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PHP - Unable Get Values From $_session, Error Msg Is Notice: Undefined Variable: _session
First let me explain my code. This is later included in project_status.php] . In project_status.php] , I have included another file project_status_app.php which contains a HTML form.
<?php
include 'inc_fn_header_and_menu.php';
function includeFile($file,$variable) {
$var = $variable;
include($file);
}
if (isset($_GET['id']) && $_GET['id']!="") {
$pid = $_GET['id'];
$_SESSION['pidForApproval'] = $_GET['id'];
$query = 'SELECT * FROM `profile` WHERE pid ='.'\''.$pid.'\'';
$result=mysqli_query($db,$queryToRetrievePP) or die("There are no records to display ... \n" . mysqli_error());
foreach ($result as $row) {
$status = $row['status'];
}
}
...........some PHP and HTML code.......
<div id="customerPurchaseApprovalForm">
<?php
echo '<p>APPROVAL FOR CUSTOMER PURCHASE</p>';
$discountApprovalStatus = "Granted";
if ($discountApprovalStatus == "Granted") {
includeFile("project_status_app.php",$highestannualvalue);
} else {
//.........
}
In project_status_app.php I am attempting to retrieve pidForApproval from the $_SESSION array.
<?php
// put your code here UPDATE `pp` SET `customer_purchase_remarks` = 'hahaha' WHERE `pp`.`id` = 207;
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
include '../../inc/fastlogin.php';
$sql = "UPDATE pp SET customer_purchase_remarks ='{$_POST['remarkstxt']}' WHERE pp.pid='{$_SESSION['pidForApproval']}'";
$result = mysqli_query ( $fastdb, $sql ) ;
if (mysqli_affected_rows($fastdb) != 1) {
$_SESSION['err_cpa_rmks'] = "<p>Error while updating WHERE id='{$_SESSION['pidForApproval']}'</p>";
//echo "<p>Error while updating WHERE id='{$_POST['pidForApproval']}'</p>".mysqli_error($fastdb);
} else {
$_SESSION['suc_cpa_rmks'] = "<p>Records was updated successfully.</p>";
//echo "Records was updated successfully.";
}
header ("location: project_status.php?id="$_SESSION['pidForApproval']);
exit();
}
?>
When I load project_status.php, project_status_app.php is supposed to display the form. Once the user fills in the form the and the submit button has been pressed, the UPDATE statement is supposed to run and then it is supposed to navigate back to project_status.php?id=FA142. But the update is failing and the when the project_status.php is loaded back, the url looks like this http://localhost/fast/project_status.php?id= . The id is empty. It is supposed to be something like this http://localhost/fast/project_status.php?id=FA142. With the id being populated at the
header ("location: project_status.php?id=".$_SESSION['pidForApproval']);
Missing some information. Similar TutorialsHello i am new to this forum and coding. I am trying to fix a auto torrent downloading script which is php and curl. I have been stucked with Undefined offset error. Your help will be very appretiated, thanks. Starting download: Mp3-data1 Notice: Undefined variable: temp in /var/www/html/torrents/bgrahul2.php on line 338 Array ( => HTTP/1.1 200 OK Server: Transmission Content-Type: application/json; charset=UTF-8 Date: Wed, 21 Sep 2011 19:58:44 GMT Content-Length: 49 {"arguments":{"torrents":[]},"result":"success"} [1] => ) Marked those lines to bold Quote $result = callTransmission(array("filename" => "/var/www/html/donofwarez/xxx/torrents/$torrentfile", "download-dir" => "/home/Downloads/$title/"), "torrent-add", $arr[1]); callTransmission(array("seedRatioLimit" => 50, "seedRatioMode" => 1), "torrent-set", $arr[1]); /* echo "<pre>"; print_r($result); echo "</pre>"; */ if (preg_match('/"percentDone":[0-9.]