|
PHP - Interpreting/correcting Code For Api-platform And Jwt
The following script comes from create a decorator example. Please take a look at __construct() and $pathItem. Doesn't look like any PHP I've ever seen. Agree? I don't think it matters and just stating so to make sure, but I am not using a docket but have api-platform on the local server. I've gotten all to work until now.
<?php
// api/src/OpenApi/JwtDecorator.php
declare(strict_types=1);
namespace App\OpenApi;
use ApiPlatform\Core\OpenApi\Factory\OpenApiFactoryInterface;
use ApiPlatform\Core\OpenApi\OpenApi;
use ApiPlatform\Core\OpenApi\Model;
final class JwtDecorator implements OpenApiFactoryInterface
{
public function __construct(
private OpenApiFactoryInterface $decorated
) {}
public function __invoke(array $context = []): OpenApi
{
$openApi = ($this->decorated)($context);
$schemas = $openApi->getComponents()->getSchemas();
$schemas['Token'] = new ArrayObject([
'type' => 'object',
'properties' => [
'token' => [
'type' => 'string',
'readOnly' => true,
],
],
]);
$schemas['Credentials'] = new ArrayObject([
'type' => 'object',
'properties' => [
'email' => [
'type' => 'string',
'example' => 'johndoe@example.com',
],
'password' => [
'type' => 'string',
'example' => 'apassword',
],
],
]);
$pathItem = new Model\PathItem(
ref: 'JWT Token',
post: new Model\Operation(
operationId: 'postCredentialsItem',
responses: [
'200' => [
'description' => 'Get JWT token',
'content' => [
'application/json' => [
'schema' => [
'$ref' => '#/components/schemas/Token',
],
],
],
],
],
summary: 'Get JWT token to login.',
requestBody: new Model\RequestBody(
description: 'Generate new JWT Token',
content: new ArrayObject([
'application/json' => [
'schema' => [
'$ref' => '#/components/schemas/Credentials',
],
],
]),
),
),
);
$openApi->getPaths()->addPath('/authentication_token', $pathItem);
return $openApi;
}
}
I am thinking that maybe the constructor needs to be changed to:
private $decorated;
public function __construct(OpenApiFactoryInterface $decorated)
{
$this->decorated = $decorated;
}
Regarding $pathItem, Model\PathItem's constructor is as follows. Any thoughts on what they are suggesting? Thanks
public function __construct(
string $ref = null,
string $summary = null,
string $description = null,
Operation $get = null,
Operation $put = null,
Operation $post = null,
Operation $delete = null,
Operation $options = null,
Operation $head = null,
Operation $patch = null,
Operation $trace = null,
?array $servers = null,
array $parameters = []
)
{/* ... */}
Edited January 28 by NotionCommotion Not using docket Similar TutorialsHi guys, First time post here so go easy on me OK, heres the deal: I have a page with a form and when submitted it needs to update MySQL tables The code for the form is as follows: Code: [Select] <form method="post" action="update.php"> <select name="Batsman"> <option value="Player 1">Player 1</option> <option value="Player 2">Player 2</option> </select> <input type="text" name="Runs" size="5" /> <input type="text" name="Overs" size="5" /> <input type="submit" value="Submit Batting Scores" /> </form> The code for the 'update.php' is as follows: Code: [Select] <?php $Batsman = $_POST['Batsman']; $Runs = $_POST['Runs']; $Overs = $_POST['Overs']; mysql_connect ("HOST", "*USERNAME*", "*PASSWORD*") or die ('error: ' .mysql_error()); mysql_select_db ("DB_NAME"); $query="UPDATE batting SET runs = ("'.$Runs.'"+runs) WHERE batsman = '$Batsman' " $query2="UPDATE bowling SET overs = ("'.$Overs.'"+overs) WHERE batsman = '$Batsman' " mysql_query($query) or die ('Error updating result: ' .mysql_error()); mysql_query($query2) or die ('Error updating result: ' .mysql_error()); echo "Results updated with: ".$Batsman." - ".$Runs." Runs" ; ?> The database layout is: 2 tables, 1 named "batting" another named "bowling" What the form SHOULD be doing is: Take what ever number is inputed to "Runs" and ADD TO THE CURRENT TOTAL of 'Runs' in 'Batting' Take what ever number is inputed to "Overs" and ADD TO CURRENT TOTAL of 'Overs' in 'bowling' The IDs on each table are 'Player 1' and 'Player 2' - labeled on each table as 'batsman' The corresponding 'batsman' is selected on the form via the drop down before submiting. For example if 'Player 2' currently has 50 'runs' in 'batting' and 10 'Overs' in 'bowling', and I then select him on the drop down and input 10 runs and 1 over, when I hit submit his data in the MySQL