PHP - Problem With Mysql Data To Html Table
Hello, I have the problem that only one user is displayed in the table require('connection/db1.php'); // Teilnehmerliste $query = 'SELECT * FROM convoy_part WHERE user_convoy= :I'; $start = $bdd->prepare($query); $start->execute(array(':I' => $_GET['id'])); //fetch $result2 = $start->fetch(); // Zählung der Datensätze $count = $start->rowCount(); <table class="table"> <thead> <tr> <th scope="col">User</th> <th scope="col">Datum</th> <th scope="col"><a class="btn btn-primary" href="convoy_user.php?id=<?php echo $result['id']; ?>&action=part" role="button">Teilnehmen</a></th> </tr> </thead> <tbody> <tr> <th scope="row"><?php echo $result2['name']; ?></th> <td><?php echo $result2['date']; ?></td> </tr> </tbody> </table>
Similar TutorialsHello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php while($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo ' <tr> <td>'.$row["id"].'</td> '; while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) { echo ' <td>'.$row1["email"].'</td> '; } if($row["validity"] == 1) { echo '<td>'.$row["validity"].' month</td>'; }else{ echo '<td>'.$row["validity"].' months</td>'; } echo ' <td>'.$row["valid_from"].'</td> <td>'.$row["valid_to"].'</td> </tr>'; } ?>
Thank you. Hi all, I'm new to php/myslq and I'm going crazy trying to figure this one out I'm building a personal calendar and I want to display the data into a HTML table. Code: [Select] //query the database $query = "SELECT * FROM tbl_events WHERE event_day=$day AND event_month=$month AND event_year=$year"; $query = mysql_query($query); //build the table echo '<table>'; for ($y = 0; $y < 6; $y++){ echo '<tr><td>'; //insert the data here echo '</td></tr>'; } echo '</table>'; When I store the events into the database, I assign a slot for each one depending on the hour. I don't want to use more than 6 events daily, hence the for loop. The problem I have is how to I insert the data into the designed <td>? In a particular day I could have only 2 events: event 1 - slot 2, event 2 - slot 6. I want to be able to enter each event into its own cell I hope I'm making myself clear enough. Sorry for any English mistakes if any. Thank you Hi, I'm trying to make a dynamic html table to contain the mysql data that is generated via php. I'm trying to display a user's friends in a table of two columns and however many rows, but can't seem to figure out what is needed to make this work. Here's my code as it stands: Code: [Select] <?php //Begin mysql query $sql = "SELECT * FROM friends WHERE username = '{$_GET['username']}' AND status = 'Active' ORDER BY friends_with ASC"; $result = mysql_query($sql); $count = mysql_num_rows($result); $sql_2 = "SELECT * FROM friends WHERE friends_with = '{$_GET['username']}' AND status = 'Active' ORDER BY username ASC"; $result_2 = mysql_query($sql_2); $count_2 = mysql_num_rows($result_2); while ($row = mysql_fetch_array($result)) { echo $row["friendswith"] . "<br>"; } while ($row_2 = mysql_fetch_array($result_2)) { echo $row_2["username"] . "<br>"; } ?> The above simply outputs all records of a user's friends (their usernames) in alphabetical order. The question of how I'd generate a new row each time a certain amount of columns have been met, however, is beyond me. Anyone know of any helpful resources that may solve my problem? Thanks in advance =) I'm not sure if my problem is with the PHP, MySQL, HTML, or all of the above, but I've used a tutorial from ScriptPlayground (http://scriptplayground.com/tutorials/php/Printing-a-MySQL-table-to-a-dynamic-HTML-table-with-PHP/) to print a table to HTML. My problem isn't that I couldn't get it to work, as you can see from my site, http://dollapal.com/offerlist.php I've used the code on my site, trying to display a list of offers, with links to each, but I actually have two questions: Is there a way to EXCLUDE columns of the table? I would rather not show the 'id' or 'points' columns, since they don't offer any worth to the user. I would also need to hopefully add a dollar sign before the 'pay' quantities if possible. I would also like use the 'title' field as a hyperlink to the URL listed in the 'URL' field, instead of simply printing the URL. Are there any simple ways to do this and not have it look terrible? I have included a copy of the script that I'm working with so far. Thank you in advance! I have a script that is supposed to allow a user to add their details to a members table in the database. It acts as if the user has been added to the database by stating the thank you message, but there is no entry into the database. I can connect to the database and have another script running OK that allows me to view all of the information in the members table with a loop (this data was entered using php my admin's GUI). Here is the script that is supposed to add the member. Any help would be greatly appreciated. <?php error_reporting(-1); $user_name = "root"; $password = ""; $database = "test"; $server = "localhost"; $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "INSERT INTO members (fname, sname, email, password, gender) VALUES ('$_POST[fname]','$_POST[sname]','$_POST[email]','$_POST[password]','$_POST[gender]')"; $result = mysql_query($SQL); mysql_close($db_handle); print "Thanks for joining us ".