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PHP - Issue Displaying Mysql Data With Php Code/ajax
Hello everyone, I begin in everything web related but I have been programming for years. I tried to code something simple : small Mysql DB (works fine) and to begin a search bar to browse data. I adapted a code that I understood provided here : https://www.cloudways.com/blog/live-search-php-mysql-ajax/. Base principle is simple : as you type in your query, it will pass the text to script.js that will forward this request to ajax.php file. In the ajax.php, a javascript function named “fill()” will pass the fetched results. This function will also display the result(s) into “display” div in the “search.php” file. The problem is that when I type anything it displays, below the search bar, at the moment I type a character: Quote
'; //Fetching result from database. while ($Result = MySQLi_fetch_array($ExecQuery)) { ?> ")'>
instead of the actual answer from my database (no error in the browser console). I tested the SQL query + the user I provide and everything seems fine. Any clue what could be the root cause ? I strongly suspect a mistake in the code as I already corrected one (script.js instead of scripts.js) but I really cannot figure out where. Thanks in advance,
problematic code (ajax.php):
<?php
//Including Database configuration file.
include "db.php";
//Getting value of "search" variable from "script.js".
if (isset($_POST['search'])) {
//Search box value assigning to $Name variable.
$Name = $_POST['search'];
//Search query.
$Query = "SELECT Name FROM search WHERE Name LIKE '%$Name%' LIMIT 5";
//Query execution
$ExecQuery = MySQLi_query($con, $Query);
//Creating unordered list to display result.
echo '
<ul>
';
//Fetching result from database.
while ($Result = MySQLi_fetch_array($ExecQuery)) {
?>
<!-- Creating unordered list items.
Calling javascript function named as "fill" found in "script.js" file.
By passing fetched result as parameter. -->
<li onclick='fill("<?php echo $Result['Name']; ?>")'>
<a>
<!-- Assigning searched result in "Search box" in "search.php" file. -->
<?php echo $Result['Name']; ?>
</li></a>
<!-- Below php code is just for closing parenthesis. Don't be confused. -->
<?php
}}
?>
</ul>
Similar TutorialsAll I am trying to do is add a record on a page without the page refreshing. For that ajax is used. Here is the code.
It does not add the record to mysql table. Can anyone tell me what I am doing wrong?
record.php
<!DOCTYPE HTML>
<html lang="en">
<head>
<script type="text/javascript" src="js/jquery-1.11.0.min.js"></script>
<script type="text/javascript" >
$(function() {
$(".submit_button").click(function() {
var textcontent = $("#content").val();
var name = $("#name").val();
var dataString = 'content='+ textcontent + '&name='+name;
if(textcontent=='')
{
alert("Enter some text..");
$("#content").focus();
}
else
{
$("#flash").show();
$("#flash").fadeIn(400).html('<span class="load">Loading..</span>');
$.ajax({
type: "POST",
url: "action.php",
data: dataString,
cache: true,
success: function(html){
$("#show").after(html);
document.getElementById('content').value='';
$("#flash").hide();
$("#content").focus();
}
});
}
return false;
});
});
</script>
</head>
<body>
<?php
$record_id = $_GET['id']; // getting ID of current page record
?>
<form action="" method="post" enctype="multipart/form-data">
<div class="field">
<label for="title">Name *</label>
<input type="text" name="name" id="name" value="" maxlength="20" placeholder="Your name">
</div>
<div class="field">
<label for="content">content *</label>
<textarea id="content" name="content" maxlength="500" placeholder="Details..."></textarea>
</div>
<input type="submit" name="submit" value="submit" class="submit_button">
</form>
<div id="flash"></div>
<div id="show"></div>
</body>
</html>
action.php
if(isset($_POST['submit'])) {
if(empty($_POST['name']) || empty($_POST['content'])) {
$error = 'Please fill in the required fields!';
} else {
try {
$name = trim($_POST['name']);
$content = trim($_POST['content']);
$stmt = $db->prepare("INSERT INTO records(record_id, name, content)
VALUES(:recordid, :name, :content");
$stmt->execute(array(
'recordid' => $record_id,
'name' => $name,
'content' => $content
));
if(!$stmt){
$error = 'Please fill in the required fields.';
} else {
$success = 'Your post has been submitted.';
}
} catch(Exception $e) {
die($e->getMessage());
}
}
}
//my controller
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use DB;
class homeController extends Controller
{
public function index() {
$employee = DB::table('employee')->orderBy('id','desc')->get();
$department = DB::table('department')->orderBy('id','desc')->get();
return view('index', ['employee' => $employee , 'department' => $department]);