+/i', $result[0], $matches)) $temp = str_replace('"id":', "", $matches[0]); // $temp="hlDr1wqu2ONtM3McVGHoVzfrkp2UgUcGwDt66IuxAe0LBkru"; $id[0] = $temp; //***OMG! We need the ids as integers! *** foreach ($id as $key => $value) { $id[$key] = (int) $value; } hi, I need help really badly for my PHP-Postcard Script. Basically it sends the card out but the URL does not work, I get the following error message: The URL is not valid and cannot be loaded It also states that Notice: Undefined index: www.voluntary.awardspace.co.uk in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 Notice: Undefined index: Postcard.php in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 See Code below: <?php session_start(); //check error log ini_set('display_errors', 1); ini_set('log_errors', 1); ini_set('error_log', dirname(__FILE__) . '/error_log.txt'); error_reporting(E_ALL); // CHANGE PARAMETERS HERE BEGIN $senderName = " Holidays From Home "; // Eg.: John's Postcards $senderEmail = "chris01@voluntary.awardspace.co.uk"; // Eg.: john@postcard.com // Change only if you have problems with urls $postcardURL = "http://".$_SERVER["www.voluntary.awardspace.co.uk"].$_SERVER["Postcard.php"]; // CHANGE PARAMETERS HERE END $result = 0; $msg = ""; $msg1 = ""; $pic = ""; function displayPhotos() { global $pic; $columns = 5; $act = 0; $act1 = 0; // Open the actual directory if($handle = opendir("thumbs")) { // Read all file from the actual directory while($file = readdir($handle)) { if(!is_dir($file)) { if(isset($pic[1])) { if($pic[1] == $act1){$sel = "checked";} else{$sel = "unchecked";} } if($act == 0){echo "<tr>";} echo "<td align='center'><img src='thumbs/$file' alt='postcard'/><br/><input type='radio' name='selimg' value='$file,$act1' $sel/></td>"; $act++; $act1++; if($act == $columns){$act = 0;echo "</tr>";} } } echo "</tr>"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd"> <html> <head> <title>Micro Postcard</title> <link href= "style/style.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="main"> <div class="style1" id="caption"> <div align="left" class="style1"></div> </div> <?php //makes sure form is correctly filled in if(!empty($_POST["submit"])) { if(empty($_POST["selimg"])){$msg = "Please select an image from above!";$result = 3;} else{$pic = explode(",",$_POST["selimg"]);} if(empty($_POST["email"]) && empty($result)){$msg1 = "You must enter an email address!";$result = 3;} $secCode = empty($_POST["secCode"]) ? "" : strtolower($_POST["secCode"]); if($secCode == $_SESSION["securityCode"] && $result != 3) { $filename = date("YmdGis"); $f = fopen("messages/".$filename.".txt","w+"); fwrite($f,$pic[0]."\n"); fwrite($f,$_POST['email']."\n"); fwrite($f,stripslashes($_POST["message"])."\n"); fclose($f); // Compose the mail $from = "From: $senderName <$senderEmail>\r\n"; $replay = "Reply-To: $senderEmail\r\n"; $params = "MIME-Version: 1.0\r\n"; $params .= "Content-type: text/plain; charset=iso-8859-1\r\n"; $mailtext = "You have just received a Virtual Postcard!\r\n\r\n You can pick up your postcard at the following web address:\r\n $postcardURL?show=$filename\r\n\r\n We hope you enjoy your postcard, and if you do, please take a moment to send a few yourself!\r\n\r\n Regards,\r\n Holidays From Home\r\n $postcardURL"; // Send email @mail($_POST["email"],"You've received a postcard",$mailtext,$from.$replay.$params); echo "<center> Your postcard was sent successfully!<br /><br /> <img src='images/$pic[0]' alt='postcard' /><br /><br /><br />".stripslashes($_POST["message"]). "</center>"; $result = 1; } else{if($result != 3){$result = 2;}} } if(!empty($_GET["show"])) { $file = $_GET["show"]; $content = file("messages/$file.txt"); $pic = $content[0]; unset($content[0]); unset($content[1]); foreach($content as $value){$main .= $value;} echo "<center> Your postcard!<br /><br /> <img src='images/$pic' alt='postcard' /><br /><br /><br />$main </center>"; } if((empty($result) || $result == 2 || $result == 3) && empty($_GET["show"])) { echo "<form action='#' method='post'> <table align='center'>"; displayPhotos(); echo "</table> <div style='color:#f00;font-size:16px;'>$msg</div> <h2>Fill in the Form and then click on Send Card!!</h2> <table width='100%'> <tr><td>Send to (email address):</td><td><div style='color:#f00;font-size:16px;'>$msg1</div><input type='text' name='email' size='30' value='".$_POST["email"]."' /></td></tr> <tr><td>Message:</td><td><textarea name='message' rows='10' cols='40'>".stripslashes($_POST["message"])."</textarea></td></tr> <tr><td colspan='2'>".