PHP - Array Not Being Passed To Function
In my main script I set $errorArray with values when required survey questions go unanswered. The ne code that checks for missing required values is working perfectly, and right before I pass $errorArray to a function which rebuilds the survey questions - this time with the error messages - I do a var_dump($errorArray) and that array has errors in it as expected. But while my function that re-builds the survey questions gets called and does indeed re-build the survey questions, the $errorArray isn't getting pased for some strange reason? (I'm not sure if i have ever passed an array to a function before.) In my function I have... function generateSurveyItem($dbc, $questionNo, $questionID, $surveyResponseArray=NULL, $errorArray=NULL){ }
When I var_dump($errorArray) at the top of the function, and submit a blank form, I end up with a blank page and a file path to my PHP script ending with... /public_html/utilities/function.php:3010:null
Questions: 1.) What is happening?
2.) I thought =NULL in the parameter list just meant that the argument is "optional"?
3.) I am able to successfully pass $surveyResponseArray to this function, so what is up with $errorArray?
P.S. When I run things, and submit an empty form - thus no "required" fields get completed - the survey gets re-displays, and any values chosen are "sticky", but my error messages should also be displayed to let the user know what is mising, and that is the part that isn't working? This has to be something silly stupid to fix... Edited February 16 by SaranacLake Similar Tutorialsi get this error Warning: current() [function.current]: Passed variable is not an array or object.. for this Code: [Select] $lastblock = current( ${"s".$row} ); print_r($lastblock); when i change to this it works.. Code: [Select] $lastblock = current( $s0 ); print_r($lastblock); The problem is i won't know the $row seeing as it is in a while loop. Solution? <?php global $places; $comm = $GLOBALS["location"]; $comm=trim($comm); while(list($one,$two) = each($places)) { echo "<option value=\"$two\""; if ( $two == $comm)echo "selected "; echo ">$two</option>\n" ; } ?> Variable passed to each() is not an array or objectHi, my code works fine but it is giving the error message Please can anyone help? Thanks This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=315384.0 hello, please i need ur help!!!! when i enter this url in my browser:http://localhost:10080/ntop/dumpData.html?language=php&proto i get: $ntopHash = array( 'ff02::1:2' => array( 'index' => '0', 'hostNumIpAddress' => 'ff02::1:2', 'hostResolvedName' => 'ff02::1:2', 'firstSeen' => '1337008485', 'lastSeen' => '1337009340', 'minTTL' => '0', 'maxTTL' => '0', 'pktSent' => '0', 'pktRcvd' => '15', 'ipBytesSent' => '0', 'ipBytesRcvd' => '0', etc...... so i'm writing a script to extract these informations and put them in a new web interface in a table. my script is: Code: [Select] <HTML> <HEAD> <LINK REL=stylesheet HREF=http://localhost:3000/style.css type="text/css"> </HEAD> <BODY BGCOLOR=red> <?php $host="localhost"; $port=10080; $url="http://localhost:10080/ntop/dumpData.html?language=php&proto"; $fp = fsockopen ($host, $port); if (!$fp) { echo "$errstr ($errno)<br>\n"; } else { $outStr = ""; fputs($fp, "GET $url HTTP/1.1\r\nHost: $host\r\n\r\n"); while (!feof($fp)) { $out = fgets($fp,128); if($out == "\n") $begin = 1; else if($begin = 1) $outStr = $out; } fclose ($fp); #echo "<pre>$outStr</pre>"; eval($outStr); } echo "<center>\n<table border>\n"; echo "<tr><th BGCOLOR=white>Sessions</th><th BGCOLOR=white>Values</th></tr>\n"; while (list ($key, $val) = each($ntopHash)) { echo "<tr><th align=center BGCOLOR=white>$key</th>\n"; echo "<td><table border>\n"; while (list ($key_1, $val_1) = each ($val)) if(gettype($val_1) == "array") { echo "<tr><th align=left>$key_1</th><td><table border>\n"; while (list ($key_2, $val_2) = each ($val_1)) { echo "<tr><th align=left>$key_2</th><td align=right> $val_2</td></tr>\n"; } echo "</table></td></tr>\n"; } else if($val_1 != "0") { if($key_1 == "sessionState") { if($val_1 == 0) $val2 = "SYN"; else if($val_1 == 1) $val2 = "SYN_ACK"; else if($val_1 == 2) $val2 = "ACTIVE"; else if($val_1 == 3) $val2 = "FIN1_ACK0"; else if($val_1 == 4) $val2 = "FIN1_ACK1"; else if($val_1 == 5) $val2 = "FIN2_ACK0"; else if($val_1 == 6) $val2 = "FIN2_ACK1"; else if($val_1 == 7) $val2 = "FIN2_ACK2"; else if($val_1 == $val2 = "TIMEOUT"; else if($val_1 == 9) $val2 = "END"; echo "<tr><th align=left>$key_1</th><td align=right> $val2</td></tr>\n"; } else echo "<tr><th align=left>$key_1</th><td align=right> $val_1</td></tr>\n"; } echo "</table></td></tr>\n"; } echo "</table>\n"; // echo "<pre>$outStr<pre>"; ?