PHP - Php Problem When No Records From Database
Google Chrome Developer Tool causes an error when I run the following and there are not any records. I keep getting errors when I try to change it.
<?php $host = 'localhost'; $user = 'root'; $pass = ''; $database = 'ecommerce'; $options = array( PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION, PDO::ATTR_EMULATE_PREPARES => false ); $keyword = $_GET['keyword']; $dbo = new PDO("mysql:host=$host;dbname=$database", $user, $pass, $options); $q1 = "SELECT * FROM products INNER JOIN keywords on keywords.keywordID = products.KeywordID and keywords.KeyWord1 = \"$keyword\" "; $counter = 10; $counter1 = 0; foreach ($dbo->query($q1) as $row) {
Similar TutorialsHello all. Please I need help to update customer table. I get the texboxes populated with select query no problem. I have html page with a search box and when the user enter their first name or last name and click search it will call up the search.php file here is the file: This code below populate the textboxes to be updated: Code: [Select] <?php if(isset($_POST['submit'])){ if(isset($_GET['go'])){ if(preg_match("^/[A-Za-z]+/", $_POST['name'])){ $name=$_POST['name']; } } else{ echo "<p>Please enter a search query</p>"; } } //connect to the database $con = mysql_connect("localhost","dbusrn","dbpwd"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydb", $con); $name = $_POST['name']; $result = mysql_query ("select * from Customer_Registration where Firstname like '%$name%' or lastname like '%$name%' "); $row = mysql_fetch_row($result); $cf_uid = $row[0]; $Firstname = $row[6]; $lastname = $row[7]; $Address = $row[8]; $Postcode = $row[9]; $Phone = $row[10]; $Email = $row[11]; $Customer_Type = $row[12]; $Computer_type = $row[13]; $Computer_maker = $row[14]; $Model = $row[15]; $OS = $row[16]; $Appointment_date = $row[17]; $Problem = $row[18]; $Solution = $row[19]; $Comment = $row[20]; ?> <form action="updatecus1.php" method="post"> <table width="100%" border="2" cellspacing="0" cellpadding="8"> <tr><td width="45%" class="FormText">Customer ID:</td> <td width="55%"><?php echo $cf_uid;?></td></tr> <tr><td width="45%" class="FormText">First name:</td> <td width="55%"><input name="Firstname" type="text" value="<?php echo $Firstname;?>"?> </td></tr> <tr><td width="45%" class="FormText">Last name:</td> <td width="55%"><input name="lastname" type="text" value="<?php echo $lastname;?>"?> </td></tr> <tr><td width="45%" class="FormText">Address:</td> <td width="55%"><input name="Address" type="text" value="<?php echo $Address; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Postcode:</td> <td width="55%"><input name="Postcode" type="text" value="<?php echo $Postcode; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Phone:</td> <td width="55%"><input name="Phone" type="text" value="<?php echo $Phone; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Email:</td> <td width="55%"><input name="Email" type="text" value="<?php echo $Email; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Customer:</td> <td width="55%"><input name="Customer_type" type="text" value="<?php echo $Customer_Type; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Computer :</td> <td width="55%"><input name="Computer_type" type="text" value="<?php echo $Computer_type; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Manufactural:</td> <td width="55%"><input name="Computer_maker" type="text" value="<?php echo $Computer_maker; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Model:</td> <td width="55%"><input name="Model" type="text" value="<?php echo $Model; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Operating System:</td> <td width="55%"><input name="First name" type="text" value="<?php echo $OS; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Appointment:</td> <td width="55%"><input name="Operating System" type="text" value="<?php echo $Appointment_date; ?>"?> </td></tr> <tr><td width="45%" class="FormText">Problem:</td> <td width="55%"><textarea name="Problem" rows="10" cols="20" ><?php echo $Problem; ?></textarea></td></tr> <tr><td width="45%" class="FormText">Solution:</td> <td width="55%"><textarea name="Solution" rows="10" cols="20" ><?php echo $Solution; ?></textarea></td></tr> <tr><td width="45%" class="FormText">Comment:</td> <td width="55%"><textarea name="Comment" rows="10" cols="20" ><?php echo $Comment; ?