PHP - How Do I Retrieve Inserted Values From Mysql Database With Respect To A User Id In Php?
Am a newbie in php. Since I can't insert values to the database with respect to a user Id or with any other token using WHERE clause. I.e "INSERT INTO receipts(date) VALUES(example) where id="**....." If I need to fetch several values of column for a particular user, how do I go about it? Thank you!!! Similar Tutorials
Query About How To Retrieve A Password From The Database And Compare To The One The User Has Entered
Ugh. Ive been asking so many questions, betcha already know my name. Hahah. Anyways, I know I already asked a question like this, but this is different. One of the values I am trying to insert into a database is simply not working. Here is the columnes in my mysql database: c_id commet story user date_added star Every value but 'commet' is getting inserted into database. NO error, no mysql errror. I have racked my brain trying to figure out what is wrong with the script. Here is my code: Code: [Select] <?php $idget = $_GET['id']; mysqlConnect(); //submit story if(isset($_POST['submit'])) { $com_form = mysql_real_escape_string(bb($_POST['commet'])); $rat_form = $_POST['rat']; $story_form = $idget; $user = $_SESSION['user']; $date = date("Y-m-d"); $query1 = " INSERT INTO story_commets(star, story, user, date_added, commet) VALUES($rat_form, '$story_form', '$user', '$date', '$com_form') "; mysql_query($query1) or die(mysql_error()); //} } // desplay reviews $query3 = " SELECT * FROM story_commets WHERE story = '$idget' ORDER BY date_added "; $select3 = mysql_query($query3) or die(mysql_error()); //$x=1; $ratav = array(); //if(mysql_num_rows($select3) == 0) //{ echo '<div id="message"> No Reviews Yet.... <>'; //} //else //{ while($rows3 = mysql_fetch_assoc($select3)) { $commetdb = $rows3['commet']; $user_com_db = $rows3['user']; $datedb = $rows3['date_added']; $stardb = $rows3['star']; //get profile picture $query4 = " SELECT * FROM login_info WHERE user = '$user_com_db' "; $select4 = mysql_query($query4) or die(mysql_error()); $rows4 = mysql_fetch_assoc($select4) or die(mysql_error()); $profile_pic = $rows4['profile_picture']; $user_id = $rows4['id']; echo " <div class='rev_cont'> <div class='info'> <img src='$profile_pic' /> <a href=?p=profile&id=$user_id> $user_com_db </a> <> <br /> <div class='rev'> <strong> $stardb/10 </strong> <br /> $commetdb <> <div id='date'> <em> Date Added: $datedb </em> <> <> <hr /> "; $ratav[]=$stardb; } $sum = array_sum($ratav); $count = count($ratav); $av = $sum / $count; $avf = round($av, 1); echo"<div id='message'> Rating Avarage: $avf /10 <>"; //} if (isset($_SESSION['user'])) { echo" <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p> <form action='?p=review&id=$idget' method='post' target='_self'> <label> Your rating is on a scale of 1-10 </label> <select name='rat'> <option> 1 </option> <option> 2 </option> <option> 3 </option> <option> 4 </option> <option> 5 </option> <option> 6 </option> <option> 7 </option> <option> 8 </option> <option> 9 </option> <option> 10 </option> </select> <label> Commets: </label> <textarea name='commet' cols='70' rows='9'></textarea> <input name='story' type='hidden' value='$idget' /> <br /> <input type='submit' value = 'Post' name='submit' /> </form> "; } else { echo "<div id='message'> Sign in to post a review! <>"; } ?> Here are the specifics if you want it. Here is the response part of the code: Code: [Select] <?php if(isset($_POST['submit'])) { $com_form = mysql_real_escape_string(bb($_POST['commet'])); $rat_form = $_POST['rat']; $story_form = $idget; $user = $_SESSION['user']; $date = date("Y-m-d"); $query1 = " INSERT INTO story_commets(star, story, user, date_added, commet) VALUES($rat_form, '$story_form', '$user', '$date', '$com_form') "; mysql_query($query1) or die(mysql_error()); //} } ?> Here is the form part of my code: Code: [Select] <?php if (isset($_SESSION['user'])) { echo" <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p> <form action='?p=review&id=$idget' method='post' target='_self'> <label> Your rating is on a scale of 1-10 </label> <select name='rat'> <option> 1 </option> <option> 2 </option> <option> 3 </option> <option> 4 </option> <option> 5 </option> <option> 6 </option> <option> 7 </option> <option> 8 </option> <option> 9 </option> <option> 10 </option> </select> <label> Commets: </label> <textarea name='commet' cols='70' rows='9'></textarea> <input name='story' type='hidden' value='$idget' /> <br /> <input type='submit' value = 'Post' name='submit' /> </form> "; } else { echo "<div id='message'> Sign in to post a review! <>"; } ?> Its probably something really mundane. HelP! I AM WORKING ON A PROJECT , I NEED YOUR HELP. I WANT TO USE EXISTING SRC OF IFRAME + RETRIVED VALUE FROM DATABASE INTO IFRAME This is my data.php to retrive values from database into iframe without refresh web page.