tables SHOULD go to 60 'runs' in 'batting' and 11 'overs' in 'bowling' Im hoping labeling the table data in this way provides a clear enough explanation of the set up with out the need to know about the subject matter in hand, (cricket, if you havent guessed already ) Now the table worked fine when I was updating to REPLACE the numbers in 'runs' or 'overs' but I need it to ADD to the existing number I was advised else where to add the '+runs' '+overs' in order to get this to work but all Im getting is an error. The current error coming back is: Quote Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in /home/a2552500/public_html/update.php on line 10 If someone can correct me whereever I am going wrong that would be great, however an explination to acompany any correction would be appreciated as Id like to learn what is wrong, why its wrong and how to fix it. Thanks in advance for your time Tom i want the code for review approval platform (costumer reviews for a product )and in backend editing the code and updating it I am working on modifying some code and wanted to check some variables, but am stuck on something that is probably simple, just over my head. If I do the following: print_r ($this); I get this result (I used PRE tags to format it) ViewList Object ( [_name] => list [_models] => Array ( => ModelList Object ( [_data] => Array ( => stdClass Object ( [id] => 70 [catid] => 1 etc...... Moving down, I typed this... print_r ($this->_models); and get this... Array ( => ModelList Object ( [_data] => Array ( => stdClass Object ( [id] => 70 [catid] => 1 How would I get, for instance, the id? If I try print_r($this->_models->list); nothing happens. In other words, if I wanted to return the id, what would it be -- $this->_models->??? . I tried all kinds of combination's and other ways to do it, just can't figure it out. I know it is my limited knowledge with PHP , so could someone point me in the right direction. Thanks, Doc [/list][/list] Could anyone help me please. I am trying to create a quiz in (quiz.php) which is works fine, but when I am trying to correct the quiz in another page (result.php) I had an error. I think the problem with posted answers and I couldn't solve it.
This is my code in (quiz.php):
<form method="post" action="result.php">
<?php
session_start();
$questionNumber = 1;
$query = mysql_query("SELECT * FROM Question WHERE TID = 'TEST' order by RAND()");
while ($result = mysql_fetch_array($query)) { ?>
<?php echo $questionNumber . ") " . $result['Question'] . "<br>"; ?>
<input type="radio" name="answer<?php echo $result["QID"] ?>" value="A"> <?php echo $result['A']; ?> <br>
<input type="radio" name="answer<?php echo $result["QID"] ?>" value="B"> <?php echo $result['B']; ?> <br>
<input type="radio" name="answer<?php echo $result["QID"] ?>" value="C"> <?php echo $result['C']; ?> <br>
<input type="radio" name="answer<?php echo $result["QID"] ?>" value="D"> <?php echo $result['D']; ?> <br>
<?php
$questionNumber +=1;
}
?>
<input type="submit" name="checkQuiz" value="Check Quiz" onclick="location.href='result.php'" />
</form>
And This is my code in (result.php):
<?php
if(isset($_POST['checkQuiz'])) {
$correctAnswers = 0;
$wrongAnswers = 0;
$idList = join (',', array_map('intval', array_keys($_POST['answer'])));
$sql = "SELECT QID, Answers FROM correct WHERE QID IN ($idList)";
while (list($QID, $correct) = mysql_fetch_row($res)) {
if ($correct == $_POST['answer'][$QID]) {
$correctAnswers +=1;
}
else {
$wrongAnswers +=1;
}
}
}
?>
// in the body
<?php
$numberOfQs = $correctAnswers + $wrongAnswers;
$score = round(($correctAnswers / $numberOfQs) * 100);
?>
Correct Answers: <?php echo $correctAnswers; ?> <br>
Wrong Answers: <?php echo $wrongAnswers; ?> <br>
Sco <?php echo $score;
?>
About the project.
We are looking to build a Car Dealer Platform (CMS) to be able to offer it as a “Software as a Service” to range of our clients. What we would like to achieve is something similar to what is currently available on the market. I did a little research and the are a lot of scripts, plugins, software and such already available online (i.e. http://www.hotscripts.com/category/scripts/php/scripts-programs/classified-ads/autos/, http://www.worksforweb.com/classifieds-software/iAuto/, http://intersofts.com/) however, we require some functionality that are not included in the above mentioned and we want this to be a bespoke platform tailored for us.
