PHP - With Ajax, Opening A Php Function On The Same Page Without Jquery.

$('table td').click(function() { //user clicks a table cell
      alert($(this).index()); //test case returns '9'
      $.ajax({
        url: "update.php",
        type: "POST",
        data: {
          action: 'clicked',
          clicked: $(this).index(), //the column that was clicked
          row: $(this).parent().attr('id').substr(4) //the row that was clicked (tr has an ID attribute like "row22")
        }
      })
      .complete(function(data) {
        alert($(this).index()); //test case should return '9', but returns '-1' instead.
        console.log(data.responseText); //console gets the assigned id from a database insert -- works fine.
        $(this).attr('id','ros'+data.responseText); //doesn't work. did .complete forget what $(this) is?
      });
}

Hello all

I have a php and jquery/ajax call I am using to create a file/send an email. I get all the contents from my textboxes but I want a message to display on the screen afterwards being success or fail. In my .ajax call My call is exiting right before the ‘success:’  part. Why is my call not succeeding? Any tips/help will be appreciated

Thank you

Html page just a form with a submit button
$(document).ready(function () {
    var form = $("#formData");
    
    $(form).on("submit", function (event) {
        event.preventDefault();
        $.ajax({
            type: "post",
            url: "file.php",
            data: $(this).serialize(),
            beforeSend: function () {
                $("#status").html('<span style="color:red;">Loading everything actually creating a .TXT file of contents...</span>')  //--works
            },
            success: function (data) { 
                var responseMsgType = "alert-" + data.type;
                var responseMsgText = data.message;
                // message below
                var alertBox = '<div class="alert ' + responseMsgType + ' alert-dismissable"><button type="button" class="close" ' +
                    'data-dismiss="alert" aria-hidden="true">&times;</button>' + responseMsgText + '</div>';
                if (responseMsgType && responseMsgText) {
                    $(form).find(".successArea").html(alertBox);
                    $(form)[0].reset();
                }
            }
        });
        return false;
    });
<?php
$controls = array('txtName' => 'Name', 'txtEmail' => 'Email', 'txtSubject' => 'Subject', 'txtMessage' => 'Message');
try {
	if(count($_POST)==0) { throw new \Exception ('Contact Form Message is empty'); }

	$headers = array('Content-Type: text/plain; charset="UTF-8";',
					 'From: ' . $email,
					 'Reply-To: ' . $email,
					 'Return-Path: ' .$email);

	$emailMessage = "You have a new message from your contact form" . PHP_EOL;
	$emailMessage .= "-------------------------------------------------------" . PHP_EOL;

	foreach($_POST as $key => $value){
        if(isset($controls[$key])) {
            $emailMessage .= "$controls[$key]: $value". PHP_EOL;
        }
    }
$mailMsg = "email6.txt";
	if(file_exists($filename) == false) {
		$fh = fopen($mailMsg, "w");
		fwrite($fh, $headers);
		fwrite($fh, $emailMessage);
		fclose($fh);
	} else {
		$fhexists = fopen($filename, "a");
		fwrite($fhexists, $content);
		fclose($fhexists);
	}

	$responseMessage = array("type" => "success", "message" => $successMessage);
}
catch (\Exception $ex) {
	$responseMessage = array("type" => "errorM", "message" => $errorMessage);
}
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
	$encodedJSON = json_encode($responseMessage);
	header("Content-Type: application/json");
	echo $encodedJSON;
} else {
	echo $responseMessage["message"];
}

I have a form with dropdown list that is populated with values from Sql Server table. Now i would like to use this selected item in SQL query. The results of this query should be shown in label or text field. So when a user selects item from dropdown menu, results from SQL query are shown at the same time.

I have two dropdown list at the moment in my form. First one gets all values from a column in table in SQL Server. And the second one should get a value from the same table based on a selection in first dropdown list.

When i load ajax.php i get 2 error mesages: 
Notice: Undefined index: machinery in C:\wamp64\www\gecko\ajaxfile.php on line  *8*
Warning: sqlsrv_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp64\www\site\ajaxfile.php on line  *16*

This is my code so far. I have tried to do it with this Ajax script. But i can only get first dropdown to work. The second dropdown(sub_machinery) does not show values, when first dropdown item is selected. The second dropdown should show values from databse table with this query( *$machineryID*  is first dropdown selected item): SELECT MachineID FROM T013 WHERE Machinery=".$machineryID.