<?php $conn = new mysqli('localhost', 'root', '', 'x'); if ($conn->connect_error) { die("Connection error: " . $conn->connect_error); } $result = $conn->query("SELECT number1 FROM users"); if ($result->num_rows > 0) { while ($row = $result->fetch_assoc()) { echo $row['number1'] . '<br>'; } } ?>
<?php include('data.php') ?> <html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> </head> <body> <div id="show"></div> <script type="text/javascript" src="jquery-3.1.1.min.js"></script> <script type="text/javascript"> $(document).ready(function() { setInterval(function () { $('#show').load('data.php') }, 1000); }); </script> <iframe id="w3" src="DATABASE RETRIVED VALUE" height="80px" width="300px" frameborder="0" style="border: 0; width:300px; height:80px; background-color: #FFF;"></iframe> </body> </html>
INDEX FILE CODES CAN SUCCESSFULLY RETRIVE VALUES FROM DATABASE BUT, I WANT TO STORE IT IN IFRAME SRC . VAR= URLS = 'HTTP://WWW.GOOGLE.COM' IFRAME SRC WILL BE VAR URLS + RETRIEVED VALUE FROM DATABASE
Hi, after following lots of advice and changing to MySqli I am running into a few probs. This is me just probably missing something stupid, I know what I want, but can't figure out what query I should use and where I should place it. All the queries I have tried have failed.
I just need a query that gets the $current_stored_password from the password field on the database, to confirm the last check
elseif ($current_password !== $current_stored_password) { include 'includes/overall/header.php'; echo $current_password . ' AND ' . $_POST['current_password'] . ' Password and password again do not match'; include 'includes/overall/header.php'; }Here is the whole script. <?php session_start(); error_reporting(0); //ini_set('display_errors', '1'); require( 'database.php' ); $username = $_SESSION['loggedinuser']; $current_stored_password = $_SESSION['password']; $current_password = $_POST['current_password']; $password = mysqli_real_escape_string($con, md5( $_POST['password'])); $password_again = mysqli_real_escape_string($con, md5( $_POST['password_again'])); // Run checks if (isset($_POST['current_password'], $_POST['password'], $_POST['password_again'])) { if( strlen( $_POST['current_password'] ) < 8 ) { include('includes/overall/header.php'); echo "Password Must Be 8 or More Characters."; include('includes/overall/footer.php'); } elseif( strlen( $_POST['password'] ) < 8 ) { include('includes/overall/header.php'); echo "Password Must Be 8 or More Characters."; include('includes/overall/footer.php'); } elseif ( strlen( $_POST['password_again'] ) < 8 ) { include('includes/overall/header.php'); echo "Password Must Be 8 or More Characters."; include('includes/overall/footer.php'); } elseif ($password !== $password_again) { include 'includes/overall/header.php'; echo ' Password and password again do not match'; include 'includes/overall/header.php'; } elseif ($current_password !== $current_stored_password) { include 'includes/overall/header.php'; echo $current_password . ' AND ' . $_POST['current_password'] . ' Password and password again do not match'; include 'includes/overall/header.php'; } else { // Define a query to run $query = "UPDATE `user` SET `password` = '$password' WHERE `username` = '$username'"; // Query the database $result = mysqli_query($con,$query); // Check if the query failed if( !$result ) { die('There was a problem executing the query ('.$query.'):<br>('.mysqli_errno($con).') '.mysqli_error($con)); } else { include 'includes/overall/header.php'; echo 'Password has been changed'; include 'includes/overall/footer.php'; } } } // Close the connection mysqli_close($con); ?>At the moment the message displayed when the form is submitted is echo $current_password . ' AND ' . $_POST['current_password'] . ' Password and password again do not match';How do I retrieve the password from the database to compare against the current password entered by the user? Any help is much appreciated. PS. Yes I know I have repeated code and that md5 is not secure, but I am just building onto a template I got and will be making changes to shorten the code and secure the password soon I am not sure if the title is correct; I tried my best.