$_POST['fname']."."; } else { print "Database NOT Found"; mysql_close($db_handle); } ?> Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hello, I know i'm new, i hope it wont stop you guys from putting 5 minutes of your time to help me out. I need a script to get some data from mysql and put this into a table. i have a mysql database called "denora" In there is a table called "chan" In table chan are the columns: chanid (unique number), channel, currentusers, mode_ls I would like the script to make a html table that lists the top10 channels (most "currentusers" on top) And when "mode_ls" is "Y" it must not be shown (secret channel) My knowledge of php and mysql arent that great so i really hope someone takes the time to help me uit Kind regards Stefan I have MySQL table with the following fields: user=>varchar product=>varchar Amount=>int Date=>date Note=>tinytext I can't add value to these field by the following php code: $date = date("Y.m.d"); $query = "INSERT INTO order VALUES ('farhad', 'Mango', '10', '$date', 'hello')"; $result = mysql_query($query) or die(mysql_error()); I receive the following warning: Warning: date(): It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'Europe/Paris' for '2.0/DST' instead in C:\inetpub\wwwroot\Okern\~order.php on line 10 Call Stack: 0.0047 325856 1. {main}() C:\inetpub\wwwroot\Okern\~order.php:0 0.0274 344912 2. date() C:\inetpub\wwwroot\Okern\~order.php:10 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order VALUES ('farhad', 'Mango', '10', '2011.04.17', 'hello')' at line 1 Hello, can someone help me with my proggraming problem please. Am new in this so i still have lots problems. I need to put all data from my MySQL table in one table in html. There is catch... i need to design output to give me table with x rows and 3 columns, so it means while reading data from database it need put every 4th in new row. And if there isnt 3 data (or better say if there isnt 3 full <td>) in row code will automatically add empty <td> or 2 in table. So...did somebody do this before or have some code ? All i got for now is Code: [Select] $td ='<td align="center"><img src="'.$row['name'].'.png" /> <p style="font-family:Verdana, Geneva, sans-serif; font-size:15px"> Number: <b style="font-size:40px;">'.$row['serial'].'</b></p> <br><img width="90" height="29" src="'.$logo.'"/></td>'; $tr ='<tr>'.$td.'</tr>'; $html='<table border="1" align="center">'.$tr.'</table>'; Thanks. I am trying to get specific data from a MySQL table but cannot seem to find a proper command. Code: [Select] $link = mysqli_connect('#####', '########', '########'); $user = $_SESSION['username']; $email = mysqli_query($link,"select email from members where username='$user'"); echo $email; Specifically, I am trying to get the email address stored for the user specified by the session, and display that address. However, I do not get any output with the current code, and am not sure what to try next. I have tried mysqli_fetch_row() but it only returns an error. Can you add a WHERE clause in $row? For example: $row['city_display'] WHERE city_display = 1 $row['city_display'] WHERE city_display = 2 etc... How can this be done? Hello, I have a script that processes data from a form, and then outputs data from a MySQL table based on which selections are made on the form. What I'm trying to do is create columns showing data for each month depending on which months the user selects, and then a "Total" column at the end of that. The output first determines the "family" the results are in, then the ID the product is for the parent family, and then it outputs the data based on what ID is listed. Unfortunately, I have no idea how to do this without nesting while loops inside other while loops which I know is bad for server performance - and yes this does take a long time to complete. Here is some of my code for this to show what I'm doing wrong: Code: [Select] $searchdatabase5 = "SELECT field3 FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field3 != 0 AND field4 != '995' GROUP BY field3"; $run5 = mysql_query($searchdatabase5) or die(mysql_error()); while($row5 = mysql_fetch_assoc($run5)) { $field5_3 = $row5['field3']; echo '<tr><td colspan="0"><hr style="width: 100%; height: 1px; color: #a0a0a0;"></td></tr><tr><td colspan="0" bgcolor="#ccffcc"><strong>FAMILY '. $field5_3 .'