The platform must have:
ability to accommodate Comcar data (http://comcar.co.uk/)
ability to accommodate Cap data (http://www.cap.co.uk/)
ability to accommodate finance calculator (i.e. https://ivendi.com/)
ability to accept stock feeds from Dealership Management System (i.e. http://www.2ndbyte.com/)
ability to send used car stock feed to used car portals such as AutoTrader (http://www.autotrader.co.uk/), Motors (http://www.motors.co.uk/), AA Cars (http://www.vcars.co.uk/)
full registration lookup on used car stock through a Vehicle Registration Mark (http://business.cap.co.uk/products-and-services/vrm-look)
Service and MOT booking to include registration lookup
easily add multi locations and assign stock for each location
capture leads via contact forms
of course must be responsive, SEO friendly and compliant with the latest web standards
easy to add new pages, locations, franchise
easy to upload the offer banners for the home page
easy to customize for each client / dealer (CSS, HTML, JS)
I am fully aware this is not a small project and it will take a lot of time and manpower to accomplish this, however I am positive about it. This would be developed in stages so we could start offering it to our clients with ideally long time support from the creators of the platform.
Here are some examples of platforms currently available on the market and few websites created based on these platforms:
NetDirector - http://www.gforces.co.uk/
http://www.hrowen.co.uk/
http://www.thurlownunn.co.uk/
http://www.deswinks.com/
http://www.glynhopkin.com/
http://www.trustford.co.uk/
http://www.westlandsmotorgroup.co.uk/ (as two franchises and uses latest version of platform)
Web21st - http://www.web21st.com/
http://www.wjking.co.uk/
http://www.sussexusedcars.uk.com/
http://www.wilsonandco.com/
http://www.findvauxhall.co.uk/
Bluesky Interactive - http://www.blueskyinteractive.co.uk/ - Cognition CMS based (http://www.blueskyinteractive.co.uk/admin/)
http://www.fish-bros.co.uk/
http://www.nowvauxhall.co.uk/
http://www.alandayvw.co.uk/
http://dinnages.co.uk/
http://griffinmill.co.uk/
Denison Automotive - http://www.denison.co.uk/automotive/
http://www.perrys.co.uk/
http://www.trusteddealers.co.uk/
http://www.westwaynissan.co.uk/
http://www.tilsungroup.com/
Please feel free to PM me anything related to the topic and ask questions if something is unclear as well as if you require more info.
What I am hoping to achieve by posting this here is to get some advice from experienced / senior php developers to point us in the right direction and hopefully to start a partnership.
We are based in North London.
Thank you.
Alek
Any pointers would be much appreciated. I got my PHP app working (not without some great help from this forum) but when I migrated my PHP scripts and MySQL database to my ISP's platform the app fell apart since the web is the destination for this app, I then had to diagnose and fix what happened. The problem: On the ISP's platform, a query string passed unescaped with say a QUOTE in it came in on the subsequent GET ESCAPED. On my platform they arrived UNESCAPED. Is this a php.ini discrepancy or a version discrepancy between us please? Thing is I'd like to get the local version working again after all the changes because what worked on one broke on the other, now the other is fixed the one is broken if you get my drift. Platform / Version variations: Local implementation is Win7, Apache 2.2.19 / PHP 5.3.6 / MySQL 5.5 ISP is Linux not sure of the Apache version believe it is 2.? PHP 5.2.14 / MySQL Client Api 4.1.22 Any input or links for reading would be appreciated. Jamie I have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this? <?php include ("includes/includes.php"); $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo "<p class='postnote'>" . $post->post . "</p"; echo "<span class='footer'>Posted By: " . $post->author . "</span>"; echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>"; echo "<span class='footer'>Tags: " . $post->tags . "</span>"; echo ' <div class="addthis_toolbox addthis_default_style "> <a class="addthis_button_facebook_like" fb:like:layout="button_count"></a> <a class="addthis_button_tweet"></a> <a class="addthis_counter addthis_pill_style"></a> </div> <script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script> <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>'; echo "</div>"; } ?> Advance thank you. Can you help please. The error..... Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24 code. Code: [Select] <?php //database connection. $DB = mysql_connect("localhost","root") or die(mysql_error()); if($DB){ //database name. $DB_NAME="mysql"; //select database and name. $CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name"); // if connection. }if($CON){ //show tables. $mysql_show="SHOW TABLES"; //select show and show. $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())"; } //if allowed to show. if($mysql_select2){ //while it and while($data=mysql_fetch_assoc($mysql_select2)){ //show it. echo $data; } } ?> Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code. $sql="select * from Profile where username = '$username'; $result = mysql_query( $sql, $conn ) or die( "ERR: SQL 1" ); if(mysql_num_rows($result)!