}
}
//my routes
Route::get('index','homeController@index');
//my view using blade temmplating engine
@foreach($employee as $emp)
<div class="employee">
<b>{{ $emp->name }} </b>
<a href="employee/{{ $emp->id }}">
<p class="intro">{{ substr($emp->intro ,0, 50) }}...</p>
</a>
</div>
@endforeach
@foreach($department as $dep)
<div class="department">
<b>{{ $dep->name }} </b>
<a href="department/{{ $dep->id }}">
<p class="desc">{{ substr($dep->description ,0, 100) }}...</p>
</a>
</div>
@endforeach
I want to fetch using ajax, how can i do it, teach/help me Ok... I need some help - I want to show a players balance in a game beside there name (Balance is in mysql database)I can do that but... - I also want to show if there online or offline at the same time( This is stored in a different database) I have the code which says whether they are online or offline <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> Here is the page: www.scswc.com/Offline_Users.php displaying that But I want to Create something like this: Nocvacraft Players |Online| Name:Player Balance:$20 |Offline| Name:Player Balance:$15 Here is what I have tried: <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); $query2 =mysql_query("SELECT * FROM iBalances WHERE player = $users"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query) $rows2 = mysql_fetch_array($query2)): $users = $rows['name']; $balance = $rows2['balance']; echo "<font color='black'>|Online|<br><font color='green'>Name:$usersBalance:$balance</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> I know I am trying to use a variable before it is been set - but if I don't how I have tried this as well... <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>Name:$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; $query = mysql_query("SELECT * FROM iBalances WHERE player = $users"); WHILE($rows = mysql_fetch_array($query)): $balance = $rows['balance']; echo "<font color='red'>$users $balance</font><br>"; endwhile; // ?> Can you use variables in mysql_query()?Is that why it isn't working? This is my first php script so if I need to give you more information for you to help me just tell me Thanks Here is database pictures iBalances users_online Hey guys have been trying to get this script to work for a while now, i am new to php and mysql so i am sure i am missing something simple. I have DB setup and need to pull data based on the key item code and get the following I want to get the fields item_code description allergy_statement useable_units region_availability order_lead_time ingredients for item_code 12-100 LITERALLY 12-100, no range, but like i said before i am really new to php and mysql. I have 1187 items that when a user clicks a link in search results it takes them to the product details page for that item code All that data is in my database just can't figure out how to get it out of the database. Is this even the right script to achieve that result. here is the code to get the data from database Code: [Select] <?php require_once('includes/mysql_connect_nfacts_ro.php'); $query = "SELECT item_code, description, allergy_statement, useable_units, region_availability, order_lead_time, ingredients " . "FROM products " . "WHERE item_code = '12-100' "; $resuts = mysql_query($query) or die(mysql_error()); ?> And need to display the data like so : Code: [Select] <td width="715" align="center" valign="top"> <h1>Product Details</h1> <h3>DISPLAY description HERE</h3> <table width="420" border="0"> <td class="ingreg"> </td> </table> <h5>Item Number</h5> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY ITEM_CODE HERE</td> </tr> </table> <h3>Ingredients:</h3> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY INGREDIENTS HERE</td> </tr> </table> <h4>Allergy Statement:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Allergy Statement HERE</td> </tr> </table> <h4>Useable Units Per Package:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Useable Units Per Package HERE</td> </tr> </table> <h4>Region Availability: </h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY ITEM_CODE HERE</td> </tr> </table> <h4>Order Lead Time:</h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY order lead time HERE</td> </tr> </table> <p> </p> <div align="right"></div></td> </tr> </table> how do i get data in database to display where i need it to? Can any one shine some light on this So i pull some records out of a mysql table and i want to display them in 5 even columns. I'm not entirely sure how to do the math & logic to accomplish this. The pull is simple $qry = "SELECT DIST_PART_NUM FROM $tablename"; $sql = mysql_query($qry) or die(mysql_error()); while($res = mysql_fetch_assoc($sql)) { // CREATE 5 even columns here. } so let's say i just