PHP - Unable To Save Submitted Data In A Mysql Database Using Php

Is there anyway of saving data to phpmyadmin, and linking it to another page with one button. I can do it separately but I can't seem to do it using one button.

Does anyone has any ideas!

This is actually a page to edit the drama details.
Database-  3 tables

1. drama                           dramaID    drama_title
                                              1              friends

2. drama_genre             drama_genreID     dramaID    genreID
                                               1                        1               2
                                               2                        1               1
                                               3                        1               3
3. genre                              genreID       genre
                                                1            comedy
                                                2            romance
                                                3            family
                                                4            suspense
                                                5            war
                                                6            horror

<?php       

$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'drama';
$link = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname) or trigger_error('Error connecting to mysql');

$id = $_GET['dramaID'];

$link2 = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname) or trigger_error('Error connecting to mysql');
$sql2 = "SELECT * from drama , drama_genre , genre
WHERE drama.dramaID='".$id."' AND drama_genre.dramaID='".$id."' AND drama.dramaID = drama_genre.dramaID AND drama_genre.genreID = genre.genreID";
$status2 = mysqli_query($link2,$sql2) or die (mysqli_error($link2));

$link3 = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname) or trigger_error('Error connecting to mysql');
$sql3 = "SELECT * from genre ";
$status3 = mysqli_query($link3,$sql3) or die (mysqli_error($link3));

<form method='Post' action='doUpdate.php' enctype="multipart/form-data">

<?php while ($row2 = mysqli_fetch_assoc($status2)) { ?>
                  <td height="1"></td>
               
                             <td><select name="gdrop">      
                     
      <option value="<?php echo $row2['genreID'];?>"><?php echo $row2['genre'];?></option>
                     
      <?php while ($row3 = mysqli_fetch_assoc($status3)) { ?>
                        
      <option value="<?php echo $row3['genreID'];?>"><?php echo $row3['genre'];?></option>
                     
                     
      <?php }   mysqli_close($link3);  ?>
                     
 <input type='hidden' id='drama_genreID' name='drama_genreID' value = "<?php echo          $row2['drama_genreID']; ?>"/>
                 </select>

<input type="hidden" id="dramaID" name="dramaID" value = "<?php echo $row['dramaID'];?>"/>
<input type="submit" Value="Update"/>
 
The result was there were 3 dropdown menus but only the first dropdown menu has all 6 genres from my database and also the genre that belongs to the drama.

I'm also wondering how I can bring all the drama_genreIDs to my save(doupdate.php) page and update all 3 of them because it seems like only the last dropdown menu's data is saved.

And also how can I display only 6 genres instead of 7 with the genre that belongs to the drama , being set as the default selection.


                                       

Hi Guys,

I have stuck with my problem and i am nothing to php, i already posted this to another php script forum, but haven't solve, so i wondering if anyone here help me and many thanks.

this is all about game scores from .xml file
inside the xml file itself as:
Code: [Select]
<gesmes:Envelope>
<gesmes:subject>Reference Scores</gesmes:subject>
-
<gesmes:Sender>
<gesmes:name>Game Information Scores</gesmes:name>
</gesmes:Sender>
-
<Cube>
-
<Cube time="2010-10-13">
<Cube scores="GameA1" value="1.5803"/>
<Cube scores="GameA2" value="21.35"/>
............etc
<Cube scores="GameA15" value="135"/>
</Cube>
</Cube>
</gesmes:Envelope>
then i got php script that can save all data of .xml above to mysql, look like

<?php
 
class Scores_Converter {
   
   var $xml_file = "http://192.168.1.112/gamescores/scores-daily.xml";
   var $mysql_host, $mysql_user, $mysql_pass, $mysql_db, $mysql_table;
   var $scores_values = array();
 
   //Load convertion scores
   function Scores_Converter($host,$user,$pass,$db,$tb) {
      $this->mysql_host = $host;
      $this->mysql_user = $user;
      $this->mysql_pass = $pass;
      $this->mysql_db = $db;
      $this->mysql_table = $tb;
 
      $this->checkLastUpdated();
 
      $conn = mysql_connect($this->mysql_host,$this->mysql_user,$this->mysql_pass);
 
      $rs = mysql_select_db($this->mysql_db,$conn);
 
      $sql = "SELECT * FROM ".$this->mysql_table;
 