I'm a PHP/MySQL beginner and I really need some help.
I have a small script that I am using for sending SMS. I recently added a phonebook. The problem with the phonebook right now is that it's available to all users, i.e. they can all update and delete all rows. What I would like to do is make it so that each user can update and delete only their own contacts.
I have a table call contacts. Inside that table there is first name, last name, company and phonenumber.
How can I accomplish this with PHP & MySQL?
CREATE TABLE IF NOT EXISTS `contacts` ( `contact_id` int(10) NOT NULL AUTO_INCREMENT, `firstname` varchar(255) NOT NULL, `lastname` varchar(255) NOT NULL, `company` varchar(255) NOT NULL, `cell_no` text NOT NULL, PRIMARY KEY (`contact_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; CREATE TABLE IF NOT EXISTS `users` ( `user_id` int(11) NOT NULL AUTO_INCREMENT, `users_name` varchar(30) NOT NULL, `uname` varchar(30) NOT NULL, `u_pass` varchar(60) NOT NULL, `utype` varchar(30) NOT NULL, `timezone` varchar(30) NOT NULL, `uapi_user` varchar(30) NOT NULL, `uapi_pass` varchar(60) NOT NULL, PRIMARY KEY (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; <?php if (isset($_POST['submit'])){ //form has been submitted1 $firstname = trim($_POST['firstname']); $lastname = trim($_POST['lastname']); $company = trim($_POST['company']); $cellno = trim($_POST['cell_no']); if($firstname == ''){ echo '<div class="alert alert-danger">First Name is not Valid!</div>'; exit; }elseif($lastname == ''){ echo '<div class="alert alert-danger">Last Name is not Valid!</div>'; exit; }elseif($company == ''){ echo '<div class="alert alert-danger">Company is not Valid!</div>'; exit; }elseif($cellno == ''){ echo '<div class="alert alert-danger">Cellphone Number is not Valid!</div>'; exit; }else{ $query = "Select cell_no from contacts where cell_no = '".$cellno."' "; $result = mysql_query($query); if (!mysql_num_rows($result)) { $sql = "INSERT INTO contacts(firstname, lastname, company, cell_no) values('{$firstname}','{$lastname}', '{$company}', '{$cellno}')"; $result = mysql_query($sql); confirm_query($result); //echo '<div class="alert alert-success">Successfully added.</div>'; //exit; ?> <script type="text/javascript"> window.location = "contact_list.php"; </script> <?php } else{ echo '<div class="alert alert-danger">Username. already exist!.</div>'; echo '<p><a href="new_contact.php" class="btn btn-success"> Back </a></p>'; exit; }} }else{ $firstname = ""; $lastname = ""; $company = ""; $cellno = ""; } ?> I have two pages - add_product.php and show.php here is the code for add_product.php Code: [Select] <?php ini_set('display_errors',1); error_reporting(-1); require_once ('./includes/config.inc.php'); require_once (MYSQL); $add_cat_errors = array(); if ($_SERVER['REQUEST_METHOD'] == 'POST') { // Check for a name: if (empty($_POST['product'])) { $add_cat_errors['product'] = 'Please enter the name!'; } // Check for a description: if (empty($_POST['prod_descr'])) { $add_cat_errors['prod_descr'] = 'Please enter the description!'; } // Check for a category: if (!isset($_POST['cat']) || !filter_var($_POST['cat'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['cat'] = 'Please select a category!'; } // Check for a price: if (empty($_POST['price']) || !filter_var($_POST['price'], FILTER_VALIDATE_FLOAT) || ($_POST['price'] <= 0)) { $add_cat_errors['price'] = 'Please enter a valid price!'; } // Check for a category: if (!isset($_POST['directory']) || !filter_var($_POST['directory'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['directory'] = 'Please select a directory!'; } // Check for a stock: if (empty($_POST['stock']) || !filter_var($_POST['stock'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['stock'] = 'Please enter the quantity in stock!'; } if (empty($add_cat_errors)) { $query = "INSERT INTO product (product, prod_descr, catID, price, dirID, stock) VALUES (?, ?, ?, ?, ?, ?)"; // Prepare the statement: $stmt = mysqli_prepare($dbc, $query); // For debugging purposes: // if (!