Index.php

    <!doctype html>
      <?PHP
    $server = "server";
    $options = array(  "UID" => "user",  "PWD" => "pass",  "Database" => 
    "database");
    $conn2 = sqlsrv_connect($server, $options);
    if ($conn2 === false) die("<pre>".print_r(sqlsrv_errors(), true));
    echo " ";
    ?>
    <html>
    <head>
    <meta charset="utf-8">
    <title>Untitled Document</title>
    </head>
    
    <body>
                <section id="formaT2" class="formaT2 formContent">
                <div class="row">
                    <div class="col-md-2 col-3 row-color remove-mob"></div>
                    <div class="col-md-5 col-9 bg-img" style="padding-left: 0; 
    padding-right: 0;">
                        <h1>Form</h1>
                        <div class="rest-text">
                           <div class="contactFrm">
                              <p class="statusMsg <?php echo 
    !empty($msgClass)?$msgClass:''; ?>"><?php echo $statusMsg; ?></p>
                               
                                <form action="connection.php" method="post">
                                    <div>machinery</div>     
    <select id="machinery">
       <option value="0">--Please Select Machinery--</option>
       <?php 
       // Fetch Department
       $sql = "SELECT Machinery FROM T013";
       $machanery_data = sqlsrv_query($conn2,$sql);
       while($row = sqlsrv_fetch_array($machanery_data) ){
          $id = $row['Id'];
          $machinery = $row['Machinery'];
          
          // Option
          echo "<option value='".$id."' >".$machinery."</option>";
       }
       ?>
    </select>
    <div class="clear"></div>
                                    <div>Sub Machinery</div>
    <select id="sub_machinery">
       <option value="0">- Select -</option>
    </select>
                                    
                                    <input type="submit" name="submit" 
    id="submit" class="strelka-send" value="Insert">
                                    <div class="clear"> </div>
                                </form>
                             </div> 
                         </div>
                    </div>
                </div> 
            </section>
             </script>
          <script type="text/javascript">
          $(document).ready(function(){

        $("#machinery").change(function(){
            var machinery_id = $(this).val();
    
            $.ajax({
                url:'ajaxfile.php',
                type: 'post',
                data: {machinery:machinery_id},
                dataType: 'json',
                success:function(response){
    
                    var len = response.length;
     
                    $("#sub_machinery").empty();
                    for( var i = 0; i<len; i++){
                        var machinery_id = response[i]['machinery_id'];
                        var machinery = response[i]['machinery'];
                        
                        $("#sub_machinery").append("<option 
    value='"+machinery_id+"'>"+machinery+"</option>");
    
                    }
                }
            });
        });
    
    });
          </script>
    </body>
    </html>

Ajaxfile.php

<?php
    $server = "server";
    $options = array(  "UID" => "user",  "PWD" => "pass",  
    "Database" => "database");
    $conn2 = sqlsrv_connect($server, $options);
    if ($conn2 === false) die("<pre>".print_r(sqlsrv_errors(), true));
    echo " ";

    $machineryID = $_POST['machinery'];   // department id

    $sql = "SELECT MachineID FROM T013 WHERE Machinery=".$machineryID;
    
    $result = sqlsrv_query($conn2,$sql);
    
    $machinery_arr = array();
    
    while( $row = sqlsrv_fetch_array($result) ){
        $machinery_id = $row['ID'];
        $machinery = $row['MachineID'];
    
        $machinery_arr[] = array("ID" => $machinery_id, "MachineID" => 
    $machinery);
    }
    
    // encoding array to json format
    echo json_encode($machinery_arr);
    ?>

The Business Logic is: If product is already purchased, upgrade the product

I have a customer input form to get information, along with some fields which should be auto populated based on what the customer chooses.

Screen Shot:

    https://i.stack.imgur.com/Fkyim.png
Note: Price and Shipping Weight are done with Ajax,

When we come to the shipping cost I am getting it from Magento, using a PHP function.

form :

     https://paste.ofcode.org/335FVUhpBGbazQtrcPLVQUs
PHP :

sp_cost.php

     https://paste.ofcode.org/hvG2sP9TW9CEPgMMuKXNuw
From the above code I am given the predefined value,

$results = getShippingEstimate('14419','1',"IN","642001");

How can i get country and zipcode from the user entry and return the shipping cost?