retrieved 5,000 part numbers, i'd like to display then in a table of 5 columns with 1000 records per column. This is easy math, but i need the script to automatically figure out the #'s. Also the tricky part is that i dont want to display the part numbers like so 11111 22222 33333 44444 55555 66666 77777 88888 99999 00000 but rather 11111 44444 77777 22222 55555 88888 33333 66666 99999 00000 the remainder if there is one can go in the last column or whatever is easier. I'd tried googling this, but it's not easy to phrase what i'm looking for. Thanks for the help. PS: I'm not looking to copy and paste code, if possible please explain your way so that i can learn the logic. I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though. My code for the select form including AJAX code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>AJAX Example</title> <link rel="stylesheet" type="text/css" href="Form.css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("tr:odd").addClass("odd"); }); </script> <script type="text/javascript"> function showPlayers(str) { var xmlhttp; if (str=="") { document.getElementById("DataDisplay").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); else {// code for IE6, IE5 } xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","Query.php?category_id="+str,true); xmlhttp.send(); } </script> </head> <body> <h1">AJAX Example</h1> <?php #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "You did not successfully connect to the DB!" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Error connecting to the database test!"); ?> <form name="sports" id="sports"> <legend>Select a Sport</legend> <select name="category_id" onChange="showPlayers(this.value)"> <option value="">Select a Sport:</option> <?php $sql = "SELECT category_id, sport FROM sports ". "ORDER BY sport"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n "; } ?> </select> </form> <br /> <div id="DataDisplay"></div> </body> </html> Query.php <?php #get the id $id=$_GET["category_id"]; #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "Error connecting to MySQL" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Could not select that particular Database"); #$id="category_id"; #create the query $sql ="SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '".$id."'"; echo $sql; #execute the query $rs = mysql_query($sql,$conn); #start the table code echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>"; #write the data while( $row = mysql_fetch_array( $rs) ) { echo ("<tr><td>"); echo ($row["category_id"] ); echo ("</td>"); echo ("<td>"); echo ($row["sport"]); echo ("</td>"); echo ("<td>"); echo ($row["first_name"]); echo ("</td>"); echo ("<td>"); echo ($row["last_name"]); echo ("</td></tr>"); } echo "</tr></table>"; mysql_close($conn); ?> I think the problem is either with this part in the AJAX Code: [Select] xmlhttp.open("GET","Query.php?category_id="+str,true); or most likely in my Query.php code when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work. When I echo out the SQL the result is Code: [Select] SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '' so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN. I am querying my database to show the visit statistics for a particular week and it shows the number of visits for the countries, but does not display the country name.
I have proved that the MySQL works by going into phpMyAdmin and pasting the query into SQL query tab, replacing the POST with 1, for week 1.
I can't see why it is not displying the country.
Here is the code:
<?php
include('connect_visits.php');
doDB7();
$WVisit_data="SELECT WeekNo15.WNo, WeekNo15.WCom, Countries.Country, Countries.CID, ctryvisits15.CVisits
FROM ctryvisits15
LEFT JOIN Countries
ON ctryvisits15.country = Countries.CID
LEFT JOIN WeekNo15
ON ctryvisits15.WNo = WeekNo15.WNo
WHERE ctryvisits15.WNo = '{$_POST['WeekNo']}'
ORDER BY ctryvisits15.CVisits DESC";
$WVisit_data_res = mysqli_query($mysqli, $WVisit_data) or die(mysqli_error($mysqli));
$display_block ="
<table width=\"20%\" cellpadding=\"3\" cellspacing=\"1\" border=\"1\" BGCOLOR=\"white\" >
<tr>
<th>Country</th>
<th>Visits</>
</tr>";
while ($WV_info = mysqli_fetch_array($WVisit_data_res)){
$Ctry = $WV_info['country'];
$Visits = $WV_info['CVisits'];
//add to display
$display_block .="
<tr>
<td width=\"10%\" valign=\"top\">".$Ctry."<br/></td>
<td width=\"5%\" valign=\"top\">".$Visits."<br/></td>
";
}
mysqli_free_result($WVisit_data_res);
mysqli_close($mysqli);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<!--
Design by Free CSS Templates
http://www.freecsstemplates.org
Released for free under a Creative Commons Attribution 2.5 License
Name : Yosemite
Description: A two-column, fixed-width design with dark color scheme.
