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PHP - Echo Not Working In Php Form In Ajax Call
Hi, This is my first post in this forum and am a PHP beginner. I have written a script in php and need to use echo to see the values of variables etc. However I dont get the output on the screen while using echo . I am using Xampp server with Apache. The startup.html file code is
<!DOCTYPE HTML>
</head>
and the test.php code is <?php
$lat = $_REQUEST['latitude'];
echo 'latitude- '.$lat . ', longitude- ' . $lon; Please help regards
Sanjish Similar TutorialsHi
I have an AJAX call that populates a select menu based on the selection from a previous menu. All works on on desktop browser, Safari, Firefox IE etc, however when using iOS the second select menu isn't populating.
the AJAX request is as follows
<script>
function getXMLHTTP() { //fuction to return the xml http object
var xmlhttp=false;
try{
xmlhttp=new XMLHttpRequest();
}
catch(e) {
try{
xmlhttp= new ActiveXObject("Microsoft.XMLHTTP");
}
catch(e){
try{
xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");
}
catch(e1){
xmlhttp=false;
}
}
}
return xmlhttp;
}
function getTeam(strURL) {
var req = getXMLHTTP();
if (req) {
req.onreadystatechange = function() {
if (req.readyState == 4) {
// only if "OK"
if (req.status == 200) {
document.getElementById('away-team').innerHTML=req.responseText;
} else {
alert("There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
function getGP(strURL) {
var req = getXMLHTTP();
if (req) {
req.onreadystatechange = function() {
if (req.readyState == 4) {
// only if "OK"
if (req.status == 200) {
document.getElementById('gp').innerHTML=req.responseText;
} else {
alert("There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
</script>
and the trigger for it...
<select name="year" class="txtfield" onChange="getGP('find_gp_ajax.php?season='+this.value)">
Any ideas why the call won't work on iOS?
Can anyone figure out why this works in IE and Firefox but not Safari? Any help would be great. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Concept Builders</title> <link href="_css/main.css" rel="stylesheet" type="text/css" /> <link rel="stylesheet" href="_css/megamenu.css" type="text/css" media="screen" /> <script src="_scripts/pagebuilder.js" type="text/javascript"></script> <script src="_scripts/jquery-1.7.1.min.js" type="text/javascript"></script> <script src="_scripts/jquery.nivo.slider.pack.js" type="text/javascript"></script> <script src="_scripts/jquery.easing.1.3.js" type="text/javascript"></script> <script src="js/megamenu.js" type="text/javascript"></script> <?php include 'dbconfig.php'; include 'dbopen.php'; $plan=$_GET["plan"]; $sql = "SELECT * FROM homes WHERE plan_id= '".$plan."'"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { $price=$row['price']; $sqft=$row['sqft']; $beds=$row['bedrooms']; $baths=$row['baths']; $amenities=$row['amenity_1'].", ".$row['amenity_2']; } setlocale(LC_MONETARY, 'en_US'); $price=money_format('%(#6.0n', $price); $plan_details= "<table> <tr> <td width='182' class='propDetailsHeadings'>Price:</td> <td width='75'>".$price."</td> </tr> <tr> <td class='propDetailsHeadings'>SQ Feet:</td> <td>".$sqft."</td> </tr> <tr> <td class='propDetailsHeadings'>Amenities:</td> <td></td> </tr> <tr> <td>".$amenities."</td> <td></td> </tr> </table>";?> <script language="javascript" type="text/javascript"> function loadPage() { var ajaxDisplay = document.getElementById("plan_details"); ajaxDisplay.innerHTML = <?PHP echo $plan_details;?>; } </script> </head> <body onload="loadPage()"> Hello, I've been trying this for hours now, looking at different examples and trying to change them to work for me, but with no luck... This is what I am trying to do: I have a simple form with: - 1 input field, where I can enter a number - 1 Submit Button When I enter a number into the field and click submit, I want that number to be send to the php file that is in the ajax call, then the script will take that number and run a bunch of queries and then return a new number. I want that new number to be used to call the php script via ajax again, until no number is returned, or something else is returned like the word "done" or something like that, at which point is simply makes an alert or populated a div with a message... The point is, that depending on the number entered it could take up to an hour to complete ALL the queries, so I want the script that is called to only run a fixed amount of queries at a time and then return the number it is currently at (+1), so that it can continue with the next number when it is called again. I would like to use jquery, but could also be any other way, as long as I get this to work. I already have the php script completed that needs to be called by the ajax, it returns a single number when being called. Thank you, vb I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though. My code for the select form including AJAX code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>AJAX Example</title> <link rel="stylesheet" type="text/css" href="Form.css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("tr:odd").addClass("odd"); }); </script> <script type="text/javascript"> function showPlayers(str) { var xmlhttp; if (str=="") { document.getElementById("DataDisplay").