> </center> </body> </html> and i'm having this error: Sessions Values Warning: Variable passed to each() is not an array or object in C:\xampp\htdocs\projet\sessions.php on line 33 please i need your helpppp This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=319071.0 This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=308349.0 Hello, I'm just a beginner (and french sorry for my language) : have some pb with my little implode function. It's Running well on my local webserver (MAMP - PHP PHP Version 5.2.17) but when tested on ovh server (PHP4) show this error : Warning: implode() [function.implode]: Invalid arguments passed in /homez.xx/myPathHere/entete.php5 on line 6 I understand 1/ that one argument is missing but don't find the right syntax 2/ I have tried to turn this file on php5 with this extension (ovh is under php4) Here is my code in page defining the value and where stay my query (entete.php5) <?php if (isset($theme)) { $t = implode(',',$theme); $lien = "aide.php5?theme=".$t; $aide = '<a href="'.$lien.'">'.$onglet[0].'</a>'; } else { $aide = ""; } ?> Here is my code in page which show result (aide.php5) $t = explode(',',$_GET['theme']); $n = count($t); if ($n == 1) { $where = "id = ".$t[0]; } else { $where = "id = ".$t[0]; for ($i=1;$i<$n;$i++) { $where .= " OR id=".$t[$i]; } } Hope someone kindly help me : thanks in advance I am using a PHP class (it is attached) for Google Analytics that I got from this link below: http://www.acleon.co.uk/?p=173 Unfortunately, it appears the Class has a PHP error: Warning: implode() [function.implode]: Invalid arguments passed in Galvanize.php on line 114 and line 181. This is line 114: setcookie('__utmc', implode('.', $this->UTMC), 0, $this->CookiePath, $this->getDomain()); Here is line 181: $urchinUrl .= '&utmcc=__utma%3D'.implode('.', $this->UTMA).'%3B%2B__utmz%3D'.implode('.', $this->UTMZ).'%3B'; I did not see UTMC and UTMZ declared anywhere in the Class. The class file is attached. Thanks for your help in advance. My error is 'Warning: implode() [function.implode]: Invalid arguments passed in /home/definiti/public_html/contact.php on line 73' Im not sure how to fix this error, as I looked online and it says that my implode() has the right layout too it.. Line 73 in my code (I took the HTML code out) is this line; Code: [Select] $message = implode("<br>\n", $messages); My whole code is; Code: [Select] <?php # PHP Copyright 2007, Thomas Boutell and Boutell.Com, Inc. # Edited by Definition Designs. $recipient = 'defenitiondesigns@googlemail.com'; $serverName = 'www.definition-designs.co.uk'; if ($_POST['send']) { sendMail(); } elseif (($_POST['cancel']) || ($_POST['continue'])) { redirect(); } else { displayForm(false); } function displayForm($messages) { global $login; $escapedEmail = htmlspecialchars($_POST['email']); $escapedRealName = htmlspecialchars($_POST['realname']); $escapedSubject = htmlspecialchars($_POST['subject']); $escapedBody = htmlspecialchars($_POST['body']); $returnUrl = $_POST['returnurl']; if (!strlen($returnUrl)) { $returnUrl = $_SERVER['HTTP_REFERER']; if (!strlen($returnUrl)) { $returnUrl = '/'; } } $escapedReturnUrl = htmlspecialchars($returnUrl); ?> <?php if (count($messages) > 0) { $message = implode("<br>\n", $messages); echo("<h4>$message</h4>\n"); } ?> <form method="POST" action="<?php echo $_SERVER['DOCUMENT_URL']?>"> <p> <b>Your</b> Email Address <input name="email" size="35" maxlength="35" value="<?php echo $escapedEmail?>"/> </p> <p> Your <b>Real</b> Name <input name="realname" size="35" maxlength="35" value="<?php echo $escapedRealName?>"/> </p> <p> Subject Of Your Message <input name="subject" size="35" maxlength="35" value="<?php echo $escapedSubject?>"/> </p> <p> <i>Please enter the text of your message in the field that follows.</i> </p> <textarea name="body" rows="10" cols="60"><?php echo $escapedBody?></textarea> <p> <input type="submit" name="send" value="Send Your Message"/> <input type="submit" name="cancel" value="Cancel - Never Mind"/> </p> <input type="hidden" name="returnurl" value="<?php echo $escapedReturnUrl?