$stmt) echo mysqli_stmt_error($stmt); // Bind the variables: mysqli_stmt_bind_param($stmt, 'sssssi', $name, $desc, $_POST['cat'], $_POST['price'], $_POST['directory'], $_POST['stock']); // Make the extra variable associations: $name = strip_tags($_POST['product']); $desc = strip_tags($_POST['prod_descr']); // Execute the query: mysqli_stmt_execute($stmt); if (mysqli_stmt_affected_rows($stmt) == 1) { // If it ran OK. // Print a message: echo '<h4>The product has been added!</h4>'; // Clear $_POST: $_POST = array(); // Clear $_FILES: $_FILES = array(); } else { // If it did not run OK. trigger_error('The product could not be added due to a system error. We apologize for any inconvenience.'); } } // End of $errors IF. } else { // Clear out the session on a GET request: } // End of the submission IF. require_once ('./includes/form_functions.inc.php'); ?> <form enctype="multipart/form-data" action="add_image.php?prodID={$row['prodID']}" method="post" accept-charset="utf-8"> <input type="hidden" name="MAX_FILE_SIZE" value="524288" /> Product<br /><?php create_form_input('product', 'text', $add_cat_errors); ?> Description<br /><?php create_form_input('prod_descr', 'textarea', $add_cat_errors); ?> Category<br /><select name="cat"<?php if (array_key_exists('cat', $add_cat_errors)); ?>> <option>Select One</option> <?php // Retrieve all the categories and add to the pull-down menu: $q = 'SELECT catID, cat FROM category ORDER BY cat ASC'; $r = mysqli_query ($dbc, $q); while ($row = mysqli_fetch_array ($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; // Check for stickyness: if (isset($_POST['cat']) && ($_POST['cat'] == $row[0]) ) echo ' selected="selected"'; echo ">$row[1]</option>\n"; } ?> </select><?php if (array_key_exists('cat', $add_cat_errors)) echo $add_cat_errors['cat']; ?> Price<br /><?php create_form_input('price', 'text', $add_cat_errors); ?> Directory<br /><select name="directory"<?php if (array_key_exists('directory', $add_cat_errors)); ?>> <option>Select One</option> <?php // Retrieve all the categories and add to the pull-down menu: $q = 'SELECT dirID, directory FROM directory ORDER BY directory ASC'; $r = mysqli_query ($dbc, $q); while ($row = mysqli_fetch_array ($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; // Check for stickyness: if (isset($_POST['directory']) && ($_POST['directory'] == $row[0]) ) echo ' selected="selected"'; echo ">$row[1]</option>\n"; } ?> </select><?php if (array_key_exists('directory', $add_cat_errors)) echo $add_cat_errors['directory']; ?> </select> <br /> Stock<br /><?php create_form_input('stock', 'text', $add_cat_errors); ?> <input type="submit" value="Add This Product" class="button" /> </fieldset> </form> and here is the code for show.php Code: [Select] <?php ini_set('display_errors',1); error_reporting(-1); require_once ('./includes/config.inc.php'); require_once (MYSQL); $add_cat_errors = array(); if($id = isset($_GET['prodID'])) { $q = "SELECT `prodID`, `product`, `prod_descr`, `catID`, `dirID`, `price`, `stock` FROM product WHERE `prodID`='{$_GET['prodID']}'"; $r = mysqli_query($dbc, $q); while($row = mysqli_fetch_array($r)) { echo $row['product']; echo "<br />"; echo $row['prod_descr']; echo "<br />"; echo $row['catID']; echo "<br />"; echo $row ['dirID']; echo "<br />"; echo $row['price']; echo "<br />"; echo $row['stock']; } } What I want is to try and retrieve the id of the last record inserted in add_product and pass it into show.php, but I get this error message. Quote An error occurred in script 'C:\Users\David Morgan\Desktop\WEBSITES\hairz_&_graces\site\admin\add_image.php' on line 16: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given I am struggling to find out where I am going wrong at the moment, if anyone could please help me that would be really appreciated. Hi, Im trying to retrieve HTML from a mysql database but nothing i've tried seems to work. The HTML im trying to retrieve is an iframe with a link and styles (code from amazon associates). Im trying to display links to specific products on amazon from the product page on my site. All data about the product is retrieved from the database so i have code to select the amazon link row in my database table but i cant get it to display. It says the html isnt a string so i cant echo it, fair enough. I have tried using the following code: Code: [Select] $get_buylink_sql = "SELECT mobo_buylink FROM mobo WHERE mobo_id = $mobo_id"; $get_buylink_res = mysqli_query($mysqli, $get_buylink_sql) or die(mysqli_error($mysqli)); while ($buylink = mysqli_fetch_array($get_buylink_res)) { echo"<iframe src=\"".