      $rs =  mysql_query($sql,$conn);
   
      while($row = mysql_fetch_array($rs)) {
         $this->scores_values[$row['scores']] = $row['value'];         
      }
   }
 
   /* Perform the actual conversion, defaults to 1.00 GameA1 to GameA3 */
   function convert($amount=1,$from="GameA1",$to="GameA3",$decimals=2) {
      return(number_format(($amount/$this->scores_values[$from])*$this->scores_values[$to],$decimals));
   }
 
   /* Check to see how long since the data was last updated */
   function checkLastUpdated() {
      $conn = mysql_connect($this->mysql_host,$this->mysql_user,$this->mysql_pass);
 
      $rs = mysql_select_db($this->mysql_db,$conn);
 
      $sql = "SHOW TABLE STATUS FROM ".$this->mysql_db." LIKE '".$this->mysql_table."'";
 
      $rs =  mysql_query($sql,$conn);
 
      if(mysql_num_rows($rs) == 0 ) {
         $this->createTable();
      } else {
         $row = mysql_fetch_array($rs);
         if(time() > (strtotime($row["Update_time"])+(12*60*60)) ) {
            $this->downloadValueScores();         
         }
      }
   }
 
   /* Download xml file, extract exchange values and store values in database */
   function downloadValueScores() {
      $scores_domain = substr($this->xml_file,0,strpos($this->xml_file,"/"));
      $scores_file = substr($this->xml_file,strpos($this->xml_file,"/"));
      $fp = @fsockopen($scores_domain, 80, $errno, $errstr, 10);
      if($fp) {
         $out = "GET ".$scores_file." HTTP/1.1\r\n";
         $out .= "Host: ".$scores_domain."\r\n";
         $out .= "User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8) Gecko/20051111 Firefox/1.5\r\n";
         $out .= "Connection: Close\r\n\r\n";
         fwrite($fp, $out);
         while (!feof($fp)) {
            $buffer .= fgets($fp, 128);
         }
         fclose($fp);
 
         $pattern = "{<Cube\s*scores='(\w*)'\s*value='([\d\.]*)'/>}is";
         preg_match_all($pattern,$buffer,$xml_values);
         array_shift($xml_values);
 
         for($i=0;$i<count($xml_values[0]);$i++) {
            $exchange_value[$xml_values[0][$i]] = $xml_values[1][$i];
         }
 
         $conn = mysql_connect($this->mysql_host,$this->mysql_user,$this->mysql_pass);
 
         $rs = mysql_select_db($this->mysql_db,$conn);
            
         foreach($exchange_value as $scores=>$value) {
            if((is_numeric($value)) && ($value != 0)) {
               $sql = "SELECT * FROM ".$this->mysql_table." WHERE scores='".$scores."'";
               $rs =  mysql_query($sql,$conn) or die(mysql_error());
               if(mysql_num_rows($rs) > 0) {
                  $sql = "UPDATE ".$this->mysql_table." SET value=".$value." WHERE scores='".$scores."'";
               } else {
                  $sql = "INSERT INTO ".$this->mysql_table." VALUES('".$scores."',".$value.")";
               }
               $rs =  mysql_query($sql,$conn) or die(mysql_error());
            }
         }   
      }
   }
 
   /* Create the scores table */
   function createTable() {
      $conn = mysql_connect($this->mysql_host,$this->mysql_user,$this->mysql_pass);
 
      $rs = mysql_select_db($this->mysql_db,$conn);
 
      $sql = "CREATE TABLE ".$this->mysql_table." ( scores char(3) NOT NULL default '', value float NOT NULL default '0', PRIMARY KEY(scores) ) ENGINE=MyISAM";
      
      $rs =  mysql_query($sql,$conn) or die(mysql_error());
 
      $sql = "INSERT INTO ".$this->mysql_table." VALUES('GameA0',1)";
 
      $rs =  mysql_query($sql,$conn) or die(mysql_error());
      
      $this->downloadValueScores();   
   }
 
}
?>

but that php script above just create table of mysql below

CREATE TABLE IF NOT EXISTS `scrore_table` (
  `scores` char(3) NOT NULL default '',
  `value` float NOT NULL default '0',
  PRIMARY KEY  (`scores`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