Version : 1.0
Released : 20091106
-->
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="keywords" content="" />
<meta name="description" content="" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>1066 Cards 4U - Stats for country</title>
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />
</head>
<body>
<div id="wrapper">
<div id="menu">
<ul>
<li class="current_page_item"><a href="index.php">Home</a></li>
<li><a href="Links.html">Links</a></li>
<li><a href="Verse_Menu.html">Verses</a></li>
<li><a href="Techniques.html">Techniques</a></li>
<li><a href="blog.php">Blog</a></li>
<li><a href="Gallery.html">Gallery</a></li>
<li><a href="contact.html">Contact</a></li>
<li><a href="AboutUs.html">About Us</a></li>
<li><a href="stats1.html">Stats</a></li>
</ul>
</div><!-- end #menu -->
<div id="header">
<div id="logo">
<h1><a href="http://www.1066cards4u.co.uk">1066 Cards 4U</a></h1>
</div><!-- end #wrapper -->
</div><!-- end #header -->
<div id="page">
<div id="page-bgtop">
<div id="page-bgbtm">
<div id="content">
<h3>Statistics for Week Commencing <? echo $WkCom; ?> in 2015</h3>
<div id="table">
<?php echo $display_block; ?></div>
</div><!-- end #content -->
</body>
</html>
Can you help please?
Edited by rocky48, 07 January 2015 - 07:33 AM. Hi guys. I'm trying to build a games site for a friend. Currently, the front-end (HTML/CSS) of the site is done. Now, I want to make a way for him to easily add games to the site. Ideally, I'd like to make a database with the following columns: ID, Name, Category, Link, Thumbnail_Link. So, those would be the ID, name of the game, the category, a link to the game, and a link to the 50x50 thumbnail image respectively. Then, using PHP, I'd like to call the first x number (not sure what it will be yet, let's say 50) and make format it as a grid in the following way: There's the thumbnail image followed by the game name, and they're all a clickable link to the game URL. Is this possible? How would I go about doing this? I've already set up a database for a login module to the site, so each page has already opened a connection to the MySQL database. However, I've only ever done basic PHP for mail forms and am otherwise extremely new to it, and am especially new to MySQL. Could anyone walk me through how to do this or even give me a quick example script to work off of? Thanks, any of your time is greatly appreciated! I have a table in a mysql database with 5 columns, id, Name, Wifi, Bluetooth, GPS, with rows that are for example 1, Galaxy S2, yes, yes, yes. So basically i want to build a form that has check boxes (3 checkboxes for wifi bluetooth and GPS respectively) that once selected will query the database depending on which check boxes are selected. I have made the form but need to know what to put in the filter.php to make the results be displayed accordingly. Ideally if anyone knows how i would want it so the results were shown on the same page which i believe u need to use ajax to happen but any help on how to show the results will be greatful. the code for the form i have made is as follows: Code: [Select] <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>test</title> </head> <body> <form action="filter.php" method="post"> <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="Wifi" id="r1">Wifi <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="Bluetooth" id="b1">Bluetooth <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="GPS" id="g1">GPS <input type="submit" name="formSubmit" value="Submit" /> </form> </body> </html> im not sure on how to make the filter.php page but i do have this code for displaying the all the data but i want to kno how to make it only display the data from the choices on the checkboxes Code: [Select] <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>pls work</title> </head> <body> <?php function h($s) { echo htmlspecialchars($s); } mysql_connect("localhost", "root", "") or die (mysql_error()); mysql_select_db("project") or die (mysql_error()); $result= mysql_query('SELECT * FROM test') or die('Error, query failed'); ?> <?php if (mysql_num_rows($result)==0) { ?> Database is empty <br/> <?php } else { ?> <table> <tr> <th></th> <th>Name</th> <th>Wifi</th> <th>Bluetooth</th> <th>GPS</th> </tr> <?php while ($row= mysql_fetch_assoc($result)) { ?> <tr> <td> <a href="uploaded-images/<?php h($row['Name']); ?>.jpg"> <img src="uploaded-images/<?php h($row['Name']); ?>.jpg" alt="test"/> </a> </td> <td><a href="textonly.html"><?php h($row['Name']); ?