($result == 2 ? "<p style='color:#f00;font-size:16px;'>Sorry the security code is invalid! Please try it again!</span></p>" : " ")."</tr> <tr> <td>Security code: <input class='text' name='secCode' type='text' size='10' /> </td><td><img src='securityCode.php' alt='security code' border='1' /></td> </tr> <tr><td colspan='2'> </tr> <tr><td colspan='2' align='left'><input type='submit' value='Send card!' name='submit'/></td></tr> </table> </form>"; } ?> Absolutely any help would be much appreciated. I want ot know is there a way round this problem? Here is the http://voluntary.awardspace.co.uk/Postcard.php I am absolutely desperate to solve this burning issue Code: [Select] Notice: Undefined variable: page in C:\Program Files (x86)\EasyPHP5.2.10\www\admin.php on line 119 That line is: <?php session_start(); $_SESSION['prev_page'] = $_SERVER['REQUEST_URI']; if (!session_is_registered('username')) { header("location:login.php"); } ?> <hr> <style type="text/css"> table.gridtable { color:#333333; border-width: 1px; border-color: #666666; border-collapse: collapse; width: 100%; } table.gridtable th { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; background-color: #dedede; } table.gridtable td { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; } .valid { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; background-color: transparent; } </style> </div> <div class="newsJustify"> <script type="text/javascript"> function checkall(delchk) { for (i = 0; i < delchk.length; i++) delchk[i].checked = true; } </script> <script type="text/javascript"> function uncheckall(delchk) { for (i = 0; i < delchk.length; i++) delchk.checked = false; } </script> <script language="JavaScript"> function loadPage(list) { location.href=list.options[list.selectedIndex].value } </script> <?php mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("chat") or die(mysql_error()); if (isset($_POST['del'])) { for ($count = 0; $count < count($_POST["delchk"]); $count++) { $delete = $_POST["delchk"][$count]; $query = "DELETE FROM members_shouts WHERE id = '$delete'"; $result = mysql_query($query); if (!$result) { die("Error deleting accounts! Query: $query<br />Error: " . mysql_error()); } } } $data = mysql_query("SELECT * FROM `members_shouts`") or die(mysql_error()); $rows = mysql_num_rows($data); if (isset($_GET['limit'])) { $page_rows = $_GET["limit"]; if ($page_rows == '') { $page_rows = 5; // no double quotes (int) } elseif ($page_rows == 'all') { $page_rows = $rows; } else { $page_rows = $_GET['limit']; /* validate this */ } if (!isset($_GET['pagenum'])) { $page = 1; } else { $page = (int) $_GET['pagenum']; } } else { $page_rows = 10; } ?> <?php $max_pages = ceil($rows / $page_rows); $last = ceil($rows / $page_rows); $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1; $max = 'limit ' . ($pagenum - 1) * $page_rows . ',' . $page_rows; $data_p = mysql_query("SELECT * FROM members_shouts $max") or die(mysql_error()); ?> <?php $result = mysql_query("SELECT * FROM members_shouts"); if (mysql_num_rows($result) > 0) { ?> <span style="float: left;margin-left: 2px;"> <form> <select name="file" size="1" onchange="loadPage(this.form.elements[0])" target="_parent._top"> <option value="" <?php if ($page_rows == 0) { echo 'selected'; } ?>>Select Limit</option> <option value="?limit=9" <?php if ($page_rows == 9) { echo 'selected'; } ?>>9</option> <option value="?limit=15" <?php if ($page_rows == 15) { echo 'selected'; } ?>>15</option> <option value="?limit=30" <?php if ($page_rows == 30) { echo 'selected'; } ?>>30</option> <option value="?limit=all" <?php if ($page_rows == 'all') { echo 'selected'; } ?>>All</option> </select> </form> </span> <span style="float: right;margin-top: 2px;margin-right: 2px;"> <center> <?php if ($pagenum == 1) { } else { echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1&limit={$page_rows}'>First</a> "; echo " | "; echo " "; $previous = $pagenum - 1; $current = $pagenum; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous&limit={$page_rows}'>$previous</a> "; echo " | "; } echo "$pagenum"; if ($pagenum == $last || $last == 0) { } else { $next = $pagenum + 1; echo " | "; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next&limit={$page_rows}'>$next</a> "; echo " "; echo " | "; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last&limit={$page_rows}'>Last</a> "; } ?