></textarea></td></tr> <td width="55%"><input name="submit" value="submit" type="submit" <br> <input type="Submit" value="Cancel"</br></td> </form> <?php -------------------------------------------------------------------------------------- The update.php file have the following code: Code: [Select] <?php //connect to the database $con = mysql_connect("localhost","dbusrn","dbpwd"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydb", $con); if (isset($_POST['submit'])) { $cf_uid = $_POST['cf_uid']; $Firstname = $_POST['Firstname']; $lastname = $_POST['lastname']; $Address = $_POST['Address']; $Postcode = $_POST['Postcode']; $Phone = $_POST['Phone']; $Email = $_POST['Email']; $Customer_Type = $_POST['Customer_Type']; $Computer_type = $_POST['Computer_type']; $Computer_maker = $_POST['Computer_maker']; $Model = $_POST['Model']; $OS = $_POST['OS']; $Appointment_date = $_POST['Appointment_date']; $Problem = $_POST['Problem']; $Solution = $_POST['Solution']; $Comment = $_POST['Comment']; $query = "UPDATE Customer SET Firstname='$Firstname',lastname='$lastname',Address='$Address',Postcode='$Postcode',Phone='$Phone',Email='$Email',Customer_Type='$Customer_Type',Computer_type='$Computer_type',Computer_maker='$Computer_maker',Model='$Model',OS='$OS', Appointment_date='$Appointment_date',Problem='$Problem',Solution='$Solution',Comment='$Comment' WHERE cf_uid='$cf_uid '"; mysql_query($query) or die(mysql_error()); mysql_close($con); echo "<p>Congrats Record Updated</p>"; } ?> I got congrats record updated but in actual fact no record are updated. Please help MOD EDIT: code tags added. Hello, i am having an issue when i try to go through multiple pages from a database. The database contains apartment information. I currently have it set to limit my results to 30 per page and this is working correctly, however when i try to scroll to page two like 1..2..3 i am displayed with every apartment listed in the database, and not the certain category that i would like selected. //assigning variables $SESuser_lng = $_COOKIE['SESuser_lng']; $SESuser_admlevel = $_COOKIE['SESuser_admlevel']; $id = $_GET['id']; $pgrow = $_GET['pgrow']; $msg = $_GET['msg']; $ht_filter = $_GET['ht_filter']; //sql query to retrieve result set $htfilter selects the distinct apartment categories $sqlFilter = ($ht_filter > 0 ? " WHERE p.idhotel = $ht_filter" : ""); $sql = "SELECT p.id, p.idhotel, p.nombre, p.thmb, p.archivo, h.nombre FROM prensa p LEFT JOIN hoteles h ON p.idhotel = h.id $sqlFilter ORDER BY p.nombre, h.nombre"; //DB_pager $nav = new DB_Pager('30'); $result = $nav->execute($sql, $dbcnx); //Javascript link creation <span id="display-links"><?php echo $nav->display_links(); ?></span> any help will be greatly appreciated Hi all Complete noob here..... What I have to do is create a new database every year, but I can't just import last years data completely, only records when needed. I can do it myself in PHPMyAdmin, but I don't want my employees touching mysql directly. What I am trying to do is write a php script that will serach for a reocrd in last years database and if it exists insert it into the new database if it doesn't exists bring up a form so it can be entered. Any help would be greatly appreciated. Thanx ZZ I created this database Code: [Select] <?php $mysqli = mysqli_connect('localhost', 'admin', 'jce123', 'php_class'); if(mysqli_connect_errno()) { printf("connection failed: %s\n", mysqli_connect_error()); exit(); }else{ $q = mysqli_query($mysqli, "DROP TABLE IF EXISTS airline_survey"); if($q){echo "deleted the table airline_survey....<br>";} else{echo "damm... ".mysqli_error($mysqli);} $sql = "CREATE TABLE airline_survey ( id INT NOT NULL PRIMARY KEY AUTO_INCREMENT, staff CHAR(10) NOT NULL, luggage CHAR(10) NOT NULL, seating CHAR(10) NOT NULL, clean CHAR(10) NOT NULL, noise CHAR(10) NOT NULL )"; $res = mysqli_query($mysqli, $sql); if($res === TRUE) { echo "table created"; } else { printf("Could not create table: %s\n", mysqli_error($mysqli)); } mysqli_close($mysqli); } ?> When I look at it it looks fine. I have a form that sends data to this script: Code: [Select] <?php $con = mysql_connect('localhost', 'admin', 'abc123'); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("php_class", $con); foreach ($_POST as $key => $value) { $staff = ""; $luggage = ""; $seating = ""; $clean = ""; $noise = ""; switch($key){ case "staff": $staff = $value; break; case "luggage": $luggage = $value; break; case "seating": $seating = $value; break; case "clean": $clean = $value; break; case "noise": $noise = $value; break; default: echo "we must be in the twilight zone"; } echo $staff."