=0) { process form } else { echo "That username already exist!"; } the current code of the form <?PHP //session_start(); require_once "formvalidator.php"; $show_form=true; if (!isset($_POST['Submit'])) { $human_number1 = rand(1, 12); $human_number2 = rand(1, 38); $human_answer = $human_number1 + $human_number2; $_SESSION['check_answer'] = $human_answer; } if(isset($_POST['Submit'])) { if (!isset($_SESSION['check_answer'])) { echo "<p>Error: Answer session not set</p>"; } if($_POST['math'] != $_SESSION['check_answer']) { echo "<p>You did not pass the human check.</p>"; exit(); } $validator = new FormValidator(); $validator->addValidation("FirstName","req","Please fill in FirstName"); $validator->addValidation("LastName","req","Please fill in LastName"); $validator->addValidation("UserName","req","Please fill in UserName"); $validator->addValidation("Password","req","Please fill in a Password"); $validator->addValidation("Password2","req","Please re-enter your password"); $validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!"); $validator->addValidation("email","email","The input for Email should be a valid email value"); $validator->addValidation("email","req","Please fill in Email"); $validator->addValidation("Zip","req","Please fill in your Zip Code"); $validator->addValidation("Security","req","Please fill in your Security Question"); $validator->addValidation("Security2","req","Please fill in your Security Answer"); if($validator->ValidateForm()) { $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error()); mysql_select_db("beatthis_beatthis") or die(mysql_error()); $FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file $LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file $UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file $Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file $Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file $email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file $Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file $Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file $Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file $Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file $sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; //echo $sql; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } else{ mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body); echo "<h3>Your profile information has been submitted successfully.</h3>"; } mysql_close($con); $show_form=false; } else { echo "<h3 class='ErrorTitle'>Validation Errors:</h3>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<p class='errors'>$inpname : $inp_err</p>\n"; } } } if(true == $show_form) { ?> hey gurus, i am a newbie php coder.. i am learning by example. what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage) ---------------------------------------------------------------- the table structure that will be used is as follows: user.bonus_credit user.ID bonus_credit.bonusCode bonus_credit.qty bonus_credit.value bonus_credit_usage.bonusCode bonus_credit_usage.usedBy ---------------------------------------------------------------- so lets say, in bonus_credit i have the following bonusCode = 'facebook' (this is the code they have to type to redeem the bonus qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once) value = '5' (this is the amount of bonus_credit for each qty) Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit ----------------------- i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code. if(isset($_REQUEST['btnBonus'])) { $bonus_credit = addslashes($_REQUEST['bonusCode']); $query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'"; echo "<script>window.location='myreferrals.php?msgs=2';</script>"; mysql_query($query) or die(mysql_error()); } Can you help me integrate this code :
<form method="post" action="submit.php"> <input type="checkbox" class="required" /> Click to check <br /> <input disabled="disabled" type='submit' id="submitBtn" value="Submit"> </form>In to this Contact Form code, please? <form action="../page.php?page=1" method="post" name="contact_us" onSubmit="return capCheck(this);"> <table cellpadding="5" width="100%"> <tr> <td width="10" class="required_field">*</td> <td width="80">Your Name</td> <td><input type="text" name="name" maxlength="40" style="width:400px;/></td> </tr> <tr> <td class="required_field">*</td> <td>Email Address</td> <td><input type="text" name="email" maxlength="40" style="width:400px;/></td> </tr> <tr> <td></td> <td>Comments:</td> <td><textarea name="comments" style="width: 400px; height: 250px;"></textarea></td> </tr> </table> </form I use this type of a code to send automatic emails from my website: Code: [Select] $headers = ; $headers .= ; $to = ; Click here to go to Google. ", $headers); I am having hard time figuring out how to do hyperlink on words (like here). If I do something like this: Code: [Select] <a href='http://www.google.com'>here</a> it spits out that exact thing out. Thanks you for your input Hi, Look at this code below: Code: [Select] <?php function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ""; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n"; $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = round($markTotal / $weightSession * 100); if ($markGrade >= 70) { $grade = "A"; } else if ($markGrade >= 60 && $markGrade <= 69) { $grade = "B"; } else if ($markGrade >= 50 && $markGrade <= 59) { $grade = "C"; } else if ($markGrade >= 40 && $markGrade <= 49) { $grade = "D"; } else if ($markGrade >= 30 && $markGrade <= 39) { $grade = "E"; } else if ($markGrade >= 0 && $markGrade <= 29) { $grade = "F"; } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n"; return $moduleHTML . $sessionsHTML; } $output = ""; $studentId = false; $courseId = false; $moduleId = false; while ($row = mysql_fetch_array($result)) { if($studentId != $row['StudentUsername']) { //Student has changed $studentId = $row['StudentUsername']; $output .