|
PHP - How Can I Return Errors From Php Using Ajax
//my php code sample
<?php
include_once('con.php');
if(isset($_POST['username'])){
$message = [];
if(empty($_POST['username'])){
$message['username'] = 'username required';
}
#some validation continue...
$data = $_POST['username'];
if (count($errors) === 0){
#ccode...
$message['username'] = 'success your name saved';
}
}
?>
//my jquery ajax
$('.username').click(function() {
$.ajax({
url: 'user.php',
method: 'POST',
data: $('.user').serialize(),
success: function(data) {
swal('Wow!','success message from php','success');
},
error: function(data) {
swal('Oops!','error message from php','error');
}
});
return false;
});
Similar TutorialsHI guys I have vreated a site and am now trying to validate the ip address i have created a function but am failing to get it to work i need to add the errors to add to the errors array but instead it keeps resetting and leaving me with the last error that is returned any help would be greatly appreciated im a newbie so if i can understand the concept behind whats happening it will be of great benefit Thanks Sean heres the code // Function validateIpaddress($address,$record,$errors) // { // if ($address !=="" or $address !=="ip_address") // { // Print_r($address); // echo "<br><br>"; // $fullstoppos = strpos(($address), "."); // echo "strpos = $fullstoppos"; // $fullstoppos2 = strpos(($address), ".", $fullstoppos+1); // echo "strpos2 = $fullstoppos2"; // $fullstoppos3 = strpos(($address), ".", $fullstoppos2+1); // echo "strpos3 = $fullstoppos3"; // } // if ($fullstoppos !==4 && $fullstoppos2 !==9 && $fullstoppos3 !==14) // { // $errors[] = "<br><font color='red'>Please correct the following.Or contact your client manager for assitance.<br>* $record is a required field.An ip address is a 16 digit numerical value. </font>"; // } // } $errors = validateIpaddres($_POST['destinationPoint'],A/AAAA record, $errors)
Hi all btw after the json_encode i added json_last_error_msg and recieved no error message, so its something in the jquery in my understanding
<?php
if (isset($_POST['productid_typed']))
{
$userid=$_POST['productid'];
$stid = (DBOracle::getInstance()->get_product_desc($productid));
while ($row = oci_fetch_array($stid, OCI_ASSOC))
{
$data=array();
$data['productname']=$row['P_DESC'];
oci_free_statement($stid);
oci_close($con);
}
echo json_encode($data);
}
?>
<html>
<head>
<meta charset="UTF-8">
<title>Product</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<link rel="stylesheet" href="../../bootstrap-4.5.0-dist/css/bootstrap.min.css" />
<script src="../../bootstrap-4.5.0-dist/js/bootstrap.min.js"></script>
</head>
and this is the part of the jquery and ajax (the productid_desc is an input box on the page that should be filled automaticaly)
<script>
$(document).ready(function()
{
$('#productid').focusout(function()
{
debugger;
var productid=$('input[name=productid]').val();
if (productid!==' ')
$.ajax
({
type:"POST",
url:"index.php",
data:
{
productid_typed: 1,
productid: productid
},
datatype:"json" ,
success:function(data)
{
$('#productid_desc').val(data.productname);
}
})
else
{
alert("Plase enter id");
}
});
});
</script>
Hi Guys, I'm trying the following.. returning an array from a php function to Ajax success but the alert seems to only display undefined. PHP Code: [Select] public function reply() { $item_id = $this->uri->segment(3); $type = $this->uri->segment(4); if($type == 1){ $data['get_news_item'] = $this->Newsletter_model->get_news_item($item_id); $test = array( "Paul", "Mike"); return $test; } } AJAX Code: [Select] $.ajax({ type: "POST", url: "<?php echo site_url(); ?>newsletter/reply/"+id+"/"+type, cache: false, success: function (data){ alert(data[0]); // So this should display "Paul"? }); [/code] Hi all
we have an ajax query which queries a MySQL database for cities around the world for our hotel search. We are running on a Linux web hosted server.
