PHP - Date Entry In Form
$value0 = $_POST['date1']; $value1 = $_POST['date2']; $value2 = $_POST['date3']; $sql = "INSERT INTO Datetable (startdate,enddate, total) VALUES ('$value0','$value1', '$value2')" ; $result = mysqli_query($sql); Hi, I was wondering is it possible to not insert values in MySQL if form entry is left blank? Right now if I dont enter any values in form for my dates than MySQL entry shows 0000-00-00 but I need it not to show anything.
Similar TutorialsHi, I was just trying to post form data to MySQL and trying to also post value of logged in user? but that code below doesnt work..Do you see a typo? or is it done some other way?
$uid =$_SESSION[ "uid" ]; $sql = "INSERT INTO Date (uid) VALUES (:uid)"; $query= $conn->prepare( $sql ); $query->execute( array( ':uid'=>$uid) );
Alright, wasn't quite sure how to summarize this in the title, but I want to: Check if a user status is "active" or not based on the UserName input. I have a table witch holds: Code: [Select] VarChar Username Var CharPassWord int Active Ted TedsPW 1 something like the above(assuming it formatted correctly. In my php script I will want to input a variable for Username to check for: inputUN in this example would be "Ted". $UserNameToCheck = $_GET['inputUN']; Then I want to check for that UserName in the database, if it exists, I want pull the value for the "Active" field for just that UserName and echo it. Thanks for any help. I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. I'm looking at creating a web interface for cusotmers to enter credit card information. What is the best approach for this? Keeping in mind security of data... Maybe this last point is more a question for web server administrators, but thought I'd ask anyway. When there is a duplicate entry in my database, I would like it to go to the another page that indicates the error, rather than the "Error: Duplicate entry 'username' for key 1". It happens if someone is going to join and there is a duplicate entry. I would rather it show one of my customized php pages rather than a black page stating the error. I've tried to catch the entry with some php code but it bypasses it and continues with the duplicate error. I would appreciate any direction with this. Thanks! I spent several hours trying to figure this thing out. Thought I had it nailed, but still getting duplicate record entries into the MySQL DB when I do NOT want them.
Here's the plot:
People filling out the possible attendance form for a Ham Radio event *sometimes* bring a 2nd person (either a spouse or a friend). The 2nd person may, or may not, also has a Callsign which I need to put INSERT the same MySQL Callsign column. In any event, to also identify the 2nd person as coming 'with' the 1st person.
MOST of the attendees are individuals with NO 2nd person.
My entry form has these primary fields:
callsign
fullname
AND...
callsign2
fullname2
What I came up with was to process the MySQL INSERT for the primary callsign & fullname into their respective MySQL DB Columns (which works fine), and then........... immediately following the main Query INSERT, to do a substitution type thing depending on whether or not a form entry was made in the callsign2 field, AND/OR, the fullname2 field.
This partially works, but if there is ONLY a primary callsign and fullname in the form, I'm still getting a duplicate record entry which includes the callsign in the `with` column (which should ONLY take place IF there is a 2nd person indicated).
Confusing?
Here is what I have been wrestling with to try and accomplish the objective, and now my eyes are glazed over ;-(
// TRICKY PART HERE // If a 2nd Callsign AND a Fullname if ($callsign2 != ' ' && $fullname2 != ' ') { // Still make reference to the primary Callsign in the MySQL DB `with` column $with = $callsign; // Assignment to allow 2nd Callsign to be entered in the MySQL `callsign` column $callsign=$callsign2; $fullname=$fullname2; $sql="INSERT INTO `mytable` (`callsign`, `fullname`, `with`) VALUES ('$callsign', '$fullname', '$with')"; // If NO 2nd Callsign BUT a Fullname } elseif ($callsign2 = ' ' && $fullname2 != ' ') { // Make reference to the primary Callsign in the MySQL DB `with` column $with = $callsign; $callsign=$callsign2; $fullname=$fullname2; $sql="INSERT INTO `mytable` (`callsign`, `fullname`, `with`) VALUES ('$callsign', '$fullname', '$with')"; } else { // The only thing I could thing of to (hopefully) NOT make a 2nd entry // record in the MySQL DB IF there is NO 2nd person referenced $with = $callsign; } if (!mysqli_query($con,$sql)) { die('Error: ' . mysqli_error($con)); }This mostly works EXCEPT if only a single (primary) person entry. The recap the objetives: 1. If ONLY a primary/single person entry on the form: * callsign & fullname get INSERTed into the `callsign` and `fullname` columns in the DB as ONLY one record entry 2. If BOTH a primary and 2nd person on the form: A. IF the 2nd person has a Callsign, then the 2nd record entry would be: * callsign2 & fullname2 get INSERTed into the `callsign` & `fullname` columns in the 2nd DB as a separate record entry * callsign of the primary person also gets INSERTED into the `with` column in the same 2nd DB record entry B. IF the 2nd person does NOT have a callsign, then the 2nd record entry would be: * fullname2 gets INSERTed into the `fullname` column in the DB as a separate 2nd DB record entry * callsign of the primary person also gets INSERTED into the `with` column in the same 2nd DB record entry I obvioiusly have overlooked something, but just can't seem to figure it out at this point {SIGH}. Thanks for any enlightenment. -FreakingOUT I am using php to upload a file to my server, and at the same time inserting the files name and url into my mysql database.