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); else {// code for IE6, IE5 } xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","Query.php?category_id="+str,true); xmlhttp.send(); } </script> </head> <body> <h1">AJAX Example</h1> <?php #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "You did not successfully connect to the DB!" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Error connecting to the database test!"); ?> <form name="sports" id="sports"> <legend>Select a Sport</legend> <select name="category_id" onChange="showPlayers(this.value)"> <option value="">Select a Sport:</option> <?php $sql = "SELECT category_id, sport FROM sports ". "ORDER BY sport"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n "; } ?> </select> </form> <br /> <div id="DataDisplay"></div> </body> </html> Query.php <?php #get the id $id=$_GET["category_id"]; #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "Error connecting to MySQL" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Could not select that particular Database"); #$id="category_id"; #create the query $sql ="SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '".$id."'"; echo $sql; #execute the query $rs = mysql_query($sql,$conn); #start the table code echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>"; #write the data while( $row = mysql_fetch_array( $rs) ) { echo ("<tr><td>"); echo ($row["category_id"] ); echo ("</td>"); echo ("<td>"); echo ($row["sport"]); echo ("</td>"); echo ("<td>"); echo ($row["first_name"]); echo ("</td>"); echo ("<td>"); echo ($row["last_name"]); echo ("</td></tr>"); } echo "</tr></table>"; mysql_close($conn); ?> I think the problem is either with this part in the AJAX Code: [Select] xmlhttp.open("GET","Query.php?category_id="+str,true); or most likely in my Query.php code when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work. When I echo out the SQL the result is Code: [Select] SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '' so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN. Please help me in this guys....... I am using MVC model for my application . I am stuck with the ajax call. this is my controller application/controller/admin/index.php function getCity() { $city=$this->model->getCity(); foreach($this->city as $key => $value) { echo '<option>'.$value['name'].'</option>' ; } } this is my model application/model/admin_model.php public function getCity() { if($_POST['id']) { $cid=$_POST['id']; $sth = $this->db->prepare('SELECT id, name FROM unit WHERE cid= :cid'); $sth->execute(array(':cid' => $cid)); return $sth->fetchAll(); } } this is my view <form id="city" action="<../application/admin/regstr/" method="post"> Country <select name="country" class="country"> <option value="" selected="selected">--Select Taluka--</option> <option value="1">India</option> <option value="2">USA</option> <option value="3">China</option> </select> City <select name="city" class="city"> <option selected="selected">--Select City--</option> </select> <input type="submit" /> </form> and this is my javascript for Ajax $(document).ready(function() { $(".country").change(function() { var id=$(this).val(); var dataString = 'id='+ id; $.ajax ({ type: "POST", url: "admin/getCity", data: dataString, cache: false, success: function(html) { $(".city").html(html); } }); }); }); But I am not getting the output. I have tested it with firebug in response tab. Instead of getting only option values html code as output I am getting the whole HTML page content (i.e. content of view page admin/index.php. Please help me out. Hello guys is it possible to create a single php file to contain all the functions to be called via AJAX and get AJAX to call the specific function required rather than having to create individual pages for each AJAX request you need to make? Many Thanks This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=334644.0 Hey guys, I'm making an Ajax call to my database and retrieving a newsletters HTML code as the result. I then prepend it into a div area called code_content. I use some php str_replace to add some links also. When the content loads into the div, the user can then add further content to it via Ajax calls, appending articles and that. What I'm trying to figure out is how can I then retrieve all the newly edited contents of this code_content div soni can send it to my Ajax function to write to te db? Hi all new to php and this forum i have been looking around and im very impressed most questions get answered not like on some of the forums around.