The problem we are having is when you first visit out site and type in Brisbane or Sydney it takes around 15 seconds maybe to return. After that what ever city you query is lightening fast. I have had a few friends try this and when they first visit our site they experience the same then second time around it is fast.
Could this be some sort of caching issue or setting somewhere that I am missing?
I have attached a file so you can see what I mean
Thanks in advance
Attached Files
ajaxqry.jpg 169.31KB
0 downloads I have the following code and it always says it's a string! How do I make it see it as a json object? Code: [Select] <?php //We'll return a json object from post request if ( !empty( $_POST ) ) { $arr = array ('status'=>1,'message'=>'Some message'); echo json_encode($arr); } else { ?> <input type="button" value="submit" id="submit" /> <script type="text/javascript" src="/scripts/jquery-1.4.2.js"></script> <script> var submit = document.getElementById( "submit" ); submit.onclick = function() { $.post( "test.php", function(data) { /* * This always prints as: * {"status":1,"message":"Some message"} * string * Code: undefined * Message: undefined */ alert( data + "\n" + typeof( data ) + "\nCode: " + data.status + "\nMessage: " + data.message ); } ); } </script> <? } ?> What do I do to make it a json object?
Hello all,
<?php
// Connect to Phpmyadmin database localhost.
$hostname = "localhost";//"";127.0.0.1
$username = "root";
$password = "password";//"password";
$dbname = "test";
$conn = new mysqli($hostname, $username, $password, $dbname);
if($conn -> connect_error) {
die("Connection failed: " . $conn -> connect_error);
}
// USED to CHANGE the db. - (mysqli_select_db($con, "test") or die());
/* Check to make all fields entered -make sure submitted- #2*/
if(isset($_POST["register"])) {
if(!$_POST["email"] | !$_POST["password"] | !$_POST["password2"]) {
die("You did not fill in all the fields");
}
/* do escape strings for SQL injection */
$emailsafe = mysqli_real_escape_string($conn, $_POST["email"]);
$passsafe = mysqli_real_escape_string($conn, $_POST["password"]);
$pass2safe = mysqli_real_escape_string($conn, $_POST["password2"]);
/* Check and see if email EXISTS in db. */
/* Insert email in db if does not exist */
$sql = "SELECT email FROM users WHERE email = '$emailsafe'";//limit 1
$result = $conn->query($sql) or die("invalid email check " . mysqli_error($conn));
$numrows = mysqli_num_rows($result);
if($numrows != 0) {
die("Sorry the email " . $_POST["email"] . "is already in use");
}
// check if passwords both match
if($_POST["password"] != $_POST["password2"]) {
die("Passwords did NOT match");
}
// if passwords match encrypt
$hashedpass = password_hash($passsafe, PASSWORD_DEFAULT);
// With everything escaped and hashed INSERT into db.
$sqlINSERT = "INSERT INTO users(email, password) " .
"VALUES('" . $emailsafe ."','". $hashedpass ."')";
if($query = $conn->query($sqlINSERT)=== TRUE) {
echo '<script type="text/javascript">alert("Successfully INSERTed");</script>';
} else {
die("Unsuccessful");
}
$conn->close();
?>
I ran my php with ajax and it creates the file successfully so i know it runs. I wanted to setup PHP debugging with atom or visual studio but i have not been able to successfully do that... I tried with xdebug so i just use the network tab inchrome to find if errors exist. Right now I redirect to index page after I delete a record. However I am looking to make it so that I can delete a record without redirecting the page. I know this can be accomplised using Ajax. I have spent countless hours before trying to make it work, but it did not work.
So here is a basic setup I created. Can you please update it with ajax code so that I can see how it's done properly?