$sql = "UPDATE uploads SET name = '$name', url='$target_path'"; $statement = $dbh->prepare($sql); $statement->execute();This is working, however, when I upload a new file, rather than making a new entry in my database, it just overwrites the first one. I'm quite new at mysql so was wondering how I would make it add new entrys instead of overwriting the current one? Guys: What is the way to remove white spaces in front of a form entry ? Should I use regular expression for this ? Thanks. I have a table called "colors". It has 2 columns, id and color. All I'm trying to do is pull the data into the form, then edit the colors (for example - misspelled, etc.) Then submit it back to the table. Here is the code that pulls the data into a form so I can edit it: Code: [Select] <form action="adminupdatecolors.php" method="post"> <table width="500" border="1" cellpadding="10"> <tr> <td>Color Options:</td> <td> <? $result = mysql_query("SELECT * FROM colors"); while ($row = mysql_fetch_assoc($result)) { echo '<input type="text" name="color[]" value="' . $row['color'] . '"/>' . $row['id'] . '<br />'; } ?> </td> </tr> <tr> <td> </td> <td><input type="Submit" value="Update Colors"></td> </tr> </form> </table> Here is my update script: Code: [Select] <?php include("config.php"); include("db.php"); $id=$_POST['id']; $color=$_POST['color']; $result = mysql_query("SELECT id FROM colors ORDER BY id DESC LIMIT 0,1"); if ($row = mysql_fetch_assoc($result)) { $id = $row['id']; } $sql = "DELETE FROM colors WHERE id='$id'"; mysql_query($sql) or die("Error: ".mysql_error()); foreach ($color as $colorvalue) { $sql2 = "INSERT INTO colors (id,color) VALUES ($id,'$color')"; mysql_query($sql2) or die("Error: ".mysql_error()); } header("Location: " . $config_basedir . "adminhome.php"); ?> I am trying to set up a item entry page form.png: Upon submission it shows unsuccessful even though I have checked the fields on mysql table and seem to be good am I missing something? Code: [Select] <form action="" method="post" enctype="multipart/form-data" name="Product_Entry"> <TABLE> <TR> <TD>Product ID</TD><TD><input name="SKU_ProductID" value="<?php if (isset($_post['SKU_ProductID'])) echo $_POST['SKU_ProductID']; ?>" type="text" size="11" maxlength="11" /></TD> </TR> <TR> <TD>Merchant SKU ID</TD><TD><input name="SKU_MerchSKUID" value="<?php if (isset($_post['SKU_MerchSKUID'])) echo $_POST['SKU_MerchSKUID']; ?>" type="text" size="18" maxlength="30" /></TD> </TR> <TR> <TD>Game Title</TD><TD><input name="Game_Title" value="<?php if (isset($_post['Game_Title'])) echo $_POST['Game_Title']; ?>" type="text" size="40" maxlength="40" /></TD> </TR> <TR> <TD>Platform</TD><TD><input name="Platform" value="<?php if (isset($_post['Platform'])) echo $_POST['Platform']; ?>" type="text" size="20" maxlength="20" /></TD> </TR> <TR> <TD>Genre</TD><TD><input name="Genre" value="<?php if (isset($_post['Genre'])) echo $_POST['Genre']; ?>" type="text" size="11" maxlength="11" /></TD> </TR> <TR> <TD>Weight</TD><TD><input name="Weight" value="<?php if (isset($_post['Weight'])) echo $_POST['Weight']; ?>" type="text" size="7" maxlength="7" /></TD> </TR> <TR> <TD>Supplier</TD><TD><input name="Supplier" Value="<?php if (isset($_post['Supplier'])) echo $_POST['Supplier']; ?>" type="text" size="25" maxlength="25" /></TD> </TR> <TR> <TD>Suppliers Price</TD><TD><input name="Supplier_Price" value="<?php if (isset($_post['Supplier_Price'])) echo $_POST['Supplier_Price']; ?>" type="text" size="10" maxlength="12" /></TD> </TR> <TR> <TD>Cashback</TD><TD><input name="Cashback" value="<?php if (isset($_post['Cashback'])) echo $_POST['Cashback']; ?>" type="text" size="6" maxlength="8" /></TD> </TR> <TR> <TD>Cashback Amount</TD><TD><input name="Cashback_Amount" value="<?php if (isset($_post['Cashback_Amount'])) echo $_POST['Cashback_Amount']; ?