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PHP - Specified/shared Url Parameters
Not experienced coding PHP and need help doing something which is probably very easy but looks like Mt Everest to me. FOO = 123456 BAR = abc Then, write URLs with those variables and have them work the same in a browser:
http://webpage1.com/?var1=FOO&var2=BAR
http://webpage2.com/?var1=FOO&var2=BAR
http://webpage3.com/?var1=FOO&var2=BAR If I update the fields in my local webpage and refresh browser, would like the new value(s) to be used instead. Any help with this greatly appreciated. If someone will put a file together think that I can edit and modify from there for my specific application. Thank you. Edited December 1, 2020 by XcloneSimilar TutorialsI am calling CURL and trying to do a POST request with parameters: Code: [Select] $curl = curl_init(); curl_setopt($curl, CURLOPT_HTTPHEADER, Array("Accept: application/json", "Content-Type: application/json")); curl_setopt($curl, CURLOPT_CONNECTTIMEOUT, 15); curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, true); curl_setopt($curl, CURLOPT_USERAGENT, "curl 7.23.1 (x86_64-unknown-linux-gnu)"); curl_setopt($curl, CURLOPT_USERPWD, "username:password"); curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); curl_setopt($curl, CURLOPT_URL, "https://www.mydomain.com/route"); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, "key1=blah1&key2=blah2"); return curl_exec(curl); The problem, inside the request at http://www.mydomain.com/route I am not seeing any POST parameters passed. I.E. Code: [Select] print_r($_POST); Code: [Select] Array ( ) Should have key1=blah1 and key2=blah2. Any ideas? I have some function or method. Is there a better design patter to implement this?
function myFunction($a=null,$b=null,$c=null,$d=null,$e=null,$f=null,$g=null,$h=null)
{
//Do a bunch of stuff
}
Maybe the second function?
function myNewFunction($data=array())
{
$data=array_merge(array('a'=>null,'b'=>null,'c'=>null,'d'=>null,'e'=>null,'f'=>null,'g'=>null,'h'=>null),$array);
//Do a bunch of stuff
}
Please provide decision making factors why you would use one approach over the other.
Hello - I have usually run my own servers, and always drop my .php files with MYSQL connection strings in a directory like /var, with webroot being /var/www/mysite. I now find myself in a shared hosting environment for a client and wondering the safety of my connection string .php files. Unfortunately they are sitting in a folder in the root of my hosting directory right now, and they feel vulnerable. It seems the only thing I could do would be to put the root of my hosting into a subdirectory, point the site there, and then put my connection strings on directory back. But seems the problem is they are still in my shared hosting. What's the best way to secure this type of sensitive info in a shared environment? I'm also getting ready to explore credit card processing via an API, and wondering if shared hosting is even worth it. Thanks!! Ok here it is, seems like it is an easy problem but my developers are having some issue with this, I hope you guys can help. Basic question and answer problem, where I am developing a website that uses Items and questions like " How many of this Item do you need?" the answer seems to simple. Lets say the answer Is "1". The display is given to the Item list and we move on. Here is the Problem: When selecting Muiltiple Items in the List and they all have the same question associated to each Item: "How Many Items do you need?" the the answer is shared between the Items, Again, sounds simple so far, However, when the USER selects Multiple Items on a list say 30 Items then the Question should only be dispalyed one time, not 30 times, then the answer is shared 30 times. Thats what I have now being displayed on my website, 30 of the same questions over and over again. The USER will get frustrated and leave the site never to return. Question: How can I get the Question to be displayed only once, but shared between several items on a list? This is a very serious problem fo my website because I will have not have just one Item on a list but 300 to 400 items, and if I get the answer to the problem I have just wasted 1 year of my life developing something undevelopable (is that a word?). Any Help you can give me would greatly be appricated. Thank you in advance. I have one array, called for example $MainImages : - Code: [Select] Array ( [0] => Array ( [widgetID] => 143 [image] => image_a.jpg ) [1] => Array ( [widgetID] => 147 [image] => image_b.jpg ) [2] => Array ( [widgetID] => 73 [image] => image_c.jpg ) ) and a second array, we'll call it $widgets: - Code: [Select] Array ( [0] => Array ( [widgetID] => 147 [seo_title] => An excellent class B Widget [name] => Widget B [categoryID] => 1 ) [1] => Array ( [widgetID] => 73 [seo_title] => An excellent class C Widget [name] => Widget C [categoryID] => 1 ) [2] => Array ( [widgetID] => 143 [seo_title] => An excellent class A Widget [name] => Widget A [categoryID] => 1 ) ) I want to merge the value from the [][image] key from the first array into a new [][image] key / value in the second, using a shared value as a reference...so the desired result array is: - Code: [Select] Array ( [0] => Array ( [widgetID] => 147 [seo_title] => An excellent class B Widget [name] => Widget B [categoryID] => 1 [image] => image_b.jpg ) [1] => Array ( [widgetID] => 73 [seo_title] => An excellent class C Widget [name] => Widget C [categoryID] => 1 [image] => image_c.jpg ) [2] => Array ( [widgetID] => 143 [seo_title] => An excellent class A Widget [name] => Widget A [categoryID] => 1 [image] => image_a.jpg ) ) Obviously the order is different and so they need to be merged based on the widgetID values. Also, the same widgetID may be in each array more than once. I've looked at a lot of help but can't find anything to do exactly what I need....any help would be greatly appreciated! I am on a shared hosting server running CentOS. I have copied a PHP extension (imagick.so) that was built on similar server to my shared hosting server. I have resolved most of the dependencies by placing the missing files in ~/lib but I have one that I can't figure out how to cope with. I am getting the following error: Hi,
I'm newbie. My requirement is to open network shared folder from PHP.
This works fine in IE but not in Chrome.
Can anyone please help me ....
Thanks
Hi,
I would like to ask if someone knows a trick to know if the script is running on a shared hosting or a vps or a dedicated server.
Regards
Hi, I have Code: [Select] $to = 'rberbe2002@msn.com'; $subject = 'the subject'; $message = 'hello'; $headers = 'From: webmaster@example.com'; mail($to, $subject, $message, $headers); which works fine on a shared hosting website I have, but not on a website I have on my dedicated server. Any ideas or suggestions please? Hi all i was wondering if someone knows a way to make sure an image which is uploaded isn't infected by a virus. I have read about avclam, but if your on a shared host your mostly not allowed to add own software. Isn't there maybe a php trick to resize the image which would magically remove a virus? If anyone knows a nice way or tricks to limit the virus breating space to a certain folder please let me know. This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=317008.0 I implemented google's reCAPTCHA V2 on http:// on the remote apache shared server and it worked 100%. I then changed the protocol to my shared server SSL using the same PHP script as the non-SSL script. The older version of reCaptcha had an SSL 'false' to 'true' SSL parameter, whereas I can't find one for V2. I had to use htaccess to redirect the example.com to the shared SSL server https://serverid.net/example/ which works perfectly without recCAPTCHA. I incorporated reCAPTCHA V2 and the error message where the reCAPTCHA image should be shows "ERROR: Invalid domain for site key". Hey, friends. I have some trouble on the server front. My sites have been hacked, and I need to make sure I've eradicated every trace of this exploit. I'm looking for a way to search for any and all php files contained in multiple directories with specific names. For instance, I have found a commonality in relation to where these malicious files are placed, such as: Code: [Select] /some/dir/img/somename.phpor: Code: [Select] /some/dir/js/somename.php Is there a way I can easily (e.g. using ssh and the "find" command) locate all files ending in php but only found in directories named "img"? I can't seem to find anything that would allow me to do this with find, or with a combination of find and grep. I can't go directory by directory, as some of these img directories are created many levels deep, some even in .svn directories. Any and all help is appreciated. Hackers suck. Hi, I develop some functions in PL/SQL and PL/PgSQL. In these languages are IN and OUT parameters in Functions and Store Procedures. There is IN and OUT parameters in PHP Functions? Sorry my bad english. Best Regards, Hello all, I'm kind of a noob to PHP, and as such have been teaching myself the language. I'm attempting to insert tag attributes in divs, based on whether the