<!DOCTYPE HTML> <html lang="en"> <head> <meta charset="UTF-8"> <title>Home Page</title> </head> <body> <div class="record" > <a href="record.php?id=<?php echo $record_id ?>"><?php echo $record_name; ?></a> <div class="delete-record"> <a href="delete.php">Delete Record</a> </div> </div> </body> </html> Edited by man5, 18 August 2014 - 08:55 PM. Now I'm having this strange issue with my website I'm currently working on a tester system and I've encountered a problem that I'm unable to find the issue, tho I'm thinking my ajax php part of the script to be the thing causing it even tho it seems strange that it would cause it. The first part which is connected to where the problem occurs is the echo"<form>"; and from there, It should take you to index.php?page=tester&select=answer, now that is where it in the browser goes there tho it still shows the page stuff from the last page which is index.php?page=tester&select=applications, so it's like showing both &select=answer and &select=applications on the same page. <?php $q=$_GET["q"]; include'../config/connection.php'; $result = mysql_query("SELECT * FROM applications WHERE id = '$q'"); echo "<center><table border='1'> <tr> <th>Account Name</th> <th>Character Name</th> <th>Gender</th> <th>Skin Color</th> </tr>"; $row = mysql_fetch_array($result); echo "<tr>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['charactername'] . "</td>"; echo "<td>" . $row['gender'] . "</td>"; echo "<td>" . $row['race'] . "</td>"; echo "</tr></table></center>"; echo"<br/>"; echo"<table><tr> <th>Description</th> <th>Metagaming</th> <th>Powergaming</th></tr>"; echo"<tr>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['description']."</textarea></td>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['mg']."</textarea></td>"; echo "<td><textarea readonly='readonly' style='width:22em; height:20em;'>".$row['pg']."</textarea></td>"; echo"</tr></table><table><br/><center><h1>Answer</h1><br/><form action='index.php?page=tester&select=answer' method='post'>"; echo"<textarea name='why' style='height:10em; width:60em;'></textarea><br/>"; echo"<input type='submit' name='answer' value='Accept' /><a/>"; echo"<input type='submit' name='answer' value='Decline' /></center>"; echo"<input type='hidden' name='id' value='$q'/>"; echo"</form></table>"; ?> Now on &select=answer it included a page which the script of that include consist of the stuff below, it outputs that the query was successfully, and all that. <? if(!empty($_POST['why'])) { $why = mysql_real_escape_string($_POST['why']); $answer = trim($_POST['answer']); $id = $_POST['id']; if($answer == "Accept") { $query1 = mysql_query("UPDATE characters SET accepted = '1' WHERE id = '".$id."'"); echo"Successfully accepted"; $answer = 1; } elseif($answer == "Decline") { echo"Successfully declined"; $answer = 0; } $query = mysql_query("UPDATE applications SET answer = '$why' AND tester = '".$_COOKIE['Username']."' AND accepted = '$answer' AND answered = '1' WHERE cid = '".$id."'") or die('Could not connect: ' . mysql_error()); if($query) { echo"<br/>Query went through without problems"; header("Refresh: 5;url=index.php?page=tester"); } } ?> This is the ajax part javascript of it which gets the information for index.php?page=tester&select=applications Code: [Select] <script type="text/javascript"> function showApplication(str) { if (str==""||str==0) { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","tester/applications.php?q="+str,true); xmlhttp.send(); } </script>If you need any more information feel free to ask for it. Thanks in advance. How do I display the actual errors in IIS 7.5? If I miss a semicolon, I get: "HTTP Error 500.0 - Internal Server Error" absolutely useless. In prior versions, I