</strong><br /></td></tr>'; $searchdatabase12 = "SELECT field4 FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field3 = '$field5_3' AND field4 != 0 GROUP BY field4"; $run12 = mysql_query($searchdatabase12) or die(mysql_error()); while($row12 = mysql_fetch_assoc($run12)) { $field12_4 = $row12['field4']; $searchdatabase6 = "SELECT field3,field4,field5,field6 FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field4 = '$field12_4' GROUP BY field3,field4,field5"; $run6 = mysql_query($searchdatabase6) or die(mysql_error()); while($row6 = mysql_fetch_assoc($run6)) { $field6_3 = $row6['field3']; $field6_4 = $row6['field4']; $field6_5 = $row6['field5']; $field6_6 = $row6['field6']; echo '<tr><td colspan="0">'. $field6_5 .' - '. $field6_6 .'</td></tr><tr><td valign="middle" align="left" bgcolor="#ccc" width="183px">Units</td>'; $searchdatabase7 = "SELECT * FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field5 = '$field6_5' ORDER BY year,month ASC"; $run7 = mysql_query($searchdatabase7) or die(mysql_error()); while($row7 = mysql_fetch_assoc($run7)) { $field7_3 = $row7['field3']; $field7_4 = $row7['field4']; $field7_5 = $row7['field5']; $field7_9 = $row7['field9']; $field7_10 = $row7['field10']; $field7_month = $row7['month']; $field7_year = $row7['year']; $startmonth2 = ltrim($startmonth, '0'); echo '<td bgcolor="#e6e6e6" width="95px" nowrap="nowrap" align="right">'; echo $field7_10; echo '</td>'; } Here is the output: I know the code is very bad, but what would be the best way to recreate what I have in the image? Thank you. Hello guys, im using this code atm and it's working, but the new rows created are put in the end of the table. I want them to stack up from the beginning pushing older rows down. What should i do to make that work? <?php $con = mysql_connect("localhost","*****","*******"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("ananaz_se", $con); $sql="INSERT INTO stuff (adult, namn, url) VALUES ('$_POST[adult]','$_POST[namn]','$_POST[url]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 row added"; mysql_close($con) ?> Hello there! I've been banging my head on this for a while and I just can't seem to get it to work properly. I have a dropdown menu which selects information from table1 using a select statement (this table is called 'lid'). It selects the firstname, lastname and member id from this table and shows it in the dropdown menu. I'm glad I got that part working but the hard thing is inserting the data that the user selects into another table. So when you select the id member from this dropdown menu it only inserts a blank row into table2 (which is called 'teamlid'). Can you guys help me? How can I insert the id member into my table2? What am I doing wrong here? Thanks a million! This is my first post so if I'm doing anything wrong, let me know and I'll fix it asap! My code: <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Boast & Drive</title> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css"> <style type="text/css"> .wrapper{ width: 650px; margin: 0 auto; } .page-header h2{ margin-top: 0; } table tr td:last-child a{ margin-right: 15px; } </style> </head> <body> <div class="container-fluid"> <div class="row"> <div class="col-md-12"> <div class="page-header clearfix"> <h2 class="pull-left">Teamleden</h2> <div class="btn-toolbar"> <a href="read.php" class="btn btn-primary btn-lg pull-right">Terug</a> </div> </div> <?php mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); error_reporting(E_ALL); //Verbinding maken met de database require_once "login.php"; $sql = "SELECT tl.teamnaam, tl.tl_ID, tl.lidnummer, l.voornaam, l.achternaam FROM teamlid tl JOIN lid l ON tl.lidnummer = l.lidnummer ORDER BY tl.teamnaam;"; if($result = mysqli_query($conn, $sql)) { if(mysqli_num_rows($result) > 0) { echo "<table class='table table-bordered table-striped'>"; echo "<thead>"; echo "<tr>"; echo "<th>Teamnaam</th>"; echo "<th>Tl_ID</th>"; echo "<th>Lidnummer</th>"; echo "<th>Voornaam</th>"; echo "<th>Achternaam</th>"; echo "</tr>"; echo "</thead>"; echo "<tbody>"; while($row = mysqli_fetch_array($result)){ echo "<tr>"; echo "<td>" . $row['teamnaam'] . "</td>"; echo "<td>" . $row['tl_ID'] . "</td>"; echo "<td>" . $row['lidnummer'] . "</td>"; echo "<td>" . $row['voornaam'] . "</td>"; echo "<td>" . $row['achternaam'] . "</td>"; echo "<td>"; echo "<a href='update.php?id=". $row['lidnummer'] ."' title='Gegevens wijzigen' data- toggle='tooltip'><span class='glyphicon glyphicon-pencil'></span></a>"; echo "<a href='delete.php?id=". $row['lidnummer'] ."' title='Lid verwijderen' data- toggle='tooltip'><span class='glyphicon glyphicon-trash'></span></a>"; echo "</td>"; echo "</tr>"; } echo "</tbody>"; echo "</table>"; mysqli_free_result($result); } else{ echo "<p class='lead'><em>Er zijn geen gegevens om weer te geven.