INSERT INTO `scrore_table` (`scores`, `value`) VALUES
('GameA0', 1),
('GameA1', 1.5651),
......etc
('GameA15', 95.572);

while of my existing database table look like:

CREATE TABLE IF NOT EXISTS `scrore_table` (
  `scrore_id` int(11) NOT NULL auto_increment,
  `scrore_title` varchar(32) collate utf8_bin NOT NULL default '',
  `scores` varchar(3) collate utf8_bin NOT NULL default '',
  `decimal_place` char(1) collate utf8_bin NOT NULL,
  `value` float(15,8) NOT NULL,
  `date_updated` datetime NOT NULL default '0000-00-00 00:00:00',
  PRIMARY KEY  (`currency_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1; ;

INSERT INTO `scrore_table` (`scrore_id`, `scrore_title`, `scores`, `decimal_place`, `value`, `date_updated`) VALUES
(1, 'Game Class A0', 'GameA0', '2', 1.00000000, '2010-04-06 22:00:54'),
(2, 'Game Class A1', 'GameA1', '2', 1.52600002,  '2010-04-06 22:00:54'),
..............................etc
(14, 'Game Class A15', 'GameA15', '2', 1.13999999,  '2010-04-06 22:00:54');

as i said i newbie to php then i dont know how to modify the php code above able to automatically create the table and insert/update new fields e.g. scrore_id, scrore_title,decimal_place, date_updated also all values to my existing database

i looking for some helps and thanks in advance..

Hello to all,

I have problem figuring out how to properly display data fetched from MySQL database in a HTML table.

In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table.

The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'

Can someone help me on this, I guess the problem lies in the while loop?
Here is part of the HTML code:

<thead>
 <tr>
 <th data-column-id="id" data-type="numeric">ID</th>
 <th data-column-id="email">Subscriber's Email</th>
 <th data-column-id="validity">Validity</th>
<th data-column-id="valid_from">Valid From</th>
 <th data-column-id="valid_to">Valid To</th>
</tr>
</thead>

Here is part of the PHP code:

 

    <?php
    while($row = $stmt->fetch(PDO::FETCH_ASSOC))
    {
        echo '
            <tr>
                <td>'.$row["id"].'</td>
        ';
        while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) {
        echo '
                <td>'.$row1["email"].'</td>
        ';
        }
        if($row["validity"] == 1) {
            echo '<td>'.$row["validity"].' month</td>';
        }else{
            echo '<td>'.$row["validity"].' months</td>';
        }
        echo '  <td>'.$row["valid_from"].'</td>
                <td>'.$row["valid_to"].'</td>
        </tr>';
    }
    ?>

P.S. Please know that I have purposely omitted the connection part and the methods in the class that are used in this code to keep the spot of the problem as clean as possible. If you need me to rephrase the question, please ask.

Thank you.

hi guys, im new to this forum

I'm new also to php, I need help from you guys:

I want to display personal information from a certain person (the data is on the mysql database) using his name as a link:

example:
               (index.php)
               names
                          1. Bill Gates
                          2. Mr. nice Guy
           
i want to click Bill Gates
 
   (output.php)
     Name: Bill Gates
     Country:xxxx
     Age: xx   
                 etc.

How can i make this or how to learn this?
   
                 

             
               

   
       

Hi,

I'm having trouble adding data to the database (test) that i created. I just can't see where I'm going wrong. need some other peoples opinions.

I have tried taking the id out of the SQL statement completely as it is an auto increment, but that doesn't seem to work either.

Thanks in advance...


<?php

$fname = $_POST['fname'];
$sname = $_POST['sname'];
$email = $_POST['email'];
$pword = $_POST['password'];
$gender = $_POST['gender'];
   
$user_name = "root";
$password = "";
$database = "test";
$server = "127.0.0.1";

$db_handle = mysql_connect($server, $user_name, $password);

$db_found = mysql_select_db($database, $db_handle);

if ($db_found)
{
$SQL = "INSERT INTO members (id, fname, sname, email, password, gender) VALUES (NULL, $fname, $sname, $email, $pword, $gender);";
$result = mysql_query($SQL);

mysql_close($db_handle);

print "Thanks for joining us ".$fname.".";
print "<br /><br />";
print $fname . "<br />";
print $sname . "<br />";
print $email . "<br />";
print $pword . "<br />";
print $gender . "<br />";
}
else
{
print "Database NOT Found";
mysql_close($db_handle);
}