could see the line and get to the PHP error. How do I display PHP errors? I've added: set_ini('display_errors', '1'); but it doesn't help. Hello, I've been trying this for hours now, looking at different examples and trying to change them to work for me, but with no luck... This is what I am trying to do: I have a simple form with: - 1 input field, where I can enter a number - 1 Submit Button When I enter a number into the field and click submit, I want that number to be send to the php file that is in the ajax call, then the script will take that number and run a bunch of queries and then return a new number. I want that new number to be used to call the php script via ajax again, until no number is returned, or something else is returned like the word "done" or something like that, at which point is simply makes an alert or populated a div with a message... The point is, that depending on the number entered it could take up to an hour to complete ALL the queries, so I want the script that is called to only run a fixed amount of queries at a time and then return the number it is currently at (+1), so that it can continue with the next number when it is called again. I would like to use jquery, but could also be any other way, as long as I get this to work. I already have the php script completed that needs to be called by the ajax, it returns a single number when being called. Thank you, vb As the title say, I can not for the life of me get the "$bank" content to display, no matter HOW much I try... Does anyone see any errors. I am sooooooo wiped out at this! main page <? $body = ' <script type="text/javascript" src="change-content.js"></script> <div id="addSold"> <form action="'.$_SERVER['REQUEST_URI'].'" method="post" name="form" autocomplete="off"> <fieldset id="Vehicle"> <legend>Vehicle</legend> <ul> <li><label for="Year">Year</label>'.$Year.'</li> <li><label for="Make">Make</label>'.$Make.'</li> <li><label for="Model">Model</label>'.$Model.'</li> <li><label for="Trim">Trim</label><input type="text" name="Trim" id="Trim" size="10" value="'.$trim.'" disabled="disabled"></li> </ul> <ul> <li><label for="Mileage">Mileage</label><input type="text" name="Mileage" id="Mileage" size="5" maxlength="6" value="'.$row['mileage'].'"></li> <li><label for="VIN">VIN</label><input type="text" name="VIN" id="VIN" size="23" maxlength="17" value="'.$row['vin'].'" disabled="disabled"></li> <li><label for="Color">Color</label>'.$Exterior.'</li> </ul> </fieldset> <fieldset id="Deal"> <legend>Deal</legend> <ul> <li> <label for="soldDte1">Date</label> <input type="text" name="soldDte1" id="soldDte1" size="1" maxlength="2" onkeyup="return autoTab(this, 2, event)" value="08"> / <input type="text" name="soldDte2" id="soldDte2" size="1" maxlength="2" onkeyup="return autoTab(this, 2, event)" value="30"> / <input type="text" name="soldDte3" id="soldDte3" size="1" maxlength="2" value="'.$year.'"> <a href="#"><img id="date_'.$row[stock].'" src="images/Icons/dateOff.png" onfocus="this.select();lcs(this)" onmouseover="MM_swapImage(\'date_'.$row[stock].'\',\'\',\'images/Icons/dateOn.png\',1)" onmouseout="MM_swapImgRestore()" alt="Choose Date"></a> </li> <li> <label for="salesman">Salesman</label> <select name="salesman" id="salesman"> <option></option> '.$salesmen.' </select> </li> </ul> <ul> <li> <label for="dealType">Deal Type</label> <select name="dealType" class="select-content" onchange="getFile(this.value)"> <option></option> <option value="AL">Auto Loan</option> <option value="Cash">Cash</option> <option value="CAC">Credit Acceptance</option> <option value="IH">In House</option> <option value="SAL">Sensible Auto</option> </select> </li> <li> <label for="tradeDrop">Trade</label> <select name="tradein" id="tradeDrop" onchange="show_hide_trade(this.value);"> <option value="No">No</option> <option value="Yes">Yes</option> </select> </li> </ul> </fieldset> <div id="Bank" class="view">'.