$buylink."\" style=\"width:120px;height:240px;\" scrolling=\"no\" marginwidth=\"0\" marginheight=\"0\" frameborder=\"0\"></iframe>"; } mysqli_free_result($get_buylink_res); mysqli_close($mysqli);I have also tried putting the whole iframe code in the database which didnt work either. The mobo_id variable works fine for retrieving the rest of the data and i need to get the amazon link from the same record. I hope i've put this in a way you can understand, but if not i'll try and explain better and give you a link to my site if needed. Thanks, Alex Hello, Please could someone tell me how to retrieve an incremental variable from MYSQL as soon as it is inserted? (i.e. before another variable can be inserted) Many thanks. Stu Say I have the following text stored in a MySQL database... Code: [Select] <b>Classic Quote from movie</b> and I retrieve it into a variable called $text, how do I properly echo that so that it keeps the bold tags and actually display the text "Classic quote from movie" in BOLD? I'm doing something wrong somewhere along the line (simply doing "echo $text;") because it displays on the page as... Code: [Select] <b>Classic Quote from movie</b> Instead of... Classic Quote from movie Any info on properly storing and echoing back HTML would be very appreciated. i have 8 division (div), i want to display 4 rows in 4 division and the remain 4 rows in the next 4 division here is my code structure for carousel
<div class="nyie-outer"> second row third row
fourth row fifth row sixth row seven throw eighth row
</div><!--/.second four rows here-->
sql code
CREATE TABLE product( php code
<?php how can i echo that result in those rows
Hello.
I have a bit of a problem. When I fetch the link field from the database.i don't see an actual link on the page.
One more thing, what type of field should I use to store the link in the database? Probably there is where I went wrong.
All help is
whats wrong in here for i get query failed everytime i submit the form? Code: [Select] //Create INSERT query $qry = "INSERT INTO class_members (user_name, passwrd, f_name, l_name, email, gender, date) VALUES('$user_name','".md5($_POST['password'])."','$f_name','$l_name','$email', '$gender','gmdate($date)',)"; $result = @mysql_query($qry); //Check whether the query was successful or not if($result) { header("location: register-success.php"); exit(); }else { die("Query failed"); } I have created a button which when pressed should present the user with their details (whoever is logged in), here is the form code: <form id="form1" name="form1" method="post" action="getdetails.php"> <input type="submit" name="Get Details" value="Get Details" /> </label> </p> </form> Here is the getdetails.php file <?php mysql_connect("localhost","root",""); mysql_select_db("test"); $username = $_POST['textfield']; echo '</br>'; $query = mysql_query("SELECT * FROM membersdetails WHERE name=`$username` "); while($result = mysql_fetch_array($query)) { //display echo $result['firstname']; echo $result['surname']; } ?> Its not workin at all I have attacthed the error i am getting Any help please? hi guys, im new to this forum I'm new also to php, I need help from you guys: I want to display personal information from a certain person (the data is on the mysql database) using his name as a link: example: (index.php) names 1. Bill Gates 2. Mr. nice Guy i want to click Bill Gates (output.php) Name: Bill Gates Country:xxxx Age: xx etc. How can i make this or how to learn this? hi i had database with field of name,title,post,content i want to fetch the post and content for a specific user from giving name of that user by form help me to get that ps just give me idea to how to do that/ Code: [Select] <form id="form1" name="form1" method="post" action="view.php"> <label>Name <input type="text" name="textfield" /> </label> <p> <label> <input type="submit" name="Submit" value="Submit" /> </label> </p> </form> Hello there,
I'm really new at PHP and I've been reading several beginner tutorials so please accept my apologies for any stupid questions I may ask along the way.