?>

Ugh. Ive been asking so many questions, betcha already know my name. Hahah.
Anyways, I know I already asked a question like this, but this is different.
One of the values I am trying to insert into a database is simply not working.
Here is the columnes in my mysql database:

c_id   commet       story   user      date_added   star
Every value but 'commet' is getting inserted into database.  NO error, no mysql errror. I have racked my brain trying to figure out what is wrong with the script.
Here is my code:
Code: [Select]
<?php
$idget = $_GET['id'];
mysqlConnect();
//submit story
if(isset($_POST['submit']))
{
   $com_form = mysql_real_escape_string(bb($_POST['commet']));
   $rat_form = $_POST['rat'];
   $story_form =  $idget;
   $user = $_SESSION['user'];
   $date = date("Y-m-d");
   $query1 = "
   INSERT INTO story_commets(star, story, user, date_added, commet)
   VALUES($rat_form, '$story_form', '$user', '$date', '$com_form')
   ";
   mysql_query($query1) or die(mysql_error());


      
      
   //}
}

// desplay reviews


$query3 = "
SELECT * FROM story_commets
WHERE story = '$idget'
ORDER BY date_added
";
$select3 = mysql_query($query3) or die(mysql_error());
//$x=1;
$ratav = array();
//if(mysql_num_rows($select3) == 0)
//{
   echo '<div id="message"> No Reviews Yet.... <>';
   
//}
//else
//{
while($rows3 = mysql_fetch_assoc($select3))
{
   
   
   $commetdb = $rows3['commet'];
   $user_com_db = $rows3['user'];
   $datedb = $rows3['date_added'];
   $stardb = $rows3['star'];
   //get profile picture
   $query4 = "
   SELECT * FROM login_info
   WHERE user = '$user_com_db'
   ";   
   $select4 = mysql_query($query4) or die(mysql_error());
   
   $rows4 = mysql_fetch_assoc($select4) or die(mysql_error());
      $profile_pic = $rows4['profile_picture'];
      $user_id = $rows4['id'];
   echo "
   <div class='rev_cont'>
   <div class='info'>
   <img src='$profile_pic' /> 
   <a href=?p=profile&id=$user_id> $user_com_db </a> 
   

   
   <> <br /> 
   <div class='rev'>
   <strong> $stardb/10 </strong> <br />
   $commetdb
   <> 
   <div id='date'>  <em> Date Added: $datedb </em> <> 
   <>
   <hr />
   
   
     ";
   
   $ratav[]=$stardb; 
   
     
     
}




$sum = array_sum($ratav);

$count = count($ratav);
$av = $sum / $count;
$avf = round($av, 1);
echo"<div id='message'> Rating Avarage: $avf /10 <>";
//}
if (isset($_SESSION['user']))
{
   echo"
   <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p>
<form action='?p=review&id=$idget' method='post'  target='_self'> 
 
 <label> Your rating is on a scale of 1-10 </label>
 <select name='rat'>
    <option> 1 </option>
    <option> 2 </option>
    <option> 3 </option>
    <option> 4 </option>
    <option> 5 </option>
    <option> 6 </option>
    <option> 7  </option>
    <option> 8 </option>
    <option> 9 </option>
    <option> 10 </option>
 </select>
 <label> Commets: </label>
 
 <textarea name='commet' cols='70' rows='9'></textarea>
 <input name='story' type='hidden' value='$idget' /> <br />
 <input type='submit' value = 'Post' name='submit' />
</form>

   ";
}
else 
{
   echo "<div id='message'> Sign in to post a review! <>";
}

?>



Here are the specifics if you want it.

Here is the response part of the code:
Code: [Select]
<?php
if(isset($_POST['submit']))
{
   $com_form = mysql_real_escape_string(bb($_POST['commet']));
   $rat_form = $_POST['rat'];
   $story_form =  $idget;
   $user = $_SESSION['user'];
   $date = date("Y-m-d");
   $query1 = "
   INSERT INTO story_commets(star, story, user, date_added, commet)
   VALUES($rat_form, '$story_form', '$user', '$date', '$com_form')
   ";
   mysql_query($query1) or die(mysql_error());


      
      
   //}
}
?>
Here is the form part of my code:
Code: [Select]
<?php
if (isset($_SESSION['user']))
{
   echo"
   <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p>
<form action='?p=review&id=$idget' method='post'  target='_self'> 
 