$bank.'</div> </form> </div> '; ?> get_Bank.php <? if ($_GET['dealType'] == "AL") { $bank = ' <fieldset id="AL"> <legend>Auto Loan Figures</legend> <ul> <li><label for="price">Price</label><input type="text" name="price" id="price" class="price" size="7" onchange="currency(this)"></li> <li><label for="down">Down</label><input type="text" name="down" id="down" class="price" size="6" onchange="currency(this)"></li> <li><label for="tax">Tax</label><input type="text" name="tax" id="tax" class="price" size="6" onchange="currency(this)"></li> <li><label for="reg">Plates</label><input type="text" name="reg" id="reg" class="price" size="4" onchange="currency(this)"></li> <li><label for="gap">Gap</label><input type="text" name="gap" id="gap" class="price" size="4" onchange="currency(this)"></li> </ul> <ul> <li> <label for="pymtNum">--------------- Payment ---------------</label> <input type="text" name="pymtNum" id="pymtNum" size="3" maxlength="3" onkeyup="return autoTab(this, 3, event)"> @ <input type="text" name="pymtAmnt" id="pymtAmnt" class="price" size="5" onchange="currency(this)"> per <select name="pymtType"> <option value="Weekly" selected="selected">Week</option> <option value="Monthly">Month</option> </select> </li> <li><label for="APR">APR</label><input type="text" name="APR" id="APR" class="rate" size="6" value="19.00"></li> </ul> </fieldset> '; } elseif ($_GET['dealType'] == "CAC") { $bank = ' Credit Acceptance stuff goes here '; } else { $bank = 'You must choose a bank before continuing'; } ?> change-content.js Code: [Select] window.onload = init; // finds all <select> tags will class="select-content" and activates function function init() { var sel = document.getElementsByTagName("select"); for (var i=0; i<sel.length; i++){ if (sel[i].className == "select-content") { sel[i].onchange = getFile; } sel[i].selectedIndex = 0; } } function getFile (url) { var url = "AJAX/get_Bank.php?dealType="+ this.value; if (window.XMLHttpRequest) {xmlhttp=new XMLHttpRequest();} else {xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");} xmlhttp.open("GET",url,false); xmlhttp.send(); // a loop that looks through all <div>s on the page // and then replaces the id with the value and gets that file var divs = document.getElementsByTagName("div"); for (var i=0; i<divs.length; i++) { if(divs[i].id == "bank") { divs[i].id = this.value; divs[i].innerHTML=xmlhttp.responseText; } } } Hey all. My site has a config database table that has a column showlogin to set whether or not login functionality is enabled. I'm playing around with MySQLi, Classes, and Returns. My return is always 1. Where am I going wrong? test.php <?php // Start Session session_start(); // Production Settings ini_set('display_errors', 1); mysqli_report(MYSQLI_REPORT_ALL); include 'db.php'; $mysqli = new mysqli($host, $user, $pass, $db); class styles { function showlogin($show) { global $mysqli; $select = $mysqli->query("SELECT showlogin FROM config LIMIT 1"); $value = $select->fetch_object(); if ($value->showlogin = 1) { return 1; } return 0; } } $login = new styles(); echo $login->showlogin($show); ?> Hi Everyone,
My name is Raoul Grosser, live in The Netherlands.
I'm a front/backend developer working with AngularJS and Bootstrap and Symphone2.
I've been writing PHP code for over 4 years now my focus is on opensource projects.
If you have any question, please let me know!
return (int) $value VS return $value
What is the purpose of using int in a bracket? return (int) $value
Which is the best and safest method?