></a></td> <td><?php h($row['Wifi']); ?></td> <td><?php h($row['Bluetooth']); ?></td> <td><?php h($row['GPS']); ?></td> </tr> <?php } ?> </table> <?php } ?> </body> </html> Hi all, I'm trying to display a form based on a dropd own selection. The drop down is propagated from a database query. I have the drop down list displaying, but when I click submit, I can't get the result to display. Code: [Select] $sql="SELECT id, company_name FROM webprojects ORDER BY company_name ASC"; $result=mysql_query($sql); $options=""; while ($row=mysql_fetch_array($result)) { $id=$row["id"]; $company_name=$row["company_name"]; $options.="<OPTION VALUE=\"$id\">".$company_name; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>PHP Dynamic Drop Down Menu</title> </head> <body> <form id="form1" name="form1" method="post" action="selected.php"> <SELECT NAME=id> <OPTION VALUE=0>Choose <?=$options.="<OPTION VALUE=\"$id\">".$company_name.'</option>';?> </SELECT> <label> <input type="submit" name="submit" id="submit" value="Submit" /> </label> </form> </body> </html> Any help is greatly appreciated Hi guys, I have a problem.. I have a table which shows the results, but the table is showing right at the bottom below the button "delete members" although the code is right above it so I don't really understand.. and hope someone can shed the light? Appreciated Code: [Select] <?php include "connect.php"; session_start(); if(!isset($_SESSION['email'])) { die('You have no access to this page.'); } else{ //Check if records were submitted for deletion if(isset($_POST['id']) && count($_POST['id'])) { //Ensure values are ints $deleteIDs = implode(', ', array_map('intval', $_POST['id'])); $query = "DELETE FROM member WHERE id IN ({$deleteIDs})"; //Debug line echo "Successfuly deleted member(s)"; mysql_query($query) or die(mysql_error()); } ?> <link rel="stylesheet" type="text/css" href="view.css" media="all"> <script type="text/javascript" src="view.js"></script> <body id="main_body" > <img id="top" src="top.png" alt=""> <div id="form_container"> <h1>Consult, Modify or Delete a Member</h1> <form id="form_362567" class="appnitro" method="post" action="searchmember.php"> <div class="form_description"> <h2> Consult, Search, Modify or Delete a Member</h2> <p></p> </div> <ul > <li class="section_break"> <br>Search members with any keyword or character within the options id/email/firstname/lastname/phone/address1/address2/city/county/postcode - relevant matches will show.<br><br> <b>Keyword/Character:</b><br> <input id="search" name="search" class="element text medium" type="text" maxlength="50" value=""/> <br><br> <b>Search on</b>:<br> <select name="searchvalue" id="searchvalue"> <option name="id" id="id">id</option> <option name="email" id="email">email</option> <option name="firstname" id="firstname">firstname</option> <option name="lastname" id="lastname">lastname</option> <option name="phone" id="phone">phone</option> <option name="address1" id="address1">address1</option> <option name="address2" id="address2">address2</option> <option name="city" id="city">city</option> <option name="county" id="county">county</option> <option name="postcode" id="postcode">postcode</option> </select><br><input type='submit' value='Search' name='go' /><INPUT TYPE="button" VALUE="Cancel" onClick="history.go(-1);return true;"><br> <br> To consult or modify a profile click on the member's E-mail address. <li class="section_break"> </form> <?php $result = mysql_query("SELECT * FROM member"); ?> <table border='1'> <tr> <th>First Name</th> <th>Last Name</th> <th>Phone Number</th> <th>Postcode</th> <th>E-mail</th> <th>Delete</th> </tr> <?php while($row = mysql_fetch_array($result)) { echo "<form action='' method='POST'>"; echo "<tr>"; echo "<td>" . $row['firstname'] . "</td>"; echo "<td>" . $row['lastname'] . "</td>"; echo "<td>" . $row['phone'] . "</td>"; echo "<td>" . $row['postcode'] . "</td>"; echo "<td>"; echo '<a href="consultmember.php?email='; echo $row['email']; echo '">'; echo $row['email']; echo "</a></td>"; echo "<td><input type='checkbox' name='id[]' value='{$row['id']}' /></td>"; echo "</tr>"; } ?> <br><input type='submit' value='Delete Members' name='delete' /><INPUT TYPE="button" VALUE="Cancel" onClick="history.go(-1);return true;"><br> </form> <div id="footer"> </div> </div> <img id="bottom" src="bottom.png" alt=""> </body> <?php } ?