 <label> Your rating is on a scale of 1-10 </label>
 <select name='rat'>
    <option> 1 </option>
    <option> 2 </option>
    <option> 3 </option>
    <option> 4 </option>
    <option> 5 </option>
    <option> 6 </option>
    <option> 7  </option>
    <option> 8 </option>
    <option> 9 </option>
    <option> 10 </option>
 </select>
 <label> Commets: </label>
 
 <textarea name='commet' cols='70' rows='9'></textarea>
 <input name='story' type='hidden' value='$idget' /> <br />
 <input type='submit' value = 'Post' name='submit' />
</form>

   ";
}
else 
{
   echo "<div id='message'> Sign in to post a review! <>";
}
?>
Its probably something really mundane. HelP!

hello friends,
actually i am trying to insert data in mysql
database.
here is my code

<?php
	include_once("../includes/database.php");
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Insert Product</title>
</head>

<body>
	<form action="insert_product.php" method="post" enctype="multipart/form-data">
    	<table align="center" width="600">
        <tr align="center">
        	<td colspan="8"><h2> Insert New Post</h2></td>
        </tr>
        <tr>
        	<td align="right"><b>Product Title :</b></td>
            <td><input type="text" name="product_title"  size="50" style="background-color:#06C; color:#FFF"  /></td>
        </tr>
         <tr>
        	<td align="right"><b>Product Category :</b></td>
            <td>
            	<select name="product_cat" style="background-color:#06C; color:#FFF" >
                	<option>Select A Category </option>
                    <?php 
						$get_cats = "SELECT * FROM categories";	
						$run_cats = mysqli_query($con, $get_cats);
						while($row_cats = mysqli_fetch_array($run_cats)){
							$cat_id = $row_cats['cat_id'];
							$cat_title = $row_cats['cat_title'];
							echo "<option value='$cat_id'>$cat_title</option>";
						}
					?>
                </select>
            </td>
        </tr>
         <tr>
        	<td align="right"><b>Product Platform :</b></td>
            <td>
            	<select name="product_brand" style="background-color:#06C; color:#FFF" >
                	<option>Select A Platform </option>
                    <?php 
						$get_brands = "SELECT * FROM brands";	
						$run_brands = mysqli_query($con, $get_brands);
						while($row_brands = mysqli_fetch_array($run_brands)){
							$brand_id = $row_brands['brand_id'];
							$brand_title = $row_brands['brand_title'];
							echo "<option value='$brand_id'>$brand_title</option>";
						}
					?>
                </select>
            </td>
        </tr>
         <tr>
        	<td align="right"><b>Product Image :</b></td>
            <td><input type="file" name="product_image"  /></td>
        </tr>
         <tr>
        	<td align="right"><b>Product Price :</b></td>
            <td><input type="text" name="product_price" style="background-color:#06C; color:#FFF"  /></td>
        </tr>
         <tr>
        	<td align="right" valign="top"><b>Product Description :</b></td>
            <td><textarea name="product_desc" cols="50" rows="10" style="background-color:#06C; color:#FFF"  ></textarea></td>
        </tr>
         <tr>
        	<td align="right"><b>Product Keywords :</b></td>
            <td><input type="text" name="product_keywords" size="50" style="background-color:#06C; color:#FFF" /></td>
        </tr>
         <tr align="center">
            <td colspan="8"><input type="submit" name="insert_post" value="Submit Now" /></td>
        </tr>
        </table>
    </form>
</body>
</html>

<?php
	if(isset($_POST['insert_post'])){
		$product_title = $_POST['product_title'];
		$product_cat = $_POST['product_cat'];
		$product_brand = $_POST['product_brand'];
		$product_price = $_POST['product_price'];
		$product_desc = $_POST['product_desc'];
		$product_keywords = $_POST['product_keywords'];
		$product_image = $_FILES['product_image']['name'];
		$product_image_tmp = $_FILES['product_image']['tmp_name'];
		move_uploaded_file($product_image_tmp,"product_image/$product_image");
		
		$sql = "INSERT INTO products (product_cat,product_brand,product_title,product_price,product_desc,product_image,product_keywords) VALUES ('$product_cat','$product_brand','$product_title','$product_price','$product_desc','$product_image','$product_keywords')";
		$query = mysqli_query($con, $sql);
		if($query){
			echo "<script>alert('Product Has Been Inserted')</script>";	
			echo "<script>windoow.open('insert_product.php','_self')</script>";
			exit();
		}else{
			echo "<script>alert('errror')</script>";	
		}
	}
?> 
 

but somehow its not inserting
data into my table can somebody tell wherre
m i doing mistake.

the categories and brands are displaying from database. But its not inserting data

here is my database script.