<br>"; [color=red] mysql_query("INSERT INTO airline_survey (staff, luggage, seating, clean, noise) VALUES ($staff, $luggage, $seating, $clean, $noise)");[/color] } ?> as you can see right before the insert query I test one of the variables to see if it has the string I'm expecting and it does. The problem is the script runs without giving me an error message but the data never gets inserted into the table. Code: [Select] <?php ob_start(); session_start(); $pagerank=2; if ($rank < $pagerank){ header('Location:main.php?id=lowrank.php'); } else{ $name1 = $_GET["name"]; $type2 = $_GET['type']; Echo "Your seach for ".$name1." gave the following results: "; $records_per_page = 15; $total = mysql_result(mysql_query("SELECT COUNT(*) FROM systems WHERE '$type2' LIKE '%$name1%'"), 0) or die(mysql_error()); $page_count = ceil($total / $records_per_page); Echo $total." Records Found"; echo "<table border=0>"; $page = 1; if (isset($_GET['page']) && $_GET['page'] >= 1 && $_GET['page'] <= $page_count) { $page = (int)$_GET['page']; } $skip = ($page - 1) * $records_per_page; $result = mysql_query("SELECT * FROM systems WHERE $type2 LIKE '%$name1%' ORDER BY Security DESC LIMIT $skip, $records_per_page") or die(mysql_error()); echo "<table border=1>"; echo "<td>System Name</td><td>Security</td><td>Class</td>"; while ($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td valign =top>".$row['System Name']."</td>"; echo "<td valign =top>".round($row['Security'],1)."</td>"; echo "<td valign =top>".$row['System Type']."</td>"; echo "</tr>"; } echo "</table>"; echo "<br>"; for ($i = 1; $i <= $page_count; ++$i) { echo '<a href="main.php?id=' . $_GET['id'] .'&name='.$name1.'&type='.$type1. '&page=' . $i . '">' . $i . '</a> '; } } ?> The above code takes data entered in a form and is suppose to show the matching results, but no records are showing, it works when I replace the $name1 and $type2 with the actual values, any ideas? I have a problem . I 've been trying for a long time to make an update for php mysql to change the data. but every time I do not manage to make it work with a form. but it works if I only if I put this ($ sql = "UPDATE users SET username = 'value' WHERE id = 10 " ; ) so it only works when I put the value of the id. but I want in an html form to indicate what I want to change and what id goes. but I have tried so long that I do not feel like I so want someone help me. make the same database and same as my records and make the code and test it if it works show me please my database name : web test my table called : users my records are called : id int ( 11) AUTO_INNCREMENT username , varchar ( 255 ) password , varchar ( 255 ) first_name , varchar ( 255 ) last_name , varchar ( 255 ) email, varchar ( 255 ) Age, int ( 11) Look, my update.php is like this now <?php $servername = "localhost"; $username = "root"; $password = "....."; $dbname = "webtest"; $conn = new mysqli($servername, $username, $password, $dbname); if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "UPDATE users SET password='cotton candy' WHERE id=10"; if ($conn->query($sql) === TRUE) { echo "Record updated successfully"; } else { echo "Error updating record: " . $conn->error; } $conn->close(); ?> but now i have still have to go into the php file to change the valeu or the id but i looked on site and youtube how to put it in a simple html form but it still does not work. i want it in a html from. I want that when I enter the ID that the data of the user appears and that I can change any valeu separately. This is the form that I'm using and it populates just fine but when you make the changes I can't figure out how to get it to update each record in my database. Code: [Select] <table width="100%" cellspacing="1" cellpadding="2" border="0"> <form action="<?php echo $_SERVER["PHP_SELF"] . "?update=1"; ?>" method="post"> <tr> <td><b>Category Name</b></td> <td><b>Category Description</b></td> <td><b>Order</b></td> <td align="right"><input type="submit" value="Update"></td> </tr> <?php read_cat_list($cat); for ($i = 0; $i < $cat["count"]; $i++) { echo "<tr>\n"; echo "<td width=\"30%\" valign=\"top\"><input type=\"text\" name=\"cat_name_" . safe_string($cat[$i]["cat_id"]) . "\" size=\"30\" maxlength=\"250\" value=\"" . safe_string($cat[$i]["cat_name"]) . "\"></td>\n"; echo "<td width=\"36%\" valign=\"top\"><textarea name=\"cat_desc_" . safe_string($cat[$i]["cat_id"]) . "\" rows=\"2\" cols=\"30\">" . safe_string($cat[$i]["cat_desc"]) . "</textarea></td>\n"; echo "<td width=\"10%\" valign=\"top\"><input type=\"text\" name=\"cat_order_" . safe_string($cat[$i]["cat_id"]) . "\" size=\"3\" maxlength=\"3\" value=\"" . safe_string($cat[$i]["cat_order"]) . "\"></td>\n"; echo "<td width=\"24%\" valign=\"top\">[ <a href=\"#\" onmouseover=\"window.status = 'Delete " . safe_string($cat[$i]["cat_name"]) . "'; return true;\" onmouseout=\"window.status = ''; return true;\" onclick=\"javascript:del_cat(" . $cat[$i]["cat_id"] . ", '" . safe_string($cat[$i]["cat_name"]) . "'); return false;\">Delete</a> ]</td>\n"; echo "</tr>\n"; } ?