I've gotten as far as installing XAMPP, set up a database plus PHP form and I'm struggling to figure out how to insert values from an array into my database.
I've learnt the code in one particular way (see beginner tutorials) so I was wondering if you could help me keeping this in mind. I know there'll be a million better ways to do what I'm doing but I fear I will be bamboozled with different code or differently structured code.
Anyway the tutuorials I'm reading don't see to cover how I can insert an array of values into my database, just singular values.
In the attached file, I have 10 rows of 2x text inputs (20 text inputs total). Each row allows the user to enter a CarID and CarTitle. I've commented out the jQuery which validates the inputs so I can build a rudimentary version of this validation with PHP.
I thought that because the line $sql="INSERT INTO carids_cartitles (CarID, CarTitle) VALUES ($id, $title)"; is inside the foreach, means that for each pair of values from the form it'd insert to the database.
It doesn't do this. If I enter two or more CarIDs and CarTitles, only one pair of values gets saved to the database.
I'm sorry if I haven't explained this well enough, any questions please let me know.
Many thanks for your help in advance.
Attached Files
form.php 4.43KB
5 downloads Hi, I have this form which will create a checkbox list using data from my database and also determin if a checkbox had been checked before and check if it had. <form style="text-align:center" name="PrefRestaurant" id="PrefRestaurant" action="preferances_check.php" method="post"><table align="center"> <?php checkbox(id, name, restaurants, id); ?></table> <input type="submit" name="Prefer" id="Prefer" value="Επιλογή"/></form> function checkbox($intIdField, $strNameField, $strTableName, $strOrderField, $strMethod="asc") { $strQuery = "select $intIdField, $strNameField from $strTableName order by $strOrderField $strMethod"; $rsrcResult = mysql_query($strQuery); while ($arrayRow = mysql_fetch_assoc($rsrcResult)) { $testqry = "SELECT * FROM user_restaurant WHERE user_id = $_SESSION[UserId] AND restaurant_id = $arrayRow[id]"; $rsltestqry = mysql_query($testqry); $numrows = mysql_num_rows($rsltestqry); if ($numrows == 1) { echo "<tr align=\"left\"><td><input type=\"checkbox\" name=\"restaurant[]\" value=\"$arrayRow[id]\" checked/>$arrayRow[name]</td></tr>"; } else{ echo "<tr align=\"left\"><td><input type=\"checkbox\" name=\"restaurant[]\" value=\"$arrayRow[id]\" />$arrayRow[name]</td></tr>"; } } } Now the part which I can't get to work is when I'm trying to store the new values in my database. When I click the submit button I clear my database of any row that is related to the currently loggedin user and I want to store his new preferences (checked cheboxes). I've read that only the cheked checkboxes' values are POSTed so I did this (preferances_check.php) foreach($_POST['restaurant'] as $value) { $query="INSERT INTO user_restaurant VALUES ('$_SESSION[UserId]','$value')"; } But it is not working, nothing gets written in my table Could someone please enlighten me on this? Thnks! I have posted one set of values into my database and it worked fine but when i input another set they wont go inside unless i changes the value of the primary index colum. I want to be able to insert a new values regardless of the primary index value. Any idears...? Here we go, I need to use a query where it uses a posted time value to compare if there are the same times on the posted date value. I want it so the user cant book the same time on the same day as someone before bascially. My input so far is this Code: [Select] <?php ob_start();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Conforming XHTML 1.0 Strict Template</title> <link rel="stylesheet" type="text/css" href="style.css" /> <link type="text/css" href="ui-lightness/jquery-ui-1.8.16.custom.css" rel="Stylesheet" /> <script type="text/javascript" src="js/jquery-1.6.2.min.js"></script> <script type="text/javascript" src="js/jquery-ui-1.8.16.custom.min.js"></script> </head> <body> <form name="input" action="input.php" method="post"> Subject: <input type="text" name="subject" /> First Name: <input type="text" name="firstname" /> Surname: <input type="text" name="surname" /> Trainer: <input type="text" name="trainer" /> Email: <input type="text" name="email" /> Date: <input type="text" name="event_date" id="date" /> Time: <input type="text" name="event_time" id="time" /> <input type="submit" value="Submit" name="submit" /> </form> <script type="text/javascript"> $('#date').datepicker(); $('#time').timepicker({}); </script> <?php include_once("functions/database.php"); include_once("functions/number.php"); if (isset($_POST["submit"])) { echo $_POST['event_date']; echo mdy2mysql($_POST['event_date']); echo $_POST['event_time']; echo time2mysql($_POST['event_time']); $queryselect = "SELECT * FROM events LIKE '".