO custpackage1000( id, FirstName, LastName, Country, State, City, ZipCode, Address, PayPalEmail, PhoneNumber, PrimaryEmail, WebsiteURL) VALUES ( '1', '$fname', '$lname', '$country', '$state', '$city', '$zcode', '$ppemail', '$pnumber', '$cemail', '$url')"; mysql_connect($host, $user, $pass) or die("<br /><br /><h1>Fatal error. Please contact support if this persists.</h1>"); mysql_select_db($dbname); mysql_query($query) or die ("could not open db".mysql_error()); sleep(2); ?> Why won't the code insert into my database upon submission of data? What am I doing wrong? |