>"/> </form> <?php } function redirect() { global $serverName; $returnUrl = $_POST['returnurl']; $prefix = "http://$serverName/"; if (!beginsWith($returnUrl, $prefix)) { $returnUrl = "http://$serverName/"; } header("Location: $returnUrl"); } function beginsWith($s, $prefix) { return (substr($s, 0, strlen($prefix)) === $prefix); } function sendMail() { global $recipient; $messages = array(); $email = $_POST['email']; if (!preg_match("/^[\w\+\-\.\~]+\@[\-\w\.\!]+$/", $email)) { $messages[] = "That is not a valid email address. In format: You@something.com"; } $realName = $_POST['realname']; if (!preg_match("/^[\w\ \+\-\'\"]+$/", $realName)) { $messages[] = "The real name field must contain only alphanumeric characters, spaces and + or - signs."; } $subject = $_POST['subject']; if (preg_match('/^\s*$/', $subject)) { $messages[] = "Please specify a subject for your message. "; } $body = $_POST['body']; if (preg_match('/^\s*$/', $body)) { $messages[] = "Your message was blank. Fill out a message or Click Cancel to cancel message."; } if (count($messages)) { displayForm($messages); return; } mail($recipient, $subject, $body) or die("unable to send the mail!"); $escapedReturnUrl = htmlspecialchars($_POST['returnurl']); ?> <form method="POST" action="<?php echo $_SERVER['DOCUMENT_URL']?>"> <input type="submit" name="continue" value="Click Here To Continue"/> <input type="hidden" name="returnurl" value="<?php echo $escapedReturnUrl?>"/> </form> <?php } ?> I am getting this error in the header.php of my wordpress theme... Can anyone help? Thanks! Warning: implode() [function.implode]: Invalid arguments passed in /home/bexxx/public_html/wp-content/themes/organic_portfolio_gray/header.php on line 74 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" <?php language_attributes(); ?>> <head profile="http://gmpg.org/xfn/11"> <meta http-equiv="Content-Type" content="<?php bloginfo('html_type'); ?>; charset=<?php bloginfo('charset'); ?>" /> <meta name="distribution" content="global" /> <meta name="robots" content="follow, all" /> <meta name="language" content="en" /> <title><?php wp_title(''); ?><?php if(wp_title('', false)) { echo ' :'; } ?> <?php bloginfo('name'); ?></title> <link rel="Shortcut Icon" href="<?php echo bloginfo('template_url'); ?>/images/favicon.ico" type="image/x-icon" /> <link rel="stylesheet" href="<?php bloginfo('stylesheet_url'); ?>" type="text/css" media="screen" /> <link rel="alternate" type="application/rss+xml" title="<?php bloginfo('name'); ?> RSS Feed" href="<?php bloginfo('rss2_url'); ?>" /> <link rel="alternate" type="application/atom+xml" title="<?php bloginfo('name'); ?> Atom Feed" href="<?php bloginfo('atom_url'); ?>" /> <link rel="pingback" href="<?php bloginfo('pingback_url'); ?>" /> <?php if ( is_singular() ) wp_enqueue_script( 'comment-reply' ); ?> <?php wp_enqueue_script("jquery"); ?> <?php wp_head(); ?> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/superfish/superfish.js"></script> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/superfish/hoverIntent.js"></script> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/jquery.flow.1.1.js"></script> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/iepngfix_tilebg.js"></script> <!--IE6 Fix--> <style type="text/css"> img, div, a, input, body, span { behavior: url(<?php bloginfo('template_url'); ?>/images/iepngfix.htc); } </style> <script type="text/javascript"> var $j = jQuery.noConflict(); $j(function() { $j("div#controller").jFlow({ slides: "#slides", width: "960px", height: "480px", timer: <?php echo ot_option('slider_interval'); ?>, duration: 400 }); }); </script> <script type="text/javascript"> $j(document).ready(function() { $j('ul.ot-menu').superfish(); }); </script> </head> <body> <div id="wrap"> <div id="header"> <div class="headercenter"> <p id="title"><a href="<?php echo get_option('home'); ?>/" title="Home"><?php bloginfo('name'); ?></a></p> </div> </div> <div id="navbar"> <div id="nav"> <div id="navbarleft"> <ul class="ot-menu"><li<?php if (is_home()) { echo " class=\"current_page_item\""; }?>><a href="<?php echo get_settings('home'); ?>"><?php _e("Home", 'organicthemes'); ?></a></li> <?php $include_categories = ot_option('include_categories'); ?> <?php wp_list_categories('depth=4&title_li=&sort_column=menu_order&include='.implode(',', $include_categories)); ?></ul> </div> <div id="navbarright"> <ul class="ot-menu"> <?php $include_pages = ot_option('include_pages'); ?