$_POST['event_time']."'"; if ($queryselect == true) { echo "sorry this time is already booked"; } else { $query = "INSERT INTO events (subject, firstname, surname, trainer, email, event_date, event_time, status) VALUES('".$_POST["subject"]."', '".$_POST["firstname"]."', '".$_POST["surname"]."','".$_POST["trainer"]."','".$_POST["email"]."' ,'".mdy2mysql($_POST['event_date'])."','".time2mysql($_POST['event_time'])."', 'pending' ) "; $result = mysql_query($query, $db_link) or die(mysql_error().'cannot get results!'); header("Location: input.php"); } ?> can anyone help me ? very much appreciated. Hi, I have created a session based logon system using php and MYSQL from some tutorials I found online which is working very successfully. I can log on and of and move through different pages with no problems. My query is how do I output or display the information that is specific to the user which is currently logged on and block access to any other users information. I am quite sure there is a simple solution that is escaping me. If you could point me in the right direction it would be greatly appreciated. Thanks in advance helllo dear php-commmunity new to Ruby - i need some advices - i plan to do some requests in osm-files. (openstreetmap) Question - how can i store the results on a Database - eg mysql or - (if you prefer postgresql) - note: my favorite db - at least at the moment is mysql here the code require 'open-uri' require "net/http" require 'rexml/document' def query_overpass(object_type, left,bottom,right,top, key, value) base_url = "http://www.overpass-api.de/api/xapi?" query_string = "#{object_type}[bbox=#{left},#{bottom},#{right},#{top}][#{key}=#{value}]" url = "#{base_url}#{URI.encode(query_string)}" resp = Net::HTTP.get_response(URI.parse(url)) data = resp.body return data end overpass_result = REXML::Document.new(query_overpass("node", 7.1,51.2,7.2,51.3,"amenity","restaurant|pub|ice_cream|food_court|fast_food|cafe|biergarten|bar|bakery|steak|pasta|pizza|sushi|asia|nightclub")) overpass_result.elements.each('osm/node') {|x| if !x.elements["tag[@k='name']"].nil? print x.elements["tag[@k='name']"].attributes["v"] end print " | " if !x.elements["tag[@k='addr:postcode']"].nil? print x.elements["tag[@k='addr:postcode']"].attributes["v"] print ", " end if !x.elements["tag[@k='addr:city']"].nil? print x.elements["tag[@k='addr:city']"].attributes["v"] print ", " end if !x.elements["tag[@k='addr:street']"].nil? print x.elements["tag[@k='addr:street']"].attributes["v"] print ", " end if !x.elements["tag[@k='addr:housenumber']"].nil? print x.elements["tag[@k='addr:housenumber']"].attributes["v"] end print " | " print x.attributes["lat"] print " | " print x.attributes["lon"] print " | " if !x.elements["tag[@k='website']"].nil? print x.elements["tag[@k='website']"].attributes["v"] end print " | " if !x.elements["tag[@k='amenity']"].nil? print x.elements["tag[@k='amenity']"].attributes["v"] print " | " end puts } look forward to hear from you again - i would love to store it on a mysql - database - if possible. If you would prefer postgresql - then i would takte this one.... ;-) look forward to hear from you again - i would love to store it on a mysql - database - if possible. If you would prefer postgresql - then i would takte this one.... ;-) well - i guess that the answer to this will be the same no matter what language we are using. If the db is a sql database we need to design the database schema and create the tables in the database. The first step in accessing a db in our code is to get a connection to it. If ruby is our choice of language, a search for "ruby sql connector" will give us lots of options to read about. Well - we also can do it in PHP. What do you think!? Next, based on the schema we have designed, we need to create queries suitable for storing the data. We will likely need to consider our transactional model. Again, searching "ruby sql transactional model" will give us plenty of food for thought. Finally, we may want or need to close the connection to the database. |