> </center> </span> <style type="text/css"> .clear2 { clear:both; height:0px; overflow:hidden; } </style> <div class="clear2"></div> <hr> <?php echo "<table class=\"gridtable\"> <thead> <tr> <th align=\"center\" scope=\"col\">user</th> <th align=\"center\" scope=\"col\">message</th> <th align=\"center\" scope=\"col\">when</th> <th align=\"center\" scope=\"col\">Delete?</th> </tr> </thead> <tbody>"; echo "<form name = 'myform' action='' method='post'>"; ?> <?php while ($info = mysql_fetch_array($data_p)) { echo "<tr align=\"center\">"; echo "<td class=\"valid\" >" . $info['user'] . "</td>"; echo "<td class=\"valid\" >" . $info['message'] . "</td>"; echo "<td>" . $info['when'] . "</td>"; echo '<td><input type="checkbox" id="delchk" name="delchk[]" value="' . $info['id'] . '" /></td>'; echo "</tr>"; } echo "</tbody>"; echo "</table>"; echo "<hr>"; echo "<input type='submit' name = 'del' value='Delete Selected'></form>"; echo "<input type='button' onclick='checkall(document.myform[\"delchk\"]);' value='Select All'>"; echo "<input type='button' onclick='uncheckall(document.myform[\"delchk\"]);' value='Deselect All'>"; echo "<hr>"; ?> <?php } else { // No rows were found ... echo '<center>No logged accounts.</center><hr>'; } ?> </hr> The line its refferring too is: $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1;[/QUOTE] in this block: $max_pages = ceil($rows / $page_rows); $last = ceil($rows / $page_rows); $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1; $max = 'limit ' . ($pagenum - 1) * $page_rows . ',' . $page_rows; $data_p = mysql_query("SELECT * FROM members_shouts $max") or die(mysql_error()); [/i] Hello everyone, I am working on a form that is similar to a shopping cart system and I am thinking of creating a button that submits the checked value and saves them to a $_SESSION variable. And also a link that links to a cart.html that takes the values of a $_SESSION variable. I am have trouble figuring what tag/attribute should I use in order to achieve that.
Right now my code attached below submits the checked values to cart.html directly. However I want my submit button to save the checked box to a $_SESSION variable and STAY on the same page. And then I will implement a <a> to link to the cart.php.
I researched a little bit about this subject and I know it's somewhat related to ajax/jquery. I just wanted to know more about it from you guys. I appreciate your attention for reading the post and Thanks!
Below is the form that I currently have:
<form name= "finalForm" method="POST" action="cart.php">
<input type="Submit" name="finalSelected"/>
<?php foreach($FinalName as $key => $item) {?>
<tr>
<td><input type="checkbox" name="fSelected[]" value="<?php echo htmlspecialchars($FinalID[$key])?>" />
<?php echo "$FinalID[$key] & $item";?>
</td>
</tr>
<?php } ;?>
Below is the code for cart.php
<?php
require ('connect_db.php');
if(isset($_POST['finalSelected']))
{
if(!empty($_POST['fSelected']))
{
$chosen = $_POST['fSelected'];
foreach ($chosen as $item)
echo "aID selected: $item </br>";
$delimit = implode(", ", $chosen);
print_r($delimit);
}
}
if(isset($delimit))
{
$cartSQL = "SELECT * from article where aID in ($delimit)";
$cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc));
while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH))
{
$aTitle[] = $row[ 'name' ];
}
}
?>
<table>
<?php if(isset($delimit)) {
$c=0; foreach($aTitle as $item) {?>
<tr>
<td>
<?php echo $aTitle[$c]; $c++;?>
</td>
</tr>
<?php }}?>
</table>
I am trying to create a history of requested URI's (upto 3) for two purposes Login page and Error Logging. My problem is the Session is written and the values are set yet i can not retrieve the values in it upon a refresh. The use of an Array is to manage the quantity of max values (not written in yet).