</em></p>"; } } else{ echo "De volgende fout is gevonden: " . mysqli_error($conn); } ?> <form name="dropdown" method="post"> <div class="page-header clearfix"> <h2 class="pull-left">Teamlid toevoegen</h2> </div> <p>Selecteer hieronder met behulp van het dropdown menu een lid welke je aan bovenstaand team wilt toevoegen</p> <div class="container-fluid"> <div class="row"> <?php // Variabelen aanmaken en tonen met lege waardes $teamnaam = $lidnummer = ''; // Code voor dropdown. Selecteert voornaam, achternaam en lidnummer van tabel lid) $sql = "SELECT voornaam, achternaam, lidnummer FROM lid ORDER BY achternaam"; $result = mysqli_query($conn, $sql); echo "<select id='teamLid' name='teamLid'>"; echo "<option>--Selecteer Lid--</option>"; while ($row = mysqli_fetch_array($result)) { echo "<option value='" . $row['lid'] . "'>" . $row['voornaam'] . " " . $row['achternaam'] . " " . $row['lidnummer'] . "</option>"; } echo "</select>"; if (isset($_POST["id"]) && !empty($_POST["id"])) { $id = $_POST["teamLid"]; $stmt = $conn->prepare("INSERT INTO teamlid (teamnaam, lidnummer) VALUES (?,?)"); $stmt->bind_param('si', $param_teamnaam, $param_lidnummer); $param_teamnaam = $teamnaam; $param_lidnummer = $lidnummer; $stmt->execute(); } // Verbinding sluiten mysqli_close($conn); ?> <div> <input type="hidden" name="id" value="<?php echo $id; ?>" /> <input type="submit" name="submit" class="btn btn-primary" value="Toevoegen"> </div> </div> </div> </form> </div> </div> </body> </html>
Hi, I am extracting data from a mysql db to then edit and update back into the db and use below to list items first - Code: [Select] <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); $sql="SELECT * FROM properties"; $result=mysql_query($sql); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td> <table width="400" border="1" cellspacing="0" cellpadding="3"> <tr> <td colspan="4"><strong>List data from mysql </strong> </td> </tr> <tr> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> <td align="center"><strong>Email</strong></td> <td align="center"><strong>Update</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td><? echo $rows['Property_Rating']; ?></td> <td align="center"><a href="update.php?id=<? echo $rows['ID']; ?>">update</a></td> </tr> <?php } ?> </table> </td> </tr> </table> <?php mysql_close(); ?> I then go next page where I show data and allow editing - <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); // get value of id that sent from address bar $id=$_GET['id']; // Retrieve data from database $sql="SELECT * FROM properties WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><strong>Update data in mysql</strong> </td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Property_Name</strong></td> <td align="center"><strong>roperty_Rating</strong></td> <td align="center"><strong>Property_Address</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="Property_Rating" type="text" id="Property_Rating" value="<? echo $rows['Property_Rating']; ?>"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?> And then the update page - <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); // update data in mysql database $sql="UPDATE properties SET Property_Name='$Property_Name' WHERE id='$id'"; $result=mysql_query($sql); // if successfully updated. if($result){ echo "Successful"; } else { echo "ERROR"; } ?> Everything seems ok but when I edit the data and submit I get the success message but data not changed in db. Any ideas? Thanks. MOD EDIT: code tags added. Hi I have a table (applicant) and I am looking at producing a pdf displaying various items of data from this table. I have succeeded in getting the look I want but in my query I use a fixed applicantid (in this case an id of 4). What I want to be able to do is to have the id cary according to the url. In other words, when someone comes from one web page to this one and the url is of the format .../pdf_production.php?applicantid=42. I'm not sure I've explained that very well but I hope someone can help - I think this is the last thing I need to sort out. Many thanks in advance. The code I have so far is: <?php require_once('../Connections/process.php'); ?