> <tr> <td colspan="4" align="right"><input type="submit" value="Update"></td> </tr> </form> </table> the safe_string function just cleans up the output/input from the database, This next block is my form processor for this form. Code: [Select] <?php function update_cats($vars) { $err = ""; #if ($SESSION["level"] != ADMIN) { # $err = ERR_NOT_ENOUGH_ACCESS; #} else { $temp = array_keys($vars); for ($i = 0; $i < count($temp); $i++) { if (substr($temp[$i], 0, 9) == "cat_name_") { if ($vars[$temp[$i]] == "") { $err = "Category names cannot be blank."; break; } else { $name_query["cat_name"] .= substr($temp[$i], 9) . ", "; } } } for ($i = 0; $i < count($temp); $i++) { if (substr($temp[$i], 0, 9) == "cat_desc_") { $desc_query["cat_desc"] .= substr($temp[$i], 9) . ", "; } } for ($i = 0; $i < count($temp); $i++) { if (substr($temp[$i], 0, 10) == "cat_order_") { if ($vars[$temp[$i]] == "") { $err = "Category orders cannot be blank."; break; } else { $order_query["cat_order"] .= substr($temp[$i], 10) . ", "; } } } #} if (!$err) { if ($name_query["cat_name"]) { $update_name_query = "update category"; $update_name_query .= " set cat_name = '" . $name_query["cat_name"] . "'"; $update_name_query .= " where cat_id in (" . substr($name_query["cat_name"], 0, -2) . ")"; update_db($update_name_query); } if ($desc_query["cat_desc"]) { $update_desc_query = "update category"; $update_desc_query .= " set cat_desc = '" . $name_query["cat_desc"] . "'"; $update_desc_query .= " where cat_id in (" . substr($desc_query["cat_desc"], 0, -2) . ")"; update_db($update_desc_query); } if ($order_query["cat_order"]) { $update_order_query = "update category"; $update_order_query .= " set cat_order = '" . $name_query["cat_order"] . "'"; $update_order_query .= " where cat_id in (" . substr($order_query["cat_order"], 0, -2) . ")"; update_db($update_order_query); } } return $err; } ?> update_db is my database caller, if you need any of the functions that I use that are not here please post back and tell me. now when I process the form all my fields change to this: cat_name: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, cat_desc: cat_id: 0 for all the records in the database table, I'm just trying to update each record with the values it needs Here is my database table with the data. Code: [Select] CREATE TABLE `category` ( `cat_id` int(11) NOT NULL AUTO_INCREMENT, `cat_name` varchar(255) NOT NULL, `cat_desc` text NOT NULL, `cat_order` int(11) NOT NULL, PRIMARY KEY (`cat_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=16 ; -- -- Dumping data for table `category` -- INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(1, 'Hand Tossed Pizza', '', 1); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(2, 'Hand Tossed Specialty Pizzas', '', 2); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(3, 'Chicago Style Deep Dish', '', 3); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(4, 'Specialty Chicago Style Deep Dish', '', 4); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(5, 'Chicken Wings & Tenderloins', '', 5); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(6, 'Hot Sides', '', 6); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(7, 'Hot Sandwiches', '', 7); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(8, 'Cold Sandwiches', '', 8); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(9, 'Pastas', '', 9); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(10, 'Fresh Salads', '', 10); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(11, 'Fresh Breads', '', 11); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(12, 'Soups', '', 12); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(13, 'Kids Menu', '', 13); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(14, 'Drinks', '', 14); INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(15, 'Desserts', '', 15); Hope I have provided plenty of info on what I got and what I need for it todo Thanks hello every body...