 <?php
 $con = mysqli_connect("localhost","root","","sg");
?>    

Hello, I'm new to this forum and I need some help. I'm creating a simple database that it submits data from a user input. Unfortunatly, it's not sending any data to mysql also the form is not validating each field.

Code: [Select]
<?php

if (isset($_POST['submitted'])){

$fields = array(
'email',
'state',
'district',
'gender',
'age',
'profession',
'survey',
);

foreach($fields as $fieldName) {
if(isset($_POST[$fieldName]) and trim($_POST[$fieldName]) !==''){
$fieldName = trim($_POST[$fieldName]);
}else {

$errors[] = "Please enter your". $fieldName .""; //code to validate fields
}
}
if(isset($errors)){

require_once('Connections/encourage.php');

$query = "INSERT INTO participants (email, state, district, gender, age, profession, survey) 
VALUES ('$email', '$state', '$district', '$gender', '$age', '$profession','$survey')"; //databasse connection
   
$result = mysql_query ($query); 

if ($result){

echo '<h1 id="mainhead">Thanks for submitting</hl>
<p>You are now registered</p>';
exit();

}else{

echo '<h1 id="mainhead">System Error</hl>
<p>Your registration could not be completed due to a system error We apologize for any incovience</p>';//gives system error
echo 'p' . mysql_error(). '<br /><br />Query: ' . $query . '</p>';
exit();

}
mysql_close();

} else { 

echo '<h1 id="mainhead">Error!</h1>
<p class="error">The following error(s) occurred:<br />';
foreach($errors as $msg) {
echo " - $msg<br/>\n";
}
echo '</p><p>Please try again.</p><p><br/></p>';
}

}
?>
  <form id="form1" name="form1" method="post" action"registration.php">
  <fieldset class="first">
  <label class="lableone" for="email">Email:* </label>
  <input name="email" value="<?php if(isset($_POST['email'])) echo $_POST['name'];?>"/>
 
  <label for="state"/>State:* </label>
  <input name="state" value="<?php if(isset($_POST['state'])) echo $_POST['state'];?>"/>
 
  <label for="schooldistrict"/>School District:* </label>
  <input name="schooldistrict" value="<?php if(isset($_POST['district'])) echo $_POST['district'];?>" />
 
  <label for="gender">Gender:* </label>
 <select name="gender">
   <option>Choose Your Gender</option>
   <option value="male" <?php echo ($form['gender'] == 'male' ? ' selected' : ''); ?>>Male</option>
   <option value="female"<?php echo ($form['gender'] == 'female' ? ' selected' : ''); ?>>Female</option>
 </select>
 
    <label for="age"/>Your Age:* </label>
  <input name="age" type="text" class="age" maxlength="2" value="<?php if(isset($_POST['age'])) echo $_POST['age'];?>"  />
 
  <label for="profession"/>Profession:* </label>
  <input name="profession" value="<?php if(isset($_POST['age'])) echo $_POST['age'];?>" />
 
  <label for="surveys"/>Willingness to participate in future surveys: </label>
  <input name="surveys" type="checkbox" id="surveys" value="yes" <?php echo ($form['survey'] == 'yes' ? 'checked' : '');?>/>
 
  </fieldset>
<fieldset>
  <input class="btn" name="submit" type="submit" value="Submit" />
<input class="btn" name="reset" type="reset" value="Clear Form" />
<input type="hidden" name="submitted" value="TRUE" />
</fieldset>

  </form>


Can someone help me out? Thanks in advanced! 

I need to display the last 30 days entries from database in PHP and here is the code that i am currently using, but its not working.

While entering the data in database, the date format that i am using is this...
Code: [Select]
$subon = date("F j, Y, g:i a");
And to display the code i am using this query...
Code: [Select]
$start_date = date("F j, Y, g:i a", strtotime('-30 days'));
$curr_date = date("F j, Y, g:i a");
$sql = "SELECT * FROM table WHERE status = 'approved' AND subon BETWEEN '$start_date' AND '$curr_date' ORDER BY ID DESC LIMIT 0, 5";
And then i am using the usual stuff to display the data but its not working.