Is there any one kind enough to help me out i have an api call via php and would like to output the results to owlcarousel where do i start with this.
Code i have is:
<?php
error_reporting(E_ALL); // Turn on all errors, warnings and notices for easier debugging
// API request variables
$endpoint = 'http://svcs.ebay.com/services/search/FindingService/v1'; // URL to call
$version = '1.0.0'; // API version supported by your application
$appid = 'YourAppID'; // Replace with your own AppID
$globalid = 'EBAY-GB'; // Global ID of the eBay site you want to search (e.g., EBAY-DE)
$query = 'tools'; // You may want to supply your own query
$safequery = urlencode($query); // Make the query URL-friendly
// Construct the findItemsByKeywords HTTP GET call
$apicall = "$endpoint?";
$apicall .= "OPERATION-NAME=findItemsIneBayStores";
$apicall .= "&SERVICE-VERSION=$version";
$apicall .= "&SECURITY-APPNAME=$appid";
$apicall .= "&GLOBAL-ID=$globalid";
$apicall .= "&keywords=$safequery";
$apicall .= "&storeName=yourstorename";
$apicall .= "&paginationInput.entriesPerPage=6";
$apicall .= "&paginationInput.pageNumber=1";
// Load the call and capture the document returned by eBay API
$resp = simplexml_load_file($apicall);
// Check to see if the request was successful, else print an error
if ($resp->ack == "Success") {
$results = '';
// If the response was loaded, parse it and build links
foreach ($resp->searchResult->item as $item) {
$pic = $item->galleryURL;
$link = $item->viewItemURL;
$title = $item->title;
$price = $item->currentPrice;
// For each SearchResultItem node, build a link and append it to $results
$results .= "<div id='item'><div class='img-wrap' align='center'><img src=\"$pic\" class='itemimg'></div> <div class='itemtxt' align='center'><a href=\"$link\">$title</a>$price</div></div>";
}
}
// If the response does not indicate 'Success,' print an error
else {
$results = "<h3>Oops! The request was not successful. Make sure you are using a valid ";
$results .= "AppID for the Production environment.</h3>";
}
?>
<html>
<head>
<body>
<table>
<tr>
<td>
<div id="result">
<?php echo $results;?>
</div>
</td>
</tr>
</table>
</body>
</html>
Im sure is pretty basic but being new to this i have no idea where to start,
any advice would be much appreciated.
thanks
Edited by didz666, 25 January 2015 - 02:22 PM. Hi all, I am having problems in forming this link: { echo "<a title='page $i' class='current' href='javascript:ajaxpage('view.php?catid=" . $catid ."&" ; if($subid > 0) { echo "subid="; echo $subid . "&"; } echo "p=$i', 'content';'>$i</a> "; } Which currently points to javascript:ajaxpage( and then ends! This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=357605.0 I have a page that functions like this:
The user begins by loading ajaxtest.php, then using a drop-down menu, selects a user, after which a DIV on ajaxtest.php is populated with the user's selction to getuser.php?q=John%Doe
Here's a visual representation of what is currently happening, along with the part I don't understand.
getuser.php consists largely of a a large HTML table which interacts through PHP with my SQL database. Several of the fields in this table are editable, and after the user changes one of these fields, he can press an "update" button, which calls an AJAX script in update.js and runs update.php, which contains all my SQL queries to update the database, without the user being redirected to this update.php page. All of this is processing perfectly - the user makes some sort of edit, hits "update", and the database gets updated without any redirection or refresh.