> <?php require_once('../tcpdf/config/lang/eng.php'); require_once('../tcpdf/tcpdf.php'); // get data from users table mysql_select_db($database_process, $process); $result = mysql_query("SELECT * FROM applicant WHERE applicantid = '4'"); while($row = mysql_fetch_array($result)) { $appid = $row['applicantid']; $idcode = $row['idcode']; $type = $row['type']; $company = $row['company']; $email = $row['email']; } // create new PDF document $pdf = new TCPDF(PDF_PAGE_ORIENTATION, PDF_UNIT, PDF_PAGE_FORMAT, true, 'UTF-8', false); $pdf->SetPrintHeader(false); $pdf->SetPrintFooter(false); // set default monospaced font $pdf->SetDefaultMonospacedFont(PDF_FONT_MONOSPACED); //set margins $pdf->SetMargins(PDF_MARGIN_LEFT, PDF_MARGIN_TOP, PDF_MARGIN_RIGHT); //set auto page breaks $pdf->SetAutoPageBreak(TRUE, PDF_MARGIN_BOTTOM); //set image scale factor $pdf->setImageScale(PDF_IMAGE_SCALE_RATIO); //set some language-dependent strings $pdf->setLanguageArray($l); // --------------------------------------------------------- // set font $pdf->SetFont('dejavusans', '', 10); // add a page $pdf->AddPage(); // create some HTML content $txt = <<<EOD Below are the details I require Company type: $type Company Name: $company Company email: $email EOD; // output the HTML content // $pdf->writeHTML($htmlcontent, true, 0, true, 0); $pdf->Write(0, $txt, '', 0, 'L', true, 0, false, false, 0); // $pdf->writeHTML($inlinecss, true, 0, true, 0); // reset pointer to the last page // $pdf->lastPage(); //Close and output PDF document $pdf->Output('example_006.pdf', 'I'); //============================================================+ // END OF FILE //============================================================+ ?> I have members.php: <?php /********************************************************************** Filename: members.php Version: $Id: members.php 17 2007-04-09 09:40:35Z Jez $ Description: This file displays the members screen once they've logged in. **********************************************************************/ /* Members script: */ include_once("config.php"); // Check user logged in already: checkLoggedIn("yes"); doCSS(); print("Welcome to the members page <b>".$_SESSION["login"]."</b><br>\n"); print("Your password is: <b>".$_SESSION["password"]."</b><br>\n"); print("<a href=\"logout.php"."\">Logout</a>"); ?> and functions.php: <?php /********************************************************************** Filename: functions.php Description: This file contains main stock of functions. This file is automatically 'include()'d by every page that include()'s the file 'config.php'. This has the benefit that every page that includes 'config.php' will have access to all of the functions in this file. **********************************************************************/ /******************************************************\ * Function Name : connectToDB() * * Task : create connection to db * * Arguments : none * * Globals: all defined in config.php * * Returns : none, sets $link * \******************************************************/ function connectToDB() { global $link, $dbhost, $dbuser, $dbpass, $dbname; /* Database connection: The PHP function mysql_pconnect() connects to a MySQL database with the arguments it is given. mysql_pconnect() creates a persistent database connection which can save some time when a number of mysql connections are made to the same db with the same user/password/dbhost triple. Further, when the execution of the PHP script ends, the connection to the database is NOT closed. In some rare cases this can cause problems. Alternatively mysql_connect() can be used and takes the same arguments as mysql_pconnect(). However mysql_connect() does not maintain a persistent connection - every call to mysql_connect() creates a new db connection. On a busy server this can significantly increase the amount of time taken to execute queries on the db. */ ($link = mysql_pconnect("$dbhost", "$dbuser", "$dbpass")) || die("Couldn't connect to MySQL"); // select db: mysql_select_db("$dbname", $link) || die("Couldn't open db: $dbname. Error if any was: ".mysql_error() ); } // end func dbConnect(); /******************************************************\ * Function Name : newUser($login, $pass) * * Task : Create a new user entry in the users table based on args passed * * Arguments : string($login, $pass) * * Returns : int($id), $id of new user * \******************************************************/ function newUser($login, $password) { /* Creating a New User Record in the DB: In this function we create a new user record in the db. We first build a query and save it into the $query variable. The query statement says: 'Insert the value of $login and $password into the 'login' and 'password' columns in the 'users' table' */ global $link; $query="INSERT