two
I'm creating an IPN in paypal for my membership site but the problem I'm facing is that on successfull verification of the purchase, four rows are getting inserted in the database...
The code is
<?php require '../db.php'; $paypalmode = '.sandbox'; $req = 'cmd=' . urlencode('_notify-validate'); foreach ($_POST as $key => $value) { $value = urlencode(stripslashes($value)); $req .= "&$key=$value"; } $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, 'https://www'.$paypalmode.'.paypal.com/cgi-bin/webscr'); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_POSTFIELDS, $req); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2); curl_setopt($ch, CURLOPT_HTTPHEADER, array('Host: www'.$paypalmode.'.paypal.com')); $res = curl_exec($ch); curl_close($ch); if (strcmp ($res, "VERIFIED") == 0) { $transaction_id = $_POST['txn_id']; $payerid = $_POST['payer_id']; $firstname = $_POST['first_name']; $lastname = $_POST['last_name']; $payeremail = $_POST['payer_email']; $paymentdate = $_POST['payment_date']; $paymentstatus = $_POST['payment_status']; $mdate= date('Y-m-d h:i:s',strtotime($paymentdate)); $otherstuff = json_encode($_POST); $date = date("y-m-d"); $q = $pdo->connect()->query("INSERT INTO payment (mid,username,amount,paypal_id,txn_id,received_date) VALUES('{$_SESSION['user_id']}','{$_SESSION['uname']}','{$_POST['mc_gross']}','{$_POST['payer_email']}','{$_POST['txn_id']}','$date')"); $q->execute(); $q1 = $pdo->connect()->query("UPDATE members SET amount_loaded = amount_loaded + {$_SESSION['amount']} WHERE mid = '{$_SESSION['user_id']}'"); $q1->execute(); //header("Location: funds.php"); echo "verified"; } ?>two for the payment and in the members table, the amount is getting doubled. (i.e if anybody purchases For $2, it shows $4 in the database....) Any help will be really appreciated... Hi, I have contact form in my website project. Users fill First name ,Last Name ,Email etc information. I do not want to create database and table to store this information. I want to store this information in XML file. When user will add information then information will be added in XML file. Any solution for this ? - Thanks Hi. When a record is added its done via a form and processed via inserts.php. I need to use the same form but to recall the data (by id) so it can be editted. Cant work it out though. Help would be well appreciated! edit.php: <CENTER><B>Update a Vehicle</B></CENTER> <BR> <?php $query="SELECT * FROM cars"; $result=mysql_query($query); $i=0; while ($i < $num) { $carname=mysql_result($result,$i,"CarName"); $cartitle=mysql_result($result,$i,"CarTitle"); $carprice=mysql_result($result,$i,"CarPrice"); $carmiles=mysql_result($result,$i,"CarMiles"); $cardesc=mysql_result($result,$i,"CarDescription"); ?> <form action="showroomedit.php" method="post"> <CENTER>Vehicle Name:</CENTER> <CENTER><input type="text" name="CarName" value="<?php echo $carname; ?>"></CENTER> <br> <CENTER>Vehicle Type:</CENTER> <CENTER><input type="text" name="CarTitle" value="<?php echo $cartitle; ?>"></CENTER> <br> <CENTER>Vehicle Price:</CENTER> <CENTER><input type="text" name="CarPrice" value="<?php echo $carprice; ?>"></CENTER> <br> <CENTER>Vehicle Mileage:</CENTER> <CENTER><input type="text" name="CarMiles" value="<?php echo $carmiles; ?>"></CENTER> <br> <CENTER>Vehicle Description:</CENTER> <CENTER><textarea name="CarDescription" rows="10" cols="30" value="<?php echo $cardesc; ?>"></textarea></CENTER> <br> <CENTER><input type="Submit"></CENTER> </form> </TD> cant work out why it isnt working... Code: [Select] <?php require "db/config.php"; $fname = $_POST['fname']; $lname = $_POST['lname']; $country = $_POST['country']; $state = $_POST['state']; $city = $_POST['city']; $zcode = $_POST['zcode']; $address = $_POST['address']; $ppemail = $_POST['ppemail']; $pnumber = $_POST['pnumber']; $cemail = $_POST['cemail']; $url = $_POST['url']; $price = "$5.00"; $query = "INSERT INTO custpackage1000( id, FirstName, LastName, Country, State, City, ZipCode, Address, PayPalEmail, PhoneNumber, PrimaryEmail, WebsiteURL) VALUES ( '1', '$fname', '$lname', '$country', '$state', '$city', '$zcode', '$ppemail', '$pnumber', '$cemail', '$url')"; mysql_connect($host, $user, $pass) or die("<br /><br /><h1>Fatal error. Please contact support if this persists.