<?phpSession contains
REQUEST_URI|a:1:{i:0;s:19:"1422925783,/~Debug/";}
After a refresh i expect
REQUEST_URI|a:2:{i:0;s:19:"1422925783,/~Debug/";i:1;s:28:"1422925784,/~Debug/index.php";}
Yet it only contains
REQUEST_URI|a:1:{i:0;s:28:"1422925784,/~Debug/index.php";}
Is there a way to make it
How can I go about removing a $_SESSION entity if certain array values of it equal a specific value? I am thinking something along the lines of this: if (isset($_SESSION['cart']['content'][$_POST['id']])) = array ('sizes' => 0, 'sizem' => 0, 'sizel' => 0, 'sizexl' => 0) { // remove $_SESSION['cart']['content'][$_POST['id']] } Code: [Select] <?php function Login() { session_start(); $_SESSION["loggedin"] = true; echo "You are logged in!"; header("Location: ../L_index.php"); //Aka Logged in Index. } function Logout() { $_SESSION["loggedin"] = false; session_destroy(); } function checklogin() { session_start(); if ($_SESSION["loggedin"] == true) { return true; } else { return false; } } ?> This is just a tiny bit of my code, there is security holes, but as you see, there is 3 functions: Login Logout Checklogin But when i use the Login function, everything is fine, but if i then use the checklogin, then it always returns true(it returns true after i used the logout function), why? Hi all, here's my code: Code: [Select] <?php foreach ($_SESSION['topping'] as $value) { echo "<tr><td width='30%'>Topping</td><td width='50%'>$value</td><td width='20%'><select name='notopping'>"; foreach ($_SESSION['cupcake'] as $number) { '<option name="notoppings[]" value="'.$number.'">".$number."</option>'; } echo "</select></td></tr>"; } ?> $_SESSION['cupcake'] is a value from either 6, 12, 24 or 36. What I want to do is put them into a drop down box (second foreach) as the value and the displayed value - counting up from 1 (so 1,2,3,4,5,6 or up to 12,24 etc). Also by creating this as an array, does this mean than for each topping (say Vanilla and Chocolate) the value dynamically created can be used on the next page by using $_POST['notoppings'] to display each type (two different numbers - one for Vanilla and one for Chocolate). Does that make sense? Thanks! Jason Quote Hi guys, I have a question, I have a fairly large site wich we have resellers for, but in certain circumstances for admin purposes, we need to be able to login under the same credentials EG: I might be doing something on one machine and i need to log in on another machine to do something else but with my user name and pass At the moment when i try to to this It will log out the session already logged in when i try to log in from the other machine Is there away around this,, i suspect that when i log in from the other machine its ending the first session Any Idears Guys and Gals..... really stuck I just ran into grief while trying to store a DateTime object in the SESSION variable. When I tried to use the stored value I got the error message "The DateTime object has not been correctly initialized by its constructor." I initially assumed that objects can't be stored in SESSION because there's no way to serialize and deserialize them for storage between scripts. But I've found posts by other people who have done this with without problems. If it works for others, why isn't it working for me? Is there something special about the DateTime class that prevents the PHP engine from serializing it? Here's a little script that demonstrates the problem (in PHP 5.2.5 under Windows XP): Code: [Select] <?php session_start(); if ( key_exists( 'd', $_SESSION ) ) { $d = $_SESSION['d']; echo "<br/>The value of 'd' is " . $d->format('m/d/Y'); } else { echo "'d' has no value yet."; } $d = new DateTime('2011-08-01'); $_SESSION['d'] = $d; $e = $_SESSION['d']; echo "<br/>The value of 'd' has been set to " . $e->format('m/d/Y'); ?> The first time the script is run it does not display "The value of 'd' is..." because $_SESSION['d'] does not exist. It sets the value, then retrieves it intact and displays it. The second time the script is run it tries to retireve the value but apparently gets an invalid one and displays the error. Then it sets, retrieves, and displays the value again. I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); Hello all - am looking for help with dynamic links in PHP not returning data and coughing out "Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200" The initial search is being fed from a mysql into table of results in another page ('ViewMore' being a column in my database and 'UniversityCourses' being the trigger to search that column):