INTO users (login, password) VALUES('$login', '$password')"; $result=mysql_query($query, $link) or die("Died inserting login info into db. Error returned if any: ".mysql_error()); return true; } // end func newUser($login, $pass) /******************************************************\ * Function Name : displayErrors($messages) * * Task : display a list of errors * * Arguments : array $messages * * Returns : none * \******************************************************/ function displayErrors($messages) { /* Error Handling functions: An error handling function is useful to have in any project. This particular function takes an array of messages, and for each message displays it in a list using HTML <ul><li></li></ul> tags. */ print("<b>There were problems with the previous action. Following is a list of the error messages generated:</b>\n<ul>\n"); foreach($messages as $msg){ print("<li>$msg</li>\n"); } print("</ul>\n"); } // end func displayErrors($messages) /******************************************************\ * Function Name : checkLoggedIn($status) * * Task : check if a user is (isn't) logged in depending on $status * * Arguments : quasi(!) boolean $status - "yes" or "no" * * Returns : * \******************************************************/ function checkLoggedIn($status){ /* Function to check whether a user is logged in or not: This is a function that checks if a user is already logged in or not, depending on the value of $status which is passed in as an argument. If $status is 'yes', we check if the user is already logged in; If $status is 'no', we check if the user is NOT already logged in. */ switch($status){ // if yes, check user is logged in: // ie for actions where, yes, user must be logged in(!) case "yes": if(!isset($_SESSION["loggedIn"])){ header("Location: login.php"); exit; } break; // if no, check NOT logged in: // ie for actions where user can't already be logged in // (ie for joining up or logging in) case "no": /* The '===' operator differs slightly from the '==' equality operator. $a === $b if and only if $a is equal to $b AND $a is the same variable type as $b. for example, if: $a="2"; <-- $a is a string here $b=2; <-- $b is an integer here then this test returns false: if($a===$b) whereas this test returns true: if($a==$b) */ if(isset($_SESSION["loggedIn"]) && $_SESSION["loggedIn"] === true ){ header("Location: members.php"); } break; } // if got here, all ok, return true: return true; } // end func checkLoggedIn($status) /******************************************************\ * Function Name : checkPass($login, $password) * * Task : check login/passwd match that stored in db * * Arguments : string($login, $password); * * Returns : array $row - array of member details on success * false on failure \******************************************************/ function checkPass($login, $password) { /* Password checking function: This is a simple function that takes the $login name and $password that a user submits in a form and checks that a row exists in the database whe the value of the 'login' column is the same as the value in $login and the value of the 'password' column is the same as the value in $password If exactly one row is returned, then that row of data is returned. If no row is found, the function returns 'false'. */ global $link; $query="SELECT login, password FROM users WHERE login='$login' and password='$password'"; $result=mysql_query($query, $link) or die("checkPass fatal error: ".mysql_error()); // Check exactly one row is found: if(mysql_num_rows($result)==1) { $row=mysql_fetch_array($result); return $row; } //Bad Login: return false; } // end func checkPass($login, $password) /******************************************************\ * Function Name : cleanMemberSession($login, $pass) * * Task : populate a session variable * * Arguments : string $login, string $pass taken from users table in db. * * Returns : none * \******************************************************/ function cleanMemberSession($login, $password) { /* Member session initialization function: This function initializes 3 session variables: $login, $password and $loggedIn. $login and $password are used on member pages (where you could allow the user to change their password for example). $loggedIn is a simple boolean variable which indicates whether or not the user is currently logged in. */ $_SESSION["login"]=$login; $_SESSION["password"]=$password; $_SESSION["loggedIn"]=true; } // end func cleanMemberSession($login, $pass) /******************************************************\ * Function Name : flushMemberSession($session) * * Task : unset session variables and destroy session * * Arguments : array $session * * Returns : true * \******************************************************/ function flushMemberSession() { /* Member session destruction function: This function unsets all the session variables initialized above and then destroys the current session. */ // use unset to destroy the session variables unset($_SESSION["login"]); unset($_SESSION["password"]); unset($_SESSION["loggedIn"]); // and use session_destroy to destroy all data associated // with current session: session_destroy(); return true; } // send func flushMemberSession() /******************************************************\ * Function Name : doCSS() * * Task : output the CSS for the screens * * Arguments : * * Returns : * \******************************************************/ function doCSS() { /* CSS Output: This function simply outputs some cascading style sheet data for markup by the user's browser. */ ?> <style type="text/css"> body{font-family: Arial, Helvetica; font-size: 10pt} h1{font-size: 12pt} </style> <?php } // end func doCSS() # function validates HTML form field data passed to it: function field_validator($field_descr, $field_data, $field_type, $min_length="", $max_length="", $field_required=1) { /* Field validator: This is a handy function for validating the data passed to us from a user's <form> fields. Using this function we can check a certain type of data was passed to us (email, digit, number, etc) and that the data was of a certain length. */ # array for storing error messages global $messages; # first, if no data and field is not required, just return now: if(!$field_data && !$field_required){ return; } # initialize a flag variable - used to flag whether data is valid or not $field_ok=false; # this is the regexp for email validation: $email_regexp="^([a-zA-Z0-9_\-\.]+)@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.)|"; $email_regexp.="(([a-zA-Z0-9\-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)$"; # a hash array of "types of data" pointing to "regexps" used to validate the data: $data_types=array( "email"=>$email_regexp, "digit"=>"^[0-9]$", "number"=>"^[0-9]+$", "alpha"=>"^[a-zA-Z]+$", "alpha_space"=>"^[a-zA-Z ]+$", "alphanumeric"=>"^[a-zA-Z0-9]+$", "alphanumeric_space"=>"^[a-zA-Z0-9 ]+$", "string"=>"" ); # check for required fields if ($field_required && empty($field_data)) { $messages[] = "$field_descr is a required field."; return; } # if field type is a string, no need to check regexp: if ($field_type == "string") { $field_ok = true; } else { # Check the field data against the regexp pattern: $field_ok = ereg($data_types[$field_type], $field_data); } # if field data is bad, add message: if (!$field_ok) { $messages[] = "Please enter a valid $field_descr."; return; } # field data min length checking: if ($field_ok && ($min_length > 0)) { if (strlen($field_data) < $min_length) { $messages[] = "$field_descr is invalid, it should be at least $min_length character(s)."; return; } } # field data max length checking: if ($field_ok && ($max_length > 0)) { if (strlen($field_data) > $max_length) { $messages[] = "$field_descr is invalid, it should be less than $max_length characters."; return; } } } ?> The db has an table users with id, login, password, site Question how can i get inf from "site" raw for logged user on members.php ( as a link). Pls help thanks Ok I was wondering is there a way I can select a mysql database, and order it but only show data of a certain criteria: for example Mysql database: ID | User | XP | Won | Lost 1 Freid 100 1 4 2 Smic 300 5 4 3 Retna 300 3 2 4 OBW 200 3 2 And then some php code that will retrieve this information but only display the users that have lost = 4 in a list. In other words some php code that will only list the players Freid and Smic from the msql database becuase they have Lost = 4 the code would not show Retna or OBW becuase there Lost is not = to 4 Any help would be great thanks Freid001 I have a few tables in a project and i'm linking pages together via PK/FK's. i have a main table with client names, ID, CLIENT NAME, ETC i have a table with communications COMMID, ID, CONTACT NAMES, ETC and another of communication history. COMMHISTORYID, COMMID, DATE, TIME, ETC I'm not sure how to write the query so that i can view/update information from all 3 tables on the same webpage page using php/mysql. I'd appreciate any assistance you may provide. thanks. i have a mysql table which contains name like mid mname 101 AAA 102 BBB 103 CCC now i have to print this name in a html table like AAA, BBB, CCC i am getting this by while loop in a variable but when loop changes then value also change so please tell me how i get this only in one variable & print |