> <?php wp_list_pages('title_li=&sort_column=menu_order&include='.implode(',', $include_pages)); ?> </ul> </div> </div> </div> <div style="clear:both;"></div> i have a problem i cant solved for cople of hours! this is the function: function show_posts($user_id,$limit=0){ $posts = array(); $user_string = implode(',', $user_id); $extra = " and id in ($user_string) "; if ($limit > 0){ $extra = "limit $limit"; }else{ $extra = ''; } $sql = "SELECT userid, caption, stamp, filename FROM photographs WHERE userid in ($user_string) order by stamp desc $extra"; //echo $sql; $result = mysql_query($sql) or die(mysql_error()) ; while($data = mysql_fetch_object($result)){ $posts[] = array( 'stamp' => $data->stamp, 'userid' => $data->userid, 'caption' => $data->caption, 'filename' => $data->filename, ); } return $posts; } and thats the full error: Warning: implode() [function.implode]: Invalid arguments passed in C:\wamp\www\includes\functions.php on line 12 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') order by stamp desc' at line 2 and the intresting thing that if i echo the sql i get a working one i checked it in phpmyadmin + it shows what it need to show in the index.php if i comment the "or die(mysql_error()) " here the sql when its do echo SELECT userid, caption, stamp, filename FROM photographs WHERE userid in (4,7,2) order by stamp desc limit 5 so y the hell this problem is keep coming? i really cant understand what wrong! tnx for the help! I am having some problems getting a query correct. Basically I have two tables, one with listings and another with categories. In the listings table I have a column called shortdescription. I am trying to pull the shortdescription from the listings table with the query $shortdesc = array_shift(mysql_fetch_row(mysql_query("select shortdescription from links where category = '".$scat->id."' "))); The shortdecription display properly on the pages display the listings, however I am getting the following error on any pages that only display the parent categories Warning: array_shift() [function.array-shift]: The argument should be an array in /home/...path/file.php on line 1462 The listings id numbers begin at 75+ because the initial parent category id ends at 74. The query seems to be searching for listing ids below 75 and spitting out an error because it is not finding them. Any ideas on how to eliminate this error and/or stop the query from looking for non-existant data? I want to define a function instead of repeating query in all my php pages. I call a function by passing an $id value and from that function i have to get all the info related to that id, like name, description and uom.
I am trying to do this, but i dont know how to get these values seperately.
here is my function
function items($item_id) { $details = array(); $result = mysql_query("select item_id, name, uom, description from items where item_id=".$item_id."") or die (mysql_error()); while($row = mysql_fetch_array($result)) { $details[] = array((stripslashes($row['name'])), (stripslashes($row['uom'])), (stripslashes($row['description']))); } return $details; }and i call my function like this $info = items($id);Can somebody guide me in this hi Code: [Select] function livre($form_data_array['ensino']) { } this code give me a syntax error, why? what is the correct way? thanks I hope I'm not being a vampire here sucking the life out of you guys, but I can't find any resources in google that explains how to properly use this function in a mysql array. All it does is add a url for any urls added in plaintext. Code: --- <?php function hyperlink ($string) { $string = preg_replace('#(^|\s)([a-z]+://([^\s\w/]?[\w/])*)#is', '\\1<a href="\\2" target="_blank">\\2</a>', $string); $string = preg_replace('#(^|\s)((www|ftp)\.([^\s\w/]?[\w/])*)#is', '\\1<a href="http://\\2" target="_blank">\\2</a>', $string); $string = preg_replace('#(^|\s)(([a-z0-9._%+-]+)@(([.-]?[a-z0-9])*))#is', '\\1<a href="mailto:\\2">\\2</a>', $string); return $string; } // mysql connection $result = mysql_query("SELECT * FROM top_web_articles ORDER BY ID DESC"); echo "<table border='0'>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td class='newstitle' align='left' valign='top' bgcolor='#D6D6D6'>".$row['Category']."</td></tr>"; echo "<td class='newstitle' align='left' valign='top' bgcolor='#D6D6D6'>". $row['ArticleName'] ."