</h1>"); mysql_select_db($dbname); mysql_query($query) or die ("could not open db".mysql_error()); sleep(2); ?> Why won't the code insert into my database upon submission of data? What am I doing wrong? First of all excuse me if this topic is inappropriate in this forum. But I think it's rather a PHP problem. I can't figure out multiple duplicate database records on submitting a form. The database table have two columns: the first one 'Id' with AUTO_INCREMENT and the second one 'Name'. Here's the php code for database insertion and the form: ------------------------------------------------------------------ <?php if($_GET['add_name']){ $host = *******; $user = *******'; $pass = *******; $db = *******; $con = mysql_connect($host,$user,$pass) or die; mysql_select_db($db,$con); $name = $_GET['add_name']; $sql = "INSERT INTO names (Name) VALUES ('$name')"; mysql_query($sql); } ?> <form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="GET"> Your Name: <input name="add_name" type="text" /> <input type="submit" value="Submit" /> </form> ------------------------------------------------------------------ After submitting the form to itself once I have multiple Name entries with different Ids. The curious thing is that with Chrome browser I get two duplicate records, with Mozilla - three of them. Seems like mysql_query runs multiple times. It works fine when submitting the form to a separate script and not to itself. Do I miss something? It must be very basic. I am having trouble showing reports for a given date range. Currently if I specify something like 11/03/2010 to 11/05/2010 I get results for all years within that month and day such as I may get results for 11/03/2008 11/03/2009 11/03/2010 11/04/2008 11/04/2009 11/04/2010 11/05/2008 11/05/2009 11/05/2010. I am using the following code $result = mysql_query("SELECT * FROM report WHERE date>='$date_begin' and date<='$date_end' ORDER BY 'date'",$db); I use the following format in my date feild mm/dd/yyyy My script is finally working as intended, but I want to add some additional data results. I am trying to resolve how I can display a count of ONLY the records updated by my query: // START :: Query to replace matches mysql_query("UPDATE orig_codes_1a AS a JOIN old_and_new_codes_1a AS b ON concat(a.orig_code_1, a.orig_code_2) = concat(b.old_code_1, b.old_code_2) SET a.orig_code_1 = b.new_code_1, a.orig_code_2 = b.new_code_2") or die(mysql_error()); // END :: Query to replace matches In this query I count ALL records selection: // START :: Create query to be displayed as final results of original codes table. $result = mysql_query("SELECT * FROM orig_codes_1a") or die(mysql_error()); I want to display a count on this part of the query: ....concat(a.orig_code_1, a.orig_code_2) = concat(b.old_code_1, b.old_code_2).... Hi all, I am currently returning candidates from a database initially just by the highest candidate id to the lowest... i.e. newest candidates to oldest. I have introduced a sort feature which works just fine, the problem is I am displaying my results over a few pages using pagination. The problem arises once I sort my results and then try to click onto the next page of results. Basically it is just resetting the sort as the sort relies on a button being pressed, which obviously isn't happening when the user is trying to get the next page of results. I'm not sure exactly which section of code would be relevant to this so I have posted the whole script... additionally if you need to take a look at it in action you can do so he http://www.beta.teachingagencies.co.uk/search_jobseekers.php As I say I know the problem is that when the page is changed the value is lost, but I don't have a clue how to solve the problem! Any help or advice would be appreciated. Many thanks, Greens85 I know this problem comes up a lot but it can be for various reasons so after reading up I can't decide what might be wrong. I'm still learning! I have a simple php registration form (first name, second name, email address) and every time a user submits an entry a second blank record is created in the MYSQL database after it. Any help would be great. (php code in red) Code: [Select] [color=red]<? $firstname=$_POST['firstname']; $surname=$_POST['surname']; $email=$_POST['email']; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query = "INSERT INTO register VALUES ('','$firstname','$surname','$email')"; mysql_query($query); mysql_close(); ?