> Hi There! Hopefully someone can help. I'm looking for some php script that allows me to display mysql table data in alternating row colors (eg 5 columns and 500 rows). I would also like to add pagination and limit number of rows displayed at a time to e.g. 50. If possible I'd like to be able to sort asc/desc using titles(links) at the top of the displayed data. Hopefully someone may have a script like this that also shows the mysql connection code (sample host, pass, user etc...) - a working php file so to speak that I can edit. Would really appreciate the help. If you could recommend some software or a wizard that could generate the php code for me I would really appreciate it too! THANKS! Hi, I'm trying to make a dynamic html table to contain the mysql data that is generated via php. I'm trying to display a user's friends in a table of two columns and however many rows, but can't seem to figure out what is needed to make this work. Here's my code as it stands: Code: [Select] <?php //Begin mysql query $sql = "SELECT * FROM friends WHERE username = '{$_GET['username']}' AND status = 'Active' ORDER BY friends_with ASC"; $result = mysql_query($sql); $count = mysql_num_rows($result); $sql_2 = "SELECT * FROM friends WHERE friends_with = '{$_GET['username']}' AND status = 'Active' ORDER BY username ASC"; $result_2 = mysql_query($sql_2); $count_2 = mysql_num_rows($result_2); while ($row = mysql_fetch_array($result)) { echo $row["friendswith"] . "<br>"; } while ($row_2 = mysql_fetch_array($result_2)) { echo $row_2["username"] . "<br>"; } ?> The above simply outputs all records of a user's friends (their usernames) in alphabetical order. The question of how I'd generate a new row each time a certain amount of columns have been met, however, is beyond me. Anyone know of any helpful resources that may solve my problem? Thanks in advance =) Hey guys, Having a slight problem with part of the code in my index.php file Code: [Select] mysql_select_db('db_name', $con); $result = mysql_query("SELECT * FROM spy ORDER BY id desc limit 25"); $resulto = mysql_query("SELECT * FROM spy ORDER BY id desc"); $count = mysql_num_rows($resulto); while($row = mysql_fetch_array($result)) { ?> <div class="contentDiv">Someone is looking at <?=$row[title];?> Stats for "<a href="/<?=$row[type];?>/<?=$row[code];?>/<?=$row[city];?>"><?=$row[code];?> <?=$row[city];?></a>"</div> <?}?> </div> <div id="login"></div> <? include("footer.php"); ?> </div> </body> </html> I'm getting the following error when viewing the file Code: [Select] Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in ~path to file/index.php on line 70 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in ~path to file/index.php on line 71 where lines 70 and 71 are $count = mysql_num_rows($resulto); while($row = mysql_fetch_array($result)) Any ideas on how to fix this? I m trying to fetch a image from mysql (blob) with header..here is my coding..."<?php include("db.php"); $query=mysql_query("select * from table where id='3' "); $row=mysql_fetch_array($query); $r=$row['image']; header("content-type:image"); echo $r; ?>" i want to fetch another fields from the database....but when i try to echo another fields...the page shows error or it does not echo other fields of database....please help me...how can i resolve it...i want to fetch other fields from database,like'username'password'firstname'lastname and image...thanks in advance... Hello, I've been trying this for hours now, looking at different examples and trying to change them to work for me, but with no luck... This is what I am trying to do: I have a simple form with: - 1 input field, where I can enter a number - 1 Submit Button When I enter a number into the field and click submit, I want that number to be send to the php file that is in the ajax call, then the script will take that number and run a bunch of queries and then return a new number. I want that new number to be used to call the php script via ajax again, until no number is returned, or something else is returned like the word "done" or something like that, at which point is simply makes an alert or populated a div with a message... The point is, that depending on the number entered it could take up to an hour to complete ALL the queries, so I want the script that is called to only run a fixed amount of queries at a time and then return the number it is currently at (+1), so that it can continue with the next number when it is called again. I would like to use jquery, but could also be any other way, as long as I get this to work. I already have