Here's what I can't figure out though. Once the user makes a change, and hits "update," the database updates, but the end user doesn't see those changes that he made. I can't just do a simple page refresh, because the action is taking place on getuser.php, but getuser.php is loaded inside of a #DIV on ajaxtest.php. If I use something like window.location.reload(), this just refreshes ajaxtest.php and puts the user back to the starting point of having to select a user. This is not what I want. I don't want to refresh ajaxtest.php, I want to "refresh" ajaxtest.php with getuser.php?q=John%Doe insidethe DIV on ajaxtest.php.
It seems like this is very common - several forums have this capability, where a user has a page loaded, adds a comment, and sees that comment immediately without a full page refresh. I just don't know how to do it, and I've tried at lengths to search the web for an answer with no luck.
Can someone walk me through how to do this?
Where is my "Progr" return value?
This is not my first day using php but I don't code in the language that often. I don't understand why my dynamic variable is not returned in AJAX GET? Essentially, I need to give the client a simple UI so that they can copy files to a printer and I wanted to provide a little unfiltered feedback so they knew whether operation was a success. My feedback was just going to be output of exec() function though cleaned up slightly (perhaps replace line breaks with html break tags). PHP version is 5.2.17.17 and cannot be upgraded. Web Server Apache.
PHP dumbed down code:
exec("LoadZPL_PURL.bat", $output); Hello all I have a php and jquery/ajax call I am using to create a file/send an email. I get all the contents from my textboxes but I want a message to display on the screen afterwards being success or fail. In my .ajax call My call is exiting right before the ‘success:’ part. Why is my call not succeeding? Any tips/help will be appreciated Thank you
Html page just a form with a submit button
$(document).ready(function () {
var form = $("#formData");
$(form).on("submit", function (event) {
event.preventDefault();
$.ajax({
type: "post",
url: "file.php",
data: $(this).serialize(),
beforeSend: function () {
$("#status").html('<span style="color:red;">Loading everything actually creating a .TXT file of contents...</span>') //--works
},
success: function (data) {
var responseMsgType = "alert-" + data.type;
var responseMsgText = data.message;
// message below
var alertBox = '<div class="alert ' + responseMsgType + ' alert-dismissable"><button type="button" class="close" ' +
'data-dismiss="alert" aria-hidden="true">×</button>' + responseMsgText + '</div>';
if (responseMsgType && responseMsgText) {
$(form).find(".successArea").html(alertBox);
$(form)[0].reset();
}
}
});
return false;
});
<?php
$controls = array('txtName' => 'Name', 'txtEmail' => 'Email', 'txtSubject' => 'Subject', 'txtMessage' => 'Message');
try {
if(count($_POST)==0) { throw new \Exception ('Contact Form Message is empty'); }
$headers = array('Content-Type: text/plain; charset="UTF-8";',
'From: ' . $email,
'Reply-To: ' . $email,
'Return-Path: ' .$email);
$emailMessage = "You have a new message from your contact form" . PHP_EOL;
$emailMessage .= "-------------------------------------------------------" . PHP_EOL;
foreach($_POST as $key => $value){
if(isset($controls[$key])) {
$emailMessage .= "$controls[$key]: $value". PHP_EOL;
}
}
$mailMsg = "email6.txt";
if(file_exists($filename) == false) {
$fh = fopen($mailMsg, "w");
fwrite($fh, $headers);
fwrite($fh, $emailMessage);
fclose($fh);
} else {
$fhexists = fopen($filename, "a");
fwrite($fhexists, $content);
fclose($fhexists);
}
$responseMessage = array("type" => "success", "message" => $successMessage);
}
catch (\Exception $ex) {
$responseMessage = array("type" => "errorM", "message" => $errorMessage);
}
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
$encodedJSON = json_encode($responseMessage);
header("Content-Type: application/json");
echo $encodedJSON;
} else {
echo $responseMessage["message"];
}