Somebody please help me... Thanks in advance.

I am trying to display data from mysql. Each row from the mysql database shows up under rows.

I want the rows of data from mysql  to appear in colums of 4.

can some one help please.

<?php
$sql = 'SELECT * FROM dbtable ORDER BY id';
$result = $db->query($sql);
$output[] = '<ul>';
while ($row = $result->fetch()) {
      $output[] = '<table>';
         $output[] = '<tr>';
         $output[] = '<td class="style10"><strong>'.$row['item'].'</strong></td>';
         $output[] = '</tr>';
         $output[] = '<tr>';
         $output[] = '<td><img src="images/'.$row['pic'].'" width="100" height="150" /></td>';
         $output[] = '</tr>';
         $output[] = '<tr>';
         $output[] = '<td>'.$row['description'].'</td>';
         $output[] = '</tr>';
      $output[] = '</table>';
}
echo join('',$output);
?>

I am having difficulty inserting the following codes values into my database. I know that the variables contain a value as I am displaying them on the output screen.


Code: [Select]
$link = mysql_connect($db_host,$db_user,$db_pass) or die('Unable to establish a DB connection');

mysql_select_db($db_database,$link);
mysql_query("SET names UTF8");
$usr = $userid;
$golfer = $_REQUEST['golfer'];
$tourney = $_REQUEST['tournament'];
$backup = $_REQUEST['backup'];
date_default_timezone_set('US/Eastern');
$time = date("Y-m-d H:i:s");
$t_id=1;



mysql_query("INSERT INTO weekly_picks (t_id, tournament, user, player, backup, timestamp) VALUES ('$t_id', '$tournament', '$usr', '$golfer', '$backup', '$time') or die('Error, insert query failed')");

echo $t_id; echo "<br />";
echo $tourney; echo "<br />";
echo $usr; echo "<br />";
echo $golfer; echo "<br />";
echo $backup; echo "<br />";
echo $time; echo "<br />";
echo $userdetail['email']; echo "<br />";

$to = $userdetail['email'];
$subject = "Weekly Tournament Pick for: $tourney";
$message = "This email is to confirm your pick for $tourney has been received.
Your pick is: $golfer.
Your backup pick is: $backup
The time it was submitted was $time
Do not reply to this email, the mailbox does not exist.
Contact me with any issues at xxxxxxx@xxxxxxx.com";

$from = "noreply@chubstersgcc.com";
$headers = "From:" . $from;
mail($to,$subject,$message,$headers);
?>

<div>
<p>This is to confirm that your pick has been submitted for the following tournament: <?php echo $tourney; ?>. A confirmation of your pick as also been emailed to you.</p>
<p>Your golfer: <?php echo $golfer; ?></p>
<p>Your backup: <?php echo $backup; ?></p>
<p>Your pick was submitted at: <?php echo $time; ?></p>
</div>

Hi there im not quite sure how to do something and was wondering if anyone can help me, I am going to create a large database with lots of fields and these are going to be displayed on a page i want to limit it to 20 per page and be able to sort them aswell by ID (default) and then a-z or z-a, i dont know how to do this and i also need to know how to create the next previous and last and first links im guessing theres a count++ involved ? im not quite sure but anyway if someone can help it will be great.

Thanks,

Blink359

I'm a beginner to PHP and am stuck as to how I can fetch data from a MYSQL database and output that information in html to the website. Currently I get the information from the database using normal php:

$result = mysql_query("SELECT * FROM truffleProducts");

Then I assign each field from the database to a php variable in a while loop:
 

while ($row = mysql_fetch_array($result)) {
$id = $row{'id'};
$name = $row{'name'};
$price = $row{'Price_per_kg'};
$season = $row{'Season'};
$country = $row{'Country'};
$image = $row{'image'};
$review = $row{'review'};
}

Then I just print each variable in a table using simple html and php. My problem is that it only outputs the latest element or row from my database. I want to output the database within a HTML template so that it is professional and tidy, but i cant figure out how to do that. Any help?
Edited by louiscb, 22 October 2014 - 07:58 AM.