the php script completed that needs to be called by the ajax, it returns a single number when being called. Thank you, vb I have a php tutorial that I followed for creating, inserting, selecting and updating a MySQL database with php. Everything works fine so I wanted to put it into Wordpress. I took the code and placed it into the wordpress page and everything worked just fine except the update function. Here is the tutorial I used. http://www.phpsimple.net/mysql_insert_record.html It is also the part I am having trouble with. I am able to create a record and I am also able to select a record but when I choose "update" the form doesn't load the data. It will outside the website but not inside wordpress. I am hoping this is not vague but because of my inexperience I am not sure what else to say. I will be more than happy to provide any other information you need. I have a dropdown that is on two levels. The first drop down is populated with the county list from my database. It returns the county in a drop down of what data is in the database. Then when you select the county you want the second list is populated with the city. The problem I have is the second drop down is getting more than one of the same city. So for example if you select Greater Manchester in the drop down, it should return in the city drop down Manchester and Altringham, but it show manchester twice and altringham once, not sure why it is repeating the manchester one, as I am using select distinct? does any one have any idea why i get these results like this. Heere is the code for the drop down Code: [Select] <form action="quick-results.html" METHOD="POST"><p align="right">Quick Find: <select name="region" onchange="ajaxrequest('select2',this.value)"> <option value selected="">Choose your County</option><?php echo $options; ?></select> <select name="club_town" id="select2" class="userinput"><option value selected="">Choose your City</option></select><input type="submit" value="go"></form></p> Then we have two scripts and an ajax file. Here is the script that generates the first drop down: Code: [Select] <?php include("connect.php"); $sql = mysql_query("select distinct club_county from clubs ORDER BY club_county ASC"); $options = ""; while($row = mysql_fetch_row($sql)) { $options .= "<option value=\"$row[0]\">$row[0]</option>\n"; } $region = ""; $club_town = ""; if(isset($_POST)) { $region = $_POST["region"]; $club_town = $_POST["club_town"]; } ?> Here is the script for the second drop down that gets created based on the first Code: [Select] <?php include("connect.php"); $request = $_POST["request"]; $sql = mysql_query("select distinct club_town from clubs WHERE club_county = '".$request."' "); if (mysql_num_rows($sql) ==0) { echo ("<option selected>Choose your City</option>\n"); } else { $club_town = ""; while($row = mysql_fetch_row($sql)) { $club_town .= "<option value=\"$row[0]\">$row[0]</option>\n"; echo $club_town; } } ?> And finally here is the ajax file Code: [Select] function get_XmlHttp() { var xmlHttp = null; if (window.XMLHttpRequest) { xmlHttp = new XMLHttpRequest(); } else if (window.ActiveXObject) { xmlHttp = new ActiveXObject("Microsoft.XMLHTTP"); } return xmlHttp; } function ajaxrequest(tagID, post) { var http = get_XmlHttp(); var info = 'request=' + post; http.open("POST", 'inc/destinations.ajax.city.php', true); http.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); http.send(info); http.onreadystatechange = function() { if (http.readyState == 4) { var mata = http.responseText.split("</option>"); for (i = 0; i <= (mata.length - 2); i++) { var container = document.getElementById(tagID); var newdiv = document.createElement("option"); if (i == 0) { container.innerHTML = ''; } newdiv.innerHTML = mata[i]; container.appendChild(newdiv); } } } } Help anyone? Hello friends, i need a help i have index.php and response.php and i am try to get data from response.php per once second and i am getting data in script tag. I want to use incoming data in php tag and i will parse the data however i cant do that anyone can help me ? I am trying to write a basic Private Messaging script.
I have my main page which lists all messages that have been received. I then want to click on an href link to run an ajax query to bring information in from another .php file which shows the content of the selected message.
But I can't fathom out how to do this with an href. First off, is it possible? If so, can anyone tell me what I am doing wrong?