Hello All, I have a PHP web application which will refresh itself(ajax calls connecting to the server and get the latest data) periodically. These also update the Database-based session handler class. i.e. There is NO UPDATE to the session data but the timestamp is constantly updated. Our problem is that garbage collection does not kick in as it looks at the difference between timestamp and session_gc.maxlifetime. So, if and the user is not interacting with the application. Now my question is how can I force the timeout even though refreshing happens but the user is not interacting with the application and there are "phantom" session updates made by these ajax calls. Please let me know. Thanks. hi there all. hope i can get your help. i am creating a php page that talks to mysql tabes. i want to print query into my html page inside html tags. the first echo in my code works but the one embedded inside the html code prints nothing to the page. look at my code if it helps: <html><body> <?php mysql_connect("localhost", "root", "123456") or die("Connection Failed"); mysql_select_db("man_utd")or die("Connection Failed"); $name = $_POST['members']; $query = "select * from members where username = 'burns'"; $result = mysql_query($query); while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) { echo $line['pass']; } ?> <table border="0" cellspacing="2" cellpadding="2"> <tr> <th><font face="Arial, Helvetica, sans-serif"><?php echo $line['pass']; ?></font></th> <th><font face="Arial, Helvetica, sans-serif">Value2</font></th> <th><font face="Arial, Helvetica, sans-serif">Value3</font></th> <th><font face="Arial, Helvetica, sans-serif">Value4</font></th> <th><font face="Arial, Helvetica, sans-serif">Value5</font></th> </tr> </body> </html> thanks all for any help echo will not print out a value. I do the simple string " " and it doesn't even do that. It's just blank in my browser. I use netbeans and firefox and chrome. Any idea as to what I'm doing wrong? Simple code snippet: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title>PHP Testing</title> </head> <body> <?php echo "print me"; ?> </body> </html> Thanks for any future help. My variable which should be storing XML data and echos it to the screen is echoing the data as a string without the XML structure Below is my code but it is still not working: Code: [Select] $view = $_GET['view']; $xml_data = "http://www.website.com/STRATA/" . $view .".xml"; $handle = fopen($xml_data, 'r'); $Data = fread($handle, 10000); fclose($handle); echo $Data; Please help, when I run this search and enter something in the search thats not in the database, it doesnt reply with "Your query returned 0 results" as it should. I tjust stays blank Here's the section of code in question... if ($search) // perform search only if a string was entered. { mysql_connect($host, $user, $pass) or die ("Problem connecting to Database"); $srch="%".$search."%"; $query = "select * from tvads WHERE advert LIKE '$srch' ORDER BY advert, year DESC, details ASC LIMIT 0,30"; $result = mysql_db_query("cookuk_pn", $query); if ($result) { $count = 1; print "<table border=\"0\" cellpadding=\"0\" cellspacing=\"0\" bordercolor=\"#0000FF\" width=\"900\">"; print "<tr><td width=\"200\" height=\"30\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Advert / Description</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Year</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Artist</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Track</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Buy Album</font></b></u></td>"; print "<td width=\"100\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Download MP3</font></b></u></td></tr>"; while ($row = mysql_fetch_array($result)) { // Begin while $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['advert']. "</font><br>"; $data .= "<font face=\"arial\" size=\"1\" color=\"#000080\"><i>" .$row['details']. "</i></font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['year']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['artist']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['track']. "</font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['asin_ref']. "</font></td>"; $data .= "<td width=\"100\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['mp3_ref']. "</font></td></tr>"; $count++; } // end while $data .="</table>"; echo $data; } else { echo "problems...."; } } else { echo "Your query returned 0 Results"; } ?> Hello all, I'm passing variables through a URL. This will work: echo $v4; But neither of these will: echo "<a href='test.php?v4=$v4'>Places</a>"; echo "<a href='test.php?v4=".$v4."> Places</a>"; It WILL work if I hardcode v4, like so: echo "<a href='test.php?v4=Utah'>Places</a>"; But that's useless to me, as I don't want to have to write 50 If statements for every database entry. Does anyone know how to fix this? Thanks! |
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