</td></tr>"; echo "<td class='newstitle' align='left' valign='top' bgcolor='#D6D6D6'>"hyperlink(. $row['ArticleDescription'] .);"</td></tr>"; echo "<tr><td class='newstitle' align='left' valign='top' bgcolor='#D6D6D6'><a href='". $row['URL'] . "' target='_blank'><img src='http://www.thenewsguys.ca/images/read entire article.png' alt='' width='130' height='11' border='0' /></a></td>"; echo "</tr>"; echo "<td align='left' valign='top'> </td>"; } echo "</table>"; mysql_close($con); ?> --- Error: "Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/doofyd5/public_html/trevor/playground/displayarticles.php on line 146" (Clearly an error where I'm abusing the heck out of the bolded line. Any ideas on how to properly code this? Hi,Dear Frnds...........................I Hope U r all fine. I am using php.Here is the problem in the Return array from function. This is the code. Code: [Select] <?php $store = array(); $test = get_my_links(); print_r($store); function get_my_links() { $my_array = array('e','f','g'); foreach($my_array as $key=> $list) { $store[] = $list; } return $store; } ?> Suppose the array is maked dynamically. please help me..THANKS... Hello Guys, I have a question I have the following function that is located in a different file. I want to be able to use the $lat and $long in my main page how would I code it? Code: [Select] function toCoordinates($all_address) { $bad = array( " " => "+", "," => "", "?" => "", "&" => "", "=" => "" ); $all_address = str_replace(array_keys($bad), array_values($bad), $all_address); $data = new SimpleXMLElement(file_get_contents("http://maps.google.com/maps/geo?output=xml&q={$all_address}")); $coordinates = explode(",", $data->Response->Placemark->Point->coordinates); return array( "latitude" => $coordinates[0], "longitude" => $coordinates[1] ); } Tried this but it didn't work $all_address2 = toCoordinates($all_address); echo "$all_address2; Please advise... Thanks, Dan I've written the code to generate letter and number ranges: public function generateRange($type = 'numbers', $start = 0, $end = 10) { $rangelist = array(); switch($type) { case 'upper letters': { foreach(range($start, $end) as $letter) { $rangelist[] = $letter; } } case 'lower letters': { foreach(range($start, $end) as $letter) { $rangelist[] = $letter; } } case 'numbers': { foreach(range($start, $end) as $number) { $rangelist[] = $number; } } default: { return false; } return $rangelist; } } It current doesn't seem to return the array result correctly currently. If I change the line "$rangelist[] = $number;" to "echo $number;" it does print the correct data. Any ideas on why the array return line isn't working correctly? Hey Guys, I am hoping you can help me find out why a function of mine is only returning 1 record when I am asking for 10. Here is the function I am using to get the data. When I run the $sql that is printed in phpmyadmin.... I get then records. But when I print the $event_data I am only getting 1 record. Any help would be greatly appreciated function get_events($data) { //print_r($data); $lat = $data['lat']; $long = $data['long']; $offset = $data['offset']; $radius = $data['radius']; $amount = $data['amount']; //the events query $sql = sprintf("SELECT *, ( 3959 * acos( cos( radians('%s') ) * cos( radians( latitude ) ) * cos( radians( longitude ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( latitude ) ) ) ) AS distance FROM events WHERE `status` = '0' HAVING distance < '%s' ORDER BY distance LIMIT $amount OFFSET $offset", mysql_real_escape_string($lat), mysql_real_escape_string($long), mysql_real_escape_string($lat), mysql_real_escape_string($radius)); //debugging print_r($sql); $event_data = array(); $event_data = mysql_fetch_array(mysql_query($sql)); //debugging print_r($event_data); return $event_data; } How can I make a multiple function array? i'm setting up reminders for users and fetch_reminders does what it says... fetches all the reminder functions. Well that's what I want it to do and the other functions are just checks. How can I make $reminder and array of the functions that I want checked? Is this the best way to do it? Code: [Select] $reminder =array() function fetch_reminders($reminder === true) { return true } function capital_requested_reminder($requested, $accounttype) { $requested = (int)$requested; $accounttype = (int)$accounttype; if (empty($requested) && ($accounttype === 1)) { return true; } } function associates_reminder($associates) { $associates = (int)$associates; if ($associates >= 1) { return true; } } |