= "<p><strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']})\n"; } if($courseId != $row['CourseId']) { //Course has changed $courseId = $row['CourseId']; $output .= "<br><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Course Mark</strong> <strong>Grade</strong> <br><strong>Year:</strong> {$row['Year']} </p>\n"; } if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } //Get output for last module $output .= outputModule($moduleId, $moduleName, $sessionsAry); //Display the output echo $output; } } } ?> This code allallows me to make calculations and display a student's course and linked with it the course the modules in the course and linked with modules are all the sessions. It is able to display what marks each student have got for each module and session. Now look at code below, it is able to display modules and in those modules the sessions that link to those modules: Code: [Select] <?php if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } What I want to know is how can I do something similar for course so that it picks out the right modules depending on the course it displays. There maybe some code that needs to be added in the function. Can I combine also HTML code in PHP function? For example, can a PHP function include HTML form and the PHP code to handle this form? If yes, this will make my main code much more smaller and readable. If not, is there a way to define an "external macro" like, which allow me to replace pre-defined lines of code with short alias? Hello Everyone I am new to php and indeed Web Development. After testing and Playing a bit, I can get the following code to work as two files, the form calling the *.php file to insert into the database, however, I am trying to create one html/php file that displays the form and then executes the php code to insert into the database once user clickes the button. Please can you assist me with the code? I have something horribly wrong and I cannot find it. Code: [Select] <?php> <html> <head> <title>Personal Details</title> </head> <body> <form method="post" action="contactdetails.html"><font face="Arial"> Call Sign:<br> <input name="callsign" size="5" type="text"><br> Surame:<br> <input name="surname" size="30" type="text"><br> First Name:<br> <input name="firstnames" size="30" type="text"><br> Known as:<br> <input name="knownas" size="30" type="text"><br> RSA ID No.:<br> <input name="rsaid" size="13" type="text"><br> Birth Date:<br> <input name="birthdate" size="12" type="text"><br> <input name="Insert" value="Next" type="submit"></form> </font><br> </body> </html> //php to insert data into table $callsign = $_POST['callsign']; $surname = $_POST['surname']; $firstnames = $_POST['firstnames']; $knownas = $_POST['knownas']; $rsaid = $_POST['rsaid']; $birthdate = $_POST['birthdate']; mysql_connect ("localhost", "jredpixm_testuse", "PHPDevelopment") or die ('I cannot connect to the database because: ' .mysql_error()); mysql_select_db ("jredpixm_test"); $query="INSERT INTO personal_details (callsign, surname, firstnames, knownas, rsaid, birthdate)Values ('$callsign', '$surname', '$firstnames', '$knownas', '$rsaid', '$birthdate')"; mysql_query($query) or die ('Error updating Database'); echo "<p>Thanks, your information has been added to the database.</p>"; ?> Regards Allen Michael Feathers coined the term Legacy Code as being code without automated tests.
Still however Legacy Code evokes a vision in me that it is code that is ugly, old, runs on mainframes, and is probably 3000 lines long, uses globals and questionable code practices.
But say we take this ugly nasty code, and put it very nicely under test, but without doing any refactoring, other than that necessary to be able to put it under test in the first place.
Now that code is under test. But it it still ugly. How would you call ugly code under test?
Would you make a differentiation between old & ugly and modern & pretty code if both are under test?
How can I make sure that when I submit an new form and new ID (record) is created it is always 4-Digits. record 14 = 0014, record 225 = 0225. Thanks Hi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Alright so I'm attempting to save config data via php. Bellow is the code I currently have, however I'm afraid that when I "flip the switch" and use it that it will error out because of the <?php and ?> tags inside of it... Ideas, suggestions? $config = '../includes/config.php'; $fh = fopen($config, 'w'); $data = ' <?php $dbhost = "'.$database_host.'"; $dbuser = "'.$database_username.'"; $dbpass = "'.$database_password.'"; $dbname = "'.$database_name.'"; $key = "'.$site_key.'"; $cron_key = "'.$database_cron_key.'"; ?> '; fwrite($fh, $data); fclose($fh); |
|||||||