The relevant script is:
privatemessage.php:
<?php
$query2 = DB::getInstance()->query("SELECT
c.id as cid, c.title, c.time,
m.id as membersid, m.username,
m.member_first_name, m.member_last_name
FROM conversation as c, members as m
WHERE ((c.member1='{$memberid}'
and c.read1='Yes' and c.removed1='No'
and m.id=c.member2)
OR (c.member2='{$memberid}' and c.read2='Yes'
and c.removed2='No' and m.id=c.member1))
GROUP BY m.id ORDER BY m.id DESC");
?>
<table>
<tr>
<td align="left">
<?php echo htmlentities($result2->member_first_name); ?>
<?php echo htmlentities($result2->member_last_name); ?>
<?php echo "("; echo htmlentities($result2->username); echo ")"; ?>
</td>
<td align="right">
<?php echo timeAgo(strtotime($result2->time)); ?>
</td>
</tr>
<tr>
<td colspan="2" align="left">
<form action="" method="post">
<?php echo "Subject: "; ?>
<?php echo "<input type='hidden' name='id' id='id' value='{$result2->cid}'>"; ?>
<a href="#$result2->cid" onClick="showMessages(this.value)"><?php echo htmlentities($result2->title); ?>
</form>
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script src="js/readmessage.js"></script>
</td>
</tr>
My readmessage.js code is:
function showMessages(str)
{
if (str=="")
{
document.getElementById("txtMessage").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtMessage").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","readmessage.php?q="+str,true);
xmlhttp.send();
}
And my readmessage.php code is:
<?php
require 'core/memberinit.php';
$member = new Member();
include 'timeago.php';
$memberid = $member->data() ->id;
if(isset($_GET['q'])) {
$q = html_entity_decode($_GET['q']);
$req1 = DB::getInstance()->query("SELECT title, member1, member2 FROM conversation WHERE id='{$q}' AND id2='1'");
foreach ($req1->results() as $dn1)
if($req1->count()==1)
{
if(($dn1->member1=='{$memberid}') or ($dn->member2=='{$memberid}'))
{
if($dn1->member1=='{$memberid}')
{
DB::getInstance()->query("UPDATE conversation SET read1='Yes' where id='{$q}' and id2='1'");
$user_partic = 2;
} else {
DB::getInstance()->query("UPDATE conversation SET read2='Yes' where id='{$q}' and id2='1'");
$user_partic = "1";
}
$req2 = DB::getInstance()->query("SELECT conversation.time, conversation.message,
members.id as userid, members.username, members.member_first_name, members.member_last_name
FROM conversation, members
WHERE conversation.id='{$id}' AND members.id=conversation.member1
ORDER BY conversation.id2");
if(isset($_POST['message']) and $_POST['message']!='')
{
$message = $_POST['message'];
if(get_magic_quotes_gpc())
{
$message = stripslashes($message);
}
$message = $string(nl2br(htmlentities($message, ENT_QUOTES, 'UTF-8')));
if( DB::getInstance()->query("INSERT into conversation
(id, id2, title, member1, member2, message, time, read1, read2)
VALUES('{$q}', '{(intval($req2->id2)+1)}', '', '{$memberid}', '', '{$message}', '.time().', '', '')")
and
DB::getInstance()->query("UPDATE conversation SET read'{$user_partic}'='Yes' WHERE id='{$q}' AND id2='1'"));
}
echo "<h4>";
echo $dn1->title;
echo "</h4><br><br>";
echo "<table><col width='150px'><col width='50px'><col width='150px'>";
echo "<tr><th>Member</th><th> </th><th>Message</th></tr>";
foreach ($req2->results() as $dn2)
{
echo "<tr><td>";
echo $dn2->members.member_first_name;
echo $dn2->members.member_last_name;
echo " (";
echo $dn2->members.username;
echo ") </td><td></td><td>";
echo timeAgo(strtotime($dn2->time));
echo "<br>";
echo $dn2->message;
echo "</td></tr>";
}
echo "</table>";
}
}
}
?>
However, just to try and find where the error lies, I have tried the following code for my readmessage.php file:
<?php
require 'core/memberinit.php';
$member = new Member();
include 'timeago.php';
$memberid = $member->data() ->id;
if(isset($_GET['q'])) {
$q = intval($_GET['q']);
echo $q;
}
?>
Which always returns a "0" reply - which says to me that my files are talking, but that the id isn't being carried across.
Anybody got any suggestions?
Many thanks for any help offered.
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