Thank you
Hello First of all i am very weak about OOP and classes in php. I am learning now but i stuck with very silly problem. My codes are below. <?php class myTestClass { function __construct() { $this->OldName("This is Old Name"); } function OldName($VeryOld) { if($VeryOld == "This is Old Name") $this->NewName(); else $VeryOld = "Something Wrong"; return $VeryOld; } function NewName() { echo "This is Brand New Name"; } } $i = new myTestClass(); ?> if i send value to OldName "This is Old Name" then codes works fine. But if i send "This is Old Nameeee" then does not appear anything. what i want to do is print "Something Wrong" text if i enter different value. I have no idea what return do and how it do? How to retrieve/print "Something Wrong"? i can do that with echo but i want to transfer result of return to another function. Really appreciate for any help/idea. If a user is on Page X, but not logged in, when they log in to my website, I want them to return back to Page X (in this example). To handle this, I am adding this code to the top of each webpage... Code: [Select] // Set current Script Name. $_SESSION['returnToPage'] = $_SERVER['SCRIPT_NAME']; And then as part of my Log In script I have... Code: [Select] // Redirect User. if (isset($_SESSION['returnToPage'])){ header("Location: " . BASE_URL . $_SESSION['returnToPage']); }else{ // Take user to Home Page. header("Location: " . BASE_URL . "index.php"); } What do you think about this approach? Thanks, Debbie I am trying make my code display different things depending on how many rows are returned This is my code Code: [Select] <?PHP include 'db_con.php'; $month = date("n"); $day = date("j"); $sql = mysql_query("SELECT * FROM table WHERE month = $month AND day = $day ")or die(mysql_error()); while($row = mysql_fetch_array($sql) ) if (mysql_fetch_array($row = 1 ) ) ///THIS IS AN ERROR BUT IF ONE ROW RETURNED THEN THIS { echo "ONE THING"; } elseif (mysql_fetch_array($row >1 ) )////IF > 1 ROW RETURNED THAN THIS { echo"TWO THINGS"; } else { echo "SOMETHING ELSE "; } ?> I have tried several variations of the above code but cannot get it to work. Thanks for any help anyone can give me. Hi all, I am kinda stuck on the return() statement in the php.net manual about control structures. (http://au.php.net/manual/en/function.return.php) All I see is notes on when not to use it and some scary examples with loads of foo and bar but, it's hard to find out when it would be nice to use it. At the moment i am thinking its another way of echo, but I bet that's wrong. If someone could enlighten me a bit on when return() is useful I would be very happy since i see it more often everyday. CHeers! Script:
<?php
class Article{
public function fetch_all(){
global $pdo;
$query = $pdo->prepare("SELECT * FROM `articles` ORDER BY `article_timestamp` DESC");
$query->execute();
return $query->fetchAll();
}
public function fetch_data($article_id){
global $pdo;
$query = $pdo->prepare("SELECT * FROM `articles` WHERE `article_id` = ?");
$query->bindValue(1, $article_id);
$query->execute();
return $query->fetch();
}
/*
* These have gotten added later on.
*/
public function delete($id){
global $pdo;
$query = $pdo->prepare("DELETE FROM `articles` WHERE `article_id` = ?");
$query->bindValue(1, $id);
$query->execute();
// The "return" here.
}
public function edit_page($title, $content, $aticle_id){
global $pdo;
$query = $pdo->prepare("UPDATE `articles` SET `article_title` = ?, `article_content` = ? WHERE `article_id` = ?");
$query->bindValue(1, $title);
$query->bindValue(2, $content);
$query->bindValue(3, $article_id);
$query->execute();
// The "return" here.
}
}
?>
I have this from a tutorial. In the function "fetch_all()" it uses "fetchAll()" at the spot where the "return" is, and in the function "fetch_data()" it uses "fetch()" at the spot where the "return" is.
My Question:
What may have to use for the function "delete()" and the function "edit_page()" at the spot where "return" would be?
Edited by glassfish, 29 October 2014 - 12:32 PM. I have a form page (referred to as form.php) which is then processed via a submit button, the script then processes the data from the form.php and if it discovers an error it then sets a variable containing the error message my process page contains Code: [Select] if (empty($b_addr)) { $b_addr_error = "Address is required"; $check_failed = TRUE;} header("Location: form.php"); then my form.php contains Code: [Select] $b_addr_error = safe($_GET['b_addr_error']); if (isset($_POST['$b_addr_error'])) { echo "<div class='errorfont' align='center'>'".$b_addr_error."';</div>"; } but the variables do not get passed back to form.php from the process page, any ideas? Thank you. |
|||||||