echo "<td class='result'><a href='Uni More Info.php?ID={$row['UniversityCourses']}'>{$row['ViewMore']}</a></td>";
This is working fine as I can see the various links changing when you hover over them in the table. clicking the links goes to "Uni More Info.php" where my PHP code is:
<?php
session_start();
ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL);
//Connect to the database
$mysqli = new mysqli("localhost", "jj3wg2td_wix", "MYPASSWORD", "MYDATABASE");
if(isset($_GET['post'])){
$ID=mysqli_real_escape_string($mysqli, $_GET['ID']);
$sql="SELECT * FROM uni2020 WHERE UniversityCourses='$ID'";
$result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql");
$row=mysqli_fetch_array($result);
if(isset($_GET['post'])){
$Website=mysqli_real_escape_string($mysqli,$_GET['Website']);
$UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']);
$OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']);
$sql= "INSERT INTO UniversityCourses (Website, UcasPointsRequired) VALUES ('$Website', $UcasPointsRequired');";
$result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql");
}
}
?>
<content>
<?php echo $row['Website']?>
<?php echo $row['UcasPointsRequired']?>
<?php echo $row['OverallScore']?>
</content>
The error codes are showing:
Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200 Which is the section in-between the <content></content> tags. Reading up into "Undefined Variable", it suggest that I havent "Declared the variables", but isn't that this section?:
if(isset($_GET['post'])){
$Website=mysqli_real_escape_string($mysqli,$_GET['Website']);
$UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']);
$OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']);
I am new to PHP and am learning as I go along....but yet again...I'm stumped! Any help is very much appreciated (again)!!!!
Steven I'm getting the following notice: Notice: Undefined variable: TotaalBerichten in C:\Users\Sander\Documents\**********************\index.php on line 60 Is it because it is in the IF? The code: //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} EDIT: translated to english If i modify it to: $TotaalBerichten=0; /////////////ADDED //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); echo $TotaalBerichten; //////////////////////////////////////////////////////////////////////////ADDED //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} The $TotaalBerichten is '0' while there IS a message in the database??? I don't know why I am getting an undefined variable when the url is define. look at the deleteid=6 it means it is defined and in the code it is written as below URL Quote http://www.ppp.com/storeprueba/storeadmin/inventory_list.php?deleteid=6 Code: [Select] <?php if(isset($_GET['deleteid'])){ //which is clearly active in the url then get it, /* line 27 ===> */ echo'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; exit(); } if (isset($_GET['yesdelete'])) { // remove item from system and delete its picture // delete from database $id_to_delete = $_GET['yesdelete']; $sql = mysql_query("DELETE FROM products WHERE id='$id_to_delete' LIMIT 1") or die (mysql_error()); // unlink the image from server // Remove The Pic ------------------------------------------- $pictodelete = ("../inventory_images/$id_to_delete.jpg"); if (file_exists($pictodelete)) { unlink($pictodelete); } header("location:inventory_list.php"); exit(); } ?> the echo Code: [Select] <?php echo 'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; ?> won't display the . $GET ['deleteid'] . after "Do you really want to delete product with ID of which is 6 but it won't display the number six with the actual configuration, instead it display it like Quote Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Do you really want to delete pdoruct with ID of ? Yes | No Notice not number in between 'ID of' and '?' Hello! Help me please!
My site nice work on php version 5.2.12, but now php version is changed to 5.2.17 and some code is not working.