site is viewed in IE or Firefox, to account for subtle differences in appearance. The problem, however, is that the variable $boxorlink apparently has the value "box" the second time I call the method, even though I explicitly state "other" as the parameter; the else clause is never reached. If anybody could tell me why this is happening, please let me know. My entire HTML code is below... <html> <head> <style type ="text/css"> html { background-image:url('denim.jpg'); } .wrapper { min-width:600px; width:600px; height:800px; position:fixed; } .headertext { font-weight:bold; color:#FFFFFF; font-size:24pt; font-family:sans serif; text-shadow: 0.1em 0.1em #333 } .miniheadertext { font-weight:bold; color:#FFFFFF; font-size:16pt; font-family:sans serif; text-shadow: 0.1em 0.1em #333 } div.transbox { width:750px; height:180px; margin:30px 50px; border-style:solid; border-color:#c0c0c0; background-color:#000000; /* for IE */ filter:alpha(opacity=30); /* CSS3 standard */ opacity:0.3; } div.currentpagelink { width:90px; height:22px; margin:30px 50px; background-color:#c0c0c0; font-color:#FFFFFF; font-weight:bold; font-size:14pt; font-family:sans serif; text-align:center; /* for IE */ filter:alpha(opacity=40); /* CSS3 standard */ opacity:0.4; } } div.otherpagelinks { width:100px; height:50px; font-size:14pt; font-family:sans-serif; } </style> <title> Marvin Serrano's Online Portfolio </title> <?php function checkBrowser($boxorlink, $left, $top, $displaceleft, $displacetop) { //new positions for Firefox $newleft = $left + $displaceleft; $newtop = $top + $displacetop; //positions for links... $newlinkleft = $left - $displaceleft; $newlinktop = $top - $displacetop; //checks for box on top or links; links have to be certain % from top. if ($boxorlink = 'box') { if (strpos($_SERVER['HTTP_USER_AGENT'],'MSIE') !== FALSE) { echo('left:'.$left.'%'); } else { echo('left:'.$newleft.'%'); } } elseif ($boxorlink = 'other') { if (strpos($_SERVER['HTTP_USER_AGENT'],'MSIE') !== FALSE) { echo('left:'.$left.'%;'.'top:'.$top.'%'); } else { echo('left:'.$newlinkleft.'%;'.'top:'.$newlinktop.'%'); } } } ?> </head> <div class="wrapper"> <div class ="transbox" style="position:absolute; <?php checkBrowser('box',19,0,9,0) ?>"> <div class ="headertext" style="position:absolute; left:30%; top:30%">MARVIN SERRANO</div> <div class ="miniheadertext" style="position:absolute; left:29%; top:55%">Live for today, dream for tomorrow.</div> </div> <div class ="currentpagelink" style="position:absolute; <?php checkBrowser('other',38.1,26.3,10.1,3) ?>"> Home </div> <div class="otherpagelinks"> </div> </div> </html> -Marvin I am making a function it returns one thing, but I would the like to put something into a variable to use outside the function. for example, the third parameter in preg_match() sets a variable that you can then use later in your code, how can I create a parameter like that? I got two links with a parameter with a value. When I click either link it will send me to the same challenge.php page, I'm wanting to find the value of the parameter and display the page according to what value the parameter has in the url. This script doesn't seem to be working. Code: [Select] <a href="http://www.site.com/challenge.php?id=1">Complete Challenge 1</a> <a href="http://www.site.com/challenge.php?id=2">Complete Challenge 2</a> Code: [Select] $id = $_GET['id']; if ($id=1) { echo "This is challenge 1 completed"; } elseif ($id=2) { echo "This is challenge 2 completed"; else { echo "The URL parameters didn't work"; } Any help would be appreciated thanks. Hi all, I need to get a parameter from an url, but the GET variables are passed through urldecode(). Some of my variables may have characters such as "+", ":", spaces, etc. When I use GET, all "+" are converted to spaces. I can use urlencode to get the "+" back, but also everything that was previously a space also turns into "+". Example: variable = abc+ c+:d Then I can get either: abc c :d or abc++c+:d but I want to get abc+ c+:d Would anybody know how to help me? Thanks! Hello, I have made some dynamic code that performs a query on the SQL database, I only know that query at run time. However, after reading some more about PHP, I noticed that I need to include the function mysql_real_escape_string before doing this line: @mysql_query( $aStatement); So, how can I read that $aStatement and then call the mysql_real_escape_string function for each needed parameter? Thanks. Is there an alternative way to encode url params besides: base64_encode() examples would be great. |
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