>[/color] Here is the section on the html HTML page that submits the form Code: [Select] <form action="register.php" method="post" class="BagTitle"> <table width="700" border="0" cellpadding="0" cellspacing="2"> <tr> <td width="100">First Name: </td> <td width="594"><input name="firstname" type="text" size="50" /></td> </tr> <tr> <td>Last Name: </td> <td><input name="surname" type="text" size="50" /></td> </tr> <tr> <td>E-mail:</td> <td><input name="email" type="text" size="50" /></td> </tr> <tr> <td colspan="2"> </td> </tr> <tr> <td colspan="2"><input type="Submit" value="Send" /> <input name="Reset" type="reset" value="Reset Form" /></td> </tr> </table> </form></p> Also I have no idea about securing this information. Are there any basic steps I can take? Hey, Im needing some help with an update form that I have created using PHP/MySQL. Basically the form is working great (updating records, retrieving records and showing errors) but there is a problem with the errors. If there are no errors and I edit the existing text input values, the database updates fine. However if I edit the existing text input values and there is an error, the edited input values dont save, they revert back to the values of the database. I understand why this is happening, its because the text inputs are set to show the values of the database so if i edit the existing values and an error occurs or the page is refreshed, the values revert back to the database values. However id like it so that if any text in the text field have been edited and an error occurs, the text stays to how it is until the user by passes any errors and then the database is updated. Hopefully this makes sense. I have attached the php page just incase anybody wants to look into it but any help would be much appreciated! Also, im not looking for someone to just to fix this for me but if someone knows my problem and can guide me in the right direction, that would be great. Hey, i have a script in my game that picks up the output rate of a unit which if there is more than one unit it devides, i have 3 teams and the script picks up team 1 and 2, but any units in team 3 the rate shows 0? IE HEAVY SOLDIER 100% but with the 3rd team its always showing 0% Code: [Select] <font face="Verdana" color="#000000" size="2"><b>Output Rate</b></font></td></tr>'; $sql = "SELECT id,name FROM units WHERE class={$row[0]} AND visible=1"; $r2 = mysql_query($sql); while ($row2 = mysql_fetch_row($r2)) { echo '<tr><td align="center">'.$row2[1].'</td><td align="center"><input text="text" size="5" style="'.$boxStyle.'" name="a'.$row2[0].'" value='.getRate($userid,$row2[0]).'>%</td></tr>'; } echo '<tr><td colspan="2" align="center"><input type="submit" value="Set Rates for '.$row[1].'"></td></tr>'; echo '</table></form>'; } echo '</center>'; DB's Code: [Select] FOR UNITS. id name toground toair hp class evolvesto style cost visible 6 Mulanix 10 10 200 3 0 1 20 1 5 Numani 5 5 100 3 6 1 10 1 any help would be great it's annoying me and i can't solve it. Hi, if someone could assist me, it would be much appreciated. I have a database website. I generated it using AppGini. Unfortunatly, they haven't answered my emails. What I'm trying to do is change my database to not dynamically load the selected record, but to instead load the direct URL to the record. (Here is the website address: http://2g2egkxd3.site.aplus.net/updates/bad_view.php) If you hover above the record, you will see the full URL for that record. Example: http://2g2egkxd3.site.aplus.net/updates/bad_view.php?SelectedID=Buck%20Allen But when you click it, it doesn't load that URL into the browser. I'm guessing it dynamically loads it into the page. The reason I'm trying to do this is because I want to have a social/comment system for each record/prospect and it won't work if the record is dynamically loaded. |