>" type="text" size="7" maxlength="11" /></TD> </TR> <TR> <TD><input type="hidden" name="submitted" value="true"/></TD><TD><input name="Submit" type="submit" value="Add_Product" /></TD> </TR></form></TABLE> <?php # Product Entry $page_title = 'Product Entry'; if (isset($_POST['Submit'])) { $errors = array(); if (empty($_POST['SKU_ProductID'])) { $errors[] = 'Please enter Product ID.'; } else { $sid = trim($_POST['SKU_ProductID']); } if (empty($_POST['SKU_MerchSKUID'])) { $errors[] = 'Please enter Merchant SKU.'; } else { $mid = trim($_POST['SKU_MerchSKUID']); } if (empty($_POST['Game_Title'])) { $errors[] = 'Please enter Game Title.'; } else { $gt = trim($_POST['Game_Title']); } if (empty($_POST['Platform'])) { $errors[] = 'Please enter Platform.'; } else { $pl = trim($_POST['Platform']); } if (empty($_POST['Genre'])) { $errors[] = 'Please enter Genre.'; } else { $ge = trim($_POST['Genre']); } if (empty($_POST['Weight'])) { $errors[] = 'Please enter Weight.'; } else { $we = trim($_POST['Weight']); } if (empty($_POST['Supplier'])) { $errors[] = 'Please enter Supplier.'; } else { $sup = trim($_POST['Supplier']); } if (empty($_POST['Supplier_Price'])) { $errors[] = 'Please enter Supplier Price.'; } else { $sp = trim($_POST['Supplier_Price']); } if (empty($_POST['Cashback'])) { $errors[] = 'Please enter Cashback %.'; } else { $cb = trim($_POST['Cashback']); } if (empty($_POST['Cashback_Amount'])) { $errors[] = 'Please enter Cashback Amount.'; } else { $cba = trim($_POST['Cashback_Amount']); } if (empty($errors)) { require_once ('connect.php'); [b]$q = "INSERT INTO `Products` (`SKU_ProductID`, `SKU_MerchSKUID`, `Game_Title`, `Platform`, `Genre`, `Weight`, `Supplier`, `Supplier_Price`, `Cashback`, `Cashback_Amount`) VALUES ('$sid', '$mid', '$gt', '$pl', '$ge', '$we', '$sup', '$sp', '$cb', '$cba')"; $r = @mysql_query ($dbc, $q); if ($r) { // If it ran OK. // Print a message: echo '<h1>Thank you!</h1> <p>Product Inserted!</p><p><br /></p>'; } else { // If it did not run OK. // Public message: echo '<h1>System Error</h1> <p class="error">You could not be registered due to a system error. We apologize for any inconvenience.</p>'; // Debugging message: echo '<p>' . mysqli_error($dbc) . '<br /><br />Query: ' . $q . '</p>'; } // End of if ($r) IF. mysqli_close($dbc); // Close the database connection.[/b] // Include the footer and quit the script: include ('includes/footer.html'); exit(); } else { echo '<H1>Error!</H1> <p class="error">The Following error(s) occurred:<br />'; foreach ($errors as $msg) { echo " - $msg<br />\n"; } echo '</p><p>Please try again.</p><p><br /></p>'; } } ?> If there is anything else needed let me know I have a calendar select date function for my form that returns the date in the calendar format for USA: 02/16/2012. I need to have this appear as is for the form and in the db for the 'record_date' column, but I need to format this date in mysql DATE format (2012-02-16) and submit it at the same time with another column name 'new_date' in the database in a hidden input field. Is there a way to do this possibly with a temporary table or something? Any ideas would be welcome. Doug Say I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once. Is that possible to do? Here's my code. if(isset($_POST['submit'])) { $entries = 10; $id = 55; $name = 'Smith'; $insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)"); $insert->bindParam(':id', $id); $insert->bindParam(':name', $name); $result_insert = $insert->execute(); if($result_insert == false) { echo 'Fail'; } else { echo 'Success'; } } ?> <form action="" method="post"> <input type="submit" name="submit" value="SUBMIT" /> </form> Edited January 13, 2019 by imgrooot Hi, Im having some troubles with a date picker on a form. It enters the date into the date field like this : 21 Sep 2011 I want to be able to insert it into a date field in the mysql database but it just enters it as 0000-00-00 Any ideas ? Many thanks, Scott. I am working on a form with php generated values. What I have right now is as follows:
<tr> <td><p>ENTRY TERM: <select name="entry_term" > <option value="">Choose One:</option> <?php $year=date("Y"); for ($y=0;$y<5;$y++) { echo '<option value="Fall '.($year+$y).'">Fall '.($year+$y).'</option>'; echo '<option value="Spring '.($year+$y+1).'">Spring '.($year+$y+1).'</option>'; } ?> </select> </p></td>This currently generates a list of : Fall 2014 Spring 2015 Fall 2015 Spring 2016 Fall 2016 ...etc for next 5 years What I need to do is have this time sensitive to exclude once a specific month has passed. For example once August 2014 has started "Fall 2014" should be excluded... or when Jan 2015 has started "Spring 2015" should be excluded. Can someone help me solve this as I am unsure of how to move forward with this. Thanks, Hi People. I am building a logbook application and have a form field where the user will enter a date. However, I would like to simplify it for the user and give them a button which would add "todays" date into the box for them. Please could someone tell me the code to do so. The date format in my DB is YYYY-MM-DD. The form would also need to take input from the user if they were adding info from a different day instead of today. Thanks in advance. Code: [Select] <input type="text" name="date" id="date" size = "25"/> </label> <input type="submit" name="today" id="today" value="Add Today" /> Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack Hello,
I've been going about reading different posts on here and other forums but so far I haven't been able to come across something that works for my purpose so after all the reading I thought I'd finally just ask. I'm rather new at php/sql queries so please bare with me.
First what I'm trying to accomplish.
I need a form with several fields (options) to fetch information from a table that will then display the results based on the options selected.
- from date
- to date
- employee name
- department
- branch
- product line
In other words, the purpose is to be able to choose a date range (from one day to up to a year or more) and then to be able to choose either ONE employee name to view statistics invididually from a given department and branch or to select a department to view all the statistics for everyone under that given department and/or brach and/or product line.
Now the tricky part is that besides fetching the records, calculations need to be made before the records are displayed and that part right here is what is giving me a huge headache.
This is the query that I have.
SELECT report_daily_id, report_date, emp_id, emp_fullname, emp_dept, emp_branch prod_line calls, tk_time, hld_time, ac_time, tran_calls, work_time, tran_rate, ah_time FROM daily_report GROUP BY emp_id, emp_fullname, emp_branch, emp_dept, prod_lineThe calculations based on the date range and one or more of the other options need to give me the following results. SUM(calls) AS 'Total Calls' SUM(tk_time) / SUM(calls) AS 'Talk Time' SUM(hld_time) / SUM(calls) AS 'Held Time' SUM(ac_time) / SUM(calls) AS 'AC Time' SUM(tran_calls) AS 'Total Trans' SUM(tran_calls) / SUM(calls) AS 'Tran Rate' SUM(ah_time) / SUM(calls) AS 'AH Time'I don't know how else to explain myself past this point but if you have any questions, perhaps I can answer it and give more details. Thank you, Hi. I have an input field where a date is entered, format dd-mm-yy. I need to query the database to see if this date exists. How can I convert the date to yyyymmdd before the query? Thanks Hi, I need to add a function for a date field on a form being submitted to MySQL DB. Something similar to this for a website field, except it shoudl make sure the format is in 01/05/2010 or 2numbers/2 numbers/4 numbers format... if(!mb_eregi("^[a-zA-Z0-9-#_.+!*'(),/&:;=?@]*$", $website)) $this->setError('website', 'invalid website'); elseif(mb_strlen(trim($website)) > 120) $this->setError('website', 'too long! 120 characters'); thanks in advance for any assistance. |