It showing error:
"Notice: Undefined variable: newCode in ....../humancheck.php on line 29"
In file humancheck.php on line 29:
for($i=0; $i<$config_max_digits;$i++) $newCode = $newCode.rand(0,9);This variable, it seems, taken from another file - humancheck_showcode.php: session_start(); $newCode = $HTTP_SESSION_VARS["newCode"];And, in index.php file at the beginning of the file written:
require ('human_check/humancheck.php');
And, in index.php file below is written:
<IMG src="humancheck_showcode.php">When I call the index.php file it shows error. So, I think, that variable "newCode" should be taken from file humancheck_showcode.php, but it don't do that. Code: [Select] <form method="post" action=""> <input type="input" name="user_name" /> <input type="submit" name="user_name_submit" /> </form> <?php if(!empty($_POST['user_name'])) $user_name = $_POST['user_name']; if(isset($_POST['user_name_submit'])) { $user_name_submit = $_POST['user_name_submit']; } $user_name_preg_match = preg_match('/[a-zA-Z0-9]/', $user_name); if($user_name_preg_match) { echo 'true'; } else { echo 'false'; } ?> In this script I am getting the notice: Code: [Select] Notice: Undefined variable: user_name Any suggestions how to avoid the notice in this case? Ik ben bezig met een gastenboek en snap de volgende foutmelding niet: Notice: Undefined variable: iCountFiles *************** regel 261 //Smilies toegestaan? if ($GetConfiguratie['smiley'] == 1) {$AfbeeldingenPerRegel = 12 ; if (!$rHandle = opendir('./images/smilies')) {$sP_Smilies = 'Geef de map "smilies" leesrechten!';} else {$sP_Smilies = ''; while (false !== ($sFile = readdir($rHandle))) {if (preg_match("/^([sa-zA-Z0-9]+){3}(:?\.gif|\.jpg)$/", $sFile)) { $sFileShort = preg_replace("/^([sa-zA-Z0-9]+)(:?\.gif|\.jpg)$/", "(\\1)",$sFile); $iCountFiles++ ; /////////////////////////////////////////////////////////////REGEL261 if ($iCountFiles % $AfbeeldingenPerRegel == 0) {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /><br />';} else {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /> ';} } } closedir($rHandle); } } hoe los ik dit het best op? code is Code: [Select] <?php $limit=12; if(isset( $_GET['page'])) $page=$_GET['page']; if($page<=0) $page = 1; else {$start=0;} $sql=mysql_query("select * from tbl_gallery where status=1 And category_name='0'"); $count=mysql_num_rows($sql); $totalcount=ceil($count/$limit);$start=($page-1)*$limit; $s=mysql_query("select * from tbl_gallery where status=1 And category_name='0' limit $start, $limit"); while($result=mysql_fetch_array($s)){ $start++; ?> please find the mistake hello all, i have ran into another issue i get this message when i go onto my homepage Notice: Undefined variable: layout in i have the following includes on the main index page: Code: [Select] <?php // Include Main Core File. include '_class/core.php'; // Include Config File include 'config/config.php'; include 'config/db.php'; // Use Database $obj->connect(); // Include library include '_class/library.php'; // Include layout include 'layout/index.php'; ?> on the config file i have the varible it is refering too: Code: [Select] <?php $layout = $url . "layout/"; ?> the actual file i get the error on (library.php) Code: [Select] <?php class library extends core { function advert() { /* * Name your images 1.jpg, 2.jpg etc. * * Add this line to your page where you want the images to * appear: <?php include "randomimage.php"; ?> */ // Change this to the total number of images in the folder $total = "2"; // Change to the type of files to use eg. .jpg or .gif $file_type = ".png"; // Change to the location of the folder containing the images $image_folder = $layout . "layout/images/adverts"; // You do not need to edit below this line $start = "1"; $random = mt_rand($start, $total); $image_name = $random . $file_type; echo "<img src=\"$image_folder/$image_name\" alt=\"$image_name\" />"; } } $obj = new library; ?> is there a way to make it so it $layout works on any page or file as long as its in the includes? thanks again. |
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